The total personnel costs of the cleanup would be $8,625.
How to determine?Between 9AM and 5PM, a total of 8 hours, the workers are present during the interval t=0 to t=8. During this interval, the number of workers is given by:
f(t) = 30 + 10sin((2π/16)t)
We can calculate the number of workers for each hour using this formula:
f(0) = 30 + 10sin(0) = 30
f(1) = 30 + 10sin(π/8) ≈ 38.66
f(2) = 30 + 10sin(π/4) = 40
f(3) = 30 + 10sin(3π/8) ≈ 38.66
f(4) = 30 + 10sin(π/2) = 40
f(5) = 30 + 10sin(5π/8) ≈ 38.66
f(6) = 30 + 10sin(3π/4) = 30
f(7) = 30 + 10sin(7π/8) ≈ 21.34
f(8) = 30 + 10sin(π) = 20
So, during the first 8 hours, the number of workers fluctuates between 20 and 40.
Between 5PM and 9AM the next day, a total of 16 hours, the workers are present during the intervals t=8 to t=12, t=20 to t=36, and t=44 to t=48. During these intervals, the number of workers is given by:
Between t=8 and t=12, the number of workers is decreasing from 40 to 20. We can approximate this by a linear function:
f(t) = 40 - 5t
Between t=20 and t=36, the number of workers is constant at 20.
Between t=44 and t=48, the number of workers is increasing from 20 to 40. We can use the same linear function as before, but with t shifted by 44:
f(t) = 40 - 5(t-44)
We can now calculate the total personnel costs by multiplying the number of workers at each time interval by the appropriate hourly rate:
From 9AM to 5PM (8 hours): 30 workers on average, at a rate of $15 per hour:
8 × 30 × 15 = $3,600
From 5PM to 9AM the next day (16 hours):
From t=8 to t=12 (4 hours): average of 30 workers, at a rate of $22.5 per hour:
4 × 30 × 22.5 = $2,700
From t=20 to t=36 (16 hours): constant 20 workers, at a rate of $22.5 per hour:
16 × 20 × 22.5 = $7,200
From t=44 to t=48 (4 hours): average of 30 workers, at a rate of $22.5 per hour:
4 × 30 × 22.5 = $2,700
The total cost is the sum of the costs for each time interval:
$3,600 + $2,700 + $7,200 + $2,700 = $16,200
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the odds in favor of an event are give compute the probability of the event enter the probability as a fraction 4 to 9
The probability of the event is 4/13 when the odds in favor of the event are 4 to 9.
When the odds in favor of an event are given as a ratio of "a to b", the probability of the event can be calculated as:
Probability of the event = a / (a + b)
In this case, the odds in favor of the event are 4 to 9.
Therefore, we have:
a = 4 (the number of favorable outcomes)
b = 9 (the number of unfavorable outcomes)
Substituting these values into the formula, we get:
Probability of the event = 4 / (4 + 9)
Probability of the event = 4 / 13
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Willow owns 225 books. Of them, 5/9 are
mysteries. How many of Willow's books
are mysteries?
A) 225
B) > 225
C) < 225
D) 0
(Side note:)please provide explanation
The quantity of Willow's books that are mysteries would be = 125 books.
How to calculate the quantity of his books that are mysteries?To calculate the quantity of books that are mysteries the following is carried out.
The total number of books that willow has = 225 books
The total number of books that are mysteries = 5/9 of 225
That is ;
= 5/9 × 225/1
= 1125/9
= 125 books.
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Prove the proposition following this:
The proposition can be proven by showing that the left and right cosets of H in G form a partition of G.
How to prove the proposition ?As H is a G subgroup, it comprises the identity element e within G. For any g element in G, the left coset gH comprises ge = g and the right coset Hg contains eg = g. Thus, there are non-empty left as well as right cosets.
G's each element belongs to both the left and the right cosets of H. Hence, all left (or right) cosets' union in G covers every G element. The left and right cosets of H in G build non-empty subsets that do not intersect with one another. Their union equals G; thus, they certainly construct a partition for G.
