After being pushed away from the departure gate, an aircraft is standing still with the brakes applied and the engine running on very low. When the pilot releases the brakes he finds that the plane still does not start to move. Here are three explanations for why the plane does not move. Which one do you agree with?

The eletric field on a capacitor is given by the following formula:

Where Q is the difference of charge between plates, A is the area, and e0 is a constant. It can also be written as the second formula, where V is the voltage, and d is the distance between plates.

When we use the second formula, with the values from the exercise, we get:

Thus, our final answer is E=46383.886 V/m

The net force acting on the box is 15 N. The force acting on a box is unbalanced because the force on one side is 7 N while the force on other side is 8 N.

Force is defined as a push or pull exerted on an object as a result of the interaction of the object with another object.

It can also be defined as a factor that can alter how an object moves.

Net force is defined as the force that is the result of all forces concurrently acting on an object.

It can also be defined as all of the forces acting on an object are added together into a vector.

Net force = F1 + F2 + F3

               = 7N + 4N + 4N

              = 15 N

Thus, the net force acting on the box is 15 N. The force acting on a box is unbalanced because the force on one side is 7 N while the force on other side is 8 N.

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We are given the displacement, velocity, and acceleration of a particle that describes Simple Harmonic Motion. We are asked to determine the maximum velocity of the particle. To do that we can use the following equation for the maximum velocity of a particle describing SHM:

Where:

To determine the values of amplitude and angular frequency we can use the expressions for displacement, velocity, and acceleration. The expression for displacement is:

The expression for the velocity is:

And the expression for acceleration is:

Now, from the expression for the displacement we can solve for the amplitude, like this:

Now we can replace this in the expression got eh acceleration:

Simplifying:

Now we can solve for the angular frequency:

Taking square root to both sides:

replacing the values:

Solving the operations:

Now we divide the formula for the displacement and the formula for the velocity, we get:

Simplifying we get:

Replacing the known values:

Simplifying:

Solving for "t":

Now we can replace these values in the formula for displacement to get the value of the amplitude:

Solving for the amplitude:

Replacing the known values:

Solving the operations:

Now we replace the values in the formula for the maximum velocity:

Replacing:

Therefore, the maximum velocity is 10.6 meters per second.

The average acceleration a of an object that changes its speed from v_0 to v_f during a time interval t is:

Since the car is initially moving at 25.0m/s and it stops in 3.00 seconds, then its final speed is 0m/s.

Replace v_f=0, v_0=25.0m/s and t=3.00s to find the average acceleration of the car:

Therefore, the average acceleration of the car when it stops from 25.0m/s in 3.00 seconds, is -8.33m/s^2.

Answer:

To the right

Explanation:

Metals are to the left, nonmetals are to the right. There's a border I drew that separates nonmetals and metals

Given data:

Mass of each block;

Acceleration;

The free-body diagram for A,

The free-body equation for A is given as,

The free-body diagram for B is given as,

The free-body equation for B is given as,

The free-body equation for C is given as,

The free-body equation for C is given as,

Equating equation (2) and (3),

Part (1),

The horizontal force on block A due to block B is given as,

Substituting all known values,

Therefore, the net horizontal force on block A due to block B is 28.8 N.

Part (2)

The net horizontal force on block B is given as,

Substituting all known values,

Therefore, the net horizontal force on block B is 14.4 N.

Part (3)

The horizontal force on block B due to block C is given as,

Substituting all known values,

Therefore, the horizontal force on block B due to block C is 14.4 N.

Given:

• Length = 24 m

• Temperature, T1 = 8°C

• Expansion coefficient = 11 x 10⁻⁶(°C)⁻¹

Let's solve for the following:

• (a). The increase in length of the rail when the temperature is 36 °C

To find the increase in length, apply the formula:

Where:

Lo = 24 m

α = 11 x 10⁻⁶(°C)⁻¹

T2 = 36 °C

T1 = 8°C

Thus, we have:

The increase in length is 0.0074 m.

• (b). Let's calculate the thermal stress.

To find the thermal stress, we have the formula:

Where:

Y is the young modulus = 20 x 10¹⁰ N/m

dL is the change in length = 0.0074 m

L is the length = 24 m

Input values in the formula and solve:

The thermal stress is 6.17 x 10⁷ N/m².

ANSWER:

• (a). 0.0074 m.

