an object with height 0.85 cm is placed a distance 19.75 cm in front of a convex mirror with focal length -6.25 cm,removedde6d0d485ec413711a4e98afe87284678ac0bba70217810ba692cdd66aafdf8cremoved 2m68-57-20-4f-a59d-29897 20% part (a) calculate and enter a value for the magnitude of the distance between the image and the mirror given the values in problem statement. |di||di|

You want exactly nine gallons of water, but you have seven-gallon bucket and five-gallon bucket. To solve this problem, we use the method of selective combination.

We should fill the seven gallon bucket and then pour it into five gallon bucket, leaving the two gallon behind. Discard five gallons and pour two gallon into five-gallon bucket and refill seven-gallon bucket. You will have a total of nine gallons.

To elaborate, the selective combination is an insight producing process that occurs when one merges two or more components that are seemingly unrelated to produce a working solution.

In this case, two components combined are the five-gallon bucket and the seven gallon bucket.

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We are given big parallel metallic plates aa and bb bring contrary expenses of same significance are separated through a distance dd = 45.zero mm = zero.1/2 m wherein the capacity distinction among the 2 plates is V_V ab = 360 V

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The inductor's resistance, R, is 1550.38.

1.05 H is the inductance L.

A capacitance opposes a variation in voltage, while an inductance opposes a changes in current. This is one of the key distinctions between the two components. Additionally, the capacitor and inductor both store energies with in type of either a magnetic charge and a magnetic force, respectively.

Briefing-

Given:

Emf, E=15.5V

Current, i = 4.86mA

Time, t = 0.940 ms

Maximum current, imax Calculation: 6.45mA

a) The resistance is given by,

Ꭱ= V/Imax = 10/6.45×10⁻³= 1550.38Ω

b) The inductance is given by,

L= -Rt/(1-i/imax)= 1550.38×0.940×10⁻³/In(1-4.86/6.45)

The inductance L is 1.05 H.

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Answer:

8.83 N/kg

Explanation:

To solve this problem we can use the formula:

[tex]g=G\frac{M}{r^{2} }[/tex] which describes the field strength at a certain distance from a body (where g=gravitational field strength, G=Gravitational constant, M=Mass of planet, and r=distance from center of planetary mass).

We are given the information that the radius of Venus is 6.073 x 10^6m and its mass is 4.88x10^24kg.

We are also given the gravitational constant.

Since the radius of a planet is equal to the distance between the center of the planet to its surface we can use this value for 'r'.

Therefore we now have all the information we need and so we can plug these values into the equation to solve for the gravitational field strength:

[tex]g=(6.67*10^{-11})\frac{(4.88*10^{24})}{(6.073*10^{6})^{2}}[/tex]

[tex]g=(6.67*10^{-11})\frac{(4.88*10^{24})}{3.688*10^{13}}[/tex]

[tex]g=(6.67*10^{-11})*(1.323*10^{11})[/tex]

[tex]g=8.83Nkg^{-1}[/tex] (to 2.d.p)

Normal force that will act on the body moving downward will be  480 newtons.

One of the most significant laws in all of physics is Newton's second law. F = ma, wherein F (force) as well as a (acceleration) both are vector values, can be used to represent an object with mass m is constant. A body accelerates according to the equation if there is a net force that acts on it.

Until and unless an external force occurs on a body, it is in a condition of rest or homogeneous movement in a straight line. According to Newton's first law of motion, a body won't begin to move unless and until an outside force impacts it.

given:

m=20 kg, a= 2.0m/s^2, g=10 m/s^2

   Mg-F(normal)=Ma

  60*10-F(normal)=60*2

 F(normal)=480N

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Two balls of the same mass are thrown towards a wall and collide with it moving with a speed of 5 m/s. Ball A hits the wall and rebounds with a speed of 4 m/s. Ball B hits the wall and stops. Assume that the collisions times are the same for each ball. Compared to ball B, ball A has a greater  velocity change a greater change, and  a greater  impact force.

The term "impact force" refers to a circumstance in which effort is expended to move a target object a certain distance. When two objects collide, it can be understood as the force that results. The coming together of two objects is known as an object collision. A lot happens to an object as a result of the impact force quickly. F serves as a symbol to represent it. The dimensions are specified by [M1L1T-2] and the Newton (N) unit of measurement is used. Its equation is the twice-taken time divided by the product of a body's mass and velocity. In other words, it is the proportion of kinetic energy that a body has to its total distance traveled.

