Answers
Answer:
(the length of leg)^2=87^2-60^2=3969
so when take the root :
the length of leg=63ft
Related Questions
Suppose X and Y are continuous random variables with joint pdf given by f(x, y) = 24xy if 0 < x, 0 < y, x + y < 1, and zero otherwise.
(a) Are X and Y independent? Why or why not?
(b) Find P(Y > 2X).
(c) Find the marginal pdf of X.
Answers
X and Y are not independent.
P(Y > 2X) = 3/16.
Marginal pdf of X = 12x(1-x)² for 0 < x < 1
Briefly explain about what method is used to answer each part of the question?(a) To determine if X and Y are independent, we need to check if the joint pdf can be factored into the product of the marginal pdfs:
f(x,y) = 24xy if 0 < x, 0 < y, x + y < 1, and zero otherwise.
Marginal pdf of X can be calculated by integrating the joint pdf over the all possible values of y:
f(x) = ∫ f(x,y) dy from 0 to 1-x
= ∫ 24xy dy from 0 to 1-x
= 12x(1-x)² for 0 < x < 1
Similarly, the marginal pdf of Y can be found by integrating the joint pdf over all possible values of x:
f(y) = ∫ f(x,y) dx from 0 to 1-y
= ∫ 24xy dx from 0 to 1-y
= 12y(1-y)² for 0 < y < 1
To check for independence, we need to verify if f(x,y) = f(x)f(y) for all x and y. However, if we multiply the marginal pdfs, we get:
f(x)f(y) = 144xy(1-x)²(1-y)² for 0 < x < 1 and 0 < y < 1
This is not the same as the joint pdf, so X and Y are not independent.
(b) To find P(Y > 2X), we need to integrate the joint pdf over the region where Y > 2X:
P(Y > 2X) = ∫∫ f(x,y) dA over the region where Y > 2X
= ∫∫ 24xy dA over the region where Y > 2X
= ∫∫ 24xy dxdy over the region where 0 < y < 2x and x+y < 1
= ∫[0,1/2] ∫[y/2,1-y] 24xy dxdy
= 3/16
Therefore, P(Y > 2X) = 3/16.
(c) The marginal pdf of X is given by:
f(x) = ∫ f(x,y) dy from 0 to 1-x
= ∫ 24xy dy from 0 to 1-x
= 12x(1-x)² for 0 < x < 1
Same result we get in part (a).
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X and Y are not independent.
P(Y > 2X) = 3/16.
Marginal pdf of X = 12x(1-x)² for 0 < x < 1
Briefly explain about what method is used to answer each part of the question?(a) To determine if X and Y are independent, we need to check if the joint pdf can be factored into the product of the marginal pdfs:
f(x,y) = 24xy if 0 < x, 0 < y, x + y < 1, and zero otherwise.
Marginal pdf of X can be calculated by integrating the joint pdf over the all possible values of y:
f(x) = ∫ f(x,y) dy from 0 to 1-x
= ∫ 24xy dy from 0 to 1-x
= 12x(1-x)² for 0 < x < 1
Similarly, the marginal pdf of Y can be found by integrating the joint pdf over all possible values of x:
f(y) = ∫ f(x,y) dx from 0 to 1-y
= ∫ 24xy dx from 0 to 1-y
= 12y(1-y)² for 0 < y < 1
To check for independence, we need to verify if f(x,y) = f(x)f(y) for all x and y. However, if we multiply the marginal pdfs, we get:
f(x)f(y) = 144xy(1-x)²(1-y)² for 0 < x < 1 and 0 < y < 1
This is not the same as the joint pdf, so X and Y are not independent.
(b) To find P(Y > 2X), we need to integrate the joint pdf over the region where Y > 2X:
P(Y > 2X) = ∫∫ f(x,y) dA over the region where Y > 2X
= ∫∫ 24xy dA over the region where Y > 2X
= ∫∫ 24xy dxdy over the region where 0 < y < 2x and x+y < 1
= ∫[0,1/2] ∫[y/2,1-y] 24xy dxdy
= 3/16
Therefore, P(Y > 2X) = 3/16.
(c) The marginal pdf of X is given by:
f(x) = ∫ f(x,y) dy from 0 to 1-x
= ∫ 24xy dy from 0 to 1-x
= 12x(1-x)² for 0 < x < 1
Same result we get in part (a).
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if f 0 (x) < 0 for 1 < x < 6, then f is decreasing on (1, 6)
Answers
Yes, if f 0 (x) < 0 for 1 < x < 6, then f is decreasing on (1, 6). This is because a function is decreasing on an interval if its derivative is negative on that interval.
Given that f'(x) < 0 for 1 < x < 6, we can conclude that the function f(x) is decreasing on the interval (1, 6).
