A4. Lead oxides are environmental pollutants. (a) Name the source of these pollutants. (b) What is the major adverse effect on humans?. (c) State the measures that have been put in place in order to avoid this kind of pollution..... (d) (1) Explain the meaning of the term global warming. (ii) Name a pollutant which causes global warming.​

Answer:

d

Explanation:

2H₂(g) +CO(g) → CH₄O (l)

Since H₂ was reacted with excess CO, H₂ is the limiting reagent. This means that the amount of product formed is dependent on the amount, i.e. the number of moles, of H₂.

The number of moles of H₂ can be calculated by taking the mass divided by its Mr (relative molecular mass).

Mr of H₂= 2(1)= 2

Moles of H₂ (g)

= 6.12 ÷2

= 3.06 mol

From the balanced equation, 2 moles of H₂(g) produces 1 mole of CH₄O(g).

Since we have 3.06 moles of H₂(g),

Moles of CH₄O (l) produced

= 3.06 ÷2

= 1.53 mol

Mr of CH₄O

= 12 +4 +16

= 32

Mass= mole ×Mr

Mass of CH₄O (l) produced

= 1.53(32)

= 48.96 g

Thus, d would be the best option.

Answer:

4.27 L

Explanation:

STP = 0 C   and   1 atm  

P1V1/T1   = P2V2/T2       where T is in Kelvin

P1 V1 / T1   *T2/P2   = V2

.469 * 5 / ( 273.15-123)  *  273.15/1   = V2 = 4.27 L

Answer:

Empirical: NO2. Molecular: N2O4

Explanation:

In order to determine the empirical formula, we divide each element's mass by their respective molar mass:

N: 0.3955g/14.01 g/mol = 0.02823 mol

O: 0.904g/16.00 g/mol = 0.0565 mol

Next, we take the smallest value and multiply it till it is close enough to an integer:

0.02823 x 40 = 1.12 Close enough to 1.

0.0565 x 40 = 2.26. Close enough to 2.

Therefore, the Empirical Formula is: NO2

Next, we determine how much the Empirical formula weighs and see if it matches 92g/mol:

14.01 g/mol + 2(16.00 g/mol) = 46.01 g/mol

We can assume this is roughly half of 92 g/mol so we can multiply each subscript by 2 to match the weight.

Therefore, the Molecular formula is N2O4

Hope this helped!

Polar or ionic substances dissociate into ions when dissolved in water.

Ionic substances dissociate into ions when dissolved in water because water is also a polar by nature. We know that like dissolve like so polar substances dissolve in water and dissociate into ions i.e. positive an negative ions.

So we can conclude that polar or ionic substances dissociate into ions when dissolved in water.

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Answer:

The wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm (nanometer)

Define the wavelength of a photon.

Each photon has a wavelength and a frequency. The wavelength is defined as the distance between two peaks of the electric field with the same vector.

A photon is the smallest element of electromagnetic radiation. You can think of a photon as a packet of energy travelling at the speed of light. There is no constant wavelength of a photon, it is dependent on how much energy the photon carries.

The mathematical relationship can be written as

E=hc/ λ

In terms of wavelength,

λ=hc/E

- h is planks constant

- c is the speed of light

- E is the energy of the photon

Where h = 6.626×10⁻³⁴ J⋅s is Planck’s constant and c = 3×10⁸ m/s is the speed of light.

If E = 4.56×10⁻¹⁹ J then λ = 463nm (nano meter)

Hence, the wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm(nanometer)

Hope its helpful!

Answer:

The wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm (nanometer)

Define the wavelength of a photon.

Each photon has a wavelength and a frequency. The wavelength is defined as the distance between two peaks of the electric field with the same vector.

A photon is the smallest element of electromagnetic radiation. You can think of a photon as a packet of energy travelling at the speed of light. There is no constant wavelength of a photon, it is dependent on how much energy the photon carries.

The mathematical relationship can be written as

E=hc/ λ

In terms of wavelength,

λ=hc/E

- h is planks constant

- c is the speed of light

- E is the energy of the photon

Where h = 6.626×10⁻³⁴ J⋅s is Planck’s constant and c = 3×10⁸ m/s is the speed of light.

If E = 4.56×10⁻¹⁹ J then λ = 463nm (nano meter)

Hence, the wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm(nanometer)

Answer:

is an assumption , in an idea that is proposed for the sake of argument so that it can be tested to see if it might be true.

아 이거 끝이 없어

Answer:

15.17 ml

Explanation:

4.8 % is .048 in decimal

316 ml  * .048 = 15.17 ml    ( about 1/2 ounce)

The molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

The molar mass of the gas is determined by applying Graham's law of diffusion.

R₁√M₁ = R₂√M₂

R₁/R₂ = √M₂/√M₁

R₁/R₂ = √(M₂/M₁)

where;

R₁/1.25R₁ = √(M₂/44)

1/1.25 =  √(M₂/44)

0.8 = √(M₂/44)

0.8² = M₂/44

M₂ = 0.8² x 44

M₂ = 28.16 g

Thus, the molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

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Answer:

1.) 2 Fe (s) + 3 Cl₂ (g) ---> 2 FeCl₃ (aq)

2.) 2.0 moles FeCl₃

3.) 0.67 moles FeCl₃

4.) 1.5 g FeCl₃

Explanation:

1.)

The unbalanced reaction:

Fe (s) + Cl₂ (g) ---> FeCl₃ (aq)

Reactants: 1 iron, 2 chlorine

Products: 1 iron, 3 chlorine

The balanced reaction:

2 Fe (s) + 3 Cl₂ (g) ---> 2 FeCl₃ (aq)

Reactants: 2 iron, 6 chlorine

Products: 2 iron, 6 chlorine

2.)

To find moles FeCl₃, you need to multiply the given value by the mole-to-mole ratio of Fe to FeCl₃. This ratio is constructed via the coefficients from the balanced equation.

2.0 moles Fe          2 moles FeCl₃
---------------------  x  ------------------------  = 2.0 moles FeCl₃
                                 2 moles Fe

3.)

To determine how much FeCl₃ is produced, you need to identify the limiting reagent. To find it, you need to convert both reactants to the product then identify which reactant gives you the smallest amount of product. This reactant is the limiting reagent and will give you your actual answer.

1.0 mole Fe         2 moles FeCl₃
-------------------  x  -----------------------  = 1.0 moles FeCl₃
                               2 moles Fe

1.0 mole Cl₂         2 moles FeCl₃
-------------------  x  ------------------------  = 0.67 moles FeCl₃
                              3 moles Cl₂

4.)

Because Cl₂ is the limiting reagent, we need to convert grams Cl₂ to grams FeCl₃. This can be done using the molar masses of both compounds and the mole-to-mole ratio.

Molar Mass (Cl₂): 2(35.453 g/mol)

Molar Mass (Cl₂): 70.906 g/mol

Molar Mass (FeCl₃): 55.845 g/mol + 3(35.453 g/mol)

Molar Mass (FeCl₃): 162.204 g/mol

1.0 g Cl₂          1 mole             2 moles FeCl₃         162.204 g
-------------  x  -----------------  x  -----------------------  x  ------------------  =  1.5 g FeCl₃
                      70.906 g            3 moles Cl₂              1 mole

Answer:

0.015 moles

Explanation:

0.500 m³ of a 0.150 M tetraoxosulphate solution contains 0.075 moles of tetraoxosulphate ions. Since 1 mole of H2SO4 is needed for every 2 moles of tetraoxosulphate ions, then 0.015 moles of H2SO4 are needed.

Answer:

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Explanation:

uodigdoydoydohhxoydoydodkgdyodisirs85ssto toutuset8itgxotteotsmvtieksititsgie8e85t8upfgtjwdujhftisnfvoyxuvfgkrtj57lhmdkhflfheogkhptufsjfxocljhflhfoydllbxoydoggsigxitieoyurreifosuuluprohgsjtgjzffgfhcpzfjchzjfcg gsjiggdoydogxlhd6oxhx9yfljf

The greater, the ionic property, the greater will be solubility. water is a covalent compound where calcium carbonate is ionic that's why the solubility of [tex]CaCO_{3}[/tex](s) would be greater.

The capability of a substance, the solvent, to combine with another substance, the solvent, has been known as solubility. Insolubility, or just the solute's inability to create that kind of a solution, would be the opposite attribute.

Ionic chemicals dissolve readily in just about any liquid that has the ability to rupture the ionic link present in them. Since water itself has a stronger ionic bond and is still polar in nature, water disrupts the ionic link by hydrogen bonding. Several other solvents, like kerosene and gasoline, are unable to dissolve the ionic bond.

The greater, the ionic property, the greater will be solubility. water is a covalent compound where calcium carbonate is ionic that's why the solubility of [tex]CaCO_{3}[/tex](s) would be greater in distilled water than in tap water that contains 50 mg/L of calcium ions

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According to the law of conservation of mass 1.7 grams of [tex]O_2[/tex] will be formed.

A mole is defined as 6.02214076 × 1[tex]0^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]2HgO[/tex]→ [tex]2Hg + O_2[/tex]

According to the laws of conservation mass of reactants should be equal to the mass of products.

