A woman bought a bag of rice 5700 naira and in 3 weeks later, she could only buy 2/4 of the bags for 5700 naira. Find the percentage?

Answers

Answer 1

Answer: 100% increase

Step-by-step explanation:

You need the find the cost per bag in those weeks.

Three weeks ago, she could buy a bag for N5,700.

Three weeks after that, she could only buy half a bag for the same amount. A bag therefore costs:

= 5,700 ÷ 2/4

= N11,400

The percentage increase is:

= (11,400 - 5,700) / 5,700

= 100%


Related Questions

What is -a⁻² if a = -5?

Answers

Answer:

25

Step-by-step explanation:

First, plug -5 in for a, -(-5)^2. We treat the negative on the outside of the paranthese as a -1 so we do -1 times -5 and we get 5. Then we square 5 and get 25.

Find the zeros of the following quadratic functions.
3) x2 + 5x + 6 = 0

Answers

the zeros are x= -6 & x= 1

help ASAP Ill give you brainliest

Answers

Answer:

none of these

Step-by-step explanation:

There are 3 boys walking

There are a total of 20 people

3/20 = 0.15

That is 15 percent, therefore none of these answers.

Step-by-step explanation:

any has at least one mode

Find the value of X for which the following fraction is undefined
2x²+x-15
________
2/3x²-6

Answers

Answer: ±√2

Step-by-step explanation: A fraction is undefined when its denominator is =0 or undefined. so we need to get 2/3x²-6=0 or undefined. so we can also do 3x^2-6=0. Solving yields ±√2!

31 PIONTS GIVING BRAINIEST AWNSER Any tips on how to get a grade up ???

Answers

Answer:

 Forgot picture?

Step-by-step explanation:

Answer:

You can get your grade up by studying, getting a tutor, paying attention in class, taking good notes, asking questions, and cheating (i don't recommend this one :/)

ht
Which of the following is an equivalent expression to the expressione,
А
B
D
ANSWER QUICK PLZ

Answers

Answer A is your correct answer

Sammy counts the number of people in one section of the school auditorium. He counts 18 female students, 16 male students, and 6 teachers. There are 720 people in the auditorium. Consider the probability of selecting one person at random from the auditorium

Answers

Correct Question:

He counts 18 female students, 16 male students, and 6 teachers. There are

720 people in the auditorium. Consider the probability of selecting one person

at random from the auditorium.

Which of these statements are true?

Choose all that apply.

A:  The probability of selecting a teacher is 6%.

B : The probability of selecting a student is 85%.

C : The probability of selecting a male student is 32%.

D : The probability of selecting a female student is 45%.

Step-by-step explanation:

Option B  and D are correct because

The total number of people in one cross section = 18 + 16 + 6 = 40.

A = The probability of selecting a teacher is = (6/40)x100 = 15 % not equal to 6 %

B = The probability of selecting a male student is = (34/40)x100 = 85%

C = The probability of selecting a male student is = (16/40)x100 = 40 % not equal to 32 %

D : The probability of selecting a female student is = (18/40)x100= 45%

Given the definitions of f(x) and g(x) below, find the value of (gof)(1).
f(x) = 2x² – 2x – 4
g(x) = -5x + 14

Answers

Answer:

[tex](g*f)(x) = 34[/tex]

Step-by-step explanation:

For sake of clarity, [tex](g * f)(x) = g(f(x))[/tex]

First, find [tex]f(1)[/tex]

[tex]f(1) = 2(1)^2 - 2(1) - 4\\f(1) = 2-2-4 \\f(1)=-4[/tex]

Then, take what you got for [tex]f(1)[/tex] and plug that into [tex]g(x)[/tex].  In this case, [tex]f(1) = -4[/tex]

[tex]g(-4) = -5(-4) + 14\\g(-4)= 20 + 14\\g(-4) = 34[/tex]

Please make sure to mark brainliest if this satisfies your

0 Let x₁ = and x3 = B x2 = Write H Span{x1, x2, X3}. = - Use the Gram-Schmidt process to find an orthogonal basis for H. You do not need to normalize your vectors, but give exact answers. S 100.0000 V3

Answers

Main answer: An orthogonal basis for the given span H is {x1, x2-x1, x3 - (x1 + x2 - x1)} which simplifies to {x1, x2-x1, x3-x2}.

