The magnitude and direction of the electric field at the position of this charge.3.33 N/C upward
An electric field is the electric force per unit of charge. It is assumed that the field's direction corresponds to the direction in which a positive test charge would experience force. The electric field is directed radially inward toward a negative point charge and radially outward from a positive charge.
Value of force F given = 10N
value of charge Q = 3 C
We know that E = F/Q
E = 10/3
= 3.33N
where charge is scalar quantity so the direction of force is the direction of electric field
Hence the magnitude and direction of the electric field at the position of this charge.3.33 N/C upward
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As you stand near a railroad track, a train passes by at a speed of 34.7 m/s while sounding its horn at a frequency of 215 Hz. What frequency do you hear as the train approaches you
When the train is approaching then the frequency is 239.2 Hz.
What is the frequency?This is the total number of times a periodic event happens within a given period of time. Wavelengths are used to measure periodic phenomena, which are frequently waves like sound waves. The frequency is the total number of wavelengths throughout time.
given,
speed of train = 34.5 m/s
Frequency of sound = 215 Hz
speed of sound = 341 m/s
when the train is approaching:
[tex]f1 = f[/tex]ₓ [tex]\frac{V}{V-Vt}[/tex]
[tex]f1 = 215[/tex]ₓ [tex]\frac{341}{341 + 34.5}[/tex]
f₁ = 239.2 Hz
Hence, when the train is approaching then the frequency is 239.2 Hz.
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Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is |v with arrow| = 160 km/s and the orbital period of each is 14.3 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 1030 kg.)
The mass M of the star is mathematically given as
M=24.269kg
What is the mass M of the star?Question Parameters
Orbital period P= 14.3*24*60*60 s
P= 1235520s
Speed V=160000
Generally, the equation for the Radius is mathematically given as
R =[tex]\frac{ V*t}{ 2*pi}[/tex]
Therefore
R =[tex]\frac{ ( 160000 )*(1235520 s)}{ 2*3.142}[/tex]
R=[tex]3.14581795*10^{10}[/tex]
Where
M*v^2/R = GM^2/(2R)^2
Therefore
M=[tex]=4(v^2)R/G\\\\ =4(240^2)R/G\\\\ = \frac{4*(160000)^2)*3.14581795*10^{10}}{6.67*10^{-11}}[/tex]
M=4.82956159*10^{31}kg
Considering, that the mass of our Sun is 1.99*10^{30} kg.
The mass M of the star is
M[tex]=\frac{4.82956159*10^{31}}{1.99*10^{30}}[/tex]
M=24.269
In conclusion, the mass M of the star is
M=24.269
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A generator produces 30 pulsesin 5 second. its frequency is?
Answer:
6 pulse per second
Explanation:
if,
5 secs = 30 pulse
1 sec = 30/5
1 sec = 6
What is a standard drink measurement
The standard drink measurement should contain 14 grams of pure alcohol in United States of America.
What is standard drink measurement?Standard drink measurement can be defined as the measurement of alcohol that is expected by an individual to consume daily without having a bad health effect.
In the United States of America, an amount of 14 grams of pure alcohol which can be found in 12 ounces of beer is regarded as normal.
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Sally and ner pet puagie go everywnere
together. One afternoon Sally decides to go for
a walk. She walks 8.0 x 10² m [N] in 5.0
minutes, then walks 0.30 km [E] in 1.5 minutes.
(8 marks)
d₁ = 300 m [E]
d₂ = 800 m [N]
a. Calculate the total distance she walks. (Be
careful with the units.)
b. Her budgie is lazy and always flies along the
shortest path possible when they go on these
trips. Find the magnitude and direction of the
budgies path.
c. Determine Sally's average speed for the
journey.
d. Determine the average velocity of Sally's
budgie.
a)The total distance she walks will be 1100 m.
b)The magnitude and direction of the budgie's path will be 854.4 m at 69.44°.
c)Sally's average speed for the journey will be 2.82 m/sec
d)The average velocity of Sally's budgie willl be 2.19 m/sec North of East.
What is displacement?Displacement is defined as the shortest distance between the two points.
