Arthur has a balance of $2330 on his credit card, which he plans to pay off by

making a payment of the same amount each month. Which of these monthly

amounts will allow Arthur to pay off his balance the fastest?

Answer:

[tex]5\sqrt[3]{5}[/tex]

Step-by-step explanation:

[tex]\sqrt[3]{625}[/tex] factor [tex]625^{1/3}[/tex]=[tex]5(5^{1/3} )[/tex]=5\sqrt[3]{5}

Hope that helps :)

Answer:5.7

Step-by-step explanation:

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. The distance between the point Q and the ground is h-[L cos(80°)].

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,

[tex]\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}[/tex]

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The Base is the adjacent smaller side of the angle θ.

Let the height of the support be h and the height between the point q and the ground is x. Also, the distance between point Q and the support of the seesaw is L.

Now if we look at the ΔQAR, the measure of the ∠QRA is 80°, therefore, the sine of ∠QRA can be written as,

[tex]\rm Cos(\theta)=\dfrac{Base}{Perpendicular}\\\\Cos(\angle QRA) = \dfrac{AR}{QR}\\\\Cos(\angle QRA) = \dfrac{h-x}{L}\\\\L \times Cos(80^o)=h-x\\\\x=h-[L\ Cos(80^o)][/tex]

Hence, the distance between the point Q and the ground is h-[L cos(80°)].

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Hence, option D is the correct answer to the given question.

The correct answer to the given question is the option D. i.e r=0.818 represents a stronger correlation because 0.818 > -0.926. Explanation: The strength of the correlation can be determined by the magnitude of the correlation coefficient. The correlation coefficient values vary between -1 to 1. If the value of correlation coefficient is close to -1 or 1, it indicates strong correlation. On the other hand, if the value of correlation coefficient is close to 0, it indicates a weak correlation.A correlation coefficient value of -0.926 indicates a strong negative correlation. A correlation coefficient value of 0.818 indicates a strong positive correlation. Hence, option D is the correct answer to the given question.

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Answer: 32, 27, 20

Step-by-step explanation: This is a quadratic table.

Answer:

y=2x+3

Step-by-step explanation:

Lets verify

[tex]\\ \sf\longmapsto -1=2(-2)+3=-4+3=-1[/tex]

[tex]\\ \sf\longmapsto 1=2(-1)+3=-2+4=1[/tex]

Hence verified

Answer:

C): y = 2x + 3

Step-by-step explanation:

• when x is -2:

[tex]{ \tt{y = 2(- 2) + 3}} \\ { \tt{y = - 1}}[/tex]

• when x is -1:

[tex]{ \tt{y = 2( - 1) + 3}} \\ { \tt{y = 1}}[/tex]

• since y holds for -2 and -1, it'll hold for other positive integers.

Answer:

Answer is (a)

Step-by-step explanation:

Well I didn’t really do any work but you can tell right away theres a ton of slope options so you can’t eliminate from there, BUT when you look at the y-intercept, 3 is the only y-intercept option here and the only choice with the y-intercept of 3 is (a).

Using telescoping or iteration, the closed form for the recurrence relation c₂ = 2cn-1 - 1 with co = 2 is `cₙ = 2ⁿ+1 - 1` for `n ≥ 0`.

As the recurrence relation is `c₂ = 2cn-1 - 1` with `c₀ = 2`. In the closed form, first, we write out the first few terms of the sequence: `c₀ = 2, c₁ = 3, c₂ = 5, c₃ = 9, c₄ = 17, c₅ = 33, c₆ = 65, ...`

Let's try a pattern in the sequence. Observe that `c₁ = 2c₀ + 1 = 2(2) + 1 = 5`. Similarly, `c₂ = 2c₁ + 1 = 2(5) + 1 = 11`. Continuing this process, we can see that `cₙ = 2cₙ₋₁ + 1` for `n ≥ 1`.

