Answer:
p = w/t = mgh/t = 60kg*7.2m*10.4sec/10.4 = 432 watt
The stability of a nucleus is based not on the binding energy but on the binding energy per ____________.
A. Neutrino
B. Proton
C. Electron
D. Nucleon
describe how heat energy can be transferred to either kinetic energy or gravitational potential energy
Answer:
Potential energy can transfer into other forms of energy like kinetic energy. Kinetic energy is energy an object has because of its motion. ... If released, as the ball moves faster and faster toward the ground, the force of gravity will transfer the potential energy to kinetic energy.
On a microscopic scale, conduction occurs as rapidly moving or vibrating atoms and molecules interact with neighboring particles, transferring some of their kinetic energy. Heat is transferred by conduction when adjacent atoms vibrate against one another, or as electrons move from one atom to another.
In steam engine , pistons remove some heat energy from hot gases and then uses these moving pistons to power the device attached that is hooked up . This is how heat energy can be converted to kinetic energy.
Heat engine with their thermal energy can lift up weights or pumping water to a certain height is an example that how thermal energy can be used to move an automobile to higher altitude .
What is Heat/Thermal energy ?
Heat energy is the result of the movement of tiny particles called atoms, molecules or ions in solids, liquids and gases. Heat energy can be transferred from one object to another.
In steam engine , pistons remove some heat energy from hot gases and the steam engine then uses these moving pistons to power the device attached that is hooked up . This is how heat energy can be converted to kinetic energy.
Similarly heat engine with their heat energy can lift up weights or pumping water to a certain height is an example that how heat energy can be used to move an automobile to higher altitude.
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HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE
[tex]A_x = 5.0[/tex]
[tex]A_y = -6.3[/tex]
A diagram is drawn showing a swing set with a swing pulled backward prior to release. The diagram shows how the swing will move forward and then backward after it is initially released. At which point in the diagram is all of the energy gravitational potential energy?
A) as the released swing begins moving backward
B) at the highest point as the swing moves forward
C) when the swing is pulled back prior to release
D) just after release of the swing
Answer:C) When the swing is pulled back to prior release
Explanation:
This question involves the concepts of the law of conservation of energy, gravitational potential energy, and kinetic energy.
All of the energy is gravitational potential energy at "C) when the swing is pulled back prior to release".
The law of conservation of energy states that at any point the total energy of the swing must be constant, which means:
Total Energy = Gravitational Potential Energy + Kinetic Energy = Constant
It is clear that the swing has a non-zero speed in all given situations except the situation in part C), where the swing is at rest before release. Since the kinetic energy exists due to motion in the object. Hence, the kinetic energy will be zero when the swing is pulled back prior to release. It means all the energy in the swing at this time will be the gravitational potential energy.
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The attached picture explains the law of conservation of energy.
What is the change in the internal energy of a system that does 400 joules of
work and absorbs 700 joules of heat?
A. -1,100 J
B. 1,100 J
C. 300 J
D. -300 J
Answer:
B
Explanation:
Một ô tô khối lượng một tấn chuyển động nhanh dần đều trên một đường bằng, hệ số ma sát giữa bánh xe và mặt đường là 0,1. Lực kéo của động cơ ô tô bằng 1200 N. Lấy g = 10 m/s2. Thời gian cần thiết để ô tô đạt được tốc độ 36 km/h từ trạng thái nghỉ là bao nhiêu?
How to Convert N/m2 to N/cm2 ?
1 newton / square metre =0.0001 newton / square centimetre
Formula = divide the pressure value by 10000
If a person has an acceleration of -1.5 m/s/s, then after 3.0 s thier velocity will have changed by m/s. If the initial velocity of the person was 2.0 m/s, then their new velocity is m/s. The initial velocity was in the direction and their final velocity was in the direction, so this person must have turned around during the 3.0 s. The average velocity of the person during the 3.0 s was m/s so their change in position during the 3.0 s must have been m. However, the distance the actual distance they covered was than their change in position because they changed direction.
If the person's initial position was 2.0 m, then their final position will be _____________ m.
Answer:
-1.5 m/s/s + (3.0 s + 2.0 m/s) = -7.5 m/s/s
-7.5 m/s/s x 3.0 s × 3.0 s × 3.0 s = - 202.5
You have discovered a planet that is one-quarter the radius of Earth (Rp = 1/4R⊕) and one-half as massive (Mp = 1/2M⊕). How does the gravity on the surface of this planet compare to the gravity on the surface of Earth (Fgp = XFg⊕)?
The new planet has the radius of only 1/4th of earth and mass of half that of earth. Then , the gravity on the surface of the new planet will be8 times higher than that of earth.
What is gravitational force?The gravitational force is the force by which an object attracts other object into its center of mass. Earth attracts every objects on ots surface to the ground by gravitation.
The force of gravitation is directly proportional to the mass and inversely proportional to the distance or radius of the planet.
g = G m/r²
Where G is the universal gravitational constant.
