The horizontal distance at which the parcel should be dropped away from the island in order to be landed there is 697.5 m.
What is the horizontal distance travelled by the plane?
The horizontal distance travelled by the plane is calculated as follows;
X = vt
where;
v is the horizontal speed of the planet is the time of motion of the food from the given heighth = ut + ¹/₂gt²
where;
u is initial vertical velocity = 0t is the time of motionh = 0 + ¹/₂gt²
h = ¹/₂gt²
2h = gt²
t = √(2h/g)
t = √(2 x 100 / 9.8)
t = 4.5 seconds
Horizontal distance = 155 m/s x 4.5 s
Horizontal distance = 697.5 m
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If a direct current of 5 Volts, goes through a primary coil, the voltage in the secondary coil will be double.
A) True
B) False
If a direct current of 5 Volts, goes through a primary coil, the voltage in the secondary coil will be double is the false statement.
The voltage across the secondary coil is greater than the voltage across the primary. There are fewer turns on the secondary coil than the primary.
The output power is greater than the input power. The current in the secondary coil is greater than the current in the primary coil.
The secondary voltage of a transformer may be either in phase or out of phase with the primary voltage. This depends on the direction in which the windings are wound and the arrangement of the connections to the external circuit.
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Object A is positive
Object A repels object B
Object B I attracted to objects C and D
When C is touched to an electroscope, nothing happens.
When object D touches an electroscope, the leaves repel.
What are the charges of objects B,C and D? Explain your reasoning. (3 pts)
The charges on B, C , and D objects are negative, positive and positive respectively.
The electroscope instrument is used to find out whether there is charge present and how much of it there is.
The leaves at the bottom of the electroscope spread apart when a charged object is brought close to the top of the instrument (for example, a positive charge). The positive charge on the leaves has gotten stronger as they diverge more.
This occurs when the charged object imparts a positive charge on the leaves. When the object is positively charged, this is possible. They move farther apart the higher the charge.
The charges on B, C , and D objects are negative, positive and positive respectively.
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The velocity components of an incompressible, two-dimensional velocity field are given by the equations u= y2 – x(1 + x) v = y(2x + 1) Show that the flow is irrotational and satisfies conservation of mass.
The velocity flow field is irrotational and the conservation of mass is preserved.
Irrotational flow for a two-dimensional velocity field happens when
[tex]\frac{dv}{dx} \:-\: \frac{du}{dy} \:=\: 0[/tex]
Conservation of mass for an incompressible happens when
[tex]\frac{du}{dx} \:+\: \frac{dv}{dy} \:=\: 0[/tex]
Perimeter
u = y² - x (1+x)Calculate the derivate in each function.
[tex]\frac{du}{dx} = 0 - 1 - 2x = - 2x - 1[/tex][tex]\frac{du}{dy} = 2y - 0 - 0 = 2y[/tex][tex]\frac{dv}{dx} = 2y + 0 = 2y[/tex][tex]\frac{du}{dy} = 2x + 1[/tex]Checking the irrotational flow
[tex]\frac{dv}{dx} \:-\: \frac{du}{dy} \:=\: 2y - 2y = 0[/tex]
Checking conservation of mass for an incompressible
[tex]\frac{du}{dx} \:+\: \frac{dv}{dy} \:=\: - 2x - 1 + 2x + 1 = 2x - 2x + 1 - 1 = 0[/tex]
So the velocity flow field is irrotational and the conservation of mass is preserved.
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if the mass of the earth and all objects on it were suddenly doubled, but the size remained the same, the acceleration due to gravity at the surface would become if the mass of the earth and all objects on it were suddenly doubled, but the size remained the same, the acceleration due to gravity at the surface would become 4 times what it now is. 1/2 of what it now is. 1/4 of what it now is. 2 times what it now is. the same as it now is.
Answer:
Explanation:Physics is the branch of science that deals with the structure of matter and how the fundamental constituents of the universe interact. It studies objects ranging from the very small using quantum mechanics to the entire universe using general relativity.
what is the correct formula for cauculating speed
Answer: speed = distance ÷ time
the cable lifting an elevator is wrapped around a 1.0-m-diameter cylinder that is turned by the elevator's motor. the elevator is moving upward at a speed of 1.9 m/s . it then slows to a stop, while the cylinder turns one complete revolution.
