A proton is traveling to the right at 2.0x 10^7m/s. It has a head-on perfectly elastic collision with a carbon atom. The mass of the carbon atom is 12 times the mass of the proton. What are the speeds of each after the collision? What is the direction of the proton after the collision? (up/down,left/right) What is the direction of the carbon atom after the collision? (up/down,left/right)
The speeds and the direction of each after the collision:
The proton = -1.692 x 10⁷m/s to the left.
The carbon = 0.3076 x 10⁷ m/s to the right.
The law of conservation of momentumIf there are two object each with masses m₁ and m₂ move with speed v₁ and v₂, then the two objects collide, so after colliding the speed of each object becomes v₁’ and v₂'.
Since there are no external forces acting on the system, then the momentum of the system is conserved, meaning the momentum before and after the same collision.
The equation is:
(m₁)(v₁) + (m₂)(v₂) = (m₁v₁)' + (m₂v₂)'
We have,
velocity of the proton = 2.0 x 10⁷ m/s ⇒ v₁
Mass of the proton = m₁
The velocity of a carbon atom = 0 ⇒ v₂
The mass of the carbon atom = 12 m₁
So, the speeds of proton after the collision:
(m₁)(v₁) + (m₂)(v₂) = (m₁v₁)' + (m₂v₂)'
v₁’ = (m₁ - m₂) / (m₁ + m₂) (v₁)
= (m₁ - 12m₁) / (m₁ + 12m₁) (2.0 x 10⁷)
= (-11 m₁) / (13m₁) (2.0 x 10⁷)
= -1.692 x 10⁷m/s ⇒ it's negative, so to the left.
Now, the speed of the carbon atom after collision:
V₂’ = (2m₁) / (m₁ + m₂)v₁
= 2/13 (2 x 10⁷)
= 0.3076 x 10⁷ m/s ⇒ it's positive, so to the right.
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a 0.950-kg ball is dropped from rest at a point 3.30 m above the floor. the ball rebounds straight upward to a height of 1.90 m. taking the negative direction to be downward, what is the impulse of the net force applied to the ball during the collision with the floor?
The impulse of is the product of the average force and the duration it is excreted. The impulse of the net force exerted to the ball during the impact with the floor was 4.28 N-s in magnitude and direction.
The ball weighs 0.500 kg, according to the information provided.
The floor is 1.2 meters high.
The force of impulse
The impulse of is the product of the average force and the duration it is excreted.
One instant before the collision, the velocity is 4.852 meters per second.
One instant after the collision with the floor, the velocity was 3.71 meters per second squared.
The magnitude and direction of the ball's net force impulse during the collision with the floor.
4.28N-s.
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need help with the answer
a car starting from rest has a constant acceleration of 4 m/s2. how fast will it be going in 5 seconds? group of answer choices 20 m/s 4 m/s 5 m/s 1.25 m/s
The car will be going with the speed of 20m/s in 5 seconds.
It is provided that a car is starting from the rest and has a constant acceleration of 4m/s².
The time taken by the car during its motion is 5 seconds.
Using the first equation of motion,
V = U+at
Where,
V is the final velocity,
U is the initial velocity
a is the acceleration and,
t is the time taken by the car during the motion.
Now, putting all the values accordingly,
V = 4 × 5
V = 20 m/s.
So, the car will be going at a speed of 20m/s in 5 seconds.
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a 2.55 kg bucket of sand is attached to a 1.31 m long rope and is swung in a vertical circle. at the bottom of the circle the tension in the rope is 30.2 n. what is the speed of the bucket of sand at the bottom of the circle?
Answer: v = 1.64 m/s
Explanation:
Fc = (m * v^2)/r
v = [tex]\sqrt{(r * Fc) / m}[/tex]
v = sqrt((1.31m * (30.2 N - (2.55kg * 9.8 m/s^2))) / 2.55 kg)
v = 1.64 m/s
determine the average rate of change in concentration of b from t=0 s to t=252 s.
The average rate of change in concentration is calculated to be 0.00404 M/s.
Average rate of change is described as (change in concentration)/(change in time).
Given the concentrations of the reactant (A), we may first determine the average change in A.
Change in A = 0.14 - 0.395 = -0.51 M
Average rate = -0.51 M/252 s = -0.00202 M/s
The negative sign indicates the decreasing [A] over time.