Here's a step-by-step explanation:
1. f'(x) represents the first derivative of the function f(x) with respect to x.
2. The first derivative f'(x) gives us information about the slope of the tangent line to the curve of the function f(x) at any point x.
3. If f'(x) < 0 for 1 < x < 6, it means that the slope of the tangent line is negative for every x in the interval (1, 6).
4. A negative slope indicates that the function is decreasing at that interval.
So, given the information provided, we can confirm that the function f(x) is decreasing on the interval (1, 6). Since f 0 (x) is the derivative of f(x), if it is negative for 1 < x < 6, then f(x) must be decreasing on that interval.
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Can someone help asap pleaseee
Present the evidence and find the area of the quadrilateral and show your work!
Answers
Check the picture below.
[tex]\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ a=6\\ b=10\\ h=11 \end{cases}\implies A=\cfrac{11(6+10)}{2}\implies A=88[/tex]
HELP! A gardener would like to add to their existing garden to make more flowers available for the butterflies that visit the garden. Her current garden is 20 square feet. If she added another rectangular piece with vertices located at (−18, 13), (−14, 13), (−18, 5), and (−14, 5), what is the total area of the garden?
640 ft2
320 ft2
52 ft2
32 ft2
Answers
Step-by-step explanation:
To find the area of the rectangular piece, we can use the formula:
Area = length x width
We can find the length of the rectangle by calculating the difference between its two x-coordinates:
Length = |-14 - (-18)| = 4 ft
We can find the width of the rectangle by calculating the difference between its two y-coordinates:
Width = |13 - 5| = 8 ft
Therefore, the area of the rectangular piece is:
Area = 4 ft x 8 ft = 32 ft^2
To find the total area of the garden, we need to add the area of the existing garden (which is given as 20 square feet) to the area of the new rectangular piece:
Total area = 20 ft^2 + 32 ft^2 = 52 ft^2
Therefore, the total area of the garden is 52 square feet. The answer is 52 ft^2.
Identify the formula for the margin of error for the estimate of a population mean when the population standard deviation is unknown. Choose the correct answer below. A. E=x+tα/2 s/√n OB. E= s/√n OC. E=x-tα/2 s/√n OD. E=tα/2 s/√n
Answers
Answer:
D is the correct answer
Step-by-step explanation:
The correct formula for the margin of error for estimating a population mean when the population standard deviation is unknown is E = tα/2 × s/√n.
Step 1: The margin of error (E) is a measure of the uncertainty or variability associated with estimating a population mean from a sample.
Step 2: The formula for the margin of error involves three key components:
The critical value (tα/2) from the t-distribution, which depends on the desired level of confidence (α) and the sample size (n). The critical value represents the number of standard errors away from the mean at which the confidence interval will be constructed.
The sample standard deviation (s), which is an estimate of the population standard deviation based on the sample data. Since the population standard deviation is unknown, we use the sample standard deviation as an approximation.
The square root of the sample size (√n), which accounts for the variability of the sample mean.
Step 3: The critical value (tα/2) is chosen based on the desired level of confidence. For example, if we want a 95% confidence interval, the value of α is 0.05, and we would look up the corresponding critical value for a two-tailed t-distribution with n-1 degrees of freedom.
Step 4: Once we have the critical value, we multiply it by the sample standard deviation (s) divided by the square root of the sample size (√n) to obtain the margin of error (E).
Therefore, the correct formula for the margin of error for estimating a population mean when the population standard deviation is unknown is E = tα/2 × s/√n.
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Larry has two pieces of wire. • One piece is 72 cm long and the other piece is 56 cm long. • He wants to cut the wires into pieces all the same length without any remaining. What is the longest possible cut of wire Larry can have?
Answers
To rephrase the question, we need to find the highest common factor of 72 and 56.
72 = 2^3 x 3^2
56 = 7 x 2^3
So, the highest common factor of 72 and 56 is 2^3, or 8.
Therefore, the longest possible cut of wire Larry can have is 8cm.
Answer:
I don’t know the answer
Step-by-step explanation:
A research hypothesis is that the variance of stopping distances of automobiles on wet pavement is substantially greater than the variance of stopping distances of automobiles on dry pavement. In the research study, 16 automobiles traveling at the same speeds are tested for stopping distances on wet pavement and then tested for stopping distances on dry pavement. On wet pavement, the standard deviation of stopping distances is 32 feet. On dry pavement, the standard deviation is 16 feet. a. At a 5% significance level, do the sample data justify the conclusion that the variance in stopping distances on wet pavement is greater than the variance in stopping distances on dry pavement? (Hint: construct a 5-steps hypothesis test using the critical value approach.) What are the implications of your statistical conclusions in terms of driving safety recommendations?
