(a) The force is the spring exerting on the dart is 0.7 N.
(b) The elastic potential energy stored in the spring is 7 x 10⁻³J.
(c) The kinetic energy of the dart when it reaches the natural length of the spring is 7 x 10⁻³J.
(d) The speed of the dart when it reaches the natural length of the spring is 2.65 m/s.
Force the spring exerting on the dart
F = kx
where;
k is spring constantx is compression of the springF = 35 N/m x 0.02 m
F = 0.7 N
Energy stored in the springU = ¹/₂kx²
U = ¹/₂(35)(0.02)²
U = 7 x 10⁻³ J
Kinetic energy of the dartThe elastic potential energy of the spring will be converted into kinetic energy of the dart, with a magnitude of 7 x 10⁻³ J when it reaches natural length of the spring.
Speed of the dartK.E = ¹/₂mv²
v² = (2K.E)/m
where;
v is the speed of the dartm is mass of the dartv² = (2 x 7 x 10⁻³)/(0.002)
v² = 7
v = 2.65 m/s
Thus, the force is the spring exerting on the dart is 0.7 N.
The elastic potential energy stored in the spring is 7 x 10⁻³J.
The kinetic energy of the dart when it reaches the natural length of the spring is 7 x 10⁻³J.
The speed of the dart when it reaches the natural length of the spring is 2.65 m/s.
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An object travels around a circle of radius 4.00 m with a velocity of 2.00m/s. What is its angular velocity? (Please keep your answer with two decimal place and no units)
Angular velocity of the object is 0.5 radian/second.
To find the answer, we need to know about the angular velocity.
What's the mathematical expression of angular velocity?The angular velocity= velocity/ radius
What will be the angular velocity, if an object moves in a circular path of radius 4m and velocity 2 m/s?The angular velocity of the object is 2/4 = 0.5 radian/second.
Thus, we can conclude that the angular velocity is 0.5 radian/second.
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Calculate the magnitude of the electric field inside the solid at a distance of 9.40 cmcm from the center of the cavity.
The magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.
Volume of shell of chargeV = ⁴/₃π(R³ - r³)
V = ⁴/₃π (0.092³ - 0.0655³)
V = 2.085 x 10⁻³ m³
Total charge of the surfaceQ = Vσ
where;
V is volumeσ is charge densityQ = 2.085 x 10⁻³ m³ x 7.35 x 10⁻⁴ C/m³
Q = 1.53 x 10⁻⁶ C
Electric field due to the shellE = kQ/R²
E₁ = (9 x 10⁹ x 1.53 x 10⁻⁶)/(0.092)²
E₁ = 1.627 x 10⁶ N/C
Electric field due to the charge qE₂ = (9 x 10⁹ x 2.14 x 10⁻⁶)/(0.092)²
E₂ = 2.276 x 10⁶ N/C
Electric field inside the solid at a distance of 9.50cm from the center of the cavity;
E = E₂ - E₁
E = 2.276 x 10⁶ N/C - 1.627 x 10⁶ N/C
E = 6.5 x 10⁵ N/C
Thus, the magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.
Complete question:
A point charge of -2.14uC is located in the center of a spherical cavity of radius 6.55cm inside an insulating spherical charged solid. The charge density in the solid is 7.35×10−4 C/m^3.
a) Calculate the magnitude of the electric field inside the solid at a distance of 9.20cm from the center of the cavity.
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A driver in a 2,000 kg SUV moving at 15 m/s crashes into a stopped car, causing it to be propelled forward and the truck to be slowed to 10 m/s. What is the work done on the SUV by the stopped car
The work done on the SUV by the stopped car is .
Given:- A driver in a 2,000 kg SUV moving at 15 m/s crashes into a stopped car and the truck to be slowed to 10 m/s.
To Find:- We have to find the work done on the SUV by the stopped car.
By using the concept of speed it will be solved.
According to the problem,
The work done on the SUV by the stopped car is .
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Establishing a high critical value when calculating the results of a statistical test means that a researcher will have more confidence in finding significance than when a lower critical value is established. Please select the best answer from the choices provided T F
The statement 'establishing a high critical value in a statistical test is associated with more confidence' is TRUE.
What is statistical significance?The statistical significance is a arbitrary value used to indicate that data collected can be used to confirm (or reject) my working hypothesis.