The new planet has the mass half of that of earth (me) and radius 1/4th of earth.
gn = G me/2 (re/4)²
= G 16 me/2
= 8 ge
Where ge is the gravity by earth and gn that of new planet. The gravitational force of the new planet will be 8 times greater than that of earth.
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A car moving at 8.5 m/s crashes into a tree and stops in 0.32 s. Calculate the magnitude of the force, in newtons, the seatbelts exerts on a passenger in the car to bring him to a halt. The mass of the passenger is 66.5kg.
Answer:
Explanation:
I=Q2- Q1
And I = F. (t2-t1)
t = 0,32s
v = 8,5 m/s
Q = m.v
Q=66,5.8,5 = 565,25 kg.m/s
F. (t2-t1) = 565,25
F.0,32 = 565,25
F = 1766,4 N
is the answer 1.05m?? help me please. i just want to confrim my answer :3
What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5m/s2
Answer:
F= mass× acceleration
14000 = mass × 5
mass= 14000÷5
mass= 2800
Each of the rods depicted below were machined from same stock metal. They were originally machined to be the same length, but their cross-sectional areas were different. If axial force is applied to each rod such that they all change length by the same amount, which rod experienced the largest force
The force required to extend a rod increases as the cross sectional area
increases.
The rod that experiences the largest force is rod B
Reason:
The elongation of a rod by the application of a force is given by the
following formula;
[tex]\Delta L = \dfrac{F \cdot L}{A \cdot E}[/tex]
From the above equation, we have that the elongation is inversely
proportional to the cross sectional area, such that the extension of a rod by
a given force reduces as the cross sectional area of the rod increases.
Therefore, the force required to extend the length of a rod by a specific
amount increases as the cross sectional area of the rod increases,
indicating that the rod with the largest cross sectional area require the
most force and therefore, experiences the largest force.
The rod that experiences the largest force is the rod with the largest cross
sectional area, which is rod B
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While on her concert tour in the US, my Austrian friend Andrea brought along a small electric
fabric-steamer. The steamer draws a current of 4.2 A on a 220 V line in Austria. If she plugged it
into an electrical line in the US, where the household voltage is 110 V, how much current would
the steamer draw? How well do you think it will perform?
Answer:
A battery connected to a 140 resistor dissipates 17W of power. If the circuit contains only the battery and the resistor, what is the voltage of the battery?
Explanation:
If we were to make water (H20) based on the Key Provided above,what would the water molecule look like
Answer:
Individual H2O molecules are V-shaped, consisting of two hydrogen atoms (depicted in white) attached to the sides of a single oxygen atom (depicted in red). Neighboring H2O molecules interact transiently by way of hydrogen bonds (depicted as blue and white ovals).
which of the following is not a pure substance. A. air B. water C. gold D. glucose
Answer:
C. Gold
Explanation:
Why?
Because air , water, glucose is pure substance or liquid
A device that absorbs and draws heat from a hot object, dispersing it into the
surroundings, is which one of the following?
A. Heat sink
B. Piston
C. Heat engine
D. Internal combustion engine
Answer:
A. Heat sink
Explanation:
Which of the following correctly identifies the relationship between the immune system and the integumentary system (skin, hair, & nails)?
A
The body releases solid, liquid, and gas pathogens
B
Mucus in the mouth, nose, trachea, and lungs captures pathogens
C
Bones create white blood cells
D
Hydrochloric acid in the stomach dissolves pathogens that are ingested
E
Blood carries white blood cells around the arteries, veins, and capillaries
F
The skin is the body's first physical barrier, hairs in the nose filter air as it enters the body, pores in the skin release toxins and pathogens
Answer:
F - The skin is the body's first physical barrier, hairs in the nose filter air as it enters the body, pores in the skin release toxins and pathogens
Neutrons are found in what part of an atom ?
1. Can you give an example of any energy transformation where there is no
dissipation of energy?
Answer:
The notable examples are metal bearings, with occasional lumps on the otherwise smooth surfaces catching against each other, and the flow of an electric
Conversions of Kinetic energy to and from potential energy in vacuum converts with very little loss. If you throw a rock up against gravity in a vacuum, that rock will reach a potential energy that is almost exactly equal to the initial kinetic energy. When the rock reaches its peak and comes back down, its kinetic energy will be almost exactly the same when it reaches the original altitude.
4word puzzle about sounds waves down
A 200 kg object is pulled up an incline plane that has friction as the picture above shows. The object is pulled at a constant velocity. Calculate the tension on the rope.
A. 897 N
B. 936 N
C. 852 N
D. 978 N
Explanation:
the force to pull or push the block upwards (with the rope being parallel to the inclined plane) with 0 acceleration (moves with constant velocity) and therefore the tension on the rope is
Ft = m×g×sin(angle) + y×m×g×cos(angle)
force of gravity force of friction
down (down)
m = the mass of the object = 200kg
g = Earth's gravity acceleration = 9.8m/s²
y = the Greek letter mu, the coefficient of friction (it does not say "static" or "kinetic", I assume kinetic because the object is moving with a constant velocity, but it does not matter here) = 0.05
angle = 25 degrees
the result is N (Newton).
so, let's put the numbers into the equation and calculate :
200×9.8×sin(25) + 0.05×200×9.8×cos(25) =
≈ 828.33 N + 88.82 N ≈ 917.15 N
the closest answer option is B (936 N).
