Answer:
their is always a animal or bug in nature
Explanation:
Organized procedure to study something under controlled conditions
Since Allura Red is red in color, why did we choose to use monitor the wavelength of 470 nm? does allura red transmit or absorb red light ?
Answer:
Wavelenght of light in the range of 470nm is that of blue colourand Allura red absorbs this blue light and reflects the red light
Then we can say Allura red absorbs all light colours but reflect red
Allura is red due to the fact that it absorbs the light that's in the wavelength.
From the complete information, it should be noted that even though allura red is red in color, we choose to use monitor the wavelength of 470nm because absorbs the light that's in the wavelength range of blue color and thereby reflects the red wavelength.
It should also be noted that the allura red absorbs all the other wavelengths. It doesn't absorb the red light but rather it reflects it.
In conclusion, the red light will be reflected.
Read related link on:
https://brainly.com/question/14524069
A car has an initial velocity of 50 m/s and a constant
acceleration of 5 m/s2. What is the car's velocity after 3
seconds?
A wire 6.60 m long with diameter of 2.05 mm has a resistance of 0.0310 Ω.
Find the resistivity of the material of the wire.
rho= Ω*m
Answer:
1.551×10^-8 Ωm
Explanation:
Resistivity of a material is expressed as shown;.
Resistivity = RA/l
R is the resistance of the material
A is the cross sectional area
l is the length of the wire.
Given;
R = 0.0310 Ω
A = πd²/4
A = π(2.05×10^-3)²/4
A = 0.000013204255/4
A = 0.00000330106375
A = 3.30×10^-6m
l = 6.60m
Substituting this values into the formula for calculating resistivity.
rho = 0.0310× 3.30×10^-6/6.60
rho = 1.023×10^-7/6.60
rho = 1.551×10^-8 Ωm
Hence the resistivity of the material is 1.551×10^-8 Ωm
(1.736+9.6435)÷3.22=
The answer is 3.53400621
Reduce the expression, if possible, by cancelling common factors.
Answer: 3.53400621
Explanation: Hope this helped! :)
A cheetah accelerates from rest at a rate of 9 m/s^2 for 3s. How far does it travel in this time? Assume the cheetah moves in a
straight line.
a) 27.0 m
b) 40.5 m
c) 13.5 m
d) 54.0 m
Answer:
b) 40.5 m
Explanation:
Given:
v₀ = 0 m/s
a = 9 m/s²
t = 3 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (3 s) + ½ (9 m/s²) (3 s)²
Δx = 40.5 m
what is surface tension
Answer:
Surface tension is the tendency of liquid surfaces to shrink into the minimum surface area possible. Surface tension allows insects, usually denser than water, to float and slide on a water surface.
how many legs a cow has
A squirrel is running a race where she is on track for her average velocity to be 6.0 m/s. She is distracted by a dummy of an attractive male squirrel and pauses for 3.0 s. As a result her average velocity ends up being 5.0 m/s instead. What is the length of the race? [HINT: construct two equations with the same two unknowns in them and you can solve the system of equations]
Answer:
90 m
Explanation:
There are two unknowns: the amount of time the squirrel spent running, and the length of the race. Let's call these t and x, respectively.
The average velocity is the total distance divided by the total time.
5.0 m/s = x / (t + 3.0)
The total distance is the time she spent running times the speed she ran at.
x = (6.0 m/s) t
Substitute and solve:
5 = 6t / (t + 3)
5 (t + 3) = 6t
5t + 15 = 6t
t = 15
She ran for 15 seconds (not including the 3 seconds she stopped). So the length of the race is:
x = (6.0 m/s) (15 s)
x = 90 m
A car slowed down from 70 mils to 30 mi/s on the highway in 20
seconds. What was the car's acceleration?
A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 41 km/h at the 61-m mark. He then maintains this speed for the next 83 meters before uniformly slowing to a final speed of 34 km/h at the finish line. Determine the maximum horizontal acceleration which the sprinter experiences during the run. Where does this maximum acceleration value occur
Answer:
2.13 m/s^2.
Find the remaining answer in the explanation
Explanation:
Given that a sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 41 km/h at the 61-m mark. He then maintains this speed for the next 83 meters before uniformly slowing to a final speed of 34 km/h at the finish line.
1.) The maximum horizontal acceleration will be when she attained her maximum speed. That is,
Speed = 41 km/h
Convert km/h to m/s
(41×1000) / 3600
Speed = 11.39 m/s
Using speed formula to calculate time
Speed = distance/time
11.39 = 61/t
t = 61/11.39
t = 5.36s
Where the distance = 61 m
Maximum acceleration = velocity /time
Maximum acceleration = 11.39/5.36
Maximum acceleration = 2.13 m/s^2
The maximum acceleration value occurs when the sprinter is starting from rest and attaining the maximum speed.
