A stuntman drives a car with a mass of 1800 kg on a drawbridge. The car
accelerates resulting from a constant force of 8200 N. While he is driving, the
drawbridge is raised to an incline of 30°. What is the car's new acceleration
on this incline, ignoring the force due to air resistance? (Recall that g = 9.8
m/s²)
30⁰
Force accelerating car
Weight
A. 0.3 m/s²
B. 1.2 m/s2
C. -2.5 m/s²
D. 4.0 m/s²
Halp

We will have the following:

First, we remember:

Then we will have:

So, the frequency of the wave is 53.5 Hz.

The work that was done on the system is 326 J.

The work done in moving the charge over the distance is calculated as follows;

W = Fr

W = (kq²)/r

where;

W = (9 x 10⁹) x (6 x 10⁻⁶)² / (30 x 10⁻³)

W = 360 J

The total work done on the system is calculated as follows;

Wt = Wc - We

where;

Wt = 360 J - 34 J

Wt = 326 J

Thus, we can conclude that the net work done on the system is obtained by subtracting the work done that went into thermal energy from the work done in moving the charge.

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The specific heat of the metal is  2178.7 J/kg⁰C.

The specific heat capacity of a substance is the quantity of heat needed to raise a unit mass of a substance by 1 kelvin.

The specific heat capacity of the metal is calculated by applying the principle of conservation of energy.

Heat lost by the metal = Heat gained by the ice

m₁c₁(T₁ -T) = m₂c₂(T - T₂)

where;

(1)(c₁)(5 - -8.88) = (1)(2000)(-8.88 - - 24)

(1)(c₁)(5 + 8.88) = (1)(2000)(-8.88 + 24)

13.88c₁ = 30,240

c₁ = 30,240/13.88

c₁ = 2178.7 J/kg⁰C

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Answer:

2180

Explanation:

trust me bro

Horizontal force required to slide a 150 N crate with uniform motion across a floor where the coefficient of kinetic friction is 0.20 is calculated to be 30 N .

A force that is applied in parallel to the horizon is known as horizontal force. The force exerted on a body has two components, that is the horizontal component and a vertical component.

Two types of horizontal force are :

Given , force = 150 N

Coefficient of kinetic friction, μ  = 0.20

Horizontal force, F = μmg

=0.20* 150

Horizontal force = 30 N

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The net external force exerted on a 1000-kg artillery shell accelerated at 2.80 ✕ [tex]10^{4}[/tex] m / s² fired from a battleship is 2.8 * [tex]10^{7}[/tex] N. The magnitude of the force exerted on the ship by the artillery shell is - 2.8 * [tex]10^{7}[/tex] N.

According to Newton's second law of motion,

F = m a

F = Force

m = Mass

a = Acceleration

m = 1000 kg

a = 2.80 ✕ [tex]10^{4}[/tex] m / s²

F = 1000 * 2.80 ✕ [tex]10^{4}[/tex]

F = 2.8 * [tex]10^{7}[/tex] N

This is the net external force exerted by the shell on the battleship.

According to Newton's third law of motion,

[tex]F_{BS}[/tex] = - [tex]F_{SB}[/tex]

[tex]F_{BS}[/tex] = Force exerted by the battleship on the shell

[tex]F_{SB}[/tex] = Force exerted by the shell on the battleship

[tex]F_{BS}[/tex] = 2.8 * [tex]10^{7}[/tex] N

[tex]F_{SB}[/tex] = - [tex]F_{BS}[/tex]

[tex]F_{SB}[/tex] = - 2.8 * [tex]10^{7}[/tex] N

Therefore,

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In order to find the orbital radius, we need to use Kepler's third law's equation

The formula states:

T^2/R^3 = 4pi^2/G(m)

Since the satellite is geostationary, weknow that the period of the satelitte is going to be 10.6 hours

Plugging in everything we know already

(10.6)^2/R^3 = 4pi^2/G(5.7*10^26)

(10.6)^2/4pi^2/G(5.7*10^26) = R^3

solve for R^3 = 1.08*10^17

R = 476523 m from the surface of Saturn

5.4*10^7 + 476523 = 54476523 meters for the orbital radius

Answer:

Each layer has a unique chemical composition, physical state, and can impact life on Earth's surface. Movement in the mantle caused by variations in heat from the core, cause the plates to shift, which can cause earthquakes and volcanic eruptions.

