An solution of antifreeze is prepared by mixing 47.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with 50.0 mL H2O (d = 1.00 g/mL) at 25°C. If the density of the antifreeze solution is 1.07 g/mL, what is its molarity?

Answers

Answer 1

If the density of antifreeze solution is 1.07 g/mL, then the molarity of the antifreeze solution is calculated as 8.66 M.

What is meant by molarity?

Number of moles of solute dissolved per liter of the solution is defined as molarity.

As we know, moles of EG = mass of EG / molar mass of EG

Mass of EG = 47.0 mL × 1.11 g/mL = 52.17 g

Moles of EG = 52.17 g / 62.07 g/mol = 0.840 mol

Total volume = 47.0 mL + 50.0 mL = 97.0 mL

So, mass of solution = volume of solution × density of solution

mass of solution = 97.0 mL × 1.07 g/mL = 103.79 g

As, molarity =moles of solute /volume of solution

Molarity = 0.840 mol / (97.0 mL / 1000 mL/L) = 8.66 M

Therefore, the molarity of the antifreeze solution is 8.66 M.

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Related Questions

what would go in the red square?

Answers

0.86 moles of [tex]N_2[/tex] and 1.72 moles of Li will react.

Calculation-

We must place a 3 coefficient in front of Li in order to bring the equation into balance:

[tex]N_2 + 2Li = 2Li_3N[/tex]

The balanced equation demonstrates that 2 moles of Li and 1 mole of N2 react to create 2 moles of Li3N. Therefore, we can apply the following dimensional analysis to determine how many moles of Li will react with 0.86 moles of N2:

[tex]0.86 mol N_2 x (2 mol Li / 1 mol N_2) = 1.72 mol Li[/tex]

What is an equation, in your opinion?

A declaration that two expressions with variables or integers are equal. In essence, equations are questions and attempts to systematically identify the solutions to these questions have been the driving forces behind the creation of mathematics.

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Please tell me the reagent

Answers

Alkene is transformed to alcohol via the oxymercuration-demercuration reaction. The reagent employed in this reaction is mercury (II) acetate in tetrahydrofuran, which also serves as the solvent.

Oxymercuation-demercuration The result of 2-methyl-2-butene oxymercuration-demercuration is 2-methyl-2-butanol.Oxymercuration-demercuration is the electrophilic activation of an alkene by a mercuric acetate group. It is then followed by the addition of water and, finally, reductive demercuration by sodium borohydride.In the first step, an electrophilic HgOAc+ ion is added to the double bond, yielding mercurinium ion.In the second stage, the species combines with a nucleophilic water molecule. A bonding of a HgOAc group and an OH group arises on the nearby carbon atoms as a result of this nucleophilic attack.The final product involves the Markovnikov addition reaction.

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2-10 someone do this for me correct answer only

Answers

Sulfur tetrafluoride, xenon tetrafluoride, antimony pentafluoride, ammonia, sulfur dioxide, water, carbon disulfide, 1,1-dichloroethane, arsenic trichloride

Methane with sulphur tetrafluoride has what shape?

Sulfur tetrafluoride has a see-saw structure and a single pair of electrons. Methane has a tetrahedral structure and no lone pairs of electrons. Xenon tetrafluoride contains two lone pairs of electrons and a square planar structure.

What is a tetrahedral and square planar example?

All eight of the d-electrons in the molecule Tetrachloropalladate(2-) are coupled in the lower-energy orbitals, which suggests a square planar geometry. This molecule is diamagnetic. Tetrachloronickelate, on the other hand, contains two unpaired electrons and is also d8, suggesting that it possesses a tetrahedral geometry.

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A new band sensation is playing a concert and recording it for a live album to be released this summer. Sound waves from singers in the band are displayed in the diagram below.

Answers

Answer:

Wave A (blue wave) has the highest volume because it has the highest amplitude.

Waves B and C have equal volumes because they have the equal amplitude.

Wave C (green wave) has the highest pitch because it has the highest frequency.

Waves A and B have equal pitch because they have the equal frequency.

