An object accelerates at 20 m/s2. By how much does the speed change in one second?

Answer:

reviewing the final answers the correct one is D none of the above

Explanation:

Diotria is highly used in ophthalmology and is related to distance by

       P = 1 / f

where f is the focal length of the lens in meters

Therefore from the previous definition the unit of dioctry is the inverse of the meter

   [P] = [1 / m]

when reviewing the final answers the correct one is D none of the above

Answer:

P = 2.45 N

Q = 6.65 N

Explanation:

According to Newton's 2nd Law:

Unbalanced Force = ma

where,

m = mass = 7 kg

a = acceleration

In the first case when both forces P and Q act on left side:

Unbalanced Force = P + Q

a = 1.3 m/s²

Therefore,

P + Q = (7 kg)(1.3 m/s²)

P + Q = 9.1 N   ------------------------- equation 1

Now, in second case when both forces have different directions:

Unbalanced Force = Greater Force - Smaller Force

Unbalanced Force = Q - P

a = 0.6 m/s²

Therefore,

Q - P = (7 kg)(0.6 m/s²)

Q - P = 4.2 N   ------------------- equation 2

Adding equation 1 and equation 2, we get:

(Q + P) + (Q - P) = 9.1 N + 4.2 N

2 Q = 13.3 N

Q = 6.65 N

Using this value in equation 2, we get:

6.65 N - P = 4.2 N

P = 2.45 N

Answer:

experimental group

Explanation:

please mark me as a brainlist..

Answer:

Experemtial group

Explanation:

The placebo is just sugar pills tested is ones already done and control is a mix of the two

because it uses a systematic method of asking and answering problems, and it attempts to develop solution to psychological problems.

Answer:

it uses a systematic method of asking and answering problems,

Explanation:

Answer:

The tensions in [tex]T_{BC}[/tex] is approximately 4,934.2 lb and the tension in [tex]T_{BD}[/tex] is approximately  6,035.7 lb

Explanation:

The given information are;

The angle formed by the two rope segments are;

The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°

The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°

Therefore, we have;

The tension in rope segment BC = [tex]T_{BC}[/tex]

The tension in rope segment BD = [tex]T_{BD}[/tex]

The tension in rope segment AB = [tex]T_{AB}[/tex] = Pulling force of tugboat = 1200 lb

By resolution of forces acting along the line A_F gives;

[tex]T_{BC}[/tex] × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = [tex]T_{AB}[/tex] = 1200 lb

[tex]T_{BC}[/tex] × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = 1200 lb............(1)

Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;

[tex]T_{BC}[/tex] × sin(26.0°) + [tex]T_{BD}[/tex] × sin(21.0°) = 0...........................(2)

Which gives;

[tex]T_{BC}[/tex] × sin(26.0°) = - [tex]T_{BD}[/tex] × sin(21.0°)

[tex]T_{BC}[/tex] = - [tex]T_{BD}[/tex] × sin(21.0°)/(sin(26.0°))  ≈ - [tex]T_{BD}[/tex] × 0.8175

Substituting the value of, [tex]T_{BC}[/tex], in equation (1), gives;

- [tex]T_{BD}[/tex] × 0.8175 × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = 1200 lb

- [tex]T_{BD}[/tex] × 0.7348  + [tex]T_{BD}[/tex] ×0.9336 = 1200 lb

[tex]T_{BD}[/tex] ×0.1988 = 1200 lb

[tex]T_{BD}[/tex] ≈ 1200 lb/0.1988 = 6,035.6938 lb

[tex]T_{BD}[/tex] ≈ 6,035.6938 lb

[tex]T_{BC}[/tex] ≈ - [tex]T_{BD}[/tex] × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb

[tex]T_{BC}[/tex] ≈ -4934.1733 lb

From which we have;

The tensions in [tex]T_{BC}[/tex] ≈ -4934.2 lb and  [tex]T_{BD}[/tex] ≈ 6,035.7 lb.

Answer:

ans is 120

Explanation:

I= 0.5 A

p= 60w

p=Iv

60/0.5

v= 120

Answer:

V=P/I

V=60/0.5

V=120

Explanaton:

the formula P=IV is converted to V=P/I to make V (voltage) the subject. then sub in the values to get your answer

note that potential difference is same as voltage

Answer:

1.) 11 km/s

2.) 9.03 × 10^-5 metres

Explanation:

Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.

Electron q = 1.6×10^-19 C

Electron mass = 9.11×10^-31 Kg

(a) What is the speed of the electron 1.3 ns after entering this region?

E = F/q

F = Eq

Ma = Eq

M × V/t = Eq

Substitute all the parameters into the formula

9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19

V = 7.68×10^-18 /7.0×10^-22

V = 10971.43 m/s

V = 11 Km/s approximately

(b) How far does the electron travel during the 1.3 ns interval?

The initial velocity U = 64 km/s

S = ut + 1/2at^2

S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2

S =8.32×10^-5 + 7.13×10^-6

S = 9.03 × 10^-5 metres

Sulfur, a nonmetal with 6 valence electrons atom is most likely to accept electrons to form an ionic bond option (D) correct.

Ionic bonds, also known as electrovalent bonds, are a type of connection created in a chemical molecule by the electrostatic attraction of ions with opposing charges.

As we know,

It has been shown that the top of the electronegativity scale is defined by the fundamental atomic particles F>O>N.

Ionic bonds need an electron, often a nonmetal, and an electron, typically a metal. Metals display ionic bonding because there aren't many-electron in outer orbitals.

Thus, sulfur, a nonmetal with 6 valence electrons atom is most likely to accept electrons to form an ionic bond option (D) correct.

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Answer:

The ball is in the air for approximately 0.45 seconds

Explanation:

We only need to use the information on the height of the table to find the time, since the vertical movement is a movement under the acceleration of gravity, and with no initial velocity in the y-direction (recall that the ball rolls off a 1.0 m high table)

therefore the equation of motion for the vertical component is:

[tex]y_f-y_i=\frac{1}{2}\, g\,t^2[/tex]

which for our information becomes:

[tex]y_f-y_i=\frac{1}{2}\, g\,t^2\\1 = 4.9\,t^2\\t^2=\frac{1}{4.9} \\t=\sqrt{\frac{1}{4.9}} \\t\approx 0.45\,s[/tex]

The question is incomplete; However, the height from which the stone is thrown is most likely to be what's required of the question

Answer:

See Explanation

Explanation:

Given

[tex]Initial\ Speed, u = 12.0m/s[/tex]

[tex]Time, t = 1.54\ s[/tex]

Required

Determine the height

This question will be answered using the following equation of motion;

[tex]S = ut + \frac{1}{2}gt^2[/tex]

Take g as 9.8

This gives:

[tex]S = 12 * 1.54 + \frac{1}{2} * 9.8 * 1.54^2[/tex]

[tex]S = 12 * 1.54 + \frac{1}{2} * 9.8 * 2.3716[/tex]

[tex]S = 18.48 + 11.62084[/tex]

[tex]S = 30.10084[/tex]

[tex]S = 30.1\ m[/tex] (Approximated)

Hence; Height = 30.1m

Answer:

the mass of the air in the classroom = 2322 kg

Explanation:

given:

A classroom is about 3 meters high, 20 meters wide and 30 meters long.

If the density of air is 1.29 kg/m3

find:

what is the mass of the air in the classroom?

density = mass / volume

where mass (m) = 1.29 kg/m³

volume = 3m x 20m x 30m = 1800 m³

plugin values into the formula

  1.29 kg/m³   =        mass    

                             1800 m³

mass =  1.29 kg/m³  ( 1800 m³ )

mass = 2322 kg

therefore,

the mass of the air in the classroom = 2322 kg

If A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, then the mass of the air in the classroom is 2322Kg.

Density is the ratio of mass to volume. it tells how much mass a body is having for its unit volume. for example egg yolk has 1027kg/m³ of density, means if we collect numbers of egg yolk and keep it in a container having volume 1 m³ then total amount of mass it is having will be 1027kg. Density is a scalar quantity. when we add egg yolk into the water, egg yolk has greater density than water( 997 kg/m³), because of higher density of egg yolk it contains higher mass in same volume as water. hence due to higher mass higher gravitational force is acting on the egg yolk therefore it goes down on the inside the water. water will float upon the egg yolk. same situation we have seen when we spread oil in the water. ( in that case water has higher density than oil. thats why oil floats on the water).

Given,

Height = 3 m

Width = 20 m

length= 30 m

Density of air = 1.29kg/m³

The  volume of the room = 3×20×30 m³

Volume V = 1800m³

By formula,

Density = Mass/Volume

1.29kg/m³ = Mass/1800m³

Mass of the air = 1.29×1800 = 2322 Kg

The mass of the air is classroom is 2322Kg.

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Answer:

electrical energy-found in the flow of electrical charges

chemical energy-found in the bonds BTW atoms

thermal energy-found when internal energy is transferred

nuclear energy-found in the nucleus of an atom.

The correct match is: nuclear energy: found in the nucleus of an atom, thermal energy: found when internal energy is transferred, electrical energy: found in the flow of electrical charges, chemical energy: found in the bonds between atoms.

Nuclear energy: This type of energy is obtained from an atom's nucleus. It is released by processes such as nuclear fission or fusion, which utilise the energy held inside atomic nuclei.

Thermal energy is the energy associated with an object's or a system's temperature. When there is a temperature differential, it is a type of internal energy that is exchanged between objects.

Electrical energy is associated with the passage of electric charges, such as electrons, via a conductor.

Chemical energy is contained in the bonds that connect atoms and molecules. When these connections are broken or created, it is released or absorbed during chemical processes.

Thus, this can be the match for the given forms of energy.

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Answer:

I think C but I'm not sure

The statement that illustrates how engineering has influences society is nuclear power plants provide cheap electricity to power people's homes. The correct option is A.

This claim serves as an example of how engineering has impacted society. Because they offer a practical and economical source of electricity for lighting up homes and other infrastructure, nuclear power plants have had a big impact on society.

The ability to create electricity from the energy held in atoms thanks to improvements in nuclear technology has boosted the availability and affordability of power for users.

This illustrates how advances in engineering can influence and enhance how society fulfils its energy needs.

Thus, the correct option is A.

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Meter #2 is more precise.

There's no information here that tells us which meter is more accurate.

The average speed is 1/2 m/s.

To determine the answer, we need to know about average speed.

Distance covered by an object per unit time is known as average speed.

Mathematically, average speed= Total distance travelled/ total time taken

Here, total distance travelled = 10m,

         total time taken = 20s

 Average speed = 10/20 = 1/2 m/s

Thus, we can conclude that the average speed is 1/2 m/s.

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Hello ┬┴┬┴┤◕3◕)づ├┬┴┬┴

The answer is 3 m

the gap in between 4s and 6s is 5s

you follow your finger up to the purple like, and follow the purple line in a straight line to the left. It ends at 3m and that is your answer.

Answer:

a gene is the basic physical and functional unit of heredity.

Genes are section of DNA that code for a particular trait. Genes are basic unit of inheritance in all living things specifying the physical and biological traits.

The precise meaning of the term "gene" has long been a topic of discussion in science. Here's an easy way to think about it: Our cells and tissues are built with proteins as the foundation. And genes are the area of our genome where the instructions for constructing those proteins are stored.

For instance, the human genome has over 20,000 genes that code for proteins. It's interesting to note that just 1.5% of the complete human genome contains all of the information for those 20,000 protein-coding genes.

A broader definition of a gene includes DNA sequences, sometimes called RNA genes, that include instructions for building an RNA molecule that performs a function other than directly encoding a protein.

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Answer:

The average velocity is 0.15 m/s

Explanation:

Use the definition of average velocity as the distance traveled divided the time it took.

Since the movement was on the plane from the origin (0, 0) to the point (-30, 20) corresponding to 30 m west and 20 m north, we calculate the distance using the distance between two points on the plane:

[tex]distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} = \sqrt{(-30)^2+20^2} =\sqrt{1300} \approx 36.06\,\,m[/tex]

Then the magnitude of the average velocity can be estimated via the quotient between distance divided time, but since the units required are meters per second, we first convert the four minute time into seconds: 4 * 60 = 240 seconds.

