An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars over domestic Step 1 of 2: Suppose a sample of 2676 new car buyers is drawn. Of those sampled, 642 preferred foreign over domestic cars. Using the data, estimate the proportion of new car buyers who prefer foreign cars. Enter your answer as a fraction or a decimal number rounded to three decimal places. AnswerHow to Enter 2 Points Tables Keypad Keyboard Shortcuts An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars over domestic. Step 2 of 2: Suppose a sample of 2676 new car buyers is drawn. Of those sampled, 642 preferred foreign over domestic cars. Using the data, construct the 98 % confidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars. Round your answers to three decimal places, Answer low to Enter) 2 Points T Tables Keypad Keyboard Shortcuts Lower endpoint Upper endpoint:

The amount of waste is 22 oz

The weights of the 3 rainbow trouts are:

3 Ib 5 oz, 2 Ib 12 oz, and 3 Ib 8 oz.

The total weight is:

Total = 3 Ib 5 oz + 2 Ib 12 oz + 3 Ib 8 oz

Evaluate the sum

Total = 8 Ib 25 oz

The amount she was left with is 8 Ib 2 oz

Subtract this amount from the total

Waste = 8 Ib 25 oz - 8 Ib 2 oz

Evaluate

Waste = 22 oz

Hence, the amount of waste is 22 oz

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The values of x and y by the descriptions in the task content are; 7.5 and 9 respectively.

It follows from the task content that the description in the task content registers the bottom right angle measure of the second intersection as equal to 10y.

Hence, it follows that; 10y = 90 and; y = 9.

From the first intersection; 6x + 5y = 90;

6x + 5(9) = 90

6x + 45 = 90

6x = 45

x = 45/6 = 7.5

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Step-by-step explanation:

6+8-90+90008-70000000

All possible lengths of segment AB wil be 27 < AB < 81.Option b is correct

A triangle is a three-sided polygon. It is one of the most fundamental geometric forms.

Any two triangle sides' lengths added together are longer than the third side's length.

The triangular inequality theorem is applied in three ways;

1.

AC+BC > AB

27+54 > AB

81 > AB

2.

27+AB > 54

AB> 54-27

AB > -27

3.

54+AB > 27

AB > 27-54

AB > -27

All possible lengths of segment AB wil be 27 < AB < 81.

Hence option b is correct

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Answer:

27 < AB < 81

Step-by-step explanation:

The answer above is correct.

The number of watches that just be sold is 90 and the profit is -356400.

From the information given, the equation is given as:

P = −50x² + 550x − 900

P = -5x² + 55x - 90

= -5x² + 45x + 10x - 90

= -5x(x - 9) + 10(x - 9)

= (-5x + 10)(x - 9)

x - 9 = 0

x = 0 + 9 = 9

The watches that must be sold will be (9 × 10) = 90

The profit will be:

P = −50x² + 550x − 900

P = -50(90)² + 550(90) - 900

P = -405000 + 49500 - 900

P = -356400

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A horizontal translation of the function by 4 units and a vertical translation down by 3 units

The parent function of the given function is g(x) = |x|. The resulting function (x) = | 2x − 4 | − 3 shows the following translations

A vertical stretch of the graph by 2 units

A horizontal translation of the function by 4 units and a vertical translation down by 3 units

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Answer: x=-1 and y=-2

If we know the concepts of transformations and horizontal translation and that f(x) = √x and k = - 2, then the transformed function is g(x) = √(x + 2).

The transformation of functions are operations which modify the relationship between input and outputs in a function. The parent function represents a canonical square root function and the transformed function is the consequence of applying a horizontal translation.

This kind of transformation is defined by the following expression:

g(x) = f(x - k)     (1)

Where k represents a rightward translation for k > 0.

If we know that f(x) = √x and k = - 2, then the transformed function is g(x) = √(x + 2).

