An object is released from rest from a top of a building 90 meters high. Neglect air friction.
What is the volume of its acceleration?
Calculate the time it takes to reach the floor?
With what velocity does it reach the floor?
How fast is it moving when it is 50 meter above the floor?

Answers

Answer 1

Answer:

1. a = 9.8 m/s²

2. t = 4.28 s

3. Vf = 42 m/s

4. Vf = 28 m/s  

Explanation:

1.

Since, the body is under free fall motion. Therefore, the value of its acceleration shall be equal to the acceleration due to gravity.

a = 9.8 m/s²

2.

The time taken by the ball to reach the ground can be calculated by using second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 90 m

Vi = initial velocity = 0 m/s

t = time taken = ?

Therefore,

90 m = (0 m/s)t + (1/2)(9.8 m/s²)t²

t = √(18.36 s²)

t = 4.28 s

3.

In order to find final velocity we use first equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(4.28 s)

Vf = 42 m/s

4.

when the ball is at height of 50 m, it means it has covered:

h = 90 m - 50 m = 40 m

we use third equation of motion at this point:

2gh = Vf² - Vi²

(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²

Vf = √(784 m²/s²)

Vf = 28 m/s


Related Questions

Which value represents accuracy: the mean, median, mode, range from center, or distance between farthest beanbags?

Answers

Answer:

the mean

Explanation:

The mean (informally, the “average“) is found by adding all of the numbers together and dividing by the number of items in the set: 10 + 10 + 20 + 40 + 70 / 5 = 30. The median is found by ordering the set from lowest to highest and finding the exact middle. The median is just the middle number: 20.

What is the dependent variable in this hypothesis?
After finding that objects of the same mass do not
always float or submerge the same way in a tub of
liquid, Alexis wrote a new hypothesis to test objects that
have the same mass.
o the mass of the object
O the surface area of the object
O the amount of water displaced
O the height at which the object floats
If the surface area of an object increases, then it
will float higher in the tub, because the object
would need to displace more liquid in order to sink
all the way down.

Answers

Answer:

The height at wich the object floats

Explain

took on edge 2020

Answer:

the height at which the object floats

Edge 2021

When a gas undergoes an isothermal process, there is
(A) no heat added to the gas.
(B) no work done by (or on) the gas.
(C) no change in the temperature of the gas.
(D) no change in the volume of the gas.
(E) no change in the pressure of the gas.

Answers

Answer:

(C) no change in the temperature of the gas.

Explanation:

isothermal process of a gas, can result to compression of the gas or expansion of the gas at a constant temperature (ΔT = 0).

For isothermal gas expansion, work is done in reducing the pressure of the gas by increasing its volume at a constant temperature. The change in the internal energy of this process is zero (ΔU = 0).

For isothermal gas compression, work is done in decreasing the volume of the gas by increasing its pressure at a constant temperature. The change in the internal energy of this process is also zero (ΔU = 0).

Therefore, when a gas undergoes an isothermal process, there is no change in the temperature of the gas.

You are jogging with a velocity of 2 meters/second to the west, when you feel thirsty and stops to drink water after 5 seconds. First find your velocity the moment you stopped running. Then, find your acceleration during that motion. What are the units for acceleration? What is the direction of acceleration in this motion? Show your work.

Answers

Answer:

The velocity when the runner stopped is v =0 m/s

The acceleration is [tex]a = 0.4 \ m/s [/tex]

Explanation:

From the question we are told that

The initial velocity is [tex]u = 2 \ m/s[/tex]

The time taken is [tex]t = 5 \ s[/tex]

Generally from the question we are told that the person stopped running so the person velocity at that moment is v =0 m/s

Now the acceleration is mathematically represented as

[tex]a = \frac{v - u}{t}[/tex]

=> [tex]a = \frac{0 - 2}{5}[/tex]

=> [tex]a = 0.4 \ m/s [/tex]

A woman walks 150 min 45 seconds. What was her average speed?

