A typical printed page of text contains 50 lines of 80 characters each. Imagine that a certain printer can print 6 pages per minute and that the time to write a character to the printer’s output register is so short it can be ignored. Does it make sense to run this printer using interrupt‐driven I/O if each printer requires an interrupt that takes 50 µsec all‐in to service?

Answers

Answer 1

Solution :

Given

The number of line that can be written by printer per page = 50 lines

The number of characters that can be written by printer per page = 80 characters.

Number of pages that can be written per minute = 6 pages

The speed for writing characters to the printer can be found by

= 50 x 80 x 6

= 400 characters per sec

In one second the printer has the writing speed of 400 character.

Now each of the character uses = 50 µsec of the CPU time for interrupt.

So in each second, the interrupt overhead = 20 msec

Now using the interrupt driven input/output,  980 msec time can be available for other work.

Thus, the interrupt overhead charges only 2 percent of the CPU, that will hardly affect the program to run.


Related Questions

What was a campaign belief in the 1980 presidential election? Carter called for a stronger national defense. Carter promised to appoint a woman to the Supreme Court. Reagan endorsed a conservative economic policy. Reagan supported the Equal Rights Amendment.

Answers

Answer:

C-Reagan endorsed a conservative economic policy.

Explanation:

edge21

Reagan endorsed a conservative economic policy.

What is Presidential election?

In the US, presidential elections take place every four years. The next election for the nation's top position will be in 2024 because the last one occurred in 2020.

Federal elections must take place "the Tuesday next after the first Monday in November," according to U.S. law code.

Every even-numbered year has a presidential election and a congressional midterm election (e.g. 2016, 2018, 2020.)

Therefore, Reagan endorsed a conservative economic policy.

To learn more about economic policy, refer to the link:

https://brainly.com/question/22324594

#SPJ6

A flexible rectangular area measures 2.5 m X 5.0 m in plan. It supports an external load of 150 kN/m^2. Determine the vertical stress increase due to the load at a depth of 6.25 m below the corner of the footing.

Answers

Answer:

19.0476 kN/m^2

Explanation:

Given data:

Dimension of rectangular area = 2.5m x 5.0m

external load = 150 KN/m^2

load depth = 6.25 m

calculate the vertical stress increase due to load at depth 6.25

we will use the approximate method which is

[tex]V_{s} = \frac{qBL}{(B +Z)(L+Z)}[/tex]  ------- (1)

q = 150 kN/m^2

B = 2.5 m

L = 5 m

Z = 6.25 m

substitute the given values into the equation (1) above

hence the Vs ( vertical stress ) = 19.0476 kN/m^2

11. Technicians A and B are discussing
hybrid engines. Technician A says that idle
stop in HEVs and EREVs is a safety feature
for technicians. Technician B says that
high viscosity engine oil should be used
with most hybrid electric vehicles. Who is
correct?
O A. Technician A
B. Technician B
C. Neither Technician A nor B
D. Both Technicians A and B

Answers

Answer:

C. Neither Technician A nor B

Explanation:

Just took the test

A 0.5 m rod of some material elongates 0.1 mm on heating from 20 to 112°C. Determine the value of the linear coefficient of thermal expansion [in (°C)-1] for this material.

Answers

Answer:linear coefficient of thermal expansion of the rod =2.17 x10^-6(°C)^-1

Explanation:

The Linear thermal expansion is calculated as

ΔL = αLΔT,

where ΔL = change in length L,

ΔT = the change in temperature,

α is the coefficient of linear expansion

Change in length ΔL= 0.1 mm =0.1/1000= 0.0001m

change in temperature,ΔT= Final - Initial temperature

= (112- 20)°C=92°C

Solving, we have that

ΔL = αLΔT

α=ΔL/LΔT

= 0.0001 / 0.5 x 92

=0.0001/46

=2.17 x10^-6 / °C

The  linear coefficient of thermal expansion of the rod, α =2.17 x10^-6(°C)^-1

Explain the major differences between designing buildings for earthquake resistance and for wind resistance.