Given that the distance between the two charged particles is increased by 4 times the amout, let's determine how the electrical force between them will change.

The electrical force between two charged particles is determined by the formula:

Where:

k is the constant

q1 and q2 are the two charged particles

r is the distance between the particles

From the formula, we can see that the electrical force between them is inversely proportional to the the square of the distance between the charged particles.

Thus, in order to increase the electrical force, the distance must be decreased.

If the electrical force is changed by a factor of

Answer:

3

Explanation:

because half I think is the answer

Answer:

10 m

Explanation:

5  m/s   *   2 s = 10 meters     ( see how the  ' s '  cancels out?)

A 44 kg child steps onto a scale and reads 430 N so the magnitude of the normal force acting on the child will be 430 N.

The normal force is a common force that is experienced when an object is placed on a surface and pushed against it. For instance, the normal force prevents a book from falling through a table when it is placed on one. The book is being pulled downward by gravity, but because it isn't truly falling, something must be pushing it upward. The normal force is what we refer to as. Normal refers to something that is perpendicular to the surface.

According to the question,

Normal Force=Weight of the person

= 430 N

So, the Magnitude of the normal force acting on the child will be 430 N.

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The magnitude of the vector sum of the two vectors V and W is determined as 240.84 m.

Resolution of the vectors in x and y axis

The given vector can be resolved into x and y axis as follows;

Vx = Vcosθ

Vx = 448cos(224)

Vx = -322.26

Vy = Vsinθ

Vy = 448 x sin224

Vy = -311.2

Wx = 336 x cos(75.9)

Wx = 81.86

Wy = 336 x sin75.9

Wy = 325.88

∑X = -322.26 + 81.86 = -240.4

∑Y = -311.2 + 325.88 = 14.68

Resultant vector

R = √[(-240.4)² + (14.68)²]

R = 240.84 m

In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity. A vector does not have position, while having magnitude and direction. In other words, a vector's shape is unaltered if it is shifted parallel to itself as long as its length is unaltered.

Ordinary quantities with a magnitude but no direction are referred to as scalars in contrast to vectors. For instance, while speed, time, and mass are scalars, displacement, velocity, and acceleration are vector values.

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The components of a 15 meters per second velocity at an angle of 60 above the horizontal are 13.05 m / s and 0.435 m / s

Resolving the velocity into its horizontal and vertical components, it makes a right angled triangle.

Hypotenuse = V = 15 m / s

θ = 60°

Opposite side = components = [tex]V_{y}[/tex]

Adjacent side = Horizontal component = [tex]V_{x}[/tex]

In a right angled triangle,

sin θ = Opposite side / Hypotenuse

cos θ = Adjacent side / Hypotenuse

sin 60° = [tex]V_{y}[/tex] / V

[tex]V_{y}[/tex] = 15 * 0.87

[tex]V_{y}[/tex] = 13.05 m / s

cos 60° = [tex]V_{x}[/tex] / V

[tex]V_{x}[/tex] = 0.5 * 0.87

[tex]V_{x}[/tex] = 0.435 m / s

Therefore,

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Answer:

Explanation:

Angle:

β = - 23°

( From the symmetry condition)

The accelerations due to gravitational force on the moon and the Earth different due to difference in mass of its body and its radius. No, gravitational field cannot be shielded in a vacuum.

Acceleration due to gravity = Local gravitational field strength = g

g = G M / r²

G = Gravitational constant

M = Mass of the body

r = Radius of the body

G = 6.67 * [tex]10^{-11}[/tex] N m²

From the equation,

g ∝ M

g ∝ 1 / r²

Since the Earth is much bigger and heavier than moon, the acceleration due to gravity is much lesser in moon in comparison with Earth.

Therefore, the accelerations due to gravitational force on the moon and the Earth different due to difference in mass of its body and its radius. No, gravitational field cannot be shielded in a vacuum.

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This is an example of F = ma because the net force applied is directly proportional to the weight (mass) of the basket.

Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.