Answers

Answer:

0.3

Explanation: when you average out the number sthat is the answer you get

0.3 , when you averaged out the number that what you get

A nucleus with a mass number of 64 has a mean radius of about: _________.
A. 4.8 fm.
B. 19 fm.
C. 77 fm.
D. 260 fm.
E. 2.6 × 10 5 fm

Answers

Answer:

The correct option is A

Explanation:

From the question we are told that

The mass number is [tex]A= 64[/tex]

Generally the mean radius is mathematically evaluated as

[tex]R = R_o A^{\frac{1}{3} }[/tex]

Here [tex]R_o[/tex] is a constant with a value  [tex]R_o =1.2*10^{-15}[/tex]

So  

     [tex]R  =  1.2*10^{-15} *  64^{\frac{1}{3} }[/tex]

      [tex]R  =   4.8 *10^{-15} [/tex]

        [tex]R  =   4.8\ fm [/tex]

The mean radius of a nucleus with the given mass number is 4.8 fm.

Hence, Option A. 4.8 fm is the correct answer.

Given the data in the question;

Mass number of nucleus; [tex]A = 64[/tex]

Mean radius; [tex]R =\ ?[/tex]

The volume of the nucleus is directly proportional to the total number of nucleons.

The radius of a nucleus, R, is approximately:

[tex]R = R_oA^{\frac{1}{3} }[/tex]

Where R is the radius, R₀ is constant for all nuclei ([tex]1.2*10^{-15}m \ or\ 1.2fm[/tex] ) and A is the mass number.

We substitute our values into the equation

[tex]R = 1.2fm\ *\ 64^{\frac{1}{3} }\\\\R = 1.2fm\ *\ 4\\\\R = 4.8 fm[/tex]

The mean radius of a nucleus with the given mass number is 4.8 fm.

Hence, Option A. 4.8 fm is the correct answer.

Learn more: https://brainly.com/question/1371394

What does a diagonal upward sloping line on a position time graph mean?

Answers

diagonal line means the velocity is constant.

Fossil fuels like gasoline or coal are examples of

Answers

Answer:

Nonrenewable Resources

Answer:

fossil fuels

Explanation:

A highway curve with radius R = 274 m is to be banked so that a car traveling v = 25.0 m/s will not skid sideways even in the absence of friction. At what angle should the curve be banked? 2. what is the correct equation for the sum of the forces in the x direction? What is the correct equation for the sum of the forces in the y direction? A. ΣFx:−Nsinθ=mv2/R; ΣFy:Ncosθ−mg=0 B. ΣFx:−Ncosθ=−mv2/R; ΣFy:Nsinθ−mg=0 C. ΣFx:Nsinθ=mv2/R; ΣFy:Ncosθ+mg=0 D. ΣFx:−Nsinθ=mv2/R; ΣFy:Ncosθ=0 E. ΣFx:−Nsinθ=−mv2/R; ΣFy:Ncosθ−mg=0

Answers

Answer:

A)   θ = 13.1º  , B)  E

Explanation:

A) For this exercise, let's use Newton's second law, let's set a reference frame where the axis ax is in the radial direction and is horizontal, the axis y is vertical.

In this reference system the only force that we must decompose is the Normal one, let's use trigonometry

        sin θ = Nₓ / N

        cos θ = [tex]N_{y}[/tex] / N

        Nₓ = N sin θ

       Ny = N cos θ

x-axis (radial)

        Nₓ = m a

where the acceleration is centripetal

         a = v² / R

we substitute

        -N sin θ = -m v² / R                   (1)

the negative sign indicates that the force and acceleration towards the center of the circle

y-axis (Vertical)

          Ny - W = 0

           N cos θ = mg

           N = mg / cos θ

we substitute in 1

          mg / cos θ  sin θ = m v² / R

          g tan θ = v² / R

          θ = tan⁻¹ (v² / gR)

we calculate

        θ = tan⁻¹ (25² / 9.8 274)

        θ = 13.1º

B) when comparing the equations the correct one is E

Hitting a ball off a tee would be considered which of the following?

A.

A closed serial skill

B.

An open continuous skill

C.

