The momentum of the water balloon at the given speed is 7.2 kgm/s.
The given parameters:
Speed of the water balloon, v = 18 m/sMass of the balloon, m = 0.4 kgThe momentum of the water balloon is calculated as follows;
P = mv
Substitute the given values of mass and velocity as follows;
P = 0.4 x 18
P = 7.2 kg m/s.
Thus, the momentum of the water balloon at the given speed is 7.2 kgm/s.
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Which best describes how plant and animal cells carry out the basic functions of life?
A.
Plant and animal cells do not need food molecules for growth.
B.
Plant and animal cells do not make molecules for their own growth and repair.
C.
Plant and animal cells break down food for growth and repair.
D.
Plant and animal cells perform life functions such as making food molecules for growth.
A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = â€""16t2 48t 190. Approximately when will the projectile hit the ground? 1. 5 seconds 3. 2 seconds 5. 3 seconds 6. 2 seconds.
The time for the projectile to hit the ground from the given position is 1.5 s.
The given parameters:
Initial velocity of the projectile, u = 48 ft/sHeight, h = 190 ftModel of the projectile path, h(t) = –16t² + 48t + 190.The time for the projectile to hit the ground is calculated as follows:
when the projectile hits the ground, the final velocity = 0
[tex]v_f = 0\\\\\frac{dh(t)}{dt} = v_f\\\\\frac{dh(t)}{dt} = -32t + 48\\\\-32t+48 = 0\\\\32t = 48\\\\t = \frac{48}{32} \\\\t = 1.5 \ s[/tex]
Thus, the time for the projectile to hit the ground from the given position is 1.5 s.
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what planets experience an eclipse from the sun
Answer:
Earth
Explanation:
The sun and the moon come together and they seem like one bonded.
A rocket burns fuel at a rate of 239 kg/s
and exhausts the gas at a relative speed of
6 km/s.
Find the thrust of the rocket.
Answer in units of MN.
The Thrust on the rocket is 1.434 MN.
To calculate the thrust of a rocket, we use the formula below
Thrust: This is the force that moves an aircraft through the air.
⇒Formula
T = M'×v.................... Equation 1⇒ Where:
T = Thrust of the rocketM' = Fuel ejection ratev = gas exhaust velocityFrom the question,
⇒ Given:
M' = 239 kg/sv = 60 km/s = 6000 m/s⇒ Substitute these values into equation 1
T = 239(6000)T = 1434000 NT = 1.434 MNHence, the Thrust on the rocket is 1.434 MN.
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What is the speed of an 800 kg automobile if it has a kinetic energy of 9.00 x 10^J?
Ek = 1/2 mv^2
9 × 10^4 = 1/2 × 800 × v^2
9 × 10^4/400 = 400 v^2 / 400
9 × 10^4/400 = v^2
√225 = v
15 ms⁻¹ = v
That's the only way I know how to work it out
I think in this case velocity and speed would be considered the same because me
s = d/t and v=d/t
one is distance travelled and the other is displacement of a body
A book with a. mass of 1 kg is sliding on a table. If the frictional force on the book is 5 N, calculate the book’s acceleration. Is it speeding up or slowing down?
Force = mass x acceleration:
5N = 1kg x acceleration
Acceleration = 5N / 1 kg
Acceleration = 5 m/s^2
Acceleration is a positive value so it is speeding up
how to solve for time given distance and velocity
Answer:
Well, I think you're talking about kinematics, especially uniform rectilinear motion. We know that there is a specific equation for that:
S = Vt + S0
With S being the distance, V the velocity, t the time and S0 the initial distance (initial displacement).
From this you can calculate t, if that's what you want.
Write AT LEAST 10 SENTENCES based on ONE event that has happened in your life.
Please do it am so tired
Sorry your tired, ill try to make it worth reading.
One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.
PLEASE HELP-I LITERALLY NEED THIS RIGHT NOW!!! I'LL GIVE BRAINLIEST AND 5 STARS!!!!!!!!!!!!!!!!
why has the number of islands in hawaii increased over the last 100 million years
Answer: oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.ANSWER HERE: This mean that volcanos are producing these new islands and it is creating a chain of different islands all over Hawaii.