Answers

Answer:

Earthquake's put vibration and seismic load on a building while wind puts a continuous force throughout the whole structure.

Explanation:

The most important difference between the design of a building that's resistent to earthquakes and resistant to high speed winds is that earthquake's put vibration and seismic load on a building while wind puts a continuous force throughout the whole structure.

Earthquake resistent building are equipped with a base that is isolated from the buildings with several layers of different material which absorb the vibration of the seismic waves and prevent them from reaching to the building.

Wind resistent buildings must have strong foundations and a sturdy structure/material that can withstand high pressure that the wind applies during events such as hurricanes.

I hope this answer helps.  

If a person runs a distance of 0.7 km in 3 min, what is his average speed in kilometres/hour ​

Answers

Answer:

14 km/hour

Explanation:

How does a project differ from an ongoing work effort?

Answers

Answer:

Projects have a fixed budget, while operations have to earn a profit to run the business. Projects are executed to start a new business objective and terminated when it is achieved, while operational work does not produce anything new and is ongoing.

Hope this helped!

When water levels on the exterior of a building exceed water levels on the interior, hydrostatic loads become:_______

Answers

Answer: more dense

Explanation:

What did the US and USSR agree on in the INF Treaty? They agreed to reduce nuclear weapons. They agreed that new European nations would be democratic. They agreed to tear down the Berlin Wall. They agreed that the USSR should break into several countries.

Answers

Answer:

they agreed to reduce nuclear weapons

Answer:

A

Explanation:

Edu 2023

You have a 20 Volt power source attached to a light bulb that you've measured has a resistance of 8 Ohms, what is the power output of this light bulb (in Watts)?

Answers

Answer:

50 Watts

Explanation:

For this problem, we simply apply Ohm's law:

V = IR

V / R = I

P = IV

P = ( V / R ) V

P = ( V^2 / R )

P = (20 V)^2 / 8 Ω

P = 400 V^2 / 8 Ω

P = 50 Watts

Hence, the power consumed by the lightbulb is 50 Watts.

Cheers.

What are ethics in the engineering sector?​

Answers

Answer:

Engineering ethics is the field of a system of moral principles that apply to the practice of engineering. The field examines and sets the obligations by engineers to society, to their clients, and to the profession.

Explanation:

A metal shear can be used to cut flat stock , round stock , channel iron and which of the following?

Answers

Answer:

Angle Iron

Explanation:

Mark brainliest please.

3 mA are flowing through an 18 V circuit, how much resistance (in kΩ) is in that circuit?

Answers

Answer:

6kΩ

Explanation:

If we assume that the entire circuit's current is 3 mA, then we can compute the resistance within the circuit with the application of Ohm's law:

V = IR

V/I = R

R = V / I

R = 18V / 3 mA

R = 6kΩ

Hence, the resistance of the circuit is 6kΩ.

Cheers.

You have a 12 volt power source running through a circuit that has 3kΩ of resistance, how many amps (in mA) can flow through the circuit?

Answers

Answer:

4mA

Explanation:

For this problem, we will simply apply Ohm's law:

V = IR

V/R = I

I = V / R

I = 12 volt / 3kΩ

I = 4mA

Hence, the current in the circuit is 4mA.

Cheers.

What prevented this weld from becoming ropey?
A lower ampera
A higher voltage
The position of the weld
The stepping motion of the weld

Answers

Answer:

If I am not mistaken I believe it is a higher voltage.

Explanation:

Hope this helps

A, higher voltage is correct

Which option identifies the step skipped in the following scenario?

Eric is a newly hired engineer who has just ruined a prototype of a very expensive jet plane made from steel. He was short on time, so he rushed the molds of the body of the jet, causing them to crack. The cost incurred put the project far over budget.


He deviated from the design plans of the project.

