an object at the origin at time has velocity measured in meters per second, when, if ever, does the object return to the origin? t/40 . see example 5 on page 239 of the textbook for a similar problem. hint: you are looking for the time such that .

Answers

Answer 1

For the given velocity function , the object will not return to the origin .

In the question ,

it is given that ,

the velocity function is v(t) = { t/35  , 0 ≤ t ≤ 70

                                               { 2    ,  70 ≤ t ≤ 175

                                               { 7 - t/35  ,   175 < t  .

So , For t ≤ 175 , velocity is positive ,

So , [tex]\int\limits^T_0 {v(t) } \, dt[/tex]  = [tex]\int\limits^{70}_0 {t/35 } \, dt[/tex]  +  [tex]\int\limits^{175}_{70} {2 } \, dt[/tex]  + [tex]\int\limits^{T}_{175} {(7 - t/35) } \, dt[/tex]

On integrating ,

we get ,

x(T) = [t²/70]⁷⁰₀  + [2t]¹⁷⁵₇₀  + [7t - t/70[tex]]^{T} _{175}[/tex]

x(T) = (70 - 0) + (350 - 0) + (7T - T²/70) - (1225 - 875/2)

x(T) = 420 + 7T - T²/20 - 1575/2

x(T) = -T²/20 + 7T - 735/2

x(T) = ( -T² + 140T - 7350)/20

For the object to return to the origin , x(T) = 0

So , (-T² + 140T - 7350)/20 = 0

T² - 140T + 7350 = 0

Therefore , Discriminant (D) = b² - 4ac

= (-140)² - 4(1)(7350)

= 19600 - 29400

= -9800 < 0 .

So , the root is imaginary , hence at no value of T , the object will not return to the origin for the given information .

Therefore , the object will not return to the origin .

The given question is incomplete , the complete question is

An object at the origin at time has velocity  

                                      v(t) = { t/35  , 0 ≤ t ≤ 70

                                               { 2    ,  70 ≤ t ≤ 175

                                               { 7 - t/35  ,   175 < t  .

measured in meters per second, when, if ever, does the object return to the origin ?

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An Object At The Origin At Time Has Velocity Measured In Meters Per Second, When, If Ever, Does The Object

Related Questions

is y=-2x - 4 proportional?

Answers

Answer:

It does not represent a proportional relationship

Step-by-step explanation:

Answer:

It does not represent a proportional relationship

Step-by-step explanation For a line, the constant of proportionality is a fancy way to say the slope. It makes more sense without the intercept: y=2xclearly, the constant of proportionality is 2.

let r be the distance from a uniformly randomly chosen point in the unit disk and the origin (0,0). find the probability density function fr(r) and cumu- lative distribution function fr(r) of r. (hint: do not attempt to use your answer from part (a)).

Answers

The probability density function fr(r) of the distance from a uniformly randomly chosen point in the unit disk to the origin is r, and the cumulative distribution function Fr(r) is (r² / 2).

To find the probability density function (PDF) and cumulative distribution function (CDF) of the distance from a uniformly randomly chosen point in the unit disk to the origin, we can first find the area of the unit disk and the area of the annulus centered at the origin and bounded by two circles with radii r and r + dr. The PDF is then the ratio of the area of the annulus to the total area of the unit disk, and the CDF is the ratio of the area of the annulus to the total area of the unit disk up to radius r.

The area of the unit disk is simply the area of a circle with radius 1, which is pi. The area of the annulus centered at the origin and bounded by two circles with radii r and r + dr is equal to the difference between the areas of the two circles, which is pi(r + dr)² - pi(r²). Therefore, the PDF of r is:

fr(r) = [pi(r + dr)² - pi(r²)] / pi = r + dr²

The CDF of r is the sum of the PDFs up to radius r, which is:

Fr(r) = ∫fr(t)dt from 0 to r = ∫(t + dt²)dt from 0 to r = (r² / 2) + (r × dt) + (dt³ / 3)

We can take the limit as dt approaches 0 to get the final expression for the CDF:

Fr(r) = (r² / 2)

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PLEASE HELP
find the sum of ( 2.25 x 10^19) and ( 6.7 x 10^17) Write the answer using proper scientific notation.