2. For the following reaction, what volume of 1.8M Na2CO3 is needed to react with 10.0L of 0.30M of
AICI3

Answers

Answer:

Molarity = 3.33 L

Explanation:

The balanced chemical equation for the reaction is:

Na2CO3 + 2AlCl3 → 2NaCl + Al2(CO3)3

To determine the volume of 1.8 M Na2CO3 needed, we need to use the stoichiometry of the reaction and the formula:

Molarity (M) = moles of solute / liters of solution

First, let's find the moles of AlCl3 in 10.0 L of 0.30 M solution:

moles AlCl3 = Molarity x Volume = 0.30 mol/L x 10.0 L = 3.0 mol

From the balanced equation, we can see that 1 mole of Na2CO3 reacts with 2 moles of AlCl3. Therefore, we need:

moles Na2CO3 = (2/1) x moles AlCl3 = 2 x 3.0 mol = 6.0 mol

Now we can use the formula for molarity to find the volume of 1.8 M Na2CO3 needed:

Molarity = moles of solute / liters of solution

1.8 mol/L = 6.0 mol / liters of Na2CO3

Solving for liters of Na2CO3:

liters of Na2CO3 = moles of solute / Molarity = 6.0 mol / 1.8 mol/L = 3.33 L

Therefore, we need 3.33 L of 1.8 M Na2CO3 to react with 10.0 L of 0.30 M AlCl3.

7. How many total atoms are present on the reactant side of the equation?
A. 3
B. 6
C. 7
D. 13

Answers

There are 6 atoms of oxygen present on the reactants side of the given reaction. Thus the correct answer is option B.

How do you calculate the total atoms present on the reactant side?

Firstly, let us write the accurate chemical equation and then subsequently we will balance it as and when needed.

4Fe+3O₂→2Fe₂O₃

This is the correct balanced chemical equation for the reaction. And as we can find that the amount of iron and oxygen atoms on the reactants side is equivalent to that of the products side. This corroborates that the given chemical equation is correctly balanced.

Now, the query is based on counting the total number of oxygen atoms present on the side of reactants. As we can clearly see on the reactant side  there are three Oxygen molecules that are present. That means that there are a total of six oxygen atoms, since 3*2 gives us a total of 6 oxygen atoms.

Hence, there are a sum total of six O₂ atoms that are present on the reactant side of the provided chemical equation.

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The full question is:

How many oxygen atoms are present on the reactant side of the chemical equation  4Fe+3O₂→2Fe₂O₃?

A. 3

B. 6

C. 7

D. 13

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Write word equations for the following skeleton equations. C2H6 (g) + O2 (g) CO2 (g) +H2O (g)

Answers

The word equation for the skeleton chemical equation would be Ethane gas + Oxygen gas -> Carbon dioxide gas + Water vapor.

How to write the word equation ?

Described in this reaction, ethane (C2H6) and oxygen (O2) unite to synthesize carbon dioxide (CO2) and water vapor (H2O). The reactants are situated on the left side of the arrow marker, while the products are displayed on the right. All entities specified are presented in the gaseous state as denoted by the (g) symbol.

The word equation for the skeleton chemical reaction C2H6 (g) + O2 (g) -> CO2 (g) + H2O (g) is showcased as follows:

Ethane gas + Oxygen gas -> Carbon dioxide gas + Water vapor

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The substances in the table are combined, and Substance 1 loses 40 calories of heat. How many calories of heat will Substance 2
eventually gain?
A 0
B 20
C 40
D 80

Answers

Answer:

C: 40.

Explanation:

To answer this question, we need to use the concept of heat transfer and the law of conservation of energy, which states that energy cannot be created or destroyed, only transferred or transformed from one form to another.

When two substances are in contact, heat can flow from one substance to another until they reach thermal equilibrium (i.e., they have the same temperature). In this case, Substance 1 loses 40 calories of heat, which means it gives off 40 calories of heat to Substance 2. Therefore, Substance 2 will gain 40 calories of heat to reach thermal equilibrium.

Therefore, the correct answer is option C: 40.

Determine the quantity in grams of CO(NH2) that are in 0.57 moles of CO(NH»).
0.95 g

Answers

Answer: 34.24 g

Explanation: The molar mass of CO(NH2) can be calculated by including up the nuclear masses of each component within the atom. The nuclear masses of carbon (C), oxygen (O), nitrogen (N), and hydrogen (H) are 12.01 g/mol, 16.00 g/mol, 14.01 g/mol, and 1.01 g/mol, individually.

