A. The acceleration of the electron is 5.71×10¹⁴ m/s²
B. The time taken for the electron to reach the grid is 7.01×10⁻⁹ s
C. The net force of the electron is 5.20×10⁻¹⁶ N
A. How to determine the acceleration of the electron
The acceleration can be obtained as illustrated below:
Initial velocity (u) = 0 m/sFinal velocity (v) = 4.0×10⁶ m/sDistance (s) = 1.4 cm = 1.4 / 100 = 0.014 mAcceleration (a) =?v² = u² + 2as
(4.0×10⁶)² = 0² + (2 × a × 0.014)
(4.0×10⁶)² = 0 + 0.028a
(4.0×10⁶)² = 0.028a
Divide both side by 0.028
a = (4.0×10⁶)² / 0.028
a = 5.71×10¹⁴ m/s²
B. How to determine the time
The time taken for the electron to reach the grid can be obtained as follow:
Initial velocity (u) = 0 m/sFinal velocity (v) = 4.0×10⁶ m/sAcceleration (a) = 5.71×10¹⁴ m/s²Time (t) =?a = (v – u) / t
5.71×10¹⁴ = (4.0×10⁶ – 0) / t
5.71×10¹⁴ = 4.0×10⁶ / t
Cross multiply
5.71×10¹⁴ × t = 4.0×10⁶
Divide both sides by 5.71×10¹⁴
t = 4.0×10⁶ / 5.71×10¹⁴
t = 7.01×10⁻⁹ s
C. How to determine the net force
Mass (m) = 9.11×10⁻³¹ KgAcceleration (a) = 5.71×10¹⁴ m/s²Net force (F) =?Net force = mass × acceleration
Net force = 9.11×10⁻³¹ × 5.71×10¹⁴
Net force = 5.20×10⁻¹⁶ N
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A 227.1 g sample of water at 12.2°C is heated to steam at 115.6°C. How much heat was absorbed?
??? kcal
According to the given statement the heat absorbed is 43676.78 J .
How do you calculate heat absorbed?The water's specific heat and the formula Q= mcΔT are used to compute the amount of heat absorbed. At 100°C, water vaporizes into steam. Calculating the amount of heat absorbed requires multiplying the number of moles of water by the molar heat of vaporization.
Briefing:Mass, m = 227.1grams
To find how much heat is absorbed when 227.1 grams of steam is heated from 115.6°C to 12.2°C.
Heat absorbed is given by :
Q= mcΔT
c is specific heat of water
Put all the values, we get :
Q = 227.1 * 1.86 * (115.6 - 12.2)
Q = 43676.78 J
43676.78 J heat is absorbed.
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pls help me with my question
In astronomy, luminosity is the power (amount of energy per unit of time) emitted in all directions by a celestial body. It is directly related to the absolute magnitude of the star. The luminosity of the Sun, L☉ is the classical unit used in astronomy to compare the luminosity of other stars. Its approximate value is:
[tex]L=3.827\times10^{26}W[/tex]From the options, the correct one is:
A. Sun
Calculate the orbital radius of a geostationary satellite orbiting Saturn, where a day is 10.6 hrs? (MS = 5.7x1026 kg, rS = 5.4x107 m)
In order to find the orbital radius, we need to use Kepler's third law's equation
The formula states:
T^2/R^3 = 4pi^2/G(m)
Since the satellite is geostationary, weknow that the period of the satelitte is going to be 10.6 hours
Plugging in everything we know already
(10.6)^2/R^3 = 4pi^2/G(5.7*10^26)
(10.6)^2/4pi^2/G(5.7*10^26) = R^3
solve for R^3 = 1.08*10^17
R = 476523 m from the surface of Saturn
5.4*10^7 + 476523 = 54476523 meters for the orbital radius
Which one is the answer
The graph that shows the relationship between the speed and the kinetic energy is option B.
What is the relationship between kinetic energy and speed?Recall that the kinetic energy is referred to as the speed that a body possess by virtue of its motion. Thus an object that is in motion is said to posses the kinetic energy. The kinetic energy is the energy of an object that has a velocity
The kinetic energy is linearly related to the speed of the object. This implies that the speed is directly proportional to the kinetic energy of the object. If there is a direct relationship, it the follows that the graph of the speed against the kinetic energy of the object ought to be a straight line graph.
As such, the relationship between the kinetic energy and the speed of the object can be seen from the image in option B.
