The exit temperature = 5333.33 K
Explanation:The inlet pressure: P₁ = 150 kpa
The inlet temperature T₁ = 400K
The exit pressure, P₂ = 2 MPa = 2000 kPa
The exit tenperature, T₂ = ?
The relationship between temperature and pressure for an isentropic process is shown below
[tex]\frac{T_2}{T_1}=\frac{P_2}{P_1}[/tex]Substitute the given parameters into the formula and solve for T₂
[tex]\begin{gathered} \frac{T_2}{400}=\frac{2000}{150} \\ \\ T_2=400(\frac{2000}{150}) \\ \\ T_2=5333.33K \\ \end{gathered}[/tex]The exit temperature = 5333.33 K
Find the force required to do 25 joule work when the force causes a displacement of 0.5m
Answer: Force required to 25 joule work when the force causes a displacement of 0.5m is 50N
Explanation: To calculate the work done we use the formula
W=F.s (1)
W= work done
F= force applied s= displacement
Given, work done W= 25 joules= 25 J
displacement s= 0.5m
∴From equation (1) we get the force required when work is done and displacement is given, that is
F[tex]=\frac{W}{s}[/tex] (2)
∴Force required [tex]F=\frac{W}{s}= \frac{25J}{0.5m}=50N[/tex]
(1 J is the work done by a force of 1 N acting over a displacement of 1 m and so 1 J= 1 Nm⇒ 1 N = 1 J/m)
ANS: Force required to do 25 J work when a force causes displacement of 0.5m = 50 N
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A battery-powered lawn mower has a mass of 25.0 kg. If a student pushes the lawn
mower with 15.5 N of force, the lawn mower’s motor provides a force of 20.0 N, and
the grass provides a resistance force of 3.00 N, what is the net force and acceleration
of the lawn mower?
The net force of the lawn mower is 32.5 N and acceleration is 1.62 m/s^2.
The student pushes the lawn mower with 15.5 force and the lawn mower's motor provides 20.0 N force. The grass has a resistance force 3.0 N which is in opposite direction to the student's and lawn mower's forces. So, the net force is given,
F = 15.5 N + 20.0 N - 3.0 N = 32.5 N
According to Newton's second law, we know the relation between acceleration and force applied. Force is equal to mass times acceleration. The mass of the lawn mower is 25.0 kg.
[tex]a=\frac{F}{m}[/tex]
a = 32.5/20 = 1.62 m/s^2
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Which is the CORRECT description of the sequence of energy transformations occurring in this system?
Answer:
Explanation:
(I) Electrical energy into sound energy. (ii) Heat energy into kinetic energy (or mechanical energy). (iii) Chemical energy into kinetic energy (or mechanical energy). (iv) Chemical energy into heat energy
How do the masses of objects affect the strength of gravitational force?
Answer:
So as the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation:
If the mass of one of the objects is doubled, then the force of gravity between them is doubled. If the mass of one of the objects is tripled, then the force of gravity between them is tripled.
You are asked to consult for the city's research hospital, where a group of doctors is investigating the bombardment of cancer tumors with high-energy ions. The ions are fired directly toward the center of the tumor at speeds of 5. 5 ×106m/s. To cover the entire tumor area, the ions are deflected sideways by passing them between two charged metal plates that accelerate the ions perpendicular to the direction of their initial motion. The acceleration region is 5. 0 cm long, and the ends of the acceleration plates are 1. 5 m from the patient.
What sideways acceleration is required to deflect an ion 2. 0 cm to one side?
Express your answer to two significant figures and include the appropriate units
The sideways acceleration is required to deflect an ion 2. 0 cm to one side is [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex].