Answers
State the null and alternative hypotheses, determine the level of significance, Calculate the test statistic also determine the critical value.
Define the driving safety recommendations?Step 1: Express the invalid and elective speculations,
The invalid speculation is that the change of halting distances on wet asphalt is equivalent to or not exactly the fluctuation of halting distances on dry asphalt.
H0: σ2(wet) ≤ σ2(dry)
The other possibility is that the variance of stopping distances on wet pavement is greater than that on dry pavement.
Ha: σ2(wet) > σ2(dry)
Step 2: Choose the appropriate test and determine the significance level,
The level of significance is 5%. Since we are comparing two variances of normally distributed populations, we will use the F-test.
Step 3: Calculate the test statistic,
The F-test measurement is determined as the proportion of the example differences:
F = s2(wet)/s2(dry)
where s2(wet) and s2(dry) are the sample variances of stopping distances on wet and dry pavement, respectively.
F = 32²/16² = 4
Step 4: Determine the critical value
The critical value for the F-test with 15 and 15 degrees of freedom (16-1 and 16-1) at a 5% level of significance is 2.54 (from F-tables).
Step 5: Settle on a choice and decipher the outcomes,
Since the calculated F-value of 4 is greater than the critical value of 2.54, we reject the null hypothesis. We can conclude that the variance of stopping distances on wet pavement is greater than the variance of stopping distances on dry pavement.
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Find the area of the circle. Round your
answer to the nearest tenth.
1.
4 cm
2.
12 m
Answers
Answer:
50.3 cm²113.1 m²Step-by-step explanation:
You want the areas of two circles, one with radius 4 cm, the other with diameter 12 m.
AreaThe area of a circle is given by the formula ...
A = πr²
The radius (r) is half the diameter, so the second circle's radius is 6 m.
1) 4 cmThe area is ...
π(4 cm)² = 16π cm² ≈ 50.3 cm²
2) 6 mThe area is ...
π(6 m)² = 36π m² ≈ 113.1 m²
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show that a countably infinite number of guests arriv- ing at hilbert’s fully occupied grand hotel can be given rooms without evicting any current guest.
Answers
The countably infinite number of guests can be accommodated by moving each current guest to the next room number (i.e., guest in room 1 moves to room 2, guest in room 2 moves to room 3, and so on) and then assigning the newly arrived guests to the vacated rooms (i.e., guest 1 goes to room 1, guest 2 goes to room 2, and so on).
This way, every guest still has a room and no one is evicted.
The solution to this problem relies on the fact that the set of natural numbers (which is countably infinite) can be put into one-to-one correspondence with the set of positive even numbers (also countably infinite).
This means that each current guest can be moved to the next room number without any gaps or overlaps, and the newly arrived guests can be assigned to the vacated rooms in the same manner.
The concept of one-to-one correspondence is fundamental to understanding countability and infinite sets, and it plays a key role in many mathematical proofs and arguments.
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Use the graphs to identify the following: axis of symmetry, x-intercept(s), y-intercept, & vertex.
Determine the interval in which the function is positive.
Question 4 options:
(1.5, ∞)
(-∞, 1.5)
(-∞, -1) or (4, ∞)
(-1, 4)
Answers
Answer:
axis of symmetry=(1.5,6.5)
x intercept= (-1,1.5)
y intercept=(4,0)
United Bank offers a 15-year mortgage at an APR of 6.2%. Capitol Bank offers a 25-year mortgage at an APR of 6.5%. Marcy wants to borrow $120,000.
a. What would the monthly payment be from United Bank?
b. What would the total interest be from United Bank? Round to the nearest ten dollars.
c. What would the monthly payment be from Capitol Bank?
d. What would the total interest be from Capitol Bank? Round to the nearest ten dollars.
e. Which bank has the lower total interest, and by how much?
f. What is the difference in the monthly payments?
g. How many years of payments do you avoid if you decide to take out the shorter mortgage?
Answers
If United Bank offers a 15-year mortgage at an APR of 6.2%.
a. Monthly Payment is $1,025.90
b. Total Interest is $64,662
c. Monthly Payment $810.55
d. Total Interest is $123,165
e. Difference in the monthly payments is $215.35.
