The distance at which the probe should be placed so that the voltmeter reads 200 V is equal to 0.216 cm.
To find the distance at which the voltmeter reads 200 V, we need to use the equation for the electric potential at a point due to a continuous distribution of charge:
V = k * ∫λ(r')/r' dr'
where V is the electric potential at a distance r from the center of the cylinder, k is the Coulomb constant (8.99 x 10^9 N*m^2/C^2), λ is the linear charge density (13.0 nC/m in this case), and r' is a dummy variable of integration.
To find the electric potential at a distance r from the surface of the cylinder, we can split the integral into two parts: one from the surface of the cylinder (r') to the point where the probe is placed (r), and one from r to the center of the cylinder (which will be a negative value since the charge density is negative):
V = k * [∫λ(r')/r' dr' from r'=r to r'=2.4 cm] + k * [∫λ(r')/r' dr' from r'=2.4 cm to r'=0]
The first term on the right hand side represents the potential at the point where the probe is placed, and the second term represents the potential at the surface of the cylinder. We are given that the potential at the surface is 200 V, so we can set the equation equal to 200 V and solve for r:
200 V = k * [∫λ(r')/r' dr' from r'=r to r'=2.4 cm] + k * [∫λ(r')/r' dr' from r'=2.4 cm to r'=0]
To solve this equation, we need to evaluate the integrals on the right hand side. The first integral is easy to evaluate:
∫λ(r')/r' dr' from r'=r to r'=2.4 cm = λ * ln(2.4 cm/r)
The second integral is a little more tricky, but we can use the fact that the charge density is uniform to simplify it:
∫λ(r')/r' dr' from r'=2.4 cm to r'=0 = λ * ∫1/r' dr' from r'=2.4 cm to r'=0
= λ * [ln(r')] from r'=2.4 cm to r'=0
= λ * [-ln(2.4 cm)]
Substituting these values back into the original equation and solving for r, we find that the distance at which the voltmeter reads 200 V is:
r = 2.4 cm * exp(-200 V / (k * λ))
r = 0.216 cm
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Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 22.0 and carries a clockwise current of 15.0 , as viewed from above, and the outer wire has a diameter of 40.0. What must be the direction (as viewed from above) of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires? What must be the magnitude of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?
The current in the outer wire is in the counterclockwise direction.
The concept of the right-hand thumb rule and magnetic field at the center of a current carrying loop is required to solve the problem.
First, determine the direction of the current in the outer wire by using the right-hand thumb rule. Then, calculate the magnitude of current in the outer wire by equating the sum of magnetic fields due to each wire to zero.
The magnetic field at the center of a current loop is, B = [tex]\mu[/tex]₀I/2R
Here, I is the current through the loop, R is the radius of the loop, and
[tex]\mu[/tex]₀ is the permeability of free space.
The right-hand thumb rule is used to find the direction of the magnetic field. Curl the fingers of the right hand into a half circle in such a way that the thumb points in the direction of the current, then the fingers will point in the direction of the magnetic field.
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the speed of a bobsled is increasing because it has an acceleration of 2.4 m/s2. at a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total 450 n. the combined mass of the bobsled and its riders is 270 kg. (a) What is the magnitude of the force propelling the boblsed forward?
(b) What is the magnitude of the net force that acts on the bobsled?
The speed of a bobsled is increasing because it has an acceleration of 2.4 m/s2. at a given instant in time 1363.6N.
Describe what acceleration is.Acceleration refers to the rate at which the velocity and direction of a moving object change over time. Anything is said to be sped when it goes straighter and faster or slower. Therefore, even though the speed is constant, travel on a circle increases due to the constant change in direction.
In what ways do velocity and velocity differ?The rate at which a displacement varies is measured by its velocity. Speed changes occur at an accelerated rate. Its magnitude and orientation are both present, making it a vector quantity. As the rate at which velocity changes, acceleration is likewise a vector quantity.