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A group of students must design an egg-carrying device that will prevent a raw egg from breaking when it is dropped from a two-story
window The diagram shows one group's design. How does the parachute help to minimize the force on the egg upon impact with the
ground?
Hydraulic systems utilize Bernoulli’s principle. T. F.
its FALSE
The answer is true, that the hydraulic press utilizes Bernoulli's principle.
It can be derived from the Principle of conservation of energy.
What is Bernoulli's Principle?According to Bernoulli's principle, which governs fluid dynamics, a fluid's speed increases concurrently with a reduction in pressure or potential energy. The mathematical concept is named after Swiss mathematician Daniel Bernoulli, who first published it in his book Hydrodynamics in 1738.
The venturi tube is a real-world example of Bernoulli's Principle in action. The venturi tube has an air intake that constricts to a throat and an exit segment that widens as it moves backward. The entrance and outflow both have the same diameter.
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module 2 question 3
You drive 5.00 km in a straight line in a direction 20° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.
The distance to drive East is 1.7 km and the distance you would have to drive North is 4.7 km
The North-East, East and North travel distances from a right angled triangle. So trigonometric ratios are applicable.
sin θ = East distance / NE distance
sin 20° = East distance / 5
East distance = 1.7 km
cos θ = North distance / NE distance
cos 20° = North distance / 5
North distance = 4.7 km
Some of the basic trigonometric ratios are:
sin θ = Opposite side / Hypotenusecos θ = Adjacent side / Hypotenusetan θ = Opposite side/ Adjacent sideTherefore, the distance to drive East is 1.7 km and the distance to drive North is 4.7 km
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calculate the net force acting on the box in the following. refer to the screenshot below.
The net force acting on the box is 5N , and it is unbalanced.
since the forces acting on the system is 7N and 2N which is opposite direction.
Explanation:The sum of all forces acting on an object is known as net force. Newton's second law, which states that F = ma, where F is the net force, can be used to calculate the net force. m is the object's mass. a represents acceleration.When two forces act in the same direction on an object, the net force equals the sum of the two forces.In general, when opposing forces act on an object, such as the book on the table, the net force equals the difference between the two forces. In other words, the net force is calculated by subtracting one force from the other. The net force is zero if the opposing forces are equal or balanced.
here given two forces ,
f1 = 7N
f2 = 2N
since both forces are in opposite direction ,
Net force = f1 - f2
= 7N - 2N
= 5N
so the net force that act on the given box is 5N and unbalanced .
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Problem 7(a) Two different heavy objects are dropped from the same height. State
a) the acceleration of free fall of each object.
b) State any assumptions made.
The acceleration of free fall of each object will be the same.
An assumption made is that both objects must be on Earth.
What is acceleration of free fall?
The acceleration of free fall of every object is the acceleration experienced by the freely falling object as a result of the effect of gravitation of earth alone.
Mathematically, the formula for acceleration of free fall of every object on earth is given as;
g = GM/R²
where;
G is universal gravitation constantM is mass of the objectR is radius of the objectg is acceleration due to gravityThe value of acceleration due to gravity on Earth is 9.8 m/s².
Since both objects are dropped from same height on Earth, they will experience equal acceleration of free fall.
The assumptions made are;
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Three forces act on a moving object. One force has a magnitude of 84.4 N and is directed due north. Another has a magnitude of 42.7 N
and is directed due west. What must be (a) the magnitude and (b) the direction of the third force, such that the object continues to
move with a constant velocity? Express your answer as a positive angle south of east.
The direction of the third force, such that the object continues to
move with a constant velocity is 94.5N at 0.19° south of east.
What is applied force?The force that one thing exerts on another. A barrel being pushed by a human is an illustration of applied force. When the individual pushes the barrel, the barrel experiences an applied force. Newton's second law of motion defines the force formula as follows: A force is equal to an object's mass times its acceleration, or F = m a. You must use SI units when applying this formula: kilograms for mass, meters per second squared for acceleration, and newtons for force. a push or pull that an object has experienced. Here, an object is given a force by a person or any other thing. A chair being pushed to the opposite side of the room, for instance.
For the object to move with constant velocity the total acceleration must be zero.
So,
Total F = [tex]F_{1} +F_{2} +F_{3}[/tex]
ma = 0
[tex]F_{1}[/tex] = 84.4N
[tex]F_{2}[/tex] = 42.7 N
[tex]F_{3} = -F_{1} - F_{2}[/tex]
= 94.58 N
TanФ = 0.19°
Hence [tex]F_{3}[/tex] = 94.5N at 0.19° south of east.