• (b). 6.17 x 10⁷ N/m²

Answer:

Explanation:

Given:

U = 590 V

I = 1.0 A

R₁ = 770 Ω

I* = 500 mA = 0.5 A

_________________

P - ?

A)

Power:

P = U·I = 590·1.0 = 590 W

B)

Сurrent:

I₁ = U / R ₁ = 590 / 770 = 0.770 A =  770 mA

C)

This current is life-threatening!!!

I₁ > I*     (700 mA > 500 mA)

D)

Energy received:

E = I₁²·R₁ = 0.770²· 770 ≈ 460 W

The force of friction on an inclined plane, will act upward to oppose the downward motion of the object on the inclined plane.

The force of friction is the force that opposes the motion of an object.

Since the force of friction opposes the motion of an object, it acts upward along the plane for an object moving along an inclined plane.

As the object moves downwards, the force of friction will act upwards to oppose the downward motion of the object.

Mathematically, the magnitude of force of friction on an object moving along inclined plane is given as;

Ff = μmg

where;

Thus, the force of friction on an inclined plane, will act upward to oppose the downward motion of the object on the inclined plane.

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The complete question is below:

For friction on an incline, what direction does force of friction (Fp) point?

The first thing an alien would notice about gravity on earth is how it affects their movement. If their planet is closer to the sun in their solar system, they'd be accustomed to a higher pull of gravity, hence weight. Based on the above, an alien will feel lighter on earth without auto-assistive gravity adjuster technology.

The simplest way to test gravity is by comparing my weight using "homemade" scales on the ship, then checking that against my weight off the ship.

The simplest way to describe Earth's gravity to those the home planet is to use scientific language. The acceleration of gravity at the Earth's surface is approximately 9.8 meters (32 feet) per second every second. This is constant.

Gravity, often known as gravitation, is a force that exists between all physical things in the universe. The force of gravity seeks to draw any two objects or particles with nonzero mass toward one other. Gravity affects things of all sizes, from subatomic particles to galaxy clusters.

Einstein proposed that the geometry of spacetime is what causes the force we call gravity. A mass (or energy) concentration, such as the Earth or sun, bends space around it in the same way as a boulder bends the flow of a river. As a result, gravity was created.

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Part 1

C. Its frequency remains the same.

Part 2

A. A wave's frequency always remains the same.

The relationship between wavelength, frequency, and speed is given as:

When the frequency of a wave increases, its wavelength also increases.

The speed of a wave does not change as its frequency changes, and vice-versa.

Therefore, as the speed of the wave decreases, its frequency remains the same

A wave's frequency always remains the same regardless of the speed and wavelength

The total mechanical energy of a spaceship will be E = - GMm/2(R+h)

which is moving in circular orbit  at height R above the surface of a planet of mass M and radius R . Here, m is the mass of spaceship and G is gravitational force.

Therefore, when the engine of spaceship of mass (m) is switch offed and moving in circular orbit of a planet at height R above the surface of a planet of mass M and radius R then the mechanical energy is given by

E = - GMm/2(R+h)

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The cannon ball will travel the highest distance when the angle of projection is 35 degrees.

The maximum height reached by a projectile is calculated using the following formula.

H = u²sin²θ/2g

where;

when the angle of projection is 25 degrees;

H = (15² (sin 25)²) / (2 x 9.8)

H = 2.05 m

when the angle of projection is 35 degrees;

H =  (15² (sin 35)²) / (2 x 9.8)

H = 3.78 m

Thus, the cannon ball will travel the highest distance when the angle of projection is 35 degrees.

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The given graph is about velocity and time, the dependent and independent variable, respectively. As we can observe, line E crosses the zero level to the negative zone, which means the object didn't stop but changed its direction.

Answer:

reflection

Explanation:

it is a regular reflaction of light

Answer and step by step explanation:

First of all, I'm assuming you have had calculus, or this is going to be very awkward. Then, I'm replacing w with the Greek letter omega, it's a pet peeve of mine, sorry.

Shockingly, the derivative of a vector is computed by taking the derivative of each component (by linearity). If you've never heard the word derivative yet, you can think of the x and y components as two harmonic motions out of phase by 90°, and the z component as having constant speed h (harmonic motion is what you see when a mass moves along a circle with constant angular velocity and you look at it from the side).

At this point, let's use the derivative method for question a:

[tex]v(t)=\dot{r}(t)=\left[\begin{array}{ccc}-\omega r\sin(\omega t)\\\omega r\ cos(\omega t)\\h\end{array}\right]; a(t)=\dot v(t)=\ddot{r}(t)=\left[\begin{array}{ccc}-\omega ^2r\cos(\omega t)\\-\omega ^2r\ sin(\omega t)\\0\end{array}\right]\\[/tex]

Point b requires computing angles, which screams dot product to me.

[tex]\vec v(t) \cdot \vec a(t) =\left[\begin{array}{ccc}-\omega r\sin(\omega t)\\\omega r\ cos(\omega t)\\h\end{array}\right]\cdot \left[\begin{array}{ccc}-\omega ^2r\cos(\omega t)\\-\omega ^2r\ sin(\omega t)\\0\end{array}\right] = + \omega^3r^2 sin (\omega t) cos (\omega t) -\omega^3r^2 cos (\omega t) sin (\omega t) = 0 = ||\vec v|| ||\vec a|| cos \theta \implies cos\theta = 0 \implies \theta=\frac \pi2[/tex]

Now, the implied part is granted by the fact that we are assuming neither the velocity nor the acceleration are both zero, so the only option is for the cosine being zero, that makes the two vector orthogonal.

Finally, for point c, let's just take the moduli of both velocity and acceleration [tex]||\vec v|| = \omega r; ||\vec a||=\omega^2 r[/tex] and let's convert the angular velocity in civiliz... err, IS units: [tex]40 rpm = 40\times \frac{2\pi}{60}rad/s = \frac 43 rad/s[/tex]

Let's replace and we get

[tex]v=\frac83= 2.6 m/s\\a= \frac{32}3 = 10.5 m/s^2[/tex]

Answer:

see below

Explanation:

F=ma

50 = 400 a

A = 50/400 = .125 m/s^2

Accel = change in v / change in t

      .125 =  (12-10) / t       Shows t = 16 seconds

Ecology is the study of the way all living things relate to each other in the world.

This is referred to as the science which deals with the study of organisms and how they interact with their environment. It comprises of the study of the organisms present and their habitat.

Their habitat is the area where they live which comprises of many resources such as food, water etc which are needed for their growth and survival. The living things interact with it for beneficial reasons and is the reason why Ecology was chosen as the correct choice.

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Earth's tilted axis and revolution around the sun causes the seasons.

Different parts of Earth receive the Sun's direct rays, throughout the year. So,  it's summer in the Northern Hemisphere when the North Pole tilts toward the Sun. It's winter in the Northern Hemisphere when south Pole tilts toward the Sun.

As we know that the Earth rotates with a constant speed, so that every hour the direct beam will traverse across a single standard meridian. Rotation of Earth 15 degrees is equivalent to unit of one hour . When Earth rotates in such a way  that the beam of the sun shifts +1∘ of longitude from East to West and time taken is 4 minutes.

The tilt of the Earth's axis is important because it governs the strength of warming of the sun's energy. The tilt of the surface of the Earth also causes light to be spread across a larger area of land which is termed as called the cosine projection effect.

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The temperature of the gas (in °C) at this pressure is 248.5 °C

Temperature is a bodily quantity that expresses the hotness of count or radiation. There are 3 kinds of temperature scales. Temperature is the degree of hotness or coldness of an item.

Temperature is a degree of the common kinetic energy of the debris in an object. whilst the temperature increases, the motion of those particles also increases. Temperature is measured with a thermometer or calorimeter.

Given;

P₁ = 1.2 x10⁵ Pa = 1.18430792

T₁ = 25.0°C = 298 K

P₂ = 2.1x10 Pa = 0.000207253886

T₂ = ?

using ideal gas equaion:-

PV = nRT

P₁/T₁ = P₂/T₂

T₂ = P₂T₁  /P₁

   = 2.1x10⁵ x  298 / 1.2 x10⁵

   = 521.5 K

   = 248.5 °C

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Answer:

Chromatography is a process for separating components of a mixture. To get the process started, the mixture is dissolved in a substance called the mobile phase, which carries it through a second substance called the stationary phase.

Explanation:

hope it will be helpful

Answer:

Chromatography is a process for separating components of a mixture.

Explanation:

To get the process started, the mixture is dissolved in a substance called the mobile phase, which carries it through a second substance called the stationary phase.

Have a good day!