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5. What is the mass of a car that its going 2 m/s² and then hits a tree with a force of 6000N
GIVEN
WORK
ANSWER:3000kg
Answer:
Below is the explanation
Explanation:
You use Newton's second law which states:
Force (N) = mass (kg) x acceleration (m/s squared)
So we substitute:
6000 = ? x 2
Rearrange so:
? = 6000/2
which = 3000 kg
most of the new star formation in the galaxy is found in the most of the new star formation in the galaxy is found in the bulge. halo. galactic center. spiral arms. globular clusters.
"Most of the new star formation in the galaxy is found in the spiral arms."
Spiral arms are the regions of strong star formation and are more prominent in blue light. From the centre of spiral and barred spiral galaxies, these regions extend.
Transient weaknesses in the gases that encourage star formation and produce turbulence lead to spiral arms. In other words, spiral arms contain a lot of gases, which are the primary building blocks needed for the development of new stars.
They are not hard or permanent structures, as evidenced by the presence of spiral arms. A density wave is currently thought to circle a spiral galaxy, creating spiral arms.
The thin disk of the galaxy contains all of the spiral arms.
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A water wave is called a deep-water wave if the water’s depth is more than one-quarter of the wavelength. Unlike the waves
we’ve considered in this chapter, the speed of a deep-water wave depends on its wavelength:
v = Bgl2p Longer wavelengths travel faster. Let’s apply this to standing waves. Consider a diving pool that is 5.0 m deep and 10.0 m wide. Standing water waves can set up across the width of the pool. Because water sloshes up and down at the sides of the pool, the boundary conditions require antinodes at x = 0 and x = L. Thus a standing water wave resembles a standing sound wave in an open-open tube.
a. What are the wavelengths of the first three standing-wave modes for water in the pool? Do they satisfy the condition for being deep-water waves?
b. What are the wave speeds for each of these waves?
c. Derive a general expression for the frequencies fm of the possible standing waves. Your expression should be in terms of m, g, and L.
d. What are the oscillation periods of the first three standing wave
The oscillation periods of the first three standing wave is 3.58 sec.
Deep-sea waves lie deeper than half a wavelength. A water wave is a shallow water wave if the depth is less than the wavelength divided by 20.
calculation:-
a. The wavelength of the first three standing waves are V = √g h m/2π
b. V1 = 5.59, V2 = 3.95, V3 = 3.22 m/s
C. A general expression for the frequencies fm of the possible standing waves. Your expression should be in terms of m, g, and L frequency = 1/lamda m × √g h m/2π.
d. The oscillation periods of the first three standing wave are T = 1/f
= √4πL/ng
putting the values t = 3.58
t2 = 2.52 sec and t3 = 1.25 sec.
Deep-sea waves do not interact with the seafloor on their way so their velocity is independent of water depth. However, when the wave enters shallow water, the interaction with the bottom changes the wave. The wave speed slows down the wavelength shortens and the wave height increases.
They bend in paths that are more perpendicular to the water surface propagate more slowly and decrease in wavelength as they enter shallow water. So when a wave of water travels from deep water to shallow water it slows down shortens its wavelength and changes direction.
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which of the following is the statement of dalton's law of partial pressures? multiple choice question. pv
The statement of dalton's law of partial pressures is the total pressure by a mixture of gases is equal to the sum of the partial pressures of each gas that makes up the mixture. The correct answer is B.
The pressure that each gas would produce if it occupied the same volume of the mixture at the same temperature alone is referred to as the partial pressure.
the law of partial pressure known as Dalton's Law A combination of gases exerts a pressure that is equal to the sum of the pressures that each gas exerts on its own. Each gas exerts pressure directly proportional to the amount of that gas present in the gas mixture.
In closed vessels over water, Dalton found that oxygen interacted with either one or two volumes of nitric oxide. This ground-breaking observation of integral multiple proportions served as crucial experimental support for his fledgling atomic theories.
Your question is incomplete but most probably your full question was
Which of the following is a statement of daltons law of partial pressure
A. The total pressure of a mixture of gases is the product of the partial pressures of each gas in the mixture
B. The total pressure of a mixture of gases is the sum of the partial presaure of each gas that makes up the mixture
C. gases can exist as mixtures at STP only
D. in a mixture of two gases, the pressure of each gas is 1/2 of the total pressure
E. the partial pressure of a gas is equal to the total pressure of the mixture
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mcdougal products is considering the purchase of new equipment to place in its factory. the equipment would cost $365,000, have a ten-year useful life and a salvage value at the end of its useful life of $65,000. the company estimates that annual revenues and expenses associated with the equipment would be as follows: the payback period of the new equipment is closest to:
The payback period of the new equipment is closest to 17.8%
Simple rate of return is equal to annual operating income minus the initial investment.
=$65000/365000
=17.8%
The payback period describes how long it will take to return the cost of an investment. The time it takes for an investment to break even can be summed up in this way. The payback period is important because people and businesses invest money primarily to be compensated. The payback period is the amount of time an investor would need to invest in a project before they would be able to repay their initial investment. The investment's break-even point is closely related to it.
Instead of using the units of a break-even analysis, Payback Period employs years to quantify investment opportunities and risk in a rapid and straightforward manner.
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A stone is dropped from the top of a cliff. The splash it makes when striking the water below is heard 5.0 later.
The height of the cliff that a stone is dropped from the top, the splash it made as it hit the water below was heard 5.0 s later is 857.5 m.
Sound reflectionSound can bounce when it hits an object that has a hard surface and is not easily penetrated by waves. Examples of objects that can reflect sound are glass walls, iron, zinc, cave walls, and seabeds.
This reflected sound can be used to measure the depth of the sea or the distance of the walls of the cave passage. One of the uses of sound reflection is to know the depth of the sea or the distance of the cave walls.
The equation to determine the distance is:
s = ½ (v) (t)
s = distance or height
t = time
v = velocity of the sound wave (343 m/s)
We have,
Time = 5.0 s
Velocity of the sound wave = 343 m/s
So, the height of the cliff:
s = ½ (v) (t)
= ½ (343) (5)
= 857.5 m
The question is incomplete, it should be:
A stone is dropped from the top of a cliff. The splash it makes when striking the water below is heard 5.0 s later. How high is the cliff?
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suppose that 256.0 j of heat is transferred by conduction from a heat reservoir at a temperature of 420.0 k
Answer:
ΔS= -1 J/K
Explanation:
Using this data
Heat Q= -256.0J
Temperature T=420.0 K
To find
Entropy change ΔS
Solution
We know that the entropy change of system is ΔS is given by
ΔS=Q/T
We have take heat value Q as negative because the heat is removed from heat reservoir
So
ΔS=(-256J/470K)
ΔS= -1 J/K
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a full moon appears larger on the horizon than it does overhead not because of the refraction of the atmosphere but because of an optical illusion. objects in the foreground influence the perceived size of objects in the background, and when the moon is on the horizon amid trees and houses the brain interprets it as being larger than when it appears overhead in the absence of those objects.
Moon Illusion is an Optical Phenomenon. This occurs because when the moon is near the horizon, Earthly things that resemble the moon on your retina generate a misunderstanding or inaccurate perception of distance and size.
The brain interprets the low moon as being bigger since it is lower in the sky than the higher moon.
The mechanism behind size-distance perception in everyday life, which transforms planar pictures that fall on the retina into a perception of hard objects moving in space, is related to the moon illusion.
What happens when the mechanism acts in an uncommon circumstance is what causes the moon illusion. In typical perception, the angular size of the light image stimulating our eyes expands or shrinks as rigid objects move in depth (distance).
The sense of hard objects with shifting depth perception is produced naturally by the brain in response to these changing stimuli. The ground and horizon make the moon appear comparatively close when it is close to the horizon.
Due to the moon's shifting apparent position in depth while the light stimulus stays constant, the moon appears extraordinarily huge due to the brain's size-distance mechanism.
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Mass of a particle is 5 times its rest mass, calculate its velocity.
you place a small air cart on a 3.00 m air track and set it into motion with a speed of 0.70 m/s. due to very good elastic bumpers at each end of the track, the cart oscillates back and forth between the two ends of the track with essentially no loss in energy. determine the period and the frequency for this motion. you may assume that the length of the cart is negligible compared to the length of the track.
The motion has an 8.57 second period, and its frequency is 0.11 Hz. You can suppose that the distance between the cart and the track is little.
Period= T = 2*3/0.7 = 8.57 sec
The period of the motion is 8.57seconds
freq = f = 1/T = 1 /8.57 = 0.11 Hz
The frequency of the motion is0.11Hz
The number of waves that pass a fixed point in a unit of time is known as frequency in physics. It is also the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. When a body in periodic motion moves through a series of events or locations before returning to its initial state, it is said to have experienced one cycle or one vibration. A simple harmonic motion is also seen under angular velocity.
If one cycle or vibration takes half a second to complete, the frequency is two per second; if it takes a full hour, the frequency is one hundred per hour. Frequency is often equal to the reciprocal of the period, or time interval; for example, frequency = 1/period = 1. (time interval).
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A fisherman has caught a fish on his pole, and to keep the pole steady he has to apply an upward force of F2 = 240 N at an angle of 83.5° with respect to the pole (see figure). The length of his pole is 4.1 m, and he is holding it a distance 0.35 m from the end, where he is applying a downward force F1.
With how much force, F1, in newtons, does he have to push straight downward on the end of his pole to keep the pole from moving? You may assume the pole is massless. F1 = What is the mass of the fish on the end of the pole, in kilograms? m =
The mass of the fish on the end of the pole, in kilograms m =2.090Kg.
What is Force?
Force is an influence that can cause an object to change its motion, direction, shape, or other physical attributes. Forces can be applied to objects, creating a change in their acceleration, velocity, or momentum. Forces can be either contact forces, such as pushing or pulling on an object, or non-contact forces, such as gravity, magnetism, and electricity. Forces can be described in terms of magnitude, direction, and point of application. Magnitude is the strength of the force, direction is the path the force is applied, and point of application is the point on the object where the force is applied. Forces can also be classified as balanced or unbalanced. Balanced forces occur when two forces of equal magnitude and opposite direction act on an object, resulting in no net force. Unbalanced forces occur when two forces of unequal magnitude act on an object, resulting in a net force.
Given that,
F2 = 240N
Angle = 83.5 degree
Length = 4.1m
Distance = 0.35m
How much force, F1 in newtons ?
What kind of fish is that hanging off the end of the pole?
Thus,
Calculating Torque about ‘A’
For equillibrium ∑τa= 0
F1 * L + F2 * (L – d) = 0
F1 * L= - F2* (L – d)
F1L SinΘ= F2(L – d) SinΘ
F1 = F2 (L – d)/L
F1 = 240 (4.1 – 0.35)/4.1
F1 = 219.51N
For equillibrium ∑ Fnet = 0
F2 + F1 + mg = 0
mg = F2- F1
m = F2 - F1/ g
m = 2.090Kg
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The figure below shows an overhead view of three particles on which external forces act. The magnitudes and directions of the forces on two of the particles are indicated.
The
figure below shows an overhead view of three p
(a) What are the magnitude and direction of the force acting on the third particle if the center of mass of the three-particle system is stationary?
8 N, rightward
8 N, leftward
2 N, rightward
2 N, leftward
(b) What are the magnitude and direction of the force acting on the third particle if the center of mass of the three-particle system is moving at a constant velocity rightward?
2 N, rightward
8 N, leftward
2 N, leftward
8 N, rightward
(c) What are the magnitude and direction of the force acting on the third particle if the center of mass of the three-particle system is accelerating rightward?
less than 2 N, rightward
greater than 2 N, rightward
greater than 2 N, leftward
less than 2 N, leftward
On two of the particles, the strengths and directions of the applied force are shown. 2 N to the right, 2 N to the right, and more than 2 N to the right
a) 2 N rightward
for the center of mass to be stationary,
Net force = 0
SO, 2N rightward
(b) 2N rightward
for the center of mass to move with constant velocity
Net force = 0
So, 2N rightward
(c) greater than 2N rightward
for the center of mass to accelerate in rightward
Net force should be in rightward
So, greater than 2N rightward
In mechanics, a force is any action that has the potential to change, maintain, or deform a body's motion. The three principles of motion outlined by Isaac Newton in his Principia Mathematica are frequently used to illustrate the concept of force (1687). Newton's first law states that a body at rest or moving uniformly in a straight line will stay in that state until a force is applied to it. According to the second law, a body will accelerate (change in velocity) in the direction of any external force acting on it. The strength of the external force directly correlates with the strength of the acceleration.
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find the volume of a gas in liters if 2.95 mol has a pressure of 0.760 atm at a temperature of 52oc. group of answer choices
The volume of a gas in liters if 2.95 mol has a pressure of 0.760 atm at a temperature of 52oc is 116.584.
volume of a gas = 2.95 × 0.760 × 52 = 116.584
We understand temperature as the average translational kinetic energy linked to the disordered motion of atoms and molecules, and the kinetic temperature as derived from kinetic theory provides reasonable accuracy. In light of the fact that higher energy molecules are colliding with lower energy molecules and transferring energy to them, it follows naturally that the flow of heat is from a region of high temperature toward a region of lower temperature. Since temperature only measures the kinetic energy portion of internal energy, it is not directly proportional to internal energy, so two objects with the same temperature do not necessarily have the same internal energy (see water-metal example). The three commonly used temperature scales are used to measure temperatures (Celsius, Kelvin, and Fahrenheit).
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a student spins a cup that is in contact with a platform in a horizontal circular path at a constant speed, as shown in figure 1. the platform is connected to two strings that are held by the student as the platform-cup system experiences uniform circular motion. a free-body diagram of the cup is shown in figure 2. which statement of reasoning best supports and correctly identifies the magnitude of the force the cup exerts on the platform?
√F1²+F2², because this force reflects the overall force the cup has applied to the platform.
What factors contribute to circular motion?The change in direction and centripetal force. A centripetal force is applied to any item travelling in a circle (or along a spherical route). Towards other words, the item is being physically pushed or pulled in the direction of the circle's center. This is the necessary centripetal force.
What exactly is the force pulling on a particle traveling in a circle?Centripetal force is the name of the force exerted on a particle that is rotating in a circle. It is this centripetal force that is focused inward that prevents the particle from deviating from or losing its circular course.
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while cruising at 190 knots, you wish to establish a climb at 160 knots. when entering the climb (full panel), it would be proper to make the initial pitch change by increasing back elevator pressure until the
You want to start a climb at 160 knots while cruising at 190 mph. It would be reasonable to perform the initial pitch change upon starting the climb (full panel) by increasing the rear elevator pressure until the Attitude indicator displays.
Once the knots are set, you can adjust the pressure until the pitch attitude indicator approximates the pitch attitude required for the 160-knot climb. The approximate pitch attitude needed for the 160-knot climb. You want to start a climb at 130 knots while cruising at 160 knots. It is proper to make the initial pitch change while starting a climb (full panel) by increasing the back elevator pressure until the attitude indicator displays the approximate pitch attitude needed for a 130-knot ascent. You want to start a climb at 130 knots while cruising at 160 knots. It is proper to adjust the initial pitch while commencing the climb (full panel) by raising the back elevator pressure till the end.
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A student calculates the time taken (in minutes) for the light from the sun to reach the Earth. The sun is 93 million miles away (1 mile 1.609 km) and the speed of light is 3.00 x 108 m/s. The calculation is set up as follows: 9.3 x 10^7 mi x 1609 km/1 mi x 10^3m/1 km x 1 s/3.00 x 10^8 m x 1 min/60s Select the correct answer, quoted to the correct number of significant figures. O 8.3 min, since 9.3 x 10 has 2 significant figures O 8.313, since 1.609 has 4 significant figures O 8 min, since there is only 1 significant figure in 60 s O 8.31 min, since 3.00 x 10° has 3 significant figurts
The time taken (in minutes) for the light from the sun to reach the Earth is 8.3 minutes.
The speed of sunlight is 300,000 kilometres per second. The basic equation "time= (distance/speed)" can be used to determine how long it takes for sunlight to reach Earth.
We are given that,
Speed of light = c = 3×10⁸ m/s
Distance from sun to earth = d = 93 million miles = 148.8× 10⁹m
Thus to calculate the time of sun light which is reached to earth by the equation,
t = d / c
t = (148.8 × 10⁹m)/( 3×10⁸ m/s)
t = 496 sec
t = 8 min 3 sec.