Distance travelled in north direction,d₁ = 8.0 x 10² m
Time elapsed travelled in north direction,t₁ = 5.0 minutes
Distance travelled in east direction,d₂ = 0.30 km = 3.0 × 10² m
Time elapsed travelled in east direction,t₂= 1.5 minutes
The total distance she walks,d =? m
The magnitude and direction of the budgies path will be, D
Sally's average speed for the journey, [tex]\rm S_{avg}[/tex]
The average velocity of Sally's budgie,[tex]\rm V_{avg}[/tex]
a)
The total distance she walks is found as;
d=d₁+d₂
d=800 m +300 m
d = 1100 m
b)
The magnitude and direction of the budgies path will be;
[tex]\rm D = \sqrt{d_1 ^2 + d_2^2 } \\\\ D = \sqrt{800^2 +300^2 } \\\\ D = 854.4 \ m[/tex]
The direction of the displacement is;
[tex]\rm \theta = tan^{-1} \frac{800}{300} \\\\ \theta = tan^{-1}(2.6) \\\\ \theta = 69.44 ^ 0[/tex]
c)journey is found as;
Sally's average speed for the
[tex]\rm S_{avg} = \frac{d}{t} \\\\ S_{avg} =\frac{100}{300+900} \\\\ S_{avg} =2.82 \ m/sec[/tex]
d)
The average velocity of Sally's budgie is found as;
[tex]\rm V_{avg} = \frac{854.4}{300+ 900 } \\\\ V_{avg} = 2.19 \ m/sec[/tex] North of east
Hence, the total distance she walks, the magnitude and direction of the budgie's path, Sally's average speed, and the average velocity of Sally's budgie will be 1100 m,854.4 m at 69.44°,2.82 m/sec, and 2.19 m/sec North of East.
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Which of the following is NOT considered electromagnetic radiation? x-rays radio waves cosmic rays ultraviolet light
Answer:
Cosmic ray is not considered electromagnetic radiation.
Explanation:
Electromagnetic radiation refers to
It is Radiation that has both electric and magnetic fields and travels in waves.Electromagnetic radiation can vary in strength from low energy to high energy.X rays are the rays produced when a negatively charged electrode is heated by electricity and electrons are released, thereby producing energy. It is a type of radiation called EM waves.
Radio wave are wave from the portion of the electromagnetic spectrum at lower frequencies than microwaves. It is an EM wave.
Ultraviolet wave Invisible rays that are part of the energy that comes from the sun. It is an example of EM wave.
Cosmic ray is a high-speed particle either an atomic nucleus or an electron that travels through space.
Cosmic ray is not an electromagnetic wave.
Hence
Cosmic ray is not considered electromagnetic radiation
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A current magnetic relay is often used to assist in the starting of the compressor, but most new appliances use a(n) ____________________ device.
A current magnetic relay is often used to assist in the starting of the compressor, but most new appliances use positive temperature coefficient (PTC) device.
What is a compressor?A compressor can be defined as a mechanical device that is designed and developed to provide power to refrigerators, especially by increasing the pressure on air or other applicable gases.
According to heating, ventilation, and air conditioning (HVAC), a current magnetic relay is mostly used to assist in the starting of the compressor, but many new electrical appliances use positive temperature coefficient (PTC) device.
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A coffee filter of mass 1.5 grams dropped from a height of 3 m reaches the ground with a speed of 0.7 m/s. How much kinetic energy Kair did the air molecules gain from the falling coffee filter? Start from the Energy Principle, and choose as the system the coffee filter, the Earth, and the air.
The kinetic energy gained by the air molecules is 0.0437 J
Given:
Mass of a coffee filter, m = 1.5 g
Height from which it is dropped, h = 3 m
Speed at ground, v = 0.7 m/s
Initially, the coffee filter has potential energy. It is given by :
[tex]P =mgh[/tex]
P = 1.5 × 10⁻³ kg × 9.8 m/s² × 3m
P = 0.0441 J
Finally, it will have kinetic energy. It is given by :
[tex]E= \frac{1}{2} mv^{2}[/tex]
[tex]E= \frac{1}{2}[/tex]×[tex]1.4[/tex] × 10⁻³ × (0.7)²
E = 0.000343 J
The kinetic energy Kair did the air molecules gain from the falling coffee filter is :
E = 0.000343 - 0.0441
= 0.0437 J
So, the kinetic energy Kair did the air molecules gain from the falling coffee filter is 0.0437 J
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In example 18. 4 of the text, the deflection angle of the laser beam as it exits the prism is 22. 6º. If the prism had been made of glass instead of polystyrene plastic, what would the deflection angle have been?.