Supporting explanation: Given, x₁ = 0, x₂ = 1, x₃ = √3The span of H is the set of all linear combinations of x1, x2 and x3.So, we have to find an orthogonal basis for H using the Gram-Schmidt process. Let's start with the first vector x1 = [0, 0, 0]The second vector x2 is the projection of x2 onto the subspace perpendicular to x1. x2 is already perpendicular to x1 so x2-x1 = x2. So, the second vector is x2 = [0, 1, 0].The third vector x3 is the projection of x3 onto the subspace perpendicular to x1 and x2. x3 is not perpendicular to x1 and x2, so we subtract the projections of x3 onto x1 and x2 from x3. Projection of x3 onto x1:projx₁(x₃) = x₁ [(x₁ . x₃)/(x₁ . x₁)] = [0, 0, 0]Projection of x3 onto x2:projx₂(x₃) = x₂ [(x₂ . x₃)/(x₂ . x₂)] = [0, √3/3, 0]Therefore, x3 - projx₁(x₃) - projx₂(x₃) = [0, √3/3, √3]So, the orthogonal basis for H is {x1, x2-x1, x3 - (x1 + x2 - x1)} which simplifies to {x1, x2-x1, x3-x2}.

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Information from a poll of registered voters in a city to assess voter support for a new school tax was the basis for the following statements.

The poll showed 51% of the respondents in this city's school district are in favor of the tax. The approval rating rises to 58% for those with children in public schools. It falls to 45% for those with no children in public schools. The older the respondent, the less favorable the view of the proposed tax: 38% of those over age 56 said they would vote for the tax compared with 73% of 18- to 25-year-olds.

Suppose that a registered voter from this city is selected at random, and define the following events.

F = event that the selected individual favors the school tax
C = event that the selected individual has children in the public schools
O = event that the selected individual is over 56 years old
Y = event that the selected individual is 18–25 years old

Use the given information to estimate the values of the following probabilities. (1) P(F) (ii) P(FIC) (iii) PCFCS) (iv) P(FIO)

Answers

The probability that the selected individual has children in public schools AND favors the school tax is 0.32

The probability that the selected individual favors the school tax AND has children in public schools is 0.32.

The probability that the selected individual favors the school tax AND does NOT have children in public schools is 0.2.

The probability that the selected individual favors the school tax AND is over 56 years old is 0.15.

The probability that the selected individual favors the school tax AND is 18-25 years old is 0.45.

Based on the given information, the probability of event F (the selected individual favors the school tax) is 0.54, as 54% of the respondents are in favor of the tax. The probability of event C (the selected individual has children in public schools) is 0.59, as the approval rating rises to 59% for those with children in public schools. The probability of event O (the selected individual is over 56 years old) is 0.37, as only 37% of those over age 56 said they would vote for the tax. The probability of event Y (the selected individual is 18-25 years old) is 0.71, as 71% of 18- to 25-year-olds said they would vote for the tax.

Using these probabilities, we can estimate the values of the following probabilities:

(1) P(CF) is the probability that the selected individual has children in public schools AND favors the school tax. Based on the given information, we can multiply the probabilities of events C and F: P(CF) = 0.59 * 0.54 = 0.318, or approximately 0.32.

(ii) P(FIC) is the probability that the selected individual favors the school tax AND has children in public schools. This is the same as P(CF), so P(FIC) = 0.32.

(iii) P(FIN) is the probability that the selected individual favors the school tax AND does NOT have children in public schools. To calculate this, we can use the fact that the approval rating falls to 44% for those with no children in public schools. So, P(FIN) = 0.44 * (1 - 0.59) = 0.18, or approximately 0.2.

(iv) P(FTO) is the probability that the selected individual favors the school tax AND is over 56 years old. To calculate this, we can use the fact that the approval rating for those over 56 years old is only 37%. So, P(FTO) = 0.37 * (1 - 0.59) = 0.1523, or approximately 0.15.

(v) P(FY) is the probability that the selected individual favors the school tax AND is 18-25 years old. To calculate this, we can use the fact that the approval rating for those 18-25 years old is 71%. So, P(FY) = 0.71 * (1 - 0.37) = 0.4477, or approximately 0.45.