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A hydraulic lift is used to lift a car. The small piston has a radius of 5 cm and the large piston has a radius of 50 cm. If a driver applies a force of 88 N to the small piston, what is the weight of the car the large piston can support?
Answer:
F = 880 N
Explanation:
Apply Pascal's Principle.
f / a = F / A
Because the pressure (P = F/A) is equal on both sides of the piston.
So, using the International System of Units:
f / a = F / A
88 / 0.05 = F / 0.50
F = (88/0.05) * 0.50
F = 880 N
PLEASE HELP QUICKLY
Félix baumgartner jumps out of a hot air balloon at a height of 39km. He wears a special suit and his total mass is 120kg. He was the first person to break sound barrier( at a velocity of 343m/s). Calculate how far in km he had fallen to break the sound barrier
The distance in Km he has fallen to break the sound barrier is 6 Km
To obtain the answer to the question, we'll beging by calculating the time taken to break the sound barrier. This can be obtained as follow:
Initial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Final velocity (v) = 343Time (t) = ?v = u + gt
343 = 0 + (9.8 × t)
343 = 0 + 9.8t
343 = 9.8t
Divide both sides by 9.8
t = 343 / 9.8
t = 35 s
How to determine the heightFinally, we can obtain the height as follow:
Time (t) = 35 sAcceleration due to gravity (g) = 9.8 m/s²Height (h) =?h = ½gt²
h = ½ × 9.8 × 35²
h = 4.9 × 1225
h = 6002.5
Divide by 1000 to express in Km
h = 6002.5 / 1000
h = 6 Km
Thus, Félix baumgartner broke the sound barrier when he had fallen 6 Km
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A ball is thrown vertically upward with a speed of
25.0 m/s from a height of 2.0 m.
a. How high does the ball rise?
b. How long does it take to reach its highest point?
c. How long does the ball take to hit the ground
after it reaches its highest point?
d. What is the ball's velocity when it returns to
the level from which it started?
a.) the ball rises to a height of 31.88m
b.) It takes the ball 2.55 seconds to reach its highest point
c.) It takes the ball 2.55 seconds to hit the ground
d.) The ball's velocity is -24.99 m/s in the negative direction which is downwards.
What is velocity?Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
From the given question, we have that
b.) At highest point velocity of the ball will become zero so v=0m/s.
So using equation
v = u + gt
0 = 25 - 9.8t
t = 25/9.8 s =2.551 s
Time taken by the ball to reach its highest point will be 2.551 seconds .
a.) The height the ball rises is given by
v²-u²=2gh
=> 0-(25.0)²=-2*9.8*h
=> 19.6h= (25.0)²
=> h= 31.88m.
c.) It will take the ball 2.55 seconds to hit the ground
after it reaches its highest point because it will take the ball same time for the ball to reach its highest point or fall to the ground.
d.) velocity = u - gt
V = 0 - 9.8 * 2.55
V= -24.99 m/s in the negative direction which is downwards.
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a crate is accelerated at .035 m/s for 28.0 s along a conveyor belt. If the crates initial speed is 0.76 m/s what is it's final speed?
The final speed of the crate with an initial speed of 0.76 m / s accelerated at 0.035 m/s for 28.0 s along a conveyor belt is 1.74 m / s
v = u + at
v = Final speed
u = Initial speed
a = Acceleration
t = Time
a = 0.035 m / s²
y = 28 s
u = 0.76 m / s
v = 0.76 + ( 0.035 * 28 )
v = 0.76 + 0.98
v = 1.74 m / s
The equation used to solve the problem is an equation of motion. An equation of motion describes the position of an object using acceleration, displacement, time, initial and final velocities.
Therefore, the final speed of the crate is 1.74 m / s
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the angular velocity of a rotating rigid body is -4+j-2k.find the linear velocity if a point p(5,1,3) on the body relative to a point Q(3,4,2) on the axis of rotation
The linear velocity of a point p(5,1,3) on the body relative to a point Q(3,4,2) on the axis of rotation is 17.13 m/s.
What is linear velocity?
Linear velocity is defined as the rate of change of displacement with respect to time when the object moves along a straight path.
