An argon gas occupies 56.2 L at 760 torr. If the volume of gas dereases to 1/4 of the original volume ,calculate its final pressure

Answer:

The path difference must be equal to an integral (1 * lambda, 2 * lambda, -------n * lambda) number of wavelengths for constructive interference to occur.

Answer:

Power = ML²T⁻³

Pressure = ML⁻¹T⁻²

Explanation:

Applying,

Power(P) = Work(W)/Time(t)

P = W/t..................... Equation 1

But

W = Fd............. Equation 2

Where F = force, d = distance

Also,

F = ma.............. Equation 3

Where m = mass, a = acceleration.

Also,

a = v/t................  Equation 4

Where v = velocity

Also,

v = d/t............... Equation 5

Where d = distance

Substitute equation 5 into equation 4

a = d/t²................. Equation 6

Substitute equation 6 into equation 3

F = m(d/t²)........... Equation 7

Susbtitute equation 7 into equation 2

W = m(d/t²)×d

W = md²/t²........... Equation 8

Substitute equation 8 into equation 1

P = (md²/t²)/t

P = md²/t³............ Equation 9

In dimension,

mass(m) = M, distance(d) = L, time(t) = T

Substitute into equation 9

P = ML²/T³

P = ML²T⁻³

And

Pressure(R) = Force(F)/Area(A)

R = F/A................ Equation 10

F = md/t²,

A = d²

Susbtitute into equation 10

R = (md/t²)/d²

R = m/t²d

Therefore,

R = ML⁻¹T⁻²

Answer:

[tex]D_T=18.567m[/tex]

Explanation:

From the question we are told that:

Acceleration [tex]a=8.0 m/s^2[/tex]

Displacement [tex]d=1.05 m[/tex]

Initial time [tex]t_1=6.0s[/tex]

Final Time [tex]t_2=2.5s[/tex]

Generally the equation for Velocity of 1.05 travel is mathematically given by

Using Newton's Law of Motion

 [tex]V^2=2as[/tex]

 [tex]V=\sqrt{2*6*1.05}[/tex]

 [tex]V=4.1m/s[/tex]

Generally the equation for Distance traveled before stop is mathematically given by

 [tex]d_2=v*t_1[/tex]

 [tex]d_2=3.098*4[/tex]

 [tex]d_2=12.392[/tex]

Generally the equation for Distance to stop is mathematically given by

Since For this Final section

Final velocity [tex]v_3=0 m/s[/tex]

Initial velocity [tex]u_3=4.1 m/s[/tex]

Therefore

Using Newton's Law of Motion

 [tex]-a_3=(4.1)/(2.5)[/tex]

 [tex]-a_3=1.64m/s^2[/tex]

Giving

 [tex]v_3^2=u^2-2ad_3[/tex]

Therefore

 [tex]d_3=\frac{u_3^2}{2ad_3}[/tex]

 [tex]d_3=\frac{4.1^2}{2*1.64}[/tex]

 [tex]d_3=5.125m[/tex]

Generally the Total Distance Traveled is mathematically given by

 [tex]D_T=d_1+d_2+d_3[/tex]

 [tex]D_T=5.125m+12.392+1.05 m[/tex]

 [tex]D_T=18.567m[/tex]

Answer:

Explanation:

Angular momentum is L = mvr:

L = (5.2)(1.8)(.86) so

L = 8.05 kg*m/s

Answer:

Coefficient of kinetic friction = 0.38 (Approx.)

Explanation:

Given:

Applied force = 45 N

Mass of wooden crate = 12 kg

Find:

Coefficient of kinetic friction

Computation:

Coefficient of kinetic friction = Applied force / (Mass)(Acceleration due to gravity)

Coefficient of kinetic friction = 45 / (12)(9.8)

Coefficient of kinetic friction = 45 / 117.6

Coefficient of kinetic friction = 0.3826

Coefficient of kinetic friction = 0.38 (Approx.)

Answer:

the types of force shown in the picture is

balanced force.

Answer:

When electrons flow through wires from a terminal to a terminal circuit is created.

Answer:

[tex] \large{ \tt{☄ EXPLANATION}} : [/tex]

[tex] \large{ \tt{♡ \: LET'S \: GET \: STARTED}} : [/tex]

[tex] \large{ \boxed{ \tt{❃ \: WORK ( \: W \: ) = FORCE\: ( \: F) \times DISPLACEMENT \: ( \: D \: )}}}[/tex]

- Plug the values and then simplify !

