An astronaut uses a pendulum with a mass of 0.200 kg to measure the acceleration due to gravity on Planet X. He lifts the pendulum's mass a vertical height of 0.500 m and is able to determine that it gains 15.0 J of gravitational potential energy as it is lifted. Using this information, calculate the acceleration due to gravity (g) on Planet X

Answers

Answer 1

Answer:

Explanation:

PE = mgh

g = PE/mh

g = 15.0 / (0.200(0.500))

g = 150 m/s²

This is one strong astronaut if he can work in an environment where gravity is more than 15 times stronger than on earth.


Related Questions

A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of 1=1.31 m/s . At a lower point, the diameter of the stream has decreased by a factor of 0.805 . What is the vertical distance ℎ between these two points?

Answers

Answer:

Explanation:

as the mass cannot change, the volume per unit time is also constant so the area of the stream times the velocity is constant

If the diameter is 1 where velocity is 1.31 m/s

area is proportional to the square of the diameter    A = (π/4)d²

1²(1.31) = 0.805²(v)

v = 1.31/0.805² = 2.02 m/s

v² = u² + 2as

2.02² = 1.31² + 2(9.81)h

h = 0.120819... m

h = 12.0 cm


You hang a light in front of your house using an
elaborate system to keep the 12-kg object in static
equilibrium (Figure 1). What are the magnitudes of the
forces that the ropes must exert on the knot connecting
the three ropes if 02 = 639 and 03 = 45° ?

Answers

The magnitudes of the forces that the ropes must exert on the knot connecting are :

F₁ = 118 N F₂ = 89.21 N F₃ = 57.28 N

Given data :

Mass ( M ) = 12 kg

∅₂ = 63°

∅₃ = 45°

Determine the magnitudes of the forces exerted by the ropes on the connecting knot

a) Force exerted by the first rope = weight of rope

∴  F₁ = mg

     = 12 * 9.81 ≈  118 kg

b) Force exerted by the second rope

applying equilibrium condition of force in the vertical direction

F₂ sin∅₂ + F₃ sin∅₃ - mg = 0  ---- ( 1 )

where: F₃ = ( F₂ cos∅₂ / cos∅₃ ) --- ( 2 )  applying equilibrium condition of force in the horizontal direction

Back to equation ( 1 )

F₂ =  [ ( mg / cos∅₂ ) / tan∅₂ + tan∅₃ ]

   = [ ( 118 / cos 63° ) / ( tan 63° + tan 45° ) ]

   = 89.21 N

C ) Force exerted by the third rope

Applying equation ( 2 )

F₃ = ( F₂ cos∅₂ / cos∅₃ )

    = ( 89.21 * cos 63 / cos 45 )

    = 57.28 N

Hence we can conclude that The magnitudes of the forces that the ropes must exert on the knot connecting are :

F₁ = 118 N, F₂ = 89.21 N, F₃ = 57.28 N

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How do we become children of Abraham and sons of God?

Answers

Answer:

we already are.

Explanation:

God created us, and we are the descendants of Abraham. if you want to choose to live against it, you'll be doing something similar to fighting a current. gods love is unfathomable. he is the only true God, and is our father in heaven.

We are the descendants of Abraham and God crest us and loved us.

Find the magnitude of the potential difference between two points located 1.2 m apart in a uniform 700 N/C electric field, if a line between the points is parallel to the field. Express your answer in volts.

Answers

The magnitude of the potential difference between the two points is 840 V

To solve the problem above, we need to use the formula of Potential difference as related to distance and electric field.

Potential difference: This can be defined as the work required to move a unit charge from a point to another in an electric field.

⇒ Formula:

 V = E×d.................. Equation 1

⇒ Where:

V = Potential differenceE = Electric Fieldd = Distance

From the question,

⇒ Given:

E = 700 N/Cd = 1.2 m

⇒ Substitute these values into equation 1

V = 700(1.2)V = 840 V

Hence, The magnitude of the potential difference between the two points is 840 V

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What are the symmetry operations of molecule AB4, where the molecule b lies at the center of the square and A lies at the center of the square and is not coplaner with B atoms. How to find the multiplication table

Answers

The symmetry operations of molecule AB₄ is tetrahedral  and they are :

E : Identity4C₃ : axis of rotation 3C₂ : axis of rotation3S₄ : Rotation-reflection axis 6бd  

To find the multiplication table we have to apply the multiplication table for Td symmetry ( attached below )

