an article summarizes a report of law enforcement agencies regarding the use of social media to screen applicants for employment. the report was based on a survey of 731 law enforcement agencies. one question on the survey asked if the agency routinely reviewed applicants' social media activity during background checks. for purposes of this exercise, suppose that the 731 agencies were selected at random, and that you want to use the survey data to decide if there is convincing evidence that more than 25% of law enforcement agencies review applicants' social media activity as part of routine background checks.

Answer: We conclude that the mean commute time in the U.S. is less than half an hour. We are given a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time. In this sample, the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

So, Null Hypothesis,  :  30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis,  :  < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

                          T.S. =    ~

where,  = sample mean commute time = 27.6 minutes

           s = sample standard deviation = 19.6 minutes

           n = sample of people from the 2000 U.S. Census = 500

So, the test statistics  =    ~

                                      =  -2.738

The value of t test statistic is -2.738.

Also, P-value of test statistics is given by the following formula;

          P-value = P(  < -1.645)

Since, we know that at large sample size, the t distribution follows like normal distribution, that means;

             P(  < -1.645)  =  P(Z < -1.645) = 1 - P(Z  1.645)

                                        =  1 - 0.95002 = 0.04998

Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

The coordinates of the polygon before and after dilation is below

preimage      image

J (2, 4)           J' (4, 8)

K (4, 4)           K' (4, 4)  

P (3, 2)            P' (6, 4)

Dilation is a method of transformation that magnify or shrink the preimage depending on the scale factor

The transformation rule for dilation is as follows

(x, y) for a scale factor of r → (rx, ry)

following similar procedure for the given problem we have

preimage                           image

J (2, 4)   → (2 * 2, 4 * 2) →   J' (4, 8)

K (4, 4)  → (4 * 2, 4 * 2) →    K' (8, 8)  

P (3, 2)  → (3 * 2, 2 * 2) →    P' (6, 4)

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Answer:

[tex]\frac{1}{6}[/tex]

Step-by-step explanation:

let the denominator of the fraction be x , then the fraction is

[tex]\frac{x-5}{x}[/tex]

increasing the numerator and denominator by 4

[tex]\frac{x-5+4}{x+4}[/tex] = [tex]\frac{x-1}{x+4}[/tex]

this fraction is then equal to 3 times ( triple ) the value of the fraction, so

[tex]\frac{x-1}{x+4}[/tex] = [tex]\frac{3(x-5)}{x}[/tex] ( cross- multiplying )

3(x - 5)(x + 4) = x(x - 1) ← expand factors on left using FOIL

3(x² - x - 20) = x(x - 1) ← distribute parenthesis on both sides

3x² - 3x - 60 = x² - x ( subtract x² - x from both sides )

2x² - 2x - 60 = 0 ( divide through by 2 )

x² - x - 30 = 0 ← in standard form

(x - 6)(x + 5) = 0

equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 5 = 0 ⇒ x = - 5

however, x > 0 , then x = 6

original fraction

= [tex]\frac{x-5}{x}[/tex] = [tex]\frac{6-5}{6}[/tex] = [tex]\frac{1}{6}[/tex]

Answer:

Step-by-step explanation:

1 is correct

2 is correct

3 is wrong

4 is correct

5 is correct

6 is wrong

7 is wrong

For 7:

360 - 90 - 61 - 65

= 144

For 6:

180 - 144

= 36

For 3:

180 - 115 - 36

= 29

The linear equation of the table is, t = -5/3a +19

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

y = mx + c

where

y = dependent variable

m = slope

x = independent variable

c = y - intercept

Here we have the table with the values of t and the value of a.

Now, we need to find the linear equation for this table.

In order to find the linear equation, we need the values of slope and the y intercept values.

To find the value of slope we have to take two point from the given table.

They are (6,9) and (9,4).

Now, apply the value on the slope formula, then we get,

m = (4 - 9) / (9 - 6)

m = -5/3

Now, we have to use the slope m and the point (6,9), to find the value of y intercept,

Then we get the value of c as,

9= -5/3(6)+c

9=-10+c

c=19

Therefore, the linear equation of the table is, t = -5/3a +19

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Answer:

There are 80 lunch items altogether.

Step-by-step explanation:

If the ratio of hotdogs to hamburgers is 10:30 then all we have to do is multiply the whole ratio by 2 to get 20:60.

So it there are 20 hotdogs and 60 hamburgers then there are 80 lunch items altogether because 20+60=80.

;)

Answer: 15

Step-by-step explanation:

screenshot

Answer:

What is the largest y-value that satisfies this system?

1/2(x-3)(x-2)=y

2(x-1/2)=y

Step-by-step explanation:

the first one has a binomial times a binomial which you have to do the generic rectangle if you did you would get

x² - 5x + 6 = y you keep parenthesis and the 1/2 and bring down to get

1/2(x² - 5x + 6) = y then distribute

1/2x² - 5/2 + 3 = y

2(x - 1/2) = y the distribute and get

2x - 1 = y

so the first one has the largest y-value

The weight of each of his checked bags will be; 15.5 kg.

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that; Number of checked bags = 2

Backpack weight = 4 kg

The total weight of Carl's baggage 35kg

Let w be the weight of each checked bag.

Weight of 2 checked bags = 2w

It can be found as; Weight of 2 checked bags + Backpack weight =  Total weight of Carl's baggage

Then;

2w + 4 = 35

Subtract 4 from both sides;

2w + 4 = 35

2w  = 31

Divide 2 from both sides;

w = 15.5

Therefore, the weight of each of his checked bags will be; 15.5 kg.

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Answer:

7 :D

Step-by-step explanation:

Lets go step by step!

When we do something to one side, we must do it to the other!

2x - 5 < 9

2x - 5 + 5 < 9 + 5

2x < 14

2x/2 < 14/2

x < 7

Your answer is 7 :D

Have an amazing day!

Please rate and mark brainliest!

Answer:

x=7

Step-by-step explanation: Okay so,

2x−5=9

First, you take the 5 and add it to the 9:

2x=9+5=

2x=14

Then you divide 2x by 2 and what you do to one side you do to the other, so you also divide 14 by 2:

2x/2=14/2=

x=7

Hope this helps!

The pair of numbers that would be in the columns, considering the proportional relationship, is given as follows:

20 would be in the column for 2, and 60 would be in the column for 6.

A proportional relationship is a special linear function, with intercept having a value of zero, in which the output variable is obtained with the multiplication of the input variable and the constant of proportionality k, as shown as follows:

y = kx

The table is extended to represent more equivalent ratios for 2:6, hence the constant of the relationship is given as follows:

k = 6/2 = 3.

Hence the equation is:

y = 3x.

The values given by each column are given as follows:

When x = 20, the numeric value of the relationship is of:

y = 3 x 20 = 60.

Hence the first option is correct.

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Answer:

y = - [tex]\frac{3}{5}[/tex] x + 8

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - [tex]\frac{3}{5}[/tex] , then

y = - [tex]\frac{3}{5}[/tex] x + c ← is the partial equation

to find c substitute (5, 5 ) into the partial equation

5 = - 3 + c ⇒ c = 5 + 3 = 8

y = - [tex]\frac{3}{5}[/tex] x + 8 ← equation of line

The length of side BC is 15.6 cm and the size of angle EDC in degrees is 56.5°

From the question, we are to determine the length of BC

From the given information,

m ∠ABC = 30°

AC = 9 cm

By using SOH CAH TOA, we can write that

tan (m ∠ABC) = AC / BC

tan (30°) = 9 / BC

BC = 9 / tan (30°)

BC = 15.588

BC ≈ 15.6 cm

To determine the measure of angle EDC,

First we will determine the length of CD

From the diagram,

BD = BC + CD

20 = 15.588 + CD

CD = 20 - 15.588

CD = 4.412

Now, using SOH CAH TOA

cos (m ∠EDC) = CD / DE

cos (m ∠EDC) = 4.412 / 8

cos (m ∠EDC) = 0.5515

m ∠EDC = cos⁻¹(0.5515)

m ∠EDC = 56.5300°

m ∠EDC ≈ 56.5°

Hence, the length of BC is 15.6 cm and the measure of EDC is 56.5°

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The original price for the television is $883.51

A store will discount an item by a percent of the original price.

Given that, a store is having a sale on televisions, all televisions are on sale for 15% off, a customer buys a television for $750.99.

Let the original price be x

x*(100-15)% = 750.99

x = 750.99*100/85

x = 883.51

Hence, the original price for the television is $883.51

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Answer:

[tex]x^{2}[/tex] -x -6

Step-by-step explanation:

You combine the like terms 2x and -3x which is -x

Answer:

The answer would be -1/3.