The deflection angle is 37.29º if the prism was made of polystyrene plastic.
What is a laser beam?
Laser beam is a light beam propagating dominantly in one direction.
It is a beam of radiation produced from a laser.
Here given that,
refraction index of glass, n1= 1.52
refraction index of polystyrene plastic, n2 = 1.59
deflection angle, B = 22.6º
For the second surface,
B = 45º - 22.6º
B = 22.40º
Now from the formula of Snell's law:
n1 sinФ = n2 sin B
sin B / sinФ = n1 / n2
sinФ = (sin 22.40º) * ( 1/ 1.59)
Ф = 37.29º
Hence,
The deflection angle is 37.29º if the prism was made of polystyrene plastic.
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The single-pole, single-throw switch is normally wired ? between the source and the load to turn devices on and off.
In series.
Single-pole and single-throw switch:
A switch with only one input and one output is referred to as a Single Pole Single Throw (SPST) switch. This indicates that it has a single output terminal and a single input terminal.
A single pole, one throw switch functions as an on/off switch in circuits. The circuit is turned on when the switch is closed. The circuit is shut off when the switch is open.
Thus, SPST switches are relatively basic in design.
Circuit for a single-pole, single-throw (SPST) switch
Types:
According to the application, it can be divided into three categories, including:
Simple SPST(ON)-OFF, Push-to-close, SPST MomentaryON-(OFF), Push-to-Open, SPST MomentaryInches Switch SPSTLearn more about terminal here:
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Hello people ~
Antoine and Adriane are each at the top of a Ferris wheel. After one revolution, each will again be at the top. Which sinusoid (sine or cosine) should you graph to model the ride of your chosen rider? Why? Assume that each Ferris wheel starts at time 't = O' seconds.
Answer:
graph of cosine function
Explanation:
f(x) = sin(x)
The curve of the sine function crosses the y-axis at the origin, heads up to y = 1 at x = π/2 and down to y = -1 at x = 3π/2.
Domain: (-∞, ∞)
Range: [-1, 1]
f(x) = cos(x)
The curve of the cosine function crosses the y-axis at (0, 1) which is its maximum, heads down to y = -1 at x = π then heads up again.
Domain: (-∞, ∞)
Range: [-1, 1]
Given information:
Antoine and Adriane begin their journey at the top of the Ferris wheel.After one revolution, they will again be at the top of the wheel.If the wheel starts when time t = 0 seconds, and they begin their journey at the top of the wheel (the maximum point), the most appropriate graph to model their ride is the graph of the cosine function since it is at its highest point when x = 0.
What must the amplitude of a traveling wave of frequency 72.0 Hz be in order for the average power carried by the wave to be 0.363 W
The amplitude of the wave is determined from the tension in the wire, speed of the wave, frequency of the wave and average power of the wave.
Amplitude of the wave
The amplitude of the wave travelling at the given frequency and power is calculated as follows;
U = (¹/₂)(T/v²)(ω²)(A²)(v)
U = (¹/₂)(T/v)(ω²)(A²)
U = (¹/₂)(T/v)(2πf)²(A²)
where;
U is the average power of the waveT is the tension in the wireω angular frequency of the waveA is amplitude of the wavev is the speed of the wavef is frequency of the waveThus, the amplitude of the wave is determined from the tension in the wire, speed of the wave, frequency of the wave and average power of the wave.
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. A pilot diverted a fighter jet 20.0 km [S 38.0° E] to avoid thunderstorm, and then flew 60.0 km [S 55.0° W] to get back on track. If the diversion lasted a total of 2.00 minutes, what was the average velocity of the jet during the diversion?
The average velocity of the jet during the diversion is 518.75 m/s.
Displacement of the pilot
The displacement of the pilot from the starting position is calculated as follows;
d² = 20² + 60² - 2(20)(60) x cos(θ)
where;
θ is the angle between 20 km and 60 km leg of triangle formed from the motion.θ = (90 - 38) + (90 - 55) = 87⁰
d² = 20² + 60² - 2(20)(60) x cos(87)
d² = 3874.39
d = 62.25 km
Average velocity of the pilotV = total displacement/total time
where;
time = 2mins = 0.033 hourV = (62.25 km)/(0.033 hr)
V = 1,867.5 km/hr = 518.75 m/s
Thus, the average velocity of the jet during the diversion is 518.75 m/s.