Mathematically, Newton's Second Law of Motion is given by this expression;

F = ma

Where:

In conclusion, the above scenario is an example of the demonstration of Newton's Second Law of Motion.

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The final speed of the crate with an initial speed of 0.76 m / s accelerated at 0.035 m/s for 28.0 s along a conveyor belt is 1.74 m / s

v = u + at

v = Final speed

u = Initial speed

a = Acceleration

t = Time

a = 0.035 m / s²

y = 28 s

u = 0.76 m / s

v = 0.76 + ( 0.035 * 28 )

v = 0.76 + 0.98

v = 1.74 m / s

The equation used to solve the problem is an equation of motion. An equation of motion describes the position of an object using acceleration, displacement, time, initial and final velocities.

Therefore, the final speed of the crate is 1.74 m / s

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The speed (in cm/s) of the electron, given that it travels 2.68 m in 6.11×10⁻⁸ s is 4.39×10⁵ cm/s

We'll begin by defining speed. This is given below.

Speed is defined as the distance travelled per unit.

Speed = distance / time

With the above formula, we can obtain the speed of the electron. Details below

The following data were obtained from the question give above:

Speed = distance / time

Speed = 0.0268 cm / 6.11×10⁻⁸ s

Speed = 4.39×10⁵ cm/s

Therefore, the speed is 4.39×10⁵ cm/s

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The tension in the cable during this motion will be 3750 lbs , when a steel cable carries a 3000 lbs load which is descending with a speed of 12 ft/s.

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The dot used to represent the Sun’s location in the picture is too large to represent the size of the Sun on the picture.

1 cm = 10000 light-years

1 mm = 1000 light-years

Dot = 0.5 to 1 mm

Diameter of the Sun = 1.5 * [tex]10^{-7}[/tex] light-years = 1.5 * [tex]10^{-10}[/tex] mm

On comparing, the Sun should not be visible to a human eye in that picture. Even using an Electron microscope, we cannot spot the Sun according to the given scale.

A light-year is a measurement of distance. It is the distance travelled by light in one year.

Light speed = 300000 km / s = 9.46 * [tex]10^{12}[/tex] km / yr

1 light year = 9.46 * [tex]10^{12}[/tex] km

Diameter of sun = 1.39 * [tex]10^{6}[/tex] km

Therefore, the dot used to represent the Sun’s location in the picture is too large to represent the size of the Sun on the picture.

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Answer:

It is because of the pressure exerted by water. As the depth of water increases, the pressure also increases.

Explanation:

The orbital period could be obtained from the question as 8.98 * 10^7 m.

We know that the solar system is composed of the sun and the planets. The planets are known to move around the sun in concentric circles. Following the heliocentric model of the solar system, the sun is at the center of the solar system at all times and all the other planets tend to move round the sun at a good distance that is appropriate for each.

Now we have that;

T = √4π^2r^3/GM

T = period of the orbit

r = radius of the orbit

G = gravitational constant

M = mass of the planet

Hence, we have;

R = ∛T^2GM/4π^2

R =∛ (26 * 60 * 60)^2 * 6.67 * 10^-11 * 4.9 * 10^25/ 4 * (3.142)^2

R = ∛2.86 * 10^25/39.49

R = 8.98 * 10^7 m

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The electric field at point P  is mathematically given as

E=-6.69n-m^2/c

This is further explained below.

Generally, the equation for magnetic Flux is mathematically given as

[tex]Flux $=\mathrm{E}.2 \mathrm{~A}\\=\mathrm{Q}_{\text { enc }} / \varepsilon_0$[/tex]

[tex]=\mathrm{E} 2 \mathrm{~A}\\\\=\mathrm{p} * \mathrm{Vol} / \varepsilon_0$[/tex]

[tex]=E 2\left(d x^* d y\right)\\\\=p^*\left(d x^* d y^* 2^* d z\right) / \varepsilon O$[/tex]

E=p^* d z /

Taking into account the fact that Let the permittivity of the slab is approximate:

[tex]$\varepsilon O=8.85^* 10^{\wedge}-12 \mathrm{~F} / \mathrm{m}$[/tex]

Distance from the origin to the point in question:

dz=0.0015m

Charge distribution over the slab is uniform:

[tex]&\mathrm{p}=\mathrm{Q} / \mathrm{vol}=\left(-7.9 * 10^{\wedge}-11\right) \mathrm{C} /\left(0.005^* 2 * 2\right) \mathrm{m}^{\wedge} 3 \\[/tex]

p=-3.95^* 10^-9

[tex]\mathrm{E}=\mathrm{p}^* \mathrm{dz} / \varepsilon 0\\\\=\left(3.95^* 10^{\wedge}-9 * .0015\right) / 8.85^* 10^{\wedge}^{-11} \\[/tex]

E=-6.69n-m^2/c

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The rider's apparent weight during the launch is 2940 N.

