An air traffic controller is tracking two planes. To start, Plane A was at an altitude of 1300 meters, and Plane B was at an altitude of 1092 meters. Plane A is gaining altitude at 17 meters per second, and Plane B is gaining altitude at 21 meters per second. Let x be the number of seconds passed
Answers
(A) The expression for each plane are as follows;
Plane A; 1300 + 17x
Plane B; 1092 + 21x
B). The equation to show when the two planes would be at the same altitude is; 1300 + 17x = 1092 + 21x.
Which equation shows when the two planes would be at the same altitude?It follows from the task content that the initial altitudes of plane A and B are 1300 and 1092 respectively.
Since plane A gains altitude at 17 meters per second; The expression for the altitude after x seconds is;
1300 + 17x
Also, since plane B gains altitude at 21 meters per second; The expression for the altitude after x seconds is;
1092 + 21x
Ultimately, at the point when the two planes are at the same altitude; the equation which is true about the situation is;
1300 + 17x = 1092 + 21x.
Read more on linear equations and expressions;
https://brainly.com/question/29270827
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