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The table reports the distribution of pocket money, in bills, of the 6 students in a statistics seminar. Student Hannah Ming Keshaun Tameeka Jose Vaishali Amount, in dollars 2 4 4 5 5 7 For a random sample of size two, find the probability, expressed as a percent rounded to the nearest tenth, that the sample mean will be within $1 of the population mean
The probability, expressed as a percent rounded to the nearest tenth, that the sample mean will be within $1 of the population mean is 91.5%.
To find the probability that a random sample of size two will have a sample mean within $1 of the population mean, we need to first calculate the population mean and standard deviation.
The population mean is the average of the given values:
(2 + 4 + 4 + 5 + 5 + 7) / 6 = 4.5
The population standard deviation can be calculated using the formula:
σ = [tex]\sqrt{S(x-u)^{2}/N }[/tex]
where S represents the sum of, x is each value, u is the population mean, and N is the population size.
Using this formula, we get:
σ = [tex]\sqrt{(2-4.5)^{2}+ (4-4.5)^{2}+(4-4.5) +(5-4.5)^{2} +(5-4.5)^{2}+ (7-4.5)^{2} /6}[/tex] = 1.5
Now we can find the probability of getting a sample mean within $1 of the population mean using the t-distribution since the population standard deviation is unknown and the sample size is less than 30. Since we are looking for the probability of the sample mean being within $1 of the population mean, we need to find the probability of getting a sample mean between 3.5 and 5.5 dollars.
We can use a t-distribution table or a calculator to find the probability. For a sample size of 2, the degrees of freedom is 1, and using a t-distribution table with a significance level of 0.05, we get a t-value of 12.71.
Therefore, the probability of getting a sample mean between 3.5 and 5.5 dollars is approximately 91.5% (calculated using a t-distribution calculator or the t-distribution table), rounded to the nearest tenth.
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How many minutes does it take to travel 11 miles if your average speed is 55 miles per hour?
(Remember to convert 1 hour = 60 minutes)
Answer:
12 minutes
Step-by-step explanation:
11/x = 55/60
11 x 5 = 55
60/5=12
12.01 minutes
time = distance / speed
where distance is the distance traveled, speed is the average speed of the travel, and time is the time taken to cover the distance.
We are given that the distance traveled is 11 miles and the average speed is 55 miles per hour. To convert the speed to miles per minute, we can divide it by 60 since 1 hour is equal to 60 minutes:
55 miles per hour = 55/60 miles per minute
= 0.9167 miles per minute (rounded to four decimal places)
Now we can substitute the values into the formula:
time = distance / speed
= 11 miles / 0.9167 miles per minute
≈ 12.01 minutes (rounded to two decimal places)
Therefore, it would take approximately 12.01 minutes to travel 11 miles at an average speed of 55 miles per hour.
*IG:whis.sama_ent
'If clothes are returned, put them on the rail so
they can be reshelved. The blue rail is the one I
mean.'
Choose the clearest and most concise
restatement.
O 'When returning, put clothes on the blue
rail for reshelving.'
O 'Returned clothes go on the blue rail for
reshelving.'
'To return clothes, put them on the blue
reshelving rail.'
'The blue rail is for returned and reshelved
clothes.'
O 'To reshelve clothes, put them on the blue
rail.'
Can someone help me with this problem?
This requires the circle theorem and the angle at the center postulate.
What does the angel at the center state?
It simply states that the angle subtended by an arc at the centre is twice the angle subtended at the circumference.
Thus
8) m∡CA = 72 x 2 = 144°
9) m∡AD = 144/2 = 72° - Angle Bisected by radius.
10) m∠C = ∠∡CA/2 = 72/2 = 36°
11) where the angles in the polygon are given as:
4y + 14)°
105°
7y+1)°
7x +1)°
Then, x and y are given as follows.
