an arctic weather balloon is filled with of helium gas inside a prep shed. the temperature inside the shed is . the balloon is then taken outside, where the temperature is . calculate the new volume of the balloon.

To check in case the splitting of a long-chain hydrocarbon has created alkenes, the gas created can be bubbled through natural gas or aromatic rich petroleum gas.

The first beginning of cracking of hydrocarbons is alkanes. The items of splitting incorporate alkanes and alkenes, individuals of a different homologous series.

An alkene could be a hydrocarbon that contains a carbon-carbon twofold bond. The longer alkanes are warmed, and their vapors are passed over a hot catalyst. This causes covalent bonds to break and change.

In thermal breaking, tall temperatures (ordinarily within the run of 450°C to 750°C) and weights (up to approximately 70 climates) are utilized to break the huge hydrocarbons into littler ones.

Thermal splitting gives blends of items containing tall extents of hydrocarbons with two-fold bonds - alkenes.

Catalytic cracking uses a temperature of approximately 550°C and a catalyst known as a zeolite which contains aluminum oxide and silicon oxide. Steam cracking uses a higher temperature of over 800°C and no catalyst.

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The correct answer is All of the answer choices are correct.

A biochemical process that involves the addition of phosphate to an organic compound. In biological systems, this reaction is vital for the cellular storage and transfer of free energy using energy carrier molecules.

The first step in the metabolism of carbohydrates is frequently their phosphorylation. Because the phosphate group stops the molecules from migrating back across the transporter, phosphorylation enables cells to store carbohydrates. Glucose phosphorylation is a crucial step in the metabolism of sugar.

The chemical formula for the first step of glycolysis, which involves the conversion of D-glucose to D-glucose-6-phosphate, is provided by

          D-glucose + ATP → D-glucose-6-phosphate + ADP

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The complete question is :

The process of phosphorylation

(a) adds a phosphate group to a molecule.

(b) may energize the target molecule.

(c) removes a phosphate group from a molecule.

(d) may change the shape of the target molecule.

(e) All of the answer choices are correct

Stable isotopes tend to have a very different amount of protons to neutrons because the ratio of protons and neutrons is nearly 1 or less than 1.5, whereas the number of protons and neutrons in unstable isotopes is greater than 1.5

Isotopes of elements are atoms of the same elements having the same number of protons but different numbers of protons.

Isotopes of elements may either be stable isotopes or unstable isotopes.

Stable isotopes are isotopes whose nuclei do not spontaneously decay and emit nuclear particles as well as radiation. Stable isotopes usually have a proton and neutron ratio that is less than 1 : 1.5.

Unstable isotopes are isotopes whose nuclei spontaneously decay and emit nuclear particles as well as radiation. Unstable isotopes usually have a proton and neutron ratio that is greater than 1 : 1.5.  The spontaneous decay of unstable isotopes is due to the presence of the excess neutrons in the nucleus of the atom.

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In this question, we have to determine the way in which an electron move from a ground state to an excited state, and the way this occurs is by absorbing energy, when the right amount of energy hits the electron, this electron will jump to a higher energy level. Therefore the answer will be the 1st option

The very light weight of carbon tube makes it far more stronger than steel.

Aside the fact that carbon fibre has more strength than its respective steel, its durability is also an important property which makes it of better use. This implies that it can be used over a long period of time.

However, the great advantage it has over steel or any other metal is that it is very cheap to produce or manufacture.

Carbon is a chemical element found in the group 4 of the periodic table. It has atomic number of 6, valence electrons of 4, proton number of 6, neutron number of 6 and has 6 electrons.

In conclusion, carbon fibre is more stronger than steel in all characteristics including its safety.

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Consider the combustion of methane:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

The reactant is decreasing at the fastest rate is CH₄.

Combustion of methane CH₄ is a reaction between methane and oxygen present in the air to produce carbon dioxide and water.

the reaction involved is

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

The limiting reagent in this reaction is methane because the other reactant is oxygen which is present in air is always there ion excess. thus, the amount of carbon dioxide and water produced in the combustion of methane will depend upon the amount of methane burnt .

