A yoyo with a mass of m = 150 g is released from rest as shown in the figure.

The inner radius of the yoyo is r = 2.14 cm, and the outer radius is R = 4.00 cm, and the moment of inertia about the axis perpendicular to the plane of the yoyo and passing through the center of mass is I[tex]_{cm}[/tex] = 1.01×10-4 kgm2.

1. Determine the linear acceleration of the yoyo.

2. Determine the angular acceleration of the yoyo.

3. What is the weight of the yoyo? (Hint: It's not 150 g)

4. What is the tension in the rope?

5. If a 1.27 m long section of the rope unwinds from the yoyo, then what will be the angular speed of the yoyo?

80000 Joule is the change in the internal energy of the gas.

ΔW = -pdV

ΔW = -pd (V₂ -V₁)

ΔW = - 1.65×10⁵ pa (0.320m³ - 0.110m³)

     = - 0.35×10⁵ pa.m³

     = - 35000 (N/m³)(m³)

     = -35000 Nm

ΔW = -35000 Joule

Therefore, work done by the system = -35000 Joule

ΔV = ΔQ + ΔW

Given:

ΔQ = 1.15×10⁵ Joule

ΔW = -35000 Joule

ΔU = 1.15×10⁵ Joule - 35000 Joule

      = 80000 Joule.

Therefore, the change in the internal energy of the gas= 80000 Joule.

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Based on the nature of friction:

Friction is the opposition to the relative motion of an object over another at their surfaces of contact.

The coefficient of friction is a ratio of the frictional force and the normal reaction.

The coefficient of friction of rough surfaces is greater than that of smooth surfaces.

In the given experiment:

In conclusion, the experiment demonstrates that the coefficient of friction  is a constant for given surfaces and does not depend on the mass of the object.

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At the top of the circle, the net force on the ball is pointing downward, so that by Newton's second law

[tex]\sum F = -ma \implies F_{\rm tension} + F_{\rm weight} = \dfrac{mv^2}R[/tex]

where [tex]a=\frac{v^2}R[/tex] because the ball is undergoing circular motion with constant speed.

Plug in everything you know and solve for [tex]v[/tex].

[tex]4.0\,\mathrm N + (0.17\,\mathrm{kg}) g = \dfrac{(0.17\,\mathrm{kg})v^2}{0.62\,\rm m} \\\\ \implies v^2 = \dfrac{0.62\,\rm m}{0.17\,\rm kg} \left(4.0\,\mathrm N + (0.17\,\mathrm{kg}) g\right) \\\\ \implies v^2 \approx 21 \dfrac{\mathrm m^2}{\mathrm s^2} \implies \boxed{v \approx 4.5\dfrac{\rm m}{\rm s}}[/tex]

Plug this into the acceleration equation and solve for [tex]a[/tex].

[tex]a = \dfrac{21\frac{\mathrm m^2}{\mathrm s^2}}{0.62\,\rm m} \implies \boxed{a \approx 33\dfrac{\rm m}{\mathrm s^2}}[/tex]

The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

From ohm's law; V = I × R

Where V is the voltage, I is the current and R is the resistance.

Also, Power is expressed as; P = V × I

Where V is voltage and I is current.

Given that;

First, we determine the current flow through the bulb.

V = I × R

12.0V = I × 10.0 ohms

I = 12.0 ÷ 10.0

I = 1.2A

Next, we determine the power of the bulb.

P = V × I

P = 12.0V × 1.2A

P = 14.4 Watts

Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

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The types of fusion that occurs in stars are:

A nuclear fusion is reaction in which nucleus of small atoms combine together to produces atoms of larger nucleus.

The types of nuclear fusion that can occur in a star include;

In conclusion, the types of fusion that occur in stars are proton-proton fusion, carbon cycle fusion and helium fusion.

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According to Newton's second law

Answer:

electric motors is the answer

The component of the total velocity in the x - direction is 6.96 m/s.

The component of the total velocity in the y - direction is 2.95 m/s.

The component of the total velocity in the x - direction is calculated as follows;

v(x) = vtot cosθ

where;

v(x) = 7.56 x cos(23)

v(x) = 6.96 m/s

v(y) = vtot sinθ

v(y) = 7.56 x sin(23)

v(y) = 2.95 m/s

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The tension in rope B is determined as 46.17 N.

