A specimen of steel 100mm diameter with a guage length of 100mm tested a distruction it has an extension of 0.50mm under a load of 70KN and the load at elastic limit is 10KN the maximum load is 140KN the total extension of fracture is 58mm and the diameter at the neck is 16mm . find the Stress of elastic limit, young modulus, percentage enlogation, percentage reduction in area , and ultimate tensile stress?​

Answers

Answer 1

The stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

How to calculate the values

Stress = Force / Area

Young's modulus = Stress / Strain

Percentage elongation = (extension / gauge length) x 100%

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Ultimate tensile stress = Maximum load / Area

Diameter of specimen = 100 mm

Gauge length = 100 mm

Extension at 70 KN load = 0.50 mm

Load at elastic limit = 10 KN

Maximum load = 140 KN

Total extension at fracture = 58 mm

Diameter at neck = 16 mm

We can calculate the area of the specimen as follows:

Area = π/4 x d^2

Area = π/4 x (100 mm)^2

Area = 7853.98 mm^2

The stress at elastic limit can be calculated as:

Stress = Load / Area

Stress = 10 KN / 7853.98 mm^2

Stress = 1.27 N/mm^2

The Young's modulus can be calculated as:

Strain = Extension / Gauge length

Strain = 0.50 mm / 100 mm

Strain = 0.005

Stress = Load / Area

Load = Stress x Area

Load = 1.27 N/mm^2 x 7853.98 mm^2

Load = 9982.16 N

Young's modulus = Stress / Strain

Young's modulus = 1.27 N/mm^2 / 0.005

Young's modulus = 254 N/mm^2

The percentage elongation can be calculated as:

Percentage elongation = (extension / gauge length) x 100%

Percentage elongation = (58 mm - 0.50 mm) / 100 mm x 100%

Percentage elongation = 57.5%

The percentage reduction in area can be calculated as:

Original area = π/4 x (100 mm)^2 = 7853.98 mm^2

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Percentage reduction in area = [(7853.98 mm^2 - 201.06 mm^2) / 7853.98 mm^2] x 100%

Percentage reduction in area = 97.44%

The ultimate tensile stress can be calculated as:

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Ultimate tensile stress = Maximum load / Area

Ultimate tensile stress = 140 KN / 201.06 mm^2

Ultimate tensile stress = 696.67 N/mm^2

Therefore, the stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

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Answers

Based on the information provided, the function updateScore(player, points) may not be a good candidate to be placed in a library.
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Which two statements correctly describe a router memory type and its contents? (Choose two)

Answers

Answer:

One statement that describes a router memory type is that it is typically volatile memory, meaning that its contents are lost when the router is powered off or restarted.

Another statement is that router memory often contains the operating system and configuration files for the router.

Explanation:

Here are two statements that correctly describe a router memory type and its contents:

1. Router Memory Type: RAM (Random Access Memory)
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2. Router Memory Type: NVRAM (Non-Volatile Random Access Memory)
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Question 8
An electrical transformer leak of PCBs resulted in the destruction of millions of dollars worth of chicken and eggs in:
a. Montana
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d. Wisconsin

Answers

The electrical transformer leak of PCBs resulted in the destruction of millions of dollars worth of chicken and eggs in New York.An electrical transformer leak of PCBs resulted in the destruction of millions of dollars worth of chicken and eggs in:c. Michigan

The incident you are referring to occurred in Michigan. In 1973, an electrical transformer owned by the Michigan-based company Consumers Power leaked polychlorinated biphenyls (PCBs) into the nearby creek, which was a source of water for a chicken farm. The PCBs contaminated the chickens and their eggs, resulting in the destruction of millions of dollars worth of poultry and eggs. This incident was one of the first high-profile cases that brought attention to the environmental hazards of PCBs, which were widely used in electrical equipment and other industrial applications at the time.

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a 3-phase, 75 hp, 440 v induction motor has a full-load efficiency of 91 percent and a power factor of 83 percent. calculate the nominal current per phase.