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The area of the deck is 413 square feet

Start by calculating the area of the outer rectangle using:

Area = Length * Width

This gives

Area1 = (18 + 12) * (16 + 8)

Area1 = 720

Next, calculate the area of the inner rectangle using:

Area = Length * Width

This gives

Area2 = 16 * (18 + 8)

Area2 = 416

Subtract these areas

A1 = Area1 - Area2

A1 = 720 - 416

A1 = 304

Next, calculate the area of the outer semicircle using:

Area = 0.5πR²

This gives

Area1 = 0.5 * 3 * (12-1)²

Area1 = 181.5

Next, calculate the area of the inner semicircle using:

Area = 0.5πr²

This gives

Area2 = 0.5 * 3 * (7)²

Area2 = 73.5

Subtract these areas

A2 = Area1 - Area2

A2 = 181.5 - 73.5

A2 = 108

Add A1 and A2

A = 304 + 108

Evaluate the sum

A = 412

Hence, the area of the deck is 413 square feet

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Answer: 140°

Step-by-step explanation:

- all straight lines are 180°

- since ACD and DCB help to create the straight line they must equal 180° when combined

- so 180 - 40 = 140

- therefore, ACD is 40° and DCB is 140°

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Answer:

2nd option

Step-by-step explanation:

the quadrilateral has 1 pair of parallel sides and is therefore a trapezoid.

• each lower base angle is supplementary to the upper base angle on the same side, that is

∠ 1 + ∠ 2 = 180° , so

x + x + 50 = 180

2x + 50 = 180 ( subtract 50 from both sides )

2x = 130 ( divide both sides by 2 )

x = 65

then

∠ 1 = x = 65°

∠ 2 = x + 50 = 65 + 50 = 115°

Using the arc length formula, the length of ST in the circle is: 15 units.

Arc length of a circle = ∅/360 × 2πr.

In the image given, we have:

∅ = m∠TSU = 72º

Arc length TU = 6π

r = ST

Plug in the values

6π = 72/360 × 2π(ST)

6π = 0.2 × 2π(ST)

6π/2π = 0.2 × ST

3 = 0.2(ST)

3/0.2 = ST

ST = 15 units.

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When writing an informative essay about an event in history, you should:

To avoid finding it difficult to find information on your topics, pick a topic that has been well researched and has several sources of information on it. European history is well researched.

In the introduction, talk about why you think this topic is significant and include a thesis statement that would be the main logic you are producing details about.

Then divide this thesis into several points and talk about each point in a different paragraph. Use sentences that are not too long so that people don't lose interest.

Use primary and secondary information sources but make sure you reference these sources in the required format.

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The distance from the center of dilation, P, to.the image vertice S' is; 6 units.

It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.

Ultimately, since the dilation factor is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6 units.

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Answer: OPTION C

Step-by-step explanation:

Answer:

1 9/20x or 29/20x

Step-by-step explanation:

Reorder so it can be seen better

5x-4x+1/5x+1/4x

Combine like terms

x+1/5x+1/4x

Common multiple

x+4/20x+5/20x

Combine like terms

9/20x+x

Finalize

29/20x

Simplified

1 9/20x

Answer: -1/20x

Step-by-step explanation:

got all 5 correct this one was one of my five

El cuadrado completo es:

[tex]\left[\begin{array}{ccc}0.048&0.056&0.016\\0.008&0.04&0.072\\0.064&0.024&0.032\end{array}\right][/tex]

Tenemos el cuadrado:

[tex]\left[\begin{array}{ccc}0.048&a&0.016\\b&c&0.072\\0.064&e&f\end{array}\right][/tex]

Y queremos encontrar los valores de las letras, tal que cada suma de columna, fila y de cada diagonal de 0.12,

Entonces tenemos:

0.048 + b + 0.064 = 0.12

b = 0.12 - 0.048 - 0.064 = 0.008

0.016 + 0.072 + f = 0.12

f = 0.12 - 0.016 - 0.072 = 0.032

Tambien las diagonales deben dar 0.12, entonces:

0.064 + c + 0.016 = 0.12

c = 0.12 - 0.016 - 0.064 = 0.04

Reemplazando esos valores obtenemos:

[tex]\left[\begin{array}{ccc}0.048&a&0.016\\0.008&0.04&0.072\\0.064&e&0.032\end{array}\right][/tex]

Ahora las filas tambien deben dar 0.12:

0.048 + a + 0.016 = 0.12

a = 0.12 - 0.048 - 0.016 = 0.056

0.064 + e + 0.032 = 0.12

e = 0.12 - 0.064 - 0.032 = 0.024

El cuadrado completo es:

[tex]\left[\begin{array}{ccc}0.048&0.056&0.016\\0.008&0.04&0.072\\0.064&0.024&0.032\end{array}\right][/tex]

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Answer:

[tex]y = 4 \cos(4\pi \: t + \frac{\pi}{4} ) [/tex]

[tex]y = a\cos(w\: t + \alpha ) [/tex]

[tex]w = 4\pi[/tex]

[tex]2\pi \: f = 4\pi[/tex]

[tex]f = 2[/tex]

Answer:

[tex]\displaystyle 2[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Acos(Bx - C) + D[/tex]

When working with a trigonometric equation like this, always remember the information below:

[tex]\displaystyle Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A|[/tex]

So, the first procedure is to find the period of this graph, and when calculated, you should arrive at this:

[tex]\displaystyle \boxed{\frac{1}{2}} = \frac{2}{4\pi}\pi[/tex]

You will then plug this into the frequency formula, [tex]\displaystyle T^{-1} = F.[/tex] Look below:

[tex]\displaystyle \frac{1}{2}^{-1} = F \\ \\ \boxed{2 = F}[/tex]

Therefore, the frequency of motion is two hertz.

I am delighted to assist you at any time.

The difference of squares is 4m^2 - 20mn + 25n^2

Its a perfect square trinomial.

A perfect square trinomial is the square of a binomial. It follows a pattern when it is factored, so that the first and last terms are perfect squares of monomials and the middle term is twice their product. If the pattern does not fit for a particular trinomial, it is not a perfect square trinomial.

(-2m + 5n)^2

(-2m + 5n)(-2m + 5n)

4m^2-10mn-10mn+25n^2

4m^2 - 20mn + 25n^2

Thus, the difference of squares is 4m^2 - 20mn + 25n^2

Its a perfect square trinomial.

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The surface area of the cylinder is 244. 92 inches²

surface area of a cylinder = 2πr(r + h)

where

Therefore,

r = 6 / 2 = 3 inches

h = 10 inches

surface area of a cylinder =  2 × 3.14 × 3(3 + 10)

surface area of a cylinder = 18.84(13)

surface area of a cylinder = 244.92

surface area of a cylinder = 244. 92 inches²

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Answer:

50 points

Step-by-step explanation:

Let the total points scored by the team = x

30% of x = 15 points

     [tex]\sf \dfrac{30}{100}*x = 15\\\\[/tex]

              [tex]\sf x = 15* \dfrac{100}{30}\\\\ x = 50[/tex]

The team scored 50 points.

Answer: 8/15, 15/8

Step-by-step explanation:

By the Pythagorean theorem, the length of the unknown side is

[tex]\sqrt{17^{2}-8^{2}}=15[/tex]

So, the tangents of the acute angles are [tex]\boxed{\frac{8}{15}, \frac{15}{8}}[/tex]

The value of 'x' that would make Line segment T V is parallel to Line segment Q S is 10. Option C

It is important to note that for line TV to be parallel to line QS, the sides of the triangle must be divided equally.

Thus, we have

RT/TQ = RV/VS

RT = x + 10

TQ = x - 3

RV = x + 10

VS = x

Substitute the value

[tex]\frac{x + 4}{x-3} = \frac{x + 10}{x}[/tex]
Cross multiply

(x+ 4) × x = (x + 10) × (x-3)

x² + 4x =  x² -3x + 10x -30

Divide through by x²

4x = -3x + 10x - 30

Collect like terms

4x + 3x - 10x = - 30

-3x = -30

x = -30/ -3

x = 10

Thus, the value of 'x' that would make Line segment T V is parallel to Line segment Q S is 10 Option C

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There are 9240 ways to select a committee to develop a discrete math course if the committee is to consist of three faculty from the math department and four from the computer science department.