Answer:
Oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.
A 7.5 kg beaver dives horizontally off a 50 kg log at a speed of 4 m/s. What is the speed of the log?
Answer:
[tex]0.6\; \rm m\cdot s^{-1}[/tex], assuming that drag of the water on the log is negligible.
Explanation:
The momentum [tex]p[/tex] of an object is equal to the product of mass [tex]m[/tex] and velocity [tex]v[/tex]. That is, [tex]p = m\, v[/tex].
If the drag of water on the log is negligible, momentum of the beaver and the log, combined, would be preserved.
The momentum of the beaver and the log, combined, was initially [tex]0\; \rm kg\cdot m \cdot s^{-1}[/tex].
The momentum of the beaver right after the dive would be [tex]7.5 \; {\rm kg} \times 4\; {\rm m \cdot s^{-1}} = 30\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
The sum of the momentum of the beaver and the log is conserved and should continue to be [tex]0\; {\rm kg\cdot m \cdot s^{-1}}[/tex] even after the dive. Since the momentum of the beaver is [tex]30\; {\rm kg \cdot m \cdot s^{-1}[/tex] after the dive, the momentum of the log should become [tex](-30)\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
Since the mass of the log is [tex]50\; {\rm kg}[/tex], the new velocity of this log would be:
[tex]\begin{aligned}v &= \frac{p}{m} \\ &= \frac{(-30)\; {\rm kg \cdot m \cdot s^{-1}}}{50\; {\rm kg}} \\ &= (-0.6)\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].
(The new velocity of the log is negative because the log would be moving away from the beaver.)
The speed of an object is the magnitude of velocity. For this log, a velocity of [tex](-0.6)\; {\rm m \cdot s^{-1}}[/tex] would correspond to a speed of [tex]|(-0.6)\; {\rm m \cdot s^{-1}| = 0.6\; {\rm m \cdot s^{-1}[/tex].
how much power is needed to lift a box with a force of 780 newtons over a distance of 2 meters in 45 seconds
Answer:
34.67 WExplanation:
Power is the rate at which work is done and can be found by using the formula
[tex]p = \frac{w}{t} \\ [/tex]
p is the power in Watts (W)
w is the workdone in joules
t is time in s
but workdone = force × distance
From the question
force = 780 N
distance = 2 m
workdone = 780 × 2 = 1560 N
Since we now have the value of workdone we can find the power
We have
[tex]p = \frac{1560}{45} = 34.6666666... \\ [/tex]
We have the final answer as
34.67 WHope this helps you
a car dealer sells 4 makes of cars in 5 colors with either standard or automatic transmissions. how many variations does the dealership offer?
The number of variations the dealership have is 40 cars.
Data given;
The number of different product = 4The number of transmission = 2 (standard or automatic)The numbers of colors available = 5Dealership variationThis is the total numbers of cars available in the dealer shop at the moment.
To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.
This is equal to
[tex]4*2*5=40[/tex]
From the above calculation, we can say that the variations the dealership offers is 40
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You're driving your pickup truck around a curve with a radius of 22 m. A box in the back of the truck is pressed up against the wall of the truck. How fast must you drive so that the force of the wall on the box equals the weight of the box?
Answer:
Explanation:
Centrifugal force Fc = m x v2 / r
Weight = mg
As required by the question
Fc = W
v2 /r = g
given radius r = 22 m
v2 /22 = 9.8
Solve for v
required speed v = √(22 * 9.8)
= 14.35 m/s
v=15 m/s
this may help you
The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.
What is centrifugal force?The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.
The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:
[tex]{\displaystyle F=m\omega ^{2}r}[/tex]
Given, the radius of the curve, r = 22m
The acceleration, a = v²/r
The weight of the box, W = mg
We know that, F = ma
mg = m(v²/r)
v = √gr
[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]
v = 14.68 m/s
Therefore, you should drive at a speed of 14.68 m/s
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A dog is pulling an empty sled attached by a harness that is parallel to the
ground in the snow. The sled is moving with constant velocity. The mass of
the sled is 1.2 kg, and the coefficient of static friction is 0.20. Determine the
harness tension.
Answer:
Explanation:
There are only two forces causing motion involved. They oppose each other. You know this because there is no acceleration of the sled: you see only a velocity.
