Answer:
An electric battery provides a current.. answer is continuous
a man holds a 1.00-kg box above his head for 2 minutes. the work done by the man during these 2 minutes is
The work done by the man during these 2 minutes is zero.
What is work?A force must be applied in order to produce work, and there must also be motion or displacement in the force's direction. The amount of work performed by a force acting on an item is equal to the force's magnitude times the distance travelled in the force's direction. Work has only magnitude and no direction. As a result, work is a scalar quantity.
According to the question, a man holds a 1.00-kg box above his head for 2 minutes. No displacement happens in this two minutes. So, no work is done by the man.
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1. If I drop a watermelon from the top of one of the tower dorms at JMU, and it takes
3.50 seconds to hit the ground, how tall the building is in meters.
What is the acceleration of the watermelon as it falls?
Answer:
Below
Explanation:
The accelerateinon, a, of the watermelon is just the acceleration of gravity on Earth = 9.81 m/s^2
the height will be found by
Height = 1/2 a t^2 = 1/2 (9.81)(3.50)^2 = 60.1 m
5. Distance covered by a moving body is always greater than 0.
Displacement of a particle can be >,< or=0
a.Both assertions and reason are correct, reason is the the correct explanation
b. Both assertions and reason are correct; reason isn't the correct explanation of the assertion.
c. Assertion is correct but reason isn't
d Assertion is not correct but reason is
Answer:
Explanation:
c. Assertion is correct but reason isn't
4. for the circuit in fig. 21.53: 1. find the value of l in millihenries if the resonant frequency is 1800 hz. 2. calculate xl and xc how do they compare? 3. find the magnitude of the current i rms at resonance. 4. find the power dissipated by the circuit at resonance. 5. what is the apparent power delivered to the system at resonance? 6. what is the power factor of the circuit at resonance? 7. calculate the q of the circuit and the resulting bandwidth. 8. find the cutoff frequencies, and calculate the power dissipated by the circuit at these frequencies.
Where loads are likely to be ON for 4 hours, the computed load for sizing branch-circuit conductors and OCPDs must be calculated by multiplying the actual load current times ___.
We have to multiply the actual load current times by 1.25 (2017 NEC: 210.20(A)).
NEC 210.20(A) Continuous and Noncontinuous Loads:
The rating of the overcurrent device must be no less than the noncontinuous load plus 125 percent of the continuous load when a branch circuit delivers continuous loads or any combination of continuous and noncontinuous loads.
With one exception, the ampere rating of the overcurrent device may not be less than the total of the continuous load and the noncontinuous load when the assembly, including the overcurrent devices safeguarding the branch circuit(s), is rated for operation at 100% of its rating.
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An air-filled toroidal solenoid has a mean radius of 15.0cm and a cross-sectional area of 5.00cm2 . When the current is 12.5A , the energy stored is
0.390J .How many turns does the winding have?
The number of turns the winding have in an air-filled toroidal solenoid that has a mean radius of 15.0cm and a cross-sectional area of 5.00cm2 is 2745 turns
According to Ampere's law,
B = μo N I / 2 π r
Φ[tex]_{B}[/tex] = B A
Φ[tex]_{B}[/tex] = μo N I A / 2 π r
B = Magnetic field
μo = Absolute permeability of free space
N = Number of turns
I = Current
r = Radial distance
A = Cross sectional area
U = Energy stored
U = 1 / 2 L I²
L = 2 U / I²
L = N Φ[tex]_{B}[/tex] / I
μo = 4 π * [tex]10^{-7}[/tex] H / m
U = 0.39 J
r = 15 cm = 0.15 m
I = 12.5 A
A = 5 cm² = 5 * [tex]10^{-4}[/tex] m²
Equating,
2 U / I² = N Φ[tex]_{B}[/tex] / I
2 U / I² = μo N² I A / 2 π r I
4 π r U / μo I² A = N²
N² = ( 4 * 3.14 * 0.15 * 0.39 ) / ( 4 * 3.14 * [tex]10^{-7}[/tex] * 12.5² * 5 * [tex]10^{-4}[/tex] )
N² = 0.74 / 9812.5 * [tex]10^{-11}[/tex]
N² = 7.54 * [tex]10^{6}[/tex]
N = 2.745 * 10³
N = 2745 turns
Therefore, the number of turns the winding have are 2745 turns
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Why are the inner planets (those which orbit inside the asteroid belt) all relatively small and rocky, whereas the outer planets are large and mostly composed of gas?