The most widely used value to measure the statistical significance is the p threshold.
In conclusion, the statement 'Establishing a high critical value when calculating the results of a statistical test means that a researcher will have more confidence in finding significance than when a lower critical value is established' is TRUE.
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Answer:
The answer is F or false
Explanation:
correct edge 2023
While in Earth's orbit, an 80-kg astronaut carrying a 20-kg tool kit is initially drifting toward a stationary space shuttle at a speed of 2 m/s. If she throws the tool kit toward the shuttle with a speed of 6 m/s, her final speed is what value
The answer is 1 m/s toward the shuttle.
In physics, conservation means that the initial and final values are equivalent. This implies that a system's total starting and total final momentums will be identical in terms of momentum. The force acting on an item will always be equal to the change in the object's momentum over time, according to Newton's second law.
Therefore, initial momentum = final momentum
Pi = Pf
100*2 = 20*6+80*v
200 = 120+80*v
200-120 = 80*v
80 = 80*v
1 = v
v = 1 m/s
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An asteroid on the earth's orbit experiences a free-fall acceleration which is 8.0 times smaller than it would be on the earth. what is the distance between the asteroid and the earth's surface measured in the earth's radii? neglect the gravity of the moon.
The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82 R
What are the Asteroids:
Asteroids are small, rocky objects that orbit the Sun. They are much smaller than planets.They are found between the orbits of Mars and Jupiter, though some have more eccentric orbits.here,
An asteroid experiences acceleration on earth's orbit which is 8.0 times smaller than it on the earth surface.
Free fall acceleration of Asteroid:
on earth's surface = gon earth's orbit = g' = g / 8so,
g' = GM /(R + x)^2 ------1
g = GM / R^2
g' = 1/8 ( GM / R^2 ) -------1
where G is gravitational constant
M is mass of earth
R is earth's radius
comparing both equations 1 and 2
GM /(R + x)^2 = 1/8 ( GM / R^2 )
8 R^2 = (R + x)^2
2√2 * R = R + x
x = R (2√2 - 1)
x = 1.82*R
hence, The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82*R
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Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical
equation:
(Na₂HPO4-Na4P₂07
+ H₂0
The coefficients in order are 2, 1, 1
What is balanced chemical equation?A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.
In other words, the mass and the charge are balanced on both sides of the reaction.
According to the given situation,
To balance the the chemical equation,
Step 1 - Add a 2 on the Na2HPO4:
2(Na₂HPO₄) ⇒ Na4P₂O₇ + H₂O
Step 2 -Next take count of each element on both sides to see if the 2 is balanced or not:
On the left there are 4 Na, 2 H, 2 P, and 8 O
On the right there are 4 Na, 2 H, 2 P, and 8 O
Step 3 - Now we will divide by 2
i.e. 2 NA.H. P
The coefficient of Na is 2 , Coefficient of H is 1 and Coefficient of P is 1
Therefore,
The coefficients in order are 2, 1, 1.
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Which mechanical component is required in every gas-engine vehicle, but often not needed in an electric vehicle?.
a gearbox bru.
An object is placed 10 cm from a convex lens of focal length 20 cm. What is the lateral magnification of the object?.
Answer:Solution
verified
Verified by Toppr
Given:u=−10cm f=20cm (convex lens)
To find: v and image's nature.
Solution: From lens formula
v
1
−
u
1
=
f
1
v
1
+
10
1
=
20
1
Explanation:
Who challenged the traditional belief that the orbits of the planets were spherical, showing that the five known planets moved around the sun in elliptical paths
Answer: Johannes Kepler challenged the traditional belief that, the orbits of the planets were spherical, showing that the five known planets moved around the sun in elliptical paths.
Explanation: To find the correct explanation, we have to know more about the History of planetary motion and the Kepler's laws.
What is the history of planetary motion?In B.C 350, Aristotle-Universe was composed of 55 concentric rotating sphere, centered in Earth.Aristarchus- Sun and stars were fixed, and the planets rotated about the sun.Ptolemy-Planets moves around the earth, in small circle.Copernicus-Retrograde motion of planets as observed from earth.Galileo-Motion of moons orbiting Jupiter.Kepler- Planet moves in an elliptical orbit.What is Kepler's law of planetary motion?First law: Planet moves in an elliptical orbit with sun as one of the foci.2nd law: Planets sweeps equal area in equal interval of time.3rd law: The square of the time period of motion is proportional to the cube of its mean radius.Thus, from the above explanation we can conclude that, Johannes Kepler challenged the traditional belief that, the orbits of the planets were spherical, showing that the five known planets moved around the sun in elliptical paths.