23.5 grams - 21.8 grams

1.7 grams of [tex]O_2[/tex] will be formed.

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From the calculation, the moles of water produced is 18 moles of water.

A decomposition reaction is one in which a substance is split up into smaller parts.

We have the reaction; 2 Cr(OH)3(aq) ------------> Cr2O3(s) + 3H2O(l)

From this reaction;

2 moles of  Cr(OH)3 produced 3 moles of water

12 moles of  Cr(OH)3 will produce;

12 moles  *  3 moles / 2moles

= 18 moles of water

Hence, 12 moles of chromium (III) hydroxide produces 18 moles of water.

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77.78 kJ of energy is released when 1 mol of glucose is burned, 2802.5 kJ of energy is released.

A mole is defined as 6.02214076 ×[tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Calculate the moles of 5.00g of glucose.

Given mass = 5.00g

The molar mass of glucose = 180.156 g/mol

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{5.00g}{180.156 g/mol}[/tex]

Moles =0.02775372455

The quantity of energy released to a person by eating 5.00g of glucose in a candy.

0.02775372455 x 2802.5 kJ

77.77981305 kJ =77.78 kJ

Hence, 777.78 kJ of energy is released.

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The electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

The expression 'electronic configuration' makes reference to the spacial arrangement of electrons in distinct energy orbitals of an atom/molecule.

The orbitals are designed with numbers and letters, whereas the amount of electrons in each orbital is expressed as superscripts (e.g., 1s² 2s² 2p² in the C atom that form glucose).

In conclusion, electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

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The equation that is correct for coffee-cup calorimeter is q reaction = -q calorimeter. Details about coffee-cup calorimeter.

A calorimeter is an apparatus for measuring the heat generated or absorbed by either a chemical reaction, change of phase or some other physical change.

A coffee-cup calorimeter is a specific type of calorimeter that involves the absorption of heat of a reaction by water when a reaction occurs.

The enthalpy change of the reaction is equal in magnitude but opposite in sign to the heat flow for the water:

qreaction = -(qwater)

Therefore, the equation that is correct for coffee-cup calorimeter is q reaction = -q calorimeter.

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Answer:

655

Explanation:

using bodmas, (bracket first), 8.81-7.50=1.31

1.31÷0.0020=655

Answer:

Nitrite

Explanation:

Nitrous Oxide = N₂O

Nitrite = NO₂

Ammonia = NH₃

Nitrate = NO₃⁻

The  Percent yield of  soap is 17.8%

Percent yield is given as follows:

The actual yield of soap = 6.2 g

The expected yield is determined from the equation of the reaction.

The equation of the reaction is given as follows:

NaOH + CH₃(CH₂)₁₄COOH ----> CH₃(CH₂)₁₄COONa + H₂O

Molar mass of (palm kernel oil) CH₃(CH₂)₁₄COOH = 256 g/mol

Molar mass of NaOH = 40 g/mol

Molar mass of (soap) CH₃(CH₂)₁₄COONa = 278 g/mol

Mass of palm kernel oil = 9.9 g

Expected mass of soap = 5/40 * 278 = 34.75 g

Percent yield = 6.2/34.75 * 100 = 17.8%

Therefore, the Percent yield of  soap is 17.8%

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Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

[tex]percent yield=\frac{actual yield}{theorical yield}x100[/tex]

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the definition of percent yields:

[tex]percent yield=\frac{1.22 mol}{1.60 mol}x100[/tex]

Solving:

percent yield= 76.25%

Finally, the percent yield for the reaction is 76.25%.

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Answer:

2 HgO → 2 Hg + O2

Explanation:
Decomposition is when one reactant breaks down into two or more products due to heat, light or electricity
Here mercury (II) oxide goes through thermal decomposition to make mercury and oxygen

Answer:

2HgO—»2Hg+O_2

Explanation:

The decomposition reaction

Here Mercury oxide gives mercury and oxygen

so option A is decomposition

Theoretical yield produced is 31.8 gram and the percentage yield is 62.27%.

The zinc (Zn) is more reactive than lead (Pb). So that zinc loses electrons more easily than lead .

And the electrons of Zn are transfer to lead in this reaction .

This question is a limiting reactant question .

And For limiting reactant questions so that we need to determine that how much product can be produced by all reactant .

Zinc and Lead (II) nitrate react to form Zinc Nitrate and Lead.