A) 231.7 X 10^15

B) 2.317 X10^19

C) 231.7 X 10^17

D) 2.317 X 10^15

Answers

Answer:

Step-by-step explanation:

The sum of (2.25 x 10^19) and (6.7 x 10^17) is (2.317 x 10^19).

To find the sum of these two numbers, we first need to line up the decimal points and add the numbers as we would with any other addition problem:

2.25 x 10^19

+ 6.7 x 10^17

Then, we can carry the 1 and add the numbers:

2.25 x 10^19

6.7 x 10^17

2.317 x 10^19

The sum of these two numbers is 2.317 x 10^19, which is equal to choice B.

Reason
The coordinates of point D are (4, 5) and coordinates of point E are (5, 3) By the midpoint formula
Length of segment DE is √√5 and length of segment AC is 2√5
Segment DE is half the length of segment AC
Slope of segment DE is -2 and slope of segment AC is -2
Segment DE is parallel to segment AC
Which of the following completes the proof? (6 points)
Statement
By the addition property
By the distance formula
By construction
Given
By substitution
By the slope formula
Slopes of parallel lines are equal

Answers

The required solutions following the sequence are given as,
(a) By the distance formula,
(b) By the addition of property,
(c) By the slope formula slopes of parallel lines are equal.

Here,
The coordinates of point D are (4, 5) and the coordinates of point E are (5, 3)
The distance formula is given as,

D = √[[x₂ - x₁]² + [y₂+ - y₁]²]


By distance formula,
DE = √5

Segment DE is half the length of segment AC
AC = DE + DE
AC = 2DE
AC = 2√5

The property used is an addition property.

Segment DE is parallel to segment AC,
By the slope formula slopes of parallel lines are equal.

Thus, the complete reasoning of the solution is shown above.

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8−
n
m

+p
2
8, minus, start fraction, m, divided by, n, end fraction, plus, p, squared when m=8m=8m, equals, 8, n=2n=2n, equals, 2, p=7p=7p, equals, 7.

Answers

The required simplified value o the given expression is 53.

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Given expression,
= 8 - m/n + p²

Now, put m = 8 n = 2 and p = 7

So,
= 8 - 8 / 2 + 7²
= 8 - 4 + 49

= 4 + 49

= 53

Thus, the required simplified value o the given expression is 53.

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A rectangle has length that is 4 inches greater than twice its width. The perimeter of the rectangle is 26 inches. What is the area?

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A rectangle has length that is 4 inches greater than twice its width. The permitted of the rectangle is 26 inches. What is the area?

The lifetime X of a certain brand of sixty-watt light bulb is exponentially distributed with population mean 1000 hours, that is, 5.23 1 e/1000 1000 f(x) x > 0. If 30 light bulbs having this lifetime distribution are placed on test, find the probability that 10 or fewer of these light bulbs survive to time 1200 by (a) writing a mathematical expression, (b) giving an R statement that will compute the probability.

Answers

The function given by f(x) = 1/1000×e^(-x/1000) is the expression that represents the function that 10 or fewer of the bulbs survive to time 1200.

Given, the lifetime X of a certain brand of sixty-watt light bulb is exponentially distributed with population mean 1000 hours.

That is, 5.231(e/1000)f(x) x > 0. I

f 30 light bulbs having this lifetime distribution are placed on test.

we have to find the probability that 10 or fewer of these light bulbs survive to time 1200.

as, we have to find the expression for the function f(x) so that 10 or fewer of the given light bulbs survive to time 1200.

f(x) = 1/1000×e^(-x/1000)

So, the function given by f(x) = 1/1000×e^(-x/1000) is the expression that represents the function that 10 or fewer of the bulbs survive to time 1200.

Hence, the function given by f(x) = 1/1000×e^(-x/1000) is the expression that represents the function that 10 or fewer of the bulbs survive to time 1200.