[tex] \large{ \bf{↦ \: 150 = F \times 10}}[/tex]

[tex] \large{ \bf{↦F\times 10 = 150}}[/tex]

[tex] \large{ \bf{↦ \: F = \frac{150}{10}}} [/tex]

[tex] \large {\bf{↦F = \boxed{ \bf{15} \: N}}}[/tex]

[tex] \boxed{ \boxed{ \large{ \tt{✤ \: OUR \: FINAL \: ANSWER : \boxed{ \bf{15 \: n}}}}}}[/tex]

ツ Hope I helped ! ۵

☪ Have a wonderful day / evening ! ☼

# StayInAndExplore ! ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

[tex]\huge{ \mathrm{  \underline{ Answer }\:  \:  ✓ }}[/tex]

Total force acting on right side = 800 N

Total force acting on left side :

Now, equivalent force acting on the plane is :

And the direction of equivalent force will be the direction of greater force, that is right direction.

Hence, Correct option is :

_____________________________

[tex]\mathrm{ \:TeeNForeveR\:}[/tex]

Answer:

The system will tend to person A

Explanation:

A force is defined as either a pull or a push, in this scenario person A weighs lass that person B, so the resultant effect of the 10N interactive force will tend towards person A.

This is solely because person A is less than person B in weigh

Explanation:

given Time Period = 5 Sec

Amplitude = 1m, Wave length = 15 m

using time period = 1/ frequency , Frequency = 1/5 cycles per sec = 0.2 sec = 12 per min

wave speed= Frequency * Wave length

speed = 0.2*15 = 3m/s

Force is a push or pull that changes or attempts to change the shape or size of an object's position.

F = m × a

Here

F= Force

m= mass of object

a= Acceleration

According to law of conservation of energy,

= ½mv² = mgh

= mv² = 2mgh

= v² = 2mgh/m

= v = √2gh

So, now just put the values of g & h, abd you are done;

= v = √2×9.8×1.6

= v = √31.36

= v = 5.6 m/s

Answer:

Waves. Refraction is an effect that occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light. ... The wavelength decreases as the light enters the medium and the light wave changes direction.

Explanation:

As a wavelength increases in size, its frequency and energy (E) decrease. From these equations you may realize that as the frequency increases, the wavelength gets shorter. ... Mechanical and electromagnetic waves with long wavelengths contain less energy than waves with short wavelengths.

Answer:

67.5

Explanation:

The plane accelerates at 2.7m/s,^2

Time is 25 seconds

The velocity can be calculated as follows

= 25×2.7

= 67.5

Hence the speed f the plane is 67.5

Translate to English please

Answer:

Change is for better and is necessary too. Everyone knows it but only the ones who apply it are the ones whom we call as intelligent. When a person changes in an order to make his life better, he chooses the right thing because staying put at a place in life doesn't take anyone anywhere.

Taking the example of a few infamous personalities, whom we consider as intelligent, we see a common thing that each one of them had a certain vision in life and in order to achieve it, they were ready to accept any kind of change and still are. So, this makes it clear that change is what leads us to our goal and in order to achieve it, we need to change with time.

Answer:

T = 0.01 s

Explanation:

Given that,

The frequency of the beats of a hummingbird, f = 100 Hz

We need to find the period of the hummingbirds flaps. Let the time is t. We know that the relation between frequency and time period is given by :

T = 1/f

Put all the values,

T = 1/100 = 0.01 s

So, the time period of the humming bird is 0.01 s.

The answer for this question is negative externality

Answer:

 v_f = 20 m / s

Explanation:

For this exercise let's use the relationship between momentum and moment

        I = Δp

        F t = m v_f - m v₀

as the body starts from rest v₀ = 0

        F t = m v_f

        v_f = [tex]\frac{F t}{m}[/tex]

let's calculate

        v_f = 4 2 / 0.4

         v_f = 20 m / s

Answer:

  t = 0.714 s and  x = 5.0 m

Explanation:

This is a projectile throwing exercise, in this case when the skater leaves the bridge he goes with horizontal speed

         vₓ = 7.0 m / s

Let's find the time it takes to get to the river

         y = y₀ + v_{oy} t - ½ g t²

the initial vertical speed is zero and when it reaches the river its height is zero

