Answer:
The turntable's angular speed after the event is 28.687 revolutions per minute.
Explanation:
The system formed by the turntable and the two block are not under the effect of any external force, so we can apply the Principle of Conservation of Angular Momentum, which states that:
[tex]I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}[/tex] (1)
Where:
[tex]I_{T}[/tex] - Moment of inertia of the turntable, in kilogram-square meters.
[tex]r[/tex] - Distance of the block regarding the center of the turntable, in meters.
[tex]m[/tex] - Mass of the object, in kilograms.
[tex]\omega_{o}[/tex] - Initial angular speed of the turntable, in radians per second.
[tex]\omega_{f}[/tex] - Final angular speed of the turntable-objects system, in radians per second.
In addition, the momentum of inertia of the turntable is determined by following formula:
[tex]I_{T} = \frac{1}{2}\cdot M\cdot r^{2}[/tex] (2)
Where [tex]M[/tex] is the mass of the turntable, in kilograms.
If we know that [tex]\omega_{o} \approx 7.330\,\frac{rad}{s}[/tex], [tex]M = 1.5\,kg[/tex], [tex]m = 0.54\,kg[/tex] and [tex]r = 0.1\,m[/tex], then the angular speed of the turntable after the event is:
[tex]I_{T} = \frac{1}{2}\cdot M\cdot r^{2}[/tex]
[tex]I_{T} = 7.5\times 10^{-3}\,kg\cdot m^{2}[/tex]
[tex]I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}[/tex]
[tex]\omega_{f} = \frac{I_{T}\cdot \omega_{o}}{2\cdot r^{2}\cdot m +I_{T}}[/tex]
[tex]\omega_{T} = 3.004\,\frac{rad}{s}[/tex] ([tex]28.687\,\frac{rev}{min}[/tex])
The turntable's angular speed after the event is 28.687 revolutions per minute.
Examples of cell division: to grow larger, to repair injured tissue, reproduce through cell division.
Mitosis produces identical ____body____ cells.
Before a cell divides, it makes full copies of the DNA in its nucleus____this is called interphase_____.
Parent cell______original/old______: A cell that will divide or is dividing
Daughter cells_____copy/new_______: The 2 new cells that result from the division
Steps of the cell cycle:not equally divided in time
1.interphase
2.mitosis
3.cytokinesis
Answer:
try this
Explanation:
the cosmos just like humanity of earth its living like a mirror
A heavy rock and a light rock are dropped from the same height and experience no significant air resistance as they fall. Which of the following statements about these rocks are correct?O Just as they are about to reach the ground, the heavier rock has more kinetic energy than the lighter rockO The moment they were released, both rocks had the same amount of gravitational potential energy O Both rocks have the same kinetic energy when they reach the ground O The heavier rock reaches the ground before the lighter rock. .O Both rocks different acceleration as they are about to reach the ground
The correct statement about the rocks is Just as they are about to reach the ground, the heavier rock has more kinetic energy than the lighter rock.
As per the known fact, kinetic energy is the product mass, square of velocity and 0.5. Thus, it is due to the motion of object. Potential energy is the product mass, acceleration due to gravity and height. It is due to the height of object.
Also, momentum is another factor that will influence the results in situation mentioned in question. Based on this, momentum is the product of mass and velocity of the object. Considering momentum and kinetic energy, the heavier rock will have more kinetic energy.
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WILL GIVE BRAINLY - 14 points
A quarterback throws a football at 35 m/s at a certain angle above the horizontal. If it took the ball 8.98 s to reach the top of its path, how long was it in the air?
rearest hundreth pls!!
PS
and explain if u can :,) not needed but will help u get the brainliest answer!!!!!!!!!!!!!!!!1111
Answer:
17.96 s
Explanation:
To find the total time the ball was in the air, we need to first find the time it took to reach the top of its path and then double that time to find the total time in the air.
The time it took to reach the top of its path is given by: t = v/g
Substituting in the known values and solving for t, we get: t = 35 m/s / 9.8 m/s^2 = 8.98 s
To find the total time the ball was in the air, we need to double the time it took to reach the top of its path, so the total time in the air is: 2 * 8.98 s = 17.96 s
Rounding to the nearest hundredth, the total time the ball was in the air is 17.96 s. Therefore, the answer is 17.96.