Suppose you performed the experiment in atmosphere of Argon at 25 deg. C, (viscosity of argon is 2.26X10^-5 N.s/m^2 at that temperature), and measured terminal speed of 2.64X10^-5 m/s and weight-neutralizing voltage of 35.0 V. How many electrons have been attached to, or detached from the initially neutral plastic sphere
Following are the calculation to the given question:
Given:
Please find the given question.
To find:
value=?
Solution:
With terminal voltage, no force equals zero.
So,
[tex]\to mg = 6\times \pi \times \eta \times r\times \vartheta \\\\[/tex]
As [tex]35\ V[/tex] is weight neutralizing voltage
[tex]\to mg= q\times v \times r\\\\[/tex]
So,
[tex]\to q\times v \times r= 6 \times \pi \times \eta \times r \times \vartheta \\\\\to q\times v = 6 \times \pi \times \eta \times \vartheta \\\\\to q =\frac{6 \times \pi \times \eta \times \vartheta}{v} \\\\[/tex]
[tex]=\frac{6 \times 3.14 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 18.84 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\ =3.2 \times 10^{-10}\ coulombs[/tex]
Therefore
[tex]\to q= n \times e\\\\[/tex]
Hence n comes to be [tex]2\times 10^9\[/tex] electrons.
Learn more:
brainly.com/question/12816494
can anyone help me with this.
Answer:
A. smaller arteries
Explanation:
A. because it makes no sence.
You must exert a force of 5N on a book to slide it across a table. If you do 2.5 J of work in the process, how far has the book moved?
Answer:
0.5 m
Explanation:
The following data were obtained from the question:
Force (F) applied = 5 N
Work done (W) = 2.5 J
Distance (s) =?
Work done (W) can be defined as the product of force (F) and distance (s) moved in the direction of the force. From the above definition, work done (W) can be represented mathematically as:
Work done (W) = Force (F) × Distance (s)
W = F × s
With the above formula, we can obtain the distance moved by the book as shown below:
Force (F) applied = 5 N
Work done (W) = 2.5 J
Distance (s) =?
W = F × s
2.5 = 5 × s
Divide both side by 5
s = 2.5/5
s = 0.5 m
Therefore, the book moved a distance of 0.5 m.
What do we know has to be TRUE about the action and reaction force below?
the boot kecked the ball which is frictinal force
Two satellites orbit earth at altitudes of 7500 km and 15000 km above earth's surface. Which satellite is faster and by what factor?
Answer:
The satellite that is 7500 km above earth's surface is 1.24 times faster than the satellite at 15000 km above earth's surface
Explanation:
Generally the gravitational force acting on each satellite is mathematically represented as
[tex]F = \frac{G * M_e * m_2 }{r^2}[/tex]
Here [tex]M_e[/tex] is the mass of the earth
[tex]r = r_e + R [/tex]
So [tex] r_e [/tex] is the radius of the satellite and R is the radius of earth with value R = 6371 km
This force is also equivalent to the centripetal force acting on each satellite which is mathematically represented as
[tex]F = \frac{mv^2}{ r^2}[/tex]
So
[tex]\frac{mv^2}{ r^2} = \frac{G * m_1 * m_2 }{r^2}[/tex]
=> [tex]v = \sqrt{ \frac{GM_e}{r} }[/tex]
So for [tex]r = 7500+ 6371 = 13871 \ km [/tex]
We have that
[tex]v_1 = \sqrt{ \frac{GM_e}{13871} }[/tex]
and [tex]r = 15000+ 6371 = 21371 \ km [/tex]
We have that
[tex]v_2 = \sqrt{ \frac{GM_e}{21371} }[/tex]
So
[tex]\frac{v_1}{v_2} = \frac{\sqrt{\frac{GM_e}{13871} } }{ \sqrt{\frac{GM_e}{21371}} }[/tex][tex]v = \sqrt{ \frac{GM_e}{r} }[/tex]
=> [tex]\frac{v_1}{v_2} = \sqrt{ \frac{21371}{13871} }[/tex]
=> [tex]v_1 = 1.24 v_2[/tex]
So satellite that is 7500 km above earth's surface is 1.24 times faster than the satellite at 15000 km above earth's surface
How fast do you go if you move 80 meters in 0.20 seconds?
Answer: I HOPE IT HELPS
Use this Speed Calculator to calculate the speed you have travelled based ... (so add three 0s to your kilometres to get metres) and a mile is 1609 metres. ... You will have distance per time such as kilometres per hour or metres per second. ... If you want help with that, click on hyperlink for metres or for minutes and seconds.