Velocity = 5. 5 × [tex]10^{6}[/tex] m/s
acceleration region = L1 = 5.0 cm = 0.05 m
Ends of the acceleration plates = L2 1. 5 m
D = 0.02 m
a = [tex]\frac{2v^{2}d }{2L1L2+L1^{2}}[/tex]
Putting the values
a = 2×( 5. 5 × [tex]10^{6}[/tex])^2 × 0.02 m / 2 × 0.05m × 1.5m + (0.05m)^2
a = 1×10^12 m^2/s / 0.15m^2+2.5×10^-3m^2
a = 2 ×10^5 m^2/s / 0.1525 m^2
a = [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex]
The sideways acceleration is required to deflect an ion 2. 0 cm to one side is [tex]6.56[/tex]×[tex]10^{12}[/tex] m/[tex]s^{2}[/tex].
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The sideways acceleration required to deflect an ion 2.0cm to one side is [tex]7.9*10^{12} m/s^{2}[/tex] expressed to 2 significant figures
Given the following:
V = 5.5 X10 m/s
Acceleration region (L[tex]^{1}[/tex]) = 5.0 cm long
Ends of the acceleration plates are L[tex]_{2}[/tex] = 1.5m from the patient
Now determine the sideways acceleration to deflect anion
d=2.0cm to one side.
Sideway acceleration is:
[tex]a=\frac{2V^{2}d }{2L_{1}L_{2}+L_{1} ^{2} }[/tex]
[tex]a=\frac{2*(5.5*10^{6})^{2}*0.02 }{(2*0.05*1.5)+0.05^{2} }[/tex]
[tex]a=7.9344*10^{12}m/s^{2} \\[/tex]
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the motion of one particle of a gas is unaffected by the motion of other particles of the gas unless the particles _____.
The motion of one particle of a gas is unaffected by the motion of other particles of the gas unless the particles collide.
What causes the motion of particles?Heat is the primary cause of particle motion on Earth. The temperature of any substance is correlated with the energy of the atoms and molecules that comprise it. Energy is conserved, thus if one particle loses energy, another one acquires it.
What is the motion of particles of matter called?The components of matter are also continually in motion. They are energetic in motion. The kinetic theory of matter states that all matter is made up of particles that are constantly moving.
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What’s The difference between oxygen and water.
100 POINTS
Answer:
Oxygen gas is two oxygen atoms bonded together, O2. Water, is one oxygen atom bonded to two different hydrogen atoms, H2O
Explanation:
Ted wants to hang a wall clock on the wall by using a string. if the mass of the wall clock is 0.250 kilograms, what should be the tension of the string so that it can sustain the weight of the wall clock? a. 0.245 newtons b. 2.45 newtons c. 0 newtons d. 4.90 newtons e. 0.120 newtons
Answer:
B. 2.45 Newtons
Explanation:
This is a tension force problem with only tension and the weight force acting on the object. Using Newton's second law F=ma, and there being no acceleration in the system, T-w=0. Using this, T=w. w=mg, therefore (.250kg)(9.8m/s^2) = 2.45 Newtons
Answer:
See image
Explanation:
Plato
Cliff divers at acapulco jump into the sea from a cliff 30.3 m high. at the level of the sea, a rock sticks out a horizontal distance of 7.94 m. the acceleration of gravity is 9.8 m/^2
If there isn't any beginning vertical velocity, figure out how long it will take to get to the water, then divide that number by the horizontal distance to get the necessary minimum horizontal speed.and for t=6.18 sec, we obtain v =1.28 m/s.
Velocity is the rate of change in direction of an object in motion as measured by a specific standard of time and observed from a specific point of reference (for example, 60 km/h northbound). A key idea in kinematics, the area of classical mechanics that studies how bodies move, is velocity.
The definition of velocity requires both its magnitude and its direction because it is a physical vector quantity. Speed is a coherently derived unit that is measured in the SI (metric system) as metres per second (m/s or m/s1). Speed is the scalar absolute value (magnitude) of velocity. A scalar is a number, such as "5 meters per second," whereas a vector is "5 meters per second east." the case
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The inner diameter of a small test-tube Can be measured accurately using
Answer:
the Vernier caliper
Explanation:
Answer:
Vernier caliper
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a force of 40N stretches a wire through 3.0 cm what force will stretch it through 5.0cm and through what length will a force of 100N stretch it ?what assumption have you made
When the extension of the spring becomes 5 cm, the applied force is 66.67 N.
