Anyone want to try this?

I’ll give the answer later.

If your try doing this then... good luck! :)

Answer:

2*2*3*5

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer: 45

Step-by-step explanation: The 3rd partner has 45% of the store. Which is also $315,000.

Answer: the third partner owns 45% or $315,000 of the business.

Step-by-step explanation:

30 percent of 700,000=210,00

25 percent of 700,000=175,000

175,000+210,000=385,000

700,000-385,000= 315,000

the third partner owns 315,000 and 315,000=45%

Answer:

-207

Step-by-step explanation:

Using r= -3, we can substitute r in the whole equation as (-3) which gives you: ((-3)-3)^3 +(-3)^2. Now you can calculate these values in a step by step manner. (-6)^3 +9 then to -216 +9 which brings you to the answer of -207.

Answer:

225

Step-by-step explanation:

(r - 3)³ + r² if r = -3 and s = -4

(-3 - 3)^3 + (-3)^2

(-6)^3 + (9)

(-6 x -6 x -6) + 9

-216 + 9

-207

Answer:

a

Step-by-step explanation:

Answer: D

Step-by-step explanation:

Answer:

4^2 + 5 = 21, 5^2 + 3 = 28, 7^2 + 3 = 52, 3^2 + 43 = 52, 7^2 + 19 = 68, 3^2 + 11 = 20, 1^2+19 = 20. I can't find a prime number and a perfect square that sums to 13.

Explanation:

these are primarily derived by finding the closest perfect square to a number and finding the difference to make the sum work, or finding the simplest prime number that will reduce the number which is a multiple of a perfect square.

Answer:

[tex] \cos (u + v) = -\dfrac{56}{65} [/tex]

Good job!

Step-by-step explanation:

[tex] \cos (u + v) = \cos u \cos v - \sin u \sin v [/tex]

[tex] \sin u = -\dfrac{3}{5} [/tex]; u is in QIII.

That makes [tex] \cos u = -\dfrac{4}{5} [/tex]

[tex] \sin v = -\dfrac{12}{13} [/tex]; v is in QIV.

That makes [tex] \cos v = \dfrac{5}{13} [/tex]

[tex] \cos (u + v) = (-\dfrac{4}{5})(\dfrac{5}{13}) - (-\dfrac{3}{5})(-\dfrac{12}{13}) [/tex]

[tex] \cos (u + v) = -\dfrac{20}{65} - \dfrac{36}{65} [/tex]

[tex] \cos (u + v) = -\dfrac{56}{65} [/tex]

You are correct.

Answer:

Step-by-step explanation:

-0.8615

Answer: The cost per bag is $27

Step-by-step explanation:

Divide 135 by 5 = 27

Unit ratio means that if you know the rate per unit, you can calculate the cost by multiplying the constant rate by the number of units. In this question, the rate is $27 and the unit is the bag.

The ratio looks like

1:27 as 2:54 as 3:81 as 4:108 as 5:135

They are all equivalent to 1/27

y = 27x is another way of writing an equation for this ratio.

Answer:

24

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

Answer:

answer is 142

Step-by-step explanation:

Answer:

-56.9034

Step-by-step explanation:

Answer:

b + 2 = 6

Step-by-step explanation:

This may not be the right answer, but its what I think it is.

Answer:

10 feet.

Step-by-step explanation:

First time: 160/2=80.

Second time: 80/2=40.

Third time: 40/2=20.

Fourth time: 20/2=10.

Boom.

Answer: 6

Step 1: Subtract 8.

32 - 8 = 24

Step 2: Divide by 4, since the question is asking for 4 times the number.

24 ÷ 4 = 6

Answer = 6

Answer:

I'll assume that x2 = x^2 and y2 = y^2 and the answer is sqrt{35}.

Step-by-step explanation:

This problem invovles completing the square, so if I square (x+y), I get

x^2+2xy+y^2, and since xy = 6, 2xy = 12, 23+12 = 35, and your answer is sqrt{35}.

