The distance above the ground the rock should be raised in order to hits the ground double of initial time is 4h.
The given parameters;
initial velocity of the rock, u = 0height above the ground, = htime of motion of the rock from the height = t₀The time of motion of the rock from the given height is calculated as;
[tex]h = ut + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt_0^2\\\\h = \frac{1}{2} gt_0^2\\\\t_0^2 = \frac{2h}{g} \\\\t_0 = \sqrt{\frac{2h}{g} }[/tex]
When the time of motion is doubled to 2t₀, the height above the ground should be;
[tex]2(t_0) = 2(\sqrt{\frac{2h}{g} } )\\\\2(t_0) = \sqrt{\frac{4\times 2h}{g} }[/tex]
Thus, the distance above the ground the rock should be raised in order to hits the ground double of initial time is 4h.
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Help me pls I need to turn this in quick!!!!
Answer:
C. When the waves overlap, they will cancel eanch other out and disappear
Explanation:
hope its help heart brainliest thnks
A light, inextensible cord passes over a light,
frictionless pulley
with a radius of 7.2 cm
It has a(n) 16 kg mass on the left and a(n)
6.7 kg mass on the right, both hanging freely.
Initially their center of masses are a vertical
distance 4.2 m apart.
The acceleration of gravity is 9.8 m/s^2
The question tied to it is…
What is the tension
in the cord when they
pass each other?
Answer in units of N.
Answer: T = 93 N
Explanation:
Assuming the pulley is ideal meaning frictionless as mentioned and also negligible mass.
ΣF = Σma
Mg - mg = Ma + ma
a = g(M - m) / (M + m)
Now looking only at the larger mass as it falls
Mg - T = Ma
T = Mg - Ma
T = Mg - Mg(M - m) / (M + m)
T = Mg(1 -(M - m) / (M + m))
T = 16(9.8)(1 - (16 - 6.7) / (16 + 6.7))
T = 93 N
or looking only at the smaller mass
T - mg = ma
T = m(g + a)
T = m(g + g(M - m) / (M + m))
T = mg(1 + (M - m) / (M + m))
T = 6.7(9.8)(1 + (16 - 6.7) / (16 + 6.7))
T = 93 N
The depth of a pond is 1.5m. Calculate the pressure caused by the water at the bottom of the pond.
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}[/tex]
[tex]\\ \sf\longmapsto Pressure=4.4Pa[/tex]
Answer:
Area=1.5(1.5)=2.25m^2
Force of gravity=10N
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}
⟼Pressure=
Area
Force
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}
⟼Pressure=
2.25
10
\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}
⟼Pressure=4.4Pa
How did kepler develop his second law of motion ?
A. He invented a telescope that was strong enough to view all plants of the solar system along their orbits
B. He compared data of planetary motion at different times along orbits
C. He made accurate measurements of the positions of all the planets over many years
D. He used a telescope to carefully follow and time the orbital motion of mars
He developed his second law of motion by using a telescope to carefully follow and time the orbital motion of mars .
What is a Telescope?This is a device which is used to form magnified images of distant objects. Kepler used it to observe the orbit motion of mars.
He discovered that planets do not move with constant speed along their orbits which led to his second law of motion.
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u= (-5,3) find the magnitude of u. please help me
u = 5.83
Explanation:
The magnitude of a vector [tex]\vec{u}[/tex] is
[tex]|\vec{u}| = \sqrt{u_z^2 + u_y^2} = \sqrt{(-5)^2 + (3)^2}[/tex]
[tex]\:\:\:\:\:\:\:= \sqrt{34} = 5.83[/tex]
There are 100000 billion billion ......systems
DUE IN 3 HOURS! PLEASE HELP AND SOLVE A-E.
For a projectile with initial velocity of 51.5 m/s and angle of elevation equal to 4 degrees.
a) Compute the horizontal velocity of the projectile in m/s.
b) Compute the vertical velocity in m/s.
c) Compute the time of flight for the projectile.
d) Compute the distance downrange.
e) Compute the maximum height reached by the projectile.
Answer:
Below
Explanation:
c) To find the time of flight of a projectile (assuming from the given information that there is no vertical displacement) you can use this formula :
t = 2(Vi) Sinx / g
t = 2(51.5m/s) Sin(4) / 9.8 m/s^2
t = 0.733 seconds
t = 0.73 seconds
d) To find the displacement in the x-direction you can use this formula :
dx = vi^2 sin(2x) / g
dx = (51.5m/s)^2 sin(2(4)) / 9.8m/s^2
dx = 37.6654 m
dx = 37.7 meters
e) To find the peak height of the projectile you can use this formula :
v^2sin^2(x) = 2gh
(51.5m/s)^2sin^2(4) = 2(9.8m/s^2)h
h = 0.658 meters
h = 0.66 meters
Hope this helps! Best of luck <3
Where does the energy of a breaking wave originate?
Answer:
Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest.
Explanation:
Figure 10.20 in your textbook shows an energy diagram for a system with total energy E1. Suppose the system's total energy is E2 = (1/3)E1. In what ways could the particle move?
Select all that apply.
a.) It could remain at rest at x3.
b.) It could oscillate between x1 and x5.
c.) It could undergo small oscillations around x2.
d.) It could undergo small oscillations around x3.
e.) It could undergo small oscillations around x4.
Please explain why, I have an exam coming up and want to understand the concept.
The particles can undergo small oscillations around x₂.
The given parameters;
initial energy of the particles = E₁final energy of the particles, E₂ = 0.33E₁The movement of the particles depends on the kinetic energy of the particles.
When kinetic energy of the particles is 100%, the particles can oscillate from x₁ to x₅.
However, when the total energy of this particles is reduced to one-third (¹/₃) or 33% of the initial energy of the particle, the oscillation of the particles will be reduced.
The maximum position the particle can oscillate is x₅The half position the particles can oscillate is x₃Since 33% is less than the half of the energy of the particle, the particle will oscillate between x₁ and x₂.
Thus, we can conclude that the particles can undergo small oscillations around x₂.
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what greenhouse gasses do for the atmosphere
Answer:
Explanation:
Earth's atmosphere contains greenhouse gases that trap heat. While they allow sunlight to pass through the atmosphere, they also prevent the heat it brings from leaving it.
celera
An
A force F = 89.2 N acts at an angle a = 38°
with respect to the horizontal on a block of
mass m = 26.8 kg, which is at rest on a
horizontal plane.
The acceleration of gravity is 9.81 m/s2.
If the static frictional coefficient is pls
0.74, what is the force of static friction?
=
Hi there!
We know that the MAXIMUM static friction force to be overcome is:
Fs (Force of Static Friction) = μN (Normal Force)
The normal force is equal to the weight of the block AND the vertical component of the applied force, so:
N = Mg + Fasinθ
Plug in the given values:
N = 26.8(9.81) + (89.2)sin(38) = 317.825 N
Multiply by the force of static friction to derive the static force:
0.74 * 317.825 = 325.191 N <-- MAXIMUM STATIC FRICTION FORCE
The force applied, if not greater than this value, will result in an EQUAL and OPPOSITE static frictional force. Thus:
Fs = Horizontal component of the applied force
Fs = 89.2cos(38) = 70.291 N
1. What is meant by the phrase, "a sound mind and a sound
body'?
Answer:
A sound mind in a sound body implies that you're capable of positive thinking for a better quality of life and physical functioning. When you exercise, your body releases endorphins, a chemical that triggers a positive response in the body. This shows that the more you sweat, the better you feel about yourself.
Explanation:
A toy car is released from rest at the top of a ramp. The car
speeds up as it moves down the ramp. When it reaches the
bottom of the ramp, the toy car rolls across the floor and
eventually stops.
Which two statements identify evidence that energy was conserved?
A. As the car rolls down the ramp, it speeds up because gravitational
potential energy is transformed into kinetic energy.
B. As the car rolls down the ramp, it speeds up because thermal
energy due to friction is transformed into kinetic energy.
m C. As the car rolls across the floor, it stops because its kinetic
energy is transformed into gravitational potential energy,
1 D. As the car rolls across the floor, it stops because its kinetic energy
is transformed into thermal energy due to friction
Answer:
A and DDD
Explanation:
The two statements identify evidence that energy was conserved are, as the car rolls down the ramp, it speeds up because gravitational
potential energy is transformed into kinetic energy and as the car rolls across the floor, it stops because its kinetic energy is transformed into thermal energy due to friction, therefore the correct answer is option C.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
As given in the problem statement a toy car is released from rest at the top of a ramp. The car speeds up as it moves down the ramp. When it reaches the bottom of the ramp, the toy car rolls across the floor and
eventually stops.
