The ratio of the radius of the aluminum sphere to the radius of the lead sphere can be represented as:
[tex]\displaystyle \frac{r_{Al}}{r_{Pb}} =\sqrt[3]{\frac{\rho_{Pb}}{\rho_{Al}} }[/tex]
What is the density?The density of a material can be measured as the mass per unit volume of the material. The average density equals the mass divided by its total volume.
The mathematical formula for the density can be expressed as follows:
Density = Mass/Volume
The S.I. unit of the density that is used to measure is Kg/m³. If the size increases, the mass increases as well but the density remains constant.
Given the mass of the Al = mass pf the Pb
The ratio density of the Al and Pb can be represented as:
[tex]\displaystyle \frac{\rho_{Al}}{\rho_{Pb}} } = \frac{m/4\pi r_{Al}^3}{m/4\pi r_{Pb}^3}[/tex]
[tex]\displaystyle \frac{\rho_{Al}}{\rho_{Pb}} } = \frac{ r_{Pb}^3}{r_{Al}^3}[/tex]
[tex]\displaystyle \frac{r_{Al}}{r_{Pb}} =\sqrt[3]{\frac{\rho_{Pb}}{\rho_{Al}} }[/tex]
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what is the value of resistor r in the figure(figure 1) if δv=8v and i=6a?
The value of the resistor is 24Ω.
A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance. Resistors have a variety of purposes in electronic circuits, including lowering current flow, adjusting signal levels, dividing voltages, biassing active components, and terminating transmission lines.
We are given that,
Voltage = δv =8v
Current = i =6a
So that , the resistance can be calculated by the formula by,
R = Vi
R = 8v × 6a
R = 24 Ω
Therefore , the of resistor would be 24Ω.
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a thin rod of mass m and length l is suspended vertically from a frictionless pivot at its upper end. a mass m of putty traveling horizontally with a speed υ strikes the rod at its cm and sticks there. Explain why the intial angular momentum is what it is?
The rotating equivalent of linear momentum in physics is called angular momentum, also known as moment of momentum or rotational momentum.
Conservation of Angular Momentum m v (L/2) = I w => w^2 = m^2 v^2 L^2/(4 I^2)---------eq1
Conservation of Energy (1/2) I w^2 = (m + M)g h----------------eq2 where h = height of the center of mass
Relate h to h': h' = height from the bottom a= angle between rod and the normal
(L/2 -(L/2) cos(a)) = h (L - L cos(a))=h' => h=h'/2--------------------------eq3
Compute I=moment of inertia I=m(L/2)^2 + (1/12) M L^2 + M(L/2)^2 I= [(L^2)/4](m + 4M/3)------------------eq4
Plug eq1 and eq3 into eq2 (1/2) I m^2 v^2 L^2/(4 I^2) = (m + M)g h'/2 Solve for h' h'=m^2 v^2 /((m + M)g)
Then use eq4 to get the final result h'=m^2 v^2 /((m + 4M/3)(m + M)g)
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what is the mass (in grams) of 235u that, when undergoing induced fission, would produce the same amount of thermal energy as 1 tonne of coal?
10 to the power 6 grams is the mass of 235u that, when undergoing induced fission, would produce the same amount of thermal energy as 1 tonne of coal.
The process of nuclear fission involves the splitting of an atom's nucleus into two or more smaller nuclei. Even by the energetic standards of radioactive decay, the fission process releases a very high quantity of energy and frequently results in gamma photons. German chemist Otto Hahn and his assistant Fritz Strassmann made the discovery of nuclear fission of heavy elements with the help of Austrian-Swedish physicist Lise Meitner. Hahn recognized that there had been an atomic "burst." Meitner and her nephew Otto Robert Frisch conceptualized it in January 1939. Frisch gave the procedure its name using the analogy of biological cell division. Nuclear fission is an extremely dense source of energy because the quantity of free energy present in nuclear fuel is millions of times more than the amount of free energy present in an equivalent mass of chemical fuel, such as gasoline. Nuclear waste is a problem because the byproducts of nuclear fission are, on average, far more radioactive than the heavy elements that are typically fissioned as fuel and stay so for long periods of time. Plutonium is created by neutron absorption that does not result in fission from 238 U, as well as small actinides from both 235 U and 238 U.