f. You could save 10 years of payments
What is the monthly payment?Using this formula to find the monthly payment
Monthly Payment = P * (r * (1 + r)^n) / ((1 + r)^n - 1)
Total Interest = (Monthly Payment * n) - P
where
P= principal amount borrowed
r = monthly interest rate (APR / 12)
n = total number of monthly payments
a. United Bank Monthly payment
P = $120,000
r = 6.2% / 12 = 0.00517
n = 15 years * 12 months/year = 180
Monthly Payment = 120000 * (0.00517 * (1 + 0.00517)^180) / ((1 + 0.00517)^180 - 1)
Monthly Payment = $1,025.90
b. United Ban Total interest
Total Interest = ($1,025.90* 180) - 120000
Total Interest = $64,662
c. Capitol Bank Monthly payment
P = $120,000
r = 6.5% / 12 = 0.00542
n = 25 years * 12 months/year = 300
Monthly Payment = 120000 * (0.00542 * (1 + 0.00542)^300) / ((1 + 0.00542)^300 - 1)
Monthly Payment = $810.55
d. Capitol Bank Total interest
Total Interest = (810.55 * 300) - 120000
Total Interest = $123,165
e. Capitol Bank has the higher total interest by $58,503 ( $123,165 - $64,662).
f. The difference in the monthly payments is:
$1025.90 - $810.55= $215.35.
g. You could save 10 years of payments if you took up a 15-year mortgage as opposed to a 25-year mortgage.
Therefore the Monthly Payment is $1,025.90.
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. In How many way a committee 3 professors and 2 instructors be chosen from 6 professors and 8 instructors if the committee consists at least one professor?
Answers
In total 560 ways a committee of 3 professors and 2 instructors can be chosen from 6 professors and 8 instructors if the committee consists of at least one professor.
What is combination?Combinations are used to calculate the total number of possible outcomes from a given set of items.
The total number of possibilities of selecting a committee of 3 professors and 2 instructors from 6 professors and 8 instructors is calculated using the combination formula:
Number of ways of selecting a committee=
{Number of ways of selecting 3 professors from 6 professors} X {Number of ways of selecting 2 instructors from 8 instructors}
= (6C3) X (8C2)
= (6!/(3!*3!)) X (8!/(2!*6!))
= 20 X 28
= 560
Therefore, in total 560 ways a committee of 3 professors and 2 instructors can be chosen from 6 professors and 8 instructors if the committee consists of at least one professor.
From this sample space, 3 professors and 2 instructors are required to be selected for the committee. Therefore, the combination formula is used to calculate the total number of ways of selecting the committee in which the order of the members doesn't matter.
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Josiah begins his shopping at the music store. He finds the CD he wants and it has a price sticker that reads $15.99. The tax rate for the city is 8.25%. How much will Josiah pay for the CD? Round your answer to the nearest cent.
Answers
Sales tax = 8.25% of $15.99
Sales tax = (8.25/100) x $15.99
Sales tax = $1.32 (rounded to the nearest cent)
So the total cost for Josiah to purchase the CD is:
Total cost = Price of CD + Sales tax
Total cost = $15.99 + $1.32
Total cost = $17.31
Therefore, Josiah will pay $17.31 for the CD.
Uh- ;-; I- Wh- Idek what i'm doing anymore :,)
Answers
36/9=4
Perimeter: 26 meters
4+4+9+9=26 meters
Answer:
4 and 26
Step-by-step explanation:
If the area is 36 and the length is 9 that means that the width is 4 because if we multiply 9 by 4 we get 36.
The perimeter is just adding 4 + 4 + 9 + 9 = 26
Hope this helps :)
Pls brainliest...
Assume x and y are functions of t. Evaluate dy/dt for 3xy-4x+6y^3= -108
with the conditons dx/dt=-12, x=6, y=-2
dy/dt=
Answers
your answer :- the value of dy/dt is 28/3.
To find dy/dt, we need to take the derivative of both sides of the equation 3xy-4x+6y^3= -108 with respect to t:
d/dt(3xy-4x+6y^3) = d/dt(-108)
Using the product rule and chain rule, we get:
3x(dy/dt) + 3y(dx/dt) - 4(dx/dt) + 18y^2(dy/dt) = 0
Substituting the given values of dx/dt, x, and y, we get:
3(6)(dy/dt) + 3(-2)(-12) - 4(-12) + 18(-2)^2(dy/dt) = 0
Simplifying and solving for dy/dt, we get:
18dy/dt - 24 - 72 - 72 = 0
18dy/dt = 168
dy/dt = 168/18
dy/dt = 28/3
Therefore, the value of dy/dt is 28/3.
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Of 18 students want to share 2 bags of chips equally which fraction represents the amount of Chip's each student should receive
Answers
The fraction that represents the amount of chips each student should receive is 1/9 or 2/18. (Option 4)
The problem states that 18 students want to share two bags of chips equally. Therefore, we need to divide the chips into 18 equal parts to find the amount each student should receive. We can represent this as:
2 bags of chips = 18 equal parts
To find the fraction of chips each student should receive, we need to divide the total number of parts (18) by the number of students (18):
18 parts ÷ 18 students = 1 part/student
Therefore, each student should receive 1 part out of the 18 total parts. We can express this as a fraction:
1 part/18 parts = 1/18
Since we have two bags of chips, each containing 1/18 of the total chips, we can add them together to get the total amount of chips each student should receive:
1/18 + 1/18 = 2/18
Simplifying this fraction, we get:
2/18 = 1/9
Therefore, each student should receive 1/9 of the total chips.