Molar mass of CO(NH2) = 1 x molar mass of C + 1 x molar mass of O + 2 x molar mass of N + 4 x molar mass of H

Molar mass of CO(NH2) = 1 x 12.01 g/mol + 1 x 16.00 g/mol + 2 x 14.01 g/mol + 4 x 1.01 g/mol

Molar mass of CO(NH2) = 60.06 g/mol

Presently, we will utilize this molar mass to change over moles of CO(NH2) to grams of CO(NH2):

mass of CO(NH2) = number of moles x molar mass

mass of CO(NH2) = 0.57 mol x 60.06 g/mol

mass of CO(NH2) = 34.24 g

Hence, there are 34.24 grams of CO(NH2) in 0.57 moles of CO(NH2). The answer isn't among the choices, so we have to be calculate the proper reply.

To discover the proper reply, ready to utilize the relationship between moles and mass:

mass = moles x molar mass

mass = 0.57 moles x 60.06 g/mol = 34.24 g

A 1.000 g sample of an unknown compound containing only carbon, hydrogen, and oxygen was analyzed
through combustion analysis and yielded 2.224 g of CO, and 0.3035 g of H,O. What is the compound's
empirical formula?

Answers

The moles of carbon, hydrogen, and oxygen may not be whole numbers, we may need to round them to the nearest whole number to get the simplest ratio.

What is Empirical Formula?

The empirical formula of a chemical compound represents the simplest, most reduced ratio of atoms in that compound. It shows the relative number of atoms of each element present in the compound, expressed as the smallest whole numbers. In other words, it gives the simplest whole number ratio of the elements in a compound.

Mass of carbon = moles of CO

Mass of hydrogen = 2 x moles of H2O (since each H2O molecule has 2 hydrogen atoms)

Calculate the moles of oxygen in the compound.

Given:

Mass of oxygen = moles of CO (since each CO molecule has 1 oxygen atom) + moles of H2O (since each H2O molecule has 1 oxygen atom)

Determine the empirical formula.

The empirical formula represents the simplest, most reduced ratio of atoms in the compound. To determine it, we can use the mole ratios of carbon, hydrogen, and oxygen calculated in the previous steps.

Empirical formula = CxHyOz, where x, y, and z represent the mole ratios of carbon, hydrogen, and oxygen, respectively.

Now, let's plug in the calculated values for moles of carbon, hydrogen, and oxygen into the empirical formula:

Empirical formula = C moles : H moles : O moles

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Final answer:

The empirical formula of the unknown compound given the combustion analysis data is C2H3O.

Explanation:

The first step in solving this problem is to know how much carbon and hydrogen in grams are in the carbon dioxide (CO2) and water (H2O) produced. From the mass of CO2, we get 2.224g * 0.2729 (proportion of carbon in CO2) = 0.607g C. And the mass of hydrogen is 0.3035 g * 0.1119 (proportion of hydrogen in H2O) = 0.034g H. The remaining mass is 1g (total mass) - 0.607g C - 0.034g H = 0.359g O. Then, we need to convert these values to moles. This gives us 0.607g C * (1 mole C / 12.01 g C) = 0.050 moles C, 0.034g H * (1 mole H / 1.01 g H) = 0.033 moles H, and 0.359g O * (1 mole O / 16.00 g O) = 0.022 moles O.

By finding the ratio of these moles, we get C2H3O, which is the empirical formula of the compound.

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What is the mass of a 0.230 mole sample of potassium metal?

Answers

Answer:

Explanation:

0.25 moles KCl = 19g KCl (molar mass KCl = 74.6g)

Identify the differences in composition properties

Answers

Answer:

The composition and properties of a substance are different from each other.

The composition of a substance is what he substance is made of.

Let's take water as an example. We know that the chemical formula for water is  . This tells us that water has 2 hydrogen molecules and 1 oxygen molecule. That is the composition of water.

The properties of a substance are how a substance appears and behaves both chemically and physically.

Again, let's use water as an example. Most times, water is a clear liquid. It freezes at 0 degrees Celsius and boils at 100 degrees Celsius. These are some of water's physical properties. Water also has many chemical properties; however, we needn't go into those.

Explanation:

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I NEED HELP WITH THIS QUESTION THANK YOU

Answers

The mole fraction of the solute in the solution is calculated as 0.1406.

What is non volatile solute?

Non-volatile solute is a substance that does not readily evaporate at given temperature and pressure.

Raoult's law : P_total = P_solute + P_water

P_total is total vapor pressure of solution, P_solute is partial pressure of  solute, and P_water is partial pressure of water.

Since the solute is non-volatile, we can assume that its partial pressure is negligible compared to the pressure of water. Therefore: P_total ≈ P_water

P_total = X_water * P°_water

X_water is mole fraction of water and P°_water is vapor pressure of pure water at same temperature.