Answer:
The temperature of the early solar system explains why the inner planets are rocky and the outer ones are gaseous.
Explanation:
The outer planets are much larger than the inner planets. Because of their large mass and cooler temperature, they have a very different composition; they are mostly made of light elements with extended atmospheres in a gaseous form. Outer planets exist in much bigger systems than inner planets.
The reason for different composition of planets has to do with how the solar system formed. In the early solar system, there was a disk of material rotating around the Sun, from which the planets eventually formed. However, to form planets required some kind of initial clump in the protoplanetary disk. These clumps were probably formed from collisions of solid particles. Different elements become solid at different temperatures: the most common elements, hydrogen and helium, never became solid, but hydrogen compounds (like water) can solidify at colder temperatures, like those in the outer solar system. In the inner solar system, it was too hot for these compounds to solidify; only rocks and metals can solidify at these temperatures. Hence, only small planetesimals formed in the inner solar system.
an athlete swings a ball, connected to the end of a chain, in a horizontal circle. the athlete is able to rotate the ball at the rate of 7.80 rev/s when the length of the chain is 0.600 m. when he increases the length to 0.900 m, he is able to rotate the ball only 5.99 rev/s.
1276.9 m/s² is the angular acceleration of 0.900 m, he is able to rotate the ball only 5.99 rev/s.
v=33.9m/s
r=0.9 m
a=v²/r
a=1149.21/0.9
a=1276.9 m/s²
The rate at which the angular velocity in a circular motion varies over time is known as the angular acceleration. Rotational acceleration is another name for it. Given that it has both a magnitude and a direction, it is a vector quantity. Angular acceleration is represented by the letter alpha.
Variable velocity is what causes the acceleration. The phrase "angular acceleration" is used to describe variations in rotational speed in spinning objects. According to the connection, the angular displacement of a spinning object depends on time t. Every time a body rotates, it experiences angular acceleration. A quantitative vector can be used to express the change in angular velocity per unit of time.
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How long does it take to use 266 W of power pushing at 113 N for a distance of 9 meters?
The power pushing at 113 N for a distance of 9 meters. The time taken is 0.22 seconds.
Power :
Power is defined as the speed at which work is performed on an object.
work done = Force x Distance
Power = Work done/ Time
Power = (Force x Distance)/Time
Power = 226 Watt
Force = 113 N
Distance taken = 9 meters
To calculate power we use :
Power = (Force x Distance)/Time
266W = (113N x 9s)/Time
Time = 266W/(113N x 9m)
Time = 266W/(113N x 9m)
Time = 0.22 seconds
The power pushing at 113 N for a distance of 9 meters. The time taken is 0.22 seconds.
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In a game of shuffleboard (played on a horizontal surface), a puck is given an initial speed of 6. 0 m/s. It slides a distance of 9. 0 m before coming to rest. What is the coefficient of kinetic friction between the puck and the surface?.
The coefficient of kinetic friction between the puck and surface id 0.20.
What is coefficient of kinetic friction?
Coefficient of kinetic friction is the ratio between frictional force present in the motion of two surfaces that are in contact to the normal force that presses the two surface together.
It is calculated mathematically as: μ = F/N, where
F= frictional force and N= normal force.
v2 = u2 +2as
0= 62 + 2a9
18a + 36= 0
18a = -36
a= -2
friction = μ × normal force
or friction =ma
ma= μN
ma= μ(mg)
μ = a/g where g = 9.8 N
μ= -2/9.8
⇒0.20.
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Classify the disadvantages of unconventional oil and gas extraction as belonging to ei sands mining. ther hydraulic fracturing or tar Hydraulic fracturing Tar sands mining Answer Bank local groundwater contamination huge lakes of acidic and toxic wastewater Output outpaces transportation capacity requires heated pipelines for transport destroys habitat and pollutes watersheds corporate rights to oil and gas on private property The breakeven price is S60 per barrel. ye more greenhouse gas emissions Wastewater in injection wells triggers earthquakes.