Then the average velocity becomes:

[tex]v_{ave}=\frac{distance}{time} =\frac{36.06}{240} =0.15\,\,m/s[/tex]

Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.

Explanation:

Answer:

Newton was convinced the planets must obey the same physical laws that are observed on Earth. This meant there must be an unseen force acting on them. He knew from experiment that, in the absence of an applied force, a moving body will continue in a straight line forever.

Explanation:

Answer:

t = 13.43 s

Explanation:

In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:

Vf = Vi + at

where,

Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)

Vi = Initial Velocity of the Plane = 95 m/s

a = deceleration of the plane = - 7.07 m/s²

t = minimum time interval needed to stop the plane = ?

Therefore,

0 m/s = 95 m/s + (- 7.07 m/s²)t

t = (95 m/s)/(7.07 m/s²)

t = 13.43 s

The best description of a gaseous substance is : (B). It has no definite shape or volume and will expand indefinitely.

A gaseous substance can be defined as a substance that is gaseous in nature or exhibit gaseous properties

A gaseous substance is just like a gas that its particles have unrestricted movement and the force of attraction between the particles are very weak or negligible.

In conclusion, The best description of a gaseous substance is : (B). It has no definite shape or volume and will expand indefinitely.

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Answer:

high frequent sound

Explanation:

because if its low than its slower.

Answer:

Ta - Tb = 4.84 sec (approx)

Explanation:

Time taken by A = Time taken By B + Extra time

Ta - Tb = T

We know that

Time (T) = [v-u] /a ...................[a=9.8 m/s²]

So,

Ta - Tb = [v-u] /a

Ta - Tb = [-23.7-23.7] /9.8

Ta - Tb = 4.8367 sec

Ta - Tb = 4.84 sec (approx)

The part B of the question is missing and it is;

b) What is the height between the two window ledges?

Answer:

A) 20.76 m/s

B) 161.52 m

Explanation:

A) To calculate the initial speed we use the formula from Newton's first law of motion:

v = u + at

Making u the subject gives;

u = v - at

Where;

v is the final velocity which is the speed when Jill sees the pot = 60 m/s

u is the initial velocity which is the speed when Jack sees the pot go by

t is the time between the two observed events = 4 s

a in this question is acceleration due to gravity = 9.81 m/s².

Plugging in the relevant values into the initial velocity equation gives;

u = 60 - (9.81 × 4)

u = 20.76 m/s

B) To get the height difference, we will use the formula;

(y1 - y0) = ut + ½at²

Thus, plugging in the relevant values, we have;

y1 - y0 = (20.76 × 4) + (½ × 9.81 × 4²)

(y1 - y0) = 161.52 m

Answer:

Distance = πr

Displacement = 2r

Explanation:

First we need to find the distance covered by the car. As the car is travelling on a circular path and it traveled to a diametrically opposite point on the circular path. Therefore, the distance covered by the car must be the half value of the circumference.

Distance = Circumference/2

Distance = 2πr/2

Distance = πr

Since, displacement is the straight line distance between two points. So, the displacement in moving from a point to its diametrically opposite point must be equal to the diameter of circle:

Displacement = Diameter

Displacement = 2r

Explanation:

Q1. Given:

v = 0 m/s

a = -5.5 m/s²

t = 3.5 s

Find: Δx

Δx = vt − ½ at²

Δx = (0 m/s) (3.5 s) − ½ (-5.5 m/s²) (3.5 s)²

Δx ≈ 33.7 m

Q2. Given:

Δx = 400 m

v₀ = 7.0 m/s

v = 35 m/s

Find: a

v² = v₀² + 2aΔx

(35 m/s)² = (7.0 m/s)² + 2a (400 m)

a = 1.47 m/s²

Answer:

Correct Answer: B. Beaker A will be 72 °C and beaker B will be 28 °C.

This one is actually right!

Answer:

Explanation

He runs at 5m/s, so in 30 s he should be at 150m.  So you have to do 125m - 150m and you'll get -25m, this is his initial position. They want to know the time when he hits 75m, so you would do 75 + 25, and get 100. Then do 100m / 5m/s, and you will get 25 seconds.

Answer:

0.00050, 0.000000000406, 36513