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Hubble's law is a statement of a direct correlation between the distance to a galaxy and its recessional velocity as determined by the red shift. It states that all galaxies are moving away from the Earth and from each other.

Edwin Hubble discovered that most of the galaxies are moving away from the Earth and away from each other. He also discovered that there is a relationship between the distance to a galaxy and its speed. He stated that the farther away a galaxy is, the faster it is moving away from us. Hence, Hubble’s law, also known as the Hubble–Lemaître law, refers to the observation in physical cosmology that galaxies are moving away from Earth at speeds proportional to their distance.

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The magnitude of the force that maintains circular motion acting on the puck is 15.68 Newtons and the linear speed of the puck is 30.854 m/s.

Uniform circular motion is the motion in a circle at constant speed and Instantaneous velocity is always tangent to the circle. The acceleration, called the centripetal acceleration, points toward the center of the circle.

For an object to be in uniform circular motion, Newton’s 2 nd law requires a net force acting on it. This net force is called centripetal force. Physically, the centripetal force can be the tension in a string, the gravity on a satellite, the normal force of a ring, etc.

Don’t count the centripetal force as an additional force in the free-body-diagram.. It refers to the required net force for circular motion.A centrifuge works by spinning very fast. An object in the tube requires a large centripetal force. When the liquid can’t provide such a large force, the object will move (sink) to the end of the tube.

we have,

Force = mg = 1.6 x 9.8 = 15.68 Newtons

now Force = F = m'v^2/R

15.68 = 0.028 x v^2/1.7

Speed = v = 30.854 m/s

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The length of the can above the water level is  0.052195 m  .

In the question ,

it is given that ,

capacity of the soda can = 355 ml = 0.000355 m³

diameter of the soda can = 6.2 cm = 0.062 m

mass of the soda can = 20g = 0.02 Kg

given that the soda can is half filled , so , the water volume in the can is

= 0.000355/2 m³

= 0.0001775 m³

Let the density of the water be  = 1000 kg/m³

So , the mass of the half filled water will be = 1000×0.0001775

Let water density be 1000kg/m³ , the mass of this half-filled water is

= 0.1775

So , The total mass of the water-can system is = 0.1775 + 0.02 = 0.1975 kg

Now , For the system to stay balanced, the total mass should be equal to the mass of water displaced by can submerged

So , The volume of water displaced by submerged can is

= 0.1975/1000 = 0.0001975 m³

So , Volume of the can that is not submerged( above water level) is

= 0.000355 - 0.0001975

= 0.0001575 m³

We know that base area of  can = πr² = π(d/2)² = π×(0.062/2)²

= 0.00301754 m²

So , the length of the can above water is = 0.0001575/0.00301754

= 0.0521948342 m

≈ 0.052195 m

Therefore , the can will be 0.052195 m above the water level .

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The magnitude of the force that a concrete support exerts on the bridge (a) at the near end is 2593 N  (b) at the far end is  2002 N    .

In the question ,

it is given that ,

the hiker weighs : [tex]W_{h}[/tex] = 985 N

the bridge's weight ([tex]W_{b}[/tex]) is = 3610 N ,

let the magnitude of the force that concrete support exerts on bridge at near end is = F₁    and

let magnitude of force that concrete support exerts on bridge at far end is = F₂ .

Since the bridge is in equilibrium   , the sum of all the forces in the vertical direction will be = 0 .

So , F₁ + F₂ -  [tex]W_{h}[/tex] - [tex]W_{b}[/tex] = 0

Substituting the value ,

we get ,

F₁ + F₂ -  985 - 3610 = 0

F₁ + F₂ = 4595 N

also given that , the hiker is at 1/5th position of the length of bridge from left support = L/5 m .

Since the bridge is not rotating , the net torque will be 0 .

[tex]T_{net}[/tex] = 0 .