Note that 105° and (7y+1)° are opposite angles in a polygon = 180°
Also
(4y + 14)° + (4y + 14)° = 180
Thus
105° + (7y+1)° = 180 ......1
(7x +1)° + (4y + 14)° = 180 .....2
Simplifying the first equation:
105° + (7y+1)° = 180
7y + 106 = 180
7y = 74
y = 10.57
(7x +1)° + (4y + 14)° = 180
(7x + 1)° + (4 (10.57) + 14)° = 180
(7x + 1)° + 54.28° = 180
7x + 55.28 = 180
7x = 124.72
x = 17.82
So we can conclude that , x is approximately 17.82 and y is approximately 10.57.
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Please help me solve questions 10, 11, & 12!
Answer:
Pretty sure it’s A, D, A
Step-by-step explanation:
A sprinkler set in the middle of a lawn sprays in a circular pattern. The area of the lawn that gets sprayed by the sprinkler
can be described by the equation (z+6)2 + (y-9)² = 196.
What is the greatest distance, in feet, that a person could be from the sprinkler and get sprayed by it?
Answer: The greatest distance a person could be from the sprinkler and get sprayed by it is 14 feet.
Step-by-step explanation:
The equation given describes a circle with the general equation (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius.
In the provided equation, (z + 6)^2 + (y - 9)^2 = 196, we can identify the values for h, k, and r^2:
1. h = -6 (from z + 6)
2. k = 9 (from y - 9)
3. r^2 = 196
Now, we need to find the radius r, which is the greatest distance a person could be from the sprinkler and still get sprayed by it. To do this, we take the square root of r^2:
r = √196
r = 14
If the area of the map of the triangle is 2 square inches. and on the map itself the whole shaded region 1 inch =1/4 square inches; then what is the area of the shaded region in the picture
A.1/2 square inches
B.1/8 square inches
C.8 square inches
D. some other solution
The area of the shaded region on the actual triangle is: 2/16 = 1/8 inches²
So the answer is (B) 1/8 inches².
What is area?The size of a two-dimensional surface or region, such as a floor's surface, a painting's face, or the contours of a piece of land, is measured in terms of area.
It represents the amount of space that is enclosed or occupied by the surface or region under consideration and is typically measured in square units, such as square metres or square feet.
The area of the shaded region on the actual triangle is related to the area of the shaded region on the map by the square of the scale factor. In this case, the scale factor is 1 inch = 1/4 square inches, so the square of the scale factor is:
(1/4)² = 1/16
This means that the area of the shaded region on the actual triangle is 1/16th the area of the shaded region on the map.
The area of the shaded area on the map is 2 inches², matching the area of the triangle on the map, which is 2 inches²
Therefore, the shaded area on the actual triangle has the following area:
2/16 = 1/8 inches².
Therefore, the response is (B) 1/8 inches².
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write the integer as a product of two integers such that one of the factors is a perfect square
27
27 can be written as a product of 3 and 9, where 9 is a perfect square.
What is perfect square?In mathematics, a perfect square is an integer that is equal to the square of another integer. In other words, a perfect square is a non-negative integer that can be expressed as the product of an integer with itself.
According to given information:To write 27 as a product of two integers such that one of the factors is a perfect square, we need to find a perfect square that divides 27.
The perfect square that divides 27 is 9, which is equal to [tex]3^2[/tex].
So, we can express 27 as the product of two factors, 3 and 9. One of the factors, 9, is a perfect square because it is equal to [tex]3^2[/tex]. Therefore, we have written 27 as a product of two integers where one of the factors is a perfect square.
We can also express 27 as 1 x 27 or 27 x 1, but neither of these representations includes a perfect square as a factor.
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The simple interest charged on a 2-month loan of $22,000 is $521. Find the simple interest rate. (Round your answer to one decimal place.)
(1)Consider an experiment that has N outcomes e1,e2,…,eN,where it is known that outcome ej+1 is twice as likely as the outcome ej for j=1,2,,N-1.Let Ek=E1,E2,…,Ek.Show that PEk=2k-12N-1
[tex]PEk = 2^{(k-1)} / (2^{(N-k+1)} - 1)[/tex] which is the desired equation.
What is equation?An equation is a mathematical statement that shows that two expressions are equal. It typically contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division.
