A thumbtack that is tossed can land point up or point down. The probability of a tack landing point up is 0.2. A simulation was conducted in which a trial consisted of tossing 5 thumbtacks and recording the number of thumbtacks that land point up. Many trials of the simulation were conducted and the results are shown in the histogram.
Based on the results of the simulation, which of the following is closest to the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed?
A 0.09
B 0.19
C 0.28
D 0.72
E 0.91
Answers
Answer:
Option C: 0.28
Step-by-step explanation:
This is a binomial probability distribution problem.
Now, we want to find the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed. This is written as;
P(X ≥ 2) = P(2) + P(3) + P(4) + P(5)
From the histogram;
P(5) = 0.02
P(4) = 0.02
P(3) = 0.05
P(2) = 0.19
Thus;
P(X ≥ 2) = 0.19 + 0.05 + 0.02 + 0.02
P(X ≥ 2) = 0.28
From the histogram, it is found that there is a 0.28 = 28% probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed, option C.
------------------
The probabilities given by the histogram are:
[tex]P(X = 0) = 0.33[/tex]
[tex]P(X = 1) = 0.39[/tex]
[tex]P(X = 2) = 0.19[/tex]
[tex]P(X = 3) = 0.05[/tex]
[tex]P(X = 4) = 0.02[/tex]
[tex]P(X = 5) = 0.02[/tex]
The probability of at least 2 up is:
[tex]P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.019 + 0.05 + 0.02 + 0.02 = 0.28[/tex]
0.28 = 28% probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed, option C.
A similar problem is given at https://brainly.com/question/24141790
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Answers
Answer:
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Step-by-step explanation:
z = (x-μ)/σ,
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σ is the population standard deviation.
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Approximately = 15.21 years