The length produced by a force of 100 N is 7.5 cm.
What is spring constant?The spring constant of a spring is also known as force constant, is the ratio of force to the extension of a spring.
The force constant of a spring describes how stiff a spring is or how tough a spring is.
The force constant of the given spring is calculated as follows;
k = F/x
where;
F is the applied force on the springx is the extension of the springk is the spring constantThe extension of the spring = 3 cm = 0.03 m
The force is given as 40 N
K = 40 N / 0.03 m
K = 1,333.33 N/m
If the extension of the spring becomes 5 cm, the applied force is calculated as follows;
F = kx
F = 1,333.33 x 0.05
F = 66.67 N
The extension produced by a force of 100 N;
x = F/k
x = 100/1,333.33
x = 0.075 m = 7.5 cm
The assumption made is that the applied force is directly proportional to the extension of the spring.
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in the winter sport of bobsledding, athletes push their sled along a horizontal ice surface and then hop on the sled as it starts to careen down the steeply sloped track. in one event, the sled reaches a top speed of 9.2 m/sm/s before starting down the initial part of the track, which is sloped downward at an angle of 9.0 ∘∘.
Due to the principle of energy conservation, the sled's initial potential and kinetic energy are identical to its ultimate kinetic energy. So the correct answer is vf =21.71 m/s.
According to no 12th law, additional forces are equal to M. A. Therefore, in this instance, MG sine data equals M. A. This will give us A. equals theta in the G symbol It will be the first equation at A. equals D B divided by D T. By using dx by DT, or D X by D T, we can multiply and divide. D X's indu D D. As a result, we shall obtain V D V by D X equals a. The second equation will be this.
The result of equation 192 is then that D V by D X equals G sign theta. Therefore, V D V is G scientology to be X equal. Now that D V equals integral energy, we can integrate this integral. G sign to D X to D. that we will receive G scientific data is equivalent to energy We Squire divided by two. X. We'll see. At X=0, nothing happens. We will have a speed of 9.2 m/s. 9.2 squared divided by two will equal C. 42.32 is what that comes to.
Then we divide Squire by two to get theta in the G sign. X + 42.32. Then, using this information, we can determine that we are equivalent to the root energy of two indu G sine theta into X plus 42.32. The numbers that are route off two can be changed to 9.8 m/s. Nine degree Squire In is 0.156. surplus food industry 1 40 m less 42.32. We shall therefore arrive at a quanto of 21.71 m/s by solving this.
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a truck of mass 2.40×103kg is moving at 25.0 m/s . when the driver applies the brakes, the truck comes a stop after traveling 48.0 m . how much time is required for the truck to stop?
The time required by the truck moving with speed 25.0 m/s and covering the distance 48.0 m is 3.84 seconds.
What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity.
As given in the question,
the initial speed of the truck when brakes are applied (u) = 25 m/s.
Final speed (v) = 0 m/s
The distance covered after brakes are applied (s) = 48 m.
By the Newton's equation of motion
[tex]v^2 = u^2 + 2as[/tex]
Putting values from the question from the question.
0 = (25)^2 + 2a(48)
a = -6.51 m/s^2
Now by the equation,
v = u + at
Putting value from question
0 = 25 - 6.51 t
t = 25/6.5
t = 3.84 seconds
Therefore, time taken is 3.84 seconds.
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find the stationary front located in northwestern canada. the likely air mass to the west of the stationary front is a air mass which is likely to be than the air mass to the east.
According to air masses classification, we can assume that to the west of the stationary front in northwestern Canada there is a maritime Polar (mP) air mass which is likely to be warmer than the air mass to the east. Option B) mP, warmer.
What are the air masses?
Air masses are horizontal extensions of moving air in which humidity, temperature, and physical properties are homogeneous.