The disadvantages of unconventional oil and gas extraction as belonging to tar sands mining are as follows:-
Oil and gas extraction:-
Local groundwater contaminationCorporate rights to oil and gas on private propertyWaste water in injection wells triggers earthquakesOutput outpaces transportationsTar sand mining:-
20% more greenhouse gas emissionRequires heated pipelines for transportHuge lakes of acidic and toxic waste waterDestroys habitat and pollutes watershedsLearn more about gas extraction here:- https://brainly.com/question/1990340
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Disclaimer:- your question is incomplete, please see below for the complete question.
Classify the disadvantages of unconventional oil and gas extraction as belonging to ei sands mining.
a. ther hydraulic fracturing or tar Hydraulic fracturing Tar sands.
b. mining Answer Bank local groundwater contamination huge lakes of acidic and toxic.
C. wastewater Output outpaces transportation capacity requires heated pipelines for transport destroys habitat and pollutes watersheds corporate rights to oil and gas on private property
D.The breakeven price is S60 per barrel. ye more greenhouse gas emissions Wastewater in injection wells triggers earthquakes
A car accelerates from an initial velocity of vi=20 m/s to a final velocity of bc=35 m/s in a time interval of 5 s find avarage acceleration
Answer:
Average acceleration of the car = 3 m/s²
Explanation:
According to the question,
Initial velocity of the car ([tex] \rm v_i [/tex]) = 20 m/s
Final velocity of the car ([tex] \rm v_f [/tex]) = 35 m/s
Time interval of uniform acceleration (t) = 5 s
By using [tex] 1^{st} [/tex] kinematic equation and substituting value we get:
[tex] \rm \implies v_f = v_i + at \\ \\ \rm \implies at = v_f - v_i \\ \\ \rm \implies a = \dfrac{v_f - v_i }{t} \\ \\ \rm \implies a = \dfrac{35 - 20 }{5} \\ \\ \rm \implies a = \frac{15}{5} \\ \\ \rm \implies a = 3 \: m {s}^{ - 2} [/tex]
[tex] \therefore [/tex]
Average acceleration of the car is 3 m/s²
consider two satellites s1 and s2 in circular orbits with periods of 8 hours and 16 hours how high are the satellites above the earth's surface?
Consider two satellites s1 and s2 in circular orbits with periods of 8 hours and 16 hours . satellites will be 80129 m and 130829 m high above the earth's surface
h1 = [tex]{(GM(e) * T^{2} / 4 pi^{2} )}^{1/3}[/tex] - R(e)
= ( 6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] * [tex]8^{2}[/tex] / 4 * [tex]3.14^{2}[/tex]) - 6371
= 80129 m
h2 = (6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] * [tex]16^{2}[/tex] / 4 * [tex]3.14^{2}[/tex]) - 6371
= 130829 m
satellites will be 80129 m and 130829 m high above the earth's surface
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What particle determines how an atom bond
A 950 kg truck accelerates from rest to 15 m/s in 2. 3 seconds as it drives down a rough road. If the forward force of the engine is 7000 newtons determine the force of friction between the tires and the road? express your answer in newtons.
Because friction always opposes motion, according to Newton's second law of motion, F f 804 N.
What is the example of friction?Vehicle operation on a surface- When a truck is being driven, the engine exerts a force on the wheel that propels the vehicle forward. The vehicle can't move ahead because of the friction between both the wheels as well as the ground. Consequently, the car keeps from skidding.
What avoids rubbing?The resistance between the surfaces can be decreased by using lubricants like oil or grease. Friction can be decreased by polishing its surface, which makes it smooth.
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a weather balloon is floating at a constant height above earth when it releases a pack of instruments. if the pack hits the ground with a velocity of -76.5 m/s what is the packs displacement? how long does the pack fall?
Answer:
below
Explanation:
vf = 76.5
vf= at
76.5 = 9.81 t shows t = 7.798 s
d = 1/2 a t^2 = 1/2 ( 9.81)(7.798)^2 = 298.3 m
A patient with end-stage heart disease asks, "after i meet the physical criteria for a heart transplantation, will i then be selected as a candidate?" which response from the nurse is the most appropriate?.