The time taken by the elevator to stop if the cable lifting an elevator is wrapped around a 1.0-m-diameter cylinder and the elevator is moving upward at a speed of 1.9 m/s is 3.28 s
d = 1 m
r = d / 2
r = 1 / 2 = 0.5 m
Vertical distance travelled = Circumference of the cylinder
s = 2 π r
s = 2 * 3.14 * 0.5
s = 3.14 m
v² = u² + 2 a s
v = 0
u = 1.9 m / s
0 = 1.9² + ( 2 * a * 3.14 )
6.28 a = - 3.61
a = - 0.58 m / s²
v = u + at
0 = 1.9 + ( - 0.58 * t )
t = 1.9 / 0.58
t = 3.28 s
Therefore, the time taken by the elevator to stop is 3.28 s
The given question is incomplete. The complete question is:
The cable lifting an elevator is wrapped around a 1.0-m-diameter cylinder that is turned by the elevator's motor. The elevator is moving upward at a speed of 1.9 m/s. It then slows to a stop as the cylinder makes one complete turn at constant angular acceleration. How long does it take for the elevator to stop?
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a car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 34 ft/s2. what is the distance covered before the car comes to a stop?
The calculated value is 84.03 ft. The deceleration will be calculated by multiplying the final velocity by the initial velocity, then dividing that result by the time it takes for the velocity to drop.
Given that you don't have enough time to complete this task, you can only apply the kinematic formula Vf 2 = Vi 2 + 2aD, which includes all the variables.
0 for Vf = Final Velocity (since you are trying to stop)
Initial Velocity = 50 MPH (Vi)
a= acceleration equals 32 ft/s2.
D is the distance covered (displacement)
We must ensure that all variables and constants are in the same units before we can use this formula. This means that all of your measurements should be in feet (ft) or miles (mi), and all of your time measurements must be in seconds (s) or meters (m).
Now calculate the distance by separating D by itself.
D= (-5377.7778/ -64)\s
= 84.03 ft
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Seetha is moving to a new house. Her old house is 5.8 km away from her new house. Find the distance between her new house and old house in meter.
Answer:
5.8km=5800m
Explanation:
You have to convert kilometres into metres
Answer:
It's 5,800 meters
Explanation:
In the question the distance has been already given, what's required is converting it from Kilometers to Meters. This means you will need to multiply 5.8 by 1000 to get your answer.
if the 140 g ball is moving horizontally at 23 m/s , and the catch is made when the ballplayer is at the highest point of his leap, what is his speed immediately after stopping the ball?
The speed immediately after stopping the ball is 0.049 m/s.
What is meant by velocity?Velocity is the directional speed of a moving object as an indication of its rate of change in location as perceived from a specific frame of reference and measured by a specific time standard.
Given,
The mass of ball m = 140 g = 0.140 kg.
The speed of ball u = 23 m/s.
We must determine the speed at which the ballplayer is at the peak of his leap. They will remain together. Allow them to move at the speed of V.
Allow a 65-kilogram baseball player to jump straight up to catch a hard-hit ball. Then, according to linear momentum conservation.
mu+ Mu'=(m+ M)V
In this case, u' represents the player's initial speed. Because the player was initially at rest, u' = 0.
(0.140×23)+(65×0)=(0.140+65)V
V=(0.140×23)/(0.140+65)
V=3.22/65.14
V=0.0494
Therefore, the speed immediately after stopping the ball is 0.049 m/s.
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one advantage of the hubble space telescope over ground based ones is that
Space telescopes have the advantage of being above the blurring effects of the Earth's atmosphere.
A surrounding is a layer of fuel or layers of gases that envelop a planet and is held in a region through the gravity of the planetary frame. A planet retains its surroundings whilst the gravity is exceptional and the temperature of the surroundings is low. A stellar ecosystem is the outer area of a celeb, which includes the layers above the opaque photosphere; stars of low temperature may have outer atmospheres containing compound molecules.