Air masses can be classified according to their temperature (Cold or Warm), nature (continental -c- or maritime -m-), Origin region (Polar -P-, Artic -A-, Antarctic -AA-, Tropical -T-, Equatorial -E-)
Joining the previous classifications, we can identify different air masses
Continental Arctic and Antarctic air masses (cA and CAA)Maritime Artic air masses (mA)Continental Polar air masses (cP)Maritime Polar air masses (mP)Maritime Tropical (mT)Continental Tropical air masses (cT)Maritime Equatorial (mE)Maritime Polar air masses (mP)
These are cold and humid air masses that originate far from the poles and imply mild weather in coastal regions. In the winter they can be warmer than the continental Polar Air Masses (cP) and cooler in the summer. The masses that penetrate from the west are forced to rise when they encounter obstacles causing precipitation.Looking at the image, we will focus on the superior left area near the A. This is a red line with semicircles that represents a warmer front.
This red line comes from the west and moves forward to the northeast. Since this point is located near the coast, we can assume this is a maritime air mass.
These red lines, which represent worm fronts, suggest that to the west, the air is warmer than to the east.
The likely air mass to the west of the stationary front is a maritime Polar (mP) air mass which is likely to be warmer than the air mass to the east.
Option B) mP, warmer.
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Complete question
Find the stationary front located in northwesterm Canada.
The likely air mass to the west of the stationary front is ______ a air mass that is likely to be _____ than the air mass to the east.
A) cP: cooler
B) mP: warmer
C) cP: warmer
D) ml: warmer
A negatively charged conductor is brought in contact with a neutral conductor.
Which choice most accurately describes the motion of charge between these two objects?
The electrons in the charged object are attracted to the protons in the neutral object. Some of the electrons move from the
charged object to the neutral object, resulting in two negatively charged objects.
The protons in the neutral object are attracted to the charged object. Some of the protons move from the charged object
O to the neutral object. Finally, the neutral object becomes negatively charged, while the initial charged object becomes
neutral.
The protons in the neutral object are attracted to the charged object. Some of the protons move from the charged object
to the neutral object, resulting in two negatively charged objects.
The electrons in the charged object are attracted to the protons in the neutral object. Some of the electrons move from the
O charged object to the neutral object. Finally, the neutral object becomes negatively charged, while the initial charged
object becomes neutral.
When a negatively charged conductor is brought in contact with a neutral conductor, then both objects become charged negatively.
Conductors are substances through which electrons flow freely. When a conducting material has a charge, the charges repel and move away from each other, distributing themselves evenly about the outer surface .
Charging by conduction involves the contact between a charged and a neutral object. Therefore, when an uncharged conductor is brought in contact with a charged conductor, charge is shared between the two conductors and hence the uncharged conductor also gets charged.
Both objects have the same type of charge, during charging by conduction. If a negative object is used to charge a neutral object, then both objects become negatively charged.
Any charged object whether positively or negatively charged have an attractive interaction with a neutral object. Positively charged and neutral objects attract each other and similarly negatively charged and neutral objects attract each other.
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Identify the technologies as wireless technology or wired technology
Answer:
Headphones
Explanation:
There is some with wires and without
Answer:
headphones,phones,computers,robots,
Explanation:
some may have wires some may not but even if i did not answer correctly please give me a brainlyest
a 0.6 kg squirrel falling at 14 m/s hits in a pile of leaves and comes to rest in 2 s. find the normal force of the leaves on the squirrel as it comes to rest.
If a 0.6 kg squirrel falling at 14 m/s hits a pile of leaves and comes to rest in 2 s , the normal force of the leaves on the squirrel as it comes to rest would be 4.2 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem a 0.6 kg squirrel falling at 14 m/s hits in a pile of leaves and comes to rest in 2 s.
The change in the moment of the squirrel = 0.6 × 14
=8.4 Kg - m/s
The normal force = rate of the change of the momentum
= 8.4 / 2
= 4.2 Newtons
Thus, the normal force of the leaves on the squirrel as it comes to rest would be 4.2 Newtons.