The time taken by the projectile to reach the highest point would be one half of the total time of the projectile , therefore the correct answer is option D .

It is the motion of any object or body when it is ejected off the surface of the earth and follows any curving path while being affected by the gravitational pull of the planet .

As given in the problem Set the cannon to have an initial speed of 25 m / s at an angle of 30 degrees .

Thus, the right response is option D because it would take the projectile half as long to reach the highest position.

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As the horizontal component of the velocity is constant throughout the projectile, the time of the flight of the projectile is independent of the horizontal velocity, therefore the correct answer is option E .

It is the motion of any object or body when it is ejected off the surface of the earth and follows any curving path while being affected by the gravitational pull of the planet .

The total time of the flight of the projectile = 2uSinθ / g

Thus , the time of the flight of the projectile is independent of the horizontal velocity, therefore the correct answer is option E.

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Given data

*The given mass of the solid cylinder is m = 0.274 kg

*The given radius of the cylinder is r = 2.00 cm = 0.02 m

*The given speed is v = 5.00 cm/s = 0.05 m/s

The formula for the total kinetic energy is given as

*Here U_K is the translation kinetic energy

*Here U_R is the rotational kinetic energy

*Here 'I' is the moment of inertia of the solid cylinder

Substitute the known values in the above expression as

Hence, the total kinetic energy is U_T = 5.13 × 10^-1 mJ

Answer:

Explanation:

A scientist adds different amounts of salt to 5 bottles of water. She then measures how long it takes for the water to boil. What is the responding variable in this experiment? A. The time it takes for the water to boil B. The amount of salt added to the water C. The kind of bottles used D. The brand of salt used

From conservation of momentum we have that:

Solving for v we have that:

Therefore the velocity of the ball after the collision is 28.33 m/s

The speed of the block when it has moved a distance of 0.0200 m from its initial position is 0.29 m/s.

The mass of the block is 2.55 Kg. Coefficient of kinetic friction is 0.45. Spring constant is 870N/m. The final compression of the spring is 0.0160 meters. The block is moved by distance of 0.0200 meters.

By considering the block-spring system, we can use Work energy theorem here,

According to work energy theorem,

Work done by conservative forces on the body + Work done by none conservative forces = Total change in kinetic energy of the body.

Work done by Conservative forces = 1/2Kx².

Where,

K is spring constant,

x is the compression in spring,

Work done by non-conservative forces = umgd

Where,

u is the coefficient of kinetic friction,

m is mass of the block,

d is the distance by which the block moves,

Here, we will take spring force as positive because the spring force and displacement both are in same direction,

Putting all the values,

1/2Kx² - umgd = 1/2mV² - 1/2mU²

1/2(870)(0.016)² - 0.45(2.55)(9.8)(0.02) = 1/2(2.55)V²

0.11136 - 0.22491= (1.275)V²

0.11355/1.275 = V²

V = 0.29 m/s.

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Inside the nucleus, two protons are held together by a strong nuclear force which overcomes the repulsion. This is sometimes referred to as strong interaction.

The strong nuclear force or the strong interaction is strong enough to overcome the repulsive force between the two positively charged protons and thereby allowing protons and neutrons to stick together even in a small space. Protons are held together by the strong attractive nuclear force that binds together protons and neutrons.

The strong force is one of the four fundamental forces of nature that include  gravity, electromagnetism, and the weak nuclear force. The strong force holds protons and neutrons within the nucleus of the atom and thus creating densest environments in nature.

The strong force dies off  very fast with distance more than gravity or the electromagnetic force. It's difficult to detect the strong force outside of a nucleus.

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In the given question projectile is fired horizontally at an angle of 70° with the speed of 0.11km/s ,(=110m/s).

to find the range and height

height=544.66m

time= 10.54 second

range=793.63m

vy=0

h=v^2sin^2θ/ 2g

v=0.11km/s  =110m/s

θ=70°

range=v^2sin2θ/ g

horizontal velocity,

vx= 110cos70=37.622 m/s

vertical velocity,

vy=110sin70=103.36 m/s

using the equation of motion

s=ut+1/2 at^2

range, s=0, t=total time taken

range= 110^2 sin 2*70/9.8

range=793.63m

t= vsinθ/ g

=110 sin 70/9.8

time= 10.54 second

s=(110sin 70)*10.54 +1/2(-9.8)* (10.54^2)

s=1089-544.34

height=544.66m

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