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give the phases into which matter can be classified, and an example of each
Explanation:
there are 4 phases in which matter could be classified.
1. Solid: an example of this would be the metal copper.
2. Liquid: an example of this would be H2O or water.
3. Gas: an example of this would be oxygen gas or O2
4. Plasma: an example of this would be lightning.
hope this helps :)
A cylindrical metal rod has a resistance R . If both its length and its diameter are tripled, its new resistance will be:
The new resistance will be 9R
A longer wire should have a higher electrical resistance than a wire with a bigger cross section, and vice versa. The electrical resistance of a wire should also be affected by the material from which it is formed.
The resistance of a wire is R = ρL/A. The volume of a wire is LA. If L increases by 3, then A must decrease by 3 in order for the volume to remain constant. If L increases by 3 and A decreases by 3, then L/A increases by 9 .
Hence the new resistance will be 9R
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The force between two interacting charges is 9.0 × 10-5 newtons. They are kept 1 meter apart. If the magnitude of one charge is 1.0 × 10-6 coulombs, what is the magnitude of the other charge?
Pluto users ??
The magnitude of other charge will be 1 × 10⁻² coulomb
The formula of electrostatic force is
Electrostatic force = K q1 q1 / r²
where k is the coulomb's constant whose value is 9 × 10⁹
q1 and a2 are the magnitude of charges
and r is the distance between them
magnitude of the force given to us is 9.0 × 10⁻⁵ newtons
magnitude of one charge = 1.0 × 10⁻⁶ coulomb
Force = K q1 q2 / r²
9.0 × 10⁻⁵ = ( ( 9 × 10⁹ ) × ( 1.0 × 10⁻⁶ ) × q2 ) / 1
9.0 × 10⁻⁵ = 9 × 10³ × q2
10⁻² = q2
Charge on q2 is 1 × 10⁻² coulomb
So the magnitude of the second charge is came out to be 1 × 10⁻² coulomb after applying the formula of electrostatic force.
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A worker pushing a 35.0-kg wooden crate at a constant speed for 12.0 m along a wood floor does 350 J of work by applying a constant horizontal force of magnitude F on the crate. (a) Determine the value of F. (b) If the worker now applies a force greater than F, describe the subsequent motion of the crate. (c) Describe what would happen to the crate if the applied force is less than F.
If the force is increased, the crate will become accelerated while if the force is decreased, the crate will decelerate.
How do we obtain the force?Recall that the force is the product of mass and acceleration. Now we know that work is done when the force applied moves a distance. Since the velocity is constant;
W = Fs
F= W/s
F = 350 J/ 12.0 m
F = 29.2 N
If the force is increased, the crate will become accelerated while if the force is decreased, the crate will decelerate.
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At what height from the surface of the earth does the value of acceleration due to gravity be 2.45m/s square where the radius of the earth is 6400 km.
Answer: 6,277,647m
Explanation:
Radius of Earth = 6400km
To calculate the gravitational acceleration of a planet, we use the following formula:
g = mG/r^2
Gravitational acceleration is equal to the mass of the planet multiplied by the gravitational constant all divided by the radius of the planet squared.
We already know what the gravitational acceleration will be, 2.45m/s^2.
So, 2.45m/s^2 = mG/r^2
the mass of the earth is equal to 5.9*10^24.
And the gravitational constant is equal to 6.67408 * 10^-11.
We don't know the radius though.
2.45m/s^2 = 5.9*10^24 * 6.67408 * 10^-11 divided by r^2
2.45m/s^2 = 3.93 * 10^14 divide by r^2
Now, we can cross-multiply.
2.45m/s^2 * r^2 = 3.93 * 10^14
divide r^2 from both sides.
r^2 = 3.93 * 10^14 divided by 2.45m/s^2
r^2 = 1.6*10^14.
Now, take the square root of both sides.
r = 12,677,647 meters from the center of the Earth.
To calculate the height from the surface of the Earth, we need to subtract r by the Earth's radius.
That will be 12,677,647-6.400.000m = 6,277,647m from the surface of Earth.
Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another and ends up as what?
Answer:
Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.
Explanation:
The solar energy cycle functions in the following form:
Considering that 100% of energy is directed at earth.When 100% light is incident on the Earth's surface about 6-7% of it is reflected back by the atmosphere into space.20% is reflected back by the clouds.And about 4% is reflected back by Earth's surface.16% of solar energy is absorbed by the atmosphere, 3% is absorbed by clouds and 51% is absorbed by land and ocean.From the absorbed energy, 64% is radiated back to space from clouds and atmosphere and 6% is directly radiated back to space from earth.From the radiated energy 15% is absorbed by the atmosphere and 23% is carried by the clouds and atmosphere through the latent heat in water vapor.Therefore, absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.
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The current in a wire is 3 a . calculate the charge that flows through the wire in 1 minute
The charge of the wire is 180 C.
What is a charge?The term charge is defined as the product of the current and the time taken. Thus we can write that;
Q = It
Q = charge
I = current
t = time
Hence;
Q = 3 A * 1 * 60 s = 180 C
Thus the charge of the wire is 180 C
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A converging lens of focal length 15cm is used to obtain a real image magnified 1½ times. calculate the distance of the image from the lens
a. 37.5cm
b. 22.5cm
c.15.0cm
d.7.5cm
e.3.3cm
Answer:
don't know the answers sorry
A jumbo jet must reach a speed of 360 km/h on the runway for takeoff. What is the lowest constant acceleration needed for takeoff from a 1.80 km runway
The lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
To find the answer, we need to know about the Newton's equation of motion.
What's the Newton's equation of motion to find the acceleration in term of initial velocity, final velocity and distance?The Newton's equation of motion that connects velocity, distance and acceleration is V² - U²= 2aSV= final velocity, U= initial velocity, S= distance and a= accelerationWhat's the acceleration, if the initial velocity, final velocity and distance are 0 m/s, 360km/h and 1.8 km respectively?Here, S= 1.8 km or 1800 m, V= 360km/h or 100m/s , U= 0 m/sSo, 100²-0= 2×a×1800=> 10000= 3600a
=> a= 10000/3600 = 2.8 m/s²
Thus, we can conclude that the lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
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The box resting on the inclined plane above has a mass of 20kg. The incline sits at a 30o angle. Find the friction force between the box and the incline if the box does not slide down the incline.
The friction force between the box and the incline if the box does not slide down the incline will be 0.577
The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are several kinds of friction: Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.
Given the box resting on the inclined plane above has a mass of 20kg and the The incline sits at a 30 degree angle
We have to find the friction force between the box and the incline if the box does not slide down the incline
Since the frictional force F₁ must equal or exceed gravitational force F₂ down the incline:
F₁ = F₂
μmgcosΘ = mgsinΘ
μ = (mgsinΘ)/(mgcosΘ)
μ = tanΘ
μ = 0.577
Hence the friction force between the box and the incline if the box does not slide down the incline will be 0.577
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:The resistance created by the box's friction with the incline The slope will be 0.577 if the box doesn't descend.
Friction is the force that prevents solid surfaces, fluid layers, and material constituents from sliding past one another. Different types of friction exist. Dry friction opposes the relative lateral motion of two touching solid surfaces.
Given that the 20-kg box lying on the inclined plane above and the incline's 30 degree inclination
If the box does not slide down the incline, we must determine the friction force between them.
Given that the gravitational force F2 down the gradient must be equal to or greater than the frictional force F1,
F₁ = F₂
If mgcosx = mgsinx
equals (mgsinx)/(mgcosx)
μ = tanx
μ = 0.577
Therefore, if the box does not slide down the incline, the friction force between the box and the incline will be 0.577.
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A uniform mixture consist of 30cm3 of water and 40cm3of ethanol. if the densities of water and ethanol are 1g/cm3 and 0.85g/cm3 respectively. determine the densities of the mixture.
The total density of the mixture is 0.485 g/cm^3
What is density:
The density, of a substance is its mass per unit volume. Density is denoted with symbol ρThe formula of density:
ρ = m / vhere,
volume of water, v1 = 30 cm^3
volume of ethanol, v2 = 40 cm^3
density of water, ρ1 = 1 g/cm^3
density of ethanol, ρ2 = 0.85 g/cm^3
so, according to formula,
for water
ρ1 = m1 / v1
m1 = ρ1 * v1
m1 = (1) * (30)
m1 = 30 grams
for ethanol
ρ2 = m2 / v2
m2 = ρ2 * v2
m2 = (0.85) * (40c)
m2 = 34 grams
total mass, M= m1 + m2
M= 30 + 34
M= 64 grams
total volume, V= v1 + v2
V= 30 + 40
V= 70 g/cm^3
Density of the mixture:
ρ = M / V
ρ = 34 / 70
ρ = 0.485 g/cm^3
Hence The total density of the mixture is 0.485 g/cm^3
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Boxes A and B are being pulled to the right on a frictionless surface. Box A has a larger mass than B. How do the two tension forces compare
Answer:
Tension T1 is less than tension T2.
