Aristotle's rhetorical triangle tells us that effective messages show awareness of

ethos, pathos, and logos
logic, emotion, and values
speaker, audience, and purpose
thought, voice, and opinion

Light hits a mirror at a 45° angle. It will be reflected at an angle equal to 45°

According to law of reflection, when a light ray falls on a surface that is smooth, the angle of reflection will be equal to the angle of incidence. The incident ray, the reflected ray and the normal to the surface all will lie in the same plane.

Reflection is the process in which a light ray gets bounced back after falling on a surface. The angle between in the incident ray and the normal to the surface is known as angle of incidence. The angle between in the reflected ray and the normal to the surface is known as angle of reflection.

Therefore, light hits a mirror at a 45° angle. It will be reflected at an angle equal to 45°

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The largest value of w (in N)that they can support as shown in equilibrium.

What is equilibrium?

a State of balance between opposing forces or actions that is either static as in nobody acted on by forces whose resultant is zero or dynamic reaction when the rates of reaction in both differentions are equal.

Sol- the total force in x direction is given as,

€Fx=0

T1 sin 37°=T2 sin 53°

100×3/5 =T/2 ×4/5

T2=75 N

The given total force is-

€Fy=0

T1 cos 37°=T2 cos 53°+W

W=80×4/5 -75×3/5

W=19N

Thus

The largest value of W is 19N.

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Answer:

The answer is the asterism.

Explanation:

An asterism is recognizable pattern of stars . some other commonly recognized asterisms are the little dipper ,orion's belt , and the teapot

The circuit is drawn given below

When the key is 'on' then the current is flowing and all the lamps will glow

Resistance is used to resist the flow of current.

Ammeter is used to measure the current flowing in the circuit

Answer: d = 8 sin (πt

Explanation:

when displacement is 0m in t = 0s, then it's a sine equation

∴ d = A sin (ωt + Ф)

when t = 0, then there's no initial phase

Period ⇒ 2π/ω = 2 ⇒ ω = π

∴ d = 8 sin (πt)

Given:

The refractive index of the air, n₁=1.0003

The angle of incidence, θ₁=87°

The angle of refraction, θ₂=10°

To find:

The refractive index of the medium.

Explanation:

From the snell's law,

Where n₂ is the refractive index of the medium.

On substituting the known values,

Final answer:

Thus the refractive index of the medium is 5.75

Given that, Anton is applying a force on a cart making it move around.

The forces acting on the cart are gravitational force, normal force, frictional force, and the force applied by Anton.

The gravitational force will be acting downwards. From Newton's third law there will be a reaction force to the gravitational force and that is called the normal force. And the formal force will be acting upwards. These two forces are equal to each other in magnitude. And thus they will cancel each other out making the net force on the cart in the vertical direction zero.

The force applied by Anton will be acting forward and the frictional force will be opposing the movement of the cart. The net force in the horizontal direction will be directed forward.

From Newton's second law, the net force is equal to the product of the mass of the cart and the acceleration produced by the net force.

ANSWER:

250 J

STEP-BY-STEP EXPLANATION:

F = 20N is required to stretch the spring by 4 meters

We know that the force is equal to:

We solve for k (spring constant):

The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:

The work required is 250 joules.

First, take into account that the open circle means that the point is not included into the domain and the range. The closed point means that such a point is included into both domain and range.

In this case, althoug there is a open circle, there is another part of the curve on which the y value is included into the path.

Then, the range of the graph is:

ran f = [2,7]

Which is equivalent to all number from 2 to 7.

