A student runs a simulation of a skateboarder going back and forth on a U-shaped ramp. The skateboarder begins with 1,560 joules of potential energy. The bar graph shows the energy of the skateboarder system at the end of the simulation. What are the potential energy (PE) and kinetic energy (KE) of the skateboarder at the end of the simulation?

PE = 520 J; KE = 520 J.

PE = 0 J; KE = 1,560 J.

PE = 0 J; KE = 0 J.

PE = 780 J; KE = 0 J.

The acceleration will be constant and in a downward direction. And as the ball moves in direction of the acceleration so the velocity will keep increasing because velocity is inversely proportional to height, when the ball is in free fall.

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is accelerating.

Free fall is characterized as a condition where an object is only affected by gravity. The ball experiences an external force, which quickens its motion. Gravitational acceleration is another name for this rate of free-fall acceleration. A downward motion without any beginning force or speed is called a free fall.

Hence, the acceleration will be constant and in a downward direction. And as the ball moves in direction of the acceleration so the velocity will keep increasing because velocity is inversely proportional to height, when the ball is in free fall.

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The concept that the information applies to is illustrated below:

Dark matter:

Detected through its gravitational attraction

Has mass

Most common forms of mass in the halo of the Milky way galaxy, likely to consist of subatomic particles.

Dark energy:

Inferred to exist from the measured acceleration of the universe's expansion.

The proposed source of a universal repulsive force.

Dark matter and dark energy:

The universe contains more of this than it contains matter made from atoms.

We do not know what it is made of.

Neither:

Blocks light from stars behind it, 'dark' because it emits only infrared light.

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A spring will therefore need 72 J of work to stretch an additional 4 cm from its equilibrium length if it takes 9 J to stretch it that far.

The length of a multi-mode optical fiber required to achieve a static mode distribution from a particular excitation condition is known as the equilibrium length, and it is sometimes used to characterize stationary mode distributions. There is a location where the weight and spring force are equal in magnitude but in the opposite direction. The equilibrium position is where you are at this moment. There is a net force known as the restoring force that is directed toward the equilibrium position if the mass is in any other position.

F = -kx. The proportional constant k is referred to as the "spring constant". It gauges the stiffness of the spring. When a spring is stretched or compressed to a length that differs by an amount equal to or greater than x, it produces a force F = -kx in the direction of its equilibrium position. From its equilibrium length.

Knowing that the results of the work done to lengthen the springs will be reported as

U=1/2kx

so here we have

9= 1/2 k〖(0.02)〗^2

so we have

K=45000N/m

Now, we must locate the work completed to extend the spring from x = 2 cm to x = 4 cm

here we have

U=1/2 k(x 2/1-x 2/2

now we have

U=1/2(45000)(〖0.06)〗^2-〖0.02〗^2)

U= 72J

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The net force is 5 N and the class that won is Mrs. Wade's class (Option B)

We can obtain the net force by using the following formula:

Net force = Opposite force - force of pull

Now, we shall determine the net force as illustrated below:

Net force = Opposite force - force of pull

Net force = Mrs. Wade’s class - Mrs. Hankinson’s class

Net force = 105 - 100

Net force = 5 N

From the above calculation, we can say that the net force is 5 N and the class that won given the above data is Mrs. Wade’s class

Therefore, the correct answer to the question is:

5 N, Mrs. Wade's class (Option B)

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Answer:

heat and pressure is the correct answer

Only when heat is transferred from the system to its surroundings does a closed system suffer a decrease in entropy.

define entropy ?

Entropy is a key term in physics and chemistry, and it also has applications in cosmology and economics. It is a branch of physics known as thermodynamics. It is a key idea in physical chemistry.

Entropy is the measure of the disorder of a system. It is a comprehensive feature of a thermodynamic system, which implies that its value varies with the amount of matter present. Entropy is usually denoted by the letter S in equations and has units of joules per kelvin (JK1) or kgm2s2K1. Entropy is low in a highly ordered system.

Only when heat is transferred from the system to its surroundings does a closed system suffer a decrease in entropy.

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The amount of force that hit the wall is 200N.

Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body and which has a direction.

The force can be calculated by multiplying the mass by the acceleration as follows:

Force = mass × acceleration

According to this question, an object of 20kg accelerates at 10 m/s² into a wall. The force applied is as follows:

Force = 20kg × 10m/s² = 200N

Therefore, 200N is the force applied by the object on the wall.