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use the reflection method to find a green's function that solves the problem on a semicircular region-AG(x, xo)= მ (x-xo) G(x, xo)=0 მ/მy G(x, xo) = 0in Ω = {x=(x, y): x^2+y^2 <1, y>0}, on T1 = {x=(x, y): x^2+y^2=1, y>0}, on T2 = {x=(x, 0): -1< x <1},

Answers

The Green's function that solves the problem on a semicircular region is given by G(x, xo) = მ (x-xo)(cos(θ)sin(θ)).

What is Green's function?

Green's function is an important mathematical tool used to solve differential equations. It is defined as a solution to a homogeneous linear differential equation with a source, or delta, function as its input. Green's functions are also known as impulse response functions and can be used to describe the response of a system to an arbitrary input. Green's functions provide a way to solve differential equations without having to solve the entire equation all at once. They are particularly useful for solving equations with boundary conditions that are difficult to solve without the use of Green's functions. Green's functions can also be used to solve integral equations and provide a powerful tool for solving many physical problems.

The reflection method for finding a Green's function for a problem on a semicircular region can be used as follows. First, we solve the problem on the half-plane by finding a Green's function G(x, xo) that satisfies the boundary conditions given. Then, we reflect the solution across the boundary of the semicircle, namely T1 and T2, to obtain the Green's function on the entire semicircle.
The Green's function on the half-plane is given by G(x, xo) = მ (x-xo). Using this solution, we can reflect it across the boundary of the semicircle. For T1, the reflected solution is given by G(x, xo) = მ (x-xo)cos(θ), where θ is the angle between the normal vector to T1 and the vector from xo to x. For T2, the reflected solution is given by G(x, xo) = მ (x-xo)sin(θ), where θ is the angle between the normal vector to T2 and the vector from xo to x.
Therefore, the Green's function that solves the problem on a semicircular region is given by G(x, xo) = მ (x-xo)(cos(θ)sin(θ)).

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Write a MATLAB code for the following question:
Customers depart from a bookstore according to a Poisson process with the rate of 4 customers per hour. Let N be the number of books that each customer buys which is independent of other customers and has the following distributions: P(N=0) = 0.2; P(N=1) = 0.4; P(N=2) = 0.2 What is the probability that we have at least one customer buying 2 or more books before having two customers buying no books?

Answers

The probability that we have at least one customer buying 2 or more books before having two customers buying no books is 0.984.

Here is a possible MATLAB code to solve the problem:

%START

% Set the rate of the Poisson process

lambda = 4;

% Set the probabilities of N taking different values

p0 = 0.2;

p1 = 0.4;

p2 = 0.2;

% Compute the probability of having at least one customer buying 2 or more books

% before having two customers buying no books

prob = poisscdf(2-1, lambda*p0) - poisscdf(1-1, lambda*p0);

% Display the result

fprintf('Probability of having at least one customer buying 2 or more books before having two customers buying no books: %.4f\n', prob);

%END

This code uses the poisscdf function to compute the probability of having a certain number of events (customers buying 2 or more books or customers buying no books) in a given time period (one hour), assuming that the events occur according to a Poisson process with the given rate (4 customers per hour).

The probability of having at least one customer buying 2 or more books before having two customers buying no books is then computed as the probability of having 2 or more customers buying 2 or more books minus the probability of having 1 or more customers buying 2 or more books. The result is displayed using the fprintf function.

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Use wage data (Data is posted on blackboard) to estimate the following model and answer the questions: Wage= Bo+ Bi educ+ B2 exper+B3 gender +B4 race+Bs gender*exper+E Gender=1 for male and gender=0 for female Race=1 for white and race=0 for non-white 1- Interpret all the coefficients. 2- Is there a significant wage difference between white and non-white? at a=0.05 3- Test for global usefulness of the model at a=0.05. 4- Test if the experience is a significant determinant of wage at a=0.10.

