A turntable, with a mass of 1.5 kg and diameter of 20 cm, rotates at 70 rpm on frictionless bearings. Two 540 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick to it.

Required:
What is the turntable's angular speed, in rpm, just after this event?

Initially rolling inside a horizontal circle five meters above the ground at a speed of two meters per second, the ball breaks the string as it approaches true North. Though it is falling, it is still heading in the direction

The lower string, however, is the one that snaps if it is forcefully yanked. The prevailing theory holds that the mass's inertia prevents it from moving and, as a result, from pulling on the top string.

If both strings are equally strong, the top string will break sooner. However, a change in tension from the lower string takes a moment to transfer because of the inertia of a hanging object.

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The moment of inertia of the system is I = 3ml^2/4 and the radius of gyration is r = l/2√3.

To find the moment of inertia of the system, we need to consider the contributions of each rod to the overall rotational inertia. The moment of inertia of a rod about an axis passing through its center of mass and perpendicular to its length is given by I = ml^2/12. Since there are three rods in the system, the total moment of inertia is I = 3ml^2/12 = 3ml^2/4.

The radius of gyration is a measure of how far the mass of the object is distributed from the axis of rotation. For an object with uniform mass distribution, the radius of gyration is given by r = √(I/m). In this case, the mass of the system is 3m, so the radius of gyration is

This is the distance from the center of mass to the point where the mass of the system can be considered to be concentrated for the purpose of calculating rotational dynamics.

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Answer:

try this

Explanation:

the cosmos just like humanity of earth its living like a mirror

Answer:

thing will slide apart

Explanation:

Friction prevents objects from sliding apart. Everything would slide to the lowest point if there was no friction. It would be impossible to scale anything. We will be unable to write without friction.

1) Before the boiling point, the temperature of the water increases and it begins to boil. Boiling is the physical process by which a liquid changes to a gaseous state. It runs when the temperature of the entire liquid is equal to the boiling point of the liquid at that pressure. As the liquid continues to heat up, it absorbs heat, but without raising the temperature, it uses the heat to transform the substance from the liquid to the gaseous state, shifting the entire mass into the gaseous state. The heat that is generated in heating most of the liquid is called sensible heat, and the heat that appears during a change of state is called latent heat of boiling or vaporization.

2) Because iron is "closer" to its molecules, it can absorb more energy and, as a result, heat up faster. Instead, bricks have tiny air holes. That is, its molecules are "far away" and are not easily heated. As they conduct heat (conduction or convection), they lose energy.

3) When a piece of heated iron is placed in room temperature water, the iron gives off heat to the water (cooling) and the water receives heat (heating). Because the iron gives heat.

4) When you put a brick on top of an iron and heat it up, the iron heats up faster and starts heating the brick by conduction (because the material sticks together). In addition, the heat absorption capacity of the brick itself makes it warmer.

What is heat energy?

The term "thermal energy" is used loosely in various contexts of physics and engineering. We can refer to some well-defined physical concepts. These include the internal energy or enthalpy of matter and radiation. Heat (and thermodynamic work) defined as the mode of energy transfer. and the characteristic energies of the degrees of freedom of the system described by its microscopic particle content (where T denotes the temperature and Boltzmann constant).

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A secondary pollutant is a type of air pollutant that is created in the atmosphere as a result of chemical or physical interactions here between primary pollutants or between the primary pollutants themselves.

Surfaces of both water and soil can become contaminated by air pollution. This may cause crop death or lower crop yield. Young plants as well as trees can die as a result. Acid rain can be produced when airborne sulfur dioxide and nitrogen oxides particles combine with atmospheric water and oxygen.

Gases and solid particles in the air combine to create air pollution. Particles may include exhaust from cars, industrial chemicals, dust, pollen, and mold spores. A significant contributor to urban air pollution is the gas ozone. Smog is the term used to describe ozone-based air pollution. There are certain toxic air contaminants.

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Work of art from the Amarna Period that is abstract or descriptive in nature.

That momentarily altered during the Amarna Period. The neck, arms, and hands were among the longer characteristics on the body. The traditional Egyptian painting form was briefly replaced by this strange new art form, which resulted in portraits of people that were virtually caricatures.

Religious iconoclasts are associated with the Amarna Period. Because he only worshiped the Aten, the pharaoh Amenhotep IV changed his name to Akhenaten. At Tell el-Amarna in Middle Egypt, he constructed a brand-new capital and cemetery.

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The number of years required for the asteroid to make one revolution about the sun will be 4.55 years

What is the meaning of Kepler's third law?

According to Kepler's Third Law, the planets' squared orbital periods and cubes of their semi-major axes are directly inversely related. According to Kepler's Third Law, a planet's period of orbiting the Sun grows exponentially with its orbital radius.

The sun is at the focus of elliptical planetary orbits, according to the first law. The radius vector from the sun to a planet sweeps equal regions in equal amounts of time, according to the second law.

According to Kepler's Third Law,

T^2 is directly proportional to r^3

(T1/T2)^2 = (r1/r2)^3

Time taken by earth to complete 1 revolution, T1 = 1 year

Time taken by asteroid to complete 1 revolution T2

distance of earth r1 = r

distance of asteroid r2 = 4.55r

So,

1/T2 = r/4.55r

T2 = 4.55 years

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Based on the information provided, there is a change of 12 Jules in the kinetic energy during segment 2.

Kinetic energy can be defined as the energy produced by the motion of a body. Due to this, the level of energy can change depending on movement. The change in the kinetic energy can be calculated by considering the initial kinetic energy and the final kinetic energy. Moreover, the energy is measured using Joules.

Let's consider first the information given:

Based on the velocity, let's caclulate the change in the kinetic energy:

Final Kinetic energy - Initial kinetic energy

1/2 x 0.5 (8^2-4^2) = 12 Joules

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The  Kinetic energy of the system T = 6m * b² * ω² / 2

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force.

To find the kinetic energy of the system;

The kinetic energy of the bar OC is given by:

T_OC = 1/2 * m * b² * ω²

Note that:

m= Metre

b= Bar

ω = omega

The kinetic energy of the bar AB is given by:

T_AB = 1/2 * (2m) * (2b)² * ω²

The kinetic energy of the sliders A and B is given by:

T_A+B = 1/2 * m * v_A² + 1/2 * m * v_B²

where v_A and v_B are the velocities of sliders A and B, respectively.

To find the velocities of the sliders, we can use the relationship between the angular velocity of the bar OC and the linear velocities of the sliders:

v_A = b * ω * cos(φ)

v_B = b * ω * sin(φ)

Substituting these expressions into the equation for T_A+B, we get:

T_A+B = 1/2 * m * (b * ω * cos(φ))² + 1/2 * m * (b * ω * sin(φ))²

= 1/2 * m * b² * ω² * (cos^2(φ) + sin²(φ))

= 1/2 * m * b² * ω²

Since cos²(φ) + sin²(φ) = 1, the kinetic energy of the sliders is equal to the kinetic energy of the bar OC.

Finally, the total kinetic energy of the system is the sum of the kinetic energies of the three parts:

T = T_OC + T_AB + T_A+B

= 1/2 * m * b² * ω² + 1/2 * (2m) * (2b)^2 * ω² + 1/2 * m * b² * ω²

= (m+4m+m) * b² * ω²/ 2

= 6m * b² * ω² / 2

Therefore, the total kinetic energy of the system is given by:

T = 6m * b² * ω² / 2

Therefore, one should note  that this result does not depend on the value of φ, so it is not necessary to know the value of φ in order to find the kinetic energy of the system.

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The magnitude of the net horizontal force on the puck is 12 N.

The magnitude of the net horizontal force on the puck is the sum of all the forces acting on the puck along the horizontal direction.

The net horizontal force acting on the puck is obtained by applying Newton's second law of motion. Newton's second law of motion states that the force applied on an object is directly proportional to the product of mass and acceleration of the oobject.