The torque due to weight of hiker, due to weight of bridge and due to right end support about point nearest support is written as :

So ,  [tex]W_{h}[/tex]×(L/5) +  [tex]W_{b}[/tex]×(L/2) - F₂×L = 0

[tex]W_{h}[/tex]×(1/5) +  [tex]W_{b}[/tex]×(1/2) = F₂

985×(1/5) + 3610×(1/2) = F₂

So , F₂ = 2002 N

Substituting the value of force in the equation F₁ + F₂ = 4595 N  ,

we get ,

F₁ + 2002 = 4595

F₁ = 4595 - 2002

F₁ = 2593 N

Therefore , The magnitude of the force at the near end is 2593 N and at the far end is 2002 N .

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Determine the torque around this point created by each force acting on the wrist and select an axis to compute the torques about.

The forearm is the upper limb component that reaches from the shoulder to the wrist. Its bone structure is made up of the ulna and radius which are positioned laterally (medially).

The term "arm" most commonly refers to the entire upper limb appendage, although in anatomy, the phrase "forearm" is used to distinguish it from that.

As a result, the stress exerted by the bicep is 7.38 times more than the weight supported.

The formula for torque is Γ=r×F=rFsin(θ). Torque is, in additional observations, the cross product of the force vector & the distance vector, where a is the angle between r & F.

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The answer is, p(x) = 0.1x + 1          (p(x) is the pressure at a depth x)

Just what is pressure?

The amount of force applied to a certain region is referred to as pressure.

1 atmosphere is the pressure at sea level.

Sydney dove to a depth of 23 meters.

23-meter depth equals 3.3 atmospheres of pressure

23-meter deep pressure equals pressure at sea level plus k.

Sydney dove to a depth of 3.3 meters, where 3.3 = 23 k + 1 is the diving rate constant.

By deducting 1 from either side, we arrive at 3.3 - 1 = 23k + 1 -1.

2.3 = 23k is obtained by eliminating the +1 and -1 from the right side.

After subtracting the 23s from the top and bottom of the left side, we arrive at k = 0.1 by dividing both sides by 23.

When we enter k's value into the equation, we obtain

Pressure at a specific depth is equal to sea level pressure plus k. * Sydney's depth dove

p(x) = 1 + k(x)     [where p(x) is the pressure at a depth x]

=> p(x) = 1 + 0.1(x)

=> p(x) = 0.1x + 1

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Inversely proportional to the rectangular of the angular velocity inversely proportional to kinetic energy no longer depends on the mass of the rotating item.

The kinetic energy  of a rotating body is given as

K=1/ 2 Iω

The moment of inertia relies upon the distribution of mass.

subsequently, the kinetic energy relies upon each distribution of mass and angular pace.

Kinetic energy is the energy an object has due to its movement. If we want to accelerate an object, then we need to apply a force applying a force calls for us to do paintings. After paintings have been accomplished, energy has been transferred to the object, and the object might be shifting at a new steady pace.

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The value of m is 0.534 kg

f1 =0.92  Hz

f2 = 0.58  Hz

Δm = m2 - m1 =  800 g kg

Mass-spring oscillation occurs with a frequency of:

f = (1/2π)√(k/m)

k = m(2πf)²

When we have: we may conclude that k is constant for both trials.

k = k

m1(2πf1)² = m2(2πf2)²

m1 = m2(f2/f1)²

m1 = (m1+Δm)(f2/f1)²

m1 = Δm/((f1/f2)²-1)

m 1 = 0. 800 g/ (0.92/0.58)^2 – 1

= 0.534 kg or 0.53kg or 534 g

A mass m linked to a spring produces an oscillation with a period of 4 s. A spring's time period lengthens by 1 s when a 2 kg additional mass is added to it.

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The expression for [tex]v^{2}_t[/tex] is equal to √5 times of [tex]v^{2}_b[/tex] where [tex]v_t[/tex] and [tex]v_b[/tex] are the velocities of ball at top and bottom of the circle respectively.

Consider the centripetal force at any point.

T – mg cosθ = m v² ⁄ r

T = mg cosθ + m v² ⁄ r

From figure, cosθ = (r – h) ⁄ r

Substitute in the equation of T.

T = m g (r – h) ⁄ r + m v² ⁄ r

  = m ⁄ r (g (r – h) + v²)

But v² = u² – 2 g h

T = m ⁄ r (g r – g h + u² – 2 g h)

 = m ⁄ r (u² – 3 g h + g r)

This is an equation for tension in string.

Now, when ball is at the top of circle

We have,  

v = √(u² – 2 g h)

 = √(5 g r – 2 g ×(2 r))

 = √(5 g r – 4 g r)

 = √(g r)

And, when ball is at the bottom of the circle,

T[tex]_H[/tex] > 0

m ⁄ r ×(u² – 5 g r) > 0

u² – 5 g r > 0

u² > 5 g r

u > √(5 g r)

Hence,[tex]v^{2}_t[/tex] is equal to √5 times of [tex]v^{2}_b[/tex]

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This statement is True because A synchronizer sleeve is moved to the input shaft chain sprocket by the mode fork, which resembles a shift fork in a manual transmission, once four-wheel drive .

When a vehicle has a manual transmission, the driver controls the clutch and selects the appropriate gear. Most drivers believe a manual transmission, or stick gear as it is commonly known, gives them a greater sense of involvement with the car's operation and makes driving more enjoyable.

A manual gearbox is essentially a gear train that allows the driver to select from a variety of gear ratios to operate the vehicle. Higher gear ratios provide less torque but more speed, while lower gear ratios provide more torque but less speed.

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The change in the kinetic energy of the cart during the move is equal to 98.04 J

According to work energy theorem, the net work done W on an object is equal to the change in the kinetic energy of the object.

W = Kf -Ki

Here, Kf is the final kinetic energy and Ki is the initial energy

The work done on an object is,

W=Fd

Here, F is the force applied on the object and dis the displacement of the object.

Equate these two equations.

Ki-K = Fd

ΔK=Fd

The force exerted on the cart is the tension Tin the chord itself. So,

F=T

Calculate the displacement of the cart.

d = √x²+h² −√x²+h²

Substitute 5.0 m for x,, 1.0 m for x,, and 1.60 m for h.

d=√(5.0 m)² +(1.60 m)² - √(1.0 m)² +(1.60 m)²

=3.36 m

Calculate the change in kinetic energy of the cart.

ΔK = Fd

Substitute 28.0 N for F and 3.36 m for d.

ΔK = (28.0 N) (3.36 m)

=94.08 J

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Reflection of light is when light waves bounce off a surface.

Reflection occurs when light traveling through one material bounces off a different material. The reflected light continues to travel in a straight line, but in a different direction.

The incident light ray that land on the surface is called the reflected off the surface while the ray that bounces back is called the reflected ray.

For example, if an individual looks at a bird, light has reflected off that bird and traveled in nearly all directions. If some of that light enters the individual's eyes, it hits the retina at the back of the eyes. An electrical signal is passed to the person's brain, and the brain interprets the signals as an image.

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The height of the cliff will be equal to 5.37 meters, and the time taken to reach the ground if it is thrown straight down with the same speed will be equal to 0.50 s.

The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.

The maximum speed that can be maintained when a time period grows closer to zero is the starting speed.

As per the given information in the question,

Use the equation given below to find the vertical height of the cliff.

y = y₀ + ut + 1/2 at²

Here,

y represents final position of the object

y₀ is the initial position of the object and t is the time interval.

So,

y₀ = y -ut -1/2at²

y₀ = 0 - (8.16)(2.17) - 1/2(-9.8)(2.17)²

= -17.70 + 23.07

= 5.37 meters.

(b)

Now again rearrange the equation,

y = y₀ + ut + 1/2at² for y - y₀

Now, find the quadratic equation in time,

t = -u ± √[u² - 4(1/2a)(y₀ - y)]/2(1/2a)

Put the values in the above equation,

= -(-8.16 m/s) ± √[(-8.16)² - (-9.8)(2)(5.37)]

= [8.16 ± √(66.58 + 105.25)]/-9.8

= [8.16 ± 13.1]/-9.8

= -4.94/-9.8 = 0.50 s.

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Think about a single Rb atom held at t0. if allowed (from rest). See McIntyre 6.40 for a hint. There, the solution is (x, t) = (2p) TTT, with 9-2h/m. (You must determine dimensionless constant .)

Rubidium-87 has a positive scattering length at low temperatures, making it mutually repulsive despite rubidium-85's greater abundance. This prevents all condensates bar the tiniest ones from collapsing.

As a getter, rubidium is a substance that mixes with and extracts trace gases from vacuum tubes. Additionally, it is utilized in the creation of specialty glasses and photocells. It is easily ionized, 

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Statement about saturn's rings is not true is that the rings must look much the same today as they did shortly after saturn formed.

Saturn, the most beautiful planet in our solar system, is famous for its dazzling rings. These rings extend far into space and engulf many of Saturn’s moons. The brightest rings, visible from Earth in a small telescope, include the D, C and B rings, Cassini’s Division.

The A ring. Just outside the A ring is the narrow F ring, shepherded by tiny moons, Pandora and Prometheus. Beyond that are two much fainter rings named G and E. Saturn's diffuse E ring is the largest planetary ring in our solar system, extending from Mimas' orbit to Titan's orbit, about 1 million kilometers.

The particles in Saturn's rings are composed primarily of water ice and range in size from microns to tens of meters. The rings show a tremendous amount of structure on all scales. Some of this structure is related to gravitational interactions with Saturn's many moons, but much of it remains unexplained.

One moonlet, Pan, actually orbits inside the A ring in a 330-kilometer-wide (200-mile) gap called the Encke Gap. The main rings (A, B and C) are less than 100 meters (300 feet) thick in most places. The main rings are much younger than the age of the solar system, perhaps only a few hundred million years old.

Hence, the correct option is A.

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I answered it in general way

Since the field is divided into subplots and a random sample is selected from each subplot, stratified sampling is used.

Sampling is the procedure used by researchers to choose a subset of participants from a larger group, given that it is usually impossible to evaluate the entire population. In the case of stratified sampling, this entails breaking the overall population into smaller groups, known as strata, and then choosing a particular number of people from each strata. This approach ensures that the sample is chosen at random, ensuring the objectivity of the research. The approach used in the example provided was stratified sampling since a 46-acre field's general population was separated into subplots that represent was split up into smaller plots that stand in for the strata. The researcher then chose one random sample following that.

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Answer:

Aluminium is extracted from bauxite. Bauxite is the name for the ore in which around 30 to 54% of the aluminium oxide is contained. Because of the fact that aluminium has a tendency to bind with oxygen, there is very little pure aluminium found naturally.

Explanation:

In 3.5 minutes, the electromagnetic energy of the signal stated above, 71.45 pJ, is reflected to the main receiver.

Intensity = 0.75 x 10⁻¹² W/m²

Intensity = Power / Area

here, Area = A = π r = π (0.38)² = 0.4536 m²

so, Power = 0.75 x 10⁻¹² x 0.4536 = 3.402 x 10⁻¹³ W

Energy = Power x time

here, time = 3.5 minutes = 3.5 x 60 seconds

therefore, energy reflected = 3.402 x 10⁻¹³ x 3.5 x 60 = 71.45 x 10⁻¹² J = 71.45 pJ

this is the energy reflected the central receiver in 3.5 minutes.

Radiation with electromagnetic properties is electromagnetic energy. The energy connected to electromagnetic waves is commonly referred to by this phrase. Energy is what causes these waves to move through any medium. Photons, a unit of light energy that electromagnetic radiation travels in, are free of charge and mass. One of the most significant elements in the cosmos is electromagnetic energy. The force behind the electromagnetic waves is it.

When a force outside of the electrical charge accelerates it, electromagnetic energy is released. As a result of the acceleration, a wave of alternating magnetic and electric fields is created. This wave separates from the charge and flows independently through the medium.

The discrete energy packets known as photons make up electromagnetic waves.

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If the mass of one of the objects were to be doubled, then the gravitational force between the two masses would be 2 times greater than it was originally.

The gravitational force between two masses is given by the equation:

F = G x (m1 x m2) / r^2

where F is the gravitational force, G is the gravitational constant (equal to 6.67 x 10^-11 Nxm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them. If the mass of one of the objects is doubled, the gravitational force between the two masses will also be doubled. This is because the gravitational force is directly proportional to the masses of the two objects. Therefore, if the mass of one of the objects is doubled, the gravitational force between the two masses will be 2 times greater than it was originally.

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A GFCI measures the amount of current that flows from hot to neutral.

What is circuit ?

A circuit is a closed channel in electronics that permits electricity to flow from one place to another. It may contain a variety of electrical components such as transistors, resistors, and capacitors, but the flow is not hampered by a gap or break in the circuit.