Answers

To calculate the nominal current per phase for a 3-phase, 75 hp, 440 v induction motor, we need to use the following formula:

I = P / (sqrt(3) x V x EFF x PF)

Where:

I = Current per phase
P = Power in horsepower (75 hp)
V = Voltage (440 V)
EFF = Full-load efficiency (91%)
PF = Power factor (83%)

Plugging in the values, we get:

I = 75 / (sqrt(3) x 440 x 0.91 x 0.83)
I = 75 / (1.732 x 440 x 0.91 x 0.83)
I = 75 / 480.77
I = 0.156 A (rounded to three decimal places)

Therefore, the nominal current per phase for the given 3-phase, 75 hp, 440 v induction motor is 0.156 A. It's worth noting that this value is for full load conditions, and the actual current may vary depending on the motor's load and operating conditions.

We will find the nominal current per phase for a 3-phase, 75 hp, 440 V induction motor with a full-load efficiency of 91% and a power factor of 83%.

Step 1: Convert horsepower (hp) to watts (W).
1 hp = 746 W
75 hp × 746 W/hp = 56,070 W

Step 2: Calculate the input power.
Input power = Output power / Efficiency
Input power = 56,070 W / 0.91 = 61,593.41 W

Step 3: Calculate the total apparent power (S).
Apparent power = Input power / Power factor
S = 61,593.41 W / 0.83 = 74,215.44 VA

Step 4: Calculate the line voltage.
Line voltage = Phase voltage × √3
Line voltage = 440 V × √3 = 762.0 V

Step 5: Calculate the nominal current per phase.
Nominal current = Apparent power / (Line voltage × √3)
Nominal current = 74,215.44 VA / (762.0 V × √3) = 60.4 A

So, the nominal current per phase for this 3-phase, 75 hp, 440 V induction motor with a full-load efficiency of 91% and a power factor of 83% is approximately 60.4 A.

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A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 4 MPa in the boiler and 5 kPa in the condenser and a turbine inlet temperature of 700°C. The boiler is sized to provide a steam flow of 50 kg/s. Determine the power produced by the turbine and consumed by the pump. Use steam tables.

Answers

The pump work = v3.dP = 57.18 x 0.001 x ( 4000 - 20) =227.57 KW

How to solve

here At T1 = 700 C and P1 = 4 Mpa, from steam tabel : h1 =3906.41 KJ/Kg and s1 = 7.62 KJ/Kg.K

now s1 = s2 = 7.62 KJ/Kg.K as 1-2 is isentropic

so at P2 = 20 Kpa and s2 = 7.62 KJ/Kg.K , fom steam table : h2 = 2513.33 KJ/Kg

a) power produced by turbine = m.( h1 - h2) = 57.18 x ( 3906.41 - 2513.33) = 79656.15 KW

b) at P3 = 20 Kpa, 3 = vf = 0.001 m^3/kg

so pump work = v3.dP = 57.18 x 0.001 x ( 4000 - 20) =227.57 KW

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Normally counters are retentive. This means that if your accumulated count is up to 300 and power to your system is lost, when power is restored the accumulated count will be:a: 000B.250c. 300D. 999

Answers

A: 000.

Normally counters are retentive, which means they retain the accumulated count even when power is lost. So, in this case, when power is restored, the accumulated count will still be 300. However, if the counter is non-retentive, then the accumulated count would have been reset to 000 after the power loss.

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Answers

A. Carrier sense multiple access with collision detection (CSMA/CD).

In Ethernet networks, the media access control (MAC) protocol known as carrier sense multiple access with collision detection (CSMA/CD) is used to identify whether the communication channels are clear and when a device is free to send data. Devices must listen to the network in order to determine if any other devices are transmitting data at the moment. The gadget can transfer data if the channel is open. The data transmitted by both devices become corrupted if two devices attempt to communicate at the same time due to a collision. In this scenario, the devices halt transmission, wait an arbitrary period of time, and then try again. CSMA/CD helps to prevent data collisions and ensure efficient use of the network by allowing multiple devices to share the same communication channel.

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If subnetting is used in an organization, you can include the broadcast address by mistake when performing ping sweeps. How might this happen?

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When subnetting, an incorrect subnet mask or range may include the broadcast address, causing ping sweeps to mistakenly include it.