Mathematically, Newton's second law of motion is given as;

F = ma

where;

The given horizontal force on the puck include;

eastward force = 12 N

force of friction = 0 N

The net horizontal force on the puck is calculated as;

∑Fx = 0 N + 12 N

∑Fx = 12 N

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Answer:

The answer is 5 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

where

f is the force

m is the mass

From the question we have

We have the final answer as

5 m/s²

Answer:

Explanation: Force = mg as the wire is fixed at one point and the load is inserted at one end.

g=9.8m/s²

F= mg

F= 20×9.8= 19.6 newton

Strain= Δl/L

where Δl= change in length

and L= original length

Strain = 0.24×0.001 m/4m

Strain=0.00006

Stress= F/A

where A = cross sectional area

therefore A = π× (diametre/2)²

A=3.14×1²≈3.14 mm²= 0.000000314m²

Stress = 19.6/0.000000314=62420382 Pascal

Explanation:

To derive an equation for the minimum detectable fractional change in osteoporotic bone using a monochromatic beam of incident photons, we can consider the factors that affect the sensitivity of the measurement.

One important factor is the energy resolution of the detector, which determines the ability of the detector to distinguish between different energies of photons. The energy resolution can be represented by the parameter FWHM (full width at half maximum), which is the width of the energy peak at half of its maximum height. A higher FWHM corresponds to a lower energy resolution, which means that the detector is less sensitive to small changes in energy.

Another factor is the intensity of the incident photon beam, which determines the number of photons that are detected by the detector. A higher intensity corresponds to a higher number of photons and a higher signal-to-noise ratio, which makes it easier to detect small changes in the energy of the photons.

We can combine these factors into an equation that represents the minimum detectable fractional change in osteoporotic bone. Let ΔE be the minimum detectable change in energy of the photons, FWHM be the energy resolution of the detector, and I0 be the intensity of the incident photon beam. We can represent the minimum detectable fractional change in the osteoporotic bone as ΔE/E, where E is the average energy of the photons in the incident beam.

Using these variables, we can write the equation as:

ΔE/E = K * FWHM/I0

where K is a constant that depends on the specific properties of the detector and the measurement setup. This equation shows that the minimum detectable fractional change in osteoporotic bone

The plot of U versus x is given in the attachment below. The speed of the particle at x = 3.5 m is 8.37 m/s.

Here, the mechanical energy remains constant as the particle moves.

As, the mechanical energy is conserved, we can write, Ub + Kb = Ua + Ka

Making Ka as subject, we have,

Ka = Ub + Kb - Ua = 12 + 4 - 9 = 7 J

We know that, Ka = [m* (va)²]/2

The speed of the particle at x = 3.5m (within region A) is

va = √(2* Ka)/m = √(2* 7)0.2 = 8.37 m/s.

Thus, the speed at x = 3.5m is 8.37 m/s.

The question is incomplete. The complete question is ' Figure 8−49  shows a plot of potential energy U versus position x of a 0.200kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values : Ua = 9.00 J, Uc = 20.00 J, and Ud = 24.00 J. The particle is released at the point where U forms a potential hill of height  Ub = 12.00 J, with kinetic energy 4.00 J. What is the speed of the particle at x = 3.5 m. The attachment below has the missing plot.

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It moves at a pace of 116.7 meters per second at first. The velocity at time t = 0 is known as the initial velocity (u). It is the rate at which motion initially manifests itself.

What is the formula for calculating the starting value?

In mathematics, the initial value of a function represents the function's y-intercept. Beginning values can also be established using the constant in an equation. It helps to comprehend the y-intercept in graph functions.

Is the initial and ultimate velocities the same?

Initial and end velocities are equal. Consequently, there will be no difference at whatever value of "t." Consequently, this establishes that an object's initial velocity is its speed before being affected by acceleration a.

