The percentage of motorists falling in each category, in the long term, are as follows:
High-risk category = 70%
Low-risk category = 30%
Data and Calculations:
Risk Profile Categories of Motorists
High Risk Low Risk
Probability of remaining
in the same category 50% 10%
Probability of moving to another
category 50% 90%
Probability a motorist falling in the high-risk category = (50% x 50%) + (50% x 90%)
= 25% + 45%
= 70%
Probability a motorist falling in the low-risk category = (50% x 50%) + (50% x 10%)
= 25% + 5%
= 30%
Thus, the probability of a motorist falling in the high-risk category is 70%, while the probability of a motorist falling in the low-risk category is 30%.
Learn more about probability here: https://brainly.com/question/24756209
When f(x)=4, what is the value of x?
This mapping shows a functional relationship.
Domain
Range
оо
O 2
2
4
3
-3
0
4
-1
→-1
→ 3
Check the picture below.
The value of f(x) at x=4 is 2.
What is Function?A function is an expression, rule, or law in mathematics that describes a relationship between one variable (the independent variable) and another variable (the dependent variable). Functions are common in mathematics and are required for the formulation of physical relationships in the sciences.
We have to find the value of function for x=4.
This means that from the figure we have to find the value of y when x= 4.
Now, looking into the figure we have
f(4)= 2
f(0)= -2
f(-1)= -1
f(3)= 4
So, the required value is 2.
Learn more about Function here:
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Third-degree, with zeros of -4, -2, and 1, and a y-intercept of -11.
[tex]\begin{cases} x = -4\implies &x+4=0\\ x=-2\implies &x+2=0\\ x=1\implies &x-1=0 \end{cases}\qquad \implies (x+4)(x+2)(x-1)=\stackrel{y}{0}[/tex]
now, that's the equation or polynomial in factored form, hmmm we also know that it has a y-intercept of -11, namely, when x = 0 y = -11, well let's plug in a factor to it, that will reflect those values, namely say hmmm factor "a", so
[tex](x+4)(x+2)(x-1)=y\qquad \stackrel{\textit{adding "a" factor for vertical shift}}{a(x+4)(x+2)(x-1)}=y \\\\\\ \stackrel{\textit{we know that when x = 0, y = -11}}{a(0+4)(0+2)(0-1)=-11}\implies -8a=-11\implies a=\cfrac{-11}{-8}\implies a = \cfrac{11}{8} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\mathbb{FOIL}}{\cfrac{11}{8}(x^2+6x+8)}(x-1)=y\implies \cfrac{11}{8}(x^3+6x^2+8x-x^2-6x-8)=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{11}{8}(x^3+5x^2+2x-8)=y~\hfill[/tex]
Determine the slope from the given graph below:
A • The slope is 5
B • The slope is -1/5
C • The slope is 7
D • The slope is -7
(I’ll give brainliest <3)
Slope is the change in Y over the change in x.
Use 2 points on the graph(x,y) to use to solev6.
(2,3) and (0,-7)
Slope = (-7 -3) / (0-2)
Slope = -10/-2
Slope = 5
Answer: A the slope is 5
Ivy is graphing how much money she earns for each hour of babysitting. She finds that the data tends to be linear and draws a line that passes through the points (2, 17) and (5, 42.50). About how much does Ivy earn per hour? A. $42.50 B. $17 C. $25.50 D. $8.50
Answer: 8.5
Step-by-step explanation: (42.50 - 17) ÷ (5 - 2)
= 25.50 ÷ 3
= 8.5
Thank me later
Which of the following word phrases describe the expression y + 3?
A.three less than y
B.the sum of y and 3
C.the product of y and 3
D.three more than y
Helppp for a math exammm
Answer:
d.
Step-by-step explanation:
PLS HELP PLEASSSSS IM SERIOUSLY CRYING RN
[tex]x = 23[/tex]
Step-by-step explanation:
First, we need to write the equations in their standard form, i.e., all the variables and their coefficients are to be placed on the left hand side and the plain numbers on the right hand side. The first equation is already in its standard form:
[tex]2x + 5y = 35\;\;\;\;\;(1)[/tex]
but we need to rewrite the 2nd one. So the standard form of the 2nd equation can be written as
[tex]x + 15y = -10\;\;\;\;\;(2)[/tex]
Now that the equations are in their standard forms, the next step that we need to do is to eliminate one of the variables, namely the y. To do that, we need to multiply either one of the equations so that when we add them together, the y-variable gets eliminated. Note if we multiply Eqn(1) by -3, we'll get -15y on one equation and a +15y on the other equation so that when they are added together, they cancel out. So if we do that, we get
[tex]-6x - 15y = -105\;\;\;\;\;(3)[/tex]
Adding Eqn(3) to Eqn(2), we get
[tex]-5x = -115[/tex]
or
[tex]x = \dfrac{-115}{-5} = 23[/tex]
is (2×3)×4=2×(3×4) an example of associative property of multiplication?
Answer:
Yes.
Step-by-step explanation:
Associative property of multiplication is:
(A×B)×C = A×(B×C).