Thus,  Consider the combustion of methane:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

The reactant is decreasing at the fastest rate is CH₄.

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600grams of ping-pong balls is equal to 0.204doz of ping-pong balls.

When table tennis became a competitive sport, celluloid replaced the original primary ping pong ball material of cork as the industry standard.

Throughout the 1900s, these 38mm-diameter balls served as the industry standard for table tennis. We didn't notice a significant difference in the production of ping pong balls until the year 2000.

As we know,

1 doz of ping pong balls = 2.94×10^3 g

thus, 2.94×10^3g of ping pong balls = 1 doz

1 g of ping pong balls = 1/2.94×10^3 doz

600 g of ping-pong balls = 600/2.94×10^3 doz

= 0.204 doz

Hence, 600grams of ping-pong balls is equal to 0.204doz of ping-pong balls.

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Answer: D- None of the above

-

Eliminate a face shield, a face shield covers your entire face, while glasses only cover your eyes and around your eyes. Glasses are glass while shield covers are usually plastic.

Eliminate Safety glasses because, again, eye glasses only cover your eyes and the surrounding areas of your eyes with glass, the gaps beside and under them allow chemical incidents to go into your eyes. Safety glasses wrap around your head and usually completely sheild you eyes.

Eliminate splash proof chemical goggles, this would fall into the category of safety glasses.

The factors for dissolving sugar.

Warmth or Fahrenheit minus 0.2 ranges Celsius dissolves the sugar in water. because of sugar's soluble nature, it's miles present at any temperature or stress in liquid water. about 10 mins for this.

Sugar dissolves quicker in hot water than it does in bloodless water due to the fact warm water has extra strength than bloodless water. whilst water is heated, the molecules benefit energy and, therefore, pass quicker. As they flow faster, they come into contact with the sugar more often, inflicting them to dissolve more quickly.

The dissolution of sugar in water is a bodily change because it no longer brings about the formation of a new substance. it's miles a reversible alternative as sugar and water may be extracted and returned from the solution through the method of crystallization observed by evaporation.

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The concentration of C is found to be 0.0739M on establishment of equilibrium using the equilibrium constant.

The ratio of the concentration of the products to the concentration of the reactants, each increased to their respective stoichiometric coefficients, is the equilibrium constant of concentration (denoted by Kc) of a chemical process at equilibrium.

Any equilibrium reaction has an equilibrium constant that is determined by the ratio of the concentrations of the chemicals on the right to the concentrations of the substances on the left. Keep in mind that the products are always listed before the reactants when writing a ratio.

Molarity of A = No. of moles / volume

Molarity of A = 0.370 / 1L = 0.370M

[tex]Kc = \frac{[C] [D]}{[A]^2}[/tex]

Kc = [tex]\frac{(x)(x)}{(0.290 - 2x)^2}[/tex] = 0.270

[tex]0.08x^2[/tex] – 0.3132x + 0.022707 = 0

x = 0.0739M

Result:

The concentration of C is 0.0739M once equilibrium is established.

The complete and correct question is in the image.

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Using the specific heat capacities of water and ice, and taking into account the latent heat of melting for ice, we can calculate that the final temperature of the mixture will be 17.6 °C.

The negative value of the amount of heat lost by liquid water is equal to the amount of heat absorbed by the ice. The equation for calculating the amount of heat needed to change the temperature of a material looks like this:

Q = (t₂ - t₁) * c * m

t₂ - final temperature

t₁ - starting temperature (32.1 °C for water, -20.0 °C for ice)

c - specific heat capacity (4.186 J/g°C for water, 2.108 J/g°C for ice)

m - the mass of the material (325 for water, 44.0 for ice)

In addition, we have to take into account that some of the heat released by water is expended on melting the ice:

heat used for melting = m * l = 44.0 g * 334 J/g = 14696 J

l = latent heat of melting ice

This means that the heat released by water is expended on heating ice to 0°C, then melting that ice, then heating the ice water to the final temperature.