When subnetting a network, it is important to exclude the network and broadcast addresses from the range of IP addresses being scanned during a ping sweep.

However, it is possible for a mistake to be made and the broadcast address to be included in the range of IP addresses being scanned.

This can happen if the person performing the ping sweep is not familiar with the subnetting scheme or if they make a typographical error when entering the range of IP addresses.

Including the broadcast address can cause unnecessary network traffic and slow down network performance, as every device on the subnet will respond to the ping sweep.

It can also make it difficult to identify which devices are actually active on the network.

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A sine wave changes plarity at the zero crossing
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Answers

A sine wave changes polarity at the zero crossing, which is the point where the waveform crosses the x-axis and changes from positive to negative or vice versa.

PCl5 is non-polar, PCl3O is polar, SF6 is polarity  SO2Cl2 is polar, SO3 is non-polar, and SiCl4 is non-polar, according to the VSEPR theory.

It is non-polar, PCl5. Due to the arrangement created by the trigonal bipyramidal structure, opposing bonds neutralise each other's dipole moments.

Due to an imbalanced distribution of valence electrons and a net dipole moment, PCl3O is a polar molecule.

The VSEPR theory states that SF6 is non-polar. The bond dipoles are negated when six fluorine atoms are placed symmetrically around the sulphur atom.

It is evident from the tetrahedral geometry that So2Cl2 is polar. Its molecules are not in opposition to one another exactly. for the purpose of dipole moments.

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What are PG binders tested for high temperature wise?

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PG binders, also known as Performance-Graded binders, are tested for their high-temperature performance properties.

Rutting is the permanent deformation of asphalt pavement caused by repeated traffic loading, and flow is the tendency of the asphalt binder to deform and flow under high temperatures. The high-temperature performance of PG binders is determined through a series of laboratory tests known as the Superpave performance grading system. These tests measure the viscosity and stiffness of the binder at high temperatures, as well as its resistance to rutting and flow. The results of these tests are used to assign a performance grade to the binder, typically a two-letter designation such as PG64-22, which indicates its performance properties at high and low temperatures. By selecting PG binders with appropriate high-temperature performance properties, engineers and paving professionals can ensure that the asphalt pavement will resist deformation and cracking under high traffic and high-temperature conditions, providing a durable and long-lasting pavement structure.

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Which module, a DDR3 or DDR2 DIMM, uses lower voltage?

Answers

A DDR3 DIMM module uses lower voltage compared to a DDR2 DIMM module.

DDR3 and DDR2 are types of DDR SDRAM (Double Data Rate Synchronous Dynamic Random Access Memory) modules, commonly used for computer memory. DDR3, being the newer generation, operates at a lower voltage of 1.5 volts, while DDR2 operates at 1.8 volts.

The lower voltage in DDR3 modules results in reduced power consumption, making them more energy-efficient. This improvement is important for maintaining optimal system performance and reducing the strain on the power supply. In addition to lower voltage, DDR3 also offers higher data transfer rates and larger memory capacities, making it a better choice for modern computing needs.

However, it's essential to note that DDR3 and DDR2 modules are not interchangeable due to their different physical designs and voltage requirements. When upgrading or replacing memory in a computer, ensure that you use the correct type of DIMM module compatible with the motherboard and processor.

In summary, DDR3 DIMM modules use lower voltage (1.5 volts) compared to DDR2 DIMM modules (1.8 volts), making them more energy-efficient and suitable for modern computing applications.

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The line continuation character is a
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B. %
C. &
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Answers

The line continuation character is a D. \ (backslash). A line continuation character, also known as a line continuation marker or line continuation escape character, is a character or sequence of characters used in computer programming to indicate that a line of code continues on the next line, rather than ending at the current line.

In many programming languages, lines of code are typically terminated by a newline or line feed character, which signifies the end of a line of code. However, in cases where a single line of code becomes too long or exceeds the allowed line length limit of a programming language or coding style convention, a line continuation character can be used to indicate that the line of code continues on the next line.

It's important to follow the specific syntax and rules of the programming language being used when employing line continuation characters, as they can vary from language to language. Proper usage of line continuation characters can help improve code readability, especially in cases where long lines of code need to be broken down into multiple lines for better code organization and style.