305 torr = X_water * 355.1 torr (since P_total ≈ P_water)

X_water = 305 torr / 355.1 torr = 0.8594

X_solute = 1 - X_water = 1 - 0.8594 = 0.1406

Therefore, the mole fraction of the solute in the solution is 0.1406.

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How much dry solute would you take to prepare 118 mL of 0.105 M NaNO3

Answers

The amount of dry solute it would take to prepare 118 mL of 0.105 M NaNO3 is 1.05g.

How to calculate mass?

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows:

mass = no of moles × molar mass

However, the number of moles it took to prepare 118 mL of 0.105 M NaNO3 must be calculated as follows;

no of moles = 0.105 × 0.118 = 0.0124 moles

molar mass of sodium nitrate = 85g/mol

mass = 85g/mol × 0.0124 moles = 1.05g

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Water rolls off a duck's back but thoroughly wets a head of human hair. What do these observations reveal about the chemical nature of these two sur- faces?

Answers

Explanation:

The observations that water rolls off a duck's back but thoroughly wets a head of human hair reveal that the surfaces of the duck feathers and human hair have different physical and chemical properties.

Duck feathers have a unique structure that helps them repel water. They are coated in a special oil that makes them hydrophobic, or water-repelling. The oil forms a layer on the surface of the feathers that prevents water from penetrating into the feather structure. Additionally, the feather structure is tightly packed and has a lot of surface curvature, which also helps to prevent water from sticking to the feathers. This is why water rolls off a duck's back.

In contrast, human hair does not have a hydrophobic coating, and its surface is relatively smooth. This means that water can easily stick to the surface of human hair and thoroughly wet it.

Overall, these observations reveal that the chemical nature of the surfaces of duck feathers and human hair are different, and that these differences have a significant impact on how they interact with water.

How many lone pairs of electrons are in the ion OH⁻?


0

1

3

6

Answers

There are 1 lone pairs of electrons are in the ion OH⁻

An OH ion has how many lone pairs?

Since oxygen creates two bonds, we know that two electrons are required to create those two bonds. There are now just two electron pairs remaining that are not involved in bonding. Oxygen thus contains two lone pairs.

Is there a single pair of electrons in OH?

The O and H atoms are connected by a solitary covalent link. The oxygen atom has a net -1 charge, which normally manifests as the whole charge on the OH- ion. On the O atom in the OH- Lewis structure, there exist lone electron pairs.

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Which of the following choices fits in the blank to complete the equation?
ΔG° = ΔΗ°
OA. + AS
B. + TAS
O C. - AS⁰
.
OD. - TAS

Answers

The equation can be written as; ΔG = ΔH - TΔS

What is the equation of the free energy?

The equation for the free energy change (ΔG) in a system can be expressed in terms of the enthalpy change (ΔH) and entropy change (ΔS)

The Gibbs free energy equation links changes in enthalpy and entropy that occur during a process to changes in a system's free energy. If G is negative, the process can happen spontaneously and is thermodynamically beneficial.

If G is positive, the process requires an energy input and is not thermodynamically favorable. The system is in equilibrium if G is zero.

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At 25 ∘C, the equilibrium partial pressures for the reaction 3A(g)+4B(g)↽−⇀2C(g)+3D(g) were found to be PA=4.62 atm, PB=4.36 atm, PC=4.36 atm, and PD=4.70 atm. What is the standard change in Gibbs free energy of this reaction at 25 ∘C?

Answers

Answer: the standard change in Gibbs free energy of the reaction at 25 ∘C is 6.24 kJ/mol.

Explanation: One can employ the equation in order to calculate the standard Gibbs free energy change (ΔG°) for the reaction at a temperature of 25 degrees Celsius.

The standard free energy change, ΔG°, can be expressed as the negative product of the universal gas constant (R), temperature (T) and the natural logarithm of the equilibrium constant (K).

The equilibrium constant is denoted by K and the gas constant R has a value of 8.314 J/mol·K, while T stands for temperature in Kelvin, which is equivalent to 298 K for 25 ∘C.

K can be determined by utilizing the partial pressures at equilibrium.

K equals the square of the product of PC and the cube of PD divided by the cube of PA multiplied by the fourth power of PB.

After replacing the provided values, the result obtained is:

The value of K is obtained by raising 4.36 atm to the power of 2, and 4.70 atm to the power of 3, and then dividing that by the product of 4.62 atm to the power of 3 and 4.36 atm to the power of 4.