The distance the car of mass 1090 kg travels with a velocity of 16 m / s down the hill having a 11 degree decline until it comes to a stop at the end is 52 m

θ = 11°

m = 1090 kg

g = 9.8 m / s²

μ[tex]_{k}[/tex] = 0.45

W = m g

W = 1090 * 9.8

W = 10682 N

Resolving W into its horizontal and vertical components,

[tex]W_{y}[/tex] = W cos θ

[tex]W_{y}[/tex] = 10682 * cos 11°

[tex]W_{y}[/tex] = 10682 * 0.98

[tex]W_{y}[/tex] = 10468.36 N

[tex]W_{x}[/tex] = W sin θ

[tex]W_{x}[/tex] = 10682 * sin 11°

[tex]W_{x}[/tex] = 10682 * 0.19

[tex]W_{x}[/tex] = 2029.58 N

N = [tex]W_{y}[/tex]

N = 10468.36 N

F[tex]_{k}[/tex] = μ[tex]_{k}[/tex] N

F[tex]_{k}[/tex] = 0.45 * 10468.36

F[tex]_{k}[/tex] = 4710.76 N

∑ [tex]F_{x}[/tex] = m a

[tex]W_{x}[/tex] - F[tex]_{k}[/tex] =  m a

2029.58 - 4710.76 = 1090 * a

a = - 2681.18 / 1090

a = - 2.46 m / s²

Acceleration is negative because the car is decelerating in positive direction.

v² = u² + 2 a s

0 = 16² + ( 2 * - 2.46 * s )

4.92 s = 256

s = 52 m

Therefore, the distance the car travels down the hill is 52 m

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In order to calculate the resistance, we can divide the voltage and the current, according to the formula below:

Where R is the resistance (in ohm), V is the voltage (in Volt) and I is the current (in Ampere).

So, using V = 120 V and I = 60 A, we have:

Therefore the resistance is 2 ohms.

On a graph of distance vs time, a straight line indicates that a car speed is constant.

Therefore, when a car moves with constant speed the the distance time graph is in straight line.

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A ) The height of cliff from which the cannonball is shot from = 12.72 m

B ) The distance from the base of the cliff = 19.14 m

- H = [tex]u_{y}[/tex] T - 1 / 2 g T²

T = Total time taken

g = Acceleration due to gravity

H = Height above the ground  

[tex]u_{y}[/tex] = Y-component of initial velocity

T = 2.2 s

g = 9.8 m / s²

θ = 30°

u = 10 m / s

[tex]u_{y}[/tex] = u sin θ

[tex]u_{y}[/tex] = 10 * sin 30°

[tex]u_{y}[/tex] = 5 m / s

- H = ( 5 * 2.2 ) - ( 0.5 * 9.8 * 2.2 * 2.2 )

- H = 11 - 23.72

H = 12.72 m

R = [tex]u_{x}[/tex] T

[tex]u_{x}[/tex] = u cos θ

[tex]u_{x}[/tex] = 10 * cos 30°

[tex]u_{x}[/tex] = 8.7 m / s

R = 8.7 * 2.2

R = 19.14 m

Therefore,

A ) The height of cliff from which the cannonball is shot from = 12.72 m

B ) The distance from the base of the cliff = 19.14 m

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During the Maurya empire, the Indian lifestyle and manner of existence had been deeply stimulated by Buddhism. Buddhism appealed to human beings of decreased castes because it emphasized individuals' course to enlightenment and salvation, which might be attained in this existence.

The Maurya Empire's political cohesion and inner peace endorsed the expansion of trade in India. at some stage in Ashoka's reign, authorities oversaw the building of essential roadways, and the Mauryan international network of exchange multiplied. India's exports to places like Bactria and Persia blanketed silk, textiles, and spices.

The Maurya Empire become centralized through the conquest of the Indo-Gangetic simple, and its capital town become located at Pataliputra (current Patna). outdoor this imperial middle, the empire's geographical volume became dependent on the loyalty of military commanders who managed the armed towns sprinkling it.

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Since he pilot releases the brakes and he finds that the plane still does not start to move, the  explanation I agree with is option C:

The lift of the airplane is provided by the flow of air around the wings. Additionally, the wings' form contributes to lift. The airplane is being pulled toward Earth by weight. The weight of an airplane is distributed evenly from front to back during construction.

Note that the design of an airplane wing is intended to speed up airflow across the top of the wing. Air pressure decreases when it moves more quickly. Therefore, the pressure at the top of the wing is lower than that at the bottom. The pressure differential exerts a force on the wing, lifting it into the air.