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Complete Question:
A class of 18 students wants to share two bags of chips equally. Which fraction represents the amount of chips each student should receive?
18/216/218/162/18draw your own circle and illustrate the following
Answers
In the image below, Center A is located at the center of the circle and is marked by a red dot.
What is Circle?Circle is a two-dimensional geometric figure that consists of all points in a plane that are at a given distance from a given point, the centre. A circle is a simple closed shape in Euclidean geometry. It is the set of all points in a plane that are at the same distance from its centre. A circle can be defined as the locus of a point moving at a constant distance from a fixed point. It is one of the most basic shapes in geometry. It is also known as a circular arc, a closed curve, and a simple closed curve. Circular shapes are used in many areas of design, from logos to furniture.
Diameter DE is marked with a dashed line and is the longest line that can be drawn within the circle, extending from point D to point E. Radius AC is marked with a solid line, extending from point A to point C. Central angle PAC is marked by the red arc and is the angle between points P and A. Lastly, tangent OB is marked with a dotted line and is a straight line that touches the circle at only one point (point B). This line is perpendicular to the radius AC.
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complete questions as follows-
Draw your own circle and illustrate the following:
1. Center A
2. Diameter DE
3. Radius AC
4. Central angle PAC
5. Tangent OB
If j is inversely related to the cube of k, and j = 3 when k is 6, which of the following is another
possible value for j and k?
(A) j = 18, k = 2
(B) j = 6, k = 3
(C) j = 81, k = 2
(D) j = 2, k = 81
(E) j = 3, k = 2
Answers
The relationship between j and k can be expressed as j = k^(-3) * C, where C is a constant. To find the value of C, we can use the initial condition j = 3 when k = 6:
3 = 6^(-3) * C
C = 3 * 6^3 = 648
So the relationship is j = 648 / k^3. To find another possible value for j and k, we can simply plug in a different value for k:
For option A:
j = 648 / 2^3 = 81
For option B:
j = 648 / 3^3 = 24
For option C:
j = 648 / 2^3 = 81
For option D:
j = 648 / 81^3 = 0.0008
For option E:
j = 648 / 2^3 = 81
Therefore, the only option that is another possible value for j and k is (A) j = 18, k = 2.
Use the Laplace transform to solve the given initial-value problem.
y"-9y+ 20y=u(t-1), y(0) = 0, y'(0) = 1
Answers
The solution to the initial-value problem is y(t) = u(t-1)( [tex]e^5^(^t^-^1^)[/tex] - [tex]e^-^4^(^t^-^1^)[/tex] + sin(3(t-1))), which satisfies both the differential equation and the initial conditions.
Using the Laplace transform, we can solve the initial-value problem y"-9y+20y=u(t-1) with y(0)=0 and y'(0)=1. T
aking the Laplace transform of both sides and simplifying, we get Y(s) = (1/s² + 9s - 20)(1/ [tex]e^s[/tex] ). Using partial fractions, we can write this as Y(s) = (1/(s-5)) - (1/(s+4)) + (1/s² + 9s).
Taking the inverse Laplace transform and using the shift theorem, we get y(t) = u(t-1)( [tex]e^5^(^t^-^1^)[/tex] - [tex]e^-^4^(^t^-^1^)[/tex] + sin(3(t-1))). Therefore, the solution to the initial-value problem is y(t) = u(t-1)( [tex]e^5^(^t^-^1^)[/tex] - [tex]e^-^4^(^t^-^1^)[/tex] + sin(3(t-1))), where u(t-1) is the unit step function.
The Laplace transform is a powerful tool in solving initial-value problems in differential equations. By taking the Laplace transform of both sides, we can transform the differential equation into an algebraic equation, which is easier to solve.
In this case, we used partial fractions to simplify the Laplace transform and then used the inverse Laplace transform to find the solution to the initial-value problem.
The shift theorem was used to incorporate the initial condition y(0)=0.
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26. A Risk Taker (decision maker) would choose the project with a. The highest Coefficient of Variation b. The highest Expected Value c. The highest Standard Deviation d. The lowest Coefficient of Variation e. The lowest Standard Deviation
Answers
A Risk Taker (decision maker) would choose the project with a. The highest Coefficient of Variation.
What is Coefficient of Variation (CV)?The Coefficient of Variation (CV) measures the risk per unit of return, and a higher CV indicates a higher degree of risk. A risk taker is someone who is willing to take on more risk for the potential of higher rewards, so they would choose the project with the highest CV.