It is given that there are 9 faculty members in the math department and 11 in the computer science department.

[tex]C^{9} _{3} * C^{11} _{4}[/tex]

[tex]= \frac{9!}{(9-3)!3!} * \frac{11!}{(11-4)!4!}\\= 28 * 330\\= 9240[/tex]

Therefore, there are 9240 ways to select the committee.

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Answer:

16

Step-by-step explanation:

Referring to the diagram, we can use Pythagoras' Theorem to find ZY. (which is the distance from Point Y to WX)

By Pythagoras' Theorem,

[tex]c^{2} =a^{2} +b^{2} \\WY^{2} =WZ^{2} +ZY^{2} \\(16\sqrt{2}) ^{2} =16^{2} +ZY^{2} \\ZY^{2} = (16\sqrt{2}) ^{2} -16^{2} \\ZY^{2} =512-256\\ZY^{2} =256\\ZY=\sqrt{256} \\ZY=16[/tex]

Answer: 36

Step-by-step explanation:

[tex]\overline{AB} \cong \overline{BC}[/tex] (Triangle ABC is isosceles)

[tex]m\angle CAB=m\angle CBA=30^{\circ}[/tex] (base angles of an isosceles triangle are congruent)

[tex]\angle MCB=90^{\circ}[/tex] (In triangle CMB, angles in a triangle add to 180 degrees)

[tex]\angle ACM=30^{\circ}[/tex] (triangle sum theorem)

[tex]MB=24[/tex] (30-60-90 triangle CMB)

[tex]AB=12[/tex] (sides opposite congruent angles in a triangle are congruent)

[tex]AB=36[/tex] (segment addition postulate)

The value of AB = 36

An isosceles triangle is a triangle with base angles equal with any two sides equal.

Analysis:

∠ACB = 120

ABC is isosceles, so ∠CAB = ∠CBA = x

x + x + 120 = 180 ( sum of angles in Δ ABC)

2x = 60

x = 30

∠AMC = 180 - ∠BMC( angles on a straight line)

           = 180 - 60 = 120

∠ACM = 180 - (30 + 120) = 180 - 150 = 30°

∠MCB = 90°

using sine rule,

12/sin 30 = AM/ sin 30

AM = 12

MB/sin 90 = 12/sin30

MB sin 30 = 12 sin 90

MB = 12/sin 30 = 12/0.5 = 24

AB = MB + AM = 24 + 12 = 36

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-10 belongs to the set of negative integers and rational numbers and also belongs to the set of real numbers.

Answer:

to find domain just take the first values of each ordered pairs

to find the range just take the second values of each ordered pairs.

Answer:

40 total students

Explanation:

Total students: 100%

Let the number of total students be x.

Solving stepwise:

7.5% : 100% --> 3 : x

[tex]\rightarrow \sf \dfrac{7.5}{100} = \dfrac{3}{x}[/tex]

[tex]\rightarrow \sf 7.5x = 3(100)[/tex]

[tex]\rightarrow \sf 7.5x = 300[/tex]

[tex]\rightarrow \sf x =40[/tex]

The volume of the rectangular prism is 3359232 cubic centimeters

The length of the cube is given as:

Length, l = 12 cm

The volume of a cube is:

[tex]V = l^3[/tex]

So, we have:

[tex]V = 12^3[/tex]

Evaluate

V = 1728

The volume of 1944 cubes is then calculated as:

Volume = 1728 * 1944

Evaluate

Volume = 3359232

Hence, the volume of the rectangular prism is 3359232 cubic centimeters

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There are exactly 1,944 of the 12 cm, or 0.5 foot cubes inside a rectangular prism.  What is the volume of the rectangular prism in cubic centimeters?