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some time later, kid a was spinning with the same speed that kid c had originally. what would kid a's centripetal acceleration be if his distance from the center of the merry-go-round was r
Centripetal refers to “center-seeking” Quantifies the change in directionof the velocity The acceleration is directed toward the center of the circle of motion.
The magnitude of the centripetal acceleration is given by V^2/r, the direction is toward the center of the circle. The tangential component of the acceleration is due to changing speed. The centripetal component of the acceleration is due to changing direction.
When an object is rotating at a constant angular velocity, the whole object has a constant angular velocity. Therefore, every mint on the turntable has the same, constant angular velocity.
The acceleration which causes the tangential velocity to change direction is called Centripetal acceleration. Centripetal acceleration is always in toward the center of the circle.
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how are radio communications usually affected by the charged particles that reach earth from solar coronal holes?
Charged particle emissions interact with the magnetosphere of the earth to produce geomagnetic storms or disturbances.
Communication systems suffer harm from solar storms. Some radio frequencies are absorbed during geomagnetic storms while others are reflected, resulting in rapidly fluctuating signals and unexpected propagation patterns (reproducing or multiplying in unplanned directions). Amateur and public radio are frequently interfered with. The atmospheric circumstances that radio waves meet, like clouds and precipitation, reflect, absorb, scatter, refute, and diffract them. Importantly, different air conditions have distinct effects on radio waves. A different type of disturbance that might impact radio communications is a coronal mass ejection, or CME. Although in many ways superior to flares, CMEs were not identified until spacecraft were able to study the Sun from orbit.
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Wwhat was the power output of the speaker, assuming uniform spherical spreading of the sound and neglecting absorption in the air?
The speaker's power output is 785.398 W assuming uniform spherical spreading of the sound and neglecting absorption in the air.
Given the Sound Intensity = I and
the Loudspeaker Distance = r = 2.5m
Sound level produced(β) : 130 dB
The formula for calculating sound intensity is:
β = 10logI/I0
130 = 10logI/10-12
13 = logI/10-12
10^13x10^-12 = I
I = 10 W/m^
A = area, hence power (P) = IA = 4πr^2
P = 10X 4X 3.14X (2.5)^
P = 785.398W
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At a rock concert, a dB meter registered 130 dB when placed 2.5 m in front of a loudspeaker on stage. (a) What was the power output of the speaker, assuming uniform spherical spreading of the sound and neglecting absorption in the air?
if the sun is not brighter and the sun-to-earth distance has not decreased, where does this extra heat come from?
The sun's brightness is not increasing, nor has the separation between it and Earth. The greater heat must result from the atmosphere's greenhouse gases absorbing more infrared energy.
A greenhouse gas, often known as a greenhouse gas (GHG or GhG), is a gas that produces the greenhouse effect by both absorbing and emitting radiant radiation in the thermal infrared range. Water vapour, carbon dioxide, methane, nitrous oxide, and ozone are the main greenhouse gases in the Earth's atmosphere (O3). Instead of the current average of 15 °C (59 °F), without greenhouse gases, the temperature of the Earth's surface would be closer to 18 °C (0 °F). Also containing greenhouse gases are the atmospheres of Venus, Mars, and Titan.
The amount of carbon dioxide in the atmosphere has grown by more than 50% due to human activity since the start of the Industrial Revolution (about 1750), rising from 280 parts per million in 1750 to 421 parts per million in 2022.
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Which is the correct order of shortest to longest wavelength?
Below is a list of the wavelengths in order of shortest to longest from left to right. Radiation comes in many different forms, including gamma rays, X-rays, UV, visible, infrared, microwaves, and radio waves.