Briefing:

distance(s) = 1km = 1 × 1000m = 1000m

Time(t) = 60– 30 = 30s

initial velocity = u

acceleration (a) = 10m/s

using the formula

S = ut + ½at²

1000 = 30u + ½ × 10 × 30²

1000 = 30u + 5 × 900

1000 = 30u + 4500

30u = 4500 – 1000

30u = 3500

divide both sides by 30

u = 116.7m/s

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The correct option for the question is an option (c) positively charged objects do not attract or repel an uncharged object.

The analysis of stationary electrically charged particles is known as electrostatics. The charge attached to matter, which causes it to produce and feel magnetic and electric activity, is known as the electric charge.

Paper scraps are drawn to a plastic rod when brushed with fur, and a glass rod when rubbed with silk, demonstrating the electrical charge of both rods.

According to Coulomb's law, two particles with the same charge repel one another while those that have the opposite charge attract one another. Between two charged particles, there is a considerably stronger electric force in comparison to the gravitational force.

Hence, the positively charged objects do not attract or repel an uncharged object. The right answer is option C.

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The angular velocity of a  geostationary satellite is 7 × 10⁻⁵rad/s.

A geostationary satellite is an earth-orbiting satellite that travels in the same direction as the earth's rotation and is positioned at a height of around 36000 kilometers.

One orbit takes place at this altitude in 24 hours, which is how long it takes the earth to complete one rotation of its axis.

Time period of revolution = 24 hour = 24 × 60 × 60 second.

Hence, angular velocity of it = total circular angle/Time period

= 2π /( 24 × 60 × 60 ) rad/s

= 7 × 10⁻⁵rad/s.

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The Romans invented a new concrete recipe that combined pozzolana, a fine volcanic ash found in Southern Italy, with lime and water to make a strong, resistant kind of concrete.

The Roman term for concrete was opus caementicium, which meant that it was mixed with small stones. The Roman Empire's preferred building material was concrete. It has been utilized in monuments such as Rome's Pantheon, as well as wharves, breakwaters, and other harbor buildings. This is why concrete does not last as long as natural rocks. However, this is not how Roman concrete works. Theirs was made from volcanic ash, lime, and seawater, utilizing a chemical reaction that Romans may have observed in naturally cemented volcanic ash deposits known as tuff rocks.

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The magnitude of the net force on the block while it is sliding is most nearly is 14m/s when A 2 kg block, starting from rest, slides 20 m down a frictionless inclined plane from X to Y, dropping a vertical distance of 10 m.

The Plane by which no opposite force is applied on the sliding or moving object is termed as  Frictionless plane.

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The Heliocentric Theory of the world, put forward by Copernicus, held that the sun was the center of the universe and that the earth rotated around it.

In the foot-pound-second (English, or customary) system, one newton is equivalent to around 0.2248 pounds of force or 100,000 dynes in the centimeter-gram-second (CGS) system.

The letter N is frequently used to shorten the phrase "newton" in physics and engineering documents. In the absence of any other forces, one newton is the force necessary to accelerate a mass of one kilogram at a pace of one meter per second squared.

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Answer:

Answer:

let the first point be a second be b third be c fourth be d and last point be e.

The point a and d are incorrect. because tye plotting of the is incorrect

Answer:

17.96 s

Explanation:

To find the total time the ball was in the air, we need to first find the time it took to reach the top of its path and then double that time to find the total time in the air.

The time it took to reach the top of its path is given by: t = v/g

Substituting in the known values and solving for t, we get: t = 35 m/s / 9.8 m/s^2 = 8.98 s

To find the total time the ball was in the air, we need to double the time it took to reach the top of its path, so the total time in the air is: 2 * 8.98 s = 17.96 s

Rounding to the nearest hundredth, the total time the ball was in the air is 17.96 s. Therefore, the answer is 17.96.

The correct statement about the rocks is Just as they are about to reach the ground, the heavier rock has more kinetic energy than the lighter rock.

As per the known fact, kinetic energy is the product mass, square of velocity and 0.5. Thus, it is due to the motion of object. Potential energy is the product mass, acceleration due to gravity and height. It is due to the height of object.