Therefore , the sunlight reached to earth in 8min 3sec.
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and it is corrupted by additive white gaussian noise, n(t) that has power spectral density (psd) of n0/2 w/hz. the frequency response of the ideal low pass filter (lpf) is given as
The performance of a digital communication system is quantified by the probability of bit detection problems in the presence of thermal noise.
In the context of wireless communications, the major source of thermal noise is the addition of random signals arising from the vibration of atoms in the receiver electronics.
Gaussian: The probability distribution of the noise samples is Gaussian with a zero mean, i.e., in the time domain, the samples can acquire both negative and positive values in addition.
the values near zero have a higher chance of occurrence while the values far away from zero are less likely to appear.
As a result, the time domain average of a greater number of noise samples is equal to zero.
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1. Abus moves 2moveront and om east, 5 North and 3m South fay 5 second. calculate on) Total distance b) Tofal displosment c Averge speed d Average Velocity.
(a) The total distance of the bus is 10 m.
(b) The total displacement of the bus is 2.83 m.
(c) The average speed of the bus is 2 m/s.
(d) The average velocity of the bus is 0.57 m/s.
What is the total distance travelled by the bus?The total distance of the bus is the sum of all the distance covered by the bus and it is calculated as follows;
distance = 2 m + 5 m + 3 m = 10 m
The total displacement of the bus is calculated as follows;
resultant horizontal displacement = 2 m east
resultant vertical displacement = 5 m - 3 m = 2 m North
Total displacement = √ ( 2² + 2² )
Total displacement = 2.83 m
The average speed is calculated as;
average speed = 10 m / 5 s = 2 m/s
The average velocity is calculated as;
average velocity = 2.83 m / 5 s = 0.57 m/s
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A 25 cm rod moves at 6.8 m/s in a plane perpendicular to a magnetic field of strength 0.12 T. The rod, velocity vector, and magnetic field vector are mutually perpendicular, as indicated in the accompanying figure.(a) Calculate the magnetic force on an electron in the rod (In N). (Enter the magnitude.) N (b) Calculate the electric field in the rod (in V/m). (Enter the magnitude.) V/m (c) Calculate the potential difference between the ends of the rod (in V). (d) What is the speed of the rod (in m/s) if the potential difference is 1.0 V? m/s
Option B is correct. The cross product of velocity and magnetic field, q [v B], determines the strength of the force.
The magnetic field's direction is anticipated by the right-hand thumb rule, and as a result, the resultant force is perpendicular to both the velocity and magnetic field directions.
Using the known currents in the wires, the force per unit length can then be computed as follows: Fl=(4107Tm/A)(5103A)2(2)(5102m)=11010N/m.
Given, \sV=200V\sv=100m/s
e=1.6×10 \s−19 \s C
m=9.1×10 −31 \s Kg \sm \se \s \s = \s9.1×10 \s−31
1.6×10 \s−19
m \se \s \s =1.75×10 \s11
The best choice is B.
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A 12 kg runaway grocery cart runs into a spring with spring constant 220 N/m and compresses it by 80 cm .
What was the speed of the cart just before it hit the spring?
The speed of the cart just before it hit the spring is 3.42 m/s.
Elastic potential energy is the energy that is stored when a force is applied to deform an elastic object.
Given the mass of the cart is 12 kg, the spring constant is 220 N/m, and the compressed length is 80 cm.
Given that the runaway grocery cart compresses the string. When this cart stops, the kinetic energy (KE) of this cart becomes zero because of maximum compression. This KE will be converted to the elastic potential energy of the spring. Then,
[tex]\begin{aligned}U&=\frac{1}{2}kx^2\\&=\frac{1}{2}\times220\times0.80^2\\&=\mathrm{70.4\;J}\end{aligned}[/tex]
This elastic potential energy is equal to the initial KE.
[tex]\begin{aligned}70.4&=\frac{1}{2}\times 12\times v^2\\140.8&=12v^2\\v^2&=11.73\\v&=\mathrm{3.42\;m/s}\end{aligned}[/tex]
The answer is 3.42 m/s
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a parallel-plate capacitor is made from two plates 12.0 cm on each side and 4.50 mm apart. half of the space between these plates contains only air, but the other half is filled with plexiglas of dielectric constant 3.40 (figure 1). an 18.0 v battery is connected across the plates.