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See full question below

After being pushed away from the departure gate, an aircraft is standing still with the brakes applied and the engine running on very low. When the pilot releases the brakes he finds that the plane still does not start to move. Here are three explanations for why the plane does not move. Which one do you agree with?

A. When a single force that is too weak acts on an object it will not move. When the pilot releases the brakes the only force acting on the plane is that of the

engines but because this force is too weak, the plane will not move.

B. When the pilot releases the brakes two forces act on it. The engines exert a force in one direction and the ground exerts a force on the wheels in the opposite direction. The plane does not move because the force exerted by the ground on the wheels is stronger than the force of the engines.

C. When the pilot releases the brakes two forces act on it. The engines exert a force in one direction and the ground exerts a force on the wheels in the opposite direction. The plane does not move because the force exerted by the ground on the wheels is the same strength as the force of the engines.

We are asked to determine the acceleration of the system. To do that we will consider the two masses to be a single system and we will use the following free-body diagram.

Where:

To determine the components of the weight of "A" we use the following triangle:

Therefore, the vertical component is given by:

Since the weight is the product of the mass and the acceleration we have;

The horizontal component is given by:

Substituting the formula for weight:

The friction force is given by:

The normal force "N" is equivalent to the vertical component of the weight since there is no acceleration in that direction. Therefore, we have:

Substituting the values:

Now, the net force is equivalent to the forces acting on the system. Therefore, the net force is:

Substituting we get:

According to Newton's second law we have that the net force is equal to the product of the mass and the acceleration:

The total mass is the sum of the masses "A" and "B".

Substituting the net force:

Now, we divide both sides by the total mass:

Since we have that the masses are equal:

Substituting we get:

Adding the masses in the denominator:

We can cancel out the "m":

Now, we plug in the values:

Solving the operations:

Therefore, the acceleration is 1.81 meters per second square.

Part B. To determine the value of the coefficient of friction that will keep the system from accelerating we must go back to the formula for the acceleration:

Now, we will set the acceleration to zero:

Multiplying both sides by 2:

Now, we can divide both sides by "g":

Now, we solve for the coefficient of friction. We subtract 1 to both sides:

Now, we add sin(30) to both sides:

Now, we divide both sides by -cos(30):

Now, we solve the operations:

Therefore, the friction coefficient is 0.58

Best player in NBA right now Giannis Antetokounmpo.

The National Basketball Association, NBA is a professional basketball league in North America. The league consists of 30 teams and is one of the predominant expert sports activities leagues within the united states of America and Canada. It's far the finest guys professional basketball league within the international.

To sell great aware device of technical education where excellence, relevance to market desires and participation with the aid of all stakeholders are prime and principal determinants.

The NBA is a 70-year-vintage employer born from innovation. It turned into June 1946 in the big apple city while Boston garden owner Walter Brown found out that primary ice hockey arenas, which were vacant maximum nights, will be used to host basketball games.

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According to the Newton's Third law, the force sent back with equal and opposite in the reaction.

According to Newton's third law, two objects exert a force of equal magnitude and opposite direction. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force on it. Newton's 3rd law of motion states that action and reaction are always equal but opposite in direction. Newton's third law that for every action in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also uses an alike and across-form force on object A.

So we can conclude that the force is in equal in magnitude but in opposite direction according to Newton's Third law.

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A. The moment of the loop is 5.4 x [tex]10^{-3} Am^{2}[/tex]

B.  The torque exerted on the loop by the magnetic field is 4.32 [tex]10^{-3}[/tex] Nm.

Given that the current I in the circular loop is 17.0 mA and the circumference of the loop is 2.00 m.

The radius of the circular loop is calculated as given below.

2πr = 2

r = 2/2 x 3.14

r = 0.18m

The moment in the circular loop is calculated as given below.

M = in

M = 17 x [tex]10^{-3}[/tex] x 3.14 x 0.318²

M = 5.4 x [tex]10^{-3} Am^{2}[/tex].

The torque exerted on the loop by the magnetic field is given below:

T = MB

T = 5.4 x [tex]10^{-3}[/tex] x 0.800

T = 4.32 x [tex]10^{-3} Nm[/tex].