Patients ought to meet physical and psychological standards to make sure that they may be candidates for coronary heart transplantation.
The Recipient affected person has to be referred to the transplant center with an irreversible and in any other case fatal disease ensuing in organ failure, whilst still being otherwise wholesome enough to live to tell the tale and gain from an organ transplant and to comply with a lifestyles-long medication routine.
Physical criteria indications for transplant in continual heart failure include sufferers who've disabling signs regardless of most fulfilling medical control or refractory arrhythmias no matter scientific and electrophysiological methods.
The doctor will make an incision on your chest. Your health care professional will separate your chest bone and open your rib cage in order that he or she will perform for your coronary heart. Your medical professional then removes the diseased heart and sews the donor heart into place. she or he then attaches the important blood vessels to the donor's coronary heart.
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what is the range of frequency that the 3 db point occurs in? group of answer choices 0 to 10 hz 10 to 100 hz 100 to 1000 hz 1000 to 10000
The correct option is 10 to 100 Hz. A low pass and high pass filter are cascaded to create a band pass filter. It has two reactive elements, making it a second order filter.
The signal strength to frequency graph looks like this because this filter favors high frequencies: We may do a variety of signal processing operations using the low-pass and high-pass filters, including picking out a certain frequency band. We can easily sketch the perfect filter response since the -3dB point is also quite near to the place where the "unity gain" line and the asymptote for the filter's roll-off curve intersect.
Drawing piecewise-linear approximations for filter performance is no longer necessary in modern times thanks to the usage of computers, but this was not the case when electrical circuit design and analysis first started. Even with the introduction of electronic calculators, the majority of these activities were still done by hand.
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Which form of electromagnetic radiation has photons with the highest energy? Group of answer choices Infrared Radiation Gamma Rays Microwaves Radio Waves X-rays
Gamma rays is a form of electromagnetic radiation that has photons with the highest energy.
Gamma rays are a form of electromagnetic radiation (EMR). They are the similar to X-rays, distinguished only by the fact that they are emitted from an excited nucleus.
The energy of the photon is directly proportional to the frequency, that is Ε α υ. It means that if the photon has high frequency, then the energy of that photon will be high, and if the photon has lower frequency then the energy that the photon will be less.
Here it is given to determine the radiation that has high energy, which in turn means that radiation with the highest frequency is needed to be found. Hence, from the data of electromagnetic spectrum, the radiation with the highest frequency is the gamma rays with frequencies up to 10^19 Hz.
As gamma rays have the highest frequency, gamma rays will also have the highest energy, with energy extending up to few trillion electron volts.
Hence, the radiation with the highest energy is gamma rays.
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The parallax angle for the star Hadar is 0.010 arcseconds. How far away is Hadar?
The parallax angle for the star Hadar is 0.010 arcseconds. 100 PC far away is Hadar.
Parallax angle is a displacement or distinction in the apparent function of an item considered alongside two one-of-a-kind lines of sight and is measured by the attitude or semi-perspective of inclination among those two lines. because of foreshortening, close-by objects display a bigger parallax than farther items when found from distinct positions, so parallax may be used to determine distances.
To a degree of big distances, including the gap between a planet or a star from Earth, astronomers use the precept of parallax. right here, the term parallax is the semi-perspective of inclination between sightlines to the megastar, as observed while Earth is on contrary sides of the solar in its orbit. those distances shape the lowest rung of what's called "the cosmic distance ladder", the first in a succession of methods by which astronomers determine the distances to celestial items, serving as a basis for other distance measurements in astronomy forming the higher rungs of the ladder.
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You charge your cell phone every night while you are sleeping.
Throughout the school day you see your cell phone battery slowly decline. By
lunchtime your cell phone is almost dead. You remember in science class your
teacher saying that energy can't be created or destroyed. If the energy in your cell
phone battery wasn't destroyed, where did it go? Explain your answer,
Answer:Simple, it gets used up by the phone.