An open discrete skill

D.

A closed discrete skill

Answers

I think the answer would be B

The overall length of a piccolo is 30.0 cm. The resonating air column is open at both ends. (a) Find the frequency of the lowest note a piccolo can sound. (Assume that the speed of sound in air is 343 m/s.) Hz (b) Opening holes in the side of a piccolo effectively shortens the length of the resonant column. Assume the highest note a piccolo can sound is 3 000 Hz. Find the distance between adjacent antinodes for this mode of vibration.

Answers

Answer:

(a)  the frequency of the lowest note the piccolo can sound is 571.7 Hz

(b) the distance between adjacent antinodes is 5.72 cm

Explanation:

(a)

Given;

length of piccolo, L = 30 cm = 0.3 m

the speed of sound in air is 343 m/s

The wavelength of a pipe open at both ends, for the first harmonic is given;

L = A → N + N → A

L = λ / 4 +  λ / 4

L = λ / 2

λ = 2L

λ = 2 x 0.3 = 0.6 m

The fundamental frequency (lowest frequency) is given  by;

f₀ = v / λ

f₀ = (343 / 0.6)

f₀ = 571.7 Hz

(b)

Given;

highest note, f = 3000 Hz

the distance between adjacent antinodes is given by;

[tex]d = \frac{v}{2f}\\\\ d = \frac{343}{2*3000}\\\\ d = 0.0572 \ m\\\\d = 5.72 \ cm[/tex]

lol
idk what this is​

Answers

Answer:

I know

Explanation:

Physics= hard

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(b) If you decrease the length of the pendulum by 25%, how does the new period TN compare to the old period T?

Answers

Answer:

The new period will be reduced by 50%

Explanation:

The period of pendulum is given by;

[tex]T= 2\pi\sqrt{\frac{L}{g} }\\\\\frac{T}{2\pi} = \sqrt{\frac{L}{g} }\\\\(\frac{T}{2\pi} )^2 = {\frac{L}{g}}\\\\\frac{T^2}{4\pi ^2} = {\frac{L}{g}}\\\\T^2(\frac{g}{4\pi ^2}) = L\\\\ \frac{g}{4\pi ^2}= \frac{L}{T^2}\\\\\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}[/tex]

When the length is decreased by 25%, the new length L₂ is given by;

L₂ = 25/100(L₁)

L₂ = 0.25L₁

[tex]\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}\\\\T_2^2 = \frac{T_1^2L_2}{L_1} \\\\T_N^2 = \frac{T^2(0.25L_1)}{L_1}\\\\ T_N^2 =0.25T^2\\\\T_N = \sqrt{0.25T^2}}\\\\T_N = 0.5 T[/tex]

Thus, the new period will be reduced by 50%

What is the ultimate source of energy for an ecosystem?

Answers

Answer:

Obviously the answer is Sun...

Using the equation for for Newton's Second law, F=ma, solve the following problem. You have been given an object with a mass of 6g and an acceleration of 2 m/s2, what is the force?
Group of answer choices
A. 12N

B. 3N

C. 8N

D. 120N

Answers

Answer:

F = 0.012 N

Explanation:

Given that,

Mass of the object, m = 6 g

Acceleration, a = 2 m/s²

1 kg = 1000 grams

6 g = 0.006 kg

Force, F = ma

So,

[tex]F=0.006\ kg\times 2\ m/s^2\\F=0.012\ N[/tex]

So, the force is 0.012 N.

If horizontal velocity is 5 m/s, and vertical velocity is 8 m/s, what is the magnitude of the resultant velocity?