A risk taker, also known as a decision maker who is willing to accept higher risks for potentially higher rewards, would likely choose the project with the highest expected value, regardless of the coefficient of variation or standard deviation.
The expected value represents the average outcome of the project, taking into account both the probability and magnitude of each possible outcome.
However, it's important to note that a higher CV also means a higher chance of loss, so the decision should be made after careful consideration of all factors.
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Find sin 2x, cos 2x, and tan 2x from the given information. sin x = -5/13, x in Quadrant III sin 2x = cos 2x= tan 2x = Find sin 2x, cos 2x, and tan 2x from the given information. tanx= -1/4 , cosx > 0 sin 2x = cos 2x = Tan 2x = Find sin 2x, cos 2x, and tan 2x from the given information. sin x = 5/13, x in Quadrant I sin 2x = cos 2x= tan 2x = Find sin 2x, cos 2x, and tan 2x from the given information. sin x = 5/13, csc x < 0 sin 2x = cos 2x= tan 2x = If we know the values of sin x and cos x, we can find the value of sin 2x by using the Double-Angle Formula for Sine. State the formula: sin2x= If we know the value of cos x and the quadrant in which x/2 lies, we can find the value of sin (x/2) by using the Half-Angle Formula for Sine. State the formula: sin(x/2) = +-
Answers
For each given set of information:
1)sin x = -5/13, x in Quadrant III
sin 2x = -0.96, cos 2x = 0.28, tan 2x = -3.42
2)tan x = -1/4, cos x > 0
sin 2x = -0.48, cos 2x = 0.88, tan 2x = -0.55
3)sin x = 5/13, x in Quadrant I
sin 2x = 0.87, cos 2x = 0.48, tan 2x = 1.81
4)sin x = 5/13, csc x < 0
sin 2x = -0.87, cos 2x = 0.48, tan 2x = -1.81
The Double-Angle Formula for Sine is: sin 2x = 2sin x cos x.
The Half-Angle Formula for Sine is: sin(x/2) = ±√[(1 - cos x) / 2].
Since sin x = -5/13 and x is in Quadrant III, we know that cos x is negative. We can use the formula for sin 2x to find sin 2x = 2sin x cos x = 2(-5/13)(-12/13) = -0.96. Similarly, we can find cos 2x = cos²x - sin²x = (12/13)² - (-5/13)² = 0.28, and tan 2x = sin 2x / cos 2x = -3.42.
We know that tan x = -1/4 and cos x > 0. Using the Pythagorean identity, we can find sin x = √(1 - cos²x) = √(1 - (16/17)²) = -5/17 (since x is in Quadrant IV, sin x is negative). Using the formula for sin 2x, we can find sin 2x = 2sin x cos x = 2(-5/17)(16/17) = -0.48.
Similarly, we can find cos 2x = cos²x - sin²x = (16/17)² - (-5/17)² = 0.88, and tan 2x = sin 2x / cos 2x = -0.55.
Since sin x = 5/13 and x is in Quadrant I, we know that cos x is positive. Using the formula for sin 2x, we can find sin 2x = 2sin x cos x = 2(5/13)(12/13) = 0.87. Similarly, we can find cos 2x = cos²x - sin²x = (12/13)² - (5/13)² = 0.48, and tan 2x = sin 2x / cos 2x = 1.81.
Since sin x = 5/13 and csc x < 0, we know that x is in Quadrant IV. Using the formula for sin 2x, we can find sin 2x = 2sin x cos x = 2(5/13)(-12/13) = -0.87. Similarly, we can find cos 2x = cos²x - sin²x
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John recorded the weight of his dog Spot at different ages as shown in the scatter plot below. t (in pounds) 50 45 40 35 30 25 Spot's Weight X
a50
b27
c32
d36
Answers
An equation that would describe the line of best fit is
Using the line of best fit, a prediction of Spot's weight after 18 months is 35 pounds.
How to find an equation of the line of best fit for the data?In order to determine a linear equation for the line of best fit (trend line) that models the data points contained in the graph, we would use the point-slope equation:
y - y₁ = m(x - x₁)
Where:
x and y represent the data points.m represent the slope.First of all, we would determine the slope of this line;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (20 - 5)/(10 - 2)
Slope (m) = 15/8
Slope (m) = 1.875
At data point (2, 5) and a slope of 1.875, a linear equation for the line of best fit can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 5 = 1.875(x - 2)
y = 1.875x + 1.25
When x = 18, the weight is given by:
y = 1.875(18) + 1.25
y = 35 pounds.
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Complete Question:
John recorded the weight of his dog Spot at different ages as shown in the scatter plot below.
Part A:
Write an equation that would describe the line of best fit.