I don't know why there is this difference.
Once you start pulling your object With less force than friction, what should you expect your object to do? What about when your object is pulled with more force than friction?
#Case -1
If Pulling force is less than frictional force the object won't move .
#Case-2
If Pulling force is greater than frictional force then object will be .
In order to calculate friction force you need Limiting friction first .
[tex]\\ \sf\longmapsto F_L=\mu sN[/tex]
u s is coefficient of static friction and N is normal reactionAssertion: An object will continue moving uniformly on a plane frictionless surface till the resultant force acting on it is Not Zero. Reason: The bodies do not change their state of Rest or uniform motion unless an external unbalanced force acts on it
A body continues in its state of rest until it is acted upon by an unbalanced external force.
According to Newton's first law of motion, the reason for motion is the action of unbalanced forces. A body will continue in its state of rest or uniform motion unless it is acted upon by an unbalanced external force. This law also referred to as the law of inertia.
Hence, an object will continue moving uniformly on a plane friction-less surface till the resultant force acting on it is not zero according to this law. Thus, the reason is an explanation for the assertion.
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You want to determine if three different concentrations (25%, 50%, & 100%) are equally effective at inhibiting the growth of Streptococcus in the antimicrobial assay; which of the following statistical tests would be most appropriate to use? a) Student's paired t-test b) t-test for two independent groups c) Analysis of Variance (ANOVA) d) 2x2 contingency table (Chi-squared test)
Answer:
thanks thanks thanks thanks for your points
In a race, Usain Bolt accelerates at
1.99 m/s2 for the first 60.0 m, then
decelerates at -0.266 m/s2 for the final
40.0 m. What was his final velocity? (Unit = m/s)
The figure(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle, starting from θ0=0 rad at t=0s. Draw the angular-position-versus-time graph. Include an appropriate scale on both axes.
Answer:
As position is the product of velocity and time, the area under the velocity-time curve will be the position.
Between 2 and 4 s, the area increases linearly to 20(4) = 80
Between 4 and 6 s, the additional area is 0(2) = 0
Between 6 and 8 s the area increases linearly by -10(2) = -20
which is a decrease.
In the angular-position vs time graph; The angular position is derived from the area under the velocity vs time graph
Attached below is the angular position vs time graph
Given that : Angular position = Angular Velocity * time
As Time increases from 0 to 4 secs the area increases from 0 to 80 rad
As Time increases from 4 to 6 secs the area remains constant i.e. 0 rad
As Time increases from 6 to 8 secs the area under the graph decreases 80 to 60 rad
Hence we can conclude that the Angular position of the graph is derived from the area under the velocity vs time graph.
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Một lò xo nhẹ, treo thẳng đứng có độ cứng k = 100 N/m. Vật nhỏ khối lượng m = 500 g được treo vào đầu dưới của lò xo, dao động điều hòa quanh vị trí cân bằng O. Tính lực đàn hồi của lò xo khi vật trên vị trí cân bằng 9 cm, lấy g = 10 m/s2 .
Answer:20
Explanation:
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An airplane makes a gradual 90 turn while flying at a constant speed of 200 m/s. The process takes 20.0 seconds to complete. For this turn the magnitude of the average acceleration of the plane is
Answer:
Explanation:
The plane travels a distance of 200 m/s(20.0 s) = 4000 m
A 90° turn is π/2 radians
4000 = (π/2)R
R = 8000/π m
a = v²/R = 200²/8000/π = 5π m/s² ≈ 15.7 m/s²
When a airplane makes the graduall 90 turn at constant speed the average acceleration is 14.14 m/s.
What is acceleration?Acceleration equals the change in velocity. The rate of change of velocity per unit time is called acceleration. The unit of acceleration is m/s². It represents the speed of the object along with direction.
Acceleration(a) = dv/dt, dv represents change in velocity and dt represents change in time. Velocity is defined as rate of change of position with time. Acceleration has both magnitude and direction and it is a vector quantity.
Acceleration is of two types- Instantaneous acceleration and average acceleration. Instantaneos acceleration gives the acceleration at that instant where as the average acceleration is obtained by rate of change of velocity with elapsed time.
Average acceleration = Δv / Δt. Δv is the change in velocity and Δt is the elapsed time.
From the given,
An airplane makes 90° turn,
v₁ = 200 i^ (before 90 turn)
v₂ = 200 j^ (after 90 turn)
Δt = change in time
Average acceleration = Δv / Δt
= v₂ - v₁ / 20
= 200 i^ - 200 j^ /20
avg.acc = 10(-i) + 10 (j)
| avg.acc | = √ 10(-i) + 10 (j)
= √2×10
= 14.14 m/s²
Hence, the average accleration is 14.14 m/s².
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