Let's apply telescoping to this formula:```
c₁ = 2c₀ + 1c₂ = 2c₁ + 1= 2(2c₀ + 1) + 1

= 2²c₀ + 2 + 1c₃ = 2c₂ + 1

= 2(2²c₀ + 2 + 1) + 1

= 2³c₀ + 2² + 2 + 1c₄

= 2c₃ + 1= 2(2³c₀ + 2² + 2 + 1) + 1

= 2⁴c₀ + 2³ + 2² + 2 + 1

```Note that each term in this sum telescopes. In general, we can write `cₙ = 2ⁿc₀ + 2ⁿ-1 + ... + 2² + 2 + 1`. Simplifying this expression gives:```
cₙ = 2ⁿc₀ + (2ⁿ - 1)
= 2ⁿ(2) + (2ⁿ - 1)
= 2ⁿ+1 - 1 ```

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A binomial experiment consists of 12 trials. The probability of success on trial 5 is 0.16. The probability of success on trial 9 is 0.16.

In a binomial experiment, there are two outcomes that are possible in each trial: a success and a failure.

A binomial experiment consists of a fixed number of trials.

The term "probability" refers to the measure of how likely an event is to happen.

The probability of success on trial 5 is 0.16.

We are required to calculate the probability of success on trial 9.

Since the experiment consists of a fixed number of trials, we can say that probability of success in each trial is the same.

Let us assume the probability of success is p.

Therefore, the probability of failure in each trial is (1-p).

The probability of success on trial 5 is 0.16.

Therefore, p = 0.16.

The probability of failure on trial 5 is

1-p = 1-0.16

1-p = 0.84

The probability of success on trial 9 is given by:

P(success on trial 9) = p

P(success on trial 9) = 0.16.

Therefore, the probability of success on trial 9 is 0.16, which is option E.

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Answer:

61

Step-by-step explanation:

all angles that are in a triangle add up to 180

x+80+39=180

x+119=180

x=61

Hope that helps :)

Answer: I believe your answer is correct .

Answer:

yes i belive  u got it right

Step-by-step explanation:

a) To solve the recurrence relation an = an-1 + 3(n-1), a0 = 1, we can expand the recurrence relation iteratively.

a1 = a0 + 3(1-1) = 1 + 0 = 1

a2 = a1 + 3(2-1) = 1 + 3 = 4

a3 = a2 + 3(3-1) = 4 + 6 = 10

a4 = a3 + 3(4-1) = 10 + 9 = 19

...

We can observe a pattern from the values:

a0 = 1

a1 = 1

a2 = 4

a3 = 10

a4 = 19

We can notice that an = [tex]n^2 + 1.[/tex] We can prove this by induction, but in this case, we can also recognize that the given recurrence relation generates the triangular numbers (1, 3, 6, 10, 15, ...), which are defined by the formula Tn = n(n+1)/2.

Thus, the solution to the recurrence relation is an = [tex]n^2 + 1.[/tex]

b) For the recurrence relation an = an-1 + n(n-1), a0 = 3, we can again expand it iteratively:

a1 = a0 + 1(1-1) = 3 + 0 = 3

a2 = a1 + 2(2-1) = 3 + 2 = 5

a3 = a2 + 3(3-1) = 5 + 6 = 11

a4 = a3 + 4(4-1) = 11 + 12 = 23

...

Observing the values, we can notice that an =[tex]n(n^2 + 1).[/tex]

Thus, the solution to the recurrence relation is an = [tex]n(n^2 + 1).[/tex]

c) For the recurrence relation an = an-1 +[tex]3n^2[/tex], a0 = 10, we expand it iteratively:

a1 = a0 + [tex]3(1^2)[/tex] = 10 + 3 = 13

a2 = a1 + [tex]3(2^2) =[/tex] 13 + 12 = 25

a3 = a2 + [tex]3(3^2)[/tex]= 25 + 27 = 52

a4 = a3 + [tex]3(4^2)[/tex]= 52 + 48 = 100

...

We can notice that an = [tex]n^3 + 10.[/tex]

Thus, the solution to the recurrence relation is an = [tex]n^3 + 10.[/tex]

These are the solutions to the given recurrence relations.

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Answer:

the probability that a test correctly classifies as positive individuals who have preclinical disease

Step-by-step explanation:

Sensitivity represents the true positive percentage

Lets take an example if there is 90% sensitivity that means there are 90% people who have the target disease considered the test positive

So according to the given options, it is the probability in which if the test is done in a correct manner so this means that the positive individuals have the preclinical disease