Part B:
Using the line of best fit, make a prediction of Spot's weight after 18 months.
(1)
Let f be the function defined x^3 for x< or =0 or x for x>o. Which of the following statements about f is true?
(A) f is an odd function
(B) f is discontinuous at x=0
(C) f has a relative maximum
(D) f ‘(x)>0 for x not equal 0
(E) none of the above
Answers
Let f be the function defined x^3 for x< or =0 or x for x>o.
The correct answer is (D) f ‘(x)>0 for x not equal 0.
statements are false because:
(A)f is an odd function
f is not an odd function because f(-x) does not equal -f(x) for all x.
(B) f is discontinuous at x=0
f is continuous at x=0
because the limit of f as x approaches 0 from the left is 0 and the limit of f as x approaches 0 from the right is also 0, and these limits are equal to f(0)=0.
(C) f has a relative maximum
f does not have a relative maximum because f(x) increases as x increases for x>0 and decreases as x decreases for x<0, but there is no point where f(x) is greater than all nearby values of f.
(D) f ‘(x)>0 for x not equal 0
f ‘(x) = 3x^2 for x<0 and 1 for x>0, which is greater than 0 for all x not equal to 0.
(E) This statement is not true because (D) is true.
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Let f be the function defined x^3 for x< or =0 or x for x>o.
The correct answer is (D) f ‘(x)>0 for x not equal 0.
statements are false because:
(A)f is an odd function
f is not an odd function because f(-x) does not equal -f(x) for all x.
(B) f is discontinuous at x=0
f is continuous at x=0
because the limit of f as x approaches 0 from the left is 0 and the limit of f as x approaches 0 from the right is also 0, and these limits are equal to f(0)=0.
(C) f has a relative maximum
f does not have a relative maximum because f(x) increases as x increases for x>0 and decreases as x decreases for x<0, but there is no point where f(x) is greater than all nearby values of f.
(D) f ‘(x)>0 for x not equal 0
f ‘(x) = 3x^2 for x<0 and 1 for x>0, which is greater than 0 for all x not equal to 0.
(E) This statement is not true because (D) is true.
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in how many years the profit of 10,000 Willbe tk 7500 in 12½% rate of profit
Answers
It will take "6 years" for the sum of 10000 to generate an interest of 7500 at the simple interest rate of 12.5% per annum.
The "Simple-Interest" is a type of interest that is calculated as a fixed percentage of the principal amount for each period of time.
We use the formula for simple interest to find the time;
⇒ Simple Interest = (Principle × Rate × Time) / 100, where Principle is = initial sum, Rate is = interest rate per annum, and Time = time period for which interest is calculated,
In this case, we have:
Principle = 10000
Rate = 12.5%
Simple Interest = 7500
Substituting the values,
We get,
⇒ 7500 = (10000 × 12.5 × Time)/100,
⇒ 7500 = 1250 × Time,
⇒ Time = 6,
Therefore, the time taken is 6 years.
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The given question is incomplete, the complete question is
In how many years the sum of 10000 will generate an interest of 7500 at the simple interest-rate of 12.5% per annum?
can can you please solve it and tell me how you did thank you
Answers
A linear equation that best represent the given data is: A. y = 4.6x + 26.5.
How to determine the line of best fit?In this scenario, the number of times fertilized would be plotted on the x-axis (x-coordinate) of the scatter plot while the yield of crop per acre would be plotted on the y-axis (y-coordinate) of the scatter plot through the use of Microsoft Excel.
On the Microsoft Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display a linear equation for the line of best fit (trend line) on the scatter plot.
From the scatter plot (see attachment) which models the relationship between the number of times fertilized and the yield of crop per acre, a linear equation for the line of best fit is given by:
y = 4.6x + 26.5
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let x1 = 18, x2 = 10, x3 = 7, x4 = 5, and x5 = 11. find sd2.
a. 15.1
b. 18.3
c. 20.2
d. 24.7
Answers
The sd2 is 19.76 ( not listed ).
To find sd2 (the standard deviation squared) for the data set x1 = 18, x2 = 10, x3 = 7, x4 = 5, and x5 = 11, follow these steps:
1. Calculate the mean: (18 + 10 + 7 + 5 + 11) / 5 = 51 / 5 = 10.2
2. Calculate the squared deviations from the mean: (18 - 10.2)^2 = 60.84, (10 - 10.2)^2 = 0.04, (7 - 10.2)^2 = 10.24, (5 - 10.2)^2 = 27.04, (11 - 10.2)^2 = 0.64
3. Calculate the average of squared deviations: (60.84 + 0.04 + 10.24 + 27.04 + 0.64) / 5 = 98.8 / 5 = 19.76
The sd2 (standard deviation squared) for the given data set is 19.76, which is not listed among the given options (a. 15.1, b. 18.3, c. 20.2, d. 24.7).