The atmosphere of Earth consists of nitrogen (78%), oxygen (21%), argon (0.9%), carbon dioxide (0.04%), and trace gases. most organisms use oxygen for breathing; lightning and bacteria perform nitrogen fixation to provide ammonia that is used to make nucleotides and amino acids; flora, algae, and cyanobacteria use carbon dioxide for photosynthesis.
The layered composition of the ecosystem minimizes the damaging results of daylight, ultraviolet radiation, solar wind, and cosmic rays to defend organisms from genetic harm. The modern composition of the atmosphere of the Earth is made from billions of years of biochemical modification of the paleo atmosphere by residing organisms.
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at takeoff the aircraft travels at 55.0 m/s, so that the air speed relative to the bottom of the wing is 55.0 m/s. given the sea level density of air to be 1.29 kg/m3, how fast (in m/s) must it move over the upper surface to create the ideal lift?
The velocity of the aircraft to move over the upper surface to create the ideal lift is 67.64 m/s.
Describe Bernoulli's principle?
According to the Bernoulli's principle of fluid dynamics, a fluid's speed increases concurrently with a drop in static pressure or a drop in potential energy.The idea of energy conservation can be used to derive Bernoulli's principle. This implies that in a steady flow, the total amount of energy present in a fluid is constant at all points that are not affected by viscous forces. In order to achieve this, the total amount of kinetic energy, potential energy, and internal energy must remain constant.Because of Bernoulli's principle, which states that when air speeds up, pressure decreases, airplanes are able to fly. Thus, the reason a wing produces lift is because the air moves faster over the top, resulting in a region of low pressure and lift.
The ideal lift is determined by the fluid density and velocity relationship, so:
F_lift = 1/2 x p x A x (v_f^2 - v_i^2)
As a result, the fluid's density may be calculated.
p = 1.29 kg / m^3
The situation's environment indicates that the wings generate roughly 100N of lift per square meter of wings, therefore
A = 1 m^2
the beginning speed is
v_i = 55.0 m/s
Replacing
F_lift = 1/2 x 1.29 x 1 x (v_f^2 - 55 x 55)
1000 = 0.645 x (v_f^2 - 3025)
1550.387 = (v_f^2 - 3025)
v_f^2 = 4575.387
v_f = 67.64 m/s.
Hence, the velocity of the aircraft to move over the upper surface to create the ideal lift is 67.64 m/s.
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An athlete is running at a constant velocity with a javelin held in his right hand. The force he is applying on the javelin to carry it is 5. 0 newtons. If he covers a distance of 10 meters, what work has he done on the javelin?.
If he covers a distance of 10 meters, the work he has done on the javelin is 0 joule.
In physics, it measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. In its simplest form, for a constant force aligned with the direction of motion, it equals the product of the force strength and the distance traveled.
How to determine the work he has done on the javelin?
The actual formula of finding the work is
W = F × S cos a, a is the angle in which the athlete is carrying the javelin.
or, W = 5 × 10 cos90, angle is 90 with the vertical component of the force (because the force of 5N that the athlete is applying to the javelin can't possibly be in the direction that he and the javelin are moving, otherwise the javelin would be accelerating)
cos 90 = 0
therefore 5*10*0=0,
Hence work done in joules is 0 joules.
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2. consider two masses in a closed system. show that newton's third law results in conservation of momentum
Consider two masses in a closed system. The Newton 3rd law, F₁₂ = -F₂₁, will result in conservation of momentum m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.
Suppose we have two masses, m₁ and m₂. According to the Newton's 3rd Law:
F₁₂ = -F₂₁
Where:
F₁₂ = force on m₁ due to m₂
F₂₁ = force on m₂ due to m₁
If there is collision between two masses, we can assume that the forces acted in the same time interval. Hence,
F₁₂ . t = -F₂₁ . t
Force is defined as the change of momentum (Δp) over time (t), or
F = Δp / t
Substitute F . t = Δp on both sides,
Δp₁ = –Δp₂
p₁_final - p₁_initial = –(p₂_final - p₂_initial)
p₁_initial + p₂_initial = p₁_final + p₂_final
This is the conservation law of momentum.