Answers

A unit increase in gender will result in decrement of -52.73 in wage provided holding all other parameter constant.

What is parameter?

A parameter is a piece of information that an equation passes on. In terms of statistics, it means something different. In contrast to statistics, which only provide information about a small portion of the population, this value provides information about the entire population.

A parameter is constant because it was determined by surveying everyone (or everything). The average age of the students in your class, for instance, might be of interest to you. Maybe after asking everyone, you discovered that the average age was 25. Given that you polled the entire class, that qualifies as a parameter. Let's say you were curious about the median age of your grade or year.

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write two monomials with a GCF of 7x^3y, one of which has a degree of 5

Answers

The monomials with a GCF of 7x³y with degree 5 are 7x⁴y and 14x³y².

What is the highest common factor?

The Highest Common Factor (HCF) of two numbers is the highest possible number that is divisible by both numbers.

In other words, the highest common factor is the common factor between the two numbers but it should be the highest among all common factors.

As per the given GCF as 7x³y,

The GCF of 14 and 7 is 7.

The GCF of x⁴y and x³y² will be x³y.

Thus,

GCF of 7x⁴y and 14x³y² = 7x³y

So monomials are 7x⁴y and 14x³y².

Hence "The monomials are 7x⁴y and 14x³y²".

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Please help me. It's only 1 question :(

Answers

Answer:

5/12 of a pizza

Step-by-step explanation:

Question 1 A corporation has the following account balances: Common Stock, $1 par value, $80000; Paid-in Capital in Excess of Par Value, $2700000. Based on this information, the a. legal capital is $2780000 b. average price per share issued is $3.48 c. number of shares outstanding is 2780000. d. number of shares issued is 80000

Answers

The correct option is D , as the number of shares issued is 80000.

What is stock ?

In finance, stock consists of all the shares by that possession of an organization or company is split. one share of the stock means that fractional possession of the corporation in proportion to the whole range of shares.

Main body:

as per the information given in the question , Common Stock, $1 par value, $80000 which means  the number of shares issued is 80000.

hence ,correct option is D as the number of shares issued is 80000.

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There are 48 blue birds in a tree. There are 32 red burds in the tree. How many more bluebirds are there in the tree than red

Answers

Answer:

16 more blue birds

Step-by-step explanation:

If the total number of blue birds is 48

The total number of red birds is 32

then through simple subtraction we get to know that 16 more blue birds are present in the tree than the red birds

Extra Blue birds = 48-32

= 16

yolanda will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $70 and costs and costs and additional $0.30 per mile driven. The second plane has no initial fee but costs $0.80 per mile driven. How many miles would Yolanda need to drive for the two plans to cost the same?

Answers

The two plans will cost the same when Yolanda has driven 233 miles distance. That is, $70 + (0.30 x 233) = $233 = 0.80 x 233.

To find out how many miles Yolanda needs to drive for the two plans to cost the same, we need to set up an equation. The equation should calculate the total cost of each plan. For the first plan, the total cost is the initial fee plus the cost of the miles driven. For the second plan, the total cost is just the cost of the miles driven. We can then set the two equations equal to each other and solve for the number of miles distance driven. The final result is that Yolanda needs to drive 233 miles for the two plans to cost the same.

Plan 1: C = F + (D × CPM)

Plan 2: C = (D × CPM)

Plan 1 = Plan 2

F + (D × CPM) = (D × CPM)

F = 0

D × CPM = D × CPM

D = 233

Therefore, Yolanda needs to drive 233 miles for the two plans to cost the same.

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Let X denote the random variable that gives the sum of the faces that fall uppermost when two fair dice are rolled. Find P(X = 4). (Round your answer to two decimal places.)

Answers

The likelihood or the probability is 121, or 8.33%.

What is probability?

Simply put, probability measures how probable something is to occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out. Statistics is the study of events subject to probability.

The likelihood that a population parameter will be less than a given value when the null hypothesis is true is expressed as the p-value, also known as a probability value or a measure of significance, for a particular statistical model.

