An account is gaining value rate of 4.94 per year. The account held $113 in 2005 which statement is "false"

A. The account had 124.44 in 2007.

B. The account gained more money from 2013-2015 than it did 2005-2007.

C. The account gains $5.72 every year.

D. This relationship is an example of exponential growth.

Answer:

y= 6.95+0.95t

Step-by-step explanation:

Given data

The price p of a pizza is $6.95

plus $0.95 per topping

let the number of toppings be  t

and let the total cost be y

Hence for any number of topping t the cost function is

[tex]y= 6.95+0.95t[/tex]

The function rule for the prize of a pizza is

[tex]P=0.95t +6.95[/tex]

Given :

The price p of a pizza is $6.95 plus $0.95 per topping t on the pizza

Initial price of the pizza is 6.95

The cost of each topping is 0.95 .

Let 't' be the number of toppings on the pizza

Price of  a pizza = initial cost of pizza + cost per pizza ( number of toppings)

[tex]p=6.95 +0.95(t)\\P=0.95t +6.95[/tex]

The function rule for the prize of a pizza is

[tex]P=0.95t +6.95[/tex]

Learn more  : brainly.com/question/5747203

Answer:

Step-by-step explanation:

x° + y° = 180°        {suplementary angles}

x° = 3y°               {corresponding angles by parallel lines}

So:

3y° + y° = 180°

4y° = 180°

y° = 45°

y = 45

x° = 3×45° = 135°

x = 135

Answer:

20+35x=40+25x, 35x- 25x=40-20, 10x=20, x=2 , 2 sessions

Answer:

if you meant to simplify here you go

Step-by-step explanation:

0.2(3b - 15c)=

0.2(3b)+0.2(−15c)=

0.6b−3c

Answer:

0.6b-3c

Explination:

0.2(3b - 15c)

we can use dispributive property because of the parentheses

by distributing 0.2 to 3b and -15c

we get 0.6b and -3c

you could be thinking why did the numbers shrink?

the numbers decrease because every time you multiply by a decimal the number decreases

High Hopes  

                          Barry-

Answer:

The cost of a combo meal is $8 and a salad is $4.

Step-by-step explanation:

You have to form simultaneous equations with the given informations. Let combo meal be m and salad is s :

[tex]m + s = 12 - - - (1)[/tex]

[tex]2m + s = 20 - - - (2)[/tex]

Next, you have to solve these equations :

[tex](2) - (1)[/tex]

[tex]2m + s - m - s = 20 - 12[/tex]

[tex]m = 8[/tex]

[tex]sub \: \: m = 8 \: \: into \: \: (1)[/tex]

[tex](1)⇒[/tex]

[tex]8 + s = 12[/tex]

[tex]s = 4[/tex]

Answer: 8$,4$

Step-by-step explanation:

Answer:

5 and 8

Step-by-step explanation:

quadratic formula.

-(b)+sqrt(b)^2-4(a)(c)

^ans

divide the whole thing by 2(a).

If the formula isn't clear, search quadratic formula up.

Answer:

[tex]\frac{1}{2}[/tex]

Step-by-step explanation:

The equation of a line in point- slope form is

y = mx + c ( m is the slope ( gradient ), c is the y- intercept )

y = [tex]\frac{1}{2}[/tex] x ← is in point- slope firm

with gradient = [tex]\frac{1}{2}[/tex]

Answer:

I believe the answer is 4. Please correct me if I’m wrong.

Step-by-step explanation:

================================================

Work Shown:

A = old velocity = 2 m/s

B = new velocity = 10 m/s

C = change in time = 5 seconds

D = average acceleration

D = (change in velocity)/(change in time)

D = (B-A)/C

D = (10-2)/5

D = 8/5

D = 1.6 m/s^2

The acceleration 1.6 m/s^2 means that the velocity is increasing by 1.6 m/s for every second.

Answer:

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Step-by-step explanation:

Answer:

=−28

Step-by-step explanation:

Answer:

15 yards

Step-by-step explanation:

proportion:

2/5:6/X

2x=30

x=15

Answer:

2x+5+2x +3x=7x+5       2x +5+ 2x + 3x = 7x+5

Step-by-step explanation:

Answer:

2,325 grams !

Step-by-step explanation:

Answer:

x is equal to or greater than 38.

Step-by-step explanation:

use the equation 300+12x to find the amount of money in total dependent on x, the number of hours she worked.