The relationship between linear velocity and angular velocity is given as;
v = ωr
where;
ω is angular speed of the objectr is the radius of the circular pathv is the linear speed of the objectThe magnitude of the radius is calculated as follows;
r = √[(5-3)² + (1-4)² + (3-2)²]
r = 3.74 m
The magnitude of the angular speed is calculated as;
ω = √[(-4)² + (1)² + (-2)²]
ω = 4.58 rad/s
The linear speed of the object is calculated as follows;
v = ωr
v = (4.58 rad/s) x (3.74 m)
v = 17.13 m/s
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Jerry is unable to pick up the picnic
basket, then he eats spinach and
becomes stronger. Now he can easily lift
up the basket.
This is an example of F=ma
because.
This is an example of F = ma because the net force applied is directly proportional to the weight (mass) of the basket.
What is Newton's Second Law of Motion?Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.
Mathematically, Newton's Second Law of Motion is given by this expression;
F = ma
Where:
F represents the net force.m represents the mass of a physical object.a represents the acceleration of a physical object.In conclusion, the above scenario is an example of the demonstration of Newton's Second Law of Motion.
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what is friction with its SI unit
When two surface attach each other a force is produced called friction. It's SI unit is newton
PLEASE HELP!
1. Terry kicks a soccer ball that is sitting motionless on the field. What is the best description of the energy transfer? (1 point)
A. Kinetic energy is transferred from the soccer ball to Terry's foot
B. Kinetic Energy is Transferred from Terry’s foot to the soccer ball.
C. Kinetic Energy in Terrys Foot is changed to potential energy in the Soccer ball
D. Potential energy is transferred from Terry’s foot to the Soccer ball
2. Which of the Following scenarios best shows the transfer of kinetic energy?
A. a Baseball bat strikes a baseball
B. A baseball player holds a baseball at their side
C. a baseball sits on a bench
D. a baseball flies through the air
3.
A bowling ball is traveling at 7 6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
KB = m²
A. 173.28 J
B. 228 J
C. 346.65 J
D. 693 12 J
4. What happens when a tennis racket hits a ball?
A. Kinetic energy is created.
B. Potential energy in the racket is transferred to the ball.
C.Kinetic energy is transferred from the ball to the racket.
D.Kinetic energy is transferred from the racket to the ball.
Answer:
1. B. Kinetic energy is transferred from Terry's foot to the soccer ball.
2. A. A baseball bat strikes a baseball.
3. A. 173.28J
4. D. Kinetic energy is transferred from the racket to the ball.
Explanation:
I took the quiz and got 100%
Answer:
1. Kinetic energy is transferred from Terry's foot to the soccer ball.
2. A baseball bat stricks a baseball
3. 173.28
4. kinetic energy is transferred from the racket to the ball
5. 1,102.5 J
remember to keep the decimal on the last one
Explanation: They added another question so I decided to give the answer to those who had it.
1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C. What is the specific heat of the metal?
Ice: c = 2000 J/(kg*C)
(Unit = J/(kg*C))
The specific heat of the metal is 2178.7 J/kg⁰C.
What is specific heat capacity?The specific heat capacity of a substance is the quantity of heat needed to raise a unit mass of a substance by 1 kelvin.
The specific heat capacity of the metal is calculated by applying the principle of conservation of energy.
Heat lost by the metal = Heat gained by the ice
m₁c₁(T₁ -T) = m₂c₂(T - T₂)
where;
m₁ is mass of the metalm₂ is mass of the icec₁ is specific heat capacity of the metalc₂ is specific heat capacity of the iceT is the equilibrium temperatureT₁ is the initial temperature of the metalT₂ is the initial temperature of the water(1)(c₁)(5 - -8.88) = (1)(2000)(-8.88 - - 24)
(1)(c₁)(5 + 8.88) = (1)(2000)(-8.88 + 24)
13.88c₁ = 30,240
c₁ = 30,240/13.88
c₁ = 2178.7 J/kg⁰C
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Answer:
2180
Explanation:
trust me bro
Calculate the braking distance force for a driver of a 1200kg car traveling at an initial speed of 10m/s above with a braking force of -8000N
The braking distance of the driver of a 1200 kg car traveling at an initial speed of 10m/s is 7.5 m
How to determine the distanceWe'll begin by obtainig the acceleration of the car. This can be obtained as follow:
Mass (m) = 1200 KgForce (F) = -8000 NAcceleration (a) =?Force = mass × acceleration
-8000 = 1200 × a
Divide both sides by 1200
a = -8000 / 1200
a = -6.67 m/s²
Finally, we shall determine the distance. Details below
Initial velocity (u) = 10 m/sFinal velocity (v) = 0 m/s (at maximum height)Acceleration(a) = -6.67 m/s²Distance (s) =?v² = u² + 2as
0² = 10² + (2 × -6.67 × s)
0 = 100 - 13.34s
Collect like terms
0 - 100 = -13.34s
-100 = -13.34s
Divide both side by -13.34
s = -100 / -13.34
s = 7.5 m
From the above calculation, we conclude that the breaking distance is 7.5 m
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Figure 3 shows a 40 kg crate that is being pushed with constant velocity at a distance 8.0 m along a 30° incline plane by the horizontal force of 500N. The coefficient of kinetic friction between the crate and the incline, µk is 0.42. Assuming the crate is moving upwards towards the right, calculate the work done by the applied force, the frictional force and the gravitational force and the net work done on the crate.