The formula when friction is involved is
Fnet = T - mu*Normal
mu is the frictional coefficient
The normal is the downward force caused by the mass of the sled being pulled down by the gravitational constant.
The tension is brought about by the dog pulling in the opposite direction to the frictional force.
The frictional force, oddly, acts in a horizontal direction even though the normal is vertical. It does this because friction always opposes motion.
Since there is no acceleration, the net force = 0
N= m * a_g
m = 1.2 kg
a_g = 9.8
N = 1.2 * 9.8
N = 11.76
The frictional force = mu*Normal Force.
Ff = N * mu
N = 11.76
mu = 0.2
Ff = 0.2 * 11.76
Ff = 2.35
As stated The frictional force and the Tension are equal but in opposite directions
T = 2.35
The app claimed it has "Forbidden text"
A heating curve is a graph that shows the temperature change of a substance as
thermal energy is introduced.
True
False
Answer:
This statement is true, a heating curve is a graph that shows the temperature change of a substance as thermal energy is introduced.
A heating curve is a graph that represents the temperature change of a substance as thermal energy is introduced.
What is the heating curve?The heating curve can be described as the relationship between the heating supply temperature and the outside air temperature of the system. The heating curve gives what temperature the boiler is to heat the water at an outdoor temperature.
Heating curves indicate how the temperature changes as a substance are heated up. Cooling curves are generally the opposite of the heating curve. They indicate how the temperature changes as a substance are cooled down. Similar to heating curves, cooling curves have horizontal parts where the state transforms from gas to liquid/ from liquid to solid.
The heating curve represents the material in phases of solid, liquid, and gas. As this graph is a plot of T v/s q, the slope is 1/mC. As the heating continues, the solid substance melts. During this time the temperature remains constant. The length of the line can be described as the amount of heat required to melt the solid.
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c. Two persons A and B are pushing a block from opposite sides with
force of 5N and 6N respectively.
[3]
i) Find the magnitude of the resultant force on the block.
ii) Find the direction of resultant force with respect to A and B.
Answer:
1 N
Explanation:
1) You'll just have to sum the force vectors, and since they are opposite, you'll calculate the difference of their magnitudes, in absolute value.
Ftot = |F1 - F2| = 6N - 5N = 1N
2)The direction will be the same as the greater force's direction.
Help please I will mark you the brainly!
D)
Explanation:
Coz the position changes with time but the position change is not constant throughout time So, D) does not have constant velocity
A racecar was going 60 m/s when it quickly came to a full stop at a pitstop in 8.0 sec. What was the acceleration of the dragster? Answer to the nearest hundredth
John does 3.2J of work to lower the window shade in her bedroom a distance of 0.8m. How much force must John exert on the window shade?
Answer:
[tex]\boxed {\boxed {\sf 4 \ Newtons}}}[/tex]
Explanation:
Work is energy transferred when an object is moved. It is the product of force and distance.
[tex]W= F*d[/tex]
John did 3.2 Joules of work or 3.2 Newton meters of work (the units are equivalent). The window shade was lowered a distance of 0.8 meters.
W=3.2 N*m d= 0.8 mSubstitute the values into the formula.
[tex]3.2 \ N *m = F * 0.8 \ m[/tex]
We are solving for the force, so we must isolate the variable F. It is being multiplied by 0.8 meters. The inverse operation of multiplication is division, so divide both sides of the equation by 0.8 m.
[tex]\frac {3.2 \ N*m}{0.8 \ m}= \frac{ F* 0.8 \ m}{0.8 \ m}[/tex]
The units of meters cancel.
[tex]\frac {3.2 \ N}{0.8 }=F[/tex]
[tex]4 \ N = F[/tex]
John must exert 4 Newtons of force.
the normal formula to find force is F = m*a. What kind of math do you need to do
to find the mass of an object?