        0 = y₀ + 0 - ½ g t²

        t = [tex]\sqrt{\frac{2y_o}{g} }[/tex]

        t = ra 2 2.5 / 9.8

        t = 0.714 s

the distance traveled is

       x = vₓ t

       x = 7.0 0.714

       x = 5.0 m

Answer:

Initial y-component of speed

Vy = 28 * sin 30 = 14 m/sec vertically

1/2 m Vy^2 = 2 m g h    conservation of energy of y-component

h = Vy^2 / (2 * g) = 14^2 / (2 * 9.8) = 10 m

a = ( v(2) - v(1) ) ÷ ( t(2) - t(1) )

2 = ( v(2) - 10 ) ÷ ( 6 - 0 )

2 × 6 = v(2) - 10

v(2) = 12 + 10

v(2) = 22 m/s

Answer:

Aerobic Fitness. Aerobic fitness improves overall health and well-being. ...

Muscular Fitness. Strength training improves your muscle and bone health and helps with weight loss. ...

Flexibility. Flexibility allows you to move your body freely. ...

Stability and Balance

Explanation:

UP

Answer: [tex]3920\ J[/tex]

Explanation:

Given

mass of ball m=10 kg

It is placed at a height of 150 m

It is dropped from the height and allowed to free fall for 40 m

Velocity acquired by the ball during this fall is given by [tex]v^2-u^2=2as[/tex]

Insert u=0, a=g

[tex]\Rightarrow v^2-0=2\times 9.8\times 40\\\Rightarrow v=\sqrt{784}\\\Rightarrow v=28\ m/s[/tex]

Kinetic energy at this instant

[tex]K.E.=\dfrac{1}{2}\times 10\times 28^2\\\\\Rightarrow K.E.=3920\ J[/tex]

Answer:

C.

A factor of something is an ingredient, or it makes up that thing. For example, in math, we always try to find the factors of a number. We are basically trying to find the "ingredients" of a number.

Answer:

a)  [tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

b)  [tex]x=\frac{6.0}{4.3*10^{-32}}[/tex]

c) [tex]x'=\frac{6.0}{2.22*10^{-3}}[/tex]

Explanation:

From the question we are told that:

Kinetic energy of Proton[tex]K.E_p= 6.0 MeV[/tex]

Radius [tex]r=0.750[/tex]

Energy [tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

a)

[tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

b)

Generally the equation for acceleration of proton is mathematically given by

[tex]a_p=\frac{v^2}{r}[/tex]

Where

Speed of Proton particle is

[tex]V_p=2.12 *10^3 m/s[/tex]

[tex]a_p=\frac{(2.12 *10^3)^2}{0.750}\\a_p=1.27*10^{10}m/s^2[/tex]

Therefore

[tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

[tex]\frac{dE}{dt}=\frac{9*10^9*(1.6*10^{-19}^2*(1.27*10^{10})^2)}{(3*10^8)^3}[/tex]

[tex]\frac{dE}{dt}=6.881810^{-51}J/s[/tex]

Energy radiated per sec

[tex]mev=\frac{6.881810^{-51}}{1.6*10^{-19}}\\mev=4.3*10^{-32}ev[/tex]

Therefore the Fraction of its energy  it radiates per second is given as

[tex]x=\frac{ K.E_p}{mev}\\[/tex]

[tex]x=\frac{6.0}{4.3*10^{-32}}[/tex]

c)

Generally the equation for acceleration of proton is mathematically given by

[tex]a_p=\frac{v^2}{r}[/tex]

Where

Speed of Proton particle is

[tex]V_p=2.5 *10^7 m/s[/tex]

[tex]a_p=\frac{(2.5 *10^7)^2}{0.750}\\a_p=0.33*10^{14}m/s^2[/tex]

Therefore

[tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

[tex]\frac{dE}{dt}=\frac{9*10^9*(1.6*10^{-19}^2*(0.33*10^{14})^2)}{(3*10^8)^3}[/tex]

[tex]\frac{dE}{dt}=59.26^{-25}J/s[/tex]

Energy radiated per sec

[tex]mev=\frac{59.26^{-25}}{1.6*10^{-19}}\\mev=2.22*10^{-3}ev[/tex]

Therefore the Fraction of its energy  it radiates per second is given as

[tex]x'=\frac{ K.E_p}{mev}\\[/tex]

[tex]x'=\frac{6.0}{2.22*10^{-3}}[/tex]

Answer:

0.011

Explanation: