A stationary 10 kg object is located on a table near the surface of the earth. The coefficient of kinetic friction between the surfaces is 0.2. A horizontal force of 40 N is applied to the object.

The NGC 3603 region of space is shown below. It is a cloud of gas and dust. Stars are forming in this cloud. The NGC 3603 be classified as a nebula. The correct option is A.

A tiny, ball-shaped nebula is known as a planetary nebula. It generates an ionized gas that is luminous. Large and typically erratic clouds are produced by diffuse nebulae.

Due to their big stars, they typically form a cluster of stars. a cloud of gas in space that can be seen in the night sky as a vaguely discernible brilliant patch, as something black, or as a shadow against other luminous objects.

Dust and gases, primarily hydrogen and helium, make up nebulae. The mass of gas and dust eventually grows so large that it is forced to collapse by gravity. The material in the cloud's core heats up as a result of the collapse, and this hot core is the start of a star.

Therefore, the correct option is A. As a nebula.

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Answer: Calculate GPE for different gravity of different enviornments - Earth, the Moon, ... kg, g, lb, oz ... variable in the physics equation for gravitational potential energy, when three of ... PEg or PE = gravitational potential energy; m = mass of an object ... have 147.15 Joules of potential energy, PE = 3kg * 9.81 m/s2 * 5m = 147.15 J.

Answer:

C- 96 m

Explanation:

d= st

d= 8 m/s x 12 seconds

d= 96 metres

Answer:

1 half kilometer is right answer

Answer:

Infinity

Explanation:

When you have a limit approaching infinity one method you can use is to remember that the highest power dominants all of the other ones so when we have (t^2)/t-1 like in your problem, we see that t^2 has the highest power of 2 so if that's going to infinity and it's not being divided by any powers higher than it will just be inifinity.

We have that for the Question, it can be said that  in the limit calculations below, if you need to use -â or â, enter -infinity or infinity. the limit is

From the question we are told

tafu models its position with the function

p(t)= t2 t â 1 where t>1.

in the limit calculations below, if you need to use -â or â, enter -infinity or infinity.

(a) calculate the limit

Generally the equation for the Question  is mathematically given as

[tex]p(t)=\frac{t^2}{t-1}\\\\Therefore\\\\For Lim_{\infty}\\\\We have\\\\ Lim_{t->\infty} p(t)= Lim_{t->\infty}\frac{t^2}{t-1}\\\\[/tex]

Since, the equivalent degree of numerator (t^2) is greater than that of the denominator

[tex]Lim_{t->\infty} p(t)= \infty[/tex]

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Answer: 110000

Explanation:

26/9=30.5555555556

30.5555555556 x 60=1833.33333333

110000 x 60=110000

The   AMPLITUDE  of a wave is the maximum distance that the particles in a medium move from their rest position as the wave passes.

Answer:

I Choose C, Because Genetically engineered bacteria and other microorganisms are currently used to produce human insulin, human growth hormone, a protein used in blood clotting, and other pharmaceuticals and the number of such compounds could increase in the future.

So Basically There Saying It Can Be Used To Remove Certain Diseases.

Answer:

d

Explanation:

Answer:

D. Solar panels remove most of the toxic chemicals found in the atmosphere.

People do not believe it is possible to use the sun's energy to create electricity.

Explanation:

I did the test.

Answer:

D

Explanation:

The density has a formula of d = m / V.

The volumes are given as the same.

The density will be

d_lead = 113/ V

d_aluminum = 27/V

It does not matter for this question what the volume actually is. Just note that the value of the volume is the same for each ball.

A: incorrect. If the volumes are the same, the density is not the same because the masses are different.

B: incorrect. If the density of the two balls was less than water, the two balls would float. Never going to happen unless the balls are thin shells.

C: incorrect. The exact opposite is the answer.

D: Correct. This is the answer.

Answer:

It's d

Explanation:

Answer: D

Explanation:

Force of gravity

Answer:

14 m/s

Explanation:

KE=1/2mv^2

5880J= 1/2(60kg)v^2

5880J=(30)(V^2)

5880/30=V^2

196=v^2

square root of 196 is 14

Answer:

168m/s

Explanation:

Given parameters:

Frequency  = 28Hz

Wavelength  = 6m

Unknown:

Speed of the the wave travel  = ?