Based on the given figure, you have that the components of the forces on the direction of the incline are:
applied force:
Fa = 500N*cos(-30°) = 433.01N
friction force:
Fr = µk*N = µk*m*g*cos(30°) = (0.42)(40kg)(9.8 m/s^2)cos(30°) = 142.58N
gravitational force:
Fg = m*g*sin(30°) = (40kg)(9.8)sin(30°) = 196.0N
Next, consider that the work done by a force is equal to the product of the force and the distance at which the force is applied. In this case, such distance is 8m.
Then, you have:
Work done by the applied force:
WFa = (433.01N)(8.0m) = 3464.08 J
Work done by the friction force:
WFr = (142.58N)(8.0m) = 1140.64 J
Work done by the gravitational force:
WFg = (196.0N)(8.0m) = 1568.0 J
Finally, the net work, based on the direction of the forces, is:
Net work = WFa - WFr - WFg = 3464.08J - 1140.64J - 1568.0J = 755.44J
Hence, the net work is 755.44 J
Answer: Wfr = -1883.25 J
Explanation:
1) In the x direction (direction of motion of the crate):
Fcos(30^o) - f_fr - mgsin(30^o ) = 0 (because a_x = 0)
f_fr = Fcos(30^o ) - mgsin(30^o)
f_fr = (498)(√3/2) - (40)(9.81) (1/2) = 235.28 N
⇒ W_fr = f_fr.s.cos(180^o) = -(235.28)(8.0) = -1882.25 J (1)
2) In the y direction (perpendicular to the motion of the crate):
n - Fsin(30^o) - mgcos(30^o) = 0 (because a_y = 0)
⇒ n = Fsin(30^o) + mgcos(30^o) = (498)(1/2) + (40)(9.81)(√3/2) = 588.83 N
⇒ f_fr = μ_k.n = (0.40)(588.83) = 235.53 N
⇒ W_fr = f_fr.s.cos(180^o ) = -(235.53)(8.0) = -1884.24 J (2)
Average of calculations (1) & (2): W_fr = -1883.25 J
14. A 5.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball
How fast does the ball need to be moving in order to send the man off at a speed of
3.00 m/s?
Answer:
V₁ = 48 m/s
Explanation:
Using the Conservative Law of Momentum:
∑Qₓ = 0
Q₁ + Q₂ = 0
Q₁ = Q₂ (In absolute values)
Where:
Q₁: right before the impact
Q₂: right after the impact
So:
Q₁ = Q₂
m₁*V₁ + m₂*V₂ = m₁*V + m₂*V (Because both ball and man moves together)
5 * V₁ + 75 * 0 = (5 + 75)*3
5V₁ = 80 * 3
V₁ = 240/5
V₁ = 48 m/s
calculate the current that flows through a 60W bulb if the voltage across is 230V
The current flow through a 60W bulb if the voltage across is 230V is 0.26 A.
P = V I
P = Power
V = Voltage
I = Current
P = 60 W
V = 230 V
I = P / V
I = 60 / 230
I = 0.26 A
Ohm's law states that if the temperature across a conductor remains the constant, the ratio of potential difference across the conductor to the current flowing in the conductor will also be constant.
Therefore, the current flow through a 60W bulb if the voltage across is 230V is 0.26 A.
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(Figure 1) is the potential-energy diagram for a 500 g
particle that is released from rest at A. What is the particles speed at B?
The particles speed at B is 12 m/s .
What are kinetic and potential energy?Potential energy is the energy that is held in reserve in any system or object as a result of how its components are positioned or assembled. The external environment, such as air or height, is not a factor in this, though. The energy that an object or a system's particles have while in motion, however, is known as kinetic energy. An item or particle's motion gives it kinetic energy, which it might use to move. An item accelerates and gains kinetic energy when work, which transfers energy, is done on it by exerting a net force. Potential energy is a form of stored energy that is dependent on the arrangement of a system's components. In a compressed state, a spring has higher potential energy.