We must make a table for easier comprehension in order to determine the P(x=4);

Refer to the attachment for table:

There are three different ways that P(x=4) can occur based on the table. Out of 36 possible results (6 x 6 = 36), they are (1,3), (2,2), and (3,1). As a result, the chance of the event is 363; it is then reduced to 121, or 8.33%.

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help me find the slope

Answers

Answer: Rise over Run

Step-by-step explanation: Take the change in the x coordinates, and divide by the change in y coordinates.

For example, to find slope when given 2 coordinates:

(2,5)     (5, 10)

The change in the x coordinates is 3, because from 2-->5 it moves 3 places to the right. (run)

The change in the y coordinates is 5, because from 5-->10 it moves 5 places upwards. (rise)

Use rise/run.

Rise= 5 (change in y coordinate)

Run = 3 (change in x coordinate)

5/3 is the slope.

On questions like #6, the slope is -3. That is because the equation for slope is y=mx+b.

m is the coefficient of the x, so -3 is the slope.

Likewise, the slope of #2 is 7. The slope of #10 is 3/4.

Your goal here is to find the least squares line y(x) = mx + b for the following data: (-2, 1), (2, 1), (-1,-1), (0, -2), (2,-2), and (-2, 1) Feel free to use a calculator! The normal equation for determining the approximating parameters ħ and în are: Then the least squares line is: y(x) = = number + number

Answers

The least squares line , y = mx + b form from given data is y = ( -32/100 )x + ( -39/100).

We have an equation of line is

y(x) = mx + b --(1)

given data, (-2, 1), (2, 1),(-1,-1), (0,-2), (2,-2) and (-2, 1)

plugging each point on above equation we get, 1 = -2m + b ; 1 = 2m + b ; -1 = -m + b ; -2 = 0m + b ;

-2 = 2m +b ; 1 = -2m + b

The above equations can be written in matrix form as,

[ -2 1 ; 2 1 ; -1 1 ; 0 1 ; 2 1 ; -2 1] [ m ; b]

= [ 1 ; 1 ; -1 ; -2 ; -2 ; 1]

AX = B

X = (Aᵀ A)⁻¹ AᵀB where Aᵀ is transpose of matrix A and (Aᵀ A)⁻¹ is inverse of (Aᵀ A).

AᵀA = [ -2 2 -1 0 2 -2 ; 1 1 1 1 1] [ -2 1 ; 2 1 ; -1 1 ; 0 1 ; 2 1 ; -2 1] = [ 17 -1 ; -1 6 ]

so, X = [ 17 -1 ; -1 6 ] ^-1 [ -2 2 -1 0 2 -2 ; 1 1 1 1 1][ 1 ; 1 ; -1 ; -2 ; -2 ; 1]

let [ 17 -1 ; -1 6 ] = P

[ 17 -1 ; -1 6 ]⁻¹ = adj.P/det P

det P = 17×6 - 1 = 101

P⁻¹ = 1/101 [ 6 1 ; 1 17 ]

Now, X = 1/101 [ 6 1 ; 1 17 ] [ -2 2 -1 0 2 -2 ; 1 1 1 1 1][ 1 ; 1 ; -1 ; -2 ; -2 ; 1]

=> X = 1/101[ 6 1 ; 1 17 ] [ -5 ; -2 ]

=> X = 1/101 [ -32 ; -39] = [ -32/100 ; -39/100 ]

=> [ m ; b ] = [ -32/100 ; -39/100 ]

=> m = -32/100 , b = -39/100

then, y = mx + b

=> y = ( -32/100 )x + ( -39/100)

Hence, the required equation is

y = ( -32/100 )x + ( -39/100).