Explanation:Your phone uses the energy stored in the battery to perform the functions it does. Chemical energy gets converted to light (display), sound (speakers), electrical (internal processing of the phone), thermal (phone getting heated up), and to other forms.
a spring with a spring constant of 8.0 n/m is initially compressed to 5.0 cm. the work done as it is compressed another 15 cm, to a total compression of 20 cm is: a. 0.85 j. b. 0.54 j. c. 0.25 j. d. 0.15 j. e. 0.09 j.
When a spring with an initial compression of 5.0 cm is compressed by 0.15, a total compressed of 20 cm is achieved. as it is compressed another 15 cm, the work is completed. spring constant 8.0 n/m
The spring constant can be calculated using the spring constant. Springs that are more rigid are more likely to be challenging to stretch. Elastic substances make up springs. spring constant deforms when external forces are applied, but it returns to its original position once the force is removed. A linear elastic deformation has occurred with the spring. The relationship curve between force and displacement is linear.
A type of compressed spring that generates linear force is the spring.
Work completed, w = 0.5 k x - 0.5 ky
W= 1/2K (x^2 - y^2 )
W = 1/2 ( 8 ) / (20 * 10^ -2 ) ^2 - ( 5* 10 ^-2 ) ^2 J
W = 0.15 J
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a boy on board a cruise ship drops a 30.0-g marble into the ocean. if the resistive force proportionality constant is 0.500 kg/s, what is the terminal speed of the marble in m/s?
The terminal speed of the marble is 0.588 m/s.
What is speed ?"Speed" is a common name for a variety of stimulants used by teens, young adults, and others to make them more alert, focused, and sometimes uplifting. Some people use different speeds to curb their appetite.Velocity is the percentage of time an object moves along a path, and Velocity is the speed and direction of an object's movement.Speed is the street name for amphetamine sulfate, but it is sometimes used to refer to other amphetamines.It is usually an off-white or pink marble that can also appear as crystals. Some are pasty, usually white/grey or brown, and can be moist and gritty.To learn more about speed from the given link :
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an astronomer states that star p has a lower absolute brightness than star q. how would you translate this observation for a non-scientist? a star p is shinier than star q. b star q gives off more light than star p. c stars p and q are the same brightness but different distances from earth. d star p is much closer than star q.
An astronomer states that star p has a lower absolute brightness than star q. Option B. b star q gives off more light than star p.
According to astronomers Stars have a wide variety of obvious brightness measured right here on this planet. The version of their brightness is resulting from both versions of their luminosity and versions of their distance.
The plain brightness of a star is proportional to one divided by means of its distance squared. that is, if you took a star and moved it twice as some distance away, it might appear 1/4 as bright; in case you moved it four times the distance, it'd appear 1/sixteen as brilliant.
Apparent value is the brightness of a celeb because it seems to the observer. this is what stargazers look at after they take a look at the sky and notice that a few stars are brighter than others. Absolute significance is the brightness of a star from a distance of 10 parsecs away
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HELP PHYSICS 100PTS!!!
Two uniform disks with the same mass are
connected by a light inextensible string sup-
ported by a massless pulley on a frictionless
axis. The string is attached to a point on the
circumference of disk A (on the left) and is
wound around disk B (on the right) so that
the disk will rotate like a yo-yo when dropped.
the answer is WE GO DOWN 89W8 >#*#,'
A charming friend of yours who has been reading a little bit about astronomy accompanies you to the campus observatory and asks to see the kind of star that our sun will ultimately become, long, long after it has turned into a white dwarf. Why is the astronomer on duty going to have a bit of a problem satisfying her request?.
Following cooling, a white dwarf becomes too cold and dark to emit visible light.
What is white dwarf?
Like our Sun, medium-mass stars generate helium by fusing hydrogen within their cores. Our Sun is now performing this. An outward pressure results from the heat the Sun produces during the nuclear fusion of hydrogen into helium. The Sun will run out of hydrogen in its core in about 5 billion years.
The Sun begins to collapse when it runs out of hydrogen to fuse, tipping the scales in favor of gravity. However, compacting a star makes it heat up once more, allowing it to fuse what little hydrogen is left in a shell surrounding its core.