Given that molecule B lies at the corners of the square and molecule A lie at the center and is not coplanar with molecule B the symmetry operations of the molecules AB₄ will belong to a tetrahedral symmetry group which contains :

E : Identity4C₃ : axis of rotation 3C₂ : axis of rotation3S₄ : Rotation-reflection axis 6бd

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The magnetic field B at all points within the colored circle of the figure (Figure 1) has an initial magnitude of 0.780 T. (The circle could represent approximately the space inside a long, thin solenoid.) The magnetic field is directed into the plane of the diagram and is decreasing at the rate of 0.0300 T/s.
a) What is the magnitude of the induced electric field at any point on the circular conducting ring with radius r = 0.100 m ?
b) What is the direction of this field at any point on the circular conducting ring?
c) What is the current in the ring if its resistance is 4.00 Ω ?
d) What is the emf between points a and b on the ring?
e) If the ring is cut at some point and the ends are separated slightly, what will be the emf between the ends?

Answers

The magnitude of the induced electrical field is 0.0015V/m, the field is pointing towards the clockwise direction while the current in the ring will be 0.0002355A if the resistance is 4 ohms. The emf between point a and b is zero and the EMF across the point if they're slightly separated between the ends is 0.000942V

To solve this question, we would have to go about each one individually

Data:

[tex]r=10cm=0.1m\\[/tex]

a.

The magnitude of the induced electrical field at any point within the radius is

[tex]\int\limits^a_b {E} \, du=\frac{dU}{dt}=\pi \frac{dB}{dt}=\pi r^{2}\frac{dB}{dt}\\E*2\pi r=\pi r^{2}\frac{dB}{dt} \\E=\frac{r}{2}\frac{dB}{dt}=\frac{0.1}{2}*0.03=0.0015V/m[/tex]

b.

The field is pointing towards the clockwise direction.

c.

The current in the ring if we are given a resistance of 4ohms

[tex]I=\frac{emf}{R}=\frac{\pi r^{2}\frac{dB}{dt} }{R} =\frac{\pi (0.1)^2*0.03}{4} =0.0002355A[/tex]

d.

The emf between point a and b is zero

e.

The EMF across two points if they're separated by small distance across the ring is

we would use the formula to solve for the EMF

[tex]E=\pi r^{2}\frac{dB}{dt}=\pi (0.1)^2*0.03=0.000942V[/tex]

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Two forces act on a block as shown in the picture. What is the net force of the block?

30 N to the right

30 N to the left

10 N to the left 10

10 N to the right

Answers

Answer:

10 N to the left.

Explanation:

Since the forces are acting in opposite directions, you need to calculate the difference.

20 N - 10 N = 10 N

More force is being exerted to the left. Therefore, the net force is 10 N to the left.

If you have a final velocity of 50 m/s and travelled for 120 seconds. What

is your acceleration?

Answers

Answer:

a=v-u/t

Explanation:

use this formula and initial velocity is 0

Answer:

Acceleration (a) is 0.416666667 m/ s^2

Explanation:

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation

a = Δv/Δt.

did the deadliest hurricanes happen recently or in the distant past

Answers

Answer:

Galveston hurricane of 1900

Explanation:

also called Great Galveston hurricane, hurricane (tropical cyclone) of September 1900, one of the deadliest natural disasters in U.S. history, claiming more than 8,000 lives.

A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when the back pressure is sea-level standard. If the upstream tank temperature is 400 K, estimate (a) the tank pressure and (b) the mass fl ow

Answers

The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

The given parameters:

Throat area of the nozzle, [tex]A^*[/tex] = 10 cm² = 0.001 m²The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²Air pressure at sea level = 101.325 kPa

The ratio of the areas of the converging-diverging nozzle is calculated as follows;

[tex]= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896[/tex]

From supersonic isentropic table, at [tex]\frac{A}{A^*} = 2.896[/tex], we can determine the following;

[tex]M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954[/tex]

The tank pressure is calculated as follows;

[tex]\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa[/tex]

Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

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Ram jumps onto a cement floor from a height of 1m and comes to rest in 0.1sec.
Then he jumps onto a sand floor from a height of 9m and comes to rest in 1sec.
Find the ratio of forces of cement floor and sand floor.​

Answers

Answer:

3/10 F.

Explanation:

Height ( h ) = 1m

Time taken ( t ) = 0.1 second

Height² ( h² ) = 9m

Time taken² ( t² ) = 1 second

Solution,

F = ma

= m ( v - u ) / t

= m √2gh / t

now,

F/F² = √h/h² × t/t²

F¹ = 3/10 F.

answer !!