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Answer:

this video shows how to solve the problem :)

Explanation:

The acceleration will be 0.2m/s^2 while the velocity will be 1m/s

Force = 300N

Mass = 1500kg

Time = 5 seconds

We know that

Force = ma

a = F/m

a = 300/1500

a = 0.2 m/s^2

Also, the expression for Velocity is given as

Ft = mv

300*5 = 1500*v

Making velocity the subject of the formula we have

1500 = 1500*v

v = 1 m/s

The rate of change of an object's velocity with respect to time is defined as acceleration.

Acceleration implies that the speed is changing, but this is not always the case. When an object moves in a circular path at a constant speed, it is still accelerating because its velocity direction changes.

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The Hypnotic Induction Profile (HIP) or the eye roll test, first proposed by Herbert Spiegel, is a simple test to loosely determine if a person is susceptible to hypnosis. A person is asked to roll their eyes upward. The degree to which the iris and cornea are seen is measured.

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According to the given statement, the speed of a point on the rim  is 2.68 m/s.

Energy is a major factor in our everyday routines even though it is an essential need for humans. Our human-made structures are not only heated by energy, but also cooled by it. To lift you finger, climb out of bed, or even stroll down main sidewalk, you need energy.

kinetic energy = E = 0.18 J  

mass = m = 100g = 0.1 kg

diameter = d = 8.0 cm = 0.08 m

Speed = v = ?

v = 2.44 m/s

Briefing:

First convert diameter into radius

r = d/2 = 0.08/2 = 0.04 m

The moment of inertia of disc is given by

I = 0.5mr²

In which m is the disk's mass & r is its radius

I = 0.5(0.1)(0.04)²

I = 0.00008 kg.m²

Additionally, since we are discussing rotating motion, rotational kinetic energy is provided by

E  =  0.5 I ω²

we have to separate ω

ω² = E/0.5 I

ω = √E/0.5 I

ω = √0.18/0.5(0.00008)

ω = 67.08 rad/sec

Finally we know that speed is given as

v = ω r

v = 67.08 (0.04)

v = 2.68 m/s

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If all pipelines are round and of the same elevation as the question suggests, then point B's gauge pressure is 11.5 KPa.

Distance above water level is known as elevation. Elevations are often expressed in feet or meters. On charts, they can be represented by contour lines that link points of the same elevation, by colours, or by numbers that indicate the precise elevations of specific places on the Planet's surface.

From continuity equation:

Velocity of water at B = (2*pi*3²)/[2*pi*1²] =9 m/s

then from Bernoulli equation;

v² /2 + φ + p/ρ =constant

ρ=1000 kg/m³

3²/2 +φ +50000/1000 = 9²/2 +φ +P/1000

Therefore,

Pressure at B = 11.5 KPa

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The complete question is-

The 3.0 cm-diameter water line in the figure splits into two 1.0 cm-diameter pipes. All pipes are circular and at the same elevation. At point A, the water speed is 2.0 m/s and the gauge pressure is 50 kPa.

What is the gauge pressure at point B?

The answer to the question is 5.66 feet for the channel's diameter after 2 if it is 12 feet wide at 1.

Simply expressed, upstream activities comprise the discovery and production of petroleum and natural gas, whereas downstream activities relate to the procedures used from the extraction phase until the product is given to the client in the desired shape.

[tex]$$\begin{aligned}& F r_1=\frac{V_1}{\sqrt{g V_1}}=0.5 \text {, or } \sqrt{g Y_1}=2.0 V_1 \\& \text { and } \\& F_{r_2}=\frac{V_2}{\sqrt{g y_2}}=3.0 \text { where } y_2=0.5 y_1 \\& \text { Thus, } \frac{V_2}{\sqrt{0.5 g Y_1}}=3.0 \text {, or } \sqrt{g y_1}=V_2 /(3 \sqrt{0.5}) \\& \text { By equating Eq. (1) and }(2) ; 2.0 V_1=V_2 /(3 \sqrt{0.5}) \\& \text { or } \\& V_2=4.24 V_1\end{aligned}$$[/tex]

However,

[tex]$Q_1=Q_2$[/tex] or [tex]$b_1 y_1 V_1=b_2 y_2 V_2$[/tex]

where [tex]$b=$[/tex] channel width. Thus, with [tex]$b_1=12 \mathrm{ft}$[/tex]

(12ft)y₁(V₁) = b₂(0.5y₁)(4.24V₁) or b₂ = 12ft/0.5(4.24) = 5.66ft

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The complete question is-

In flowing from section 1 to section 2 along an open channel, the water depth decreases by a factor of 2 and the Froude number changes from a subcritical value of 0.5 to a supercritical value of 3.0. Determine the channel width at 2 if it is 12 ft. wide at 1.