The numeric value of K is 0.0786.

We can now compute the value of ΔG° by using the available data.

The change in Gibbs energy under standard conditions is equal to the negative product of gas constant, temperature and natural logarithm of equilibrium constant.

The standard Gibbs free energy change is determined by multiplying the constant of gas by the temperature and natural logarithm of the equilibrium constant.

The value of ΔG° can be expressed as - (8.314 J/mol·K) multiplied by 298 K and -2.547.

The standard free energy change is either 6,237 joules per mole or 6.24 kilojoules per mole.

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A snorkeler takes a syringe filled with 17 mL of air from the surface, where the pressure is 1.0 atm, to an unknown depth. The volume of the air in the syringe at this depth is 7.9 mL. What is the pressure at this depth?
Express your answer to two significant figures.

Answers

Originally there were 17 mL of air at a pressure of 1.0 atm At the unknown depth, the volume decreased to 7.9 mLUsing Boyle's Law (Pressure x Volume = Constant), we can calculate the new pressureP1 x V1 = P2 x V2Where P1 = 1.0 atm, V1 = 17 mL, V2 = 7.9 mL So we solve for P2:P2 = (P1 x V1) / V2P2 = (1.0 atm x 17 mL) / 7.9 mLP2 = 2.2 atm

_______________________________

So in short:. Original pressure (at surface) = 1.0 atm Original volume = 17 mLNew volume (at depth) = 7.9 mLUsing Boyle's Law, calculate new pressure:New pressure = (1.0 atm x 17 mL) / 7.9 mL = 2.2 atm two significant figures = 220 kPa

What is the molar solubility, S, of AgC, H; 02 if Ksp = 2.00 × 10-3?

Answers

The molar solubility of AgC, H; 02 is 0.0447 mol/L..

What is Molar Solubility?

Molar solubility refers to the maximum amount of a solute that can dissolve in a given amount of solvent at a particular temperature to form a saturated solution, usually expressed in moles per liter (mol/L or M). It is a measure of the solubility of a compound under specific conditions, such as temperature and pressure.

Molar solubility is an important parameter in chemistry and is often used to describe the solubility behavior of ionic compounds, salts, and other substances in various solvents.

Ksp = [tex]S^{2}[/tex]

Substituting the given value of Ksp, we get:

2.00 × [tex]10^{-3}[/tex] =[tex]S^{2}[/tex]

Taking the square root of both sides, we get:

S = √(2.00 × [tex]10^{-3}[/tex])

S = 0.0447 mol/L (rounded to four significant figures)

Therefore, the molar solubility of AgC, H; 02 is 0.0447 mol/L.

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0.0447 mol/L is the molar solubility, S, of AgC, H; 02 if Ksp = 2.00 × 10-3

Explain equilibrium constant.

A dynamic chemical system approaches chemical equilibrium when enough time has passed and its composition no longer exhibits any discernible propensity to change further. The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium.

The maximum number of moles of a solute that can be dissolved in a liter of solution before the solution becomes saturated is its molar solubility. Because of the relationship between the molar solubility and the solubility product, one can use the other to determine the other.

Ksp = S^2

2.00 ×10^-3  = S^2

S = √(2.00 × )

S = 0.0447 mol/L

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Draw a Lewis structure for CO32–, SF4 and HCOOH (formic acid)

Answers

The Lewis structures are shown by dots in the images attached here.

What is Lewis structure?

A Lewis structure, also known as a Lewis dot diagram, is a visual representation of the bonding between atoms or ions in a molecule. It was developed by American chemist Gilbert N. Lewis in 1916. In a Lewis structure, the chemical symbol of each atom is surrounded by a set of dots, representing the valence electrons of the atom.

These dots are arranged to indicate the sharing or transfer of electrons between atoms, and the resulting arrangement of atoms and electrons is shown as a molecular structure.

Lewis structures are useful for predicting the shape, polarity, and reactivity of molecules and for understanding the principles of chemical bonding.

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is a pH an atom, ion, molecule, macromolecule, or a cell?

Answers

Although there is some variation amongst tissues, the physiologically typical intracellular pH ranges from 7.0 to 7.4. Skeletal muscle in mammals typically has a pHi of 6.8 to 7.1.

A cell is it an atom?

A cell is the basic membrane-bound living thing and can either have one or more cells. All the molecules required for an organism to function are found in cells. An atomic is 10-10m in size. In contrast, a cellular is 10-6 metres in size. Because all cells are composed of atoms, they are therefore bigger than atoms.

