An arrow is fired at a target on a high wall. How does the energy change between the moment the arrow is fired and
Che moment it hits the target?
O The potential energy and kinetic energy remain the same.
O The potential energy decreases as kinetic energy increases.
O The kinetic energy decreases as potential energy increases.
O The kinetic energy remains at zero, but potential energy increases.

Answers

Answer 1

Answer:

C brainliest

Explanation:

Answer 2

An arrow is fired at a target on a high wall. The kinetic energy will decrease as potential energy increase.

Kinetic energy is one of the energies that is related to the motion of the particle and potential energy is one of the energies that is related to the position and height of the particle.

As the arrow in the question will go high to the wall, speed of arrow will keep on decreasing and kinetic energy keeps on decreasing and as height increases potential energy also increases.

We know that As per law of conservation of energy, as kinetic energy decreases potential energy will increase in the same amount.

Therefore, An arrow is fired at a target on a high wall. The kinetic energy will decrease as potential energy increase.

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Related Questions

Choose the options below that are true.
A. The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.
B. The rate laws of all chemical reactions can be determined directly from their net chemical equations.
C. The rate laws of bimolecular elementary reactions are second order overall.
D. The rate law for a given reaction can be determined from its reaction mechanism, without the accompanying rates of each elementary step in the mechanism.

Answers

Answer:

The options (A) -The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.  and (C) -The rate laws of bimolecular elementary reactions are second order overall ,is true.

Explanation:

(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.

(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.

(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.

(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.

Therefore , the first and third statement is true.

4. What is the molarity of a solution that contains 65g of sodium nitrate in 750? ml of solution?

Answers

Answer:

1.02 M

Explanation:

Solution contains 65g of sodium nitrate

Volume of solution = 750 ml

Now, Molar mass of sodium nitrate from online values = 84.9947 g/mol

Thus, it means 84.9947 g/mol of sodium nitrate dissolved in 1000 mL of water will be equal to 1 M molarity.

Thus;

Molarity of solution = (65/750) × (1000) × (1/84.9947) = 1.02 M

PLEASE ASNWR ASAP
If I have a 50 liter container that holds 45 moles of gas at a pressure of 2.66 x 104 mmHg, what is the
temperature inside the container? ** convert pressure to atm**

Answers

34.95 atm

lol i hope i’m not too late



Which salt preparation uses a burette and a pipette

Answers

potassium chloride from potassium hydroxide and hydrochloric acid

Some students have said that a buffer is like a proton (H ) sponge. Evaluate this statement and explain both how a buffer is like a sponge and how it is not like a sponge. For your explanation, include chemical equations, data, and create and explain molecular-level drawings. (Question is taken from Orgill and Sutherland, 2008.) (Saloni)

Answers

Answer:

i)  Buffer absorbs  H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH

ii) absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.

Explanation:

i) Buffer like a proton ( H ) sponge

Buffer absorbs  H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH

The pH of a Buffer follows the Henderson-Hasselbach model

pH = pKa + Log ([A-]/[HA])

when base is added

HA + OH^-   -------> A- + H2O

when acid is added

A^- + H^+   ---------> HA

ii) Buffer not like a proton ( H ) sponge

absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.

Reaction of Nitrile with Grignard Grignard reagents react with nitriles to give an intermediate imine anion that is hydrolyzed by the addition of water to yield a ketone. The mechanism is similar to the reduction of a nitrile to an amine except that only one nucleophilic addition occurs instead of two, and the nucleophile is a carbanion rather than a hydride ion.

Required:
Draw curved arrows to show the movement of electrons. in this step of the mechanism. Arrow-pushing Instructions

Answers

Answer:

its a.

Explanation:

thesis: physical science improves nursing through technology, energy, and Matter.

write a 4-page essay explaining how science improves Nursing career and how it revolves around

Technology

Energy

Matter

Answers

Answer:

When science educators teach nurses, their primary aim should be to help them to develop understanding of their world of nursing. From a study of registered nurses' conceptions of the physical science underlying their clinical practice, we assert that nurses' understanding of the physical sciences is inadequate in terms of the competencies required of them as nurses.

