A Van de Graaff generator is charged so that a proton at its surface accelerates radially outward at 1.35 ✕ 1012 m/s2. Find the following. (a) the magnitude of the electric force on the proton at that instant magnitude N direction ---Select--- (b) the magnitude and direction of the electric field at the surface of the generator magnitude N/C direction ---Select---

Answers

Answer 1

Answer:

(a).

We know that force is

F = m a

So

F = (1.67 x 10^(-27) x (1.38 x10^12)

F = 2.3 x 10^-15 N facing the radially outward direction

(b).

Similarly Force for charge is

F = q E = m a

So relating

E = F/q = 2.3x 10^-15 /(1.6 10^ -19

E = 144.75 N/C facing the radially outward direction

Answer 2

The answer to the question is

(a) The force on the proton is [tex]2.254\times10^{-15}\,N[/tex] directed radially outwards.

(b) The electric field at the surface of the generator is [tex]14031.25\, N/C[/tex] directed radially outwards.

The answer can be explained as shown below.

Given that a proton accelerates radially outward at [tex]1.35\times 10^{12}\,m/s^2[/tex].

ie; [tex]a=1.35\times 10^{12}\,m/s^2[/tex]We know the mass of a proton, [tex]m_p = 1.67\times10^{-27}\,kg[/tex].

From Newton's second law we have,

[tex]F=mg[/tex]

But here, [tex]m=m_p[/tex]

So, the electric force on the proton is;

[tex]F = m_p\, a= (1.67\times10^{-27}\,kg)\, \times(1.35\times 10^{12}\, m/s^2)=2.254\times10^{-15}\,N[/tex]The force on the proton is [tex]2.254\times10^{-15}\,N[/tex] directed radially outwards.

Also, we know that, in electrostatics,

[tex]F=Eq\\ \\\implies E=\frac{F}{q}[/tex]The charge of a proton is, [tex]q=1.6\times 10^{-19}\,C[/tex]

Therefore, the electric field is given by,

[tex]E=\frac{2.254\times 10^{-15}N}{1.6\times 10^{-19}\,C} = 14031.25\, N/C[/tex]The electric field at the surface of the generator is [tex]14031.25\, N/C[/tex] directed radially outwards.

Learn more about the electric force here:

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Related Questions



Which statement describes a question that can guide the design of a

scientific investigation?

A. It asks about a cause-and-effect relationship between two

variables.

B. It asks about how the observations will be organized,

C. It asks about whether a controlled variable is necessary.

D. It asks about the preferred outcome of the investigation.

Answers

Answer:

The correct answer is:

It asks about a cause-and-effect relationship between two variables (A)

Explanation:

Scientific investigations are aimed as developing a hypothesis and proving the validity or not of the hypothesis developed. In order for these hypotheses to be tested, experiments must be done, and the experiments are designed based on the identification of a cause-and-effect relationship existing between two variables to be tested, where the "cause" is varied to various degrees and the "effect" of the variation is recorded. Therefore, knowing the cause-and-effect relationship will guide the experimental design, which will be aimed at manipulating the causes to see how these manipulations affect the second variable.

Answer:

A

Explanation:

express forty meters with four significant figures

Answers

40.00 meters

add a decimal place so that trailing zeroes are counted as significant figures.

A penny is dropped from the top of the chrysler building ( 320 m high) . How fast is it moving when it hits the ground?

Answers

As the penny falls 320 meters, its vertical velocity increases at the rate of 9.8 m/s each second. Use the following equation to determine its speed when it hits the ground.
vf^2 = vi^2 + 2 * a * d, vi = 0
vf^2 = 2 * 9.8 * 320
vf = √6272
This is approximately 79 m/s. I hope this helps you to understand how to solve this type of problem.

The hot reservoir for a Carnot engine has a temperature of 889 K, while the cold reservoir has a temperature of 657 K. The heat input for this engine is 4710 J. The 657-K reservoir also serves as the hot reservoir for a second Carnot engine. This second engine uses the rejected heat of the first engine as input and extracts additional work from it. The rejected heat from the second engine goes into a reservoir that has a temperature of 406 K. Find the total work delivered by the two engines.

Answers

Answer:

Explanation:

Efficiency of first engine

= T₁ - T₂ / T₁  where T₁ is temperature of hot reservoir , T₂ is temperature of cold reservoir

= (889 - 657 ) / 889

= ,261 or 26.1 %

output of work = .261 x 4710 = 1229.15 J .

Efficiency of second engine

=  (657 - 406 ) / 657

= .382

Heat rejected in engine one is heat input of second engine

heat input of second engine = 4710 - 1229.15 = 3480.85

output of work of second engine

=  .382 x 3480.85 = 1329.68 J

Total work delivered by two engine

= 1229.15  +  1329.68 J

= 2558.83 J

what would happen to life on earth if all the plants died? plz help

Answers

Answer:

we would all die

Explanation:

If all the plants on earth died, so would the people. ... When green plants make food, they give off oxygen. This is a gas that all animals must breathe in order to stay alive. Without plants, animals would have no oxygen to breathe and would die.

I need with the basic understanding of this​

Answers

Answer:

A = air resistance

B = lift

C = thrust

D = gravity

1.00 N, 2.86° above horizontal

Explanation:

Gravity pulls down on the bird.  The thrust of the birds wings push it forward, and the lift pushes it up.  Air resistance pushes it back.

The net force in the y direction is:

∑Fᵧ = lift − gravity

∑Fᵧ = 0.20 N − 0.15 N

∑Fᵧ = 0.05 N

The net force in the x direction is:

∑Fₓ = thrust − air resistance

∑Fₓ = 1.50 N − 0.50 N

∑Fₓ = 1.00 N

The magnitude of the resultant force is:

F² = Fₓ² + Fᵧ²

F² = (1.00 N)² + (0.05 N)²

F ≈ 1.00 N

The direction of the resultant force is:

tan θ = Fᵧ / Fₓ

tan θ = (0.05 N) / (1.00 N)

θ = 2.86° above horizontal

Nami conducts an investigation on plants. She places a grow light on a timer to give the plants different amounts of light to see if this would affect their growth. Which term describes the amount of light in this investigation?

Answers

Answer:

It is independent variable

Explanation:

Answer:

D!!!!!

Explanation:

edge 2021!

Part A
Your GPS shows that your friend’s house is 10.0 km away (Figure 2). But there is a big hill between your houses and you don’t want to bike there directly. You know your friend’s street is 6.0 km north of your street. How far do you have to ride before turning north to get to your friend’s house?
8 km
Part B
Referring to the diagram in Part A, what is the sine of the angle
θ at the location of the friend's house?

Answers

Answer:

Part A

You have to ride 8.0 km before turning north to get to your friend’s house.

Part B

The sine of the angle  θ at the location of the friend's house is 0.8

Explanation:

The remaining part of the question which is an image is attached below

Explanation:

Part A

To determine how far you will ride ride before turning north,

From the diagram, that is the distance of your street.

Let the distance of your street be [tex]A[/tex]

and the distance of your friend's street be [tex]B[/tex]

and let the displacement between your friends house and your house be [tex]C[/tex]

The relation in the diagram shows a right angle triangle.

The sides of the right angle triangle are represented as [tex]A,B[/tex] and [tex]C[/tex].

To find [tex]A[/tex], which is the distance of your street,

From Pythagorean theorem, 'The square of hypotenuse is the sum of squares of the other two sides'

That is,

[tex]/Hypoyenuse/^{2} = /Adjacent/^{2} + /Opposite/^{2}[/tex]

[tex]C[/tex] is the hypotenuse, which is the displacement between your friends house and your house,

Hence, [tex]C = 10.0 km[/tex]

[tex]B[/tex] is adjacent, which is the distance of your friends street

then, [tex]B = 6.0 km[/tex]

and [tex]A[/tex] is the opposite, which is the distance of your house

From Pythagoras theorem, we can then write that,

[tex]C^{2} = B^{2} + A^{2}[/tex]

Then, [tex]10.0^{2} = 6.0^{2} + A^{2}[/tex]

[tex]A^{2} = 100.0 - 36.0\\A^{2} = 64.0\\A = \sqrt{64.0}[/tex]

[tex]A = 8.0km[/tex]

Hence, you have to ride 8.0 km before turning north to get to your friend’s house.

Part B

To find the sine of the angle  θ at the location of the friend's house,

In the diagram, the sine of the angle  θ is given by

[tex]Sin\theta = \frac{Opposite}{Hypotenuse}[/tex]

Hence, [tex]Sin\theta = \frac{A}{C}[/tex]

Then,

[tex]Sin\theta = \frac{8.0}{10}[/tex]

[tex]Sin\theta = 0.8[/tex]

Hence, the sine of the angle  θ at the location of the friend's house is 0.8

A. The amount of distance you have to ride before turning North to get to your friend’s house is 8 kilometers.

B. The sine of the angle (θ) at the location of your friend's house is 0.8.

Let your friend's house be a.Let your friend's street be b.Let the distance between your house and your friend be c.

Given the following data:

Distance c = 10 kmDistance a = 6 km

A. To determine the amount of distance you have to ride before turning North to get to your friend’s house, we would apply Pythagorean's theorem:

Mathematically, Pythagorean's theorem is given by the formula:

[tex]c^2 = a^2 + b^2\\\\10^2 =6^2+b^2\\\\100=36+b^2\\\\b^2 =100-36\\\\b^2 =64\\\\b=\sqrt{64}[/tex]

b = 8 kilometers

B. To find the sine of the angle (θ) at the location of the friend's house:

Mathematically, the sine of an angle is given by the formula:

[tex]Sin\theta = \frac{opposite}{hypotenuse}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Sin\theta = \frac{8}{10} \\\\Sin\theta = 0.8[/tex]

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What is the net force acting on the box?
0 285 N
0 185 N
SN
0 85 N
0 65 N

Answers

Answer:

the answer would be D 65N

Explanation:

just got it correct on EDG

he atomic radii of Li and O2- ions are 0.068 and 0.140 nm, respectively. (a) Calculate the force of attraction in newtons between these two ions at their equilibrium interionic separation (i.e., when the ions just touch one another). (b) What is the force of repulsion at this same separation distance

Answers

Answer:

a

 [tex]F =  -1.07 *10^{-8} \  N [/tex]

b

[tex]F_r = 1.07 *10^{-8} \ N[/tex]

Explanation:

Generally the force of attraction between this two irons is mathematically represented as

[tex]F = \frac{k * [Q_{Li} ] * [Q_{O} ] }{ r^2}[/tex]

Here k is known as the proportionality constant with value [tex]k = 2.31 * 10^ {-28} J \cdot m[/tex]

substituting -2 for [tex] Q_{O} [/tex] i.e the charge on oxygen , +1 for [tex] Q_{Li} [/tex] i.e the charge on Lithium and [tex] [0.140 + 0.068 ] nm= 0.208 nm = 0.208*10^{-9} [/tex] for r

So

[tex]F = \frac{ 2.31 * 10^ {-28}* +1 * -2 }{ ( 0.208*10^{-9} )^2 }[/tex]

[tex]F = -1.07 *10^{-8} \ N [/tex]

Generally the force of repulsion will be the magnitude but different direction to the force o attraction

So Force of repulsionn is

[tex]F_r = 1.07 *10^{-8} \ N[/tex]

Newtons Second Law of motion states that for acceleration to stay the same...​

Answers

Answer:

newton force is the state of gravity force they abstract when they came closer

What must be the acceleration of a train in order for it to stop from 12m/s in a distance of 541m?

Please help!!

Answers

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

P.S. This is part of the answer of another brainly user this is not my knowledge.

But Hope I helped you

Answer:

-0.133 m/s²

Explanation:

Given:

Δx = 541 m

v₀ = 12 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (12 m/s)² + 2a (541 m)

a = -0.133 m/s²


Derrick crawls 4 feet south, and then turns east and crawls 6 feet.
What distance did he cover?

What was his displacement?

Answers

Displacement is a vector quantity. The distance and displacement of the given object are 10 ft and 7.07 ft respectively.

Distance:

It can be defined as the change in position of the object. It is a scalar quantity.

Displacement = 4+6

Displacement = 10 ft

Displacement:It can be defined as the vector change in position overall change in position.It is a vector quantityVector quantity is the quantities that have both magnitude and direction.

[tex]\rm Dislacement =\sqrt { 4^2 +6^2}\\\\ \rm Dislacement = 7.07 ft[/tex]

Therefore, the distance and displacement of the given object are 10 ft and 7.07 ft respectively.

Learn more about Displacement:

https://brainly.com/question/10919017

HELP!!!
An arrow is shot into the air at an angle of 30.0 above the horizontal with a speed of 20.0 m/s. What are the x and y components of the
velocity of the arrow 1.0 s after it leaves the bowstring?

Answers

Answer:

Y(1s) = [tex]10\sqrt{3}[/tex] - 10.1

X(1s) = 10m/s

Explanation:

In annex I've done the explanation for the equations that I will just present here.

Assuming that the arrow stars from the position (0 ; 0) in the Cartesian Graphic, and with Xo and Yo the initial speeds:

[tex]Yo =\frac{\sqrt{3} }{2} . Vr\\Yo = \frac{\sqrt{3} }{2} . 20\\Yo = 10\sqrt{3} m/s \\Xo = \frac{1}{2} Vr\\Xo = 10m/s[/tex]

Ignoring friction with air, Xo = Xf

So, Xo is the same during all the movement.

X(1s) = 10m/s

For Yo is different. That component is suferring reductions from gravity.

We can find Yo(1s) with one the basic functions of cinematics:

Vf = Vo + at

Vf = Final Velocity

Vo = Start Velocity

a = aceleration - gravity (g) is negative here

t = time

Yf = Yo + gt

Yf = [tex]10\sqrt{3}[/tex] - 10.1

If you prefere, can be: Yf = 10. ([tex]\sqrt{3} - 1[/tex])

A car starts at 80 m/s but sees a cop and hits the brakes slowing down to 50 m/s in 2 sec.

Answers

Answer:

-15m/s/s

Explanation:

Acceleration = change in speed/ change in time

The change in speed is calculated by subtracting the initial speed from the final speed, so the change in speed is: 50 - 80 = -30m/s. The change in time is 2 - 0 = 2.

So the car acceleration is -30/2 = -15m/s/s

It is negative because it is decelerating.

Hope this helped!

.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in contact with the pavement, the lower side of the ball is temporarily flattened. Suppose the maxi-mum depth of the dent is on the order of 1 cm. Find the order of magnitude of the maximum acceleration of the ball while it is in contact with the pavement. State your assumptions, the quantities you estimate, and the values you estimate for them.

Answers

Answer:

 a = 1.1 10⁵ m / s²

Explanation:

This is a momentum exercise, where we use the relationship between momentum and momentum

          I = ∫ F dt = Δp

= p_f - p₀

as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction

        F t = 2 (m v)

therefore the average force is

         F = 2 m v / t

where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy

starting point. Done the ball is released with zero initial velocity

        Em₀ = U = mgh

final point. Upon reaching the ground, just before the deformation begins

        Em_f = K = ½ m v²

energy is conserved in this system

        Em₀ = Em_f

        m g h = ½ m v²

        v = √ (2gh)

This is the velocity of the body when it reaches the ground, so the force remains

        F = 2m √(2gh)   /t

where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds

knowing this force let's use Newton's second law

          F = m a

          a = F / m

 

          a = 2 √(2gh) / t

We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s

         a = 2 √ (2 9.8 1.5) / 10⁻³

         a = 1.1 10⁵ m / s²

a) How long (in ns) does it take light to travel 1.0 m in a vacuum?
b) What distance does light travel in water, glass, cubic zirconia during the time it travels in 1.0 m vacuum?

Answers

Answer:

a

      [tex]t  =  3.33 \  ns[/tex]

b

i      [tex]D_w  =0.75 \  m [/tex]

ii     [tex]D_g  =0.67 \  m [/tex]

iii     [tex]D_c  =0.46 \  m [/tex]

Explanation:

Generally the time taken to travel 1 m in a vacuum is mathematically represented as

       [tex]t  =  \frac{1}{c}[/tex]

Here c is the speed of light with value  [tex]c =  3.0*10^{8} \  m/s[/tex]

So  

          [tex]t  =  \frac{1}{3.0*10^{8}}[/tex]

          [tex]t  =  3.33*10^{-9} \  s[/tex]

         [tex]t  =  3.33 \  ns[/tex]

The distance light travels in water is mathematically represented as

         [tex]D_w  = \frac{c}{n_w}  *  t[/tex]

Here n_w  is the refractive index of  water with value 1.333

So

      [tex]D_w  = \frac{3.0*10^{8}}{1.333}  *  3.33*10^{-9}[/tex]

     [tex]D_w  =0.75 \  m [/tex]

The distance light travels in glass is mathematically represented as

       [tex]D_g  = \frac{c}{n_g}  *  t[/tex]

Here n_g  is the refractive index of  glass with value 1.5

So

      [tex]D_g  = \frac{3.0*10^{8}}{1.5}  *  3.33*10^{-9}[/tex]

     [tex]D_g  =0.67 \  m [/tex]

The distance light travels in cubic zirconia is mathematically represented as

       [tex]D_c  = \frac{c}{n_g}  *  t[/tex]

Here n_c  is the refractive index of cubic zirconia with value 2.15

So

      [tex]D_c  = \frac{3.0*10^{8}}{2.15}  *  3.33*10^{-9}[/tex]

     [tex]D_c  =0.46 \  m [/tex]

A sports car starts from rest at an intersection and accelerates toward the east on a straight road at 9.0 m/s2. Just as the sports car starts to move, a bus traveling east at a constant 16 m/s on the same straight road passes the sports car. When the sports car catches up with and passes the bus, how much time has elapsed

Answers

Answer:

3.6s

Explanation:

Have In mind that the sports car will catch up with bus when their positions are equal

So

S = ut + 1/2at²

where u is initial velocity

For sports car we have

x = 0 + 1/2 x 9 x t²

For Bus

S= 16ts + 0

Equating the two

1/2 x 9 x t² = 16t

4.5 x t = 16

t = 3.6s

A pendulum is 0.760 m long, and the bob has a mass of 1,00 kg. At the bottom of its swing, the bob's speed is 1.60 m/s. The tension is greater than the weight of the bob because Multiple Choice 0 its horizontal component is increasing from zero. O the bob has a downward acceleration, so the net Fy must be downward O O the bob has zero acceleration. O ( the bob has an upward acceleration, so the net Fy must be upward Required information A pendulum is 0.760 m long, and the bob has a mass of 1.00 kg. At the bottom of its swing, the bob's speed is 1.60 m/s. What is the tension in the string at the bottom of the swing?