The electromagnetic spectrum is made up of a wide variety of waves that are created when the electric field and magnetic field interact. It is believed that electromagnetic waves exhibit both wave and particle characteristics.
In essence, the photons—particle-like elements that make up electromagnetic waves and convey their energy, the wavelength and frequency of the waves. The class of electromagnetic waves is referred to as the "electromagnetic spectrum."
Electromagnetic waves are classified according to increasing wavelength: gamma rays, x-rays, ultraviolet, visible, infrared, microwaves, and radio waves.
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A man wishes to throw two darts one by one at the target at B with same speed so that they arrive at the same time. Mark the correct statements about the two projections.
If the darts are thrown at the same speed then (b) Projectile that travels along trajectory B was projected earlier and (c) Second dart must be projected at angle, such that 0 + 0,8 = 90° is correct.
Initial speed of dart A = u'
Angle of dart A = θ'
Initial speed of dart B = u''
Angle of dart B = θ''
The initial speed of both the darts is same,
Thus, u' = u'' = u
The darts are projected from same point A but not at same time; they are thrown one by one. But they travel same horizontal distance and reach B at the same time.
Since the horizontal range of both darts are same,
= [ u²sin(2θ') / g ] = [ u²sin(2θ'') / g ]
= sin(2θ') = sin(2θ'')
Now, θ' is not equal to θ'', through the figure we can assume that θ'' > θ'
Since both are acute angles,
= sinθ'' > sinθ'
Multiplying both sides by 2u/g, we get,
= [ 2u X sinθ'' / g ] > [ 2u X sinθ' / g ]
which means, trajectory T of both the darts is as:
= T'' > T'.
Thus, statement B and C are correct options.
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The complete question:
A man wishes to throw two darts one by one at the target at B with same speed so that they arrive at the same time. Mark the correct statements about the two projections. Trajectory B Trajectory A А. B (A) Projectile that travels along trajectory A was projected earlier (B) Projectile that travels along trajectory B was projected earlier. (C) Second dart must be projected at angle e, such that 0 + 0,8 = 90° (D) Second dart must be projected at angle , >, STA
A man whoe Ma i 40kg walk up a flight of 20 tep each 150mm height in 10ec. Find the average power developed. (g=10m-2)
A man whose mass is 40kg walk up a flight of 20 step each 150mm height in 10 sec. The average power developed is 12.0 W.
The average power developed by the man as he walks up the stairs, you need to know the work he does and the time it takes him to do it. First, you can find the work done by the man by multiplying his weight (which is equal to his mass multiplied by the acceleration due to gravity) by the distance he travels:
= Work = (40 kg) x (10 m/s^2) x (20 steps x 0.150 m/step)
= 120 J
Then, you can divide the work done by the time it takes to do it to find the average power developed:
= Power = Work / Time
= 120 J / 10 s
= 12.0 W
So, the average power developed by the man as he walks up the stairs is 12.0 W.
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a truck is traveling east at 30 m/s. it makes a turn and 10.0 s later it is traveling 40 m/s south. what is the average acceleration while making the turn?
The average acceleration of the truck while making the turn is 5 m/s².
Average acceleration is defined as the change in velocity for a particular time interval.
Given that, initial velocity u = 30 m/s towards east = 30 m/s i
Final velocity v = 40 m/s towards south = 40 m/s j
We know the formula for average acceleration as the ratio of change in velocity upon time
⇒ (v - u)/t = (40 j - 30 i)/10 = 4 j - 3 i
The magnitude of average velocity | a'|
| a'| = √3²+4² =√(9 + 16) = √25 = 5 m/s²
Thus, the average acceleration of a truck while making the turn is 5 m/s².