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Can someone state the range of this function pleaseee?

Answers

Answer:

Range = [0, ∞)

Step-by-step explanation:

Range is the y-values

For this question y starts at 0 and just continually goes up so:

Range = [0, ∞)

Population 1,2,4,5,8 · Draw all possible sample of size 2 W.O.R · Sampling distribution of Proportion of even No. · Verify the results

Answers

Question:

A population consists  1, 2, 4, 5, 8. Draw all possible samples of size 2  without replacement from this population.

Verify that the sample mean is an unbiased estimate of the population mean.  

Answer:

[tex]Samples: \{(1,2),(1,4),(1,5),(1,8),(2,4),(2,5),(2,8),(4,5),(4,8),(5,8)\}[/tex]

[tex]\hat p = \frac{3}{5}[/tex] --- proportion of evens

The sample mean is an unbiased estimate of the population mean.

Step-by-step explanation:

Given

[tex]Numbers: 1, 2, 4, 5, 8[/tex]

Solving (a): All possible samples of 2 (W.O.R)

W.O.R means without replacement

So, we have:

[tex]Samples: \{(1,2),(1,4),(1,5),(1,8),(2,4),(2,5),(2,8),(4,5),(4,8),(5,8)\}[/tex]

Solving (b): The sampling distribution of the proportion of even numbers

This is calculated as:

[tex]\hat p = \frac{n(Even)}{Total}[/tex]

The even samples are:

[tex]Even = \{2,4,8\}[/tex]

[tex]n(Even) = 3[/tex]

So, we have:

[tex]\hat p = \frac{3}{5}[/tex]

Solving (c): To verify

[tex]Samples: \{(1,2),(1,4),(1,5),(1,8),(2,4),(2,5),(2,8),(4,5),(4,8),(5,8)\}[/tex]

Calculate the mean of each samples

[tex]Sample\ means = \{1.5,2.5,3,4.5,3,3.5,5,4.5,6,6.5\}[/tex]

Calculate the mean of the sample means

[tex]\bar x = \frac{1.5 + 2.5 +3 + 4.5 + 4 + 3.5 + 5 + 4.5 + 6 + 6.5}{10}[/tex]

[tex]\bar x = \frac{40}{10}[/tex]

[tex]\bar x = 4[/tex]

Calculate the population mean:

[tex]Numbers: 1, 2, 4, 5, 8[/tex]

[tex]\mu = \frac{1 +2+4+5+8}{5}[/tex]

[tex]\mu = \frac{20}{5}[/tex]

[tex]\mu = 4[/tex]

[tex]\bar x = \mu = 4[/tex]

This implies that [tex]\bar x[/tex] is an unbiased estimate of the [tex]\mu[/tex]

Pip was thinking of a number. Pip halves the number and gets an answer of 87.2. Form an
equation with x from the information.

Answers

X/2= 87.2

to find X:

87.2 X 2= 174.4

therefore X is 174.4

Isaiah is decorating the outside of a box in the shape of a triangular prism. The figure
below shows a net for the box.
What is the surface area of the box, in square meters, that
Isaiah decorates

Answers

Answer:

389.19 m²

Step-by-step explanation:

The surface area of the box = area of the two equal triangles + area of the 3 different rectangles

✔️Area of the two equal triangles:

Area = 2(½*base*height)

base = 7 m

height = 8 m

Area of the two triangles = 2(½*7*8) = 56 m²

✔️Area of rectangle 1:

Area = Length*Width

L = 13 m

W = 7 m

Area of rectangle 1 = 13*7 = 91 m²

✔️Area of rectangle 2:

L = 13 m

W = 8 m

Area of rectangle 2 = 13*8 = 104 m²

✔️Area of rectangle 3:

L = 13 m

W = 10.63 m

Area of rectangle 3 = 13*10.63 = 138.19 m²

✅Surface Area of the box = 56 + 91 + 104 + 138.19 = 389.19 m²

Find the solution to the linear system of differential equations { 146 +24y 12x + 20y satisfying the initial conditions X(0) = 3 and Y(0) = 3. x(t)=__ y(t)=__

Answers

Therefore, the solution to the given system of differential equations, with the initial conditions x(0) = 3 and y(0) = 3, is:

x_(t) = 146t + 24yt + 3

y_(t) = (876t + 21) / ((-144) - 10t)

To solve the given linear system of differential equations, let's rewrite the system in a more standard form:

dx/dt = 146 + 24y

dy/dt = 12x + 20y

We'll use the initial conditions x_(0) = 3 and y_(0) = 3 to find the specific solution.

To solve the system, we can use the method of integrating factors.

Solve the first equation:

dx/dt = 146 + 24y

Rearrange the equation to isolate dx/dt:

dx = (146 + 24y) dt

Integrate both sides with respect to x:

∫dx = ∫(146 + 24y) dt

x = 146t + 24yt + C_(1) ---(1)

Solve the second equation:

dy/dt = 12x + 20y

Rearrange the equation to isolate dy/dt:

dy = (12x + 20y) dt

Integrate both sides with respect to y:

∫dy = ∫(12x + 20y) dt

y = 6x + 10yt + C_(2) ---(2)

Now, we'll apply the initial conditions x_(0) = 3 and y_(0) = 3 to find the values of C_(1) and C_(2).

From equation (1), when t = 0, x = 3:

3 = 146(0) + 24(3)(0) + C_(1)

C_(1) = 3

From equation (2), when t = 0, y = 3:

3 = 6(0) + 10(3)(0) + C_(2)

C_(2) = 3

Now, substituting the values of C_(1) and C_(2) back into equations (1) and (2), we get:

x = 146t + 24yt + 3

y = 6x + 10yt + 3

Simplifying further:

x = 146t + 24yt + 3

y = 6(146t + 24yt + 3) + 10yt + 3

x = 146t + 24yt + 3

y = 876t + 144y + 18 + 10yt + 3

x = 146t + 24yt + 3

y - 154y - 10yt = 876t + 18 + 3

(-144y) - 10yt = 876t + 21

y = (876t + 21) / (-144 - 10t)

Therefore, the solution to the given system of differential equations, with the initial conditions x(0) = 3 and y(0) = 3, is:

x_(t) = 146t + 24yt + 3

y_(t) = (876t + 21) / ((-144) - 10t)

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ABM Services paid a $4.15 annual dividend on a day it closed at a price of $54 per share. What
was the yield?

Answers

Answer:

Yield per share = 7.68% (Approx.)

Step-by-step explanation:

Given:

Dividend paid = $4.15

Price per dividend = $54

Find:

Yield per share

Computation:

Yield per share = [Dividend paid / Price per dividend]100

Yield per share = [4.15 / 54]100

Yield per share = [0.0768]100

Yield per share = 7.68% (Approx.)

A circle is inscribed in an isosceles trapezoid with bases of 8 cm and 2 cm. Find the probability that a randomly selected point inside the trapezoid lies on the circle

Answers

Given that a circle is inscribed in an isosceles trapezoid with bases of 8 cm and 2 cm. We need to find the probability that a randomly selected point inside the trapezoid lies on the circle.

The isosceles trapezoid is shown below: [asy] draw((0,0)--(8,0)--(3,5)--(1,5)--cycle); draw((1,5)--(1,0)); draw((3,5)--(3,0)); draw((0,0)--(1,5)); draw((8,0)--(3,5)); draw(circle((2.88,2.38),2.38)); label("$8$",(4,0),S); label("$2$",(1.5,5),N); [/asy]Let ABCD be the isosceles trapezoid,

where AB = 8 cm, DC = 2 cm, and AD = BC.

Since the circle is inscribed in the trapezoid, we can use the following formula:2s = AB + DC = 8 + 2 = 10 cm

Where s is the semi-perimeter of the trapezoid. Also, let O be the center of the circle. We can draw lines OA, OB, OC, and OD as shown below: [asy] draw((0,0)--(8,0)--(3,5)--(1,5)--cycle); draw((1,5)--(1,0)); draw((3,5)--(3,0)); draw((0,0)--(1,5)); draw((8,0)--(3,5)); draw(circle((2.88,2.38),2.38)); label("$A$",(0,0),SW); label("$B$",(8,0),SE); label("$C$",(3,5),N); label("$D$",(1,5),N); label("$O$",(2.88,2.38),N); label("$8$",(4,0),S); label("$2$",(1.5,5),N); draw((0,0)--(2.88,2.38)--(8,0)--cycle); label("$s$",(3,0),S); label("$s$",(1.44,2.38),E); [/asy]Since O is the center of the circle, we have:OA = OB = OC = OD = rwhere r is the radius of the circle.