Heat expended by water:

Q = (32.1 °C - X) * 325 g * 4.186 J/g°C = 43670.445 J - 1360.45 J/°C * X

Heat absorbed by ice and ice water:

Q = 20.0 °C * 44.0 g * 2.108 J/g°C + 14696 J + X * 44.0 g * 4.186 J/g°C = 16551.04 J + 184.184 J/°C * X

These amounts of heat are equal:

43670.445 J - 1360.45 J/°C * X = 16551.04 J + 184.184 J/°C * X

27119.405 J = 1544.634 J/°C * X

X = 27119.405 J / 1544.634 J/°C = 17.6 °C

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Phosphorus atom in the ground state has five electrons in its outer level and ten electrons in its kernel.

The smallest component of ordinary stuff that makes up a chemical element is an atom. Atoms that are neutral or ionized make up every solid, liquid, gas, and form of plasma. Atoms are incredibly tiny, measuring typically 100 picometers across. Ion charge or zero (neutral) electric charge.

Space makes up the majority of an atom. The rest is made up of a cloud of negatively charged electrons surrounding a positively charged nucleus made up of protons and neutrons. Compared to electrons, which are the lightest charged particles in nature, the nucleus is small and dense.

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Answer:

Cell phones combine phone technology with computer technology, and the pairing has made an unprecedented amount of information available to humans all over the world.

The shortest wavelength emitted from the initial configuration of 6 d1 is 327 nm. Here the first energy level is 6 and the last level is infinity.

Wavelength is of a radiation is the distance travelled by a wave. As the wavelength of a wave gets smaller its energy increases.

The relation between wavelength and energy levels is given below:

[tex]\frac{1}{\lambda } = R [\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}][/tex]

here, R is a constant equal to 1.1 × 10⁷ and n₁ and n₂ are two energy level.

The smallest wavelength of light emitted from hydrogen with n₁ =6 and n₂ = ∞ can be calculated as follows:

[tex]\frac{1}{\lambda } = 1.1\times 10^{7} [\frac{1}{6^{2}}-\frac{1}{\infty ^{2}}] =30.5\times 10^{5} cm[/tex]

[tex]\lambda = \frac{1}{30.5\times 10^{5}}= 327 \textup{ nm}[/tex]

Hence, wavelength of the light emitted is 327 nm.

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When pressure is constant. Temperature and volume is directly proportional.

According to Gay-Law, Lussac's the pressure of a given amount of gas, while the volume is held constant, changes directly with the absolute temperature of the gas.

Since one mole of The any ideal gas is meant to be 22.4L at STP, the gay-Lussacs law holds true. The ratios of the number of moles of gases to one another should continue to be factors and multiples of one another since this changes directly with heat (and inverse with pressure), but operates the same for all gases.

Under circumstances of constant mass and volume, Gay-law, Lussac's also known as Amonton's law, asserts that the absolute pressure and temperature of an ideal gas are directly related.

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The temperature of the system in equilibrium is 301.96 K.

The equilibrium temperature of the system depends on the heat released from both gold and water. The total heat received by the system will equal to total heat released by objects. It should follow

Q released = Q received

The heat can be defined by

Q = m . c . ΔT

where Q is heat, m is mass, c is the specific heat constant and ΔT is the change in temperature.

The given parameters are

m1 = 62.5 g = 0.0625 kg

T1 = 650 K

m2 = 165 g = 0.165 kg

T2 = 298 K

c1 = 126 J/kgK

c2 = 4200 J/kgK

Lets assume that the value of equilibrium temperature is T. Hence,

Q released = Q received

m1 . c1 . ΔT1 = m2 . c2 . ΔT

0.0625 . 126 . (T1 - T) = 0.165 . 4200 . (T - T2)

0.0625 . 126 . (650 - T) = 0.165 . 4200 . (T - 298)

5118.75 - 7.875T = 693T - 206514

700.875T = 211632.75

T = 301.96 K

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Answer:

C: 4

H: 1

Mg: 2

O : 6

Explanation:

You can quickly find out the number of valence electrons by looking at where the element is on the periodic table and referring to the table that is attached.

The marginal density function of X and Y is 1 and thus they are probability density functions and the probability of the conditions in (c) and (d) is 0.2 and 0.8 respectively.

A probability is a number that expresses the likelihood or chance that a given event will occur. Probabilities can be stated as proportions ranging from 0 to 1, as well as percentages ranging from 0% to 100%.

A probability density function, also known as the density of a continuous random variable in probability theory, is a function whose value at each given sample in the sample space may be read as offering a relative likelihood that the random variable's value will be near to that sample. Probability density functions are statistical measures that are used to predict the outcome of a discrete value. The probability density function is nonnegative all the way through, and the area under the entire curve is equal to one.

a) The marginal density of X is

[tex]f_X (x) = \int\limits^x_0 {f_{X,Y} (x,y)} \, dx = \int\limits^x_0 {2} \, dx = 2x[/tex]

If it is a pdf, then

[tex]\int\limits^1_0 {f_X(x)} \, dx = 1[/tex]

[tex]\int\limits^1_0 {2x} \, dx = x^2 |_0^1 = 1[/tex]

Since integral is 1, marginal density function of X is pdf.

b) The marginal density of Y is

[tex]f_Y (y) = \int\limits^y0 {f_{X,Y} (x,y)} \, dy = \int\limits^y_0 {2} \, dy = 2y[/tex]

If it is a pdf, then

[tex]\int\limits^1_0 {f_Y(y)} \, dy = 1[/tex]

[tex]\int\limits^1_0 {2y} \, dy = y^2 |_0^1 = 1[/tex]

Since integral is 1, marginal density function of Y is pdf.

c)

       [tex]P (x < 0.2,y > 0.5) = \int\limits^1_{0.5}\int\limits^{0.2}_0 {f_{X,Y} (x,y) \, dx \, dy = \int\limits^1_{0.5}\int\limits^{0.2}_0 2dxdy[/tex]

       [tex]= \int\limits^1_{0.5} [2x]_0^{0.2}dy = 0.4[y]_{0.5}^1 = 0.4 (1 - 0.5) = 0.2[/tex]

d)

      [tex]P (x < 0.8,y > 0.5) = \int\limits^1_{0.5}\int\limits^{0.8}_0 {f_{X,Y} (x,y) \, dx \, dy = \int\limits^1_{0.5}\int\limits^{0.8}_0 2dxdy[/tex]

      [tex]= \int\limits^1_{0.5} [2x]_0^{0.8}dy = 1.6[y]_{0.5}^1 = 1.6 (1 - 0.5) = 0.8[/tex]

The complete question is:

A chemical system that results from a chemical reaction has two important components in a blend among others. The joint distribution that describes the proportion X and Y of these two components is given by f(x,y) = 2 for 0 < x < y < 1 and f(x,y) = 0 otherwise. (a) Find the marginal density function of X and verify if it is a pdf. (b) Find the marginal density function of Y and verify if it is a pdf. (c) Find the probability that the component proportions produce results X < 0.2, Y > 0.5. (d) Find the probability that the component proportions produce results X < 0.8, Y > 0.5.

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Answer: Element Sodium (Na), Group 1, Atomic Number 11, s-block, Mass 22.990. Sources, facts, uses, scarcity (SRI), podcasts, alchemical symbols, videos and images.

Explanation:

Let's count the moles of gaseous oxygen first. Using n= m/M

=n(O)= 32.00/2×15.99)mol

= n(O)= (32.00/31.98) mol

=n(O)= 1.00mol

Let's now change every relevant value in the equation PV=nRT.

=P× 20.0L= 1.00mol× 0.0821[tex]L atm mol^{-1} K^{-1}[/tex]× 303.15K

= P× 20.0= 1.00× 0.0821atm× 303.15

[tex]P=(0.0821*300/20) atm[/tex]

P= 1.24atm

Therefore, 1.24 atm is the pressure that the oxygen gas is exerting.

The ideal gas equation is what.

The macroscopic characteristics of ideal gases are related by the ideal gas law (PV = nRT). A gas is said to be ideal if its particles don't interact with one another and don't occupy any space.