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a traveller covers1.2km distance in 5 min calculate its average velocity
Answer: Average Velocity = Distance/Time
Average Velocity = 1.2km/5min
Average Velocity = 0.24km/min
Therefore, the average velocity of the traveller is 0.24km/min.
a rock is rolled in the sand. it starts at 5.0 m/s, moves in a straight line for a distance of 3.0 m, andthen stops. what is the magnitude of the average acceleration?
The magnitude of the average acceleration is [tex]4.2 m/s^{2}[/tex].
Acceleration is the rate of change of an object's velocity with respect to time. Acceleration is a vector quantity (as long as it has magnitude and direction). The direction of an object's acceleration is given by the direction of the net force acting on that object.
As described in Newton's second law, the magnitude of an object's acceleration is the combined effect of two sources.
-The mass of this object is inversely proportional to the mass of the object.
-Depending on the material from which it is made.
Calculation :
Use the equation of linear motion:
[tex]v^{2} =( v_{0} )^{2} = 2a(x-x_{0} )[/tex]
Therefore
[tex]v = 0 m/s[/tex] - final velocity is zero
[tex]v_{0} = 5.0 m/s[/tex] - greater than initial Velocity
[tex]x - x_{0} = 3.0m[/tex] - this is the displacement.
now, a is what you are looking for.
[tex]0 = 5^{2} + 2a*3[/tex]
[tex]-25 = 6a[/tex]
[tex]a = \frac{-25}{6}[/tex]
[tex]a = -4.2 m/s^{2}[/tex]
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calculate the speed of a satellite moving in a stable circular orbit about the earth at a height of 3600
A satellite travelling at 3600 km per hour in a stable circular orbit around the earth has a speed of 6320 m/s.
Utilizing mass (of the earth and satellite) and the separation between the satellite and the earth's core, one can calculate the gravitational pull (or force) between a satellite and the earth.
The gravitational equation is v = √GM/r, where
v = orbital velocity (m/s)
G = 6.67x10-11Nm2kg2 (gravitational constant)
M is the orbiting body's mass (kg)
orbital radius, r (m)
5.97 x 10^24 kg is the Earth's mass, or M.
r = height + Earth's radius equals (6370 + 3600) x 10^3 = 9970 x 10^3 = 9.97 x 10^6 m
v = (6.67 x 10-11) x (5.97 x 10^24) / (9.97 x 10^6) = 6320 m/s
Hence speed of satellite is 6320m/s
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if you represented earth's history by a line that is 2 m long, how long a segment (in cm) would represent the 400 million years since life moved onto the land?
If you represented earth's history by a line that is 2 m long then, the segment length in 400 million years will be 43.2 cm.
The entire history of the Earth is represented by a line 5 meters long.
The age of the Earth is 4.6 billion years.
That means a length of 5 meters or 500 cm (1m = 100cm, so 5m = 5× 100 = 500 cm) represents 4.6 billion years, i.e 4600million years. (As 1 billion years = 1000 million years)
We have to calculate the length of the segment for 400 million years.
In 4600 million years, the segment length is = 500 cm
In 1 million years, the segment length will be = 500 / 4600 = 0.108 cm
In 400 million years, the segment length will be = 0.11 × 400 = 0.108 × 400 = 43.2 cm
Therefore, the segment length in 400 million years will be 43.2 cm.
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i need the answer to this one
Answer: The answer is 120 Newton.
a 5.0 kg cat and a 2.0 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw of figure ex12.31. how far to the left of the pivot must a 4.0 kg cat stand to keep the seesaw balanced?
The 4.0-m-long seesaw has a 5.0-kg cat and a 2.0-kg bowl of tuna fish at either end. To keep the seesaw balanced, a 4.0 kg cat must stand 1.5m to the left of the pivot.
Given length of seesaw (l) = 4m
Mass of first cat (m1) = 5kg
Mass of tuna fish (m) = 2kg
Mass of second cat (m2) = 4kg
Let the second cat is at a distance to the left of pivot = d
To keep the seesaw balanced we apply net momentum or torque theorem at pivot.