Step-by-step explanation:

If you plug the coordinates into slope formula (y 2 - y 1 )/ (x 2 - x 1) , you'd have 3-5 over 8-2, and once you solve that, you'll have -1/3 as your slope. Hope this helps ! :D

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Answer:

-54

Step-by-step explanation:

8(-9)=-72

6(-3)=-18

-72+(-18)=-54

-Hope this helped

Answer:

15.13 units

Step-by-step explanation:

For the given amplitude , period and displacement , equation of the modelling the displacement d as a function for the given time t for the initial movement in negative direction is equal to

d(t) = -13sin(8πt + (-8πt₀)) .  

As given in the question,

It is given that object moves in simple harmonic motion ,

Amplitude = 13cm

Period 'T' = 0.25 seconds

f = 1/T

 = 1/ 0.25

 = 100/25

 = 4 / sec

displacement d from rest position is 0.

t  = t₀

Equation of modelling the displacement d as function of time given time t

is given by :

d(t) = A sin(2πft + -2πft₀)

⇒d(t) = -13sin[2π(4t) + -2π(4t₀)]

⇒d(t) = -13sin[8πt -8πt₀]

As initial movement in negative direction.

Therefore, for the given amplitude , period and displacement , equation of the modelling the displacement d as a function for the given time t for the initial movement in negative direction is equal to

d(t) = -13sin(8πt + (-8πt₀)) .  

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Answer:

Step-by-step explanation:

It is clear that after smelting the amount of iron obtained is 12\20 = 60%.

Therefore when 45t is smelted the amount obtained = 60% x 45t

= 27t

The function, g(x), has a constant rate of change and will increase at a faster rate than the function f(x) for all the values of x.  

Given:

g(x) = 5/2 x -3 ..... (1)

f(x) = - 3.5 at x = 0

So, putting the value of x=0 in equation (1) for comparison. We get,

g(x) at x = 0

=> g(x) = 5/2 x (0) - 3

=> g(x) = -3

In this value of x function g(x) is faster than function f(x) having a value equal to -3.5.

Similarly, put x = 1 in equation (1) for comparison. We get,

=> g(x) = 5/2 x (1) - 3

=> g(x) = (5-6)/2

=> g(x) = -1/2

In this value of x function g(x) is faster than function f(x) having a value equal to -1.

Similarly, put x = 2 in equation (1) for comparison. We get,

=> g(x) = 5/2 x (2) - 3

=> g(x) = (5-3)

=> g(x) = 2

In this value of x function g(x) is faster than function f(x) having a value equal to 1.5.

Similarly, put x = 3 in equation (1) for comparison. We get,

=> g(x) = 5/2 x (3) - 3

=> g(x) = (15/2 - 3)

=> g(x) = 7.5 - 3

=> g(x) = 4.5

In this value of x function g(x) is faster than function f(x) having a value equal to 4.

Therefore, for all values of x function g(x) is faster than function f(x).

function f(x).

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The value of x is when the value of the function f(x) = 7 is x= -24 and x = 16

Function:

A correspondence from one value x of the first set A to another value y of the second set B. It relates inputs to output is known as the function of the relation.

Given,

Here we have the function f(x) = 0.5|x - 4| - 3.

Now, we have to find the value of x when the value of f(x) = 7.

In order to find the value of x as have to equate the give function with the value of f(x), that is 7,

So, when we apply these on the function then we get,

=> 7 = 0.5|x - 4|-3

Now, we have to move all the numbers instead of x, then we get,

=> 7 + 3 = 0.5|x - 4|

=> 10 = 0.5 |x - 4|

=> 10/0.5 = |x - 4|

=> 20 = |x - 4|

So in this place we can get the following forms,

=> x - 4 = 20 and

=> x - 4 = - 20

Because we get two values being an absolute value function.

Now, we have to add 4 on both sides

Then we get

=> x - 4 + 4 = 20 + 4 and

=> x - 4 + 4 = - 20 + 4

So, the value of x is

=> x = 24 and x = - 16

Therefore, for the given function the values of x are 24 and - 16.

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The population of Shanghai is 5 times larger than population of Monterrey.

What is population?

Typically, the term "population" refers to the total number of people living in a particular area, be it a city or town, region, country, continent, or the entire world.

