Answer:
1.5×10⁷ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength of radio wave (λ) = 20 m
Frequency (f) =?
Frequency and wavelength of a wave are related by the following equation:
v = λf
Where:
'v' is the velocity of electromagnetic wave.
'λ' is the wavelength
'f' is the frequency.
With the above formula, we can obtain the frequency of the radio wave as illustrated below:
Wavelength of radio wave (λ) = 20 m
Velocity (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 20 × f
Divide both side by 20
f = 3×10⁸ / 20
f = 1.5×10⁷ Hz
Thus the frequency of the radio wave is 1.5×10⁷ Hz
How many grams of iron are needed to produce 3 g of iron(III) chloride?
Answer:
5 its just what i do
Explanation:
What procedure did you use to complete the exploring cells lab?
Outline the steps of the procedure in full sentences.
33 POINTS PLS ANSWER USE SCIENTIFIC NOTATION TO SOLVE
Imformation you find on the periodic table
Answer:
Within each element square, information on the element's symbol, atomic number, atomic mass, electronegativity, electron configuration, and valence numbers can be found. At the bottom of the periodic table is a two row block of elements that contain the lanthanoids and actinides.
Explanation:
Describe the factors that affect the force of gravity
Answer:
gravity
Explanation:
gravity
Which choice has prokaryotic cells?
human blood
onion root
cow's liver
E. coli
How is drip irrigation better than canal irrigation?
Explain as well
unlike a sprinkler system that will Splash water all over the foliage of your plants a drip irrigation system will apply to water the plants where can easily be taken in by their roots
A1(OH)3 + HNO3–> H2O + A1(NO3)3
when the equation above is correctly balanced the coefficient of H2O is
A:1
B:2
C:3
D:8
Answer:
3
Explanation:
The reaction expression is given as:
Al(OH)₃ + HNO₃ → H₂O + Al(NO₃)₃
To solve this problem, let us assign coefficient a,b,c and d to each specie;
aAl(OH)₃ + bHNO₃ → cH₂O + dAl(NO₃)₃
Conserving Al : a = d
O: 3a + 3b = c + 9d
H: 3a + b = 2c
N: b = 3d
let a = 1 , d = 1, b = 3 , c = 3
Multiply through by 3;
a = 1, b = 3, c = 3 and d = 1
Al(OH)₃ + 3HNO₃ → 3H₂O + Al(NO₃)₃
What is ATP? How does it provide energy
In the following acid-base the reaction HCI is
A. Acid
B. Conjugate acid
C. Conjugate base
HCl(g) + H2O(l) →H30+(aq) + Cl-(aq)
What is the mass of .89 moles of lithium metal, used in laptop batteries?
The mass of lithium metal that is used in lithium batteries is 6.17 grams, this can be calculated by using number of moles formula.
Number of moles:It is defined as the ratio between mass and molar mass.
It is given by:
Number of moles = mass / Molar mass
What information do we have?
Number of moles= 0.89 moles
Molar mass of Lithium metal= 6.941 g/mol
To find:
Mass of Lithium metal=?
On substituting the values
n= m/M
0.89 = m/ 6.941
m= 0.89*6.941
m= 6.177 grams
Thus, the mass of lithium metal is 6.177 grams.
Find more information about Number of moles here:
brainly.com/question/13314627
ammonium phosphate is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 2.4 mol of ammonia. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.
Answer:
0.57 moles (NH4)3PO4 (2 sig. figs.)
Explanation:
To quote, J.R.
"Note: liquid ammonia (NH3) is actually aqueous ammonium hydroxide (NH4OH) because NH3 + H2O -> NH4OH.
H3PO4(aq) + 3NH4OH(aq) ==> (NH4)3PO4 + 3H2O
Assuming that H3PO4 is not limiting, i.e. it is present in excess
1.7 mol NH4OH x 1 mole (NH4)3PO4/3 moles NH4OH = 0.567 moles = 0.57 moles (NH4)3PO4 (2 sig. figs.)"
The density of mercury is 13.6 g/cm'. How many quarts does 83.0 g of Hg occupy? (1 L=1.06 qt)
Answer:
0.0064 qt
Explanation:
Given data:
Density of mercury = 13.6 g/cm³
Mass of mercury = 83.0 g
How many quarts mercury have = ?
Solution:
First of all we will calculate the volume in cm³.
d = m/v
13.6 g/cm³ = 83.0 g / volume
Volume = 83.0 g / 13.6 g/cm³
Volume = 6.1 cm³
cm³ to L:
6.1 cm³ × 1 L / 1000 cm³
0.0061 L
In quarts:
1 L = 1.06 qt
0.0061 L × 1.06 qt / 1 L
0.0064 qt
How many moles are in 56.4 grams of AlF3
Answer: 0.671614483912211
Explanation: A mole is 6.02214076×1023 (also known as the Avogadro number) I hope this helps!