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Projectile effects are a hazard in __________________. magnetic resonance imaging (MRI) fields pediatric units emesis stations operating theaters
Projectile effects are a hazard in MRI fields.
What is MRI field?MRI stands for - Magnetic resonance imaging and it is a medical imaging technique that uses a magnetic field and radio waves to create detailed images of the organs and tissues in your body.
Projectile effects are a hazard in MRI fields, due to attraction exerted by the static magnetic field of the MRI scanner on ferromagnetic objects accidentally introduced into the MRI-scanner room.
Thus, Projectile effects are a hazard in MRI fields.
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Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density n = 910 wires/m and a current per wire of IL = 0.17 A in the +z direction. The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.17 A in the -z direction.
a) Calculate the y-components of the net magnetic field in the following places: x1 = -15 cm, x2 = 6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)
B(x1)y = T
B(x2)y = T
B(x3)y = T
b) Suppose the above configuration of currents is unchanged except that the direction of the current IR is reversed so that now IR also flows in the +z direction. (The magnitude remains the same.) Calculate the y-components of the net magnetic field at the same positions as in part a).
B(x1)y = T
B(x2)y = T
B(x3)y = T
c) Return to the configuration of part a). Suppose you want to have the region 0 < x < a able to confine electrons (qe- = -1.60 x 10-19 C, me- = 9.11 x 10-31 kg) that have been accelerated from rest through a 66 V electrostatic potential. If the electrons are to be stacked in circular orbits parallel to the x-z plane with centers on the plane x = a/2, what is the minimum current per wire required if IL and IR are equal in magnitude but opposite in direction?
IL = A
Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density of n = 910 wires/m and current per wire of IL = 0.14 A in the +zdirection.
The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.14 A in the -z-direction.
(a) Calculate the y-components of the net magnetic field in the following places:
x1 = -15 cm, x2 =6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)
B(x1)y = T
B(x2)y = T
B(x3)y = T
Please check the attached file for a detailed answer.
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Two students push on a crate to slide it across the floor. One student exerts a force of 5 N to the east, and the second exerts a force of 4 N to the south. What is the magnitude of the net force the students exert on the crate
The magnitude of the net force the students exert on the crate is 6.40 N.
We have to apply the Pythagorean theorem so we have:
F= [tex]\sqrt{5^{2}+4^{2} }[/tex]
=[tex]\sqrt{25+16}\\[/tex]
=[tex]\sqrt{41}[/tex]
Finally, we have:
F = 6.40 N
In mathematics, the Pythagorean theorem, or Pythagoras' theorem, is an essential relation in Euclidean geometry some of the three sides of a right triangle. It states that the vicinity of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other aspects.
Pythagorean theorem, the geometric theorem that the sum of the squares at the legs of a right triangle is identical to the rectangular at the hypotenuse (the facet opposite the right perspective) or, in familiar algebraic notation, a2 + b2 = c2.
A Pythagorean triple consists of three fantastic integers a, b, and c, such that a2 + b2 = c2. this sort of triple is normally written (a, b, c), and an instance is (3, four, 5). If (a, b, c) is a Pythagorean triple, then so is (ka, kb, kc) for any wonderful integer.
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An 80-kg hiker climbs to the top of a tall hill and builds up 470,000 j of gravitational potential energy. how high did the hiker climb? round the answer to the nearest hundred. meters
Answer: An 80 kg hiker climbs to the top of a tall hill and builds up 470000J of gravitational potential energy. With this energy, he can climb up to 600m of Hight.
Explanation: To find the answer, we need to know about the Gravitational potential energy.
What is the gravitational potential energy?Gravitational potential energy can be defined as, the potential energy associated with a gravitational field.It has an expression,[tex]U=mgh[/tex]
where,U is the gravitational potential energy, m is the mass of the body, g is the acceleration due to gravity and h is the height.
How to solve the problem?As we know that the expression of height from the expression of gravitational potential energy as,[tex]h=U/mg[/tex]
We have, [tex]m=80kg[/tex] , [tex]U=470000J[/tex] and [tex]g=9.8 m/s^{2}[/tex] .Substituting these into the equation, we get, height as,[tex]h=470000/(80*9.8)=599.98=600 m[/tex]
Thus, from the above calculation, we can conclude that, he can climb up to 600m of Hight.
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Answer: 600 m
Explanation: Got correct on Edge
What is an application of a magnetic effect of an electric current?
And how does the application work due to the magnetic effect of an electric current?
Applications of Magnetic Effect of ELectric Current:
Electrical appliances such as the electric doorbell, electric fan, electric engines work on the principle of electromagnets. They are used in lifting weighty iron gears and iron scrap.
What is magnetic effect of electric current short answer?Magnetic field exercises a force on a current carrying conductor. The force exerted on the current carrying conductor depends upon the demand of current and movement of magnetic field acting on it.
What is an example of magnetic effect?Examples of magnetic force is a compass, a motor, the interests that hold stuff on the refrigerator, train tracks, and new roller coasters. All moving costs give rise to a magnetic field and the charges that move through its regions, share a force.
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true or false Immediately after the switch is closed, there is no current flowing through the resistor.
True. Immediately after the switch is closed, current only flows through the capacitor and not through the resistor. This is because the resistor offers resistance to the current flow while the capacitor acts as a short in the circuit.
What is a RC circuit?
Consider the circuit diagram shown below. This circuit is known as an RC circuit. In an RC circuit:
The capacitor C is connected in parallel with resistor R and potential V.When the switch is kept open, i.e. no potential is applied to the circuit for an extended period of time, the charge stored in the capacitor dissipates.This leads to the current to stop flowing thorough the other components of the circuit.Thus, when potential is applied across the capacitor (uncharged), the capacitor initially behaves as a closed wire and offers no resistance as the current flows through it whilst charging it.Once the capacitor has been charged for a long period of time, it acts as a break in the circuit wherein no current can flow through it.Now, when a switch is placed in the circuit, after the switch has been kept open for a long time, closing it causes the relative current and potential in the circuit to depend upon the state of charge in the capacitor at that instant.Supposing that the capacitor has been kept uncharged for a long period of time, at this instant when the switch is closed, only the current flows through the capacitor and not through the resistor.
This is because the resistor offers resistance to current flow while the capacitor acts as a short in the circuit.
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Binding of a signaling molecule to which type of receptor leads directly to a change in the distribution of substances on opposite sides of the membrane?.
When two sides of a membrane are in contact with each other, the distribution of ions will alter as a result of the binding of a signal molecule to a ligand-gated ion channel.
What is a ligand-gated ion channel?
Ligand-gated ion channels (LGICs) are membrane proteins that are structurally integral and feature a pore that permits the controlled passage of particular ions across the plasma membrane. The electrochemical gradient for the permeant ions drives the passive ion flux.
When a chemical ligand, such as a neurotransmitter, attaches to the protein, ligand-gated ion channels open. Changes in membrane potential cause voltage channels to open and close. When a receptor physically deforms, as in the case of pressure and touch receptors, mechanically-gated channels open.
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8 The diagram shows four identical spheres placed between two wooden blocks on a ruler.
4
A
sphere
bo
0 5
What is the diameter of one sphere?
1.0 cm
B 2.0 cm
₂
10
16
C 3.0cm
wooden block
15 cm
D 4.0cm
9
A length of cotton thread is measured between two points on a ruler as
shown in the figure below
When the length of the thread was wound closely around a pen, it goes round
six times as shown in the second figure below.
The diameter of the sphere is 2cm.
How to calculate the diameter?From the diagram, the first sphere on the ruler is at 4cn and the last sphere is at 12cm.
Therefore, the length will be:
= 12 - 4.
= 8cm
The diameter of one sphere will be:
= Length / 4
= 8/4
= 2
Therefore, the diameter of the sphere is 2cm.
Note that the second question wasn't found online.
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Which astronomer's laws of motion helped to explain the heliocentric model
Answer:
( Galileo )discovered evidence to support Copernicus' heliocentric theory when he observed four moons in orbit around Jupiter
A 5.0-kg object is moving with speed 2.0 m/s. A 1.25-kg object is moving with speed 4.0 m/s Both objects encounter the same constant braking force, and are brought to rest. Which object travels the greater distance before stopping
Acceleration is constant, so we can use the following kinematic equation and Newton's second law.