Also, momentum is another factor that will influence the results in situation mentioned in question. Based on this, momentum is the product of mass and velocity of the object. Considering momentum and kinetic energy, the heavier rock will have more kinetic energy.

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By attaching a mass of 100 g too spring 1. Play the simulator. Measure the duration of the stopwatch for 10 full cycles. The measured period by dividing the total time by 10 is 2 seconds.

The period of oscillation of the mass on spring 1, you would need to measure the time it takes for the mass to complete 10 complete cycles. You can do this by starting a stopwatch when the mass is in the down position and stopping the stopwatch when the mass returns to the down position after completing 10 cycles. Once you have measured the total time for 10 complete cycles, you can calculate the period by dividing the total time by 10. For example, if the total time for 10 complete cycles is 20 seconds, then the period would be 20 seconds / 10 = 2 seconds. We will call this value Tz.

After measuring the period of oscillation of the mass on spring 1, you should pause the simulator and remove the mass from the hook of the spring. This will allow you to perform any additional measurements or calculations without interference from the mass.

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A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.

They are present in practically all electrical networks and electronic circuits. Ohms () are used to measure resistance.

An ohm is the resistance that develops when a resistor has a one volt (V) drop across its terminals and a current of one ampere (A). The voltage across the terminal ends determines how much current flows.

There are numerous applications for resistors. Among some examples are voltage division, heat production, matching and loading circuits, gain control, and time constant setup. They have resistance ratings that span more than nine orders of magnitude and are marketed for use in various applications.

Therefore, A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.

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The minimum height that the block must start to make it around the loop without falling off is h = 5R/2

The block slides are around the inside of a circular loop. This shows that or it means that we are dealing with critical velocity in vertical circular motion.

In the critical velocity in the vertical circular motion, the formula for the minimum velocity just at the lowest Point of the vertical circle required to get the critical velocity at the highest point is given as;

v = √(5gR)

Therefore, m will cancel out to give;

½v² = gh

Plugging in the relevant values gives;

½ × [√(5gR)]² = gh

Simplify to get;

5gR = 2gh

g will cancel out to get;

5R = 2h

h = 5R/2

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he change in the pressure of the air trapped in the cylinder if its volume is increased by 20% at a constant temperature is 745 mmHg.

The change in the pressure of the air trapped in the cylinder if its volume is increased by 20% at a constant temperature is calculated from Boyle's law equation as follows:

The  Boyle's law equation is given as follows:

P₁V₁ = P₂V₂

where;

P₁ is the initial pressure

V₁ is the initial volume

P₂ is the final pressure

V₂ is the final volume

From the data given,

P₁ = 760 mmHg

V₁ = V

P₂ = ?

V₂ = V + 0.2 V

V₂ = 1.02 V

P₂ = 760 * V / 1.02 V

P₂ = 745 mmHg

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(a) The first block  moves at 4.0 m/s in the same direction right after colliding.

(b) the system's total kinetic energy changes by  28.75 J

(c) the system's total kinetic energy changes by -1.25 J

Given;

First block's mass, m1, is 5 kg.

u1 = 3.0 m/s is the first block's starting speed.

m2 weight of the second block is 10.0 kg.

u2 = 2.0 m/s is the second block's initial speed.

v2 = 2.5 m/s is the second block's final speed.

Immediately following the impact, the first block block's Part (A) velocity is as follows:

Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.

(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)

35= 2.5v₁ + 25

2.5v₁ = 35-25

2.5v₁ = 10

v₁ = 10/2.5

v₁ = 4

2.5 m/s in the same direction for v1.

Change in the system's overall kinetic energy, part (B):

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)

ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).

ΔK = 71.25 J - 42.5 J

ΔK = 28.75 J

Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s

Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)

35 = 2.5v₁ + 40

2.5v₁ = -5

2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)

K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).

ΔK = 41.25 - 42.5 J

ΔK = -1.25 J

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Answer:

294

Explanation:

5x9.8x6=294

potential energy=5(9.8)(6)

Equation

PE=MGH