Step-by-step explanation:

750-300= $450 left that needs to be save to meet her goal.

set an equation to equal 450 that includes the next part of the information given which is $12 and hour

450=12x

isolate x by dividing 12 to both sides

x= 37.5 hrs

the inequality could be :

750<_ 300+ 12x

Answer:

y = n - 0.26n

y = 0.74n

Step-by-step explanation:

The equation that can be used to express the function above is given an Exponential Decrease function

Where:

y = a(1 - r)^t

Where

y = July sales

a = n = June sales

r = rate of decrease = 26% = 0.26

t = time in months = June to July = 1 month

t = 1

Hence, our equation =

y = n( 1 - 0.26)¹

y = n(1 - 0.26)

y = n - 0.26n

y = 0.74n

The equation that can be used to determine the sales in July is given as:

y = n - 0.26n

y = 0.74n

Answer: 2

Step-by-step explanation:

Answer:

y = -2x + 2

Step-by-step explanation:

Answer:

n4ur84234r

Step-by-step explanation:

3874rfbh dc

Answer:

121

Step-by-step explanation:

96+25=121

Answer:

121

Step-by-step explanation:

(91+5) + (31-6) = ?

The first step is to solve what's in the parenthesis.

91 + 5 = 96

31 - 6 = 25

(96) + (25) =

96 + 25 = 121

(91+5) + (31-6) = 121

Therefore, the correct answer is 121.

Hope this helps :)

Answer:

The value of home when bought was $913,780.

Step-by-step explanation:

Given that:

Current worth of the house = $1,553,426

This is 70% more than the original worth of the house.

Let,

100 be the original percent and x be the original worth

Percent increase = (100+70)% = 170%

170% of x = $1,553,426

[tex]\frac{170}{100}x=1553426[/tex]

1.7x = 1553426

Dividing both sides by 1.7

[tex]\frac{1.7x}{1.7}=\frac{1553426}{1.7}\\x= 913780[/tex]

Hence,

The value of home when bought was $913,780.

Answer:

m=-1

Step-by-step explanation:

8m + 34 = 10 - 16m

fist add 16m to each side

8m+16m+34=10

then subtract 34 from each side

8m+16m=10-34

add like terms

24m=-24

divide both sides by 24

m=-1

Answer:

A.) 3/4

Step-by-step explanation:

You can find this by dividing the distance from point Z to point Y by the distance of point X to point Y. The distance from Z to Y is 6 and the distance from X to Y is 8, so that means that the slope is 6/8, which simplifies to 3/4.

9514 1404 393

Answer:

  solve for f(n) in terms of f(n-1)

Step-by-step explanation:

In general, you solve for f(n) in terms of f(n-k) for k = 1, 2, 3, ....

__

Usually, such questions arise in the context of arithmetic or geometric sequences.

Arithmetic sequence

The explicit formula for an arithmetic sequence has the general form ...

  a(n) = a(1) +d(n -1) . . . . . . . first term a(1); common difference d

The recursive formula for the same arithmetic sequence will look like ...

  a(1) = a(1) . . . . . . . the first term is the first term

  a(n) = a(n-1) +d . . . the successive terms are found by adding the common difference to the term before

__

Note: The explicit formula may be given as the linear equation a(n) = dn +b. Then the first term is a(1) = d+b.

__

Geometric sequence

The explicit formula of a geometric sequence has the general form ...

  a(n) = a(1)·r^(n -1) . . . . . . first term a(1); common ratio r

The recursive formula for the same geometric sequence will be ...

  a(1) = a(1) . . . . . . the first term is the first term

  a(n) = a(n-1)·r . . . the successive terms are found by multiplying the term before by the common ratio

__

Note: The explicit formula may be given as the exponential equation a(n) = k·r^n. Then the first term is a(1) = kr.

__

Other sequences

Suppose you're given the quadratic sequence ...

  a(n) = pn^2 +qn +r

Since the sequence is known to be quadratic (polynomial degree 2), we expect that we will only need the two previous terms a(n-1) and a(n-2). Effectively, we want to solve ...

  a(n) = c·a(n-1) +d·a(n-2) +e

for the values c, d, and e. Doing that, we find ...

  (c, d, e) = (2, -1, 2p)

So, the recursive relation is ...

  a(1) = p +q +r

  a(2) = 4p +2q +r

  a(n) = 2a(n-1) -a(n-2) +2p

__

Additional comment

The basic idea is to write the expression for a(n) in terms of terms a(n-1), a(n-2) and so on. That will be easier for polynomial sequences than for sequences of arbitrary form.

There are some known translations between explicit and recursive formulas for different kinds of sequences, as we have shown above. If you recognize the sequence you have as being of a form with a known translation, then you would make use of that known translation. (For example, Fibonacci-like sequences are originally defined as recursive, but have explicit formulas of a somewhat complicated nature. If you recognize the form, translation from the explicit formula may be easy. If you must derive the recursive relation from the explicit formula, you may be in for a lot of work.)