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Answer:

0.23 mass percent

Explanation:

The molar mass of Fe(NO3)3 is 241.9 g/mol and the molar mass of NaCl is 58.5 g/mol. This means that for every 1 mol of Fe(NO3)3, there are 4.14 mol of NaCl. In a 0.456 gram sample, this would be 0.01098 moles or 109 mg of Fe(NO3)3 and 0.456 * (4.14 mol / 1 mol) = 1.892 grams or 1892 mg of NaCl

The volume of concentrated aqueous ammonia must be diluted to 1.00 l to make a solution that has a molarity of 1.85 m. concentrated nh3 (aq) is 15 m. report the volume of concentrated aqueous ammonia in milliliters is 123 mL

The number of moles of solute must always remain constant while diluting solutions, which is the most crucial thing to remember.

In other words, the amount of solute in the concentrated sample must be identical to the amount of solute in the diluted solution.

The concentration is the number of moles per unit volume. So

c=n/V

n=CV

n= 1.85x1

n=1.85

Now your task is to determine what volume of the concentrated solution would contain this many moles of ammonia.

Plugging the values, we get

V=1.85/15

V=0.123 L

Now for dilution calculations, we have

C1V1=C2V2

V1=C2/C1.V2

V1=1.85/15x1.00= 123 mL

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Answer: combustion and exothermic

Explanation: I took the test

Combustion and exothermic describes this type of reaction.

Products are the most stable and exothermic for every combustion because they are (of an exothermic process) more stable than reactants (whose energy is substantially lower).

A material burns when it reacts with oxygen during combustion, producing energy in the form of heat and light. The temperature rises when the energy generated by an exothermic reaction is released as heat.

Burning and combustion are both terms for the exothermic reaction in which heat is released. Redox chemical processes, which are primarily what occur during combustion, require an oxidant, often air oxygen. In any event, a high-temperature exothermic combustion process occurs when anything burns.

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Some historians think that drinking wine from lead-glazed vases contributed to the fall of the Roman Empire.

Rome played a significant role in the history of wine. The first people to have an impact on winemaking on the Italian peninsula were the ancient Greeks and Etruscans.

Scientific advancements and an expanding understanding of winemaking were both brought about by the expansion of the Roman Empire. Rome had a significant impact on the history of today's important wine-producing regions in France, Germany, Italy, Portugal, and Spain.

Because the Romans believed that wine was a daily necessity, the beverage was "democratic" and widely available to everyone, including slaves, peasants, and aristocrats, both men and women. To ensure a consistent supply of wine for Roman soldiers and colonists, viticulture and wine production spread throughout the empire.

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The final volume of the gas is[tex]$1184 \mathrm{~mL}$[/tex]

This problem is based on the concept of work done in a thermodynamic process.

Thermodynamics is the science which deals with heat and work and the properties of substances. It also provides a relation between heat and work.

In thermodynamics, the work done is given by

[tex]W=-P \Delta V.[/tex]......(1)

Here, W is the work done,

[tex]$\Delta V$[/tex]

is the net change in volume and the negative sign indicates that the work has been done by the system.

This equation is expanded and written as:

[tex]$$W=-P\left(V_{\text {final }}-V_{\text {initial }}\right) .......(2)$$[/tex]

Here,

is the final volume and

[tex]$V_{\text {final }}$[/tex]

is the initial volume.

Generally,

Vinitial

760 torr [tex]$=101325 \mathrm{~Pa}$[/tex]

The pressure is given as,

783torr

Convert units of pressure as follows:

[tex]$$\begin{gathered}P=\frac{101325 \mathrm{~Pa}}{760 \text { torr }} \times 783 \\=10^5 \mathrm{~Pa}\end{gathered}$$[/tex]

The volume is given as,

[tex]$72.9 \mathrm{~mL}$[/tex]

Convert units of volume as follows:

[tex]$$\begin{gathered}V_{\text {initial }}=72.9 \mathrm{~mL} \times \frac{10^{-6} \mathrm{~m}^3}{1 \mathrm{~mL}} \\=72.9 \times 10^{-6} \mathrm{~m}^3\end{gathered}$$[/tex]

A quantity can be represented in various units. These units are related to each other by some certain values. But the calculation is done only in SI units.

Hence, conversion of these units is necessary.

Work done is given is given by the equation (2).