An 18.0 v battery is connected across the plates is 4.58 * 10^-9 J.
Ceq = A*eo/2*d * (K1 + K2)
Ceq = (0.12*0.12*8.85*10^-12)/(2*4.5*10^-3) * (1 + 3.4)
Ceq = 6.23 * 10^-11 F
Energy Stored = 1.2*cv^2
U = 1/2 * 6.23 * 10^-11 * 18.0^2 J
U = 1.0 * 10^-8 J
If we remove plexiglas,
Energy Stored = 1/2* cv^2
U = 1/2 * 2.832 * 10^-11 * 18.0^2 J
U = 4.58 * 10^-9 J
One or more electrochemical cells with external connections for powering electrical equipment make up an electric battery, which is a source of electric power. A battery's positive terminal functions as the cathode and its negative terminal as the anode while it is delivering electricity.
A battery is a device that uses an electrochemical oxidation-reduction (redox) cycle to turn the chemical energy included in its active components directly into electric energy. An electric circuit is used in this kind of reaction to transmit electrons from one substance to another.
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a plane electromagnetic wave is traveling in a vacuum. the magnetic field is directed along the z-axis and given by: B_z = 3.0 mu T sin(1.0 times 10^7 x - 3.0 times 10^15 t) True / False The wavelength lambda of the wave is 1.0 times 10^7 meters True / False The frequency f of the wave is 3.0 times 10^15 Hz. True / False The direction of the electric field is along the x-axis. True / False Doubling the magnetic field strength
In a vacuum, an electromagnetic wave is moving through the air. The wavelength is 1x10^7m and the frequency is 3x10^15Hz while the direction of the electric field is along the z-axis.
Given the magnetic field along z axis (B) = 3.0muTsin(1.0x10^7x - 3.0*10^15 t)
The formula for magnetic field is B = B0sin(wt+kx)
For direction of wave by comparing the equations we have
kx +(- 3.0 x 10^15 ) = 0
x = 3.0 x 10^15 /k in positive direction of x axis
The direction of propogation is along x axis and the magnetic field in y axis. The electric field is in both directions. So E along z axis
B0 = 3x10-7x4πT
ω = -3.0 x 10^15
∧ = 2π/k = 2x3.14/1.0x10^7 = 0.68/1.0x10^7 = 0.68x10-7
The wavelength ∧ of the wave is = 0.68x10-7m
frequency (f) = c/∧ = 3x10^8/0.68x10-7 = 4.41x10^15Hz
The frequency f of the wave is 4.41x10^15Hz
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if the breaking tension of the cord is 620 n, what is the maximum mass of the sign to put on without breaking the cord
The highest tensile stress that a material can sustain before failing, such as breaking or irreversible deformation, is known as the material's breaking strength. The point at which a material transitions from elastic to plastic deformation is defined by its tensile strength.
What is an example of breaking stress?
A metal has a breaking stress or strength of 1,000 pounds per square inch, for instance, if a metal rod with a one square inch cross section can take a pulling force of 1,000 pounds but breaks if additional force is applied.
How can I determine a string's breaking strength?
The breaking strength of the string in a basic pendulum is equal to twice the weight of the bob. When the string is horizontal, the bob is freed from its resting position. When the string forms an angle with the vertical, it snaps.
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A stone with a mass of 0.900 kg is attached to one end of a string 0.800 m long. The string will break if its tension exceeds 60.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed.
Find the maximum speed the stone can attain without breaking the string.
The centripetal force is 7.3 m/s and tension is 7.30 m/s .
What is tension ?
Any two physical objects in touch have the ability to exert forces on one another. Based on the kinds of objects in touch, we give these contact forces various names. When a rope, string, chain, or cable is one of the things applying the force, the force is referred to as tension.
What is speed ?
Speed is the rate of change in location of an item, expressed in metres per second. For instance, the speed of an item is one metre per second if it starts at the origin and goes three metres in three seconds. Speed is easily calculated by dividing a distance by a time.