Also, we have:s = OA + OB + AB/2 + DC/2s = 2r + 2s/2s = r + 5 cmWe can solve for r:r + 5 cm = 10 cmr = 5 cmNow that we know the radius of the circle, we can find the area of the trapezoid and the area of the circle.

Then, we can find the probability that a randomly selected point inside the trapezoid lies on the circle as follows:Area of trapezoid = (AB + DC)/2 × height= (8 + 2)/2 × 5= 25 cm²Area of circle = πr²= π(5)²= 25π cm²Therefore, the probability that a randomly selected point inside the trapezoid lies on the circle is:

Area of circle/Area of trapezoid= 25π/25= π/1= π

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The probability that a randomly selected point inside the trapezoid lies on the circle is 0.399 or 39.9%. Therefore, option (A) is the correct answer.

The circle is inscribed in an isosceles trapezoid with bases of 8 cm and 2 cm.

Inscribed Circle of an Isosceles Trapezoid

Therefore, the length of the parallel sides (AB and CD) is equal.

Let the length of the parallel sides be ‘a’. Then, OB = OD = r (let)

It is also given that the lengths of the parallel sides of the trapezoid are 8 cm and 2 cm.

Then, its height is given by:

h = AB - CD / 2 = (8 - 2) / 2 = 3 cm

Therefore, the length of the base BC of the right-angled triangle is equal to ‘3’.

Then, the length of the other side (AC) can be given as:

AC = sqrt((AB - BC)² + h²) = sqrt((8 - 3)² + 3²) = sqrt(34) cm

The area of the trapezoid can be calculated as follows:

Area of the trapezoid = 1/2 (sum of the parallel sides) x (height)A = 1/2 (8 + 2) x 3A = 15 sq. cm.

The area of the circle can be given by:

Area of the circle = πr²πr² = A / 2πr² = 15 / (2 x π)

Therefore, r² = 2.39

r = sqrt(2.39) sq. cm.

Now, the probability that a randomly selected point inside the trapezoid lies on the circle can be calculated by dividing the area of the circle by the area of the trapezoid:

P (point inside the trapezoid lies on the circle) = Area of the circle / Area of the trapezoid

P = πr² / 15

P = π (2.39) / 15

P = 0.399 or 39.9%

The probability that a randomly selected point inside the trapezoid lies on the circle is 0.399 or 39.9%.

Therefore, option (A) is the correct answer.

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7. An article in a journal reports that 34% of American fathers take no responsibility for child care. A researcher claims that the figure is higher for fathers in the town of Littleton. A random sample of 225 fathers from Littleton, yielded 97 who did not help with child care. Using a .05 level of significance test the claim that the proportion is at least 34%.

Answers

The calculated value of z = 2.80 > the Critical value of z = -1.645, we reject the null hypothesis.

Hence, the claim that the proportion is at least 34% is rejected.

Therefore, the researcher's claim is true that the figure is higher for fathers in Littleton.

Null hypothesis:

H0: p ≥ 0.34

Alternative hypothesis:

Ha: p < 0.34

where:p = proportion of Littleton fathers who do not help with childcare

Here, the level of significance, α = 0.05

Level of significance = α = 0.05

The test statistics for a proportion is given as z-test.  

The formula for calculating z-score for a proportion is: z = (p - P) / sqrt[P(1 - P) / n]

where:

P = Population proportion

p = Sample proportion

n = Sample size

The calculated value of z-statistics can be compared with the critical value of z-score from the standard normal distribution table at a particular level of significance.

If the calculated value of z is greater than the critical value of z, then we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.

Calculating the z-statistic:

Here, Sample size n = 225

Sample proportion

p = 97/225

= 0.4311

Population proportion

P = 0.34z

= (p - P) / sqrt[P(1 - P) / n]z

= (0.4311 - 0.34) / sqrt[(0.34)(0.66) / 225]z

= 2.80

Since the alternative hypothesis is one-tailed (Ha: p < 0.34), the critical value of z at α = 0.05 can be found as follows:

The critical value of z = zα

= -1.645

Since the calculated value of z = 2.80 > the Critical value of z = -1.645, we reject the null hypothesis.