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A kayaker is paddling across a river at 2.50m/s with a Northeastern direction (45 degrees N of E). A current pulls him with a velocity of 1.25m/s East. What is the kayakers resultant velocity?
According to the given statement The kayaker has a resultant velocity is ||v + w|| ≈ 2.80 m/s.
What is the velocity of resultant?An object's total vector velocity is the sum of its component vector velocities. The scalar product of an object's mass and acceleration vector equals the sum of the vector forces acting on it.
Briefing:The kayaker has velocity vector
v = (2.50 m/s) (cos(45º) i + sin(45º) j )
v ≈ (1.77 m/s) (i + j )
and the current has velocity vector
w = (1.25 m/s) (cos(315º) i + sin(315º) j )
w ≈ (0.884 m/s) (i - j )
The kayaker's resultant velocity is the sum of these:
v + w ≈ (2.65 m/s) i + (0.884 m/s) j
The kayaker has a resultant velocity of ||v + w|| ≈ 2.80 m/s in a direction θ such that
tan(θ) = (0.884 m/s) / (2.65 m/s)
θ ≈ 18.4º
or about 18.4º north of east.
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The complete question is -
A kayaker paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast). What is the kayaker's resultant velocity?
in about 1915, henry sincosky of philadelphia suspended himself from a rafter by gripping the rafter with the thumb of each hand on one side and the fingers on the opposite side (fig. 6-21). sincosky’s mass was 79 kg. if the coefficient of static friction between hand and rafter was 0.70, what was the least magnitude of the normal force on the rafter from each thumb or opposite fingers? (after suspending himself, sincosky chinned himself on the rafter and then moved hand-over-hand along the rafter. if you do not think sincosky’s grip was remarkable, try to repeat his stunt
The least magnitude of the normal force on the rafter from each thumb or opposite fingers is 276.5 Newtons.
As we know, henry is suspended by using his hands.
If he not going upward or downwards. we can conclude that the magnitude of all forces should be cancelling each other.
The force that is stopping the thumbs and the finger is frictional force.
Friction force f is a kind of force that comes into play when their is an actual slipping or the tendency to slip between any two contacted surface.
f = μN
where N is the normal force.
The net friction force should be equal to the total weight if the body,
Frictional force f by the fingers can be distributed equally in four parts,
mg = 4f
mg = 4μN
Mass is 79 Kg. g is 9.8m/s² and the value of μ is 0.7.
79 x 9.8 = 4 x 0.7 x N
N = 276.5 newtons.
So the least normal force on the each thumb and fingers is 276.5 N.
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Qno6: Two singers are singing simultaneouldy with intensity level of 60 db of each in a hall.
a.is intensity of sound in the hall is doubled?
b.is the intensity level of the sound is doubled
The intensity of sound in each hall will not be doubled.
The intensity of sound may be defined as, the power carried by sound waves per unit area in a direction perpendicular to that area. The intensity of sound is measured in decibel i.e. the unit is written as (dB).
It can be formulated as ,
I = pv
Where, I is the intensity of the sound, p is the pressure of sound, v is the velocity of the particle. And here, I and v are vectors, therefore they both have a magnitude and a direction. The average direction of energy flow is represented by the direction of sound intensity.
Therefore, due to the fact that our hearing is not linear and dB is a logarithmic scale, even though the energy may have doubled, the perceived intensity has not. In actuality, one of the singers' voices may both hide the other's and have the potential to improve it.
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A 12100 kg railroad car is coasting on a level, frictionless track at a speed of 19. 0 m/s when a 4790 kg load is dropped onto it. If the load is initially at rest, find the new speed of the car and the % change of the kinetic energy.
The speed of the car when the load is dropped in it is 10.90 m/s.