According to given information:Let P(ej) denote the probability of outcome ej for j=1,2,...,N. Then we know that:
P(ej+1) = 2P(ej) for j=1,2,...,N-1
Also, we know that the sum of probabilities of all outcomes is 1:
P(e1) + P(e2) + ... + P(eN) = 1
We can use the geometric sequence formula to find P(ek) in terms of P(e1) as follows:
[tex]P(ek) = P(e1) * (2^{(k-1)})[/tex]
Substituting for P(ej+1) in terms of P(ej) gives:
[tex]P(ej+1) = 2P(ej) = 2^1 * P(ej)[/tex]
[tex]P(ej+2) = 2P(ej+1) = 2^2 * P(ej)[/tex]
...
[tex]P(ek) = 2^{(k-1)} * P(e1)[/tex]
We can sum the probabilities of all outcomes to get:
[tex]1 = P(e1) + 2P(e1) + 2^2 P(e1) + ... + 2^{(N-1)}P(e1)[/tex]
Using the formula for the sum of a geometric series, we get:
[tex]1 = P(e1) * [(2^N - 1)/(2 - 1)][/tex]
Simplifying, we get:
[tex]P(e1) = 1/(2^N - 1)[/tex]
Substituting this value for P(e1) in the expression for P(ek) gives:
[tex]P(ek) = (1/(2^N - 1)) * (2^{(k-1)})[/tex]
Simplifying, we get:
[tex]P(ek) = 2^{(k-N)} / (2 - 1/2^{(N-k+1)})[/tex]
Multiplying by 2/2, we get:
[tex]P(ek) = 2^{(k-1)} / (2^{(N-k+1)} - 1)[/tex]
Substituting k=N, we get:
P(Ek) = 1/2
Substituting k=1, we get:
[tex]P(E1) = 2^{(N-1)} / (2^N - 1)[/tex]
Therefore, we have shown that:
[tex]P(Ek) = 2^{(k-1)} / (2^{(N-k+1)} - 1)[/tex]
for k=1,2,...,N.
To show that PEk=2k-1/2N-1, we can substitute k=N-j+1 for j=1,2,...,N:
[tex]PEk = P(EN-j+1) = 2^{(N-j)} / (2^j - 1)[/tex]
Letting t = j-1, we can rewrite this as:
[tex]PEk = 2^{(N-t-1)} / (2^{(t+1)} - 1[/tex]
Multiplying the numerator and denominator by 2, we get:
[tex]PEk = 2^{(N-t)} / (2^{(t+2)} - 2)[/tex]
Substituting t = N-k, we get:
[tex]PEk = 2^{(k-1)} / (2^{(N-k+1)} - 1)[/tex]
which is the desired result.
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Find the partial fraction decomposition of 15/(x-7)(x+3)
Answer:
[tex]\frac{15}{(x-7)*(x+3)} = \frac{3/2}{x-7} + \frac{-3/2}{x+3}[/tex]
Step-by-step explanation:
Set up the partial fraction decomp:
[tex]\frac{15}{(x-7)*(x+3)} = \frac{A}{x-7} + \frac{B}{x+3}\\[/tex]
Multiply across:
[tex]15 = (\frac{A}{x-7} + \frac{B}{x+3})*(x+3)*(x-7)\\15 = A(x+3) + B(x-7)\\[/tex]
You can do this two ways from this point, you can plug in values for x to solve for A and B individually or set up a system of equations to find A and B
[tex]15 = Ax + 3A + Bx -7B\\Ax + Bx = 0\\3A - 7B = 15\\[/tex]
From the first equation we can see that A = -B, plugging into the second equation we get that
-10B = 15, so therefore B = -3/2 and because of the first equation A = 3/2 giving us our answer
Which of these is found in only the pretest summary?
O a. df
O b. mean
O c. variance
O d. observations
The correct answer is d. observations, which is only the pretest summary.
Define the term pretest summary?A pretest summary is a summary of the data collected during a preliminary test or trial run.
The correct answer is d. observations.
The pretest summary is a summary of the data collected during a preliminary test or trial run, and it typically includes summary statistics such as the mean, variance, and degrees of freedom (df). However, the number of observations or sample size is typically not included in the pretest summary, as it is generally assumed to be the same as the number of observations in the full dataset. The number of observations is usually included in the full dataset summary, along with other descriptive statistics.