A 6.0 kg bag of cat food is dropped from 5.0 m ledge. How much mechanical energy does
it have just before it strikes the ground?
Answer:
294
Explanation:
5x9.8x6=294
potential energy=5(9.8)(6)
Equation
PE=MGH
Chill the water as much as possible- then add heat and observe. List below at least three things you noticed (Make sure the energy symbols box is checked.) 1.When the water is being chilled the heat flows from the water to the ice. 2. When the water is being heated the heat flows from the fire to the water 3. When the water reaches a certain temperature heat energy begins to escape in the form of ga
1) Before the boiling point, the temperature of the water increases and it begins to boil. Boiling is the physical process by which a liquid changes to a gaseous state. It runs when the temperature of the entire liquid is equal to the boiling point of the liquid at that pressure. As the liquid continues to heat up, it absorbs heat, but without raising the temperature, it uses the heat to transform the substance from the liquid to the gaseous state, shifting the entire mass into the gaseous state. The heat that is generated in heating most of the liquid is called sensible heat, and the heat that appears during a change of state is called latent heat of boiling or vaporization.
2) Because iron is "closer" to its molecules, it can absorb more energy and, as a result, heat up faster. Instead, bricks have tiny air holes. That is, its molecules are "far away" and are not easily heated. As they conduct heat (conduction or convection), they lose energy.
3) When a piece of heated iron is placed in room temperature water, the iron gives off heat to the water (cooling) and the water receives heat (heating). Because the iron gives heat.
4) When you put a brick on top of an iron and heat it up, the iron heats up faster and starts heating the brick by conduction (because the material sticks together). In addition, the heat absorption capacity of the brick itself makes it warmer.
What is heat energy?
The term "thermal energy" is used loosely in various contexts of physics and engineering. We can refer to some well-defined physical concepts. These include the internal energy or enthalpy of matter and radiation. Heat (and thermodynamic work) defined as the mode of energy transfer. and the characteristic energies of the degrees of freedom of the system described by its microscopic particle content (where T denotes the temperature and Boltzmann constant).
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We cannot work without friction . why?
Answer:
thing will slide apart
Explanation:
Friction prevents objects from sliding apart. Everything would slide to the lowest point if there was no friction. It would be impossible to scale anything. We will be unable to write without friction.
Derrick created a table of his observations from one trial of an investigation into whether a charged object will attract or repel an uncharged object. Which statement best explains an incorrect conclusion you might believe without repeated trials? object trial 1 negatively charged attract positively charged nothing (2 points) O negatively charged objects repel uncharged objects. O negatively charged objects are attracted to uncharged objects. O positively charged objects do not attract or repel an uncharged object. O positively and negatively charged objects react differently to uncharged objects
The correct option for the question is an option (c) positively charged objects do not attract or repel an uncharged object.
The analysis of stationary electrically charged particles is known as electrostatics. The charge attached to matter, which causes it to produce and feel magnetic and electric activity, is known as the electric charge.
Paper scraps are drawn to a plastic rod when brushed with fur, and a glass rod when rubbed with silk, demonstrating the electrical charge of both rods.
According to Coulomb's law, two particles with the same charge repel one another while those that have the opposite charge attract one another. Between two charged particles, there is a considerably stronger electric force in comparison to the gravitational force.
Hence, the positively charged objects do not attract or repel an uncharged object. The right answer is option C.
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Now attach the 100 g mass to spring 1. Play the simulator. Using the stopwatch, measure the time for 10 complete cycles, (starting from down, lowest position, and then up, then hitting down again: is an example of one complete cycle). Calculate the measured period by dividing the total time by 10. We will call this value Tz. Pause the simulator. Remove the 100 grams mass from the hook of the spring.
By attaching a mass of 100 g too spring 1. Play the simulator. Measure the duration of the stopwatch for 10 full cycles. The measured period by dividing the total time by 10 is 2 seconds.
The period of oscillation of the mass on spring 1, you would need to measure the time it takes for the mass to complete 10 complete cycles. You can do this by starting a stopwatch when the mass is in the down position and stopping the stopwatch when the mass returns to the down position after completing 10 cycles. Once you have measured the total time for 10 complete cycles, you can calculate the period by dividing the total time by 10. For example, if the total time for 10 complete cycles is 20 seconds, then the period would be 20 seconds / 10 = 2 seconds. We will call this value Tz.
After measuring the period of oscillation of the mass on spring 1, you should pause the simulator and remove the mass from the hook of the spring. This will allow you to perform any additional measurements or calculations without interference from the mass.
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A 5.0 kg block with a speed of 3.0 m/s collides with a 10
kg block that has a speed of 2.0 m/s in the same direction.After the
collision, the 10 kg block travels in the original direction with a
speed of 2.5 m/s. (a) What is the velocity of the 5.0 kg block immediately after the collision? (b) By how much does the total kinetic
energy of the system of two blocks change because of the collision? (c) Suppose, instead, that the 10 kg block ends up with a
speed of 4.0 m/s. What then is the change in the total kinetic energy? (d) Account for the result you obtained in
(a) The first block moves at 4.0 m/s in the same direction right after colliding.
(b) the system's total kinetic energy changes by 28.75 J
(c) the system's total kinetic energy changes by -1.25 J
Given;
First block's mass, m1, is 5 kg.
u1 = 3.0 m/s is the first block's starting speed.
m2 weight of the second block is 10.0 kg.
u2 = 2.0 m/s is the second block's initial speed.
v2 = 2.5 m/s is the second block's final speed.
Immediately following the impact, the first block block's Part (A) velocity is as follows:
Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.
(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)
35= 2.5v₁ + 25
2.5v₁ = 35-25
2.5v₁ = 10
v₁ = 10/2.5
v₁ = 4
2.5 m/s in the same direction for v1.
Change in the system's overall kinetic energy, part (B):
Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.
ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)
ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).
ΔK = 71.25 J - 42.5 J
ΔK = 28.75 J
Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s
Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)
35 = 2.5v₁ + 40
2.5v₁ = -5
2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s
Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.
K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)
K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).
ΔK = 41.25 - 42.5 J
ΔK = -1.25 J
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a tennis ball is swung in a horizontal circle by a string. if the string is broken, which picture correctly shows the path the ball will take?
Initially rolling inside a horizontal circle five meters above the ground at a speed of two meters per second, the ball breaks the string as it approaches true North. Though it is falling, it is still heading in the direction
Why does string theory defy physics?The lower string, however, is the one that snaps if it is forcefully yanked. The prevailing theory holds that the mass's inertia prevents it from moving and, as a result, from pulling on the top string.
Which string will finally snap?If both strings are equally strong, the top string will break sooner. However, a change in tension from the lower string takes a moment to transfer because of the inertia of a hanging object.
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Air trapped inside a single-piston-cylinder exerts a pressure of 760 mmHg. If its volume is increased by 20% at a constant temperature, the pressure exerted would be equal to
he change in the pressure of the air trapped in the cylinder if its volume is increased by 20% at a constant temperature is 745 mmHg.
What is the change in the pressure of the air trapped in the cylinder?The change in the pressure of the air trapped in the cylinder if its volume is increased by 20% at a constant temperature is calculated from Boyle's law equation as follows:
The Boyle's law equation is given as follows:
P₁V₁ = P₂V₂
where;
P₁ is the initial pressure
V₁ is the initial volume
P₂ is the final pressure
V₂ is the final volume
From the data given,
P₁ = 760 mmHg
V₁ = V
P₂ = ?
V₂ = V + 0.2 V
V₂ = 1.02 V
P₂ = 760 * V / 1.02 V
P₂ = 745 mmHg
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When a force of 50 Newtons acts on a mass of 10 kg the resulting acceleration
Answer:
The answer is 5 m/s²
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
where
f is the force
m is the mass
From the question we have
We have the final answer as
5 m/s²
In an experiment, a student measured the volume of a substance while the mass was changed. The student measured up to five kilograms. The graph of the data is plotted below.
A volume versus mass graph is shown with mass on the vertical axes from 1 to 10 kilograms and volume on the horizontal axis from 1 to 5 milliliters. A line from the origin through all points and beyond.
Which of the following is an error the student made in creating an accurate graph?
The axes and graph are based only on measured values.
The axes are labeled with the incorrect variables.
The plotted points do not show all data collected.