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Can anyone pls help me find the answer to this problem. I will give brainliest

Answers

Answer:

[tex]\log_{10}\sqrt{a} -\dfrac{3}{4}=\dfrac{1}{2}\log_{10}a-\dfrac{3}{4}[/tex]

Step-by-step explanation:

Given:

[tex]x=\dfrac{\sqrt{10a\sqrt{0.1}}}{10}[/tex]

Therefore:

[tex]\implies \log_{10}x=\log_{10}\left(\dfrac{\sqrt{10a\sqrt{0.1}}}{10} \right)[/tex]

[tex]\textsf{Apply the log quotient law}: \quad \log_a \left(\dfrac{x}{y}\right)=\log_ax - \log_ay[/tex]

[tex]\implies \log_{10}\sqrt{10a\sqrt{0.1}}-\log_{10}10[/tex]

[tex]\textsf{Apply log law}: \quad \log_aa=1[/tex]

[tex]\implies \log_{10}\sqrt{10a\sqrt{0.1}}-1[/tex]

[tex]\textsf{Apply radical rule: $\sqrt{ab}=\sqrt{a}\sqrt{b}$, \quad assuming $a \geq 0,\;b\geq 0$}[/tex]

[tex]\implies \log_{10}\left(\sqrt{10}\sqrt{a}\sqrt{\sqrt{0.1}}}\right)-1[/tex]

[tex]\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay[/tex]

[tex]\implies \log_{10}\sqrt{10} + \log_{10}\sqrt{a} + \log_{10}\sqrt{\sqrt{0.1}}}\right)-1[/tex]

Rewrite the radicals:

[tex]\implies \log_{10} \left(10\right)^{\frac{1}{2}} + \log_{10}\sqrt{a} + \log_{10}\left(0.1\right)^{\frac{1}{4}\right)-1[/tex]

[tex]\textsf{Apply the log power law}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies \dfrac{1}{2}\log_{10} 10 + \log_{10}\sqrt{a} + \dfrac{1}{4}\log_{10}0.1-1[/tex]

[tex]\textsf{Apply log laws}: \quad \log_aa=1 \quad \textsf{and} \quad \log_a\dfrac{1}{a}=-1[/tex]

[tex]\implies \dfrac{1}{2}(1) + \log_{10}\sqrt{a} + \dfrac{1}{4}(-1)-1[/tex]

[tex]\implies \dfrac{1}{2}+ \log_{10}\sqrt{a} -\dfrac{1}{4}-1[/tex]

[tex]\implies \log_{10}\sqrt{a} -\dfrac{3}{4}[/tex]

If you want to simplify further:

[tex]\implies \log_{10}\left(a\right)^{\frac{1}{2}} -\dfrac{3}{4}[/tex]

[tex]\implies \dfrac{1}{2}\log_{10}a-\dfrac{3}{4}[/tex]

Answer:

56

Step-by-step explanation: 10a+10 0.1 -=

24. The average price of a new car is a function of the year it was purchased. In 1994.
the average price of a new car was $16.930. In 2002, the average price was
$19.126. Find the rate of change of the average price of a new car. Include units
in your answer.

please help me i’m struggling

Answers

The rate of change of the average price of the new car is $274.50 per year.

What is the rate of change?

The rate of change of the average price of the new car is a function of the change in average price over the years and the change in the number of years.

Rate of change = change in the average price / change in the number of years

Rate of change = (price in 2002 - price in 1994)  / difference in the number of years

Rate of change = (19,126 - 16,930) / (2002 - 1994)

Rate of change = 2196 / 8

Rate of change = $274.50

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all prime number greater than 2 are odd?

Answers

Answer:

Prime numbers are odd that are greater than 2. Prime numbers are numbers that are not divisible by anything. EXAMPLE: 33 is not prime because if you take 3 times 11 then you get 33.

Step-by-step explanation:

Let X be a random variable representing the number of rolls of a fair die until we see the first 6. Next, choose with replacement a sample of size X from an urn with 5 red and 4 green balls. Let Y be the number of green balls in the sample. Find Var(Y).

Answers

As per the binomial distribution, the value of var(Y) is 0.00008

What is meant by binomial distribution?