Using the data given above:
Mass of the railroad car, m₁ = 12100kg
Mass of the load, m₂ = 4790kg
It can be assumed as the speed of the car, u₁ = 10 m/s
So, it is at rest, u₂ = 0
Here we assume the speed of the car be v
Using law of conservation of energy
Thus:
m1v1 + m2v2 = (m1v1)/ (m1 + m2)
= 12100*10 / 12100 + 4790
121000/16890
= 7.16 m/s
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Imagine that you are comparing three different ways of having a ball move down through the same height. In which case does the ball reach the bottom with the highest speed?.
When we are comparing three different ways of having a ball move down through the same height, dropping the ball reaches the bottom with the highest speed.
What happens when you drop a ball?Gravity drags the ball down and increases its speed as you drop it. At the instant of impact, it squashes when it meets the ground. The floor presses against the squished ball as it returns to its former shape, and the floor pushes back in response. The ball is sent back into the air by the force of the floor pushing on it.Where does the energy leave after you drop a ball?If you drop the basketball, gravity will draw it down, converting its potential energy to kinetic energy as it does so. The ball's potential energy drops as it approaches the ground. But, the ball also accelerates up, thus its kinetic energy increases.To learn more about dropping a ball visit:
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A cyclist with a mass of 55 kg coasts on level ground at 32,25 m·s -1 . He free wheels up an incline of 30° to the horizontal and grabs an overhanging tree branch. What is the velocity of the cyclist when he grabs the branch?
The velocity of the cyclist when he grabs the branch is 36.1 m/s.
What is the final velocity of the cyclist?The final velocity of the cyclist is calculated as follows;
The final vertical velocity of the cyclist will be smaller than the initial vertical velocity due to opposing force of gravity.
Final vertical velocity of the cyclist, Vy = vi - vi sinθ
Vy = 32.25 - 32.25 sin(30)
Vy = 16.13 m/s
The final horizontal velocity will be constant.
Vx(final) = Vx(initial)
Vx = 32.25 m/s
Resultant final velocity = √Vx² + Vy²
Resultant final velocity = √(32.25² + 16.13²)
Resultant final velocity = 36.1 m/s
Thus, the final velocity of the cyclist will change when he grabs the overhanging tree branch.
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What's the Normal Force in Newtons for a 2,899 kg Warthog that Master Chief is driving while fighting off a horde of angry aliens? Assume the Halo installation the vehicle is on has an acceleration due to gravity of 10 m/s squared
(or same as Earth).
Answer:
-28990N
Explanation:
F = mass * acceleration = 2899kg * 10m/s^2 = -28990N (because it is a normal force applying pressure upward).
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3. The diagram shows a child's mobile which is supported from the ceiling by a length of nylon thread of negligible weight. AB is a uniform horizontal rod supported at S.
c) A third fish of weight 0.30 N is suspended from the middle of the rod. The thread supporting the mobile is moved along the rod so that the rod remains horizontal. On which side of the center of the rod is the thread now attached, left or right? Explain how you arrived at your answer.
Answer:
.12 * .12 = .0144 counterclockwise torque
.06 * .18 + W * .03 = .0108 + .03 W clockwise torque
W = (.0144 - .0108) / .03 = .12 N as requested
(.12 + .06 + .12) N = .30 N total weight supported by thread
C) Suppose now rod supported at middle
.12 * .15 = .018 N counterclockwise torque
.06 * .15 = .009 N clockwise torque
Obviously the thread must be moved closer (left) to .12 weight to increase the clockwise torque (other weights are in the middle of the rod
Consider the following system, where F = 120 N, m = 1 kg, and M = 5 kg. What is the magnitude of the force with which one block acts on the other?
Consider the following system, where F = 120 N, m = 1 kg, and M = 5 kg. Force exerted by the lighter block on the heavier block is F_2=20N
What is the magnitude of the force?F = 120N
m = 1kg
M = 5kg
Generally, the equation for acceleration is mathematically given as
[tex]a=\frac{F}{m+M} \\\\a=\frac{120}{1+5} \\[/tex]
a=20m/s^2
Let's formulate the heavier block's equation of motion.