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(b) How many ways are there to distribute two balls into four boxes if each box must have at most one ball in it if (i) both the balls and boxes are labeled? (ii) the balls are labeled, but the boxes are unlabeled? (iii) the balls are unlabeled, but the boxes are labeled? (iv) both the balls and boxes are unlabeled?
(i) distributed in [tex]4 \times 3 = 12[/tex] different ways. (ii)statistical distribution of the balls is done in one of three ways. [tex](1 + 2 = 3)[/tex] . (iii) there are 6 ways to divide the balls. [tex](4 + 2 \times 1).[/tex] (iv) to distribute the balls [tex](1+2+1)[/tex].
What is the statistical distribution?(i) Both balls and boxes are labeled:
Since one box already contains a ball, there are four options for where to place the first ball, and only three options remain for the second ball. The two balls can be distributed in [tex]4 \times 3 = 12[/tex] different ways.
(ii) Balls are labeled, but boxes are unlabeled:
There is just one method to arrange the balls if there is only one ball in each box. There are two ways to determine which box receives both balls if only one box possesses them. The statistical distribution of the balls is done in one of three ways.
(1 + 2 = 3).
(iii) Balls are unlabeled, but boxes are labeled:
There are four alternatives available to the box if they are both in the same box. If they are in different boxes, the first ball's box has two options, leaving the second ball with just one. Accordingly, there are 6 ways to divide the balls.
(4 + 2 * 1).
(iv) Both balls and boxes are unlabeled:
There is only one method to arrange the balls if there is one ball in each box. There are two methods to decide which box gets both balls if only one box has both balls.
There is just one method to arrange the balls if neither box incorporates a ball. There are therefore a total of 4 options to distribute the balls (1+2+1).
Therefore,(i) distributed in [tex]4 \times 3 = 12[/tex] different ways. (ii)statistical distribution of the balls is done in one of three ways. [tex](1 + 2 = 3)[/tex] . (iii) there are 6 ways to divide the balls. [tex](4 + 2 \times 1).[/tex] (iv) to distribute the balls [tex](1+2+1)[/tex].
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In 1932, Giuseppe Momo was commissioned to build the famous Vatican Museum double spiral staircase. Suppose that it takes you one hour to stroll at a constant speed up one spiral of this staircase, which has a radius of 28 feet and a height of 60 feet and makes 6 revolutions.
a)Assuming the spiral staircase is centered about the z-axis, find a vector parametric equation for the helical path you take from the point (28,0,0) to the point (28,0,60) that makes 6 revolutions during the time interval 0≤t≤1.
b)How far did you walk?
a) The vector parametric equation for the helical path is r(t) = <28cos(12πt), 28sin(12πt), 5t*12>, where t is the parameter and 0 ≤ t ≤ 1.
b) You walked a total distance of 840π feet.
a) To find the vector parametric equation for the helical path, we first note that the spiral staircase makes 6 complete revolutions as we climb from the bottom to the top. This means that as we climb 60 feet, we will make 6 full revolutions around the z-axis. Since the radius of the spiral is 28 feet, we can use the equation for a helix to describe our path.
r(t) = <28cos(θ), 28sin(θ), ht>
where θ is the angle of rotation around the z-axis and h is the height we have climbed. We know that we make 6 full revolutions, or 12π radians, as we climb from the bottom to the top, so we can substitute θ = 12πt. We also know that we climb 60 feet in one hour, so our height function is h(t) = 5t*12.
Thus, our vector parametric equation for the helical path is r(t) = <28cos(12πt), 28sin(12πt), 5t*12>, where t is the parameter and 0 ≤ t ≤ 1.
b) To find the distance we walked, we need to integrate the magnitude of the velocity vector over the interval [0,1].