This is the torque of the current-carrying loop in a uniform magnetic field. This formula can be shown to be valid for loops of any shape. The loop carries a current I, has N turns, and the plane A and the normal to the loop each make an angle θ with the field B. The net force on the loop is zero. A magnetic field exerts a force on a straight wire through which an electric current flows. Apply torque to the loop of the wire carrying the current. A torque rotates an object around a fixed axis.

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Answer:

It reaches its top speed at the very center of the globe and continues rocketing toward the other side

Explanation:

So what happens? Well, as the ball drops through the hole it picks up speed - that's the acceleration due to gravity. It reaches its top speed at the very center of the globe and continues rocketing toward the other side.

The cannon ball will travel the highest distance when the angle of projection is 70 degrees.

The maximum height reached by a projectile is calculated using the following formula.

H = u²sin²θ/2g

where;

when the angle of projection is 60 degrees;

H = (15² (sin 60)²) / (2 x 9.8)

H = 8.6 m

when the angle of projection is 70degrees;

H =  (15² (sin 70)²) / (2 x 9.8)

H = 10.14 m

Thus, the cannon ball will travel the highest distance when the angle of projection is 70 degrees.

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For a device that electrocutes insects with an AC voltage of 4320V which is obtained from a standard 1200V transformer, If the primary coil has 21 turns, the number of turns in the secondary coil is 76 turns.

Number of turns and output voltage of the primary coil and secondary coil in a transformer are related as the ratio of number of turns in the primary and secondary coil is equal to the ratio of output voltage in the primary and secondary coil respectively.

It can be stated as N₁/N₂ = V₁/V₂, where N₁ and N₂ are the number of turns in the primary and secondary coil respectively, and V₁ and V₂ are the output voltage of primary and secondary coil respectively.

According to the question,

21/N₂ = 1200/4320

N₂ = 75.6

Hence the number of turns should be an integer value, the number of turns in secondary coil are 76 turns.

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Ball moving vertically upwards,

initial velocity = 30 m/s

final velocity = 0 m/s [ the ball stops after reaching a certain height ]

Applying v = u + at

               0 = 30 + 10t [ We divide the course of the object into an uphill travel and a descending journey by assuming there is no friction and that g is equal to 10 m/s². ]

Therefore, t = 3 seconds

By symmetry, the descent will take the same amount of time.

Therefore, the object needs a total of 6 seconds before it returns.

using, H=(v²−u²)/2a

ultimate velocity = 0 m/s (it stops when maximum height is reached)

beginning speed = 20 m/s

a = −g = −9.8m/s² (acceleration owing to gravity, negative sign because it is acting downward)

Replace the values

Obtaining, H=20.408m

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The location of the centre of the mass of the CO molecule relative to the carbon atom is 6.46 ×10⁻¹¹ m.

The Centre of Mass of that object is a position that is relative to an object or a system of objects. The average position of all parts of the system that are weighted to their masses is known as the Centre of Mass.

Given, the distance between the carbon and oxygen atoms, r = 1.13 ×10⁻¹⁰m.

The ratio of the mass of the carbon and oxygen:

Mc/Mo = 12/16 = 0.750

Consider that Xc is the position of carbon and Xo is the position of the oxygen atom in CO molecule.

The centre of the mass of the system is equal to the:

[tex]X_{co}=\frac{M_CX_C+M_OX_O}{M_C+M_O}[/tex]

[tex]X_{co}=\frac{(M_C/M_O)X_C+X_O}{M_C/M_O+1}[/tex]

As we are calculating the centre of the mass relative to the carbon atom.

Therefore Xc = 0 and Xo= 1.13 ×10⁻¹⁰m.

[tex]X_{CO} =\frac{1.13\times 10^{-10}}{0.750 +1}[/tex]

Xco = 6.46 ×10⁻¹¹ m

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Newton's third law states that; with every action, there is a direct and opposite reaction. As you walk across the flooor, you are applying a force due to your weight on the floor. The floor would apply an an equal force onto your feet which is in opposite direction and this force pushes you forward. This force is called th normal force. Thus, the correct option is

d)

The maximum height of the stone above the ground is 227.55 m.