Solution:

To solve this problem, we us the wave - velocity equation:

    Velocity  = Frequency x Wavelength

 Velocity  = 28 x  6  = 168m/s

[tex] \sf• \: Power \:( P) = 300 \: watts[/tex]

[tex] \sf• \: Current \: (I) = 30 \: amps[/tex]

[tex] \\ [/tex]

[tex] \sf• \: The \: Resistance [/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{Solution :-:- }}[/tex]

[tex] \bf \red {\bigstar{ Formula \: of \: Power \: (P) = \frac{ {I}^{2} }{R}}}[/tex]

[tex] \sf \rightarrow 300= \frac{ {30}^{2} }{ R} [/tex]

[tex] \sf \rightarrow 300 = \frac{900}{ R} [/tex]

[tex] \rightarrow \sf R = \frac{300}{900} [/tex]

[tex] \rightarrow \sf R = \frac{1}{3} [/tex]

[tex] \rightarrow \sf R = 0.33[/tex]

[tex] \bf \purple{Hence, \: the \: resistance \: is \: 0.33 \: Ω \: . }[/tex]

Answer:

11.2Watts

Explanation:

Given parameters:

Energy produced by the engine  = 670J

Time taken  = 1min  = 60s

Unknown:

Number of watts it can output  = ?

Solution:

This problem entails finding the power of the engine.

Power is the rate at which work is being done.

So;

      Power  = [tex]\frac{Work done }{time}[/tex]  

       Power  = [tex]\frac{670}{60}[/tex]    = 11.2Watts

Explanation:  

In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. Common types of potential energy include the gravitational potential energy of an object that depends on its mass and its distance from the center of mass of another object, the elastic potential energy of an extended spring, and the electric potential energy of an electric charge in an electric field. The battery is storing the energy but give it something to power and it'll give its energy to the object and a violin strings are like ruber band and if you play the violin it releases a new type of energy sound energy.

Answer:

e

Explanation:

Answer:

rotates, axis,not sure,day, not sure, night, revolves, not sure, hemisphere, towards, summer, away, winter

Explanation:

Answer:

350J

Explanation:

Given parameters:

Weight of bag  = 20N

Distance moved horizontally  = 35m

Force applied  = 10N

Unknown:

Work done on the bag  = ?

Solution:

Work done is the force applied to move a body through given distance.

  Work done  = Force applied x distance

So;

 Work done  = 10 x 35  = 350J

Answer:

v = 3.08 km/s

Explanation:

Given that,

The angular velocity of the satellite = [tex]\omega=7.27\times 10^{-5} rad/s[/tex]

A satellite is in orbit 36000km above the surface of the earth.

The radius of the earth is 6400 km

Let v is the velocity of the satellite. It can be calculated as :

[tex]v=r\omega\\\\v=(36000\times 10^3+6400\times 10^3)\times 7.27\times 10^{-5}\\\\v=3082.48\ m/s\\\\v=3.08\ km/s[/tex]

So, the velocity of the satellite is 3.08 km/s.

Answer:

The core of the sun is the region that extends from the center to about 20–25% of the solar radius. It is here, in the core, where energy is produced by hydrogen atoms (H) being converted into nuclei of helium (He). ... The core is the only part of the sun that produces an appreciable amount of heat through fusion.

Explanation:

I got you

By not running out of fuel (Hydrogen).

Rest assured ... When the sun runs low on Hydrogen, it'll go through several complex changes, and it'll end up at much much lower temperature, with much much lower energy output.

Answer:

v = 27.5 m/s

Explanation:

p = m × v

6,875 = 250 × v

250v = 6,875

v = 6,875/250

v = 27.5 m/s

Answer the term solenoid refers to a long, thin loop of wire, often wrapped around a metallic core, which produces a magnetic field when an electric current is passed through it. Solenoids are important because they can create controlled magnetic fields and can be used as electromagnets

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