The title has the incorrect order for the variables.
Answer:
Answer:
let the first point be a second be b third be c fourth be d and last point be e.
The point a and d are incorrect. because tye plotting of the is incorrect
shows a plot of potential energy u versus position x of a 0.200 kg particle that can travel only along an x axis under the influence
The plot of U versus x is given in the attachment below. The speed of the particle at x = 3.5 m is 8.37 m/s.
Here, the mechanical energy remains constant as the particle moves.
As, the mechanical energy is conserved, we can write, Ub + Kb = Ua + Ka
Making Ka as subject, we have,
Ka = Ub + Kb - Ua = 12 + 4 - 9 = 7 J
We know that, Ka = [m* (va)²]/2
The speed of the particle at x = 3.5m (within region A) is
va = √(2* Ka)/m = √(2* 7)0.2 = 8.37 m/s.
Thus, the speed at x = 3.5m is 8.37 m/s.
The question is incomplete. The complete question is ' Figure 8−49 shows a plot of potential energy U versus position x of a 0.200kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values : Ua = 9.00 J, Uc = 20.00 J, and Ud = 24.00 J. The particle is released at the point where U forms a potential hill of height Ub = 12.00 J, with kinetic energy 4.00 J. What is the speed of the particle at x = 3.5 m. The attachment below has the missing plot.
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Which of the following statements regarding the Roman use of concrete as a building material is FALSE?
O Concrete made rounded arches and curved buildings possible.
O Concrete was cheaper than cut stone.
O Concrete was more difficult to use than cut stone.
O Concrete required the use of less-skilled labor.
The Romans invented a new concrete recipe that combined pozzolana, a fine volcanic ash found in Southern Italy, with lime and water to make a strong, resistant kind of concrete.
The Roman term for concrete was opus caementicium, which meant that it was mixed with small stones. The Roman Empire's preferred building material was concrete. It has been utilized in monuments such as Rome's Pantheon, as well as wharves, breakwaters, and other harbor buildings. This is why concrete does not last as long as natural rocks. However, this is not how Roman concrete works. Theirs was made from volcanic ash, lime, and seawater, utilizing a chemical reaction that Romans may have observed in naturally cemented volcanic ash deposits known as tuff rocks.
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a load of 20kg is applied to the ends of wire 4m along and produce an extension of 0.24mm if the diameter of the wire is 2mm find the stress on the wire and strain producers
Answer:
Explanation: Force = mg as the wire is fixed at one point and the load is inserted at one end.
g=9.8m/s²
F= mg
F= 20×9.8= 19.6 newton
Strain= Δl/L
where Δl= change in length
and L= original length
Strain = 0.24×0.001 m/4m
Strain=0.00006
Stress= F/A
where A = cross sectional area
therefore A = π× (diametre/2)²
A=3.14×1²≈3.14 mm²= 0.000000314m²
Stress = 19.6/0.000000314=62420382 Pascal
For another identical object initially at rest, no frictional force is exerted during segment 2 (between t = 2 s and t = 4 s). A rope exerts the same constant force of magnitude F T as in the previous scenario. What is the change in the object's kinetic energy during segment 2?
Based on the information provided, there is a change of 12 Jules in the kinetic energy during segment 2.
What is kinetic energy?Kinetic energy can be defined as the energy produced by the motion of a body. Due to this, the level of energy can change depending on movement. The change in the kinetic energy can be calculated by considering the initial kinetic energy and the final kinetic energy. Moreover, the energy is measured using Joules.
What is the change in the kinetic energy during the segment 2?Let's consider first the information given:
Inital velocity = 4 m/sAcceleration= 2 m/s2Final velocity = 8 m/sBased on the velocity, let's caclulate the change in the kinetic energy:
Final Kinetic energy - Initial kinetic energy
1/2 x 0.5 (8^2-4^2) = 12 Joules
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Three resistors R1 = 87.6 Ω, R2 = 22.0 Ω, R3 = 70.0 Ω, and two batteries e m f1 = 40.0 V, and e m f2 = 364 V are connected as shown in the diagram below.
A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.
What is Resistors?They are present in practically all electrical networks and electronic circuits. Ohms () are used to measure resistance.