The maximum height reached by the stone is calculated by applying the following kinematic equation.

H = u²sin²θ/2g

where;

Substitute the given parameters and solve for the maximum height reached by the stone.

H = (100² x (sin 30)²)/(2 x 9.8)

H = 127.55 m

Height of the stone above the ground = 127.55 m + 100 m = 227.55 m

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The time that the ball took to take off at an angle of  29.0° is  1.13 s

When two lines meet at a point, they form an angle. The word "angle" refers to the length of the "opening" between these two rays. The symbol is used to denote it.

Radians, a unit of circularity or rotation, and degrees are the two most common units used to measure angles. In daily life, angles are present. For the design of highways, structures, and sports venues, engineers and architects use angles.

The motion along the x-direction is always uniform, so the position along the x-direction is given by

x(t) = (v₀cos∅)t

where,

v₀ is the initial speed,

cos∅ is the angle of launching,

t is the time.

We can re-write the formula as

v₀t = x(t)/cos∅        ...1

Along the y-direction the motion is accelerated (free-fall), so the equation for the vertical position is

y(t) = h = v₀sin∅t - 1/2gt²        ...2

where,

h = 45.0 m is the height of the building

g = 9.8m/s²  is the acceleration of gravity.

Substituting (1) into (2),

y(t) = h = x(t)tan∅ - 1/2gt²

And when this happens, the displacement along the x-axis is x = 47.8 m. Solving the equation for t and substituting the numbers, we find the time of flight:

[tex]t = \sqrt{\frac{2(h-xtan\theta)}{g} }[/tex]

[tex]t = \sqrt{\frac{2(45-47.8tan39^{\circ})}{9.8} }[/tex]

t = 1.13 s

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Full question

Suppose the ball is thrown from a 45m height  building as in the PRACTICE IT problem at an angle of 29.0° below the horizontal. If it strikes the ground 47.8 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.)

a) the time of flight s

The minimum force that the contestant must exert to get the block moving is 53.33 N and the acceleration of the block is 0.874m/s² once it starts to move and the force is maintained.

When a force is applied at an angle, the force will have two components, one along the floor and one along the vertical.

If the force is F applied at an angle θ, then the vertical component of force is Fsinθ and the floor component is Fcosθ.

In out case θ = 25°,

A.) There will we a frictional force acting on the body which will be opposite to the component of the force which is along the floor, if the floor component just overcomes the static frictional force than the block will start to move.

So, we can write,

Friction force =  Fcosθ

μN = Fcosθ

where,

μ is the coefficient of static friction,

N is the normal reaction by the floor on the block which would be equal to the mg,

F is the minimum force Applied.

Putting all the values,

(0.1)(10)(48) = (F)(cos25°)

48 = F(0.9)

F = 53.33 Newtons.

B.) When the block will start moving,

There will be a kinetic frictional force on it as well as a Fcosθ on it,

The friction will be opposite direction of the motion, Fcosθ will be in the direction of the motion,

So, we can write, The net force on the body

F = Fcosθ - Fr

F = Fcosθ - μN

F = Fcosθ - umgsinθ

When the box is moving the normal reaction N will be equal to the vertical component of the force,

Here, u is the coefficient of kinetic friction,

Putting all the values,

F = 48 - 0.03x10x48x0.42

F = 48 - 6.048

F = 41.95 N

we can also write,

F = ma

where a is the acceleration of the block and m is the mass of the block,

41.95 = 48a

a = 0.874m/s².

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A contestant in a winter games event pushes a 48 kg block of ice across a frozen lake with a rope over his shoulder at a 25 degree angle.

The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03.

A.) Calculate the minimum force F (in N) he must exert to get the block moving.

B.) What is its acceleration (in m/s^2) once it starts to move, if that force is maintained?

Answer:

The first option: 0.8

Explanation:

Let us draw the angle.

Now,

Now, using the Pythagoras theorem we find that

Therefore,

since for our angle, opposite = 8, we have

Therefore, the first choice (0.8) is the correct answer.