T1 < T2
Explanation:
According to given data,
mass of box A ( mA) is grater than mass of box B (mB)
we can write,
m(A) > m(B)
Newton's second law states that:
Tension of object is directly proportional to the mass of the system.
T ∝ m
here Boxes A and B are being pulled to the right on a frictionless surface,
so Tension T1 generates due to the mass of box A m(A)
and Tension T2 arises due to mass of the system m(A) + m(B)
Thus tension T1 will be less than tension T2
T1 < T2
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what are effects of high gravity on blood pressure, blood circulatory system, size of lungs, bone fragility and density
Answer:
Explanation:
On return to Earth, gravity once again “pulls” the blood and fluids into the abdomen and legs. The loss of blood volume, combined with atrophy of the heart and blood vessels that can occur in space, reduces the ability to regulate a drop in blood pressure that happens when we stand on Earth.
You have a spring-loaded air rifle. When it is loaded, the spring is compressed 0.3 m and has a spring constant of 150 N/m. In joules, how much elastic potential energy is stored in the spring
The potential energy of the spring is 6.75 J
The elastic potential energy stored in the spring is given by the equation:
[tex]E= \frac{1}{2} kx^2[/tex]
where;
k is the spring constant
x is the compression/stretching of the string
In this problem, we have the spring as follows:
k = 150 N/m is the spring constant
x = 0.3 m is the compression
Substituting in the equation, we get
[tex]E=\frac{1}{2} (150) (0.3)^2[/tex]
[tex]E=6.75J[/tex]
Therefore. the elastic potential energy stored in the spring is 6.75J .
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A leaf fell from a tree branch. The path it followed is shown in the diagram below.
Which of these best describes why the leaf fell in a crooked path instead of straight down?
The leaf fell at the crooked path instead of straight down because air currents and gravity applied changing and unbalanced forces to the leaf.
What is an air current?An air current is defined as the changes in atmospheric pressure that causes the movement of air from one area to another.
When a leaf is detached naturally from the tree, it won't fall straight down to the floor but will fall a distance away from the tree due to the action of air current and some unbalanced forces.
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Why is a white car an example of a poor blackbody radiator?
A. It reflects most of the light that hits it.
B. It absorbs most frequencies of electromagnetic radiation.
C. It emits more light when it is heated up.
D. It gives off only one frequency of electromagnetic radiation.
A white automobile is a bad example of a blackbody radiator since it reflects the majority of the light that strikes it.
Why is a white car a bad example of a radiator in a black body?The same colour as an ideal absorber, an ideal radiator, sometimes known as a blackbody, absorbs all radiation that strikes it. White, on the other hand, is a poor radiator and absorber. Like a mirror, a white object reflects all radiation.
What does a subpar blackbody radiator look like?Certainly, a red laser pointer is a poor choice for a black body, for the following reasons: A heated object, like a chunk of red-hot metal from a furnace, produces a black body spectrum.
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PLEASE HELP! Place these bodies of our solar system in the proper order of formation.
(THIS NOT PHYSICS THIS IS ASTRONOMY)
- solar nebula
- inner planets
- outer planets
- the sun
- planetesimals
Answer:
1. Solar Nebula
2. The Sun
3. Planetesimals
4. Inner planets
5. Outer planets
Explanation:
A star is formed in a molecular cloud of gas and dust, mainly composed of hydrogen and helium. The Nebular Theory establishes, for the formation of the solar system, that the cloud starts to collapse under its own gravity when it receives a shock wave from a near event, for example, a supernova explosion. That results in the cloud breaking in small pieces, and those pieces constitute a possible future star.
Then it begins to accrete and rotate as a consequence of the angular momentum. In the center of that disk when it reaches the necessary temperature and pressure a protostar will born.
Around the star, in this case the Sun, fragments of dust combine until they get a meaningful size (planetesimals). According with chemical distribution on the disk of the future solar system, rocky and iron were closer to the Sun and gasses and ice were in the outer part of disk. That may explain why the inner planets are terrestrial and the outer planets are giant gasses.