An ohm is the resistance that develops when a resistor has a one volt (V) drop across its terminals and a current of one ampere (A). The voltage across the terminal ends determines how much current flows.
There are numerous applications for resistors. Among some examples are voltage division, heat production, matching and loading circuits, gain control, and time constant setup. They have resistance ratings that span more than nine orders of magnitude and are marketed for use in various applications.
Therefore, A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.
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A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m as shown above. Question The magnitude of the net force on the block while it is sliding is most nearly
The magnitude of the net force on the block while it is sliding is most nearly is 14m/s when A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m.
What is magnitude?Magnitude in physics typically refers to a size or quantity. Simply put, "distance or quantity" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. What is Frictionless plane?The Plane by which no opposite force is applied on the sliding or moving object is termed as Frictionless plane.
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For the bar OC: mass=m, length=b, bar AB: mass=2m, length=2b ; for the slider A and B: mass=m. The angular velocity of OC is ω, (φ=60°?. Kinetic energy of the system T=?
The Kinetic energy of the system T = 6m * b² * ω² / 2
How do one calculate the Kinetic energy?The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force.
To find the kinetic energy of the system;
The kinetic energy of the bar OC is given by:
T_OC = 1/2 * m * b² * ω²
Note that:
m= Metre
b= Bar
ω = omega
The kinetic energy of the bar AB is given by:
T_AB = 1/2 * (2m) * (2b)² * ω²
The kinetic energy of the sliders A and B is given by:
T_A+B = 1/2 * m * v_A² + 1/2 * m * v_B²
where v_A and v_B are the velocities of sliders A and B, respectively.
To find the velocities of the sliders, we can use the relationship between the angular velocity of the bar OC and the linear velocities of the sliders:
v_A = b * ω * cos(φ)
v_B = b * ω * sin(φ)
Substituting these expressions into the equation for T_A+B, we get:
T_A+B = 1/2 * m * (b * ω * cos(φ))² + 1/2 * m * (b * ω * sin(φ))²
= 1/2 * m * b² * ω² * (cos^2(φ) + sin²(φ))
= 1/2 * m * b² * ω²
Since cos²(φ) + sin²(φ) = 1, the kinetic energy of the sliders is equal to the kinetic energy of the bar OC.
Finally, the total kinetic energy of the system is the sum of the kinetic energies of the three parts:
T = T_OC + T_AB + T_A+B
= 1/2 * m * b² * ω² + 1/2 * (2m) * (2b)^2 * ω² + 1/2 * m * b² * ω²
= (m+4m+m) * b² * ω²/ 2
= 6m * b² * ω² / 2
Therefore, the total kinetic energy of the system is given by:
T = 6m * b² * ω² / 2
Therefore, one should note that this result does not depend on the value of φ, so it is not necessary to know the value of φ in order to find the kinetic energy of the system.
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Two ice-hockey players simultaneously strike a puck with their sticks. The stick of one player exerts an eastward force on the puck of 12 N. The other player’s stick exerts a northward force of 15 N on the puck. Assuming that there is no frictional force between the puck and the ice, what is the magnitude of the net horizontal force on the puck?
The magnitude of the net horizontal force on the puck is 12 N.
What is net horizontal force acting on the puck?
The magnitude of the net horizontal force on the puck is the sum of all the forces acting on the puck along the horizontal direction.
The net horizontal force acting on the puck is obtained by applying Newton's second law of motion. Newton's second law of motion states that the force applied on an object is directly proportional to the product of mass and acceleration of the oobject.
Mathematically, Newton's second law of motion is given as;
F = ma
where;
m is the mass of the objecta is the acceleration of the objectThe given horizontal force on the puck include;
eastward force = 12 N
force of friction = 0 N
The net horizontal force on the puck is calculated as;
∑Fx = 0 N + 12 N
∑Fx = 12 N
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Three rods, each of mass m and length l are joined together to form a n equilateral triangle Find the moment of inertia of the system about an axis passing through its centre mass and perpendicular to the plane of the triangle.also find the radius of gyration about the same axis
The moment of inertia of the system is I = 3ml^2/4 and the radius of gyration is r = l/2√3.
To find the moment of inertia of the system, we need to consider the contributions of each rod to the overall rotational inertia. The moment of inertia of a rod about an axis passing through its center of mass and perpendicular to its length is given by I = ml^2/12. Since there are three rods in the system, the total moment of inertia is I = 3ml^2/12 = 3ml^2/4.