Explanation: Hopes this helps You A lot :-D

1. If I have 5 moles of a gas at a pressure of 7.6 atm and a volume of 12 liters, what is the temperature?

Answers

Answer:

221.22K or -51°C

Explanation:

We will be using the Ideal Gas Law to calculate the temperature of the gas. It is a mathematical relationship that describes the behavior of ideal gas ample for any combo of varying pressure, volume, temperature, and # of moles (n). It is derived by combing Boyle's Law, Charles' Law, Gay-Lussac's & Avogadro's Law.

Note: As always, remember that temperature must be in Kelvin not Celsius when using this equation.

Ideal Gas Law: [tex]PV = nRT[/tex], where P = pressure, V = volume (in Liters), n = # of moles, R = the ideal gas constant, and T = temperature (in Kelvin).

Based on the problem, we are given the pressure, volume, and # of moles. We are asked to find the temperature. What about R you ask? Well, R is a constant that is the value of 1 mole of gas at STP. R has various values depending on the pressure units. In this case, our pressure is in atm so the R value = 0.0821.

Onto the math - all that needs to be done now is to plug and chug. Plug in the given values to find the temperature:

Set up: [tex](7.6 atm)(12L) = (5 mol)(0.0821 L*atm/(mol*K))(T)[/tex]

==> [tex]T = \frac{(7.6 atm)(12L)}{(5 mol)(0.0821 L*atm/(mol*K))}[/tex]

==> T = 221.17K

The answer is 221.17K. To convert into Celsius, subtract by 273.15 to get -50.99 or -51°C.

What is the best method of separating the mixture of sand and fine salt?

Answers

By using filtration, the sand and fine salt can be effectively separated based on their difference in particle size, providing a clean separation of the two components.

Filtration is a separation technique that takes advantage of the difference in particle size between sand and salt. It involves passing the mixture through a porous material, such as filter paper or a filter funnel, which allows the liquid (saltwater) and small salt particles to pass through while retaining the larger sand particles.

Here's how the filtration process can be carried out:

1. Set up a filter apparatus with a funnel and filter paper or a filter flask.

2. Place the mixture of sand and salt in a beaker or a flask.

3. Slowly pour the mixture into the filter paper or funnel, allowing the liquid (saltwater) to pass through while retaining the sand on the filter paper.

4. Once the liquid has passed through completely, the sand will be left behind on the filter paper or in the filter flask.

5. Carefully remove the sand from the filter paper or filter flask, and the saltwater solution can be collected separately.

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Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to get to the equivalence point. Assume that your base is about 0.05 M and that your unknown acid has a molar mass around 400 g/mol. (Report your answer using 2 significant figures).

Answers

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

= 0.05 m

Molar mass of acid,

= 400 g/mol

As we know,

⇒  [tex]Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}[/tex]

On substituting the values, we get

⇒           [tex]0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}[/tex]

⇒  [tex]Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}[/tex]

⇒                                             [tex]=1.5\times 10^{-3}[/tex]  

hence,

⇒  [tex]Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}[/tex]

On substituting the values, we get

⇒  [tex]1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}[/tex]

⇒  [tex]Mass \ of \ acid=1.5\times 10^{-3}\times 400[/tex]

⇒                         [tex]=0.60 \ g[/tex]

what is the major organic product obtained from the reaction of 1-butanol with aqueous hbr at reflux

Answers

Answer:

1-bromobutane

Explanation:

The reaction of butane with aqueous HBr at reflux is an SN2 reaction. The reaction passes through a single transition state in which the bond between carbon and the leaving group as well as the bond between carbon and the incoming nucleophile are being broken and formed simultaneously. It is a synchronous reaction.

The nuclephile attacks from the backside while the leaving group departs. This leads to inversion of configuration of the product.

Consider the following intermediate chemical equations.
P₄(s)+3O₂(g) ---> P₄O₆(s) ΔH₁ = -1640kJ
P₄O₁₀(s) ---> P₄(s)+5O₂(g) ΔH₂ = 2,940.1 kJ

What is the enthalpy of the overall chemical reaction P₄O₆(s)+2O₂(g) ---> P₄O₁₀(s)
A.) -4,580 kJ
B.) -1,300 kJ
C.) 1,300 kJ
D.) 4,580 kJ

Answers

Answer:

-1,300 kJ

I don't want to explain it brainly AAAAA

The standard enthalpy of the reaction is the enthalpy change which occurs in a system when a matter is transformed by a chemical reaction under standard conditions. Here the enthalpy of the overall chemical reaction is  -1,300 kJ. The correct option is B.