F_1=F-F_2
Ma=F-F_2
It is estimated that the lighter block will exert the following force on the heavier block:
[tex]&F_2=\mathrm{F}-\mathrm{Ma} \\&F_2=120-(5 *20) \\[/tex]
F_2=20N
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block starts at the bottom of a ramp making an angle of θ with the horizontal, at initial speed v0 . as it slides up it slows due to gravity and kinetic friction, eventually coming to a stop. static friction is not large enough to hold it at res
The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort. Use Newton's second law to determine the friction force on the block.
The work-kinetic energy theorem can be used to provide a solution to this issue. Start by calculating how far the block will travel up the ramp. The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort.
You can use a free body diagram and Newton's second law to calculate the frictional force on the block. The frictional energy is calculated as the frictional force multiplied by the distance the block travels up the ramp.
The distance climbed up the ramp will also affect how much the gravitational potential energy changes. You can now generate kinetic energy.
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if you have not already done so, convert 70 mmhg and 120 mmhg into si pressure units. now that your pressures are in si units, critically think about your original claim regarding the heart’s blood pressure as either gauge pressure or absolute pressure. how does this pressure compare to atmospheric pressure? justify your reasoning regarding gauge pressure vs. absolute pressure in terms of how the body pressure compares to atmospheric pressure, which is also a pressure that is being (nearly) uniformly externed on the body at all times.
70 mmHg will convert to 9.333kpa pressure SI units while 20 mmHg will convert to 16kpa pressure SI units.
Absolute pressure for 70 mmHg is 110.658kpa
Absolute pressure for 120 mmHg is 117.325kpa
Converting 70 mmHg and 120 mmHg into SI pressure units:
If 760 mmHg=101.325kpa
∴ 70 mmHg=?
= 70*101.325/760
=9.333kpa
So 70 mmHg will be 9.333kpa
If 760 mmHg=101.325kpa
∴120 mmHg=?
=120*101.325/760
=16kpa
So 120 mmHg will be 16kpa
Blood pressure is generally measured in mmHg because mercury is used in the thermometers, so it is convenient to measure the pressure by rise in height of mercury in the thermometer.
However pressure measured by the thermometer is always gauge pressure, given by:
[tex]P_{gauge} =P_{abs} -P_{0}[/tex], where [tex]P_{0}[/tex] is atmospheric pressure and [tex]P_{abs}[/tex] is absolute pressure.
We now calculate absolute pressure for [tex]P_{1}[/tex] 70 mmHg and [tex]P_{2}[/tex] 120 mmHg,
[tex]P_{1} abs=P_{1} g+P_{0}[/tex]
[tex]=101.325+9.333[/tex]
=110.658kpa
[tex]P_{2} abs=P_{2} g+P_{0[/tex]
=101.325+16
=117.325kpa
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Which two wave features are specific to longitudinal waves?
There are four aspects of waves that only pertain to specific types of waves. Peaks and troughs are used to describe transverse waves. Compressions and rarefactions are used to describe longitudinal waves. Medium, wavelength, amplitude, and frequency are the four qualities that both types of waves have in common.
What are a longitudinal wave's two parts?In addition to longitudinal waves, which also move in the direction of the medium, there is another type of wave that does so: the transverse wave. While longitudinal waves are made up of compressions and rarefactions, transverse waves are made up of crests and troughs.
What features do longitudinal waves possess?In longitudinal waves, localized compression and rarefaction are observed. Compressions are regions of extremely high pressure because of the near proximity of the particles. Rarefactions are regions of low pressure because to the particles' enhanced dispersion.
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A weightlifter lifts a 200 Kg barbell 4m using 800W of power. How long did this take?
Answer:
9.8 seconds
Explanation:
Power = work / time
work = F * d = 200kg ( 9.81 m/s^2 ) * 4 m = 7818 J
800 W = 7818 J / t t = ~ 9.8 seconds