A standardized​ exam's scores are normally distributed. In a recent​ year, the mean test score was and the standard deviation was . The test scores of four students selected at random are ​, ​, ​, and . Find the​ z-scores that correspond to each value and determine whether any of the values are unusual.

Answer:

[tex]x=1[/tex]

Step-by-step explanation:

[tex]3x+4=17x-10[/tex]

Subtract 4 from both sides:

[tex]3x+4-4=17x-10-4[/tex]

[tex]3x=17x-14[/tex]

Subtract 17x from both sides:

[tex]3x-17x=17x-14-17x[/tex]

[tex]-14x=-14[/tex]

Divide both sides by -14:

[tex]\frac{-14x}{-14}=\frac{-14}{-14}[/tex]

[tex]x=1[/tex]

Answer:

1

Step-by-step explanation:

Step 1:

3x + 4 = 17x - 10

Step 2:

4 = 14x + 10

Step 3:

14 = 14x

Answer:

x = 1

Hope This Helps :)

Answer:

w = 6in

l = 12in

Step-by-step explanation:

To solve this problem we propose 2 equations

2w + 2l = 48in

l = 2w

We replace the value of l = (2w) into the first equation and solve

2w + 2(2w) = 48in

2w + 4w = 48in

6w = 48in

w = 48in/6

w = 8in

we replace the value of w and solve

l = 2(8in)

l = 16in

Answer:

It is 300000...........

Answer:

300,000+20,000+4,000+700+90+9

Step-by-step explanation:

Your welcome!!

Complete Question

Which of the following statements are true and which are false? Give reasons for your answers.

(i) Only one line can pass through a single point.

(ii) There are an infinite number of lines which pass through two distinct points.

(iii) A line can be produced indefinitely on both sides.

(iv) If two circles are equal, then their radii are equal.

(v) if AB=PQ and PQ=XY, then AB=XY.

A (i),(ii) - True

  (iii),(iv),(v)-False

B(i),(ii),(iii) -True

  (iv),(v)-False

C   (i),(ii) -False

     (iii),(iv),(v)-True

D  (i),(ii),(iii) -False

    (iv),(v)-True

Answer:

The  correct option is  C

Step-by-step explanation:

    i is false because several lines can pass through a single point

    ii is false because only one line can pass through two distinct points

    iii is true because you can extend a line from both points (start and  end points )

      iv is true because when two equal circle are placed together and radius is trace we will discover that they are equal

       v is true because from Euclid's First Axiom , if a=  c and c =  d  the  a =  d

Answer:

y=5x+20

Step-by-step explanation:

Answer:

260

Step-by-step explanation:

hope it helps

Hey there!☺

[tex]Answer:\boxed{1.762\times10^3}[/tex]

[tex]Explanation:[/tex]

1,762 in scientific notation would be written like this:

[tex]1,762\times10^3[/tex]

Hope this helps!

Answer:

B

Step-by-step explanation:

Answer:

14 boxes of candy would cost $35

Step-by-step explanation:

First find the unit price. It is $2.50 per box. Next multiply it by 14. It is $35 for 14 boxes of candy.

I hope this helped and have a great day.

(Please vote this the brainliest)

Answer:

c

Step-by-step explanation:

i haven't done this in over a year so my explanation wont be good but i know the answer is right

Answer:

  yes

Step-by-step explanation:

Try it and see:

  2(-1) +5(-3) = -2-15 = -17 . . . . . works in the first equation

  -4(-1) +3(-3) = 4 -9 = -5 . . . . . . works in the second equation

Yes, the ordered pair (-1, -3) satisfies the equations.

__

Or, you can check the solution using a graphing calculator.

Answer:

3x+9=57; Chris is 16 years old

Step-by-step explanation:

3x+9=57

Move the Constant to the right

3x=57-9

Calculate

3×=48

Divide both sides

x= 16

Answer:rhombus

Step-by-step explanation:

Answer:

rhombus

Step-by-step explanation:

Answer:

b. psychology drama French chemistry English

Answer: Start by listing the first five multiples of each number. Then circle the common multiples. Finally, identify the least of these common multiples. The LCM of 8 and 10 is 40.