Express 4,935,000 using standard scientific notation
Answer:
4.935×10-1
Explanation:
Take away the 0
The table below shows properties of two compounds at standard pressure. Which statement classifies the two compounds? 1)Both compounds are ionic, 2)Both compounds are molecular, 3) Compound 1 is ionic, and compound 2 is molecular, 4)Compound 1 is molecular, and compound is ionic
Answer:
answer of this question is option. 3. compound 1 is ionic ,and 2 is molecular
Compound 1 is ionic and compound 2 is molecular. The correct option is 3) Compound 1 is ionic, and compound 2 is molecular
From the question,
We are to classify the compounds according to the information provided in the table
First,
We will list the properties of ionic and molecular compounds
Properties of ionic compounds
The exist as solid at room temperature. They generally have high melting and boiling temperatures. They are good electrical conductors when molten or in solution.Properties of molecular compounds
They can exist as solid, liquid or gas.They generally have low melting and boiling temperatures. They are poor electrical conductors.In the given table,
Compound 1 has high melting and boiling points, and it is a good electrical conductor. Therefore, compound 1 is ionic
Compound 2 has low melting and boiling points, and it is a poor electrical conductor. Therefore, compound 2 is molecular
Hence, Compound 1 is ionic and compound 2 is molecular. The correct option is 3) Compound 1 is ionic, and compound 2 is molecular
Learn more on properties of ionic and molecular compounds here: https://brainly.com/question/13878434
PLZ HELP BEING TIMED!!! PLZ ANSWER!!!!
Answer:its going to be a
Explanation:
Answer:
it will option A bcs motion increases when temp increases
4.96 megameters to inches show work
what three things might influence a slide when conditions are right?
Answer:
3
Explanation:
The three things that can affect a condition to enforce a slide is friction, weight, and slope of an area. Solutions that can make flow easily are those that can create less friction depending on the condition of an environment where it is present.
PLZ HELP BEING TIMED!!!!!PLZ ANSWER!!!!
Answer:
1st one
Explanation:
Use your periodic table to determine which of the following is a non metal
A.Nitrogen
B. Lithium
C. Sodium
D. Gold
Science can best be described as
Watch the animation and identify the correct conditions for forming a hydrogen bond.
A. A hydrogen bond is equivalent to a covalent bond.
B. A hydrogen bond is possible with only certain hydrogen-containing compounds.
C. Hydrogen bonding occurs when a hydrogen atom is covalently bonded to an N , O, or F atom.
D. The CH4 molecule exhibits hydrogen bonding.
E. A hydrogen atom acquires a partial positive charge when it is covalently bonded to an F atom.
Answer:
options B,C and E are correct conditions for forming hydrogen bonds.
Explanation:
In order for particles to stick together or shows certain characteristics, there must be a bond of attractions that is making them to be able to stay together. Some of these attractions are strong while some are weak. The kind of attraction that is being considered in this question is the hydrogen bonding which is considered as part of the weak forces of attractions.
In order for hydrogen bonds to occur, there must be hydrogen atoms [option B is correct] and a much more electronegative elements such as oxygen, Fluorine and Nitrogen. Hence, option C is correct.
Since the Fluorine or oxygen or nitrogen have much more electronegative properties than hydrogen, it causes a partial negative charge on Fluorine or oxygen or nitrogen and a partial positive charge on the Hydrogen. Thus, option E is correct.
fluorine is more reactive than chlorine.
Answer:
yes because of fluorine has higher electronegativity
Annual precipitation rates can be collected for several years added together and divided by the number of years to obtain an average annual precipitation rate. True or false
Answer:
true
Explanation:
What happens when uranium-238 absorbs a neutron?
A. It is converted into large amounts of energy.
.
B. It becomes plutonium-239.
O
C. It becomes plutonium-238.
D. It becomes uranium-235.
Answer:
B. It becomes plutonium-239.
Explanation:
When uranium - 238 absorbs a neutron, it creates and becomes plutonium - 239 atom.
This is a nuclear fission process in which a radioactive nucleus is bombarded with a neutron:
²³⁸₉₂U + ¹₀n → ²³⁹₉₂Pu
The plutonium produced is not stable and it immediately disintegrates further.
Answer:
B.) It becomes plutonium-239
Explanation:
I got it correct on founders edtell
How many moles of ethane gas, C2H6(g), will occupy 15.0 L at 30 degrees Celsius and 5.0 atm?
Answer:
3 mol
Explanation:
Given data:
Volume of ethane = 15.0 L
Temperature = 30°C
Pressure = 5.0 atm
Number of moles of ethane = ?
Solution:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
30+273 = 303 K
5.0 atm × 15.0 L = n×0.0821 atm.L/ mol.K × 303 K
75 atm.L = n× 24.87 atm.L/ mol
n = 75 atm.L / 24.87 atm.L/ mol
n = 3 mol
If phosphofructokinase experienced a mutation that interfered with substrate binding, then what other enzyme is going to be most immediately impacted in terms of accessing substrate?
A. aldolase
B. fumarase
C. glucolactonase
D. hexokinase
Answer: A. aldolase
Explanation:
Phosphofructokinase, is an enzyme which is vital in the regulation of fermentation. It is involved in the glycolysis process.
When it experiences a mutation that was being interfered with the substrate binding, we should note that the enzyme that is going to be most immediately impacted in terms of accessing substrate is aldolase.
an atom has atomic number 17, in which group and in which period is this atom located?
Explanation:
period =3
Group=7
it is cl2
Answer:
Group 7 - Period 3
Explanation:
A 10.0 g sample of water was heated from 20.0°C to 50.0°C. How much energy did the water gain? The specific heat of water is 4.18 J/g·°C.
a.836 J
b.1250 J
c.2920 J
d.4180 J
Answer:
im pretty sure c
Explanation: