An isosceles triangle has side lengths of 15.6 units and 20.33 units. What is the greatest possible value of the perimeter of the triangle?

1) Between the years 2003 and 2009, 768 students joined the school.

2) It took 6 years for the population to grow from 1219 students to 1987 students.

3) The average population growth per year is 128 students per year.

P = 128 students per year

4) The population of students in the year 2000 was a total of 835 students.

5) 1219 + (p3) = 1987

6) 1987 + (p3) = 2371

P3 = 384

The mean of the data about students size of Mr. Sirac classes is 24.

Given students size of each of Mr. Sirac'sclasses 21,20,22,23,24,25,26,28,27 and we have to find the mean of the data.

We know that mean is the basically sum of numbers divided by the number. It is also known as average.

Mean =∑X/n where n is number of values and ∑X is sum of all the values.

∑X=21+20+22+23+24+25+26+28+27

=216

n=9

Mean is calculated by dividing sum by n.

Mean =216/9

=24

Hence the mean of the data about students size of each of Mr. Sirac classes is 24.

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Answer:

Step-by-step explanation:

The slope m = 3/2 and the y-intercept = ( 0, -6 ).

The graph is a solid line and shaded area below the boundary line since y is less than (3/2)x - 6.

Given that:

3x -2y ≥ 12

First we write the inequality in slope intercept form y = mx + b.

Solve for y

3x -2y ≥ 12

-2y ≥ 12 - 3x

Now, divide each term by -2

y ≤ -6 + 3x/2

We re-arrange

y ≤ (3/2)x - 6

Using the slope intercept form y = mx + b. we can see that;

m = 3/2

b = -6

Hence, the slope m = 3/2 and the y-intercept = ( 0, -6 ).

The graph is a solid line and shaded area below the boundary line since y is less than (3/2)x - 6.

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The complete inequality is y < x and y< -x

The expressions are given as:

y[ ]x and y[ ]-x

From the graph, we can see that:

Only the lower regions are shaded

This represents the less than inequality sign

Hence, the complete inequality is y < x and y< -x

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Answer:

2.75 is the median

Answer:

1.25 is the median

Step-by-step explanation:

it is the middle of the number sequence.

to find the median, place the numbers in value order and find the middle

since there is an even amount of numbers, add 2.5 and 0 (the two middle numbers) and divide them by two

The equation solved for w is w = 6g - 40

The complete question is in the attached image

The equation is given as:

g = 1/6(w + 40)

Multiply both sides by 6

6g = w + 40

Subtract 40 from both sides

w = 6g - 40

Hence, the equation solved for w is w = 6g - 40

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Answer:

8

Step-by-step explanation:

12+4=16

16 divided by 2= 8

Answer:

[tex]g(x)= -3x^{2} +4x +5[/tex]

Step-by-step explanation:

Five more = Addition of 5

Opposite = (-)

3 times = Multiplication by 3

Square = To the power (exponent) of two

4 times the number = Multiplication by 4

The number = unknown number = x

A) A parallelogram has 4 sides.

B) The opposite angles of parallelogram are congruent.

C) [tex]\angle A \cong \angle C, \angle B \cong \angle D\\\\\implies m\angle C=115^{\circ}, m\angle D=65^{\circ}[/tex]

The calculation of 129 ÷ 3.332 rounded to the appropriate number of significant digits is 39.

Given that;

129 ÷ 3.332

First we convert 3.332 to fraction

3.332 = 3.332/1

3.332 = 3.332/1 × 1000/1000 = 3332/1000

3.332 = 833/250

Hence we have;

129 ÷ 833/250

This can be written as

= 129 × 250/833

= 32250/833

= 38.71549 ≈ 39

Therefore, the calculation of 129 ÷ 3.332 rounded to the appropriate number of significant digits is 39.

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Answer:

x^2=ab

Step-by-step explanation:

Please mark as brainlist

Answer:The answer is 27.04

Step-by-step explanation:

The solution is in the attached

Answer:

.