Main body:

The population of Monterrey, Mexico is  people = [tex]4*10^6[/tex]

The population of Shanghai, China is  people  = [tex]2*10^7[/tex]

To find how many times the population of Shanghai is lager than Monterrey.

In order to find how many times the population of Shanghai is lager than Monterrey we will find the ratio of populations of Shanghai and  Monterrey.

Thus we divide the population of Shanghai by the population of Monterrey to find how many time the population of Shanghai is larger.

Thus, we have:

[tex]\frac{2*10^7}{4*10^6}[/tex]

Simplifying by using properties of exponents.

⇒  [tex]\frac{2*10^7}{4*10^6}[/tex] , USING [tex]a^{x} -a^{y} =a^{(x-y)}[/tex]

⇒ [tex]\frac{2*10}{4}[/tex]

⇒ 20/4

⇒ 5

Therefore, we can say that the population of Shanghai is 5 times larger than population of Monterrey.

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Using the formula of speed, the speed of first trains is 45 mph and the speed of second train is 60 mph.

In the given question, we have to find the speed of each.

Two trains going in opposite directions leave at the same time.

One train tavels 15 mph faster than the other.

In 6 hours the trains are 630 miles apart.

Let the speed of the first vehicle be s mph, then according to the question, the speed of the second vehicle would be (s+15) mph.

Let the first vehicle covers the distance D(1) and the second one D(2) in the prescribed time.

So, find the distance covered by the first vehicle in 6 hours by using the formula

Distance = Speed × Time

So the distance D(1) is;

D(1) = s*6

D(1) = 6s

So the distance D(2) is;

D(2) = (s+15)*6

D(2) = 6s+90

Since, after 6 hours both the vehicles are at the distance 630 miles. So, the sum of the two distances D(1) and D(2) will be equal to 630.

D(1)+D(2) = 630

Puttimg the value of D(1) and D(2)

6s+6s+90=630

Simplifying

12s+90=630

Subtract 90 on both side we get

12s=540

Divide by 12 on both side we get

s=45 mph

So the value of speed of the faster vehicle

s+15 = 45+15

s+15 = 60 mph

Hence, the speed of first train is 45 mph and the speed of second train is 60 mph.

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According to the given dot plot, the striking deviation is at the value of 4, making the correct answer option C: 4.

What is the striking deviation?

A striking deviation is a noticeable or significant difference or deviation from the norm or expected value in a data set. It refers to an observation or value that stands out from the others due to its higher frequency, magnitude, or significance. In statistics, striking deviations can be identified through various measures, such as standard deviation, variance, or graphical representation, such as dot plots or box plots.

To determine the striking deviation in the given dot plot, we need to look for the value with a noticeably larger number of dots compared to the others. We can do this by comparing the frequency of dots for each value. From the given graph, we can see that the frequency of dots at 4 is significantly higher than the other values. This means that 4 has a higher occurrence or significance in the data set compared to the other values.

Therefore, the striking deviation is at the value of 4, making the answer option C: 4.

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Answer: 25*tan(35°)

Step-by-step explanation: For this problem, since the triangle is a right triangle, you must use the formula, tangent(Ф) = opposite/adjacent. In this case, Ф = 35 degrees. The side opposite to the angle Ф is x, and the side adjacent to Ф is 25. Therefore,

tangent(35°) = x/25

After multiplying the 25 over,

x = 25*tan(35°)

A graph of the line that passes through the points (3, -7) and (-3, 5) is shown in the image attached below. Also, the equation of this line is y = -2x - 1.

Mathematically, the slope of a straight line can be calculated by using this formula;

Slope, m = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope, m = (y₂ - y₁)/(x₂ - x₁)

Based on the information provided, the points on the line include the following:

Substituting the given points into the formula, we have;

Slope, m = (5 - (-7))/(-3 - 3)

Slope, m = (5 + 7)/(-6)

Slope, m = 12/-6

Slope, m = -2

At point (3, -7), a linear equation for the line can be calculated by using the point-slope form:

y - y₁ = m(x - x₁)

Where:

Substituting the given points into the formula, we have;

y - y₁ = m(x - x₁)

y + 7 = -2(x - 3)

y + 7 = -2x + 6

y = -2x + 6 - 7

y = -2x - 1

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The equation of line passes through the points (2, 0) and (0, -1) will be;

⇒ y = 1/2 x - 1

What is Equation of line?