Zn + Pb(NO₃)₂ → Zn(NO₃)₂ + Pb

Now we have- Weight of Pb(NO₃)₂ = 49.5 g

molar mass of Pb(NO₃)₂ = 331.2 g

now moles of Pb(NO₃)₂ = 49.5 ÷ 331.2 = 0.15 moles

Moles of Pb consumed = 1 × 0.15 = 0.15

moles mass of Pb consumed = 0.15 × 207.2 = 31.8 gm

Here Zn is in excess so that lead(II) nitrate is a limiting reactant.

(a) Theoretical yield of lead -  

moles of Pb produced = 0.15 × 1  = 0.15 moles

molar mass of Pb = 207.2g

mass of Pb produced in reaction = 0.15 × 207.2   = 31.08 g

theoretical yield = 31.8 gram

(b) After separating the lead by filtration -

obtained lead = 19.8gm

Percentage yield = 19.8 ÷ 31.8 ×100 = 62.27%

so that after separating the lead the percentage yield is 62.27%.

So, After applying the concepts of stoichiometric method the theoretical yield produced came out to be 31.8 gram and the percentage yield came out to be 62.27%.

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The enthalpy change (ΔH) for the reaction (per mole H₂O produced) is 56.96 KJ/mol

Mass = density × volume

Mass = 1 × 110

Mass = 110 g

Q = MCΔT

Q = 110 × 4.184 × 4.22

Q = 1942.2128 J

Ba(OH)₂ + 2HCl --> BaCl₂ + 2H₂O

Since the reaction occurs in a constant‑pressure calorimeter, it means both reactants are sufficient enough for the reaction.

Mole of Ba(OH)₂ = molarity × volume

Mole of Ba(OH)₂ = 0.310 × (55 / 1000)

Mole of Ba(OH)₂ = 0.01705 mole

From the balanced equation above,

1 mole of Ba(OH)₂ reacted to produce 2 moles of H₂O.

Therefore,

0.01705 mole of Ba(OH)₂ will react to produce = 0.01705 × 2 = 0.0341 mole of H₂O.

ΔH = Q / n

ΔH = 1942.2128 / 0.0341

ΔH = 56956.29 J/mol

Divide by 1000 to express in KJ/mol

ΔH = 56956.29 / 1000

ΔH = 56.96 KJ/mol

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Answer:

109.988623 Pounds or 49.89kg

Explanation:

Answer:

mass = 266.8 g

Explanation:

mass = no. of moles  x   molar mass ([tex]M_r[/tex])

[tex]M_r \space\ \space\ of[/tex] [tex]Mg(NO_2)_2[/tex]   = 24 + 2[14 + 2(16)]

                                 = 116

∴ mass = 2.3  x  116

            = 266.8 g

Answer:

978.19° C

Explanation:

P1V1/T1 =P2V2/T2     Since the pressure is constant, this can be written as

V1/T1 = V2/T2      RE-ARRANGE TO

V2 *  T1/V1   = T2       Note:  T must be in Kelvin!!

1.5 L  *  (273.15 + 23)  / (.355 L ) = T2 = 1251.338 K  =978.19 C

4.21×[tex]10^{-4}[/tex] Molal is the molality, m, of a solution made by adding 8.21 g of solid naphthalene, [tex]C_{10}H_8[/tex], to 27.92 g of liquid benzene,[tex]C_6H_6[/tex].

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]

Moles of naphthalene=[tex]\frac{mass}{molar \;mass}[/tex]

Moles of naphthalene[tex]=\frac{8.21 g}{128.2 g/mol}[/tex]

=0.064

Moles of benzene[tex]=\frac{mass}{molar \;mass}[/tex]

Moles of benzene[tex]=\frac{27.92 g}{78.1 g/mol}[/tex]

=0.357

Total mole of solute= 0.064+0.357=0.421

[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]

[tex]Molality = \frac{0.421 }{1000}[/tex]

Molality = 4.21×[tex]10^{-4}[/tex] Molal

Hence, 4.21×[tex]10^{-4}[/tex] Molal is the molality, m, of a solution made by adding 8.21 g of solid naphthalene, [tex]C_{10}H_8[/tex], to 27.92 g of liquid benzene, [tex]C_6H_6[/tex].

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Taking into account the reaction stoichiometry, 2.405 moles of NaCl are formed when  127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.

In first place, the balanced reaction is:

2 FeCl+ 3 Na₂CO₂ → Fe₂(CO₃)₃ + 6 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 318 grams of Na₂CO₂ form 6 moles of NaCl, 127.49 grams of Na₂CO₂ form how many moles of NaCl?

[tex]moles of NaCl=\frac{127.49 grams of Na_{2} CO_{2} x6 moles of NaCl }{318grams of Na_{2} CO_{2} }[/tex]

moles of NaCl= 2.405 moles

Then, 2.405 moles of NaCl are formed when  127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.

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