Step-by-step explanation:

This value is approximate

=======================================================

Work Shown:

[tex]\log_{10}(2) \approx 0.301\\\\\log_{10}(3) \approx 0.477\\\\\log_{10}(6) = \log_{10}(2*3)\\\\\log_{10}(6) = \log_{10}(2)+\log_{10}(3) \ \text{ see note below}\\\\\log_{10}(6) \approx 0.301 + 0.477\\\\\log_{10}(6) \approx 0.778\\\\[/tex]

Note: I used the rule that log(A*B) = log(A)+log(B) which works for any valid log base.

Step-by-step explanation:

Since the question has already been answered, I'd like to add something new, and explain why: [tex]log_b(a*c)=log_ba+log_bc[/tex]

So let's just say that:

[tex]x=log_ba[/tex] and that [tex]y=log_bc[/tex]

This means that: [tex]b^x=a[/tex] and that [tex]b^y=c[/tex].

So if we were to multiply the two, a and c. You get

[tex]a*c=b^{x+y}[/tex]

This is due to the exponent identity that: [tex]b^a*b^c=b^{a+c}[/tex]

So if you rewrite this in logarithmic form you get:

[tex]log_b{ac}=x+y[/tex]

and remember what x and y are equal to? that's right, it's the logarithms

so now you substitute the logarithms back in and get

[tex]log_b{ac} = log_ba+log_bc[/tex]

Answer:

  B.  360 meters

Step-by-step explanation:

The triangles shown are similar, so their corresponding parts are proportional.

There are a couple of useful proportions here. We can equate the ratio of horizontal segments to the ratio of diagonal segments:

  (600 m)/(250 m) = ??/(150 m)

Or, we can equate the ratios of the diagonal segment to the corresponding horizontal segment:

  ??/(600 m) = (150 m)/(250 m)

Either way, when we multiply the equation by the denominator of ??, we get the result ...

  ?? = (600)(150/250) m = 360 m

The distance from F to G is 360 meters.

Answer:

Step-by-step explanation:

This problem is similar to many others in which the sum of two quantities and their difference are given. The solution can be found easily when the equations for the relations are written in standard form.

Let s and h represent numbers of sodas and hot dogs sold, respectively. The given relations are ...

Adding the two equations eliminates one variable.

  (s +h) +(s -h) = (235) +(59)

  2s = 294 . . . . simplify

  s = 147 . . . . . .divide by 2

  h = 147 -59 = 88 . . . . h is 59 less

147 sodas and 88 hot dogs were sold.

__

Additional comment

The solution to a "sum and difference" problem is always the same. One of the numbers is half the sum of those given, and the other is half their difference. ((235-59)/2 = 88)

Answer:

4² + b² = 12²

16 + b² = 144

b² = 144 - 16

b² = 128

b = √128

b = 11.3 feet

Step-by-step explanation:

Answer:

Proof:

By the inscribed angle theorem, we know that angle BAC is equal to angle DEC. By the second corollary to the inscribed angle theorem, we know that line segment AE is perpendicular to line segment AC. Therefore, line segment AE is tangent to circle C.

Step-by-step explanation:

Analyze and ensure the answer is correct.

Answer:

Step-by-step:

By the inscribed angle theorem, we know that angle BAC is equal to angle DEC. By the second corollary to the inscribed angle theorem, we know that line segment AE is perpendicular to line segment AC. Therefore, line segment AE is tangent to circle C.

Answer:

0.36ml

Step-by-step explanation:

Note: micrograms = [tex]10^{-6} g[/tex]

Given the concentration,

[tex]500*10^{-6} g = 1ml\\1*10^{-6}g =\frac{1}{500} ml\\180*10^{-6} g=(\frac{1}{500} *180)ml\\180micrograms = 0.36ml[/tex]

Answer:

Step-by-step explanation:

x=40

Answer:

here is

Step-by-step explanation:

5x-20=180

5x=180+20

=200

X=200/5

40

Answer:

Step-by-step explanation:

The attached graph shows the graph opens downward, so the vertex at (-2, 6) is a maximum. The y-intercept is the constant, +2.