Thus, it speeds up because gravitational potential energy is transformed into kinetic energy and as the car rolls across the floor, it stops because its kinetic energy is transformed into thermal energy due to friction, therefore the correct answer is option C.
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#SPJ5
feminine of mouse
please let me know
Answer:
a Doe
A baby mouse is called a 'pinky', a male is called a 'buck' and a female is called a 'doe'.
(hope that helped)
An elevator cable winds on a drum of radius 771 cm that is connected to a motor.
If the elevator moves down 8.60 m, how many revolutions has the drum made?
The relationship between the length of the circle and its radius allows to find the result for the revolutions turned when the distance decreases 8.60m is:
Angle = 17.8 rev
The length of a circle is given by the expression.
L = 2π r
Where L is the length of the circle and r is the radius of the circle.
They indicate the radius of the drum is r = 7.71 cm = 7.71 10⁻² m, let's find the length of the circle.
Lo = 2 π 7.71 10⁻²
Lo = 0.4844 m
Let's find the angle that the drum has rotated, using a direct proportional rule. If rotate an angle of 2π radians when you descend 0.4844 m, what angle you rotate when you descend 8.60 m.
#_ angles = [tex]8.6 m \ \frac{2\pi \ rev} { 0.4844 m}[/tex]
#_angle = 111.55 radians
Let's reduce to revolutions.
# _angles = 111.55 radians ( [tex]\frac{1 rev }{2\pi rad}[/tex] )
#_angulo = 17.8 rev
In conclusion, using the relationship between the length of the circle and its radius, we can find the result for the revolutions turned when the distance decreases is:
Angle = 17.8 rev
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Which model represents a lot of conservation of mass?
Answer:
Only option 2 has the same number of oxygen and hydrogen atoms on each side of the arrow.
Explanation:
A parkour runner is running on top of a building when he comes to the edge; the next building is 5
meters down and 8 meters over. How fast does he need to be running to make the jump?
Answer:
Explanation:
If we make a rather silly assumption that the runner does not leap upward somewhat as he leaves the edge of the first building, his initial vertical velocity is zero.
The time needed to drop 5 meters from vertical rest is
t = √(2s/g) = √(2(5)/9.8) = 1.01 s
so he needs a horizontal speed of at least
v = d/t = 8 / 1.01 = 7.91959...
v = 7.9 m/s. Better make it 8 m/s to be sure he clears the edge and lands on the roof.
a squirrel is 5.0 m away from you while moving at a constant velocity of 3 m\s away from you, how far is the squirrel after 5 seconds?
Answer: distance travel after 5 seconds = 3×5 =15 m
so squirrel is away from me by distance of 15+ 5 = 20 m
Explanation:
Answer:
I believe 20 is the answer
I’m stuck
Why do I have to run
Answer: Because
Running can significantly improve physical and mental health. As a form of aerobic exercise, running can reduce stress, improve heart health, and even help alleviate symptoms of depression. Some researchers think running may be so good for us because it's something we evolved to do. lol
Explanation:
A 77 kg girl and a 62 kg boy face each other on friction free roller skates. The girl pushes the boy, who moves away at a speed of 2.5 m/s. What is the girl's speed?
Answer:
Explanation:
conservation of momentum
Initial momentum is zero
77v + 62(2.5) = 0
77v = -155
v = -155/77 = -2.0129870...