Let:
u = initial velocity
v = final velocity
Then,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
This is another form of the conservation law of momentum. Hence, we have shown that the Newton 3rd Law will lead to the conservation of momentum.
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Select the correct answer from each drop-down menu. How can you summarize the ruler placement postulate? you can measure the between points a and b by using as zero.
The ruler placement hypothesis can be summed up as follows:
The set of points on the line and the set of real numbers are equivalent in every way, and the absolute value of the difference between the matching numbers is equal to the distance between two points.
According to this, a set of points on a line can be matched with a set of real numbers, and vice versa. In order to help you better understand the ruler placement postulate, a general overview is provided based on the fact that your question is incomplete.
A ruler is a tool or measuring device that is used to measure length and draw straight lines. A measure is used to determine the length in both measured and conventional units.
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what is it called when heat cannot escape into space?
Brownlee Heat Exchange Anomaly -Greenhouse Effect. when heat cannot escape into space.
The greenhouse effect is a process that occurs when electricity from a planet's host star is going via its ecosystem and heats the planet's floor, however, greenhouse gases within the surroundings prevent some of the warmth from returning without delay to the area, ensuing in a hotter planet. Earth's natural greenhouse impact maintains the planet from having the under-freezing temperature that it would have if there have been no greenhouse gases. moreover, human-induced increases in greenhouse gases trap more amounts of warmth, inflicting the Earth to develop warmer over the years.
most gases inside the ecosystem are transparent to infrared, however, the small share of the surroundings that constitutes greenhouse gases absorbs some of the heat emitted through the floor rather than letting it get away into space. those greenhouse gas molecules then emit radiant heat in all instructions, passing warmness to the surrounding air and warming different greenhouse gas molecules.
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a uniform slender rod ab rests on a frictionless horizontal surface, and a force p of magnitude 0.25 lb is applied at a in a direction perpendicular to the rod. assume that the rod weighs 2.15 lb.
The force implemented at the rod is P=zero.25lb P = zero.25 l b. the burden of the rod is w=1.75lb w = 1. seventy-five lb. The kinematic diagram of the rod.
Friction is any point in the consumer's journey with an organization wherein they hit a snag that slows them down or causes dissatisfaction. in the most primary concept, offering frictionless customer support way tracking the consumer adventure and improving the consumer revel in.
The overwhelming consensus is that ice has low friction because of a skinny film of liquid water coating its surface. for this reason, skaters balanced on skinny steel blades can float easily throughout the ice rink, but grind to a halt at the timber ground beyond.
Motion is certainly viable without friction even though an item is stationary in a single reference frame, in some other reference body shifting with admire the first, that identical object may be seen to be transferring. So movement actually does not need friction at all.
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50pts!
If the water displaced by an object has a volume of 0.1 m3, what is the buoyant force exerted on that object?
980 Newtons
98 Newtons
9.8 Newtons
0.98 Newtons
Answer: 980 Newtons
Explanation:
A weight lifter lifts a set of weights a vertical
distance of 3.66 m. If a constant net force of 370 N
is exerted on the weights, how much net work is done on the weights?
1.741.3
2. 1214.01
3.431.52
4. 381.92
5.874.68
6. 1179.02
7. 1354.2
8. 1154.56
9. 1509.12
10. 706.85
Answer in units of J.
Answer:
See below
Explanation:
Work = F * d
= 370 N * 3.66 m = 1354.2 J
An object accelerates uniformly from rest. If the final velocity of the object after 4.7s is 15 m/s east, what is the magnitude displacement
The displacement of the object that accelerates uniformly from rest is 35.25 m due East.
What is displacement?Displacement can be defined as distance in a specified direction.
To calculate the displacement of the object, we use the formula below.
Formula:
s = (v+u)t/2............... Equation 1Where:
s = Displacement of the objectv = Final velocityu = Initial velocityt = Time.From the question,
Given:
v = 15 m/s eastu = 0 m/s (from rest)t = 4.7 sSubstitute these values into equation 1
s = (15+0)4.7/2s = 35.25 m due East.Hence, the displacement of the body is 35.25 m due East.