- Divide: F / a
- Divide: a / F
- Multiply: F* a
- Subtract: F - a
[tex]\\ \sf\Rrightarrow F=ma[/tex]
Take a to leftAs it's multiplied on right side it will be divided on right side.[tex]\\ \sf\Rrightarrow \dfrac{F}{a}=m[/tex]
Or
[tex]\\ \sf\Rrightarrow m=\dfrac{F}{a}[/tex]
A 1500 kg car traveling 5.0 m/s collides head on with a 3000 kg truck traveling
7.0 m/s in the opposite direction. If the bumpers lock. What is the velocity of the
two vehicles together immediately following the collision?
Using law of conservation of momentum
[tex]\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3[/tex]
[tex]\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3[/tex]
[tex]\\ \sf\Rrightarrow 7500-21000=4500v_3[/tex]
[tex]\\ \sf\Rrightarrow -13500=4500v_3[/tex]
[tex]\\ \sf\Rrightarrow v_3=-3m/s[/tex]
plssssss look at the picture i need it right hurry pls
Answer:
it is B
Explanation:
Answer:
CO and H20
Explanation:
Draw a nitrogen cycle and explain in short.
please help me
Answer: biogeochemical process
Explanation:
[Ans. 2000 kg /m] f. If the mass of a substance having its volume 80 cm is 68 g. Calculate the density of the substance. Ans. 0.85 g/cm3]
Answer:
The density of the substance is
[tex]0.85\: \: g \: \: \: {cm}^{ - 3}[/tex]
Hope you could get an idea from here.
Doubt clarification - use comment section.
1. Sandra buys a $4 000 television and pays $2 000 deposit. The rest is payable in 8 equal monthly payments. If the flat rate of interest charged is 7% p.a. what is the total amount paid for the item?
Answer:
$2140
Explanation:$2000 missing plus 7 percent of 2000 is 140 so 2000+140=2140. Each month she would pay $268 approx.
The strings in a compound bow behave approximately like a
spring. A bowstring is pulled back 0.60 m with a maximum force of
267 N (AKA a 60-pound draw weight) to shoot an 18 g arrow.
Assume energy is conserved.
a) At what speed would the arrow be launched? (Note: W = FΔd uses the average
force while F = -kx uses the instantaneous force.)
The speed at which the arrow would be launched is 133.42 m/s
The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.
The equation for the work-energy theorem can be computed as:
[tex]\mathbf{W =\Delta K.E}[/tex]
[tex]\mathbf{F\Delta x =\dfrac{1}{2} mv^2}[/tex]
where;
Force (F) = 267 Ndistance Δx = 0.60 mmass (m) = 18 gspeed (v) = ???From the above equation, let make speed(v) the subject of the formula:
∴
[tex]\mathbf{v = \sqrt{\dfrac{2(F \Delta x)}{m}} }[/tex]
[tex]\mathbf{v = \sqrt{\dfrac{2(267 \times 0.60)}{0.018}} }[/tex]
v = 133.42 m/s
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what is the electric field strength at a distance of .50 m from a 1.00x10^-6 c charge?
Answer:
e = k q / r² then,
e = 9×10^9 * 1×10^-6 / 50² = 3.6 N/C
hope this helps ❤.
1) Suppose you place an object in front of a concave mirror. Which of the following statements must be true? (There could be more than one correct choice.) A) The image of the object will always be smaller than the object. B) No matter where you place the object, a real image of the object will be formed. C) The image of the object will always be inverted. D) If you position the object between the mirror and the focal point of the mirror, its image must be upright and virtual. E) No matter where you place the object, the image of the object will always be virtual and upright.
Answer:
C
Explanation:
because the concave mirror is always inverted
d ) when object is between focus and mirror , image formed is always virtual and erect
What is a Concave mirror ?
A concave mirror has a reflective surface that is curved inward and away from the light source .
a) Incorrect because image can be equal to , smaller then , and bigger then the object
b) and c) Incorrect when object is between focus and mirror , image formed is virtual and erect
d ) Correct option when object is between focus and mirror , image formed is always virtual and erect
e) Incorrect except one case in all other cases nature is real and inverted
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Which of the following is an example of physical weathering?
O calcium carbonate in limestone changes to calcium hydrogen carbonate
O flow water carves erosion channels in a hillside
Ostalactites precipitate in a cave
O acid rain corrodes a monument
Answer:
acid rain corrodes a monument. d.
Explanation:it only makes sense because its doing something to a physical object.and the other ones aren't.