When the rider is rest, the forces acting on the skyward (y-direction) are mg towards earth and F_N opposite to mg. Total force will be,

F = F_N - mg

The mass of the rider is 60 kg. When riders are launched skyward with an acceleration of 4g, the force

F = ma = m*4g

F_N - mg = m*4g

F_N - 60*9.8 = 60*4*9.8

F_N - 588 = 2352

F_N = 2352 + 588 = 2940 N

The rider's apparent weight during the launch is 2940 N.

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It will take exactly 84 days with all the researcher's experiments , even after reducing the total time needed to process all samples.

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As the source moves toward the stationary observer, the frequency the woman will hear the sound from the siren will be 484.5 Hz

Doppler effect is the frequency change due to the relative motion between a sound or light and an observer.

Given that a woman is sitting at a bus stop when an ambulance with a siren wailing at 440 Hz approaches at 31.5 m/s. If the speed of sound is to be 343 m/s, the frequency the woman hear the sound can be calculated by using the formula

Fo = FsC/(C - V)

Where

Substitute all the parameters into the formula

Fo = (440 × 343) / (343 - 31.5)

Fo = 150920 / 311.5

Fo = 484.5 Hz

Therefore, the woman will hear the sound from the siren at the frequency of 484.5 Hz

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Since the cruise ship makes its way from one island to another. The ship is in motion is compared with the reference point of option C. a lighthouse on a nearby island.

Sine the cruise ship from one Island  is relocating, the lengthy duration by the passengers within the ship makes it simple to detect the ship motion.

The skipper is the only one who is aware of the ship's direction and speed. Even though the cargo loads are stable and related to the ship's course, we cannot take them into account when calculating the traveling distance of the ship.

Since it is in the sea and relatively close to it, the lighthouse on the island can be used to calculate the distance traveled by ships. Due to its stability, we can use it as a reference point in the water that can be seen from a great distance.

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See full question below

A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?

A.

the passengers on the ship

B.

the captain of the ship

C.

a lighthouse on a nearby island

D.

the cargo inside the hull of the ship

The distance the boy can walk to the support = Lm

Board force = Fb = 200 N

Rope breaking stress = Fr = 400 N

Distance to rope = Lr = 6 m

Boy = Fm = 400N

Distance to the center of gravity of the board = Lb = 3m

According to the balance rule:

All moments and forces on the board are 0,

= (Fr)(Lr) - (Fm)(Lm) - (Fb)(Lb) = 0

= (400)(6) - (400×Lm) - (200)(3) = 0

= 2400 - 600 = 400 × Lm

= 400× Lm = 1800

= Lm = 1800

400

= Lm = 4.5m.

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The maximum stress that a material can withstand before it breaks is called breaking stress or breaking stress. Also. Breaking stress is the maximum force that can be applied to a cross-sectional area of ​​material so that it cannot withstand additional stress before it fails.

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We will haev the following:

So, the density of the material is 175/31 g/cm^; that is approximately 5.6 g/cm^3.

Answer:

1. B. Kinetic energy is transferred from Terry's foot to the soccer ball.

2. A. A baseball bat strikes a baseball.

3. A. 173.28J

4. D. Kinetic energy is transferred from the racket to the ball.

Explanation:

I took the quiz and got 100%

Answer:

1. Kinetic energy is transferred from Terry's foot to the soccer ball.

2. A baseball  bat stricks a baseball

3. 173.28

4. kinetic energy is transferred from the racket to the ball

5. 1,102.5 J

remember to keep the decimal on the last one

Explanation: They added another question so I decided to give the answer to those who had it.