[tex]{v_f}^2 - {v_i}^2 = 2a\Delta x \implies -{v_i}^2 = -2\dfrac{F}{m}\Delta x \implies {v_i}^2 = 2\dfrac{F}{m} \Delta x[/tex]
where [tex]v_i[/tex] and [tex]v_f[/tex] are initial/final velocities, [tex]a[/tex] is acceleration, [tex]\Delta x[/tex] is displacment, [tex]F[/tex] is force, and [tex]m[/tex] is mass. Since the objects are coming to rest, the acceleration opposes the direction of motion and is negative.
Solve for [tex]\Delta x[/tex].
[tex]\Delta x = -\dfrac{m {v_i}^2}{2F}[/tex]
Compute the displacements of both objects.
[tex]\Delta x_{5.0\text{-kg}} = -\dfrac{(5.0\,\mathrm{kg}) \left(2.0\frac{\rm m}{\rm s}\right)^2}{2F} = -\dfrac{10}F \dfrac{\rm m}{\rm N}[/tex]
[tex]\Delta x_{1.25\text{-kg}} = -\dfrac{(1.25\,\mathrm{kg}) \left(4.0\frac{\rm m}{\rm s}\right)^2}{2F} = -\dfrac{10}F \dfrac{\rm m}{\rm N}[/tex]
Then both objects are displaced by the same amount.
Answer:
They stop in the same distance
Explanation:
f friction is the same for both and must overcome the KE of each object to bring each to rest.
f friction * d = 1/2 mv^2 for each object :
f * d1 = 1/2 m1 v1^2 f * d2 = 1/2 m2 v2^2
= 1/2 5 (2 )^2 = 1/2 1.25 (4)^2
Object 1 KE = 10 j Object 2 KE = 10 j
f d1 / f d2 = 10 / 10 ( f is the same for both)
d1 / d2 = 1 so d1 = d2 they stop in the same distance !
Consider two pairs of protons, one pair moving toward each other at a speed of 1000 km/s and the other at a speed of 10 km/s. Which pair of protons will get closer together before they repel each other
The pair of protons with velocity 1000 km/s will get closer together before they repel each other.
To find the correct statement, we need to know about the motion of protons.
What's proton?Proton is a possibility charged subatomic particle.It resides within the nucleus.What's happened when a pair of protons moves towards each other?As a pair of protons are similarly charged, so they will be repelled when they are approach very close.Also, the closeness of approaching depends directly on the kinetic energy of these protons.So, more the velocity of the protons leads to more kinetic energy and more the closeness between them.Thus, we can conclude that the pair of protons with velocity 1000 km/s will get closer together before they repel each other.
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Horizontal angulation is: Group of answer choices the side-to-side angulation. different when using the paralleling and bisecting techniques. correct when the central ray is parallel to the curvature of the arch. determined by the Stabe bite-block.
Option A is correct as horizontal angulation is the side- to -side angulation.
When the dental X-ray tube head is positioned and the center ray is pointed in a horizontal, or side-to-side, plane, this is referred to as horizontal angulation.
It remains the same when using the paralleling and bisecting techniques.
The central ray should not be directed parallel to the curvature of the arch.
Instead, it is pointed perpendicular to the curve of the tooth arch and film to prevent errors in x-ray interpretation.
A radiograph with "open" contacts is the result of proper horizontal angulation.
A radiograph with "overlapped" contacts results from incorrect horizontal angulation.
Hence, option A is correct
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SOMEONE PLEASE HELP
A sealed pot is allowed to cool off. This is an example of
1)increasing energy of an open system.
2)decreasing energy of an open system.
3)increasing energy of a closed system.
4)decreasing energy of a closed system.
Answer:
4 decreasing energy of a closed system
An automated machine passes milk through steam at a temperature of 138OC for two seconds and then cools it rapidly. This is an example of ____________________.
Option (c) is correct
This is an example of Ultra-high-temperature pasteurization(UHT).
For ultra-high-temperature (UHT) pasteurization, milk or cream must be heated for one or two seconds to 138–150 °C (280–302 °F).