Tension in rope A is the resultant tension of the rope B and C.

T(C) = T(B) = T

where;

T² + T² = 65.3²

2T² = 4,264.09

T² = 4,264.09/2

T² = 2,132.045

T = √2,132.045

T = 46.17 N

Thus, the tension in rope B is determined as 46.17 N.

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Answer: 2.90mi/hr/s

Explanation:

Acceleration = Final Velocity - Initial over time

Acceleration = 27.8mi/hr over 9.58s.

Answer is 2.90mi/hr/s

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The power of man performing 500 J of work in 8 seconds is 62.5 J/s.

Power can be defined as the pace at which work is completed in a given amount of time.

Horsepower is sometimes used to describe the power of motor vehicles and other machinery.

The pace at which work is done on an item is defined as its power. Power is a temporal quantity.

Which is connected to how quickly a project is completed.

The power formula is shown below.

Power = Energy / Time

Power = E / T

Because the standard metric unit for labour is the Joule and the standard metric unit for time is the second, the standard metric unit for power is a Joule / second, defined as a Watt and abbreviated W.

Here we have given Energy as 500 J and Time as 8 second.

Power = Energy / Time

Power = 500 / 8  Joule / sec

Power = 250 / 4  Joule / sec

Power = 125 / 2 Joule / sec

Power = 62.5 Joule / sec  or  62.5 watt

Power came out to be 62.5 J/s when the man performed 500 Joule of work in 8 seconds.

So we can conclude that the power in the Energy transmitted per unit of time, and can be find out by dividing Energy by time. In our case the Power came out to be 62.5 Joule / Second.

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The frequency of sound at the given temperature is 200.58 Hz.

The frequency of sound at the given temperature is calculated as follows;

v = fλ

f = v/λ

where;

f = 343/1.71

f = 200.58 Hz

Thus, the frequency of sound at the given temperature is 200.58 Hz.

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The velocity of sound in air is 358m/s

Given;

v= 2f(L2-L1)

= 2.2.56.(1- 0.3)

=358 m/s

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The force the escaping gas exerts of the rocket is 10.42 N.

The force the escaping gas exerts of the rocket is calculated as follows;

F = m(v - u)/t

where;

F = (0.25)(40 - 15)/0.6

F = 10.42 N

Thus, the force the escaping gas exerts of the rocket is 10.42 N.

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Answer:

6600J

Explanation:

the formula for work is: W= F x d

F- force, d- distance

Short-duration spacecraft typically have one backup system and carry their own supply of oxygen. A large portion of the required oxygen is produced on long-duration missions, such as the International Space Station (ISS), which has been in orbit since 1998. Different sources provide the oxygen utilized on the ISS. The water electrolyzer is the primary source of metabolic oxygen. As an alternative to the electrolyzer, oxygen candles (also known as SFOGs) can produce metabolic oxygen. Additionally, oxygen is carried up whenever a cargo ship docks and stored in two tanks on the ISS Airlock. The electrolyzer electrolyzes water to create oxygen by running an electric current through it. Since water is a poor electrical conductor by itself, a little quantity of common salt is dissolved in the water to improve its electrical conductivity. Water is split into hydrogen and oxygen throughout the process.

We must keep in mind that oxygen by itself cannot be inhaled; it must be combined in the proper ratio with nitrogen to make it breathable. Two tanks aboard the ISS are used to store nitrogen, and the cargo ships that travel by from time to time also transport nitrogen cylinders. Through the electrical grid of the station, the solar panels on the station supply the necessary electricity for the oxygen generators. The majority of the required water is transported to the station by cargo supply ships. Condensers, which draw water vapor even from the station's air, ensure that not a drop of water is wasted. Using the proper equipment, water is also recycled from the astronauts' urine.

Through a suitable vent, the hydrogen gas produced during the electrolysis process is released into space. Pressurized tanks at the airlock nodes at the space station are pumped with oxygen when the cargo vehicles arrive there. Pressurized tanks there are also pumped with nitrogen. It goes without saying that the station's atmospheric controls combine the gases in the right amounts for the atmosphere of Earth and then distribute the combination throughout the cabin. The production of oxygen in space is impossible.

Answer:

convection

Explanation:

Convection is a process by which heat is transferred by the movement of a heated fluid such as air or water.