He did not use the proper materials for the project.

He did not pay attention to the cost analysis of the project.

He did not allow the metal to cool properly when making molds.

Answers

Answer:

he didn't use the proper material

Answer:

A. He did not allow the metal to cool properly when making molds.

Explanation:

sup 100 point for you

Answers

Answer:

thanks! :D

Have a good day!

Answer:

Yay, :)

Thank you!!!

1:
Determine the dynamic pressure of water received at the site described below.



Water Tower holds water at an elevation of 265 feet

Site is at an elevation of 145 feet

The water supply system uses cast iron pipes.

The water travels through 3.2 miles of pipes before reaching the site

The pipe has a diameter of 8 inches

The water travels through 9 90-degree bends, 4 Branch tees, and 1 Swing Check Valve

The water has a flow rate of 105 gpm



Round to the hundredths place (2 places after the decimal)




2:
What is the static head of a water supply system if the water tower holds water at and elevation of 462 feet and the site that uses the water is at an elevation of 294 feet?
Answer value

Answers

Answer:

20.87 Pa

Explanation:

The formula for dynamic pressure is given as;

q= 1/2*ρ*v²

where ;

q=dynamic pressure

ρ = density of fluid

v = velocity of fluid

First find v by applying the formula for flow rate as;

Q = v*A   where ;

Q= fluid flow rate

v = flow velocity

A= cross-sectional area.

A= cross-sectional vector area of the pipe given by the formula;

A= πr² = 3.14 * 4² = 50.27 in²   where r=radius of pipe obtained from the diameter given divided by 2.

Q = fluid flow rate = 105 gpm----change to m³/s as

1 gpm = 0.00006309

105 gpm = 105 * 0.00006309 = 0.006624 m³/s

A= cross-sectional vector area = 50.27 in² -------change to m² as:

1 in² = 0.0006452 m²

50.27 in² = 50.27 * 0.0006452 = 0.03243 m²

Now calculate flow velocity as;

Q =v * A

Q/A = v

0.006624 m³/s / 0.03243 m² =v

0.2043 m/s = v

Now find the dynamic pressure q given as;

q= 1/2 * ρ*v²

q= 1/2 * 1000 * 0.2043² = 20.87 Pa

Select four items that an industrial engineer must obtain in order to practice in the field.

Answers

Industrial engineers devise efficient systems that integrate workers, machines, materials, information, and energy to make a product or provide a service.

Answer:

agriculture,defense,industry,science

Explanation:

Edg 2021

You have a motor that runs at 1.5 amps from a 12 volt power source, how many watts of power is it using?

Answers

Answer:

18 Watts

Explanation:

For this problem, we simply need to understand the relationship of power to voltage and current.  This relationship is derived from Ohm's law:

Power = Voltage * Current

Given this equation, we can say the following to find the power consumption of the motor:

Power = 12volts * 1.5amps

Power = 18 Watts

Hence, the motor is consuming 18 Watts of power.

Cheers.

Samantha is reviewing an engineer’s résumé for a design project involving equipment for an agricultural firm. What is it that she is looking for in his résumé?
The engineer must have humility.
The engineer must be a civil engineer.
The engineer must have the proper credentials.
The engineer must use materials from the US Green Building Council.

Answers

Answer:

i would say C

Explanation:

Answer:

c

Explanation:

ye

How to connect the wind turbines to the grid? Give advantages and disadvantages to your answer.​

Answers

Answer:

Electricity from the wind turbine generator travels to a transmission substation where it is converted into extremely high voltage, between 155,000 and 765,000 volts, for long distance transmission on the transmission grid. This grid comprises a series of power lines that connect the power sources to demand centers.The advantages of wind energy are more apparent than the disadvantages. The main advantages include an unlimited, free, renewable resource (the wind itself), economic value, maintenance cost, and placement of wind harvesting facilities.