The most popular application of UHT is in the production of milk, although it is also used in the production of fruit juices, cream, soy milk, yoghurt, wine, soups, honey, and stews.
The normal unrefrigerated shelf life of UHT milk in a sterile container is six to nine months.
UHT milk is aseptically packaged to provide a shelf-stable good. A sterile product is put within a sterile package using aseptic packaging and such processing needs to happen in a sterile setting.
Both pasteurization and sterilization help in the destruction of microbes and enzymes by heating but pasteurization only kills the vegetative stage of the bacteria, which is where the spores survive, whereas sterilization kills all microorganisms and their spores.
Therefore, an automated machine passes milk through steam at a temperature of 138°C for two seconds and then cools it rapidly is an example of Ultra-high-temperature pasteurization.
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The pilot of the fighter jet turns by banking the wings such that the lift of the wings has a component in
the direction of the centre of the turn. The pilot wishes to turn the jet in a tight radius of 960.0 m while
maintaining a constant circular speed of 1440 km/h. Determine the angle of bank needed, measured from
the vertical.
The angle of bank needed, measured from the vertical is 86.6⁰.
Banking angle of the circular path
The angle of bank needed, measured from the vertical is calculated as follows;
v = √(rg tanθ)
where;
v is the speed = 1440 km/h = 400 m/sr is radius of the curve = 960 mg is acceleration due to gravityθ is the banking angle400² = (960 x 9.8 x tanθ)
tanθ = 400²(960 x 9.8)
tanθ = 17
θ = arc tan(17)
θ = 86.6⁰
Thus, the angle of bank needed, measured from the vertical is 86.6⁰.
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A heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h. If the COP of the heat pump is 2.8, determine the power the heat pump draws when running.
The power that heat pump draws when running will be 6.55 kj/kg
A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).
Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8
We have to determine the power the heat pump draws when running.
To solve this question we have to assume that the heat pump is at steady state
Let,
Q₁ = 22000 kj/kg
COP = 2.8
Since heat pump used to heat a house runs about one-third of the time.
So,
Q₁ = 3(22000) = 66000 kj/kg
We known the formula for cop of heat pump which is as follow:
COP = Q₁/ω
2.8 = 66000 / ω
ω = 66000 / 2.8
ω = 6.66 kj/kg
Hence the power that heat pump draws when running will be 6.55 kj/kg
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which type of rock can only form below earths surface?
Answer: Igneous it forms because of magma but magma is under the earths surface so its Igneous
Explanation:
Answer:
its metamorphic.
Explanation:
Moving a charge from point A, where the potential is 400 V, to point B, where the potential is 120 V, takes 4.3×10−4 J of work
What is the value of the charge?
Express your answer with the appropriate units.
The charge is obtained as 1.5 * 10^-5 C.
What is potential?The electric potential is the work done in moving a unit charge from one point to another.
Now we have;
W = -QdV
W = Work done in joules
Q = charge
dV = voltage change
Hence;
4.3×10−4 =- Q( 120 - 400)
Q = 4.3×10−4/280
Q = 1.5 * 10^-5 C
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A baseball rolls along a flat parking lot in a straight line at a constant speed of 3.8 m/s. How
far will the baseball roll in 15s?
This is a uniform rectilinear motion (MRU) exercise.
To start solving this exercise, we obtain the following data:
DATA:V = 3.8 m/sD = ¿?T = 15 secTo calculate the distance, multiply the speed by the time.
We apply the following formula: d = v * t
We clear our data in the formula:
[tex]\bf{d=3.8\dfrac{m}{\not{s}}*15 \not{s} }[/tex]
[tex]\bf{d=57 \ m}[/tex]
The baseball in 15 seconds will roll a distance of 57 meters.
{ Pisces04 }
explain about 3 pulley sytem and 4 pulley system and both of their uses.
Answer:
Fixed pulleys are a very common pulley. These pulleys are secured to a single spot. ...
Movable Pulleys are yet another type of pulley. ...
Compound Pulley Systems are a combination of both movable and fixed pulleys.
Explanation:
there are three different types of pulleys:
Fixed pulleys are a very common pulley. These pulleys are secured to a single spot. ...
Movable Pulleys are yet another type of pulley. ...
Compound Pulley Systems are a combination of both movable and fixed pulleys.