The radius of gyration is a measure of how far the mass of the object is distributed from the axis of rotation. For an object with uniform mass distribution, the radius of gyration is given by r = √(I/m). In this case, the mass of the system is 3m, so the radius of gyration is
r = √[(3ml^2/4)/(3m)] = √(3l^2/4) = l/2√3.This is the distance from the center of mass to the point where the mass of the system can be considered to be concentrated for the purpose of calculating rotational dynamics.
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A recreational vehicle in the amusement park is traveling on a frictionless track that can make a circular loop as shown in the figure below. The vehicle is released from a point A at a height h from the base of the circular section of the track. (a) What must be the minimum height h required for the vehicle to complete the circular section of the track at point B without falling? If h= 3.50 R and R=20 m, calculate the speed, centripetal acceleration and tangential acceleration of the occupants while the vehicle is at point C (point C is in the horizontal diameter direction).
The minimum height that the block must start to make it around the loop without falling off is h = 5R/2
What is present inside the circular loop?The block slides are around the inside of a circular loop. This shows that or it means that we are dealing with critical velocity in vertical circular motion.
In the critical velocity in the vertical circular motion, the formula for the minimum velocity just at the lowest Point of the vertical circle required to get the critical velocity at the highest point is given as;
v = √(5gR)
Therefore, m will cancel out to give;
½v² = gh
Plugging in the relevant values gives;
½ × [√(5gR)]² = gh
Simplify to get;
5gR = 2gh
g will cancel out to get;
5R = 2h
h = 5R/2
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Derive an equation which will give a minimum detectable fractional change in osteopototic bone, assuming,for simplicity a monenerget beam of incident photon.
Explanation:
To derive an equation for the minimum detectable fractional change in osteoporotic bone using a monochromatic beam of incident photons, we can consider the factors that affect the sensitivity of the measurement.
One important factor is the energy resolution of the detector, which determines the ability of the detector to distinguish between different energies of photons. The energy resolution can be represented by the parameter FWHM (full width at half maximum), which is the width of the energy peak at half of its maximum height. A higher FWHM corresponds to a lower energy resolution, which means that the detector is less sensitive to small changes in energy.
Another factor is the intensity of the incident photon beam, which determines the number of photons that are detected by the detector. A higher intensity corresponds to a higher number of photons and a higher signal-to-noise ratio, which makes it easier to detect small changes in the energy of the photons.
We can combine these factors into an equation that represents the minimum detectable fractional change in osteoporotic bone. Let ΔE be the minimum detectable change in energy of the photons, FWHM be the energy resolution of the detector, and I0 be the intensity of the incident photon beam. We can represent the minimum detectable fractional change in the osteoporotic bone as ΔE/E, where E is the average energy of the photons in the incident beam.
Using these variables, we can write the equation as:
ΔE/E = K * FWHM/I0
where K is a constant that depends on the specific properties of the detector and the measurement setup. This equation shows that the minimum detectable fractional change in osteoporotic bone
TRUE OR FALSE. air pollutant formed in the atmosphere as a result of the chemical or the physical interactions between the primary pollutants themselves or between the primary pollutants and other atmospheric components.
A secondary pollutant is a type of air pollutant that is created in the atmosphere as a result of chemical or physical interactions here between primary pollutants or between the primary pollutants themselves.
What are air contaminants and what harm do they cause?Surfaces of both water and soil can become contaminated by air pollution. This may cause crop death or lower crop yield. Young plants as well as trees can die as a result. Acid rain can be produced when airborne sulfur dioxide and nitrogen oxides particles combine with atmospheric water and oxygen.
An air pollutant is defined as what?Gases and solid particles in the air combine to create air pollution. Particles may include exhaust from cars, industrial chemicals, dust, pollen, and mold spores. A significant contributor to urban air pollution is the gas ozone. Smog is the term used to describe ozone-based air pollution. There are certain toxic air contaminants.
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A train travelling along a straight line with constant acceleration is observed to travel consecutive distances of 1km in times of 30s and 60s respectively. Find the initial velocity of the train.