It says that "The way of grouping of terms doesn't change the product."
So, given example (2×3)×4=2×(3×4) is an example of associative property of multiplication.
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807A car traveled 133 miles in 4 3/4 hours. What was the cars average speed in miles per hour?
4 3/4 = 19/4
133/(19/4) = 133(4/19) = 1197/19 = 63 mph
Help me please (I need write more something in order to I can submit answer)
Answer:
The answer is 4
Step-by-step explanation:
(-2.4)(10) / -3(2)
-24/-6
=4
Answer:
The answer will be 4! Hope this helps
[tex] \frac{8}{20} < > = \frac{7}{13} [/tex]
Compare these factions
Answer:
<
Step-by-step explanation:
Good Question!
8/20=4/10=2/5=0.4
7/13= lcm of 5 and 13 is 75.
26/75 [<] 35/75
:)
Answer: < less than
Step-by-step explanation:
1. Find LCM of 20 and 13.
20: 20,40,60,80,100,120,140,160,180,200,220,240,260,280
13: 13, 26, 39, 52, 65, 78, 91, 104, 107, 110 ...... 234, 247, 260
The LCM is 260.
2. 20*13 = 260 13*20=260
therefore we need to multiply the numerator by those 13 and 20.
8*13 = 104 7*20 = 140
3. compare Fractions:
(104/260) < (140/260)
Derivative help please
Please dont comment if you dont know,
Thank u
[tex]y = x^{\tfrac 1{\ln x}}\\\\\implies \ln y = \ln \left( x^{\tfrac 1{\ln x}} \right)\\\\\implies \ln y = \dfrac{1}{\ln x} \cdot \ln x\\\\\implies \ln y = 1\\\\\implies y =e\\\\\\\text{Now,}\\\\\ \lim \limits_{x \to \infty} x^{\tfrac 1{\ln x}}=\lim \limits_{x \to \infty} y = \lim \limits_{x \to \infty} e = e[/tex]
6. Gloria has 7 yellow pencils. She has 9 red pencils. Which strategy
would NOT help you find 9 -
- 7?
A Make 10
(B
Think Addition
Count to Subtract
My Way
The strategy that won't help her to calculate 9 - 7 is (a) Make 10
The given parameters are:
[tex]Yellow = 7[/tex]
[tex]Red = 9[/tex]
To determine 9 - 7,
She can use addition, as in 9 + (-7)She can subtract directly by countingHowever, she cannot make 10.
This is so, because 9 and 7 are not up to 10
Hence, the strategy that won't help her to calculate 9 - 7 is (a)
Read more about subtraction at:
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The sum of 8 and a number is 9
Answer:
The sum of 8 and 1 is 9.
lol
Step-by-step explanation:
one minus five i divided by two i
Answer:
-1.5
Step-by-step explanation:
Determine the slope from the given graph below:
A ⇹ The slope is -7
B ⇹ The slope is−16
C ⇹ The slope is 6
D ⇹ The slope is -6
Step-by-step explanation:
although there is no graph visible here, I suspect this is the same question as I just answered twice already.
the slope is -6.
D is the right answer.
You get a summer job and make a total of $5,500 throughout the summer months. The government takes out taxes from that money at a rate of 33%. How much money did you really make after taxes were taken out?
Answer:
$1650 is the answer hope it helps
Jeremiah buys 6 tacos and 8 enchiladas for 60 dollars. Kennedy buys 3 tacos and 2 enchiladas for 18 dollars.
Answer:
What's the question lol
At the store, you can get a 12-pack of soda for $5. How much would it cost for a 30-pack
2 with the radical of 32
In an A.P. if Tₚ = q and Tq = p, then find the rth term.
Please solve this problem
Formula:
We know that
nth term of the AP is Tn = a+(n-1)d
Where, a = First term
d = Common difference
n = number of terms
Now,
Given that
pth term of the A.P. = Tp = q
⇛a + (p-1)d = q
⇛(p-1)d = q - a
⇛d = (q-a)/(p-1) →→→→(i)
and
qth term of the A.P. = Tq = p
⇛a + (q-1) d = p
⇛ (q-1)d = p-a
⇛ d = (p-a)/(q-1) →→→→(ii)
From Eqn(i) and Eqn(ii)
⇛(q-a)/(p-1) = (p-a)/(q-1)
On applying cross multiplication then
⇛(q-a)×(q-1) = (p-a)×(p-1)
⇛q²-q-aq+a = p²-p-ap+a
⇛q²-q-aq = p²-p-ap
⇛ap-aq = p²-p+q-q²
⇛a(p-q) = (p²-q²)-(p-q)
⇛a(p-q) = (p+q)(p-q)-(p-q)
⇛ a(p-q) = (p-q){(p+q)-1}
On cancelling (p-q) both sides then
⇛a = (p+q-1) →→→→Eqn(iii)
On Substituting the value of a in Eqn(ii) then
⇛ d = [p-(p+q-1)]/(q-1)
⇛d = (p-p-q+1)/(q-1)
⇛d = (-q+1)/(q-1)
⇛d = -(q-1)/(q-1)
⇛d = -1
We have,
a = p+q-1 and d = -1
Now, rth term of the AP
⇛ Tr = a + (r-1)d
⇛Tr = (p+q-1)+(r-1)(-1)
⇛ Tr = p+q-1+(-r+1)
⇛ Tr = p+q-1-r+1
⇛ Tr = p+q-r
Therefore, Tr = p+q-r
Answer: rth term of the given A.P. is p+q-r
Answer:
rth=q+p+qxp
Step-by-step explanation:
rth= 3 of the T and Tq added together and joined.
x squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
Answer:
[tex]x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}[/tex] and [tex]y=-1,\frac{1}{2}[/tex]
The ordered pair solutions are [tex](-\sqrt{\frac{7}{4}},0.5)[/tex], [tex](\sqrt{\frac{7}{4}},0.5)[/tex], [tex](-1,-1)[/tex], and [tex](1,-1)[/tex].
Step-by-step explanation:
I'm assuming the system is [tex]\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.[/tex]:
[tex]x^2+y^2=2[/tex]
[tex]x^2+(2x^2-3)^2=2[/tex]
[tex]x^2+(4x^4-12x^2+9)=2[/tex]
[tex]x^2+4x^4-12x^2+9=2[/tex]
[tex]4x^4-11x^2+9=2[/tex]
[tex]4x^4-11x^2+7=0[/tex]
[tex]x^4-11x^2+28=0[/tex]
[tex](x^2-7)(x^2-4)=0[/tex]
[tex](4x^2-7)(x^2-1)=0[/tex]
[tex]4x^2-7=0[/tex]
[tex]4x^2=7[/tex]
[tex]x^2=\frac{7}{4}[/tex]
[tex]x=\pm\sqrt{\frac{7}{4}}[/tex]
[tex]x^2-1=0[/tex]
[tex]x^2=1[/tex]
[tex]x=\pm1[/tex]
[tex]y=2x^2-3[/tex]
[tex]y=2(\pm\sqrt{\frac{7}{4}})^2-3[/tex]
[tex]y=2({\frac{7}{4}})-3[/tex]
[tex]y=\frac{7}{2}-3[/tex]
[tex]y=\frac{1}{2}[/tex]
[tex]y=2x^2-3[/tex]
[tex]y=2(\pm1)^2-3[/tex]
[tex]y=2(1)-3[/tex]
[tex]y=2-3[/tex]
[tex]y=-1[/tex]
Therefore, [tex]x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}[/tex] and [tex]y=-1,\frac{1}{2}[/tex]
The ordered pair solutions are [tex](-\sqrt{\frac{7}{4}},0.5)[/tex], [tex](\sqrt{\frac{7}{4}},0.5)[/tex], [tex](-1,-1)[/tex], and [tex](1,-1)[/tex].
PLZ HELP OFFERING BRAINLIEST
Find the difference. 2/5 (d-10) -2/3 (d+6)
[tex]\dfrac 25 (d-10) - \dfrac 23(d+6)\\\\\\=\dfrac{6}{15} (d-10) - \dfrac{10}{15} (d+6)\\\\\\=\dfrac{6(d-10) -10(d+6)}{15}\\\\\\=\dfrac{6d -60-10d-60}{15}\\\\\\=\dfrac{-4d-120}{15}\\\\\\=-\dfrac{4d}{15} - 8[/tex]
1 4 × √ 2 = 2 n Find N
someone pease help me i really need it and giving brainlist to first answer
Answer:
I think this is what is wanted
Step-by-step explanation:
The athlete drink 16 ounces of water every two hours starting at 7:30 AM and continuing for the next 14 hours. A) how many quarts did the athlete consume? B) how many pints of water did the athlete consume?
Answer:
16x7 = 112 (16 ounces, 7 hours) 112 ounces to pints = 7 pints of water
Step-by-step explanation:
5) Write the missing numbers to find the
quotient of 782 = 17. So that 782 = 17 = 46
Answer:
quotient term: 6
dividend term: 102
Step-by-step explanation:
[tex]\dfrac{782}{17}=\dfrac{680+102}{17}=\dfrac{680}{17}+\dfrac{\boxed{102}}{17}=40 +\boxed{6} = 46[/tex]
The volume (V) of a rectangular pyramid can be determined by using the following
formula.
Iwi
V
Where l= the length of the rectangle, w = the width of the rectangle, and h = the heigh
of the pyramid, what is the result of solving this equation for w?
Ow=3V-th
O2 - V +3 - th
V3
th
3V
O w=
Answer:
[tex]{ \rm{V = \frac{lwh}{3} }} \\ \\ { \rm{3V = lwh}} \\ \\ { \boxed{ \rm{ \: w = \frac{3V}{lh } \: }}}[/tex]
Help me with this plzzzzzzzzz
What is the constant of proportionality in this table?
XY
48
5 10
6 12
10 20
Answer:
2
Ok lets start off with your 3 numbers
First do 10 / 5 = 2
Then do 12 / 6 = 2
After that do 20 / 10 = 2
now you see you that its all equivalent to 2 that's your answer!