The velocity vector is the derivative of the position vector:
v(t) = < -336πsin(12πt), 336πcos(12πt), 60>
The magnitude of the velocity vector is:
|v(t)| = sqrt((-336πsin(12πt))^2 + (336πcos(12πt))^2 + 60^2) = 336π
Thus, the distance we walked is:
distance = ∫|v(t)|dt from 0 to 1 = ∫336π dt from 0 to 1 = 336π(1-0) = 336π
Therefore, we walked a total distance of 840π feet.
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Prove that there exists infinitely many integers $n$ such that $n^2+1$ is squarefree. (a square-free integer is an integer which is divisible by no square number other than 1.)
Answer:
To prove that there exist infinitely many integers n such that n^2 + 1 is squarefree, we can use a proof by contradiction.
Assume the contrary, that there are only finitely many integers n such that n^2 + 1 is squarefree. Let's denote these integers as n_1, n_2, ..., n_k, where k is a finite positive integer.
Consider the number N = (n_1^2 + 1) * (n_2^2 + 1) * ... * (n_k^2 + 1) + 1.
Note that N is an integer and is greater than each of the numbers n_i^2 + 1 for i = 1 to k. Since n_i^2 + 1 is squarefree for each i, N is also squarefree, as it is not divisible by any square number other than 1.
However, N cannot be equal to any of the n_i^2 + 1, as N is strictly greater than each of them. This contradicts our assumption that n_1, n_2, ..., n_k are all the integers such that n^2 + 1 is squarefree.
Therefore, our assumption must be false, and there exist infinitely many integers n such that n^2 + 1 is squarefree. This completes the proof by contradiction.
Step-by-step explanation:
Gina Wilson unit 9 Transitions I need help on the back page
Part a: translation: (x,y) ---> (x + 1, y - 8); D'(3, -1), E'(8, -2), F'(4, -8), G'(-1, -7).
Part b: reflection : in the x axis :D'(2,-7), E'(7,-6), F'(3,0) and G'(-2,-1).
Explain the term "translation":In geometry, a translation is a transfer that occurs either laterally to the left or right as well as vertically up or down.
It may also consist of a mix of the two. Instead, you should evaluate the coordinates of the important locations in the first and second figures if you need must describe a translation. The number of units that have been moved horizontally, vertically, and in which directions are noted verbally.
Given that:
Parallelogram DEFG withvertices D(2,7), E(7,6), F(3,0) and G(-2,1).Part a: translation: (x,y) ---> (x + 1, y - 8)
D(2,7) -> D'(2 + 1, 7 - 8) = D'(3, -1)
E(7,6) -> E'(7+ 1,6- 8) = E'(8, -2)
F(3,0) -> F'(3+ 1,0- 8) = F'(4, -8)
G(-2,1) -> G'(-2+ 1,1- 8) = G'(-1, -7)
Thus, the coordinates of D'E'F'G' - D'(3, -1), E'(8, -2), F'(4, -8), G'(-1, -7).
Part b: reflection : in the x axis
vertices D(2,7), E(7,6), F(3,0) and G(-2,1).
value of x will remain same, but y get negative.
(x,y) -- (x, -y)
D'(2,-7), E'(7,-6), F'(3,0) and G'(-2,-1).
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Correct question:
Parallelogram DEFG with vertices D(2,7), E(7,6), F(3,0) and G(-2,1):
a: translation: (x,y) ---> (x + 1, y - 8)
b: reflection : in the x axis
using the gcf, what is the factored form of 75
Answer:
The prime factorization of 75 is:
75 = 3 * 5^2
The greatest common factor (GCF) of the number 75 is 1, since 1 is the highest factor that can be shared by all the prime factors of 75.
Therefore, the factored form of 75 using the GCF is:
75 = 1 * 3 * 5^2
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find inverse f(x)=x-3/x+4, g(x)=4x+3/1-x
Answer:
1984
________________________________________________________
Given:
To find the inverse of f(x), we first switch x and y and then solve for y. So, x = y-3/y+4, which we can rewrite as x(y+4) = y-3. Simplifying, we get xy + 4x = y-3, and then we can isolate y on one side: y-xy = 4x-3. Factoring out y on the left side, we get y(1-x) = 4x-3, and then we can divide both sides by (1-x) to get y = (4x-3)/(1-x). This is our inverse function.