4. Trilobites are animals that lived during the Paleozoic era. They populated all parts of the
ocean showed consistent evolution over time and left behind fossils that are large
enough to be studied without a microscope. All of these characteristics make trilobites
the ideal
a. Trace fossil
b. Keystone species
c. Index fossil
d. Reference point
dnreserve the remains of dead

Answers

Answer:

c. index fossil

Explanation:

Trilobite fossils are found worldwide, with many thousands of known species. Because they evolved rapidly, and molted like other arthropods, trilobites serve as excellent index fossils. (Arthropods periodically shed their old exoskeletons, or molt.) An index fossil is one that is useful for dating and correlating the strata in which it is found.

An RLC circuit is used in a radio to tune into the radio lagos fm Station broadcasting at 93.5Hz. The resistance is 15ohms and the inductance is 1.6 H. Calculate the capacitance used​

Answers

The characteristics of the RLC circuit allow to find the result for the capacitance at a resonance of 93.5 Hz is:

Capacitance is C = 1.8 10⁻⁶ F

A series RLC circuit reaches the maximum signal for a specific frequency, called the resonance frequency, this value depends on the impedance of the circuit.

            [tex]Z^2 = R^2 + ( wL - \frac{1}{wC} )^2[/tex]  

Where Z is the impedance of the circuit, R the resistance, L the inductance, C the capacitance and w the angular velocity. The negative sign is due to the fact that the current in the capacitor and the inductor are out of phase.

In the case of resonance, the impedance term completes the circuit as a resistive system.

           [tex]wL - \frac{1}{wC} = 0 \\w^2 = \frac{1}{LC}[/tex]  

           

Indicate that the inductance L = 1.6 H and the frequency f = 93.5 Hz.

Angular velocity and frequency are related.

         

         w = 2π f

           

Let's  substitute.

          [tex]C = \frac{1}{L ( 2 \pi f)^2 }[/tex]  

 

Let's calculate.

         [tex]C = \frac{1}{1.6 \ ( 2\pi \ 93.5)^2}[/tex]  

         C = 1.8 10⁻⁶ F

In conclusion with the characteristics of the RLC circuits we can find the result for the capacitance at a 93.5 Hz resonance is:

Capacitance is C = 1.8 10⁻⁶ F

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You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1 radian/sec. The pivot breaks. Though the mass change is negligible, you need to rehang the rod halfway between the old pivot point and the middle of the rod. The new oscillation frequency is:
A. 0.88 rad/sec
B. 1.13 rad/sec
C. 1.07 rad/sec
D. 0.92 rad/sec

Answers

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

     

The given parameters;

Mass of the pendulum, = M Length of the pendulum, = LInitial angular speed, [tex]\omega _i[/tex] = 1 rad/s

The moment of inertia of the rod about the end is given as;

[tex]I_i = \frac{1}{3} ML^2[/tex]

The moment of inertia of the rod between the middle and the end is calculated as;

[tex]I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}[/tex]

Apply the principle of conservation of angular momentum as shown below;

[tex]I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f[/tex]

Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.

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Determine the rTo understand the concept of nodes of a standing wave.
The nodes of a standing wave are points where the displacement of the wave is zero at all times. Nodes are important for matching boundary conditions, for example that the point at which a string is tied to a support has zero displacement at all times (i.e., the point of attachment does not move).
Consider a standing wave, where y represents the transverse displacement of a string that extends along the x direction. Here is a common mathematical form for such a wave:

y(x,t)=Acos(kx)sin(ωt),

where A is the maximum transverse displacement of the string (the amplitude of the wave), which is assumed to be nonzero, k is the wavenumber, ω is the angular frequency of the wave, and t is time.
Part A
Which one of the following statements about wave y(x,t) is correct?

adius of the 236U nucleus.

Answers

Answer:

The nodes of a standing wave are points where the displacement of the wave is zero at all times nodes are important for matching boundary conditions for example that the point at which a string is tied to a support has zero displacement at all times ie the point of attachment does not move consider a standing

PLEASE ANSWER THIS QUICK
GIVING BRAINLIEST TO THE ONE WHO ANSWERS


Rust is a compound that occurs when the element iron and oxygen combine. Do they create a physical or a chemical change?

Answers

Answer:

I think it's a chemical change.

During a car accident on the NJ Turnpike, the airbags deploy. A 79 kg passenger traveling at 32 m/s makes impact with the airbag over a time of 0.25 seconds. What
was the impact force experienced by the passenger?