According to statement no, only system in general is constrained by conservation of momentum.

A surface is said to be frictionless if it has a loads applied on any thing that is virtually zero or insignificant, i.e., there is no resistance between the surface and the substance, allowing that object simply slide & freely move without any friction.

Although gas, sand, radiation, fields, and minuscule particles are present in outer space, their concentration is too low for them to have a significant impact on spacecraft. As a consequence, traveling objects cannot be slowed down in space by any kind of friction.

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Different landforms are created during the process of water erosion, which flows water downhill. Rills, gullies, streams, rivers, tributaries, waterfalls, floodplains, meanders, lakes, and other natural features

What are the names of a river's beginning and end?

The source and mouth of a river are its beginning and closing, respectively. Before they get to the river's mouth, numerous rivers and streams will converge. The smaller streams and rivers are referred to as tributaries.

A river's beginning is at its mouth, correct?

The mouth of a river is where it flows into an ocean, a lake, or another river. River mouths are extremely dynamic places. The flow of a river collects material from the river, debris through bank erosion, and

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The correct option is, The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too large.

What main conclusion did Shapley draw from his measurements of the distances to the globular clusters?
Shapley concluded (and other astronomers have since verified) that the center of the distribution of globular clusters is the center of the Milky Way as well, so our galaxy looks like a flat disk of stars embedded in a spherical cloud, or 'halo,' of globular clusters.

How did Shapley estimate the location of the Sun in the Milky Way?
Harlow Shapley determined the position of the Sun in the galaxy by measuring the distances to 93 globular clusters of stars.

What is a globular star cluster?
Globular clusters are stable, tightly bound clusters of tens of thousands to millions of stars. They are associated with all types of galaxies. Globular clusters are typically much larger than open clusters and are tightly gravitationally bound.

What are the characteristics of the stars in globular clusters?
Globular clusters are densely packed collections of ancient stars. Roughly spherical in shape, they contain hundreds of thousands, and sometimes millions, of stars. Studying them helps astronomers estimate the age of the universe or figure out where the center of a galaxy lies.

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If initial horizontal velocity  (Vxi) = 10 m/s, then final horizontal velocity (Vxf) = positive 10m/s.

option B is the correct answer.

The horizontal velocity of a projectile is the velocity of the projectile along the x - axis or x - direction.

During the horizontal motion of a projectile, the horizontal velocity of the projectile will be constant since gravity does not act in the horizontal direction.

That is to say, that the initial velocity of the projectile along horizontal direction will be equal to the final velocity of the projectile along the same horizontal direction.

Vxi = Vxf

where;

Thus, If the initial horizontal velocity is 10 m/s. then the final horizontal velocity will be 10 m/s.

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Average force acting on Purley is -1749m/[tex]s^{2}[/tex].

What is Newton's second law of motion?

According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is determined by multiplying its mass by its speed.

Given,

According to newton's second law of motion:

F =ma

Purley's initial speed = 173km/h

Final speed = 0

Distance traveled = 0.66 m

So, [tex]v_{i}[/tex] = 172 km/h × 1 hr/3600 s × 1000m/1km

[tex]v_{i}[/tex] = 48.1 m/s

By using kinematics

[tex]v^{2} f[/tex] = [tex]v^{2} i[/tex] + 2ad

[tex]0^{2}[/tex] = 48.[tex]1^{2}[/tex] + 2a(0.66)

-1.32a = 2309

a= -1749 m/[tex]s^{2}[/tex]

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Since impulse is defined as a change in momentum, we may conclude that since all autos are based on magnitude, their initial momentum and ultimate momentum are the same. Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5

Magnitude is a term used in physics to describe an object's maximal size and direction. Magnitude is a factor that is shared by both scalar and vector quantities. We are aware that by definition, scalar quantities are those with only magnitude. It displays an object's size, direction, or motion in absolute or relative terms. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

One is roughly 10 times greater than the other if two integers are separated by one order of magnitude. They differ by a factor of around 100 if they are separated by two orders of magnitude. The greater value is less than 10 times the smaller value when two numbers are of the same order of magnitude.