A simple circuit is illustrated using a flashlight. When the switch is turned off, the circuit is not closed, which means that no electrical current flows from the batteries to the flashlight's bulb. When you turn the switch on, a piece of metal in the flashlight physically plugs the circuit gap. Electricity goes from the batteries to the bulb, causing it to light up.

A GFCI measures the amount of current that flows from hot to neutral. If there is an imbalance, the circuit will trip. The GFCI detects mismatches as tiny as 4 or 5 milliamps and can respond in as little as one-thirtieth of a second.

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Answer:

0.500 m/s south

Explanation:

To find Patrick's average velocity for the trip, you need to find the total distance traveled and the total time taken for the trip.

Patrick walks 70.0 meters south in 150.0 seconds, for a total distance traveled of 70.0 meters. He then walks 20.0 meters north in 30.0 seconds, for a total distance traveled of 20.0 meters. The total distance traveled for the trip is therefore 70.0 + 20.0 = 90.0 meters.

The total time taken for the trip is 150.0 seconds + 30.0 seconds = 180.0 seconds.

The average velocity for the trip is the total distance traveled divided by the total time taken, so the average velocity is 90.0 meters / 180.0 seconds = 0.500 m/s.

Therefore, the correct answer is 0.500 m/s south.

The current concentration of carbon dioxide in the atmosphere is far higher than the natural range over the last 650,000 years, and is increasing rapidly for several reasons. Some of the main factors that have contributed to this increase include:

Overall, the current high levels of carbon dioxide in the atmosphere are the result of human activities, such as the burning of fossil fuels and deforestation, which have released large amounts of carbon dioxide into the atmosphere. These activities have led to a rapid increase in the concentration of carbon dioxide in the atmosphere, far beyond the natural range of concentrations over the last 650,000 years.

The smaller wavelength is 121.49515 nm and the larger wavelength is 121.4956866 nm.

It is the series of spectral lines which results in emission of UV radiations.

It happens when electron goes from n≥ 2 to n = 2

where, n = principle quantum number

The first line of Lyman series occur due to transition of electrons from n=1 to n=2

If we consider the '2p' level

The first transition of Lyman series

Energy:

-3.4015 eV ; n=2

-13.606eV ; n=1

ΔE = 4.5 * 10⁻⁵eV

Given

hc = 1239.8 eV(nm)

We know wavelength of radiation emitted is

\lambda = hc / (E₂-E₁)

If e⁻ transition occurs from n = 2P(3/2) to n = 1

E₂ - E₁ = -3.4015 eV + ΔE/2 + 13.606 eV

E₂ - E₁ = 10.2045225 eV

If e⁻ transition occurs from n = 2P(1/2) to n = 1

E₂ - E₁ = -3.4015 eV + ΔE/2 + 13.606 eV

E₂ - E₁ = 10.2044775 eV

Smaller value of wavelength = hc/E₂-E₁ = 1239.8/10.2045225 = 121.49515 nm

Larger value of wavelength = hc/E₂-E₁ = 1239.8 / 10.2044775 = 121.4956866 nm

Therefore the smaller wavelength is 121.49515 nm and the larger wavelength is 121.4956866 nm.

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The  (2) and (3), that contact force in case (a) is greater than in case (b).

What is force ?

Everyday activities like walking, setting something down on a surface, tossing something into the air, and even the tides' regular variations all include the application of force. The result of the interaction between two or more things, a force is a push or a pull.

What is acceleration ?

Acceleration is the rate at which velocity changes, as well as how quickly velocity changes over time. instantaneous acceleration is an acceleration at a single moment instantaneous acceleration divided by time deceleration

N1 and N2 are normal forces

T1 and T2 are contact force , (equal in magnitude, but opposite in direction)

i.e |T1| - |T2|

here for both case, acceleration

a = Fo/m1+ m2

a = Fo/M + 3M = Fo/um -(1)

acceleration for both cases remains same, as two blocks move with a single force fo, together

Fo – T2 = Ma or T1 = 3Ma

= T1 = 3M (Fo/4M)

T1 = 3/4  Fo –(2)

Fo – T2 = 3Ma

         T2 = Ma

         T2 = M (Fo/4) – (3)

It is obvious from (2) and (3), that contact force in case (a) is greater than in case (b).

Therefore, (2) and (3), that contact force in case (a) is greater than in case (b).

Learn more about force from the given link.

https://brainly.com/question/388851

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