Hence, the claim that the proportion is at least 34% is rejected.

Therefore, the researcher's claim is true that the figure is higher for fathers in Littleton.

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Point (2.-3) on glx) is transformed by -g[4(x+2)]. What is the new point? Show your work

Answers

After considering the given data we conclude that the new point generated is (2,3), under the condition that g(x) is transformed by [tex]-g[4(x+2)][/tex].

To evaluate the new point after the transformation of point (2,-3) by -g[4(x+2)], we can stage x=2 and g(x)=-3 into the expression [tex]-g[4(x+2)][/tex]and apply  simplification to get the new y-coordinate. Then, we can combine the new x-coordinate x=2 with the new y-coordinate to get the new point.
Stage x=2 and g(x)=-3 into [tex]-g[4(x+2)]:[/tex]
[tex]-g[4(2+2)] = -g = -(-3) = 3[/tex]
The new y-coordinate is 3.
The new point is (2,3).
Hence, the new point after the transformation of point (2,-3) by [tex]-g[4(x+2)][/tex] is (2,3).
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QUICK! Giving brainliest to correct answer

Answers

Answer:

Dominos is the better deal.

In this situation dominos is the better deal.

A type of origami paper comes in 15 cm by 15 cm
square sheets. Hilary used two sheets to make the
origami dog. What is the total area of the origami
paper that Hilary used to make the dog?

Answers

Answer:

150 cm squared

Step-by-step explanation:

I guess that's the answer if I'm wrong you can tell me right away so that I can try another method thank you.

In 3^6, 6 is called ___.



base


exponent

Answers

The answer is B, Exponent

Step-by-step explanation:

the correct answer is exponent because 6 is its power.

hope this answer will help u.

have a great time.

HELP



4(x-2+y)=???????

Answers

Answer:

4+4−8

Step-by-step explanation:

Which point on the graph represents the y-intercept?


Answers

W . The point was placed on the Y-intercept

Rewrite the expression using a DIVISION SYMBOL: "The quotient of m and 7."

Answers

Answer:

m ÷ 7

Step-by-step explanation:

"Quotient" means you're dividing, so this just means you're dividing m by 7.

If S=4 [tex]\pi[/tex] [tex]r^{2}[/tex] the value of S When R= 10[tex]\frac{1}{2}[/tex]

Answers

The Answer is 1385.

A seventh-grade class raised $380 during a candy sale. They deposited the money in a savings account for 6 months. If the bank pays 5.3% simple interest per year, how much money will be in the account after 6 months?

Answers

Answer: You want to calculate the interest on $380 at 5.3% interest per year after .5 year(s).

The formula we'll use for this is the simple interest formula, or:

Where:

P is the principal amount, $380.00.

r is the interest rate, 5.3% per year, or in decimal form, 5.3/100=0.053.

t is the time involved, 0.5....year(s) time periods.

So, t is 0.5....year time periods.

To find the simple interest, we multiply 380 × 0.053 × 0.5 to get your answer.

Step-by-step explanation:

How do you turn 5/2 into 10/4?

Answers

That’s easy. To turn 5/2 into 10/4 you multiply by 2. :D Hope this helps!

Answer:

YOU DO IT X 2

Step-by-step explanation:

Brayden invests money in an account paying a simple interest of 3.3% per year. If he invests $30 and no money will be added or removed from the investment, how much will he have in one year, in dollars and cents?

Answers

Answer:

$30.99

Step-by-step explanation:

The formula for simple interest is I = PRT where I = interest earned, P = principal amount borrowed/deposited, R = rate as a decimal, and T = time in years.

I = (30)(0.033)(1)

I = 0.99

Then add that to the amount deposited ($30) and you're done.

30 + 0.99 = $30.99

Please let me know if you have questions.

The answer is $29.01

Bases are 6 and 10 the height is 4 whats the area of the trapszoid

Answers

Answer:

here,hope this helps : )

Step-by-step explanation:

Answer: A= 32

a (Base) 6

b (Base) 10

h (Height) 4

Step-by-step explanation: A=a+b

2h=6+10

2·4=32    I really hoped this helped

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