Answers

Answer:

40 m/s

Explanation:

Earth's atmosphere is constantly bombarded by cosmic ray protons that originate somewhere in space. If the protons all passed through the atmosphere, each square meter of Earth's surface would intercept protons at the average rate of 1800 protons per second. What would be the electric current in amperes intercepted by a 41 × 107 km2 area on the planet

Answers

Answer:

Electric current in amperes = 1.1808 A

Explanation:

Given:

Intercept protons rate = 1800 protons per second

Area = 41 × 10⁷ km²

Find:

Electric current in amperes

Computation:

Current density = Intercept protons rate × 1.6 × 10⁻¹⁹

Current density = 1800 × 1.6 × 10⁻¹⁹

Current density = 2.88 × 10⁻¹⁶

1 km² = 10⁶m²

So,

Electric current in amperes =  2.88 × 10⁻¹⁶ × 41 × 10⁷ × 10⁶

Electric current in amperes = 1.1808 A

5. Why does a properly adjusted head restraint help prevent head and neck injuries to occupants in
rear-end collisions? Explain your answer in terms of the law of conservation of momentum.

Answers

Answer:

Have you tried google

Explanation:

Answer:

protect against whisplasg injuries

What is an example of intellectual development?

Answers

Answer:

learning new activities like riding a bike and playing sports. and also having the ability to collect information and remember them (memory). <3

There are four types of intellectual property rights (IP): patents, trademarks, copyrights, and trade secrets

Where do you feel that you are traveling at the fastest speed when on the swing?

Answers

Answer:

C

Explanation:

I think it's C, because at that point, you are going fastest. Sorry if im wrong, hope this helps.

Answer:

In between and the middle one

Explanation:

An excited squirrel starts from rest and accelerates towards a nut at 1.0 m/s2 for 2.0 seconds. What is the squirrel’s displacement?

Answers

Answer:

[tex]x=8m[/tex]

Explanation:

Hello,

In this case, the most suitable kinematic equation for the calculation of the squirrel's displacement is:

[tex]x=v_ot+\frac{1}{2}at^2[/tex]

Whereas the initial velocity is zero as it starts from rest, thus, we obtain:

[tex]x=\frac{1}{2}*1.0\frac{m}{s^2}*(2.0s)^2\\ \\x=8m[/tex]

Best regards.

I'm confused, and I can't seem to get this question right. someone please help. Only two forces act on an object (mass = 5.00 kg), as in the drawing. (F = 55.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object. (Drawing: 45 degrees, Fx is 40 N)

Answers

Answer:

17.6 m/s², 26.2° above x axis

Explanation:

Apply Newton's second law.

Sum of forces in the x direction:

∑Fₓ = ma

40 N + 55.0 N cos 45° = (5.00 kg) aₓ

aₓ = 15.8 m/s²

Sum of forces in the y direction:

∑Fᵧ = ma

55.0 N sin 45° = (5.00 kg) aᵧ

aᵧ = 7.78 m/s²

Use Pythagorean theorem to find the magnitude of the resultant.

a² = aₓ² + aᵧ²

a² = (15.8 m/s²)² + (7.78 m/s²)²

a = 17.6 m/s²

Use trigonometry to find the angle.

tan θ = aᵧ / aₓ

tan θ = (7.78 m/s²) / (15.8 m/s²)

θ = 26.2°

A small block with mass 0.200 kg is released from rest at the top of a frictionless incline. The block travels a distance 0.394 m down the incline in 2.00 s. The 0.200 kg block is replaced by a 0.400 kg block. If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s

Answers

Answer:

The distance traveled by the second block is 0.197 m

Explanation:

Given;

mass of the small block, m₁ = 0.2 kg

distance traveled by the block, d₁ =0.394 m

time of travel, t = 2 s

mass of the second block, m₂ = 0.4 kg

distance traveled by the second block, d₂ = ?

The work done per unit time on the inclined plane is given by;

[tex]\frac{f_1d_1}{t} = \frac{f_1d_1}{t}\\\\f_1d_1 = f_2d_2\\\\m_1gd_1 = m_2gd_2\\\\m_1d_1 = m_2d_2\\\\d_2 = \frac{m_1d_1}{m_2} \\\\d_2 = \frac{0.2*0.394}{0.4}\\\\d_2 = 0.197 \ m[/tex]

Therefore, the distance traveled by the second block is 0.197 m

An unstrained horizontal spring has a length of 0.34 m and a spring constant of 180 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.024 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges. g