Substitute [tex]$111.1 \mathrm{~J}$[/tex] for

as

[tex]$10^5 \mathrm{~Pa}$[/tex]

for

and

[tex]$72.9 \times 10^{-6} \mathrm{~m}^3$[/tex]

for

[tex]$V_{\text {initial }}$[/tex]

in equation (2).

[tex]$$\begin{gathered}111.1 \mathrm{~J}=-10^5 \mathrm{~Pa}\left(V_{\text {final }}-72.9 \times 10^{-6} \mathrm{~m}^3\right) \\111.1 \mathrm{Pam}^3=-10^5 \mathrm{~Pa}\left(V_{\text {final }}-72.9 \times 10^{-6} \mathrm{~m}^3\right) \\V_{\text {final }}=1\left(111 \times 10^{-6}+72.9 \times 10^{-6}\right) \mathrm{m}^3 \\=1184 \times 10^{-6} \mathrm{~m}^3\end{gathered}$$[/tex]

Hence,

[tex]$$\begin{gathered}V_{\text {final }}=1184 \times 10^{-6} \mathrm{~m}^3 \times \frac{1 \mathrm{~mL}}{10^{-6} \mathrm{~m}^3} \\=1184 \mathrm{~mL}\end{gathered}$$[/tex]

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In the titration of acetic acid and NaOH, the excess bases added in order to detect the indicator color change endpoint will cause the calculated and reported mass percent of acetic acid in vinegar to be too high because it is assumed more base has reacted other than has actually reacted.

An indicator is a substance that changes color as the pH of the solution in which it is present changes.

Indicators are usually solutions of weak organic acids or bases. Some examples of indicators are methyl orange, methyl red, phenolphthalein, etc.

In a titration experiment, the color changes that occur in an indicator indicate the endpoint or equivalent point of the reaction.

Some indicators produce a sharp color change at the endpoint of a titration, whereas others do not.

Indicators are chosen to produce a suitable sharp color change at the endpoint of a given reaction.

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Percent composition of an organic compound and Empirical formula of an organic compound this information can be obtained from a combustion analysis.

The empirical formula of a compound can be determined through combustion analysis, but the chemical formula cannot be (other techniques can though). Once known, the empirical formula can be used to determine the chemical formula. Combustion analysis involves burning an organic compound that has a mixture of the elements C, H, N, and S. The mass of the combustion products is then recorded. This knowledge allows us to determine the empirical formula of the original chemical.  The empirical formula of sulfur monoxide, abbreviated SO, and disulfuric dioxide, abbreviated S2O2, are two straightforward examples of this idea. The solenoid is a particular kind of electromagnet, and its function is to produce a controlled magnetic field through a coil twisted into a compact helix. In the figure below, the solenoid is depicted. A wire coil serves as the solenoid, and a soft iron plunger serves as the piston.

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Ammonium acetate is a salt formed from ammonium hydroxide (weak base) and acetic acid (weak acid).

NH4OH + CH3COOH 1  CH3COO-NH4+ + H2O

Here, pKb for NH4OH = 4.8

And, pKa for CH3COOH = 4.74

Now, for a salt of weak acid and weak base

pH = 7 + 0.5 (pKa - pKb)

pH = 7 + 0.5 (4.74 - 4.8)

pH = 7 + 0.5 (- 0.06)

pH = 7 - 0.03

pH = 6.97

Since, pH is slightly less than 7, it is slightly acidic (almost neutral).

Ammonium acetate and acetic acid are frequently combined to form a buffer solution because they are the salt of two weak acid and base. At low pressures, ammonium acetate is flammable. As a result, while preparing samples for mass spectrometry, it has been utilised to substitute cell buffers that include non-volatile salts. Due to this, it is frequently used as a buffer for mobile phases in HPLC systems with ELSD detection. This has also been done with other volatile salts, like ammonium formate.

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Answer:

Through intermolecular constant tube routes

Acid protonates the hydroxyls of the starting material, turning them into a better leaving group.

A salt is a compound formed when the negative ions from an acid combine with the positive ions of a base.

Neutralization is a chemical reaction between an acid and a base that takes place in a water solution, the products of which are water and salts.

NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O (l)

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