The stoichiometry of the equation, which states that two Bs are produced for every A utilised, is used to determine the average rate of change of B.
So, average rate of change of B is 2 × 0.00202 = 0.00404 M/s
The question is incomplete. The complete question is 'A → 2B
Time(s) Concentration of A (M)
0. 0.65
126. 0.395
252. 0.140'
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a small metal spherex is charged by losing 500 electrons. an identical metal spherey is chargedby gaining 1000 electrons.thetwospheres are first put in contact with each other andthen separated. if is the charge on an electron,what is the charge on each sphere afterseparation?
After separation, each sphere will have a charge of 250e, which is equal to the total excess charge that was transferred between the two spheres.
After sphere x loses 500 electrons, it becomes negatively charged, with a charge of -500e, where e is the charge on an electron. After sphere y gains 1000 electrons, it becomes positively charged, with a charge of 1000e.
When the two spheres are put in contact with each other and then separated, they will transfer some of their excess charges to each other until they are both neutralized. This means that sphere x will lose some of its excess electrons to sphere y, and sphere y will gain some of the electrons that sphere x loses.
The total charge of the two spheres after separation will be the sum of the charges on each sphere. Therefore, the charge on sphere x after separation will be (-500e + 1000e) / 2 = 250e, and the charge on sphere y after separation will be (-500e + 1000e) / 2 = 250e.
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a car pulls away from a stop sign with a constant acceleration. after traveling 10 m, its speed is 5 m/s. what will its speed be after traveling 40 m?
Speed be after traveling 40 m is 10 m/s.
From kinetic equation we will have
[tex]Vf^{2}[/tex] - [tex]Vi^{2}[/tex] = 2ad
5² - Vi² = 2a × 10
after 40m distance
[tex]Vf^{2}[/tex] - [tex]Vi^{2}[/tex] = 2a × 40
here let say it start from rest
vi = 0
5² - 0 = 2a × 10
[tex]Vf^{2}[/tex] - 0 = 2a × 40
divide the two equation
[tex]Vf^{2}[/tex] /25 = 2a ×40 / 2a × 10
Vf = 10 m/s
The rate at which an object moves in relation to a reference point is measured as its speed. It is regarded as a magnitude or scalar quantity and has no direction. The formula: can be used to calculate speed.
Speed equals Distance/Time.
Average Speed - The average speed of an object is determined by the distance it covered in a predetermined amount of time. A car's average speed over the period of an hour if it traveled 50 miles is 50 mph. The car may have experienced instantaneous speeds between 40 and 60 mph throughout that time, but its average speed was 50 mph.
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the perfect order measures how effectively logistics serves the customer while the landed cost measures how efficiently logistics provides that service.a) trueb) false
AutoLFADS is a framework for large-scale neural network training for generalised estimate of single-trial population dynamics.
What is neural network ?
Deep learning techniques are based on neural networks, sometimes referred to as artificial neural networks (ANNs) or simulated neural networks (SNNs), which are a subset of machine learning. Their structure and nomenclature are modelled after the human brain, mirroring the communication between organic neurons.
Deep neural network of population dynamics models require considerable hyperparameter adjustment for each dataset to function at the cutting edge. Without using behavioural or task information, AutoLFADS is a model-tuning framework that generates high-performing autoencoding models automatically using data from a range of brain regions and activities.
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Pellets of mass 2.0 g are fired in parallel paths with speeds of 120 m/s through a hole 1.5 mm in diameter.How far from the hole must you be to detect a 1.0-cm-diameter spread in the beam of pellets?
The distance from the hole must be 2.244 × 10⁻²⁷ m to detect a 1.0 cm diameter spread in the beam of pellets.
Given that,
Mass of the pellet m = 2 g
Speed of the pellet v = 120 m/s
Diameter of the hole d = 1.5 mm = 1.5 × 10⁻³ m
Distance between the pellet and the hole D = 1 cm = 1 × 10⁻² m
Let us find the wavelength,
λ = h/mv = (6.626 × 10⁻³⁶)/(2 × 120) = 2.76 × 10⁻³³ m
So, y = (1.22 λD)/d = (1.22 × 2.76 × 10⁻³³ × 1 × 10⁻²)/(1.5 × 10⁻³) = 2.244 × 10⁻²⁷ m
Thus, the distance from the hole must be 2.244 × 10⁻²⁷ m to detect a 1.0 cm diameter spread in the beam of pellets.
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You have lenses with the following focal lengths:f= 25mm, 50mm, 100mm, and 200mm. - n what arrangement would you use these lenses to get the highest-power telescope? Fo=200, fe=25
Answer:To use these lenses to get the highest power telescopeFo=
Explanation:
The magnifier. Then we need only one lens. The angular exaggeration of the magnifier when the object is put veritably near to the focal point is given by the formula
M =
f
25 cm
where ff is the focal point. thus, the lower the focal length the larger the exaggeration therefore we should elect the lens with the shortest focal length which is the one with
f = 25 mm.
Step 2
2 of 4
{ The microscope.} The microscope. Then we need two lenses. The angular exaggeration of the microscope is given by
L ⋅ 25 cm
thus, lower the product of the focal lengths of the two lenses the larger the exaggeration. thus we should elect the two lenses with the lowest focal lengths i.e. boxed{f_0 = 25
= 25 mm and f
e
= 50 mm.
Step 3
3 of 4
{ The telescope.} The telescope. Then we need two lenses. The angular exaggeration of the telescope is given by
M = - frac{f_0}{f_e}
M = −
f
e
f
0
i.e. it's directly commensurable to the focal length of the objective lens and equally commensurable to the focal length of the eye piece lens. thus we should elect the objective lens with the loftiest possible focal length and the eyepiece lens with the lowest possible focal length
a body of mass 2.64 kg is pushed straight upward by a 32.9 n vertical force. what is its acceleration (in m/s2)?
A body of mass 2.64 kg is pushed straight upward by a 32.9 N vertical force, then its acceleration is 2.67m/s^2
Given the mass of body (m) = 2.64kg
Force acting on the body (F) = 32.9N
We know that F = ma where a is the acceleration on the body.
Here when body is thrown upwards acceleration acts upwards along with the force but in the opposite direction the gravitational acceleration acts downwards.
Then Fg force due to gravity is = mg where g is the gravitational acceleration = 9.8m/s^2
Fnet = F - Fg
ma = F- mg
a = 32.9 - (2.64x9.8)/2.64 = 2.66
Hence the acceleration acting on the body is 2.67m/s^2
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Which occurs when white light separates into a spectrum of colors when it passes through a glass prism?
A spectrum of seven colors ( red, orange, yellow, green, blue, indigo, and violet) is created when white light travels through a glass prism and is dispersed.
When white light travels through a prism, dispersion is the breaking of the light into its individual colors. The seven colors that make up the spectrum are produced. White light experiences varying degrees of color bending when it passes through a prism.
The longest wavelength and least bending color are red, yet violet bends the most. A red light would therefore be at the apex of the created spectrum, violet would be at the bottom, and the remaining hues or colors would be in between.
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A transformer has 132 kV across its primary coil and 33 kV across the secondary coil. It produces a current of 8 A in its secondary coil. How much current flows through the primary coil? [4 marks]
Answer:
32 A.
Explanation:
In a transformer, the ratio of the voltage across the primary coil to the voltage across the secondary coil is equal to the ratio of the current in the primary coil to the current in the secondary coil. This relationship is known as the transformer equation, and it can be written as follows:
Vp / Vs = Is / Ip
Where Vp is the voltage across the primary coil, Vs is the voltage across the secondary coil, Is is the current in the secondary coil, and Ip is the current in the primary coil.
Given the values provided in the problem, we can substitute them into the transformer equation to find the current in the primary coil:
Ip = (Vp * Is) / Vs
= (132 kV * 8 A) / 33 kV
= 32 A
Therefore, the current in the primary coil of the transformer is 32 A.
a certain photodiode has a short circuit current of and an open-circuit voltage of . if the fill factor is 50 %, what is the maximum power that can be drawn from this photodiode?
The maximum power that can be drawn from this photodiode is 5.6 μ w.
A photodiode is a light-touchy semiconductor diode. It produces cutting-edge when it absorbs photons. The bundle of a photodiode allows light to reach the sensitive part of the device. The bundle may additionally consist of lenses or optical filters.
Calculation:-
FF = Pmax/Pt
Pmax = ff× Pt
= 0.5 * 80 μ * 140 m
= Pmax = 5.6 μ w
Photodiodes. Photodiodes are a category of diodes that converts mild power to power. Their running is exactly the other of LEDs that are additionally diodes however they convert power to mild strength. Photodiodes also can be utilized in detecting the brightness of the light.
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Which of the following is true of the
magnitudes of tensions T₁, T2, and T3 in the
ropes in the diagram shown?
(A) The magnitude of tension T3 must be
greater than 20 N.
(B) The magnitude of the tension T₂ is
greater than T₁.
(C) The sum of the y-components of T₁ and
T₂ is equal to 20 N.
(D) The sum of the magnitudes of T₁ and T₂
is equal to T3.
(E) The sum of the magnitudes of T₂ and T3
is equal to T₁:
The true statement of the magnitudes of tensions T₁, T2, and T3 in the
ropes in the diagram shown is the sum of the y-components of T₁ and
T₂ is equal to 20 N.
Option C is correct.
What is tension?Tension is described as the pulling force transmitted axially by the means of a string, a rope, chain, or similar object, or by each end of a rod, truss member, or similar three-dimensional object.
Tension might also be described as the action-reaction pair of forces acting at each end of said elements.
We know that the block remains in equilibrium, so the forces must balance themselves in each direction at all points.
Consider the forces acting at the intersection of the three strings.
Here T3 =W=20N
The forces at the point must balance in vertical direction.
Therefore T3= Sum of y-components of T1 and T2 =20N
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an object of mass m moves at a constant speed v around a circular path of radius r. the net force applied on the object is f. if the acceleration of the object is halved, what happened to the mass?
A mass m object travels along a circular path with a radius r at a constant speed v. The object is subjected to a net force of f. The mass stays unchanged if the object's acceleration is cut in half.
An item moving in a circle at a consistent speed is known as uniform circular motion. An object constantly changes its direction as it moves in a circle. The object is always traveling tangent to the circle.
Given that an object experiences centripetal force as it moves in a circular motion.
So, Force (f) is = mv2/r, where m is an object's mass, v is its speed, and r is its path's radius.
In this case, centripetal acceleration is equal to (ac) = v2/r.
Given that when acceleration is halved:
ac' = ac/2 = v^2/2r
There is no effect on mass as it will remain constant throughout the circular motion of the object but net force will be effected.
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the moon has a mass of 1×1022 kg, and the gravitational field strength at a distance r from the planet is 0.001 n/kg. what is the gravitational force exerted on the moon while it is in orbit around the planet?
a. 0 N
b. 1 x 10^19 N
c. 1 x 10^22 N
d. 1 x 10^25 N
The gravitational force exerted on the moon of mass 1×10²² kg is 1×10¹⁹ N. And the right option is b. 1×10¹⁹ N
What is gravitational force?Gravitational force is the most prevalent force in the universe, pulling together on any two objects with mass in the universe.
To calculate the gravitational force exerted on the moon, we use the formula below.
Formula:
F = mE.................... Equation 1Where:
F = Gravitational forcem = Mass of the moonE = Gravitational field strengthFrom the question,
Given:
m = 1×10²² kgE = 0.001 N/kgSubstitute these values into equation 1
F = ( 1×10²²×0.001)F = 1×10¹⁹ NHence, the gravitational force exerted on the moon is 1×10¹⁹ N.
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if two cars are both travelling at 50 km/h and they collide head on, the effect is similar to a car colliding with a wall at what velocity ?
The effect is similar to a car colliding with a wall at a velocity of 50 km/h.
What is the principle of conservation of linear momentum?
The principle of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.
Mathematically, the law of conservation of linear momentum is given as;
Pi = Pf
where;
Pi is the sum of the initial momentumPf is the sum of the final momentumm₁u₁ = m₂u₂
where;
m₁ is the initial massu₁ is the initial velocitym₂ is the final massu₂ is the initial velocityBased on Newton's third law of motion, action and reaction are equal and opposite.
If the car collides with a stationary wall, the wall will exert equal and opposite reaction to the car. If a car hits a wall with a velocity of 50 km/h, the wall will move at a velocity of 50 km/h provided it has equal mass with the car.
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A ray of light travelling in air strikes the surface of Jell-O at an angle of 37.1 degrees. If the light travels at 2.92 x 10^8 m/s through the Jell-O a
a) what is the index of refraction for Jell-O
b) What is the angle of refraction
Someone please help me fast
a) The index of refraction for Jell-O is 1.027.
b) The angle of refraction is 38.28°.