Answers

Answer:

a

         [tex]q_1 = -1.389 *10^{-5} \  C [/tex]   , [tex]q_2 = -1.389 *10^{-5} \  C [/tex]

OR

           [tex]q_1 = 1.389 *10^{-5} \  C [/tex]   , [tex]q_2 = 1.389 *10^{-5} \  C [/tex]    

b

[tex]q_1 = 1.389 *10^{-5} \ C [/tex] and [tex]q_2 = 1.389 *10^{-5} \ C [/tex]

Explanation:

Generally the force exerted on the string is mathematically represented as

[tex]F = k * e[/tex]

substituting values 180 N/m for k and 0.024 m for e

[tex]F = 180 * 0.024[/tex]

[tex]F = 4.32 \ N[/tex]

This force can also equivalent to the electrostatic force between the charges i.e

[tex]F = k * \frac{q^2}{ r^2}[/tex]

substituting [tex]9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex] for k and ( 0.34 + 0.024 = 0.364 m) for r we have

[tex] 4.32= 9*10^{9} * \frac{q^2}{ (0.364)^2}[/tex]

[tex]q = \sqrt{1.929 *10^{-10}}[/tex]

[tex]q = 1.389 *10^{-5} \ C [/tex]

Given the spring was stretched it means that the force between the charges is a repulsive for which tell us that both charge are of the same sign thus the possible  algebraic signs  of the charges are

         [tex]q_1 = -1.389 *10^{-5} \  C [/tex]   , [tex]q_2 = -1.389 *10^{-5} \  C [/tex]

OR

[tex]q_1 = 1.389 *10^{-5} \ C [/tex] , [tex]q_2 = 1.389 *10^{-5} \ C [/tex]

What was the current annual rate of inflation in 2009?
pls help !

Answers

Answer:

The 2009 inflation rate was -0.36%. The current year-over-year inflation rate (2019 to 2020) is now 0.99%

Explanation:

how do accelerating objects act

Answers

Explanation:

They speed up, slow down, or change direction.

Answer:In order for object to be accelerating, the net force (sum of all forces) acting on the object has to be non-zero. According to Newton's Second Law of Motion, Force = Mass x Acceleration. ... If the object is sitting motionless on the ground, then the net force (sum of all forces) acting on it is zero.

Explanation:

1. Looking at the planet vs. eccentricity table, which two planets have the greatest eccentricity?

Answers

Answer:

Pluto & Mercury

Explanation:

Pluto's eccentricity is 0.248

Mercury's eccentricity is 0.206

What is the mass of the cube
Density is 40 g/cm3
Length of the side= 2 cm

Answers

Answer:

80

Explanation:

because of the denstiy formula

how to find range with height and velocity

Answers

Answer:

[tex]R= \frac{ v_ i\: ^2\:\times sin\:20}{g}[/tex]

Explanation:

A cyclist accelerates from rest to 8 m/s in 3 seconds. How far did the cycles travel in 3 seconds?​

Answers

Answer:

[tex] \boxed{\sf Distance \ travelled = 12 \ m} [/tex]

Given:

Initial speed (u) = 0 m/s (Accelerates from rest)

Final speed (v) = 8 m/s

Time taken (t) = 3 seconds

To Find:

Distance travelled by cyclist (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

[tex] \boxed{ \bold{s = (\frac{v + u}{2} )t}}[/tex]

By substituting value of v, u & t in the equation we get:

[tex] \sf \implies s = ( \frac{8 + 0}{2} ) \times 3 \\ \\ \sf \implies s = \frac{8}{2} \times 3 \\ \\ \sf \implies s = 4 \times 3 \\ \\ \sf \implies s = 12 \: m[/tex]

[tex] \therefore[/tex]

Distance travelled by cyclist (s) = 12 m

Answer:

s(distance) =36m

Explanation:

u(initial velocity) =0 m/s

a =8 m/s^2

t=3s

s=ut+1/2at^2

s=1/2(8)(3)^2

s=1/2(8)(3)(3)

s=4(9)

s=36m

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