Torque net about pivot = 0
The pivot is situated at middle of seesaw so the distance from first cat to seesaw and from fish to seesaw = 2m
Force acted on first cat (F1) = m1xg = 5x9.8 = 49N
Force acted on second cat (F2) = m2xg = 4x9.8 = 39.2N
Force acted on tuna fish (F3) = mxg = 2x9.8 = 19.6N
Tourque(T) = force x distance (perpendicular)
Tnet= 49X2 - 39.2Xd - 19.6x2 = 0
58.8 = 39.2d
d = 1.5m
Hence the distance from the left of pivot where the second cat to be situated is 1.5m
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a concave mirror having a focal length of magnitude 5.0 cm forms an image 4.0 cm behind the mirror. where is the object for this image?
A concave mirror having a focal length of magnitude 5.0 cm forms an image 4.0 cm behind the mirror. Thing that is present in front of the mirror is the object for this image.
A mirror with a curved reflecting surface is referred to as a curved mirror. The surface could be concave mirror or convex (bulging outward) (recessed inward). Although optical systems occasionally employ alternative shapes, most curved mirrors have surfaces that are formed like a portion of a spherical. Since spherical mirror systems, like spherical lenses, are subject to spherical aberration, the most prevalent non-spherical variant is found in optical instruments such as reflecting telescopes that must picture distant objects. Mirrors that distort images are used for amusement. Concave and convex sections on them provide purposefully distorted images. When the object is positioned at specific distances, they also offer images that are either magnified or greatly diminished (smaller). A curved mirror with a reflective surface that bulges in the direction of the light source is referred to as a convex mirror or diverging mirror. Convex mirrors do not focus light since they reflect it outward. Since the focal point (F) and the center of curvature (2F) are both fictitious positions "within" the mirror that cannot be reached, such mirrors always produce a virtual image.
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you are raising a flag on a flagpole. you apply 2 kg of force to the rope to raise the flag 10 meters in 5 seconds. the amount of power you expend doing so is
Typically, pulleys are used to raise objects, particularly heavy objects. The load is the thing that a pulley lifts. The effort is the force delivered to the pulley.
The first weight to be lifted up, if the man exerts enough force (T), is the one whose force of gravity (mass times g) is exceeded by 2T. Weights do matter since the force of gravity is proportional to mass; the lightest weight rises first. To lift the bucket out of the well, pulley systems are used. Pulleys are essential to the operation of numerous forms of workout equipment. Heavy materials can be lifted and moved using construction pulleys.
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what produces the retrograde motion of mars, and what geometric arrangements did ptolemy use to explain this motion?
Due of Earth's far bigger orbit than Mars', as Earth passes it, Mars seems to be going backwards. Ptolemy postulated that planets orbited on epicyles that revolved around deferents to explain this.
Mars experiences retrograde motion when Earth, which moves more quickly than Mars, passes it. Due to this, Mars seems to move westward in retrograde motion, which is the real or apparent travel of a body in a direction that differs from that of the majority of solar system members' (direct) movements or the motion of other astronomical systems with a preferred direction of motion. All of the planets, with the exception of Venus and Uranus, rotate counterclockwise on their own axes as seen from a location in space north of the solar system (from a large distance above the North Pole of the Earth). Venus and Uranus, therefore, exhibit retrograde rotation. Fewer than half of the known satellites of the planets exhibit retrograde rotation.
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a falling coconut has a mass of 3.5 kg and an upward force of air resistance of 12 n. a) calculate the net force on the coconut as it falls
The coconut is subject to a downward force of 1.47 N from gravity. The gravitational pull of the tree causes a coconut to fall from it.
The gravitational pull is both an attracting and non-contact force. The coconut consequently falls from the tree. Given that palm trees may reach heights of up to 30 meters (98 feet) over, or the equivalent of an 8-story building, a coconut can fall at a rate of up to 85 kilometers per hour (53 mph). Accordingly, the force of the coconut as it lands on the ground is equal to a ton of weight.