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During a baseball game, a batter hits a popup to a fielder 84 m away. The acceleration of gravity is 9.8 m/s 2 . If the ball remains in the air for 5 s, how high does it rise? Answer in units of m.
The ball rises up to 30.625 m high.
What is gravity?The force that pulls items toward the centre of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.
Given parameters:
Horizontal range of the ball; R = 84 m.
Time of flight of the ball: T = 5 s.
Acceleration due to gravity; g = 9.8 m/s².
We have to find, maximum height obtained by the ball; H = ?
In projectile motion, time of flight is; T = 2usinθ/g
Where, u = initial velocity of the ball and θ = angle of projection.
So, 2usinθ/g = 5
⇒ usinθ = 5g/2 = (5×9.8)/2m/s = 24.5 m/s.
Then maximum height obtained by the ball;
H = u²sin²θ/2g
= 24.5²/(2×9.8) = 30.625 m.
Hence, maximum height obtained by the ball is 30.625 m.
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Now our wavelength is getting longer because the waves are stretching out. This make the _________ lower as well as the pitch we hear.
Now our wavelength is getting longer because the waves are stretching out. This makes the 1. Frequency is lower as well as the pitch we hear.
Wavelength is the gap among equal factors (adjacent crests) in the adjacent cycles of a waveform sign propagated in the area or alongside a twine. In wi-fi systems, this duration is generally laid out in meters (m), centimeters (cm), or millimeters (mm).
Equation of the wavelength, we will tell that the wavelength of a wave is inversely proportional to its frequency, i.e., because the frequency of a wave increases, its wavelength decreases.
A better-frequency sound has a better pitch, and a decreased-frequency sound has a lower pitch. In discern 10.2 sound A has a better pitch than sound B. for example, the chirp of a bird would have an excessive pitch, but the roar of a lion could have a low pitch. The human ear can discover a huge variety of frequencies.
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Disclaimer:- your question is incomplete, please see below for the complete question.
Now our wavelength is getting longer because the waves are stretching out. This makes the _________ lower as well as the pitch we hear.
1. Frequency
2. Loudness
3. Amplitude
a horizontal force is applied to a 4.0 kg box. the box starts from rest moves a horizontal distance of 8.0 meters and obtains a velocity of 6.0 m/s. the system is frictionless. the horizontal force is: a. 3.0 n. b. 5.0 n. c. 7.0 n. d. 9.0 n. e. 11 n.
According to Newton's first law, an object will accelerate at a constant rate if its net force is zero. The calculated value is 39.2 N
This indicates that the velocity is constant but does not necessarily imply that the item is at rest.
F = m a
= 4 kg x 2.5 m/s/s x 10 N, correct.
The formula for Fgrav is:
Fgrav = m • g
= 4 kg • 9.8 m/s/s
= 39.2 N since the mass is known.
The normal force is equivalent to the gravitational force since there is no vertical acceleration. A force in physics is any interaction that, if left unchecked, will alter an object's motion. An object with mass can change its velocity due to a force, which includes starting to move from a state,
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if you throw a ball up into the air with an initial vertical velocity of 30 m/s how long will the ball be in the air before it comes all the way back down to your hand
Answer:
Below
Explanation:
Here is a way:
When the ball reaches its maximum height , it is 1/2 of the way back to your hand AND its velocity = 0 Find this time and double it to get to your hand.
Vf = vo - at
0 = 30 - 9.81(t) shows to to max height = 3.06 seconds
double it : = 6.12 seconds
question a toy doll and a toy robot are standing on a frictionless surface facing each other. the doll has a mass of 0.20 kg, and the robot has a mass of 0.30 kg. the robot pushes on the doll with a force of 0.30 n. the magnitude of the acceleration of the robot is
The magnitude of the acceleration of the robot is 1 m/s².
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
mass of doll = 0.20 kg
mass of robot = 0.30 kg
Force on dall by robot = 0.30 N
acceleration on doll = mass of doll / force of robot
= 0.20 / 0.30
= 0.67 m/s²
Same force applied to the robot by Newton's third law of motion = 0.30 N
acceleration of the robot = mass of robot/force
= 0.30 / 0.30
= 1 m/s²
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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according to your observations and background reading, how would redesign the wind turbine to maximize its output? consider wind direction, blade attack angle, etc.