What keeps a cell's pH stable?

Acid excretion, efflux through plasma membranes, and buffering mechanisms all work together to precisely preserve the pH of body fluids. Protons are extruded from the cytosol into the extracellular space through the organic cation transporter (MCT) and the Na+/H+ exchanger (NHE).

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.A) Calculate the molecular formula of a compound with an empirical formula of P2O5 and a molar mass of 283.88 g/mol.
B) Calculate the empirical formula of a compound containing 52.14% carbon, 13.12% hydrogen, and 34.73% oxygen.

Answers

A) The molecular formula is: P₄O₁₀; B) This gives us the empirical formula: C₂H₆O

What is empirical formula?

The simplest whole number ratio of atoms in a compound is called the empirical formula.

A) Empirical formula mass of P₂O₅ = 2(atomic mass of P) + 5(atomic mass of O)

= 2(30.97 g/mol) + 5(15.99 g/mol)

= 141.94 g/mol

Molecular mass / Empirical formula mass = 283.88 g/mol / 141.94 g/mol = 2

This tells us that the molecular formula is twice the empirical formula, so the molecular formula is: P₄O₁₀

B)  moles of C = 52.14 g / 12.01 g/mol = 4.344 mol

moles of H = 13.12 g / 1.01 g/mol = 12.97 mol

moles of O = 34.73 g / 16.00 g/mol = 2.17 mol

4.344 mol / 2.17 mol = 2.00

12.97 mol / 2.17 mol = 6.00

2.17 mol / 2.17 mol = 1.00

This gives us the empirical formula: C₂H₆O

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How many moles exist in 6.035 x 10^25 atoms of boron?

Please help

Answers

To determine the number of moles of boron in 6.035 x 10^25 atoms of boron, we need to use Avogadro's number, which is 6.022 x 10^23 particles per mole. We can set up a proportion to solve for the number of moles:

(6.035 x 10^25 atoms) / (6.022 x 10^23 atoms/mol) = x moles

Simplifying the expression on the left side, we get:

x = (6.035 / 6.022) x (10^25 / 10^23) moles

x = 1.002 moles

Therefore, there are 1.002 moles of boron in 6.035 x 10^25 atoms of boron.

After a jar of liquid has been sealed, the level of the liquid decreases slightly because of evaporation. After a slight decrease, the level of the liquid ceases to change. Why?

Answers

Explanation: The level of the liquid in a sealed jar decreases slightly due to the evaporation of some of the liquid molecules into the air space above the liquid. However, once the concentration of the liquid molecules in the air space reaches a certain level, the rate of evaporation will slow down. This is because the concentration of the liquid molecules in the air space will eventually reach a point where the rate of evaporation is balanced by the rate of condensation.

At this point, the liquid molecules in the air space will be colliding with the surface of the liquid at the same rate that liquid molecules are evaporating from the surface of the liquid. As a result, the level of the liquid will cease to change, and the liquid will remain at a stable level within the jar.

Use the kinetic-molecular theory to explain each observation given.
a. Wax melts near the flame of a burning candle.
b. Liquid water may be converted into ice cubes in a freezer.
c. Ginger ale flows to match the shape of a glass.
d. Water gradually evaporates from a swimming pool.
e. Water vapor condenses inside house windows on cold days.
f. Snow gradually disappears, even when the tem- perature remains below freezing. g. Solids and liquids cannot be compressed as much as gases.

Answers

a. Wax melts near the flame of a burning candle because the kinetic-molecular theory states that the higher the temperature, the faster the molecules move. Since the flame of a burning candle is hot, the wax molecules move faster, allowing them to take up more space and eventually melt.

What is kinetic-molecular theory?

The kinetic-molecular theory is based on the following five fundamental principles:

The average distances between the molecules that make up a gas are substantially bigger than the diameters of the individual molecules. When compared to the volume of the gas itself, the volume filled by the gas' molecules is insignificant.

In a perfect gas, neither the molecules nor the container walls are attracted to one another.

The molecules move randomly and continuously and, as physical objects, they are subject to Newton's laws of motion. Until they collide with one another or the container walls, the molecules move in a straight line.

Collisions are fully elastic; although two molecules' orientations and kinetic energies change when they collide, the overall kinetic energy is conserved. It is not "sticky" to collide.