The range is the vertical extent of the function. Its upper limit is the maximum value of the function (6), and its lower limit is negative infinity.

  The range is {y l y ≤ 6}.

The graph opens downward, so it is increasing to the left of its maximum value, and decreasing to the right of its maximum. The x-coordinate of the maximum (-2) defines the upper limit of the increasing interval.

  The function is increasing over the interval (-∞, -2).

The y-intercept of the graph is where it crosses the y-axis. The value of x is zero there, so the value of the function is the value of its constant, +2.

  The function has a positive y-intercept.

The range of the given relation is:   range = { 3, 9, 10}

Range is the out come of the event is know as y.

Here, the given relation:

               R = {(0,3), (8,9), (16,10)

Now, range = { 3, 9, 10}

Thus, the range of the given relation is: range = { 3, 9, 10}

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Answer:

C

Step-by-step explanation:

it just is

Answer:

f-(g/h) is an algebraic expression of the difference of f and the quotient of g and h.

Step-by-step explanation:

[tex]f - ( \frac{g}{h} )[/tex]

I hope it was helpful for you..m

The requried algebraic expression of English phrase is given as f - g/h.

The algebraic expression consists of constants and variables. eg x, y, z, etc.

the equation is the relationship between variables and represented as y = ax + b is an example of a polynomial equation.

here,
The difference between f and the quotient of g and h.
The difference represents the subtraction of values, and the quotient can be obtained by division of g by h.
So,
Required algebraic expression,
= f - g/h

Thus, the required expression is given as f - g/h.

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The product is equal to:

[tex]\frac{18}{25}(cos(165) + i*sin(165))[/tex]

Remember that we can write a complex number in polar form as:

[tex]R*e^{i*a} = R*(cos(a) + i*sin(a))[/tex]

Then the given product:

[tex]\frac{6}{5}*(cos(120) + i*sin(120))*\frac{3}{5}*(cos(45) + i*sin(45))[/tex]

can be rewritten to:

[tex](\frac{6}{5}*e^{i*120})*(\frac{3}{5}*e^{i*45})[/tex]

Now is easier to solve the product:

[tex](\frac{6}{5}*e^{i*120})*(\frac{3}{5}*e^{i*45})\\\\= \frac{6}{5} *\frac{3}{5} *e^{i*(120 + 45)}\\\\= \frac{18}{25}*e^{i*165}\\\\= \frac{18}{25}(cos(165) + i*sin(165))[/tex]

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By using the table, we see that the correct options are:

a) f(2) = 7

b) f(x) = 3 when x = 8.

c) f⁻¹(7) = 2

d) f⁻¹(x) = 8 when x = 3.

Here we have a table of x and f(x).

First, we want to find f(2). To get that, we need to go to the row where we have x = 2.

In that same row we can see that f(x) = 7.

Then f(2) = 7.

Then it says:

"if f(x) = 3, then x = ?"

This time we do the opposite. We find the row where f(x) = 3, and then we see the value of x in that row.

In the second row (counting from the bottom) we can see that when x = 8, f(x) = 3.

Then:

"if f(x) = 3, x = 8"

Then we want to get the inverse of f(x) evaluated in 7.

Here we use the rule:

[tex]f(x) = y\\f^{-1}(y) = x[/tex]

Then

[tex]f(2) = 7\\f^{-1}(7) = 2[/tex]

The answer here is 2.

Finally:

"if the inverse evaluated in x si 8, then what is the value of x"

Similar to before, we know that when we evaluate f(x) in 8, the outcome is 3.

Then when we evaluate the inverse in 3, the outcome is 8.

So here we must have x = 3.

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