Therefore the first option is correct

Answer:

Part A

750, 2250, 6750, 20250, 60750

Part B

1640250

Answer:

The slope is [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

[tex]\frac{Y_{2} -Y_{1} }{X_{2}-X_{1} }[/tex]

-7-(-3)= -7+3= 4

4/?

7-(-9)= 7+9 = 16

4/16=1/4

I hope this helps :-)

Answer:

Step-by-step explanation:

x = 9

Answer:

12 feet or 4 feet.......

After taking the given data into consideration we conclude that
a) the half-life of the unknown radioactive element is approximately 1921.7 days.
b) approximately 1011.4 days, or about 2.77 years, for a sample of 100 mg to decay to 55 mg.

(a) The half-life of a radioactive element is the time needed for half of the material to decay. To find the half-life of the unknown radioactive element, we can use the fact that in 560 days, the radioactivity of a sample decreases by 36 percent. Let T be the half-life of the element. Then, we have:
[tex]0.5 = (1 - 0.36)^{(560/T)}[/tex]
Simplifying this equation, we get:
[tex]0.5 = 0.64^{(560/T)}[/tex]
Taking the natural logarithm of both sides, we get:
[tex]ln(0.5) = ln(0.64)^{(560/T)}[/tex]
[tex]ln(0.5) = (560/T) * ln(0.64)[/tex]
Solving for T, we get:
[tex]T = -560 / (ln(0.64) * ln(0.5))[/tex]
[tex]T \approx 1921.7 days[/tex]

(b) To find how long it will take for a sample of 100 mg to decay to 55 mg, we can use the half-life formula:
[tex]N = N_0 * (1/2)^{(t/T)}[/tex]
where:
N is the final amount, which is 55 mg in this case
[tex]N_0[/tex] is the initial amount, which is 100 mg in this case
t is the time it takes for the sample to decay from [tex]N_0[/tex] to N
T is the half-life of the element, which we found to be approximately 1921.7 days
Substituting the values, we get:
[tex]55 = 100 * (1/2)^{(t/1921.7)}[/tex]
Simplifying this equation, we get:
[tex]0.55 = (1/2)^{(t/1921.7)}[/tex]
Taking the natural logarithm of both sides, we get:
[tex]ln(0.55) = (t/1921.7) * ln(1/2)[/tex]
Solving for t, we get:
[tex]t = -1921.7 * ln(0.55) / ln(1/2)[/tex]
[tex]t \approx 1011.4 days[/tex]
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Answer:

the answer is  10

Step-by-step explanation:

Answer: 10

Why? Because 10x5=50 and then 10x2=20 ten can be used for both of them! Hope this helps^^ please give me brainlist if you could but you don’t have too!^^

Answer:

1.8

Step-by-step explanation:

- hope this helps!!

73.12 m2

Step-by-step explanation:

determine triangle area.

8x12=96   96/2=48

determine area of half circle

diameter=8

radius=4

4π²/2=25.1327412287

add two areas together.

48+25.1327412287=73.1327412287

round the nearest hundredth

73.1327412287=73.12 m2

Answer:

Topic : CIRCLE

1. Capture/ cut outs pictures that represents a Circle then paste it in a long band paper.

2. Make a reflection in CERA form

C-Content (min. 5sentence)

E- experience(min. 5 sen.)

R-reflection (min.5 sent.)

A- Application (min.5

Yes, it is possible to fill all twenty mugs.

Answer:

1. y=2x^2-8X-1

2. y=-6x^2+36x-63

3. y=-3x^2+18x-34

4. y=9x^2+54x+76

5. y=-x^2+8x-22

6. y=6x^2-48x+90

7. y=8x^2+16x+5

8. y=2x^2-8x+1

Have a great day :)

Answer: it's  1 1/2

please give me brainlest

The present value needed to accumulate $150,000 after 6 years with a 2% interest rate compounded quarterly is $131,488

To calculate the present value needed to accumulate $150,000 after 6 years with a 2% interest rate compounded quarterly, we can use the formula for compound interest:

Present Value = Future Value / (1 + r/n)^(n*t)

Where:

Future Value = $150,000

Interest Rate (r) = 2% = 0.02 (converted to decimal)

Number of Compounding Periods per Year (n) = 4 (quarterly compounding)

Number of Years (t) = 6

Substituting these values into the formula, we have:

Present Value = $150,000 / (1 + 0.02/4)^(4*6)

Calculating inside the parentheses first:

Present Value = $150,000 / (1 + 0.005)^(24)

Next, calculate the exponent:

Present Value = $150,000 / (1.005)^(24)

Using a calculator or spreadsheet, we can evaluate the expression inside the parentheses and then divide $150,000 by that result to find the present value. Rounding to the nearest dollar, the present value needed is $131,488.

Therefore, the amount to be invested now or the present value needed is $131,488.

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The correct answer is option B. 232.6 mg/mL which is the concentration of the vial after reconstitution.

To determine that 232.6 mg/mL is the concentration of the antibiotic vial after reconstitution, we need to calculate the amount of antibiotic in grams divided by the final volume in milliliters.

The vial states that it needs to be reconstituted with 8.6 mL of sterile water for a final volume of 10 mL. This means that the antibiotic will be dissolved in 8.6 mL of sterile water.

Since the vial contains 2 grams of antibiotic, the concentration can be calculated as follows:

Concentration = Amount of antibiotic (g) / Final volume (mL)

Concentration = 2 g / 8.6 mL

Simplifying the expression, we get:

Concentration ≈ 0.2326 g/mL

Therefore, the correct option is B) 232.6 mg/mL, the concentration of the vial after reconstitution.

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The expression for a(t) is 8(1-t)/(1+t)² and A(2) = -8/9.

An expression is a combination of numbers, variables, and operations. Expressions can be used to represent quantities, relationships, and functions. While there are different types of expression such as arithmetic expression, algebraic expression and function, this as an algebraic expression.

To determine the expression that represents a(t); we have to factor the expression 8t/(1+t²).

8t/(1+t²) = 8t/(1+t)(1-t)

Dividing by 1 - t

a(t) = 8t/(1+t)

Simplifying further;

a(t) = 8(1-t)/(1+t)²

To solve for A(2), we need to plug t = 2 into the expression;

A(2) = 8(1-2)/(1+2)²

A(2) = -8/9

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Answer:

when a = 6, substitute 6 in the equation for a:

7(a + 2) = 7(6)+ 14

Step-by-step explanation:

Answer:

56

Step-by-step explanation:

When a = 6

7(a+2)

7(6+2)

7(8)

56

Answer:

-43 yards is the answer...

To prove that the explicit formula for the nth term of a geometric sequence is given by an = a₀.rⁿ, we will use mathematical induction. Mathematical induction is a proof technique used to establish a statement or property for all natural numbers or integers greater than or equal to a starting value.

Step 1: Base Case

For n = 0, the formula gives a₀.r⁰ = a₀, which is the first term of the sequence. So, the formula holds true for the initial value.

Step 2: Inductive Hypothesis

Assume that the formula holds for some arbitrary value k, i.e., ak = a₀.rᵏ.

Step 3: Inductive Step

We need to prove that the formula also holds for k+1, i.e., a(k+1) = a₀.r^(k+1).

Using the definition of a geometric sequence, we have:

a(k+1) = r.aₖ

Now substitute the inductive hypothesis into the above equation:

a(k+1) = r.(a₀.rᵏ) = (r.a₀).rᵏ = a₀.r^(k+1)

Therefore, we have shown that if the formula holds for k, then it also holds for k+1.

Step 4: Conclusion

By the principle of mathematical induction, the explicit formula for the nth term of a geometric sequence, given by an = a₀.rⁿ, is true for all non-negative integers n.

Thus, we have proved the claim using mathematical induction.

The question should be:

Recall the following definition of an Geometric Sequence.

A sequence a₀, a₁, a₂, ... is called an geometric sequence if, and only if there is a constant r such that

ak = r.a_k_-1 where k≥ 1.

Also recall that we "claimed" the explicit formula for the nth term of the geometric sequence is given by

an = a₀.rⁿ  where n≥ 0. Use mathematical induction to prove that our claim is true.

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