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A single panel or group of panels units designed for assembly in the form of a single panel, including buses and automatic over-current devices, and equipped with or without switches for the control of light, heat or power circuits.
100 definations

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Based on the information provided, it sounds like the question is asking for a definition of a panel or panel unit that can be used for controlling light, heat, or power circuits. A panel is typically a collection of electrical components, including buses and over-current devices, that are assembled into a single unit for ease of installation and use.

These panels may be equipped with switches or other control devices to help manage the flow of electricity within a building or other structure. Some panels may be designed for use in specific applications, such as lighting or HVAC systems, while others may be more general-purpose units that can be used for a variety of purposes. Overall, panels are an important part of many electrical systems and can help to simplify the installation and management of these systems.

The degree to which one input can be substituted by another without having an impact on the entire manufacturing process is referred to as input substitutability. Perfect substitutability is described in panel (a), where inputs can be swapped out for one another with no change to the manufacturing process.

The complimentary inputs discussed in panel (d) are extremely specialised and cannot be substituted in any way. Inputs can be swapped, although there are some restrictions and costs involved, as shown in Panel (c).

When inputs are intermediate items, their capacity to be substituted depends on how elastic the market for the ultimate product is, as shown in panel (b). Consequently, panel is the appropriate order from easy to toughest scenario of input substitutability.

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_______ is a term often used to describe comprehensive efforts to monitor and improve all aspects of quality within a firm.
Ethics, Robotics, Expert systems, TQM, CIMS

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TQM (Total Quality Management) is a term often used to describe comprehensive efforts to monitor and improve all aspects of quality within a firm. This can include considerations of ethics and responsible use of emerging technologies like robotics and expert systems.


Total Quality Management (TQM) is a term often used to describe comprehensive efforts to monitor and improve all aspects of quality within a firm. TQM involves continuous improvement processes, employee involvement, and customer satisfaction to ensure a high level of quality in products and services.

Caroline is building an expert system for wartime defense. Which of these is true about the system she is building? A. The expert system can demonstrate atta.

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"is a term often used to describe comprehensive efforts to monitor and improve all aspects of quality within a firm."

TQM (Total Quality Management) is a term often used to describe comprehensive efforts to monitor and improve all aspects of quality within a firm.

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A restricted area must be properly marked to inform personnel they are in the vicinity of a restricted area. True or False?

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Answer : True. A restricted area must be properly marked to inform personnel they are in the vicinity of a restricted area. This helps to ensure that personnel are aware of the potential risks and take appropriate precautions while working in that area.

The majority of earthquake zones are distributed near or at tectonic plate boundaries, frequently in vicinity clusters. Most earthquakes are located within the Pacific Ocean's Ring of Fireplaces. Convergent or conservative barriers are linked to earthquakes that are most effective.

The majority of earthquakes will occur near any type of plate border. Massive earthquakes frequently begin at the plate boundaries. Around the arena, there could be an earthquake belt where plate motion causes earthquakes to rise. When tension or electricity is released from the crust, an earthquake is caused.

On the ridges, there seem to be a lot of shallow earthquakes. They are usuallyb, orange or yellow in colour, and shallow in depth.

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Non metallic auxiliary gutters shall have expansion fitting installed where the expected length change due to expansion and contraction due to temperature change is more than ________ inches.
366.14

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Nonmetallic auxiliary gutters shall have expansion fittings installed where the expected length change due to expansion and contraction due to temperature change is more than 366.14 inches.

According to the National Electrical Code (NEC) Section 366.14, non-metallic auxiliary gutters should have expansion fittings installed when the expected length change due to expansion and contraction from temperature changes is more than 1/4 inch (0.25 inches).

The National Electrical Code (NEC) or NFPA 70 is the standard for the safety of electrical installations and equipment in the United States. It is part of the National Fire Code series published by the National Fire Protection Association (NFPA), a private trade association.  Although the word "state" is used, it is not a federal law. It is often adopted by states and municipalities in an effort to standardize electronic security management. In some cases, NECs are modified, modified, and possibly rejected according to regional policies voted on by local leaders.

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