Answers

Answer:

  T = 13.17 N

the correct one is there is a digested centripetal acceleration towards upward

Explanation:

For this exercise we can use Newton's second law at the bottom of the pendulum's path

we will assume that the upward direction is positive

              T - W = m a

in this case it is describing a circle the acceleration is central

              a = v² / R

where the radius of the trajectories equals the length of the pendulum

             R = L

we substitute

            T = mg + m v² / L

             T = m (g + v² / L)

When reviewing the different statements, the correct one is there is a digested centripetal acceleration towards upward

let's calculate the tension of the rope

             T = 1 (9.8 + 1.6 2 / 0.760)

             T = 13.17 N

why is evidence good for practice

Answers

Answer:

HEYO BRO! (my bad for da caps)

Explanation:

Evidence-based practice (EBP) is the idea that occupational practices ought to be based on scientific evidence. That at first sight may seem to be obviously desirable, but the proposal has been controversial.

Happy to Help From, Adam

bc U know what ur doing...?

Scientific notation: Convert 7.1 x 10-3 to decimal notation.​

Answers

Answer: hey

your answer is gonna be

71000.

Explanation:

what is alpha decay?

Answers

Answer:Alpha decay, type of radioactive disintegration in which some unstable atomic nuclei dissipate excess energy by spontaneously ejecting an alpha particle.

Explanation:

A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.

Answers

Answer:

what's the question ,so I can answer it right ?

r = (2+2+1) i - (t+1)] + t3 k
what is the direction of initial velocity

Answers

Answer:

In the - j direction, that is negative of the y-axis

Explanation:

As typed in the question, the position of the object is given by the expression in three component ( i, j, k) form:

r (t) = 5  i  - (t + 1 )  j  + t^3  k

and since the velocity is the derivative of position with respect to time, by doing the derivative of this expression we get:

v(t) = 0  i  -  1  j   +3 t^2  k

which for the initial velocity requested (that is at time zero) we have:

v(t) = 0  i  -  1  j   +3 (0)^2  k = = 1  j

Then the direction of the initial velocity is entirely in the direction of the j versor, that is pointing to the negative of the y-axis.

One of the specific goals of of environmental analysis is:____________
a: To provide organized information, for the development of the organization's internal analysis, mission, vision , values and strategy.
b: To measure organizational efficiency.
c: To ignore minor competitors.
d: To develop a list of "one-word: descriptions of the external environment.

Answers

Answer:

a: To provide organized information, for the development of the organization's internal analysis, mission, vision, values, and strategy.

Explanation:

Environmental analysis is a process in business wherein the internal and external factors that can affect a business are examined so as to help improve the organization's goals and strategies. The internal analysis serves as a guide to checkmate the organization and to see if they have adopted the right strategies that suit their external environment.

Competitors in the external environment can have a huge impact on the business. So the internal workings of the organization should align with the external factors. The organized information would also be useful in forecasting the growth of the business.          

I need help ASAP plzzz!!!!

Answers

Answer:

1. coffee maker 2.store B. 3.yes 5. 180

When is the kinetic energy of the ball being transformed into gravitational potential energy?

Answers

Answer:

The second option

Explanation:

I am not sure sry

how are weak and strong forces different

Answers

Answer:

What is the difference between the electrons in the nucleus and the ones in orbit around the nucleus? ... The Strong Nuclear Force is an attractive force between protons and neutrons that keep the nucleus together and the Weak Nuclear Force is responsible for the radioactive decay of certain nuclei

Explanation:

How fast does the moon rotate around the Earth?

Answers

The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. As a result, the moon does not seem to be spinning but appears to observers from Earth to be keeping almost perfectly still.

Answer:

approximately 27 days

The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis.

Explanation:

Why is it important not to present a biased argument as a public speaker?
A.
Because it is unconvincing
B.
Because it is immoral
C.
Because it is unfair
D.
Because it is pointless

Answers

Answer:

Explanation:

a) because it's immoral as you're trying to convince people of your views when you should be giving both sides of the story so people are able to come up with their own opinions on what you're talking about

Other Questions
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