Answers

Hi there!

Recall that:

Impulse = Δ in momentum = mΔv

Impulse = Force · time

Begin by calculating the change in momentum, or impulse.

I = mΔv = m(vf - vi)

I = (79)(0 - 32) = -2528 Ns

Now, we can use the equation relating force and time to impulse.

I = Ft

Rearrange for time:

I/F = t

-2528/0.25 = -10112 N

**OR, if magnitude ⇒ |-10112| = 10112 N

Which of the following is NOT a function of the lens in the eye?
W
It can perform minor adjustments for distance.
It flattens when light rays from distant objects are to be focused.
It is a light receptor that generates nerve signals that are sent to the brain
It maintains its spherical shape to view nearby objects.

Answers

Answer:

the last one

Explanation:

i need some help getting started on an essay for physics. i decided on the topic of roller costers and dont know how to start it. see the image on my requirements.​

Answers

Explanation:

force , motion , electric current

9. If the force acting on a mass of 4kg accelerates it at a rate of 2m/s2, what will be the acceleration of the body when the force is doubled? ​

Answers

Explanation:

Force= mass× acceleration

Force= 4×2

= 8N

Doubling the force, 8×2= 16N

16= 4 × a

a= 16/4

= 4m/s²

What is the significance of Isaac's name?

Answers

[tex] \large \bf{Answer:-}[/tex]

The name Isaac means “one who laughs” or “one who rejoices.” In the Old Testament of the Bible, Isaac is the firstborn son of Abraham. He is one of the three biblical patriarchs revered by Jews, Christians, and Muslims.

consider a throw ball to the air ,whre lagragian is given by ,L( m /2+Y^ '2 +Z^' 2 ]- msz, find the two concider momuntum when it is invariant under translation at x&x+E and y&yE(both x and y are cyclic cordinate)​

Answers

Explanation:

ANDSHESAIDSHESAIDSHESAID☹️ SHE'S FROMHAWAIIYOUKNOWHOWTOSPEAKCUTEIN JAPANESE KAWAII

How do you find the capacitance in this?

Answers

Answer:

Explanation:

parallel capacitances add directly

Series capacitances add by reciprocal of sum of reciprocals.

Ceq = [ C ] + [1 / (1/C + 1/C)] + [1 / (1/C + 1/C + 1/C)]

Ceq = [ C ] + [C / 2] + [C / 3]

Ceq = [ 6C/6 ] + [3C / 6] + [2C / 6]

Ceq = 11C/6

how is the atomic mass determined?

Answers

Answer:

Atomic mass is defined as the number of protons and neutrons in an atom, where each proton and neutron has a mass of approximately 1 amu (1.0073 and 1.0087, respectively). The electrons within an atom are so miniscule compared to protons and neutrons that their mass is negligible.

Explanation:

A 2.8 kg rectangular air mattress is 2.00 m long, 0.500 m wide, and
0.100 m thick. What mass can it support in water before sinking?
160 m long When a truck ulls

Answers

First off, we have to assume that the 2.8 kg mass of the air matress includes both the material that the matress is constructed from and the air that is contained within.

The mattress can support a total weight that is equal to the weight of water that the air matress displaces.

The volume of the air mattress is:

V(mattress) = (2 m)(0.5 m)(0.1 m) = 0.1 m³

This volume is equal to the maximum amount of water that the matress can displace in the water before it begins sinking.

The density of water is 1000 kg / m²

The weight of the maximum amount of displaced water is:

V(matress) * (density of water) * (g) = (0.1 m³) * (1000 kg / m³) * (9.81 m / s²) = 981 N.

Let m represent the mass that the matress is supporting.

The total weight of the matress and the supported mass is:

(2.8 + m) * 9.81

Setting this weight equal to the weight of the water displaced gives:

(2.8 + m) * 9.81 = 981

2.8 + m = 100

m = 100 - 2.8

m = 97.2 kg

Mass the air mattress support before sinking will be M = 97.2 kg

What will be the mass mattress will support?

Given that

mass of mattress m=2.8 kg

Length = 2.00 m  

width =0.5 m  

The mattress can support a total weight that is equal to the weight of water that the air mattress displaces.

The volume of the air mattress will be equal to

[tex]V= (2\times 0.5\times 0.1)[/tex]

[tex]V= 0.1 m^{3}[/tex]

This volume is equal to the maximum amount of water that the mattress can displace in the water before it begins sinking.