What is enthalpy change?

In any general chemical reaction, the reactants undergo chemical changes to form products. The change in enthalpy is represented as ΔrH and is termed as the reaction enthalpy. It can be calculated by subtracting the sum of enthalpies of all the reactants from that of the products.

ΔrH  = ∑ aiH products - ∑ bi H reactants

Here we should reverse the first reaction and also multiply its ΔH by (- 1):

P₄O₆(s) → P₄(s) + 3O₂(g), ΔH₁' = 1640.1 kJ.

The second reaction is also reversed and also multiply its ΔH by (- 1):

P₄(s) + 5O₂(g) → P₄O₁₀(s), ΔH₂' = - 2940.1 kJ.

If we add the two reactions after modification, we get:

P₄O₆(s) → P₄O₁₀(s).

Therefore,  ΔH = ΔH₁' + ΔH₂' = 1640.1 kJ + (- 2940.1 kJ) = - 1300 kJ.

Thus the correct option is B.

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1.Are forests a renewable or non-renewable resource? Give reasons for both possibilities

Answers

Answer:

Forests are renewable

Explanation:

Forests can grow again, but it takes forever to grow a new one so it shouldn't be taken for granted! You can remake a whole new forest, but it will take around 50 years and a lot of animals will die without them before that time comes!

But then again, it could be a non-renewable resources; because it takes so long to grow a new one!

Hope this helps!

what do you mean by carrier​

Answers

Ans: A carrier is an individual who carries and is capable of passing on a genetic mutation associated with a disease and may or may not display disease symptoms. Carriers are associated with diseases inherited as recessive traits. An individual having one normal allele and one mutated allele does not have the disease.

Answer:

1 : one that carries : bearer, messenger. 2a : an individual or organization engaged in transporting passengers or goods for hire. b : a transportation line carrying mail between post offices.

For the reaction 2 Cr(s) + 3 Pb²⁺(aq) ⟶ 3 Pb(s) + 2 Cr³⁺(aq), what is the value of n in the Nernst equation?

Answers

Answer:

The value of n is 6

Explanation:

The half-reactions of the problem are:

Cr(s) → Cr³⁺ + 3e⁻

Pb²⁺ + 2e⁻→ Pb(s)

To balance the electrons we must multiply the half-reactions as follows:

2 * (Cr(s) → Cr³⁺ + 3e⁻)

3 * (Pb²⁺ + 2e⁻→ Pb(s))

2Cr(s) → 2Cr³⁺ + 6e⁻

3Pb²⁺ + 6e⁻→ 3Pb(s)

In Nernst equation, the value of n are the electrons used to balance the reaction, as in this problem, the electrons are 6:

The value of n is 6

In a sample of neon, carbon, and oxygen gas, the total pressure is 9 atm.
The partial pressure of neon is 2 atm and the partial pressure of oxygen is 2
atm. What is the partial pressure of carbon?
9 atm
3 atm
5 atm
4 atm

Answers

Answer:

5 atm

Explanation:

add boh partial pressures and subtract from total pressure

A truck accelerates at a rate of 14 m/s2 . The truck weighs 17000 kg. What is the amount of force
necessary for the truck to accelerate at this rate?

Answers

Answer:

238000 N

Explanation:

Use F=ma

Mass= 17000 kg

Accel.= 14 m/s²

For a theoretical yield of 23 g and actual
yield of 13 g, calculate the percent yield for a
chemical reaction.
1. 63.6364
2. 76.4706
3. 71.4286
4. 57.1429
5. 56.5217
6. 40
7. 70
8. 60
9. 52.6316
10. 41.6667
Answer in units of %.

Answers

Answer:

5. 56.5217

Explanation:

Calculate percent yield by (actual yield / theoretical yield) times 100

(13/23) x 100 = 56.52173913

Calculate the volume of 0.10 M sucrose solution that must be diluted to prepare 10.00 ml of a 0.015 M sucrose solution

Answers

The solution is 6.0 8ML

The energy of flowing electrons
A. A. LightLightB. B. ChemicalChemicalC. C. ElectricalElectricalD. D. TransformationTransformationE. E. MechanicalMechanical

Answers

Answer:

C. ElectricalElectrical

Explanation:

( it might be wrong pls dont report me just let me kno y its wrong )

When a balloon is blown up then let go air molecules rush out of the balloon and join the air molecules in earths atmosphere what happens to the enthalpy in the balloon?

Answers

Answer: It decreases

Answer: It decreases.

Explanation: a p e x :)

Why are some resources, like fossils, found in some places and not in others?

Answers

Answer:

Because thats where the animal passed away

Explanation:

Several elements must be transmuted to sea the real implications of this event
a.surpassed
b.estimated
c.changed
d.summed

thanks guys :)​

Answers

C, Changed because it’s transmuted which can cause change of events

Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.

Answers

Answer:

The total amount of energy required is 25,515.2 J.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When a system absorbs (or gives up) a certain amount of heat, it can happen that:

experience a change in its temperature, which involves sensible heat, undergoes a phase change at constant temperature, or latent heat.

To calculate the latent heat the formula is used:

Q = m. L

Where

Q: amount of heat m: mass L: latent heat

To calculate sensible heat the following formula is used:

Q = m. c. ΔT

where:

Q: amount of sensible heat  m: body mass c: specific heat of the substance ΔT: temperature range

In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is  4.184 [tex]\frac{J}{g*C}[/tex]:

q1 = m*c*(Tfinal-Tinitial)

q1 = 10.0 g *(4.184 [tex]\frac{J}{g*C}[/tex])* (100 - 35.0 C) = 2719.6 J

Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 [tex]\frac{J}{g}[/tex]:

q2 = m*(heat of vaporization)

q2 = 10.0 g*(2259.36 [tex]\frac{J}{g}[/tex]) = 22593.6 J

Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is  2.02 [tex]\frac{J}{g*C}[/tex] :

q3 = m*c*(Tfinal-Tinitial)

q3 = 10.0 g*(2.02 [tex]\frac{J}{g*C}[/tex])*(110-100 C) = 202 J

The total amount of energy can be calculated as:

Q= q1 + q2 + q3

Q= 2719.6 J + 22593.6 J + 202 J

Q=25,515.2 J

The total amount of energy required is 25,515.2 J.

How many moles are there in 4.9x10^23 molecules of CO2?
F. 0.81 moles of CO2
G 8.14X10^45
H. 2.95X10^47
J. 2052.44

Answers

Answer:

0.81 moles

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\ [/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

[tex]n = \frac{4.9 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{4.9}{6.02} \\ = 0.813953...[/tex]

We have the final answer as

0.81 moles

Hope this helps you

if a gas sample has a pressure of 30.7 kPa at 273 K, what does the temperature have to decrease to lower the pressure to 28.4 kPa?​
253K
268K
262K

Answers

253 K

P1/T1 = P2/T2

P1 = 30.7 kPa
T1 = 273 K
P2 = 28.4 kPa

Solve for T2 —> T2 = P2T1/P1
T2 = (28.4 kPa)(273 K) / (30.7 kPa) = 253 K

You have a bag of chips at a constant pressure of 1 Atm with a volume of .5 L and a temperature of 10C. The bag is left under the sun for a couple of hours at a temperature of 35 C, what will its new volume be?

Answers

Answer:

0.54 L

Explanation:

Given that,

Initial volume, V₁ = 0.5 L

Initial temperature, T₁ = 10°C = 283 K

Final temperature, T₂ = 35 C = 308 K

We need to find the final volume. The relation between the volume and temperature is given by :

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{0.5\times 308 }{283}\\\\V_2=0.54\ L[/tex]

So, the new volume is 0.54 L.

oxidation and reduction occur simultaneusly​

Answers

Yes, oxidation and reduction occur simultaneously in many chemical reactions. In fact, oxidation and reduction are two sides of the same chemical reaction, which occur at the same time in opposite directions.

Lab: Enthalpy.
What were the learning goals of this lab experiment? Check all that apply.
to use mass and temperature data to do computations involving heat
to demonstrate that different reactions have different enthalpies
to compute a reaction’s enthalpy directly using mass measurements and a calorimeter
to compute the enthalpy of a reaction that cannot be measured directly using a simple calorimeter
Hess
’s law allows you to find the net enthalpy of the magnesium combustion by adding the enthalpies of intermediate reactions.
To find the enthalpy of a reaction in the lab, you measured the
mass
of the reactants
and the
temperature
change during the reaction.
In both Reactions 1 and 2, the temperature change was
positive
, meaning that the
reactions
gave off
heat.

Answers

Answer:

to use mass and temperature data to do computations involving heat

to compute a reaction’s enthalpy directly using mass measurements and a calorimeter

To find the enthalpy of a reaction in the lab, you measured the mass

of the reactants

and the

temperature

change during the reaction.

Explanation:

Was that good?

Enthalpy is a thermodynamic system's internal energy total as well as the volume times pressure ratio.

What is Enthalpy?

Enthalpy is a property or state function that resembles energy; it has the same dimensions as energy and is therefore measured in joules or ergs. The value of enthalpy is solely dependent on the temperature, pressure, and composition of the system, not on its history.

Enthalpy, denoted by the symbol H, is the sum of the internal energy, denoted by E, and the product of the pressure and volume, denoted by PV.

The change in internal energy is equal to the heat transmitted to, less the work done by, the system, according to the law of energy conservation.

Therefore, Enthalpy is a thermodynamic system's internal energy total as well as the volume times pressure ratio.

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You are given three liquids, pentane (C5H12), water (H2O), and tetrachloromethane (CCl4), and are told to make solutions.

a. Predict whether you will be able to make a solution with pentane and tetrachloromethane
b. Predict whether you will be able to make a solution with pentane and water, and give your reasoning.

Answers

Answer:

A. predict whether you will be able to make a solution with pentane and tetrachloromethane

Explanation:

Sana nakatulong

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A Fidelity mutual fund sells its Volkswagen stock to a French investor. An American cell phone company establishes an office in the Czech Republic. 20. Which transaction would increase US net capital outflow through foreign direct investment? 21. Which transactions would decrease US net capital outflow through foreign portfolio investment? The Neoclassical growth model was developed by a. Paul Krugman b. Jerome Powell c. Thomas Sargent d. Robert Solow e. 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Project A generates the following cash flows: year ""zero"" = 311 dollars (outflow); year 1 = 266 dollars (inflow); year 2 = 319 dollars (inflow); year 3 = 381 dollars (inflow); year 4 = 111 dollars (inflow). Project B generates the following cash flows: year ""zero"" = 230 dollars (outflow); year 1 = 120 dollars (inflow); year 2 = 100 dollars (inflow); year 3 = 200 dollars (inflow); year 4 = 120 dollars (inflow). The MARR is 12 %. Compute the Benefit/Cost ratio of the BEST project. Based on your reading of process management/strategy, analyze and map a process in your work place and recommend improvements to be implemented. assume working in any company Formulating a Strategy' is part of the __________- managerial function. 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In this test, a person fasts and then drinks a solution of glucose. Changes in blood glucose levels, as well as insulin and glucagon levels, are then followed over time. After Jessie has fasted for 12 hours, her baseline glucose, glucagon, and insulin levels are measured just before the test begins. She is then asked to drink a solution of 75 g of glucose in water, and her blood is drawn and tested every 60 minutes for five hours. How does the body supply glucose to the brain during periods of fasting? O Adipose cells break down triacylglycerides, convert fatty acids to glucose, and export glucose into the blood. The liver performs gluconeogenesis and glycogenolysis and exports glucose into the blood. The brain generates large amounts of its own glucose through glycogenolysis. Skeletal muscles perform glycogenolysis and export glucose into the blood. Skeletal muscles perform gluconeogenesis and export glucose into the blood. The test results reveal that Jessie was hypoglycemic when the test began. Other than her initial hypoglycemia, her response to the glucose challenge is completely normal. However, during the last hour of the test, her blood glucose level slowly falls below the normal range. To test this hypothesis, you could administer an oral glucose tolerance test to examine how her body responds to ingested glucose. In this test, a person fasts and then drinks a solution of glucose. Changes in blood glucose levels, as well as insulin and glucagon levels, are then followed over time. A healthy individual who has fasted for 12 hours would likely have blood glucose levels at the low end of the normal range, because the liver maintains glucose homeostasis through glycogenolysis and gluconeogenesis. After Jessie has fasted for 12 hours, her baseline glucose, glucagon, and insulin levels are measured just before the test begins. 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Find the flux of F across the part of the paraboloid x + y + z = 12 that lies above the plane z = 3 and is oriented upward.