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4. A 2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a
level frictionless surface. Calculate the power output.
The power output of 2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a level frictionless surface is 24.09 watts.
What is power?In science, power is the time required to do work or provide energy, expressed as work done W or energy transferred divided by the time interval t - or W/t. A fixed amount of work can be done for a long time with a low-powered engine, or for a short time with a high-powered engine. The unit of power is work (or energy) per unit of time. Such as foot pounds per minute, joules (or watts) per second, and ergs per second. Force can also be expressed as the product of the force required to move an object and the object's velocity in the direction of the force. If the magnitude of the force F is measured in pounds and the velocity ν is measured in feet per minute, then the power is equal to Fν foot pounds per minute.
Given,
Mass of object (m) = 2.00 kg
Distance covered (s) = 1.5 m
Velocity of object (v) = 3.00 m/s
For calculation of acceleration:
v² = u² + 2as
3² = 0 + 2 × a × 1.5
9 = 3a
a = 2 m/s²
For calculation of time:
s = ut + ¹/₂at²
1.5 = 0 × t + ¹/₂ × 2 × t²
1.5 = t²
t = 1.22 sec.
For calculation of gravitational force:
F = mg
F = 2 × 9.8
F = 19.6 N
For calculation of work done:
W = F × s
W = 19.6 × 1.5
W = 29.4 J
For calculation of power output:
P = W/t
P = 29.4/1.22
P = 24.09 watts
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nuclear fission produces a large yield of energy; however, this energy is not in the form of electricity. what form of energy is produced by fission?
Nuclear fission reactions result in the release of kinetic energy.
What is nuclear fission ?
Nuclear fission is the procedure in nuclear physics whereby an atom's nucleus divides into two daughter cells
Nuclear fission is the process by which an atom's nucleus breaks into two lighter nuclei during a nuclear reaction. This decay may occur naturally as a result of spontaneous radioactive decay, or it may be replicated in a laboratory setting by meeting the appropriate circumstances (bombarding with neutrinos). The resultant fragments typically weigh less when combined than the initial bulk. In the aforementioned process, the missing mass is what is transformed into nuclear energy.The kinetic velocities of the neutrons and fission products make up the majority of the energy released. uranium-235, plutonium-239, a combination of the two typical of modern nuclear power reactors, and uranium-233 utilised in the thorium cycle thermal neutron fission product yields by mass.
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what is the radius of a sphere that has a density of 5000 kg/m3 and a mass of 6.00 kg?
The radius of the sphere is 0.065 meters
How to calculate the radius of a sphere?Be sure all data has the same unit. Based on the question, density and mass have been known. Both of them have the same unit, therefore we don't need to change anything at first. Calculate the volume. There is a relationship between density, mass, and volume. Knowing the radius, you can count the volume of the sphere first. The formula of volume is [tex]\frac{mass}{density}[/tex]Volume of the sphere: [tex]\frac{6 kg}{5000kg/m^{3} }[/tex] = 0.0012 [tex]m^{3}[/tex]
3. Calculate the radius from the volume.
The volume of sphere is defined with [tex]\frac{4}{3}[/tex] x [tex]\pi[/tex] x [tex]r^{3}[/tex]
From step 2, the volume is 0.0012 [tex]m^{3}[/tex] so it can be written like this :
Volume = [tex]\frac{4}{3}[/tex] x [tex]\pi[/tex] x [tex]r^{3}[/tex]
0.0012 = [tex]\frac{4}{3}[/tex] x 3.14 x [tex]r^{3}[/tex]
[tex]r^{3}[/tex] = [tex]\frac{0.0012 x 3}{4 x 3.14}[/tex]
[tex]r^{3}[/tex] = [tex]\frac{0.0036}{12.56}[/tex] = 0.000286
r = [tex]\sqrt[3]{0.000286}[/tex] = 0.065 meters
Thus, the radius of a sphere that has a density of 5000 kg/m3 and a mass of 6.00 kg is 0.065 meters.