We know the density of water is 1000 kg / m²

We can calculate the weight of the maximum amount of water that mattress will displace

[tex]V\times density of water\times g=0.1\times 1000\times 9.81=981N[/tex]

Let M represent the mass that the mattress is supporting.

The total weight of the mattress and the supported mass is:

[tex](2.8+M)\times9.81[/tex]

Setting this weight equal to the weight of the water displaced gives:

[tex](2.8+M)\times9.81=981[/tex]

[tex]2.8+M=100[/tex]

m = 97.2 kg

Hence Mass the air mattress support before sinking will be M = 97.2 kg

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Ginny is snowboarding down a ski slope. Her total mass (including the snowboard) is 68.5 kg. When she reaches the bottom of the slope, she is moving at 6.55 m/s. The coefficient of friction between the snowboard and the ground is 0.088 . How fast will Ginny be moving 2 seconds after reaching the bottom of the slope?
1) 5.71 m/s
2)5.91 m/s
3)4.82 m/s
4)4.08 m/s

Answers

Answer:

Explanation:

Assuming the run out at the bottom of the slope is horizontal

μ = Ff/N = Ff/mg

Ff = μmg

a = Ff/m = μmg/m = μg

v = u + at

v = u + μgt

v = 6.55 - 0.088(9.81)(2)

v = 4.82 m/s

After reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).

What is Friction?

Friction is the force which opposes the relative motion of solid surfaces, fluid layers, and material elements that are sliding against each other. There are many types of friction like

Dry frictionFluid frictionLubricated friction Skin friction Internal friction

Friction can be expressed as

Ff = μFN

where, Ff is the force of friction (N)

μ is the coefficient of friction.

FN is the normal force

As per the above equation, it is actually the normal force, not the weight, which is responsible for friction.

For given information,

Assuming the bottom of the slope is horizontal

So, μ = Ff/N = Ff/mg

Ff = μmg

a = Ff/m = μmg/m = μg

v = u + at (u- initial speed, v= final speed, a= acceleration and t= time)

v = u + μgt (g= acceleration due to gravity)

u = 6.55 - 0.088(9.81)(2)

u = 4.82 m/s

Thus, after reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).

Learn more about Friction, here:

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#SPJ2

Which variable mentioned in Table 2-1 is kept constant? a. amount of time spent swimming b. type of swimming stroke c. number of calories used d. the person swimming

Answers

Answer:

a. amount of time spent swimming

Explain how the graphic organizer helped you formulate your decision and participate in the discussion.

Answers

Answer:

The graphic organizers help to keep track of the details. They are a visual representation of knowledge that rescue the important aspects of a concept using labels within a scheme. They also present information in a concise manner, highlighting the organization and the relationship of the concepts. Graphic organizers help students organize their thinking process and their writing.

Explanation:

A block of mass m=10 kg at rest slides down a rough incline plane of θ=30° and length l=5 m. The coefficient of kinetic friction between the block and the incline is μ_k=0.1. At the bottom of the plane the block continues to slide on a frictionless surface and hits a spring with spring constant k=100 N/m.

Answers

The speed of the block at point B = 6.36 m/s

Given data :

Mass ( m ) = 10 kg

Angle of inclination ( θ ) = 30°

Length of incline = 5 m

Determine the speed of the block at a point B on the incline

First step : Calculate the work done by frictional force

given that there is no friction on the horizontal plane. Vinclined = Vhorizontal

∴ Work done by frictional force ( Wf ) = F * L cos 180

                                                              = - ( μ_k * N ) L

                                                              = - (0.1 * 84.86   ) * 5  = - 42.4 Joule

where N = mg cos 30°

              = 10 * 9.8 * 0.866 = 84.86

Next step : Calculate the speed of the block at point B

applying work energy theorem

Wf = ΔK.E + ΔP.E

     = ( 1/2 mv² - 0 ) + ( 0 - mgh )

∴ - 42.48  = 1/2 mv² - mgh

1/2 mv² = mgh - 42.48

            = 10 * 9.8 * 5 sin 30° - 42.4

       v²  = 40.52

V ( speed of the block at point B ) = 6.36 m/s

Hence we can conclude that the speed of the block at point B = 6.36 m/s

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Attached below is the complete question related to your question

Where is a divergent boundary most likely to be found?

Answers

Answer:

mid-ocean oceanic ridges

Explanation:

Answer:

mid-ocean oceanic ridges

Explanation:

Divergent boundaries are most likely to be found at mid-oceean oceanic ridges.

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