The mass of the particle = 500g
= 0.5 kg
The energy of the particle when it is released
E = 5g
The potential energy at B
= 2 J
Loss in potential energy = gain in kinetic energy.
K.E.= 1/2 × m × v²
Here after putting values we get
speed at B = 12m/s.
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The components of a 15 meters per second velocity at an angle of 60 above the horizontal are
The components of a 15 meters per second velocity at an angle of 60 above the horizontal are 13.05 m / s and 0.435 m / s
Resolving the velocity into its horizontal and vertical components, it makes a right angled triangle.
Hypotenuse = V = 15 m / s
θ = 60°
Opposite side = components = [tex]V_{y}[/tex]
Adjacent side = Horizontal component = [tex]V_{x}[/tex]
In a right angled triangle,
sin θ = Opposite side / Hypotenuse
cos θ = Adjacent side / Hypotenuse
sin 60° = [tex]V_{y}[/tex] / V
[tex]V_{y}[/tex] = 15 * 0.87
[tex]V_{y}[/tex] = 13.05 m / s
cos 60° = [tex]V_{x}[/tex] / V
[tex]V_{x}[/tex] = 0.5 * 0.87
[tex]V_{x}[/tex] = 0.435 m / s
Therefore,
The horizontal component, [tex]V_{x}[/tex] = 0.435 m / sThe vertical component, [tex]V_{y}[/tex] = 13.05 m / s.To know more about components of velocity
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Compute the density in g/cm3 of a piece of metal that has a mass of 0.350 kg and a volume of 62 cm3.answer in g/cm3
We will haev the following:
[tex]\begin{gathered} \rho=\frac{350g}{62cm^3}\Rightarrow\rho=\frac{175}{31}g/cm^3 \\ \\ \Rightarrow\rho\approx5.6g/cm^3 \end{gathered}[/tex]So, the density of the material is 175/31 g/cm^; that is approximately 5.6 g/cm^3.
When light falls on a soap bubble or on the oily film spread on a water puddle, a spectrum of colors is observed. How is this spectrum of colors formed?1) separation of white light by a prism2) absorption of colors in a pigment present3) constructive and destructive interference of light waves4) reflection of light by soap bubble or oil film
When the light falls on a soap bubble spread on a water puddle, and a spectrum of color is observed due to constructive and destructive of light waves which means option (3) is correct. Light waves interfere into each other to produce a spectrum which consists of bright and dark fringes.
Atwood machine question: details are in photos attached
First, let's calculate the forces in the 3 kg mass:
[tex]W_1-T=m_1\cdot a[/tex]Then, the forces in the 2 kg mass:
[tex]T-W_2=m_2\cdot a[/tex]From the first equation, let's solve it for T:
[tex]T=W_1-m_1a[/tex]Using this value of T in the second equation, we have:
[tex]\begin{gathered} W_1-m_1a-W_2=m_2\cdot a \\ W_1-W_2=m_2a+m_1a \\ m_1g-m_2g=a\cdot(m_1+m_2)_{} \\ a=g\frac{(m_1-m_2)}{(m_1+m_2)} \end{gathered}[/tex]Finally, using the given values (with g = 10 m/s²), we have:
[tex]a=10\cdot\frac{(3-2)}{(3+2)}=10\cdot\frac{1}{5}=2\text{ m/s2}[/tex]If the acceleration is 2 m/s², after 2 seconds the speed is:
[tex]\begin{gathered} V=V_0+a\cdot t \\ V=0+2\cdot2 \\ V=4\text{ m/s} \end{gathered}[/tex]Therefore the correct option is the second one.
Which of the following describes how deforestation impacts the climate in areas where trees once stood?The elimination of a protective covering causes the sun to dry out the ground.The lack of carbon in the atmosphere causes radical temperature fluctuations.The decrease in plants to absorb water causes a greater level of water precipitation.The change in covered areas causes winds to be stronger and colder weather results.
Take into accouint that the regions that suffer deforestation tend to generate soil erosion to eventually become non-productive land.
Then, from the given choices you have that deforestation impacts in the following way:
The elimination of a protective covering causes the sun to dry out the ground.
An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward
with the horizontal.
What is the magnitude of the velocity when it hits the ground?
Answer:
Explanation:
Angle:
β = - 23°
( From the symmetry condition)