We can learn about the age of the universe from white dwarfs. Our galaxy and the age of the universe would be lowered if we could calculate how long it takes for a white dwarf to cool into a black dwarf.
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Candace is a goalie on her hockey team who has a reputation for stopping every puck before it enters the goal. Which skill most likely helps candace respond as the puck flies in her direction?.
Reaction time is the skill that mostly helps candace respond as the puck flies in her direction
Reaction time (RT) is a measure of the quickness with which a person responds to some sort of stimulus. It is defined as the interval of time between the stimulus and voluntary response in the subject.
Her reaction time is really quick , She reacts quickly to the different areas that the puck is going and is able to go across the crease to stop it
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scientists attribute some global warming and cooling periods to the culmination of the effects of the milankovitch cycles. milankovitch cycles are variances in earth's axis and orbit that correspond to the earth's position in relation to the sun. classify each constituent of the milankovitch cycles as pertaining to orbital eccentricity, axial tilt, or axial precession.
Each constituent of the Milankovitch cycles as pertaining to orbital eccentricity, axial tilt, or axial precession are classified accordingly.
The constituents of the Milankovitch cycles as pertaining to orbital eccentricity are:
Path varies from round to elliptical.100000 year cycleThe earth's changing distance from sun during orbit impacts the climate , sometimes producing glacial periods.The constituents of the Milankovitch cycles as pertaining to axial tilt are:
41000 year cycle.Changes to earth's orientation to the sun affect the severity of seasons.The angle of earth's tilt change as it spins on its axis.When the angle from vertical is greater , seasons become greater in variability.The constituents of the Milankovitch cycles as pertaining to axial precession are:
20000 year cycle.The earth "wobbles" on its axis, which can change the orientation of the axis with celestial bodies.Therefore, each constituent of the Milankovitch cycles as pertaining to orbital eccentricity, axial tilt, or axial precession are classified accordingly.
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what is the difference between average speed, average velocity, and instantaneous velocity mathematically?
Divided by the amount of time passed, the average speed is obtained. The limit of average velocity as elapsed time approaches zero is the instantaneous velocity of an object. v (t) = d d t x (t). v (t) = d d t x (t).
The average velocity rate of change is a measure of how much one variable has changed overall relative to another. The instantaneous rate of change, also known as the derivative, quantifies the precise rate at which one variable changes in relation to a precise, extremely small change in another variable.Average speed is the ratio of an object's total distance travelled to its total travel time. Average acceleration is calculated by dividing the change in velocity by the amount of time that has passed; instantaneous acceleration is the acceleration at a specific time. Average acceleration is the acceleration at a specific moment in time; instantaneous acceleration is the velocity change divided by the amount of time that has passed. As a result, only when the body is moving at a constant speed can instantaneous speed and average speed be equal. Instantaneous speed and instantaneous velocity have the same magnitude.
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the drawing shows a skateboarder moving at 6.90 m/s along a horizontal section of a track that is slanted upward by 0
The maximum height H to which she rises above the end of the track that is slanted upward by 48° above the horizontal at its end is 1.11 m
KE = 1 / 2 m v²
PE = m g h
According to law of conservation of energy,
KE ( Initial ) + PE ( Initial ) = KE ( Final ) + PE ( Final )
h ( Initial ) = 0
v ( Initial ) = 6.9 m / s
g = 9.8 m / s²
h = 0.4 m
1 / 2 m vi² + m g hi = 1 / 2 m v² + m g h
1 / 2 m vi² = 1 / 2 m v² + m g h
vi² = v² + 2 g h
6.9² = v² + ( 2 * 9.8 * 0.4 )
v² = 47.61 - 7.84
v² = 39.77 m / s
H = vi² sin²θ / 2 g
θ = 48°
H = 39.77 * sin²48° / ( 2 * 9.8 )
H = 21.78 / 19.6
H = 1.11 m
Therefore, the maximum height H to which she rises above the end of the track is 1.11 m
The given question is incomplete. The complete question is;
The drawing shows a skateboarder moving at 6.9 m/s along a horizontal section of a track that is slanted upward by 48° above the horizontal at its end, which is 0.40 m above the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to which she rises above the end of the track.
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