It moves at a pace of 116.7 meters per second at first. The velocity at time t = 0 is known as the initial velocity (u). It is the rate at which motion initially manifests itself.
What is the formula for calculating the starting value?
In mathematics, the initial value of a function represents the function's y-intercept. Beginning values can also be established using the constant in an equation. It helps to comprehend the y-intercept in graph functions.
Is the initial and ultimate velocities the same?
Initial and end velocities are equal. Consequently, there will be no difference at whatever value of "t." Consequently, this establishes that an object's initial velocity is its speed before being affected by acceleration a.
Briefing:
distance(s) = 1km = 1 × 1000m = 1000m
Time(t) = 60– 30 = 30s
initial velocity = u
acceleration (a) = 10m/s
using the formula
S = ut + ½at²
1000 = 30u + ½ × 10 × 30²
1000 = 30u + 5 × 900
1000 = 30u + 4500
30u = 4500 – 1000
30u = 3500
divide both sides by 30
u = 116.7m/s
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A geostationary satellite for communications seems to be in a fixed spot above the equator because it has the same angular velocity as the earth.
a, show that if it goes round once a day its angular velocity is a little over 7 * 10*-5 rad/s.
The angular velocity of a geostationary satellite is 7 × 10⁻⁵rad/s.
What are geostationary satellite?A geostationary satellite is an earth-orbiting satellite that travels in the same direction as the earth's rotation and is positioned at a height of around 36000 kilometers.
One orbit takes place at this altitude in 24 hours, which is how long it takes the earth to complete one rotation of its axis.
Time period of revolution = 24 hour = 24 × 60 × 60 second.
Hence, angular velocity of it = total circular angle/Time period
= 2π /( 24 × 60 × 60 ) rad/s
= 7 × 10⁻⁵rad/s.
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the mean distance of an asteroid from the sun is 4.55 times that of earth from the sun. from kepler's law of periods, calculate the number of years required for the asteroid to make one revolution about the sun.
The number of years required for the asteroid to make one revolution about the sun will be 4.55 years
What is the meaning of Kepler's third law?
According to Kepler's Third Law, the planets' squared orbital periods and cubes of their semi-major axes are directly inversely related. According to Kepler's Third Law, a planet's period of orbiting the Sun grows exponentially with its orbital radius.
The sun is at the focus of elliptical planetary orbits, according to the first law. The radius vector from the sun to a planet sweeps equal regions in equal amounts of time, according to the second law.
According to Kepler's Third Law,
T^2 is directly proportional to r^3
(T1/T2)^2 = (r1/r2)^3
Time taken by earth to complete 1 revolution, T1 = 1 year
Time taken by asteroid to complete 1 revolution T2
distance of earth r1 = r
distance of asteroid r2 = 4.55r
So,
1/T2 = r/4.55r
T2 = 4.55 years
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the first modern astronomer to propose a sun-centered universe was . group of answer choices nicolaus copernicus tycho brahe sir isaac newton galileo
The Heliocentric Theory of the world, put forward by Copernicus, held that the sun was the center of the universe and that the earth rotated around it.
What does one newton weigh?In the foot-pound-second (English, or customary) system, one newton is equivalent to around 0.2248 pounds of force or 100,000 dynes in the centimeter-gram-second (CGS) system.
What in physics is a newton?The letter N is frequently used to shorten the phrase "newton" in physics and engineering documents. In the absence of any other forces, one newton is the force necessary to accelerate a mass of one kilogram at a pace of one meter per second squared.
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Which of the following works of art is from the Amarna Period? How to: Items can be selected or deselected by clicking anywhere on the box. Selected items are highlighted in blue. 1 2 3 4
Work of art from the Amarna Period that is abstract or descriptive in nature.
What modifications did the Amarna Period bring to the arts?That momentarily altered during the Amarna Period. The neck, arms, and hands were among the longer characteristics on the body. The traditional Egyptian painting form was briefly replaced by this strange new art form, which resulted in portraits of people that were virtually caricatures.
What is renowned about the Amarna Period?Religious iconoclasts are associated with the Amarna Period. Because he only worshiped the Aten, the pharaoh Amenhotep IV changed his name to Akhenaten. At Tell el-Amarna in Middle Egypt, he constructed a brand-new capital and cemetery.
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