The relationship between the average gas molecule kinetic energy and absolute temperature is direct. The word "average" is crucial in this context because individual molecules' velocities and kinetic energy will vary widely, with some even having zero velocities at specific times. This suggests that if the temperature were to drop to absolute zero, all molecular motion would stop.

Explanation:

b.  Since a freezer is much colder than room temperature, the water molecules move very slowly and become organized, allowing them to form ice cubes.

c. All matter is made up of many small particles that are in constant motion. When the ginger ale is poured into the glass, the molecules of the liquid spread out to fill the shape of the glass due to their motion.

d. The molecules in a liquid are in constant motion, and that when they move, they bump into each other, passing energy from one to the other. This energy causes the particles to move faster. As they move faster, they create turbulence that causes them to break away from the liquid surface. These particles then form a vapor, which is an invisible form of water called water vapor. As these particles accumulate together, they gradually evaporate from the swimming pool, eventually diminishing its water level.

e. Water vapor condenses inside house windows on cold days because the molecules of water vapor slow down and as they lose energy they no longer have enough kinetic energy to remain in the gaseous state. The molecules then condense and form liquid water droplets on cool surfaces such as windows.

f. Snow gradually disappears even when the temperature remains below freezing because the heat stored in the snow starts to melt the snow. This occurs even when the outside temperature remains at freezing or below because the heat is released from the snow and warms the surrounding air.

g. Solids and liquids cannot be compressed as much as gases because the particles of gases have more energy and thus more freedom of movement than particles of solids and liquids. The particles of gases can move around and can occupy larger spaces than particles of solids and liquids, allowing them to be compressed more effectively.

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The density of helium in a balloon is 1.18 g/L. If a balloon holds 2.93 L of He, how many atoms of He are in
the balloon?

Answers

Answer: (a) 8.33x10^24.

Explanation: In the realm of gas thermodynamics, the variables P, V, n, R, and T denote pressure, volume, number of moles of gas, gas constant, and temperature in Kelvin, respectively.

It is feasible to manipulate this equation for the purpose of deducing n, which denotes the quantity of moles of gas.

The equation n = (PV) / (RT) represents the number of moles present in a gas system, where P, V, R, and T denote the pressure, volume, ideal gas constant, and temperature, respectively. This formula serves as a fundamental expression in thermodynamics and is employed in various fields of science, notably chemistry and physics, as a means of determining the amount of substance in a gaseous system. Its rigorous derivation and application have been extensively studied in the academic realm, and it remains a pivotal concept in modern scientific research.

Ascertaining the quantity of helium atoms contained within the balloon necessitates the conversion of the amount of helium moles into a corresponding number of helium atoms. The quantity of atoms in a single mole of any given substance, as denoted by Avogadro's number, is 6.022 x 10^23.

Initially, it is necessary to determine the quantity of moles of helium present within the spherical object.

The quantity n is expressed as the ratio of the product of the pressure and volume, PV, to the product of the universal gas constant, R, the temperature, T, and is mathematically represented as n = (PV) / (RT). Upon substituting the relevant values in this equation, where the pressure is not explicitly given, n may be calculated as (1.18 g/L x 2.93 L) / (0.0821 L-atm/mol-K x 273 K).

The quantity of substance present is 0.1386 mol.

Subsequently, the subsequent step would be to transform the aforementioned measurement into the numerical value representing the quantity of helium atoms present.

The numerical value of helium atoms can be expressed as the product of a constant factor 'n' and the Avogadro constant. That is, the number of atoms of helium is determined by multiplying 'n' with Avogadro's number.

The quantity of helium atoms is equivalent to 0.1386 moles, multiplied by the constant Avogadro's number of 6.022 x 10^23 atoms per mole.

The quantity of helium atoms is 8.33 x 10^23.

Final answer:

To calculate the number of atoms of helium in the balloon, we can use Avogadro's number and the molar mass of helium.

Explanation:

The number of atoms of helium in the balloon can be calculated using the Avogadro's number and the molar mass of helium. The molar mass of helium is 4.0026 g/mol. First, we need to calculate the number of moles of helium in the balloon by dividing the mass of helium by its molar mass:

Number of moles of helium = Mass of helium / Molar mass of helium

Once we have the number of moles, we can use Avogadro's number to calculate the number of atoms:

Number of atoms of helium = Number of moles of helium * Avogadro's number

Let's substitute the values into the formula to find the number of atoms of helium in the balloon:

Number of atoms of helium = (1.18 g/L * 2.93 L) / (4.0026 g/mol) * (6.022 x 10^23 atoms/mol)

Solving this equation will give us the number of atoms of helium in the balloon.