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

Two points on the line are (2, 0) and (0, -1).

Now,

Since, The equation of line passes through the points (2, 0) and (0, -1).

So, We need to find the slope of the line.

Hence, Slope of the line is,

m = (y₂ - y₁) / (x₂ - x₁)

m = (- 1 - 0) / (0 - 2)

m = - 1 / - 2

m = 1 / 2

Thus, The equation of line with slope 1 / 2 is,

⇒ y - 0 = 1 / 2 (x - 2)

⇒ y = 1/2 x - 1

⇒ y = 1/2 x - 1

Therefore, The equation of line passes through the points (2 , 0) and

(0, - 1) will be;

⇒ y = 1/2 x - 1

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Answer:

  x ∈ {2, 3, 4, 5, 6}

Step-by-step explanation:

You want the positive integer solutions of ||x²-2x|-|3x-20|| = |x²+x-20|.

Each of the absolute value functions has turning points where the argument is zero. Those turning points are ...

  x²-2x   ⇒   x(x-2) = 0   ⇒   turning points at x=0 and x=2

  3x-20   ⇒   x -20/3 = 0   ⇒   turning point at x=20/3

  x²+x-20   ⇒   (x+5)(x-4) = 0   ⇒   turning points at x=-5 and x=4

In numerical order, the turning points are ...

  x ∈ {-5, 0, 2, 4, 20/3}

These divide the domain of the equation into 6 intervals. Since we are concerned only with positive integer solutions, we are only interested in the intervals ...

  [0, 2), [2, 4), [4, 20/3), [20/3, ∞)

In this domain, x²-2x < 0, 3x-20 < 0, and x²+x-20 < 0. This means the equation becomes ...

  |-(x² -2x) +(3x -20)| = -(x² +x -20)

The difference in the absolute value bars is negative, so we get the equation ...

  -(-x² +2x +3x -20) = -x² -x +20

  2x² -4x = 0 . . . . . . . add x²+x+20

  x = 0 . . . . . x = 2 is not in the domain

There are no positive integer solutions in this domain.

In this domain, x²-2x > 0, 3x-20 < 0, and x²+x-20 < 0. This means the equation becomes ...

  |(x² -2x) +(3x -20)| = -(x² +x -20)

The difference in the absolute value bars is negative, so we get the equation ...

  -(x² -2x +3x -20) = -x² -x +20

  0 = 0 . . . . . . . . . . . . add x² +x -20

  2 ≤ x < 4 . . . . . . . . all x-values in the domain are solutions

The positive integer solutions are x = 2, x = 3.

In this domain, x²-2x > 0, 3x-20 < 0, and x²+x-20 > 0. This means the equation becomes ...

  |(x² -2x) +(3x -20)| = x² +x -20

The difference in the absolute value bars is positive, so we get the equation ...

  (x² -2x +3x -20) = x² +x -20

  0 = 0 . . . . . . . subtract x² +x -20

  4 ≤ x < 6 2/3 . . . . . . . . . all values of x in the domain are solutions

The positive integer solutions are x = 4, x = 5, x = 6.

In this domain, x²-2x > 0, 3x-20 > 0, and x²+x-20 > 0. This means the equation becomes ...

  |(x² -2x) -(3x -20)| = x² +x -20

The difference in the absolute value bars is positive, so we get the equation ...

  x² -2x -3x +20 = x² +x -20

  -6x +40 = 0 . . . . . . . subtract x² +x -20

  x = 6 2/3 . . . . . . . add 6x, divide by 6

There are no positive integer solutions in this domain.

The positive integer values of x are {2, 3, 4, 5, 6}.

Using the inequality concept, the expression which models the maximum

number of days in which she can rent the car is 56. 37x + 45 ≤ 440.

Maximum amount allowed to spend

= $440

Rental car company fixed charge per day to rent a car = $56.37

Hawa drives a car to 500 miles.

Rate per mile drive = $0.09

let x days be maximum number of days hawa afford rent with budget.

the inequality equation exists here is

(days × charge of rent per day) + (rate per mile x number of miles) ≤ 440

=> 56.37x + 0.09 × 500 ≤ 440

=> 56.37x + 45 ≤ 440

Therefore, the required inequality is 56.37x + 45 ≤ 440

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