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why keep your engine running when you wait to pick up your husband when you could just stop the engine to save gas, meanwhile, keeping your lights, air conditioning, and wipers running normally?
There are several reasons why you might want to keep your engine running when you are waiting to pick up your husband, even if you could stop the engine to save gas.
One reason is that keeping the engine running allows you to use the car's electrical systems, such as the lights, air conditioning, and wipers, without draining the battery. If you turn off the engine and use these systems, the battery will eventually drain, and you may have to jump-start the car to get it running again.
Another reason is that turning off the engine and restarting it can be hard on the engine and may reduce its lifespan. When you turn off the engine, all of the internal components come to a stop and may experience wear and tear when the engine is restarted. By keeping the engine running, you can avoid this additional wear and tear.
Finally, keeping the engine running may be more convenient and safer. It allows you to keep the car's systems running and be ready to drive at a moment's notice, which may be important if you are waiting in a potentially dangerous or unfamiliar location.
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. calculate the velocity of water at the top of the tank and through the side pipe. what principle are you using
As per Torricelli's Theorem velocity of efflux, i.e., the velocity with which the liquid flows out of a hole is equal to [tex]\sqrt{2gh[/tex]
Where h = the depth of the hole below the liquid surface.
According to Bernoulli's principle, "Within a horizontal flow of fluid, points of higher fluid speed will have less pressure than points of slower fluid speed."
The more depth the hole is, the more the velocity of the liquid that comes out of the hole. The velocity is maximum if the hole is at the bottom of the tank.
Pipe velocity is an area-averaged property independent of the pipe's cross-sectional flow distribution. It does not matter whether the flow is laminar or turbulent. Along the central axis, fluid may be traveling at twice the calculated pipe velocity.
The given question is incomplete, the related concepts has been described here for reference.
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Determine how much heat needs to be transferred to 1 kg of ice at -10C to turn it into water at 15C. The specific heat capacities of ice and water are 2.1 and 4.2 kJ, respectively, the specific heat of melting of ice is 330 kJ/kg
Answer: If you drop ice into hot water will result in the ice melting
Explanation:
what happens if the woman suddenly slides closer to the hub by 0.400 m? (select all that apply.)
The new net torque is in the opposite direction and hhas greater magnitude than that of previous.
What is torque?The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction.
A vector quantity is a torque. The force acting on the axis determines the direction of the torque vector.
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a proton is accelerated by a uniform 360 n/c electric field. find the kinetic eergy and the velocity of the proton after it has traveled 50
The kinetic energy is 2.88 × 10-17 J and the velocity of the proton will be 180 m/s
The kinetic energy of the proton is given by
KE = qV = (1.60217662 × 10-19 C) (360 N/C) (0.50 m)
= 2.88 × 10-17 J, The velocity of the proton is given by:
V = (360 N/C) (0.50 m) =0.360 x 0.50 = 0.180 m/s .
This means that after the proton has traveled 50 cm, it will have a kinetic energy of 2.88 × 10-17 J and a velocity of 180 m/s. This result is because the electric field is uniform and constant, and the proton is accelerated by the same amount throughout its journey. This means that the velocity and kinetic energy of the proton will increase linearly with the distance traveled. The electric field provides the proton with a constant acceleration, and as the proton travels further, it gains more kinetic energy and a higher velocity.
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a thin nonconducting rod with a uniform distribution of positive charge q is bent into a circle of radius r. the central perpendicular axis through the ring is a z axis, with the origin at the center of the ring.
Answer:
E max
=3.46×10
7
N/C
Explanation:
If the radius and charge are R and Q. We need to calculate the electric field due to the rod. Using formula of electric field. Where, Q = charge. z = distance. If z = 0, Then, The electric field is (b). If z = ∞, z>>R. So, R = 0. Then, the electric field is (c). In terms of R, We need to calculate the positive distance. If . Then, Taking only positive distance (d).