In math, the Binomial distribution counts the number of successes in n trials, where sampling is done with replacement or the probability of success is constant from trial to trial

Here we have given that,  X be a random variable representing the number of rolls of a fair die until we see the first 6. Next, choose with replacement a sample of size X from an urn with 5 red and 4 green balls. Let Y be the number of green balls in the sample.

And we need to find the value of var(Y).

Here we know that the value of n = 6 and the value of x is 4 and the probability is 0.05.

Then as per the binomial distribution formula, it can be calculated as,

By using a calculator, you can enter trials=6, p=0.05, and X=4 into a binomial probability distribution function (PDF). If doing this by hand, apply the binomial probability formula:

=> [6!/4!(6-4)!] x 0.05⁴ x (1- 0.05)⁶⁻⁴

=> 0.00008

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16.13- cerebral tumors and cell phone use. in a case-controlled study on cerebral tumors and cell phone use, tumors occurred more frequently on the same side of the head where cellular telephones had been used in 26 of 41 cases. test the hypothesis that there is an equal distribution of contralaterial and ipsilateral tumors in the population. use a two-sided alternative.

Answers

Null Hypothesis: H0: There is an equal distribution of contralateral and ipsilateral tumors in the population.Ha: There is not an equal distribution of contralateral and ipsilateral tumors in the population.

1) Calculate the observed value:

The observed value is 26 out of 41 cases.

2) Calculate the expected value:

The expected value is 20.5 out of 41 cases.

3) Calculate the test statistic:

The test statistic is (26-20.5)/sqrt(20.5) = 2.44

4) State the critical value:

The critical value for a two-sided test with a significance level of 0.05 is 1.96.

5) The test statistic (2.44) is greater than the critical value (1.96), so we reject the null hypothesis and conclude that there is not an equal distribution of contralateral and ipsilateral tumors in the population.

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If the simple interest on $2,000 for 7 years is $1,120, then what is the interest rate?
The rate is %.

Answers

Answer:

Rate= I*100/P*T

R= 1120 * 100/2000*7

R= 112000/14000

R= 8%

Consider the point of intersection where the vertical line X=2 meets the line y=7x+9

Answers

The point of intersection (x,y) is  = (2,23)

Replace every x with 2 and simplify

y = 7x+9

y = 7*2 + 9

y = 14 + 9

y = 23 is the y coordinate

The vertical line x = 2 meets the diagonal line y = 7x+9 at the location (x,y) = (2,23)

What are Coordinates ?

The position of a point or points on a graph or grid is shown by its coordinates. The origin is defined as the point (0, 0). The coordinates are two units to the right in the x-direction and four units up in the y-direction according to the point (2, 4).

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of 649 adults selected randomly from one town, 54 of them smoke. construct a 92.5 percent n interval for the true percentage of all adults in the town that smoke.

Answers

The 92.5% of confidence interval for the percentage of adults is

(-1.176 ,  1.342).

as per given in the question,

The total number of adults (n) is 649

The number of smokers (x) = 54

the probability of getting a smoker is P =x/n

=> P = 54/649

=> 0.083

not getting a smoker is

1 - P = 1-0.083

=> 0.916

At 92.5% confidence level the Z critical value is ,

[tex]\alpha[/tex] = 1 - 92.5%

=> 1 - 0.925

=> 0.075

[tex]\alpha[/tex] / 2 = 0.075/ 2

=> 0.0375

now,

for the two tail test

Z[tex]\alpha[/tex]/2

= Z(0.0375)

= 1.7805

Margin of error

E = [tex]Z\alpha / 2 * \sqrt{( p * (1 - p) / n)}[/tex]

= 1.780 [tex]\times (\sqrt{((0.083 \times 0.916 ) / 649)}[/tex]

= 1.2596

A 92.5 % confidence interval for population proportion p is ,

P- E < P < P + E

0.083- 1.259 < P < 0.083 + 1.259

-1.176 < p < 1.342

(-1.176 ,  1.342) is the interval

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a small island is 3 miles from the nearest point p on the straight shoreline of a large lake. if a woman on the island can row a boat 3 miles per hour and can walk 4 miles per hour, where should the boat be landed in order to arrive at a town 7 miles down the shore from p in the least time? let x be the distance (in miles) between point p and where the boat lands on the lakeshore.