What is the index of refraction?The index of refraction measures how a light beam bends when it travels through different media. The refractive index n is defined as the ratio of the sine of the angle of incidence to the sine of the angle of refraction.
if i is the angle of incidence of a ray in vacuum (angle between the incoming ray and the perpendicular to the surface of a medium, known as the normal), and r is the angle of refraction (angle between the ray in the medium and the normal). Then:
[tex]n = \frac{sini}{sinr}[/tex]
a) the index of refraction for Jell-O is = speed of light in air/speed of the light in the medium
= 3.00x 10^8 m/s /2.92 x 10^8 m/s
= 1.027
b) the angle of refraction is = sin⁻¹(1.027sin37.1°)
= 38.28°
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what is the wavelength of an electromagnetic wave that has a frequency of 1 hertz? a. less than 1 m b. 1 m c. more than 1 m
The wavelength of an electromagnetic wave that has a frequency of 1 hertz more than 1 m.
In a vacuum, electromagnetic waves move at a constant speed of 3.00 x 108 ms-1. Both the magnetic and electric fields have no effect on them. However, they can exhibit diffraction or interference. Any medium, including air, a solid, or a vacuum, can be traversed by an electromagnetic wave. It is not dependent on a medium to spread or move from one location to another. The opposite is true for mechanical waves, which require a medium to propagate (like sound or water waves). Transverse waves are electromagnetic waves. Thus, they are evaluated based on their amplitude (height) and wavelength (distance between the highest and lowest points of two successive waves).
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Two positive point charges q are placed on the x-axis, one at x = a and one at x = -a.a. Derive an expression for the electric field at points on the x-axis, where ?a < x < a.
Th electric field at a point between 2 points is given by E = [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)
Formula for electric field at a point on x-axis is given by:
E = [tex]\frac{kq}{r^2}[/tex] ----(i)
where k is constant, q is magnitude of charge and r is the distance from charge where electric field is to be found.
Q (-a,0)____________________(x,0)_____________________Q(a,0)
so we have to fing electric field at point (x,0) due to the both charges shown in the figure.
due to point charge at pont (-a,0) the electric field is in the positive x direction and due to charge at point (a,0) the electric field is in negative x direction.
let [tex]E_1[/tex] be the electric field due to charge at point (-a,0)
let [tex]E_2[/tex] be the electric field due to charge at point (a,0)
[tex]E_1[/tex] = [tex]\frac{kQ}{(a+x)^2}[/tex] (i^)
where i^ is unit vector along x- axis
[tex]E_2[/tex] = [tex]\frac{kQ}{(a-x)^2}[/tex] (-i^)
[tex]E_1+E_2 = \frac{kQ}{(x+a)^2}[/tex] i^ [tex]+ \frac{kQ}{(a-x)^2}[/tex] (-i^)
=> [tex]\frac{-4kQax}{(a^2-x^2)^2}[/tex] i^
so [tex]E_1 + E_2 =[/tex] [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)
so for any point a < x < a .
Th electric field is given by E = [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)
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what is the frequency of a photon that is emitted when the dipole moment of a proton flips in a magnetic field of 2.1 t? the energy of a photon is related to its frequency by the equation e
42 Hz is the frequency of a photon that is emitted when the dipole moment of a proton flips in a magnetic field of 2.1 t, the energy of a photon is related to its frequency by the equation e.
The magnetic influence on moving electric charges, electric currents and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. Paramagnetism, diamagnetism, and antiferromagnetism are three additional magnetic effects that a nonuniform magnetic field can have on "nonmagnetic" materials, albeit these forces are often so minute that they can only be detected by laboratory equipment. Electric currents, like those utilized in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetized things. Electric charges in motion and the intrinsic magnetic moments of elementary particles, which are connected to their spin, a fundamental quantum feature, create magnetic fields. As parts of the electromagnetic force, one of the four fundamental forces of nature, magnetic and electric fields are interdependent.
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FILL IN THE BLANK. on a typical seismogram, ____________ will show the highest amplitudes.
On a typical seismogram, surface waves will show the highest amplitudes.
Seismogram. the file of an earthquake's seismic waves produced through a seismograph. floor waves ( L ) remaining to go away focus; best travels via solids; reasons crust to ripple like waves on ocean (maximum destructive) Body waves ( P & S )waves journey quickest and are the primary to reach from the earthquake.
In S or shear waves, rock oscillates perpendicular to the course of wave propagation. In rock, S waves commonly journey approximately 60% the velocity of P waves, and the S wave constantly arrives after the P wave.