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Problema Matemático:
Carlos entrena en el gimnasio por la mañana de las
07:20 a las 09:55 y en la tarde de las 18:05 hasta la
19:40 horas. ¿Cuántos minutos entrena Carlos c
día?
Answers
Answer:
Para calcular la cantidad de minutos que Carlos entrena cada día, necesitamos sumar el tiempo que pasa en el gimnasio por la mañana y por la tarde, en minutos.
Por la mañana, Carlos entrena desde las 07:20 hasta las 09:55. Para calcular el tiempo en minutos, podemos restar los minutos de inicio (20) de los minutos de final (55) en la hora de inicio (07), y luego multiplicar el resultado por 60 (porque hay 60 minutos en una hora). Así:
(09 - 07) horas x 60 minutos/hora + (55 - 20) minutos = 2 x 60 + 35 minutos = 120 + 35 minutos = 155 minutos
Por la tarde, Carlos entrena desde las 18:05 hasta las 19:40. Podemos hacer el mismo cálculo:
(19 - 18) horas x 60 minutos/hora + (40 - 05) minutos = 1 x 60 + 35 minutos = 60 + 35 minutos = 95 minutos
Entonces, en total, Carlos entrena 155 minutos por la mañana y 95 minutos por la tarde, lo que suma un total de 250 minutos al día.
pls help! i’m in desperate need
Answers
Explanation: the area is 25pi, and since the area of a circle is pi(r^2), r^2=25 therefore r =5. Since this is asking for diameter and diameters are twice the value of radii, the diameter is 10in. (5 times 2)
SEE THE ATTACHED DOCUMENTS AND ANSWER
Answers
The angle between AFE is measured (A) 42°.
How to determine angles?Since ΔABC is an equilateral triangle, all its angles are 60°. Since CAD-18°,: ∠CAE = ∠CAD + ∠DAE = 18° + 60° = 78°.
Since AC is the angle bisector of ∠BCD,:
∠ACB = ∠ACD = (1/2)∠BCD. Since ΔABC is equilateral, ∠BCA = 60°.
Therefore, ∠BCD = ∠BCA + ∠ACB = 60° + (1/2)∠BCD, which implies that ∠ACB = 30°.
Since BE- CD,:
∠BEC = ∠BCD - ∠CED = ∠ACB - ∠CED = 30° - ∠CED.
Since ∠CAF = 12°,:
∠BAC = ∠CAD + ∠DAF = 18° + 12° = 30°.
Therefore, ∠BCA = 30°, and BC = AC.
Let x = ∠CED. Since BE = CD and BC = AC,: CE = AD = BC = AC.
In ΔCED,: ∠ECD = 180° - ∠CED - ∠CDE = 180° - x - 60° = 120° - x.
In ΔCAD,: ∠CAD + ∠CDA + ∠ACD = 180°, which implies that ∠CDA = 60° - (1/2)∠CAD = 60° - 9° = 51°.
In ΔADF,: ∠ADF = 180° - ∠BAC - ∠DAF = 180° - 30° - 12° = 138°.
In ΔAFE,: ∠AFE = ∠ACB + ∠BEC + ∠CED + ∠ECD + ∠CDA + ∠ADF = 30° + (180° - 30° - x) + x + (120° - x) + 51° + 138° = 489° - x.
Since the angles of a triangle sum to 180°:
∠AFE + ∠EAF + ∠AEF = 180°
∠AFE + 60° + 78° = 180°
∠AFE = 42°.
Therefore, the answer is (A) 42°.
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In the data set below, 19 is an outlier: 19, 8, 7, 5, 4, 9, 2, 5, 8, 6 true or false
Answers
Answer:
True.
In the data set 19, 8, 7, 5, 4, 9, 2, 5, 8, 6, the value 19 is an outlier. An outlier is a data point that is significantly different from the rest of the data points in a set. In this case, the value 19 is much higher than the other values in the set. This could be due to a number of factors, such as a data entry error or a genuine outlier.
There are a number of ways to identify outliers. One common method is to use the interquartile range (IQR). The IQR is the difference between the third and first quartiles of a data set. A data point that is more than 1.5 times the IQR above the third quartile or below the first quartile is considered to be an outlier.
In this case, the value 19 is more than 1.5 times the IQR above the third quartile. Therefore, it is considered to be an outlier.
Outliers can be removed from a data set, or they can be left in. Removing outliers can sometimes improve the accuracy of statistical analysis, but it is important to be careful not to remove too many data points. Leaving outliers in can sometimes make the data set more difficult to analyze, but it can also provide useful information about the data.
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
Outliers are numbers far from the rest of the numbers.