Step-by-step explanation:

Answer:

Start by listing the first five multiples of each number. Then circle the common multiples

Step-by-step explanation:

Answer:

Total variable costs for the summer at each price:

a. = $10,185

b. = $5,820

c. = $1,455

Step-by-step explanation:

a. 35 lawns per week x 12 weeks x $24.25 variable cost

= 35 * 12 * $24.25

= $10,185

b. 20 lawns per week x 12 weeks x $24.25 variable cost

= 20 * 12 * $24.25

= $5,820

c. 5 lawns per week x 12 weeks x $24.25 variable cost

= 5 * 12 * $24.25

= $1,455

d. The variable cost, as can be seen from above, changes based on the volume of activity or production.  The number of lawns influenced the cost, since the other indexes are the same in each case.

Answer: 112.5 hours

Step-by-step explanation:

Answer:

-9 feet

Step-by-step explanation:

The turtle was already at -2 feet below sea level, then the turtle went 7 more feet down. Which means that -2 +7 = -9

Answer:

12z−32

Step-by-step explanation:

Distribute:

=(−4)(z)+(−4)(3)+(−4)(5)+(−4)(−4z)

=−4z+−12+−20+16z

Combine Like Terms:

=−4z+−12+−20+16z

=(−4z+16z)+(−12+−20)

=12z+−32

Answer:

If corresponding vertices on an image and a preimage are connected with line segments, the line segments are divided equally by the line of reflection. That is, the perpendicular distance from the line of reflection to either of the corresponding vertices is the same. Line  is a perpendicular bisector of the connecting line segments.

Step-by-step explanation:

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)'                                 [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S)                               [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S))   [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

Answer: if x = O in the denominator of the first term or if x = -2 in the second term, the results are undefined.

Step-by-step explanation: If the denominator of a fraction is 0 there is no number that solves it because it is impossible to divide by zero.

The average of anything can be calculated by adding up all the terms and dividing by the number of terms.

In this case,

the number of terms = 3

x = the missing test score.

(91 + 72 + x) / 3 = 80

Let's multiply both sides by 3

91 + 72 + x = 240

Combine like terms.

163 + x = 240

Subtract 163 from both sides

x = 77

Carlos scored a 77 on his third test.

Answer:

4

Step-by-step explanation:

The degree of a polynomial is a coefficient with the highest power. In the polynomial given, the highest degree (power) is 4.

Best of Luck!

Answer:

The answer is − 152

Step-by-step explanation:

That was found using PEMDAS.

Answer:

-152

Step-by-step explanation:

use pemdas method

Answer:

Step-by-step explanation:

We have 6 numbers, the mean is the average of all 6, so adding all 6 numbers together and dividing by 6 will give you 3. Because of this we know the 6 numbers will have to add up to 18.

The median is the middle number, but we have an even number so the median is found by adding the 2 middle numbers and dividing by 2.

Because the mean is low, we can guess the first 2 numbers will be small, so let's try 1.  

1 + 1 + _ + _ + _ + _

The remaining 4 numbers will have to add up to 16, and the next 2 numbers need to add up to 12. There would not be any possible combination where this would work. Now we know our first 2 numbers are too big.

Now we try 0.

0 + 0 + _ + _ + _ + _

Now our remaining 4 numbers neet to be 18, but the middle 2 need to add to 12 (so when we divide by 2 we get 6) so 0 is still too big!

-2 + -2 + _ + _ + _ + _  

If we try -2 now the next 4 numbers need to add to 22, but that's still not going to work because 22-12 = 10 and the last 2 numbers have to be the same, or larger than the middle 2.

-3 + -3 + _ + _ + _ + _  

With -3 then our total of the remaining 4 numbers needs to be 24 and 24-12 = 12 so this could be an option!