A room is filled with saturated moist air at 25°C and a total pressure of 100 kPa. If the mass of dry air in the room is 100 kg, the mass of water vapor is:_______

a. 0.52 kg
b. 1.97 kg
c. 2.96 kg
d. 2.04 kg
e. 3.17 kg

Answers

Answer:the mass of water vapor is=d. 2.04 kg

Explanation:

The humidity ratio by mass is given as

x = mw / ma                                  (1)

where

mw = mass of water vapor

ma = mass of dry air

And also humidity ratio by pressure by  Ideal Gas Law is given as

x = 0.62198 pw / (pa - pw)                            (2)

where

pw = partial pressure of water vapor in moist air

pa = atmospheric pressure of moist air

Equating both equation we have that

Humidity ratio =  0.62198 pw / (pa - pw)= mw / ma      (3)

From the from the water table at 25°C,

water vapor partial pressure = 23.8 torr

 1 atm =760 torr.

1 atm = 101.325 kPa,

So, 760 torr =101.325 kPa,

Therefore 23.8 torr =3.173kPa

Humidity ratio =  0.62198 pw / (pa - pw)= mw / ma  

0.62198 x 3.173 / (100-3.173)= mw / 100

1.9736 /96.827=mw/100

0.0204=mw/100

mw=2.04kg

Tech a says you should push the wrench when braking a fastener loose. Tech b says that you should pull the wrench when braking a fastener loose. Who is correct?

Answers

Answer:

tech b because gut feeling

Explanation:

A pointer is spun on a fair wheel of chance having its periphery labeled Trom 0 to 100. (a) Whhat is the sample space for this experiment? (b)What is the probability that the pointer will stop between 20 and 35? (c) What is the probability that the wheel will stop on 58?

Answers

Answer:

A pointer is spun on a fair wheel of chance having its periphery labeled Trom 0 to 100. (a) Whhat is the sample space for this experiment? (b)What is the probability that the pointer will stop between 20 and 35? (c) What is the probability that the wheel will stop on 58?

Explanation:

thats all you said

Answer:

hii my name is RAGHAV what is your name

Explanation:

this question is which chapter

A well-insulated heat exchanger has one line with 2 kg/s of air at 125 kPa and 1000 K entering, and leaving at 100 kPa and 400 K. The other line has 0.5 kg/s water entering at 200 kPa and 20 °C, and leaving at 200 kPa. Calculate the exit temperature of the water and the total rate of entropy generation?

Answers

Answer:

120°C

Explanation:

Step one:

given data

T_{wi} = 20^{\circ}C

T_{Ai}=1000K

T_{Ae}= 400kPa

P_{Wi}=200kPa

P_{Ai}=125kPa

P_{We}=200kPa

P_{Ae}=100kPa

m_A=2kg/s

m_W=0.5kg/s

We know that the energy equation is

[tex]m_Ah_{Ai}+m_Wh_W=m_Ah_{Ae}+m_Wh_{We}[/tex]

making [tex]h_{We}[/tex] the subject of formula we have

[tex]h_{We}=h_{Wi}+\frac{m_A}{mW}(h_A-h_{Ae})[/tex]

from the saturated water table B.1.1 , corresponding to  [tex]T_{wi}= 20c[/tex]

[tex]h_{Wi}=83.94kJ/kg[/tex]

from the ideal gas properties of air table B.7.1 , corresponding to T=1000K

the enthalpy is:

[tex]h_{Ai}=1046.22kJ/kg[/tex]

from the ideal gas properties of air table B.7.1 corresponding to T=400K

[tex]h_{Ae}=401.30kJ/kg[/tex]

Step two:

substituting into the equation we have

[tex]h_{We}=h_{Wi}+\frac{m_A}{mW}(h_A-h_{Ae})[/tex]

[tex]h_{We}=83.94+\frac{2}{0.5}(2046.22-401.30)\\\\h_{We}=2663.62kJ/kg[/tex]

from saturated water table B.1.2 at [tex]P_{We}=200kPa[/tex]  we can obtain the specific enthalpy:

[tex]h_g=2706.63kJ/kg[/tex]

we can see that [tex]h_g>h_{Wi}[/tex], hence there are two phases

from saturated water table B.1.2 at [tex]P_{We}=200kPa[/tex]

[tex]T_{We}=120 ^{\circ} C[/tex]

True or false Osha engineering controls are the last strategy of control an employer should use for job hazards

Answers

Answer:

false

Explanation:

A well is located in a 20.1-m thick confined aquifer with a conductivity of 14.9 m/day and a storativity of 0.0051. If the well is pumped at a constant rate of 500 gpm, what is the drawdown at a distance of 7.0 m from the well after 1 day of pumping?

Answers

Answer:

S = 5.7209 M

Explanation:

Given data:

B = 20.1 m

conductivity ( K ) = 14.9 m/day

Storativity  ( s ) = 0.0051

1 gpm = 5.451 m^3/day

calculate the Transmissibility ( T ) = K * B

                                                       = 14.9 * 20.1 = 299.5  m^2/day

Note :

t = 1

U = ( r^2* S ) / (4*T* t )

  = ( 7^2 * 0.0051 ) / ( 4 * 299.5 * 1 ) = 2.0859 * 10^-4

Applying the thesis method

W(u) = -0.5772 - In(U)

       = 7.9

next we calculate the pumping rate from well ( Q ) in m^3/day

= 500 * 5.451 m^3 /day

= 2725.5 m^3 /day

Finally calculate the drawdown at a distance of 7.0 m form the well after 1 day of pumping

S = [tex]\frac{Q}{4\pi T} * W (u)[/tex]

 where : Q = 2725.5

               T = 299.5

               W(u)  = 7.9

substitute the given values into equation above

S = 5.7209 M

Propylene (C3H6) is burned with 50 percent excess air during a combustion process. Assuming complete combustion and a total pressure of 105 kPa. Determine:

a. the air-fuel ratio
b. the temperature at which the water vapor in the products will start condensing.

Answers

Answer:

44.59°c

Explanation:

Given data :

Total pressure = 105 kpa

complete combustion

A) Determine air-fuel ratio

A-F = [tex]\frac{N_{air} }{N_{fuel} } = \frac{(Nm)_{air} }{(Nm)_{c} (Nm)_{n} }[/tex]

N = number of mole

m = molar mass

A-F = [tex]\frac{(6.75*4.76)kmole * ( 29kg/mol)}{(3kmole)* 12kg/mol + (6kmol)*(1kg/mol)}[/tex]  =  22.2 kg air/fuel

hence the ratio of Fuel-air = 1 : 22.2

B) Determine the temperature at which water vapor in the products start condensing

First we determine the partial  pressure of water vapor before using the steam table to determine the corresponding saturation temp

partial pressure of water vapor

Pv = [tex]\frac{(N_{water vapor}) }{N_{pro} } * ( P_{ro} )[/tex]

N watervapor ( number of mole of water vapor ) = 3

N pro ( total number of mole of product = 3 + 3 + 2.25 + 25.28 = 33.53 kmol

Pro = 105

hence Pv = ( 3/33.53 ) * 105 =  9.39kPa

from the steam pressure table the corresponding saturation temperature to 9.39kPa =  44.59° c

Temperature at which condensing will start = 44.59°c

An equation showing the products of propylene with their mole numbers is attached below

1. Every employer shall keep the records of all accidents, dangerous occurrences, occupation
diseases and occupational poisoning at the workplace for​

Answers

l/blouoojiklnkjhljm,jl,mj l, j/ll

The regulations require various records to be kept for a minimum period of 3 years. Such records must be kept at the place where the work to which they relate is carried on or, if this is not practicable, at the responsible persons place of business. Such records must include The date and time of the occurrence.
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