Automobile-1 Mass= 2000kg = 5m/s

Automobile-2 Mass= 1000kg = 10m/s

Automobile-3 Mass= 500kg = 20m/s

Automobile-4 Mass= 4000kg = 5m/s

Automobile-5 Mass= 500kg = 10m/s

Automobile-6 Mass= 1000kg = 20m/s

Since we now understand that each car's momentum is the result of its mass and velocity, we will have

Automobile-1

P₁ = m × v

P₁ = (2000)(5)

P₁ = 2 × 10⁴kgm/s

Automobile-2

P₂ = m × v

P₂ = (1000)(10)

P₂ = 10⁴kgm/s

Automobile-3

P₃ = m × v

P₃ = (500)(20)

P₃ = 10⁴kgm/s

Automobile-4

P₄ = m × v

P₄ = (4000)(5)

P₄ = 2 × 10⁵kgm/s

Automobile-5

P₅ = m × v

P₅ = (500)(10)

P₅ = 10³kgm/s

Automobile-6

P₆ = m × v

P₆ = (1000)(20)

P₆ = 2 × 10⁵kgm/s

Then the momentum is:

Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5

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Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation.

Part A. The midway magnitude of the electric field is 17.2 * 10³ N/C.

Part B. The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.

The intensity of an Electric Field

Given this, the wire length is 9.50 cm and the charge density is 125 nC/m.

Part A

The electric field at the wires halfway is

E = q/4πε * 1/ (z(z²/a²+1)¹/²)

Where E is the intensity of the electric field, 8.85*10⁻¹² is the permittivity, z is 5.5 cm, a is the midpoint, 9.5/2 cm, and q is the charge density.

Substituting the value in the above equation

E = 17.2 * 10³N/C

The midway magnitude of the electric field is 17.2 * 10³ N/C

Part B

When the wire is a circle then, the charge density at the wire is

Q = q*l

Q= 1.235 * 10⁻⁸ * 0.095

Q = 1.235*10⁻⁸ C

And to calculate the radius

r = l/2π

r = 9.50/ 2*3.14

r = 1.512cm

r = 0.015m

The electric field density at the midpoint of the circle is,

E = Q/4π * z(z²+r²)¹/² * E

Substituting the values in the above equation, we get

E = 47.17 * 10³ N/C

The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.

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Answer: 3.81 m/s^2.

Explanation: use the equation for acceleration, which is a = (F - f)/m. In this case, we are given the force applied by Marvin (F), the force of friction (f), and the mass of the dresser (m). Plugging in the given values, we get a = (90 N - 24 N)/(52.8 kg) = 3.81 m/s^2.

VL (peak) = VL × √2= 2.335 angle (90) volts is the rms current in the circuit.

Rms current is Root-Mean-Square of instantaneous current values. The RMS value of alternating current is given by direct current which flows through a resistance

At resonance the capacitive and inductive reactance are such that they cancel each other and the circuit is entirely resistive at that point

so,

At resonance the current is given as

I(rms) = Erms/R = 125 /740 = 0.169 A= 1.6 × 10^-1 A

Now for series RLC circuit the resonant frequency is given as

w= 2πf=1/• LC = 1/√41× 10^-3* 0.44××10^-3

f= 37.94 Hz

The inductive reactance at resonant frequency is given as

xL= jwL = j 2πf×L = j×2×π×37.94×41×10^-3 = j9. 77 ohm= 9.77 angle (90)

as 9.77 angle (90) = 9.77 cos 90+ j9. 77 sin (90) = 0+ j9.77

So the voltage across the inductor is given as

VL= I×XL

=0.16 × 9.77 angle (90) = 1.65 angle (90)

Note this is the rns value for the peak value the voltage is to be multiplied by √2

VL (peak) = VL ×√2= 2.335 angle (90) volts

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The wavelength of light emitted from the tube as atom returns to the ground state is 1.02×[tex]10^{-7[/tex]m.

The spectrum of the electromagnetic radiation emitted or absorbed by an electron during transitions between different energy levels within an atom. When an electron gets excited from one energy level to another, it either emits or absorbs light of a specific wavelength.

The wavelength can be determined by either energy or by frequency.

in the question energy of an atom is given, so we will use wavelength energy formula.