P waves are compressional waves and journey at the best velocity; hence, they come first.The primary, or P, waves journey maximum fast and are the primary to be registered through the seismograph. Secondary, or S, waves journey extra slowly.
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Two atellite are monitored a they orbit the earth, atellite y i four time a far from the earth center a atellite x i. If the period of revolution of x i T then what i the period of y ?
The period of y for two satellites that are being watched as they orbit the planet is 22.63 times, and if the period of rotation of satellite x is T, satellite y.
Is four times as far from the Centre of the earth as satellite x. A satellite, often known as an artificial satellite, is a spacecraft that has been put into orbit on purpose. With the exception of passive satellites, most spacecraft have a method for producing electricity for the electronics they carry, such as solar cells or radioisotope thermoelectric generators. From above the Northern Hemisphere, Earth circles the Sun in a counterclockwise manner at an average distance of 149.60 million kilometres. It takes 365.256 days to complete one orbit.
Tx/Ty = (rx/ry) 3/2 = (8/1) 3/2 = 8 3/2 where Tx/Ty = (rx/ry) 3/2 =
X's revolution lasts for 8/3 = 22.63 times as long as Y does
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a current of 0.30 a is passed through a lamp for 2.0 minutes. the energy dissipated by this lamp during the 2.0 minutes is 216 j. what is the potential (in v) of the power supply?
The potential (in v) of the power supply 6 Volt.
Calculation :
The energy formula ,
H = VIT
Where,
H=energy dissipated the lamp
I=current through the lamp
V = potential difference
t=time during which the current flows through the lamp
From the question we have,
Current(I)=0.3A
The Energy supplied(E)=216 j
Time during which the current flows(t)=2 minutes=2×60 seconds
H = VIT
216 j = v * 0.3 A *120 sec
V = 216/( 0.3 A *120 sec)
V = 6 Volt
Scientists define energy as the ability to do work. Modern civilization is possible because humans have learned to convert energy from one form to another and use it for work.
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a system does 164 j of work on its environment and gains 77 j of heat in the process. find the change in the internal energy o
The change in internal energy of system is −87 J and that of environment is 87 J.
Calculation :
given,
Q = 164 j
W = 77 j
Q = W +ΔU
77 = 164 + ΔU
ΔU = 77 - 164
= - 87 j
The change in internal energy of system is −87 J and that of environment is 87 J.
In physics, energy is the quantitative property transmitted to the body or physical system, perceived in the performance of work and in the form of heat and light. Energy is Conserved - The law of conservation of energy states that energy can be transformed into form, but cannot be created or destroyed. The unit of measure for energy in the International System of Units (SI) is the joule (J).
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as a tennis ball is struck, it departs from the racket horizontally with a speed of 29.0 m/s. the ball hits the court at a horizontal distance of 19.3 m from the racket. how far above the court is the tennis ball when it leaves the racket? 2.3 incorrect: your answer is incorrect. m
The tennis ball is 2.15 metre above the court.
The tennis ball departs from the racket horizontally with a speed of 29m/s and it hits the court at a horizontal distance of 19.3 m from the racket.
The vertical height of the tennis ball before it leave the racket can be found by using the relation,
R = V√(2H/g)
Where,
R is the horizontal range,
V is the initial speed of the tennis ball,
H is the vertical height of the tennis ball from the court,
g is the gravitational acceleration.
Putting all the values,
We get,
19.3 = 29√(2H/9.8)
H = 2.15 m.
So, the height of the tennis ball is 2.15m
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Describe how the nature vs nurture debate can be applied to the study of phobias.
an object travels in a circular path of radius r at a constant speed v. what happens to the object's acceleration if the speed is doubled and the radius stays unchanged?
If the speed is doubled and the radius stays unchanged Acceleration becomes half.
For uniform circular motion, acceleration=v2/r where v is velocity and r is radius.
Let initial velocity be V and initial radius be R. So, initial acceleration = V2/R.
Finally, velocity is unchanged(=V) and radius is doubled. So, radius is 2R.
Hence, centripetal acceleration = V2/(2R) = 1/2 V2/R.
So, acceleration becomes half.
Any change in an object's velocity causes an acceleration, including increasing speed, decreasing speed, or changing direction. Yes, that's correct even when the traveling item neither speeds up nor slows down a change in direction of motion causes an acceleration.
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