Tension (force) in string = mv²/R = 0.90v²/0.80 = 1.125v²
Tension (force) in string = 60.0 N
set Tensions equal:
1.125v² = 53.33
v = v53.33
v = 7.30 m/s (speed of mass at which string breaks)
circumference of path mass travels = 2pR = 5.02 m
time of one rev that gives a tangential speed of 7.3 m
T = 5.02/7.3 = 0.69 sec
rev/sec = 1/0.69 = 1.45 rps
60 x 1.45 = 87 rpm
centripetal force = Tension
mv^2/r = T
0.9xv^2/0.8 =60
v=7.3 m/s
Therefore, the centripetal force is 7.3 m/s and tension is 7.30 m/s .
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How does the inertia of the model car compare with the inertia of a real car
The mass of a real car is greater than that of a model car, hence it will have higher inertia.
What is inertia and give its example?
The concept of inertia states that an object will maintain its current motion unless a force changes its speed or direction. The phrase should be taken as a shortened form of Newton's first law of motion's description of "the principle of inertia."
Case Studies of the Law of Inertia in Daily Life (Inertia of Motion) People slump forward when the bus abruptly stops. The top part of the body continues to move forward due to inertia of motion when the driver of a bus abruptly brakes, but the bottom section of the body comes to rest along with the bus.
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white light falls on two narrow slits separated by 0.50 mm. the interference pattern is observed on a screen 5.5 m away.
The separation between the first maxima for red light (λ = 700nm) and violet light (λ = 400nm) = 80 x 10⁻⁵ cm
Light interferenceLight interference is a condition when two or more light waves combine to form a combined light wave. The condition for this light interference is that the light waves come from a coherent source, so that the amplitude, wavelength, and frequency are the same, and the phase difference is always fixed.
The question is incomplete, it should be:
What is the separation between the first maxima for red light (λ = 700nm) and violet light (λ = 400nm)?
We have,
Distance between slits = 0,5 mm = 5 x 10⁻⁴ m
Distance between the slit and the screen = 5.5 m
λ red = 700 nm =
λ violet = 400 nm
So, The separation between the first maxima:
Sin ∅m = mλ/d
= (1 x 400 x 10⁻⁹)/5 x 10⁻⁴
= 80 x 10⁻⁵ cm
The question is incomplete, it should be:
White light falls on two narrow slits separated by 0.50 mm. The interference pattern is observed on a screen 5.5 m away. (a) What is the separation between the first maxima for red light (λ = 700 nm) and violet light (λ = 400 nm)?
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messier 74 (m74), nicknamed the phantom galaxy, is a grand design spiral galaxy located in the constellation pisces. it can be found 1.5 degrees east-northeast of , the brightest star in pisces. g
It's called the Phantom because the galaxy's surface brightness is low.
Because of the galaxy's low surface brightness, it is known as the Phantom. Of all the Messier objects that amateur astronomers view using tiny telescopes, it is the most challenging to locate. The galaxy almost faces Earth, which accounts for the low surface brightness.
M74 is a star in the constellation Pisces that is around 32 million light-years from Earth. Through modest telescopes, the galaxy appears as a dim patch of light with an apparent magnitude of only 10. The ideal time to view it is around November. A spiral galaxy with a majestic pattern, M74 is the ideal illustration.
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Clearing forests for oil palm plantations is an example of large-scale agriculture. Oil palms are also plants. However, it is not desirable to have large areas of forest plants replaced by oil palms. Why is that so?
It is not desirable to have large areas of forest plants replaced by oil palms because animals and plants may be affected in regions of fragmented habitat, which is an important issue in ecosystem disturbance and loss of biodiversity.
What are ecosystem disturbances and loss of biodiversity?Ecosystem disturbance is an ecological concept that makes reference to the different human activities and natural processes (such as earthquake catastrophes) that are to break the delicate internal homeostatic equilibrium of the ecosystems. Moreover, loss of biodiversity refers to the loss of variation due to the extinction of populations and even species.
Therefore, with this data, we can see that ecosystem disturbance and loss of biodiversity are fundamental processes and they have been associated with the process of replacement of native trees in natural forests with oil palms, which have negative outcomes for the surrounding environment.
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