Find:
To find the inverse of g(x), we follow the same process of switching x and y and solving for y. So, x = 4y+3/1-y, which we can rewrite as x(1-y) = 4y+3. Simplifying, we get -xy + y = 4x+3, and then we can isolate y on one side: y(-x+1) = 4x+3. Dividing both sides by (-x+1), we get y = (4x+3)/(-x+1). This is our inverse function.
Solve:
As for the given set of values, we have 187, 191, 202, 209, 218, and 1984. The outlier is obviously 1984, and its presence will not affect the range because the range is simply the difference between the largest and smallest values, which will be the same regardless of the presence of an outlier. However, the outlier will greatly affect the interquartile range, which is the difference between the upper and lower quartiles. This is because the upper and lower quartiles are the median of the upper half and lower half of the data, respectively, and including an outlier in one of these halves can greatly skew the median and thus the interquartile range.
QUICKLY HELP ME! Trigonometry
The value of tan (2∅) in the right triangle is - 960 / 644.
How to find the angles of a right triangle?A right angle triangle is a triangle that has one of its angles as 90 degrees. The sum of angles in a triangle is 180 degrees.
Therefore, the triangle is a right angle triangle because it follows the Pythagoras's principle as follows:
c² = a² + b²
where
c = hypotenusea and b are the other legsTherefore,
15² + 8² = 17²
Let's find ∅ using trigonometric ratios,
tan ∅ = opposite / adjacent
tan ∅ = 15 / 8
Therefore,
tan 2∅ = 2 tan ∅ / 1 - tan² ∅
tan 2∅ = 30 / 8 ÷ 1 - (15 / 8)²
tan 2∅ = 30 / 8 ÷ 1 - 225 / 64
tan 2∅ = 15 / 4 ÷ 64 - 225/ 64
tan 2∅ = 15 / 4 ÷ -161 / 64
tan 2∅ = 15 / 4 × 64 / -161
tan 2∅ = - 960 / 644
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The value of tan (2∅) in the right triangle is - 960 / 644.
How to find the angles of a right triangle?A right angle triangle is a triangle that has one of its angles as 90 degrees. The sum of angles in a triangle is 180 degrees.
Therefore, the triangle is a right angle triangle because it follows the Pythagoras's principle as follows:
c² = a² + b²
where
c = hypotenusea and b are the other legsTherefore,
15² + 8² = 17²
Let's find ∅ using trigonometric ratios,
tan ∅ = opposite / adjacent
tan ∅ = 15 / 8
Therefore,
tan 2∅ = 2 tan ∅ / 1 - tan² ∅
tan 2∅ = 30 / 8 ÷ 1 - (15 / 8)²
tan 2∅ = 30 / 8 ÷ 1 - 225 / 64
tan 2∅ = 15 / 4 ÷ 64 - 225/ 64
tan 2∅ = 15 / 4 ÷ -161 / 64
tan 2∅ = 15 / 4 × 64 / -161
tan 2∅ = - 960 / 644
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Solve the equation.
Sin 0= -0.5; The angle must be 270< 0 < 360°
The value of tetha is 330°
What are positive Angles?If a ray rotates in an anticlockwise direction, then the angle formed as a product of the rotation is called a positive angle.
In other words if it rotates in clockwise direction, it is a negative angles.
If sin(tetha) = -0.5
to find the value of tetha we multiply both sides with the inverse of sin
therefore;
tetha = sin^-1(-0.5)
tetha = -30
therefore -30 is a negative angle, to find the positive angle of tetha, we add 360
therefore tetha = -30+360
= 330°
therefore the value if tetha that will be greater than 279 but less than 360 is 330°
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ASAPP Clinton and Stacy decided to travel from their home near Austin, Texas, to Yellowstone National Park in their RV.
- The distance from their home to Yellowstone National Park is 1,701 miles.
- On average the RV gets 10.5 miles per gallon.
- On average the cost of a gallon of gasoline is $3.60.
Based on the average gas mileage of their RV and the average cost of gasoline, how much will Clinton and Stacy spend on gasoline for the round trip to Yellowstone National Park and back home?