Answer:

Directly proportional relationships always pass through the origin (0,0). There are other linear relationships that do not pass through the origin.

The graph of a proportional relationship must pass through the origin (0,0). Because of the value of k, the ordered pair (0, 0) satisfies this equation.

The relation between lines and points is described by a graph, which is a mathematical description of a network. A graph is made up of some points and connecting lines. It doesn't matter how long the lines are or where the points are located. A node is specified for each element in a graph.

A ray is used to describe any proportional relationship using an equation of the form y = kx. The ordered pair (0, 0) satisfies this equation regardless of the value of k, hence the ray or line must traverse the origin.

Thus, the graph of a proportional relationship must pass through the origin (0,0). Because of the value of k, the ordered pair (0, 0) satisfies this equation.

Learn more about the graph here,

https://brainly.com/question/17267403

#SPJ2

Answer:

3

Step-by-step explanation:

he pattern is continued by adding 3 to the last number each time, like this: 1, 8, 27, 64, 125, 216, 343, 512, 729

Answer:

37

Step-by-step explanation:

Sorry if this is wong I haven't done these in awhile, but this is how I got it.

f(X)=3x+7

f(10)=3(10) +7

f(10)=30 +7

f(10)=37

Answer:

f(10)=37

Step-by-step explanation:

f(x)=3x+7

(for f(10) we sub 10 for x)

f(10)=3×10+7

=30+7

=37

Answer:

1) [tex]f'(t)=4t,\ g'(t)=3t^2+4[/tex]

2) [tex]p(t) =2t^5+8t^3[/tex]

[tex]p'(t)=10t^4+24t^2[/tex]

3) False

4)[tex]q(t) =\dfrac{1}{2}t+2t^{-1}[/tex]

[tex]q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]

5) False

Step-by-step explanation:

Given that:

[tex]f(t) = 2t^2[/tex] and [tex]g(t) = t^3 + 4t[/tex]

Formula:

[tex]1. \dfrac{d}{dx}x^n=nx^{n-1}[/tex]

[tex]2. \dfrac{d}{dx}C.f(x)=C.f'(x)\ \{\text{C is a constant}\}[/tex]

1) Using above formula:

[tex]f'(t)=2\times 2 t^{2-1}=4t[/tex]

[tex]g'(t)=3t^{3-1}+4\times 1 t^{1-1}=3t^2+4[/tex]

2) [tex]p(t) =2t^2(t^3+4t)[/tex]

Rewriting the formula by distributing the [tex]2t^2[/tex] term:

[tex]p(t) =2t^2.t^3+2t^2.4t=2t^5+8t^3[/tex]

[tex]p'(t) = 10t^4+24t^2[/tex]

3) By using answers of part (1):

[tex]f'(t).g'(t)=12t^3+16t[/tex]

[tex]p'(t) = 10t^4+24t^2[/tex]

Therefore it is False that [tex]p'(t) = f'(t).g'(t)[/tex]

4) [tex]q(t)=\dfrac{t^3+4t}{2t^2}[/tex]

Writing by distributing:

[tex]q(t)=\dfrac{t^3}{2t^2}+\dfrac{4t}{2t^2}\\\Rightarrow q(t) =\dfrac{t}{2}+\dfrac{2}{t}\\\Rightarrow q(t) =\dfrac{1}{2}t+2t^{-1}[/tex]

Using the formula:

[tex]q'(t)=\dfrac{1}{2}t^{1-1}+2\dfrac{-1}{t^2}\\\Rightarrow q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]

(5)By using answers in part (1):

[tex]\dfrac{g'(t)}{f'(t)}=\dfrac{3t^2+4}{4t}=\dfrac{3}{4}t+\dfrac{1}t[/tex]

[tex]q'(t)=\dfrac{1}{2}-\dfrac{2}{t^2}[/tex]

Therefore, it is False that:

[tex]q'(t)=\dfrac{g'(t)}{f'(t)}[/tex]

Answer:

ill give u the answer if u do 73 divided by 2628

Step-by-step explanation:

Answer:

x = 11

Step-by-step explanation:

f(x) = -x + 7

f(x) = -4

Using substitution, -x + 7 = -4

Then you can solve from there

-x + 7 = -4

-x = -11

x = 11

Hope this helps!