Answers

The point where the boat should be landed is the point 3.4 miles from point P towards the town.

The point where the boat should be landed can be found by expressing

the distance traveled on the boat and walking as a function of time.

Given that x represents the distance from point P to the boat landing point.

Therefore, distance of rowing the boat = √((12 - x)² + 3²)

The total time, t, is, therefore;

[tex]t=\frac{12-x}{4} +\frac{\sqrt{x^2+3^2} }{3}-----------(1)[/tex]

differentiate the above equation we get:

[tex]\frac{dt}{dx} =\frac{d}{dx} (\frac{12-x}{4} +\frac{\sqrt{x^2+3^2} }{3} )\\\\\\=\frac{12.(-3+4*\frac{2x}{2*\sqrt{x^2+9} } )}{144} \\\\\\=\frac{12(-3+4*\frac{2x}{2*\sqrt{x^2+9} }) }{144}\\\\=-\frac{1}{4} +\frac{x}{3*\sqrt{x^2+9} } \\\\\frac{x}{3*\sqrt{x^2+9} }=\frac{1}{4} \\\\cross multiplying both terms we get:\\\\4x=3*\sqrt{x^2+9}[/tex]

squaring on both sides we get:

16x^2=9(X^2+9)

16x^2=9x^2+81

7x^2=81

[tex]x=\frac{9*\sqrt{x} }{7}[/tex]

Approximately,x=3.4 miles.

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It takes Christina 2 minutes to read one page of her 250 page book. Which of the following represents the appropriate domain and range for a function relating the total time she has spent reading the book, x, and the number of pages she has read, y?

Answers

Answer:

Domain: 0<=x<=500

Range: 0<=y<=250

Step-by-step explanation:

I'm not sure if this is what you asked for. She spend 2 minutes reading 1 page, there are 250 pages, therefore: 250*2=500

the range is simply the total pages

Hope this help!


The water tank at the institution is
full. A water truck begin to full the tank with
water at a rate of 8 litres per minute. After 15 minutes the tank was 5/2 full. Calculate
the number of litres of water that the tank can hold

Answers

The number of litres of water the tank can hold is 48 litres

What is Volume?

Volume is defined as the space occupied within the boundaries of an object in three-dimensional space. It is also known as the capacity of the object.

Volume can be measured in cubic units, litres and gallons.

If the rate of pump is 8minutes per minute, therefore in 15 minutes, 15×8 = 120 litres is in the tank.

120 litres is 5/2 full

the volume of the tank will be 120×2/5

= 240/5

= 48litres

Therefore the volume of the tank is 48litres

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Write an exponential function (1 , 10.4) and (4 , 665.6)

Answers

Answer:

[tex]f(x)=2.6(4)^x[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{9 cm}\underline{General form of an Exponential Function}\\\\$f(x)=ab^x$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the initial value ($y$-intercept). \\ \phantom{ww}$\bullet$ $b$ is the base (growth/decay factor) in decimal form.\\\end{minipage}}[/tex]

Given points:

(1, 10.4)(4, 665.6)

Substitute the given points into the formula to create two equations:

[tex]\implies 10.4=ab[/tex]

[tex]\implies 665.6=ab^4[/tex]

Divide the second equation by the first to eliminate a, then solve for b:

[tex]\implies \dfrac{665.6}{10.4}=\dfrac{ab^4}{ab}[/tex]

[tex]\implies 64=\dfrac{b^4}{b}[/tex]

[tex]\implies 64=b^3[/tex]

[tex]\implies b=\sqrt[3]{64}[/tex]

[tex]\implies b=4[/tex]

Substitute the found value of b into the first equation and solve for a:

[tex]\implies 10.4=4a[/tex]

[tex]\implies a=2.6[/tex]

Therefore, the exponential function is:

[tex]f(x)=2.6(4)^x[/tex]

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