Our numbers could be:

-3, -3, 6, 6, 6, 6

Let's check:

-3 + -3 + 6 + 6 + 6 + 6 = 18   18/6 = 3    and our middle 2 numbers are 6 so our median would be 6.

If the numbers all have to be different we can come up with a different solution by making our first 2 numbers smaller.

-9, -5, 5, 7, 9, 11  

Let's check

-9 + -5 + 5 + 7 + 9 + 11

-14 + 32 = 18  mean  18/6 = 3      median 5+7 = 12 and 12/2 = 6

So that could also work! There are actually many options that would be correct!

One of the set of numbers whose mean is 3 and median is 6 is 0, 1, 5, 7, 2 and 3.

Mean of a set of numbers is the average value of the numbers. Mean is calculated by taking the sum of the given numbers divided by the total number of numbers.

Let x₁, x₂, x₃, x₄, x₅ and x₆ be the six numbers.

We have mean = 3

⇒ (x₁ + x₂ + x₃ + x₄ + x₅ + x₆) / 6 = 3

⇒ x₁ + x₂ + x₃ + x₄ + x₅ + x₆ = 18

Median is the midpoint of the set of numbers arranged in ascending or descending orders.

If the number of set of numbers are odd, then median is the midpoint of the set and if the number of the set is even, then median is the average of the middle two elements.

Median = 6

Since there are 6 numbers here median = (x₃ + x₄) / 2

(x₃ + x₄) / 2 = 6

(x₃ + x₄) = 12

So x₁ + x₂ + x₅ + x₆ = 18 - 12 = 6

Lets just say x₁ = 0, x₂ = 1, x₅ = 2 and x₆ = 3, the sum of which equals 6.

Now, let x₃ = 5 and x₄ = 7, such that x₃ + x₄ = 12

So one of the set which satisfies the given conditions is x₁, x₂, x₃, x₄, x₅ and x₆ = 0, 1, 5, 7, 2 and 3 respectively.

Hence, one of the list of 6 numbers whose mean equals 3 and median equals 6 is 0, 1, 5, 7, 2 and 3.

To learn more about Mean, click:

https://brainly.com/question/26509052

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Answer:

I thinks so

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

we have the point

[tex](2,-4)[/tex]

so when

x=2

y=4

so we can try on all equations

[tex]y_1=2|x-2|-4\\\\y_1=2|2-2|-4\\\\y_1=2|0|-4\\\\y_1=0-4\\\\y_1=-4[/tex]

so equation 1 could be

[tex]y_2=\frac{1}{2} |x-2|-4\\\\y_2=\frac{1}{2}|2-2|-4\\\\y_2=\frac{1}{2}|0|-4\\\\y_2=0-4\\\\y_2=-4[/tex]

so equation 2 could be

[tex]y_3=2|x+2|-4\\\\y_3=2|2+2|-4\\\\y_3=2|4|-4\\\\y_3=8-4\\\\y_3=4[/tex]

so equation 3 is not

[tex]y_4=\frac{1}{2}|x+2|-4\\\\y_4=\frac{1}{2}|2+2|-4\\\\y_4=\frac{1}{2}|4|-4\\\\y_4=\frac{1}{2}(4)-4\\\\y_4=2-4\\\\y_4=-2[/tex]

so equation 4 is not

So another point that we have is

[tex](0,-3)[/tex]

so we plug in

[tex]y_1=2|x-2|-4\\\\y_1=2|0-2|-4\\\\y_1=2|-2|-4\\\\y_1=4-4\\\\y_1=0[/tex]

so this isn't

[tex]y_2=\frac{1}{2}|x-2|-4\\\\y_2=\frac{1}{2}|0-2|-4\\\\y_2=\frac{1}{2}|-2|-4\\\\y_2=\frac{1}{2}(2)-4\\\\y_2=1-4\\\\y_2=-3[/tex]

so the answer is b