λ=hc/E =6.626×10⁻³⁴J⋅s×2.998×10⁸m⋅s⁻¹/12.08 ×1.6×[tex]10^{-19[/tex]

= 19.864×[tex]10^{-7[/tex]/19.328

= 1.02 ×[tex]10^{-7[/tex] m

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The accelaration of the edge of the rotor is linear acceleration.

Accelaration is the rate of the change of the velocity of an object with respect by time.

The electric motor is  spinning at a rate of 2695 Devolution Permanent. By two by over 60 is how this can be converted into reading persecond. The value is coming out at 282.08 ingredient per second. The areas of the model is 7.605 cm. The linear acceleration of the by  motor is what we have to l find. We have to find out of  the tangential acceleration that is given by the formula and omega squared R, if I substitute the values. This will be to 82.08 The  motor has a linear Acceleration.

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Dark matter was first detected because the excess for the amount of gravity that could be present due to the luminous mass.

Since, by measuring the rotation of the galaxies and their gravitational attraction, the scientists determined that there appeared to be an excess of gravity, which could not be explained by the amount of luminous mass present. This led to the conclusion that dark matter must exist to explain this excess gravity.

Dark matter plays a fundamental role in the formation and evolution of galaxies. This invisible matter is composed of subatomic particles that interact with gravity, but does not emit light, so it cannot be detected directly. Despite this invisibility, advances in technology have allowed scientists to determine the amount of dark matter present in the Universe and its contribution to the evolution of galaxies.

Studies of galaxies suggest that dark matter plays an important role in their formation, this means that dark matter is responsible for the formation of galactic structures, such as disks and the central bar.

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The angle measure of angle B = 25° and angle C = 65° and angle D = 25°.

The given parameters are;

The orientation of the two mirrors = At right angle to each other

The laser light is directed at one of the mirror

The measure of angle, A = 25°

The measures of angle B, C, and D are found as follows;

We have;

∠A = ∠B = 25°, by angle of incidence equals angle of reflection

∠B = 25°

∠B + ∠C = 90° by sum of the acute angles of a right triangle

25° + ∠C = 90°

∴ ∠C = 90° - 25° = 65°

∠C = 65°

∠E = ∠C = 65° by angle of incidence equals angle of reflection

∴ ∠E = 65°

Line 'L' is perpendicular to the second mirror, therefore, the angle between line 'L' and the second mirror = 90° = ∠E + ∠D

∠E + ∠D = 90°,  by angle sum property

Therefore;

65° + ∠D = 90°

∴ ∠D = 90° - 65° = 25°

∠D = 25°

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A planet has a different meaning than the astronomical understanding of what a planet is. Before the advent of telescopes, the night sky was thought to consist of two very similar components. Fixed stars, which are stationary relative to each other, and moving objects ("wandering stars").

What are planets?

Planets are large, round objects that are neither stars nor remnants. The best theory of planet formation available is the nebular hypothesis, which postulates that interstellar clouds collapse from the nebula, creating young protostars orbiting the protoplanetary disk. Planets grow within this disk by the gradual accumulation of matter by gravity, a process called accretion. The solar system has at least eight planets: the terrestrial planets Mercury, Venus, Earth, and Mars, and the giant planets Jupiter, Saturn, Uranus, and Neptune. Each of these planets rotates around an axis that is tilted with respect to the poles of its orbit. All of them have atmospheres, but Mercury's is faint, and some share features such as ice caps, seasons, volcanism, hurricanes, tectonics, and even hydrology. Except, the planets in our solar system generate magnetic fields, and all planets except Venus and Mercury have natural satellites. Giant planets have planetary rings, most notably Saturn's rings.

Some cultures equate celestial bodies with gods, and these connections to mythology and folklore exist in naming schemes for newly discovered celestial bodies in the solar system. When the heliocentric theory superseded the heliocentric theory in the 16th century and his 17th century, the earth itself was recognized as a planet.

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The acceleration of the crate is 0 m/s2.

This is because the force applied is equal to the force of friction between the crate and the floor, so the crate is not accelerating. The force of friction is equal to the force applied, and since no acceleration is occurring, the force must be equal to the mass of the crate multiplied by the acceleration of gravity (9.81 m/s2).

This means that the force applied (1 N) is equal to the mass of the crate (27 kg) multiplied by the acceleration of gravity (9.81 m/s2). Therefore, the acceleration of the crate is 0 m/s2.

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it is 20 4×5 trust me i did this for like 30 min