|v| = 2.0 m/s
An ideal gas occupies a volume of 1cm^ atv20°c and atmospheric pressure determine the number of molecules of gas in the container
Answer:
By Charles Law the volume of 1 cm^3 at standard conditions is
V = V0 * 273 / 293 = 1 cm^3 * .932 cm^3
Reducing the temperature to 0 deg C results in a volume of .932 cm^3
1 mole of gas contains 22.4 L of gas
1 L = 1000 cm^3
1000 cm^3 / L / (.932 cm^3 / container) = 1073 containers / L
So 1 mole of gas = 1073 containers * 22.4 L /container = 24,305 L
6.02E23 molecules / mole * 1 / 24305 molecules / mole = 2.48E19
number of molecules present = 2.48 * 10^19
(Easier to calculate volume of 1 cc
1 cc = 6.02E23 / (1000 * 22.4) = 2.69E19 molecules in 1 cc
Vol of 1cc = 273 / 293 = .932
2.69E19 * .932 = 2.51 * 10^19)
Which of the following has the greatest momentum? (Hint: momentum = mass x velocity)
a. a 4.0 kg bowling ball moving at 2.0 m/s
b. a 0.15 kg baseball moving at 10.0 m/s
c. a 1.6 x 10^3 kg car moving at 0.5 m/s
d. a 2 kg bullet moving at 950 m/s
Answer:
therefore, the correct answer is Option D.
Explanation:
a. 4×2=8kgm/s
b. 0.15×10=1.5kgm/s
c. 1.6×10³×0.5=800kgm/s
d. 2×950=1900kgm/s.
hope this helps you
An elevator cable winds on a drum of radius 77.1 cm that is connected to a motor.
If the elevator moves down 8.60 m, how many revolutions has the drum made?
Place the yellow, 25g ball at 60 cm on the ramp. How far did the box move? Measure from the left side of the box.
Answer: approximately 13-15 centimeters
SI unit pf pressure is?
The SI unit for pressure is the pascal (Pa), equal to one newton per square metre (N/m2, or kg·m−1·s−2).
A car accelerates from 10m/s to 50m/s over a distance of som. What is the
acceleration of the car?
Answer:
40m/s
Explanation:
50m/s - 10m/s = 40m/s
Một ròng rọc có dạng khối lượng 3kg, bán kính 20cm, người ta treo hai quả nặng có khối lượng m1= 2kg và m2 = 5kg vào hai đầu một sợi dây vắt qua một ròng rọc có trục quay cố định nằm ngang, sợi dây không dãn và không trượt trên ròng rọc. Lấy gia tốc trọng trường g = 10m/s2g. Gia tốc của các vật là bao nhiêu?.
Answer:Một ròng rọc có dạng khối lượng 3kg, bán kính 20cm, người ta treo hai quả nặng có khối lượng m1= 2kg và m2 = 5kg vào hai đầu một sợi dây vắt qua một ròng rọc có trục quay cố định nằm ngang, sợi dây không dãn và không trượt trên ròng rọc. Lấy gia tốc trọng trường g = 10m/s2g. Gia tốc của các vật là bao nhiêu
Explanation:
1. production of a ____often caused by fizzing and_____
2.Produces an____
Change in____ or_____ (heat, light, sound)
A jet plane flying 600 m/s experiences an acceleration of 39.24 m/s² when pulling out of the circular section of a dive. What is the radius of curvature of this section of the dive?
The options are:
1.2 km
5.8 km
0.64 km
9.2 km
7.0 km
Answer:
Explanation:
If we are to assume that the plane is at the bottom of a circular movement and just about to depart in level flight, then
(39.34 - 9.81) = 600²/R
R = 12,190.992211... m
Which is very close to the 1.2 km option
A shopper is pushing a cart down a grocery store aisle. Starting from rest, the shopper applies a constant force to the cart for 4.0 s. From t = 4s until t = 4 s until t = 8 s, the shopper applies just enough force to balance the friction on the cart. Finally, the shopper applies a constant force to slow the cart until it comes to rest att = 12 s. The resulting position-time graph is shown below. What is the average acceleration of the shopping cart during its 12s motion?
A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².
A shopper is pushing a cart down a grocery store aisle. The movement of the cart is:
It starts from rest.From t = 0 s to t = 4.0 s it is accelerated with a constant force.From t = 4 s to t = 8.0 s it receives just enough force to balance the friction on the cart.From t = 8 s to t = 12 s it is decelerated until it comes to rest.All in all, at the initial time (t = 0 s), the velocity is 0 m/s (rest) and at the final time (t = 12 s) the velocity is 0 m/s as well (rest). The average acceleration in that period is:
[tex]a = \frac{v_{12}-v__o}{t_{12}-t_0} = \frac{0m/m-0m/s}{12s-0s} = 0 m/s^{2}[/tex]
A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².
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Answer:0 m/s2
Explanation: Cus i said so.