(I apologize if I'm incorrect)

Answer:

486 inches is 13.5 yards and 162 inches is 4.5 yards please mark brainlist thank you

Answer:

17.7

Step-by-step explanation:

The tenths place is the very first value after the decimal. The number 17.68694 rounds up to 17.7, because .68 is closer to .7 than it is to .6.

Answer:

a) C) The system has no solutions only when h=3 and k is any real number.

b) D) The system has a unique solution when [tex]h=(-\infty,3)U(3,\infty)[/tex] and k is any real number.

c) The system has may solutions when h=3 and k=15

Step-by-step explanation:

a) In order to determine when the system will have no solution, we can start by solving the equation by substitution. We can solve the first equation for x1:

[tex]x_{1}+hx_{2}=3[/tex]

so

[tex]x_{1}=3-hx_{2}[/tex]

Next we can substitute this into the second equation so we get:

[tex]5(3-hx_{2})+15x_{2}=k[/tex]

We distribute the 5 into the first parenthesis so we get:

[tex]15-5hx_{2}+15x_{2}=k[/tex]

and group like terms:

[tex]-5hx_{2}+15x_{2}=k-15[/tex]

we factor x2 so we get:

[tex]x_{2}(-5h+15)=k-15[/tex]

and solve for x2:

[tex]x_{2}=\frac{k-15}{-5h+15}[/tex]

this final answer is important because it tells us what value the system of equations is not valid for. That answer will not ve vallid if the denominator is zero, so we can set the denominator equal to zero and solve for h, so we get:

[tex]-5h+15= 0[/tex]

and solve for h:

[tex]-5h= -15[/tex]

[tex]h=\frac{-15}{-5}[/tex]

[tex]h= 3[/tex]

so it doesn't really matter what value k gets since all that matters is that the denominator of the answer isn't zero.

b)

For part b we need to know when the system of equations will have infinitely many answers. Generally, this will happen when both equations are basically the same, so we need to make sure to simplify the second equation so it looks like the first equation, compare them and determine the respective coefficients.

So we take the second equation and factor it:

[tex]5x_{1}+15x_{2}=k[/tex]

we start by factoring a 5 from the left side of the equation so we get:

[tex]5(x_{1}+3x_{2})=k[/tex]

Next, we divide both sides of the equation into 5 so we get:

[tex]x_{1}+3x_{2}=\frac{k}{5}[/tex]

we now compare it to the first equation:

[tex]x_{1}+hx_{2}=3[/tex]

[tex]x_{1}+3x_{2}=\frac{k}{5}[/tex]

In this case, every coefficient of the two equations must be the same for us to get infinitely many answers, so we can see that h=3 and [tex]\frac{k}{5}=3[/tex]

when taking the second condition and solving for k we get that:

[tex]k=3(5)[/tex]

so

k=15

Anything else than the specific combination h=3 and k=15 will give us unique solutions, so for b, the answer is:

D) The system has a unique solution when and k is any real number.

c)

We have already solved part c on the previous part of the problem, so the answer is:

The system has many solutions when h=3 and k=15

Answer:

Step-by-step explanation:

ADE=DHG

FEH=IHE

ADE=DHE

ADC=EHI

BEF=IHE <This would be the correct answer if segment CDEF is parallel to segment GHI.

Answer:

true

Step-by-step explanation:

Trust me

Answer:

True

Step-by-step explanation:

2(12)+3(12)=60

24+36=60