Explanation:
An electronic line judge camera captures the impact of a 57.0-g tennis ball traveling at 32.2 m/s with the side line of a tennis court. The ball rebounds with a speed of 21.6 m/s and is seen to be in contact with the ground for 3.94 ms. What is the magnitude of the average acceleration of the ball during the time it is in contact with the ground
Answer:
average acceleration is 1.365 × [tex]10^{4}[/tex] m/s²
Explanation:
given data
initila speed u = -32.2 m/s
final speed v = 21.6 m/s
time taken t = 0.00394 s
solution
we get here average acceleration that will be express as
v = u + at ..........................1
put here value and we get
21.6 = -32.2 + a × 0.00394
solve it we get
a = 1.365 × [tex]10^{4}[/tex] m/s²
so average acceleration is 1.365 × [tex]10^{4}[/tex] m/s²
What contributions did Johannesburg Kepler make
Answer:
Multiple
Explanation:
He was the first to determine that refraction drives vision in the eye. Using two eyes enables depth perception. Kepler is also known for defining laws regarding planetary motion.
Which of the following is the best thermal conductor?
A. Fiberglass.
B. Stainless.
C. Steel.
D. Wood.
E. Silver
Answer:
steel because being alloy in metal it has free electrons in metals
What happens if we increase the value of the resistor in forward bias connection?
How many meters are in 5.0 cm?
500
0.050
0.0005
0.5
Explanation:
100cm=1m
5 cm= x
cross multiple
x=5/100
=0.05m
There are 0.05 meters in 5 cm. The correct option among the following is option (B).
In the metric system, a centimeter (cm) is a unit of length. It is one centimeter (1 cm = 0.01 m) in size. Small distances or measurements, such as the length, height, or width of items, are frequently measured in centimeters. Due to its practical size for many routine measurements, it is also frequently employed in scientific and mathematical computations.
In the International System of Units (SI), the meter serves as the base unit and is frequently used to measure lengths, heights, and other measurements. It serves as the basic building block for other metric units like centimeters (one meter equals one hundred centimeters) and kilometers (one kilometer equals one thousand meters).
So, to convert 5.0 cm to meters:
5.0 cm ÷ 100 = 0.05 m
Hence, 5.0 cm is equal to 0.05 meters. The correct option is (B).
To learn more about meters, here:
https://brainly.com/question/13187866
#SPJ4
What acceleration would a 18 kg box have if we pushed it with a force of 250 N across a surface that
has a coefficient of friction of 0.8?
N
Answer:
[tex]a=0.08\ m/s^2[/tex]
Explanation:
Given that,
Mass of a box, m = 18 kg
It is pushed with a force of 250 N
The coefficient of friction is 0.8
We need to find the acceleration of the box.
Normal force acting on the box,
N = mg
M = 18 × 10
N = 180 N
The force acting on the force in terms of coefficient of friction is given by :
[tex]F=\mu mg\\\\\text{or}\\\\ ma=\mu mg\\\\a=\dfrac{\mu }{g}\\\\a=\dfrac{0.8}{10}\\\\a=0.08\ m/s^2[/tex]
So, the acceleration of the box is [tex]0.08\ m/s^2[/tex]
A place kicker launches a kickoff at an angle of 25° to the horizontal and at a velocity of 20 m/s. Calculate the initial velocities in the x- and y-directions.
Willie swift drives a hockey puck into the goal at a speed of 34.8 m/s. From a distance of 60.0 m, how long will it take to reach the net?
Explanation:
distance = rate*time
time = distance divided by rate
now just substitute
time = distance (60 m) divided by rate (34.8 m/sec)
What is the net Force needed to get a 16 kg box moving 4 m/s^2?
Answer:
The net force should be of a magnitude of 64 N
Explanation:
We use Newton's second Law for this:
[tex]F_{net} = m\,*\,a[/tex]
which for our case gives:
[tex]F_{net} = m\,*\,a=16\,(4)\,N= 64\,\,N[/tex]
5 blocks east and 2 blocks north and 6 blocks and then 8 blocks south. what's the total distance traveled?
Answer:
The answer is 21
Explanation:
5 + 2 + 6 + 8 = 21
What are the benefits of evolution for the human population?
Answer:
I hope you fall down a 40 floor hotel resort onto the porch, and explode into the gushing body you are!
Explanation:
Compare How does
the horse's average speed
from 60 s to 120 s compare
to its average speed from
120 s to 180 s?
Answer:
3.75 m/s
Explanation:
Formula:
Average Speed = Total Distance / Total Time
Given:
Total Distance = 150 m
Total Time = 160 - 120 = 40 s
To Find:
Average Speed
Solution:
Average Speed = 150/40
Average Speed = 3.75 m/s
A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.
What is the time interval of marble?
Answer:
t = 6.09 seconds
Explanation:
Given that,
Speed, v = 44.1 cm/s
Distance, d = 269 cm
We need to find the time interval of the marble. Speed is distance per unit time.
[tex]v=\dfrac{d}{t}\\\\\implies t=\dfrac{d}{v}\\\\t=\dfrac{269\ \text{cm}}{44.1\ \text{cm/s}}\\\\t=6.09\ s[/tex]
Hence, the time interval of the marble is 6.09 seconds.