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Calculate to what temperature 75.0 grams of carbon tetrachloride gas, CCl4 would need to be heated to have a volume of 2.00 liters at 250 °C.

(Ideal Gas Law Problem)

Answers

Answer:

The CCl4 gas would need to be heated to -178.7 °C to have a volume of 2.00 liters at 250 °C.

Step-by-step explanation:

First, we need to calculate the number of moles of CCl4:

[tex]\sf:\implies n = \dfrac{m}{M}[/tex]

[tex]\sf:\implies n = \dfrac{75.0\: g}{154.0\: g/mol}[/tex]

[tex]\sf:\implies n = 0.487\: moles[/tex]

Next, we can use the ideal gas law to solve for the temperature:

[tex]\sf\qquad\dashrightarrow PV = nRT[/tex]

where:

P is the pressureV is the volumen is the number of molesR is the gas constant (0.08206 L·atm/mol·K)T is the temperature in Kelvin

We need to convert the given temperature of 250 °C to Kelvin:

[tex]\sf:\implies T = 250 ^{\circ}C + 273.15[/tex]

[tex]\sf:\implies T = 523.15\: K[/tex]

Now we can plug in the values and solve for T:

[tex]\sf:\implies (1\: atm)(2.00\: L) = (0.487\: mol)(0.08206\: L\cdot atm/mol\cdot K)T[/tex]

[tex]\sf:\implies T = \dfrac{(1\: atm)(2.00\: L)}{(0.487\: mol)(0.08206\: L\cdot atm/mol\cdot K)}[/tex]

[tex]\sf:\implies T = 94.5\: K[/tex]

Finally, we need to convert the temperature back to Celsius:

[tex]\sf:\implies T = 94.5\: K - 273.15[/tex]

[tex]\sf:\implies \boxed{\bold{\:\:T = -178.7 ^{\circ}C\:\:}}\:\:\:\green{\checkmark}[/tex]

Therefore, the CCl4 gas would need to be heated to -178.7 °C to have a volume of 2.00 liters at 250 °C.

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300.0 mL of a 0.400 M solution of NaI is diluted to 700.0 mL. What is the new concentration of the solution?

Answers

Answer:

the new concentration of the solution is 0.171 M.

Explanation:

To solve this problem, we can use the formula for dilution:

C1V1 = C2V2

where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Substituting the given values, we get:

(0.400 M)(300.0 mL) = C2(700.0 mL)

Solving for C2, we get:

C2 = (0.400 M)(300.0 mL) / (700.0 mL)

C2 = 0.171 M

Therefore, the new concentration of the solution is 0.171 M.

V
A student dissolves 11.S g of sodium hydroxide (NaOH) in 250. g of water in a well-insulated open cup. He then observes the temperature of the water rise
from 20.0 °C to 31.3 °C over the course of 6.7 minutes.
Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction:
NaOH(s) -. Na (ag) + OH (ag)
You can make any reasonable assumptions about the physical properties of the solution. Be sure answers you calculate using measured data are rounded to 3
significant digits.
Note for advanced students: it's possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and
published values for this reaction.
is this reaction exothermic, endothermic, or neither?
Oexothermic
O endothermic
O neither
0.°
If you said the reaction was exothermic or endothermic, calculate the amount of
heat that was released or absorbed by the reaction in this case.
Calculate the reaction enthalpy AH.
nen per mole of NaOH.
kJ

Answers

According to the question the reaction enthalpy is thus 10610 J / 0.278 moles = 38.3 kJ/mol.

What is enthalpy?

Enthalpy is a thermodynamic property of a system that measures the total energy content of a system. It is a state function that is expressed in terms of internal energy, pressure, and volume of a system. Enthalpy represents the amount of energy that is associated with a chemical reaction or physical change.

The reaction is exothermic, meaning that heat is released during the reaction. The amount of heat released can be calculated with the equation q = mcΔT, where q is the heat released, m is the mass of the solution, c is the specific heat capacity of the solution, and ΔT is the change in temperature of the solution. Using the given data, the amount of heat released by the reaction can be calculated as q = (250 g)(4.184 J/g-K)(11.1 K) = 10610 J. The enthalpy change for the reaction can then be calculated by dividing the heat released by the number of moles of NaOH, which is 11.1 g / 40.00 g/mol = 0.278 moles. The reaction enthalpy is thus 10610 J / 0.278 moles = 38.3 kJ/mol.

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