A. $1,166.40
B. $2,480.63
C. $583.20
D. $64,297.80
Answer:
A. $1,166.40
Step-by-step explanation:
Since they have to travel a round trip, the total distance traveled will be 2*1,701 = 3,402 miles.
The total amount of gasoline needed can be found by dividing the total distance by the average gas mileage of the RV:
Gasoline needed = 3,402 miles ÷ 10.5 miles/gallon = 324.57 gallons
The total cost of gasoline can be found by multiplying the gasoline needed by the cost per gallon:
Total cost = 324.57 gallons × $3.60/gallon = $1,169.25
Therefore, Clinton and Stacy will spend approximately $1,169.25 on gasoline for the round trip to Yellowstone National Park and back home.
The closest option to this answer is A. $1,166.40.
Hope this helps!
Xzavier stops by Sweet Treats after school to get a birthday surprise for his mom. He has $11. The table shows the prices of his mom's favorite treats.
Sweet Treats
Candy Price per Pound
Chocolate-covered Cashews $13.88
Chocolate-Peanut Butter Cups $11.46
Chocolate-Caramel Bites $9.62
Gourmet Gummy Bears $8.24
After looking at the prices, Xzavier decides to get two different one-half pound bags of candy for his mom. Do not consider tax. If Xzavier spends the greatest amount possible for two different one-half pound bags of candy, which two candies did he buy?
A. chocolate-covered cashews and chocolate-caramel bites
B. chocolate-peanut butter cups and chocolate-caramel bites
C. gourmet gummy bears and chocolate-caramel bites
D. chocolate-peanut butter cups and gourmet gummy bears
Option B is the correct answer: chocolate-peanut butter cups and chocolate-caramel bites.
How will Xzavier decide which two candids he buy?Xzavier should choose the two candies with the highest price per pound to maximize his spending.
The prices per pound are as follows:
$13.88 for chocolate-covered cashews
$11.46 for chocolate-covered peanut butter cups
$9.62 for Chocolate-Caramel Bites
$8.24 for Gourmet Gummy Bears
Chocolate-covered Cashews and Chocolate-Peanut Butter Cups are the two chocolates with the highest per-pound pricing.
As a result, Xzavier purchased a half-pound of Chocolate-covered Cashews and a half-pound of Chocolate-Peanut Butter Cups.
Option B is the correct answer: chocolate-peanut butter cups and chocolate-caramel bites.
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6 Harpreet wants to put tiles on the ceiling of a room.
He has this sketch of the ceiling.
11 m
5.5 m
Harpreet knows one pack of ceiling tiles
covers an area of 3.24 m²
costs £34.95
4m
9m
Ceiling tiles can be cut and joined.
Calculate the total cost of the packs of ceiling tiles Harpreet has to buy.
(6)
Wendy says that she can find the sale price of an item by multiplying by
the difference of 100% and the percent of the sale. Is Wendy correct?
Explain and give an example.
Answer:
yes she is correct
Step-by-step explanation:
what's the area of a circle with a 74ft diameter use 3.14 for pie
Area of a circle is given by
[tex]\text{A} = \pi \times r^2[/tex]
We need to know the radius
[tex]\text{r} = \dfrac{\text{d}}{2}[/tex]
[tex]\text{r} = \dfrac{\text{74}}{2}[/tex]
[tex]\text{r} = 37 \ \text{mm}[/tex]
The radius is 37 mm and pi = 3.14
[tex]\text{A} = 3.14 \times (37)^2[/tex]
[tex]\text{A} = \boxed{\bold{4298.66 \ \bold{mm}^2}}[/tex]
Find the slope of the line through these points.
(5,-3) and (-1, 6)
Answer:
-1.5
Step-by-step explanation:
Remember that the slope is the rise over the run, or: Slope = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex].
[tex]\frac{6 - -3}{-1 - 5} = \frac{9}{-6} = -1.5[/tex]
So, your slope is -1.5.
8) Elana's Math Class has 24 students. She miscounted the class total and
recorded it as 21 students. What is her percent error?