The answer is Conduction: the process of heat is directly transmitted through a substance when there is a difference in temperature.

The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

The total capacitance of the circuit is calculated as follows;

Capacitors in series;

1/Ct = 1/8 + 1/7.5

1/Ct = 0.25833

Ct = 3.87 mF

Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

Ct = 30.87 mF

Ct = 0.03087 F

Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

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Answer:

Centripetal acceleration of this aircraft: approximately [tex]6.52\; {\rm m \cdot s^{-2}}[/tex].

Distance covered during the turn: approximately [tex]63.2\; {\rm km}[/tex].

Time required for the turn: approximately [tex]0.0242\; \text{hours}[/tex] (approximately [tex]87.2\; {\rm s}[/tex].)

Explanation:

Convert velocity and radius to standard units:

[tex]\begin{aligned}v &= 2610\; {\rm km \cdot h^{-1}} \times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &= 725\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

[tex]\begin{aligned} r = 80.5\; {\rm km} \times \frac{1000\; {\rm m}}{1\; {\rm km}} = 8.05 \times 10^{4}\; {\rm m}\end{aligned}[/tex].

Hence, the centripetal acceleration of this aircraft:

[tex]\begin{aligned} a &= \frac{v^{2}}{r} \\ &= \frac{(725\; {\rm m\cdot s^{-1}})^{2} }{8.05 \times 10^{4}\; {\rm m}} \\ &\approx 6.53\; {\rm m \cdot s^{-2}}\end{aligned}[/tex].

The trajectory of the turn is an arc with a radius of [tex]r = 80.5\; {\rm km}[/tex] and a central angle of [tex]\theta = 90^{\circ} = (\pi / 4)[/tex]. The length of this arc would be:

[tex]\begin{aligned} s &= r\, \theta \\ &= 80.5\; {\rm km} \times (\pi / 4) \\ &\approx 63.2\; {\rm km}\end{aligned}[/tex].

The time required to travel [tex]63.2\; {\rm km}[/tex] at a speed of [tex]2610\; {\rm km \cdot h^{-1}}[/tex] would be:

[tex]\begin{aligned}t &= \frac{s}{v} \\ &\approx \frac{63.2\; {\rm km}}{2610\; {\rm km \cdot h^{-1}}} \\ &\approx 0.0242\; {\rm h} \\ &\approx 0.0242 \; {\rm h} \times \frac{3600\; {\rm s}}{1\; {\rm h}} \\ &\approx 87.2\; {\rm s} \end{aligned}[/tex].

Compressibility of a substance is defined as the ratio of volumetric strain to the change in pressure. It is also equal to the reciprocal of the bulk modulus of the substance. It is denoted by K (kappa).

, for an isothermal process.

As we know that, work done for isothermal reversible expansion is given by-

Answer:

0.18 N or 180 N

Explanation:

Mass,m = 150g

acceleration,a = 1.2m/s2

CHANGE FROM g TO kg

1kg =1000g

so 150g =150/1000 = 0.15kg

But Force, F = mass,m × acceleration,a

F=ma

F=0.15×1.2

F= 0.18 N

We can get water from the sweat and exhaled breath of the people present in the space station.

We can get water from the sweat and exhaled breath. The water we drink is recycled from the sweat and exhaled breath of the people present in the space station which was collected through  condensation on the Space Station's walls.

So we can conclude we can get water from the sweat and exhaled breath of the people present in the space station.

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The main way in which an altimeter measures the altitude of an object is by calculating the location's air pressure.

This refers to the instrument that is used to measure the altitude of an object when it is at a fixed level.

Hence, we can see that an altimeter should NOT be confused with a barometer, because although they both measure pressure, a barometer calculates the change in air pressure and elevation based on available weather.

Please note that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.

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Answer:

According to second law of motion,the acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

So simply, it can be affected due to increasing force as there is close relationship between momentum.

Explanation:

The more inertia that an object has, the more mass that it has. A more massive object has a greater tendency to resist changes in its state of motion.

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If resistor A, B and C are arranged in series, same current will flow in all the resistors and 2A will flow is resistor C.

This is the type of circuit arrangement in which the resistors are arranged in series order.

In this type of circuit arrangement, same current flows in every component of the circuit.

Thus, if resistor A, B and C are arranged in series, same current will flow in all the resistors and 2A will flow is resistor C.

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