The wind turbine gives maximize its output when a turbine having longer blades.
Wind turbines :
A wind turbine is a device that uses the wind's kinetic energy to create electricity.
These early windmills were used to run mills powered by the wind, as their name suggests.Wind turbines can sweep more ground, catch more wind, and generate more electricity when their rotor diameters are larger.Wind turbines with blades and horizontal axis.Three things should be taken into account when determining value:
(1) Installation fees
(2) projected annual power output
(3) assurance regarding the projected yearly power production
The wind turbine gives maximize its output when a turbine having longer blades.
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What will the density be if the radius of the sphere is halved, compressing the air within?.
The resultant density of the sphere when its radius is halved is eight times the initial density of the sphere.
Let the radius of the sphere = r
The volume of the sphere = [tex]\frac{4}{3} \pi r^{3}[/tex]
Mass of the sphere = M
Now, The density of the sphere = D = Mass/Volume
So, The density will be,
[tex]D = \frac{M}{\frac{4}{3} \pi r^{3} } = \frac{3M}{4\pi r^{3} }[/tex]
It is given that the radius of the sphere is halved, then
[tex]D' = \frac{M}{\frac{4}{3} \pi (\frac{r}{2} )^{3} } = \frac{24M}{4\pi r^{3} } = \frac{6M}{\pi r^{3} }[/tex]
Now, Dividing both the densities, D and D', we get
[tex]\frac{D}{D'} = \frac{1}{8}\\ \\D' = 8D[/tex]
Hence, The resultant density of the sphere when its radius is halved is eight times the initial density of the sphere.
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A sled and rider, gliding over horizontal, frictionless ice at 4.7 m/s , have a combined mass of 74 kg . The sled then slides over a rough spot in the ice, slowing down to 2.9 m/s . What impulse was delivered to the sled by the friction force from the rough spot? Express your answer to two significant figures and include the appropriate units.
The Impulse is - 74 Ns
Impulse (symbolized by J or Imp) is the integral of a force, F, over the time interval, t, for which it acts.
The SI unit of impulse is the newton second (N⋅s)
Examples of impluse in real life could include hitting a ball,tossing a coin, kick starting scooter etc.
The values known to us are -
J =?
Mass (m) = 74 kg
Initial velocity (Vi) = 4 m/s
Final velocity (Vf) = 3 m/s
To find Impulse-
J = ΔP = m ( Vi-Vf)
J = 74kg ( 3m/s- 4m/s)
J = - 74 Ns
The impulse is -74Ns, here the negative sign indicates the direction of impulse, in the opposite direction of motion.
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An 9 kg object is accelerated with 450N of force. What will be the acceleration of the object? Show your work.
Answer:
Explanation:
Given:
m = 9 kg
F = 450 N
_________
a - ?
According to Newton's 2nd law:
a = F / m
a = 450 / 9 = 50 m/s²
definition of sound waves
Answer:
Explanation:
a wave of compression and rarefaction, by which sound is propagated in an elastic medium such as air.
astronomers have detected storms in the atmospheres of the jovian planets, including giant storms that are larger than the entire planet earth. listed below are characteristics of storms. sort these characteristics according to whether they are associated with jovian storms only, terrestrial storms only, or both jovian and terrestrial storms.
The listed characteristics of storms are sorted according to whether they are associated with Jovian storms only, terrestrial storms only, or both Jovian and terrestrial storms.
Jovian storms are associated with oppositely-directed high-speed atmospheric flowsJovian storms are hosted by rapidly-rotating planetTerrestrial storms are powered by solar radiationTerrestrial storms are short-lived (hours to days)Both Jovian and terrestrial storms involve upwelling gassesBoth Jovian and terrestrial storms involve circulating windsThe terrestrial planets are the planets of inner solar system such as Mercury, Venus, Earth and Mars. Unlike terrestrial planets Jovian planets do not have a solid surface. They are primarily composed of hydrogen and helium in their atmosphere.
Therefore, the listed characteristics of storms are sorted according to whether they are associated with Jovian storms only, terrestrial storms only, or both Jovian and terrestrial storms.
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