a solenoid has 15 turns per centimeter of its length. the solenoid is twisted into a circle so that it becomes shaped like a toroid. what is the magnetic field at the center of each turn of the toroid? the current is 29 mama .

Answers

Answer 1

The magnetic field at the center of each turn of toroid is: 2.826×10⁻⁵ T

What is a magnetic field?

Magnetic field is a vector field in surrounding of a magnet, electric current carrying conductor or a changing electric field, in which magnetic forces can be experienced.

Magnetic field of a toroid is calculated as (B): μ₀nI

Where, μ₀= permeability

n= Number of turns in toroid

I= Current

B= Magnetic field

In the given question,

n=15 turns/cm

I=15mA

Now turns per meter length is: 15/10⁻²=1500turns per meter

The magnetic field at the center of each turn of the toroid is(B): μ₀nI

B= (4[tex]\pi[/tex]×10⁻⁷)(1500)(15×10⁻³A)

B= 2826×10⁻⁸ T

B= 2.826×10⁻⁵ T

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Related Questions

Free-body diagrams for four situations are shown below. For each situation, determine the net force acting upon the object. Your answer must include both the magnitude and the direction of the net force vector. You should have ​four (4) total responses to this question (labeled A, B, C, and D).

Answers

Answer:

A) 3 N [south]

B) 0 N

C) 5 N [south]

D) 4 N [east]

Explanation:

A) 5 - 2 = 3

B) equal forces

C) 0 + 5 = 5

D) 7 - 3 = 4

Can you explain for me Colomb's Torsion Balance Experiment​

Answers

The two experiments that Coulomb's to show the relationship between electrostatic force and that law carries Coulomb's name today to include this relationship as a fundamental component.

Torsion balance is used to study the repulsion and attraction forces of charged particles and found that the strength of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

A bar is suspended from the centre of the torsion balance by a thin fibre. The fibre functions as a flimsy torsion spring.

The torsion balance in Coulomb's experiment was a suspended metal-coated ball attached to one end of an insulating rod.

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saturn orbits the sun at more than 50% of the speed of Mars 
true or false????

Answers

Answer:

(TRUE) Mars seems to pass the fastest, Jupiter next, and Saturn the slowest. But all exhibit that puzzling quirk--near the point of their celestial course precisely opposite the Sun ("opposition"), their action amongst the stars briefly turns around.

Explanation:

Mars: 24.077 km/s (53,853 miles per

hour), or a period of about 686.93 days.

Answer:is true

Explanation:

Mr. Mangan is in freefall on Planet Y. His velocity increases from rest to 30 m/s in 1.2 s. If his mass is 86 kg, what is his weight on Planet Y? What is the gravitational field strength on Planet Y?

Answers

Explanation:

First, we need to calculate the gravitational field strength g on Planet Y. So, we will use the following e

pingus pingus pingus pingus pingus pingus

Answers

Answer: pingus

Explanation: pingus

if solar radiation is 1190 w/m2 , how many photons strike the leaf every second? assume three significant figures and an average wavelength of 504 nm for solar radiation.

Answers

7.15 x 10^17 photons strike the leaf every second if solar radiation is 1190 w/m2 strike .

Solar radiation intensity = 1200 W/m2

= 1200 J/m2 s-1 (1 W = 1 J/s)

Area of leaf = 2.35 cm2

= 2.35 x 10-4 m2 (1 cm2 = 10-4 m2)

Total energy striking leaf per second = intensity x area x time

= 1200 J/m2 s-1 x 2.35 x 10-4 m2 x 1 s

= 0.282 J

Wavelength λ = 504 nm = 504 x 10-9 m (1 nm = 10-9 m)

Energy of 1 photon E = hc/λ

= 6.626 x 10-34 x 2.998 x 108/504 x 10-9

= 3.9414 x 10-19 J

where h is Planck constant and c is speed of light

Number of photons striking leaf per second = total energy/energy of 1 photon

= 0.282/3.9414 x 10-19

= 7.15 x 10^17 photons

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an aluminum wire having a cross-sectional area equal to 5.10 10-6 m2 carries a current of 7.50 a. the density of aluminum is 2.70 g/cm3. assume each aluminum atom supplies one conduction electron per atom. find the drift speed of the electrons in the wire.

Answers

1.29×10^-4 m/s is the drift speed of the electrons in the wire.

volume=molar mass/density= 26.98g/2.7g/cm3 = 9.99 cm3

n=(6.02E23 electron/volume)*(1.00E6 cm3/ 1 m3) = 6.024E28 m3

V= I/neA= 7.50 A/(6.024E28 m3)×(1.60E-19 C)×(5.60E-6 m2))

V= 1.29×10^-4 m/s

Electrons and other subatomic particles constantly migrate in arbitrary ways. When exposed to an electric field, electrons do travel randomly, but they do so slowly in the direction of the applied electric field. The drift velocity refers to the overall speed of these electrons.

M/s is the SI unit for drift velocity. It can also be expressed in m2/ (V.s). The relationship between the electrons' current density and their drift velocity is straightforward. Additionally, when the strength of the electric field grows, the drift velocity and current flowing through the conductor do as well.

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would adding mass to the top of a slope in the form of houses or buildings make the mass more or less likely to slide?

Answers

adding mass to the top of a slope in the form of houses or buildings make the mass more likely to slide because the houses add weight to the slope making it more unstable.

When a slope breaks, there is mass waste. When a slope is excessively steep and unstable given the materials and environmental factors at play, it fails. The slope angle and the underlying material's strength are the two main criteria that eventually influence slope stability.

On the Earth's surface, the force of gravity, which contributes to mass wasting, is mostly constant, however there are minor fluctuations based on the height and density of the underlying rock. In the illustration, the force of gravity is seen pulling a rock block on a slope down toward the center of the Earth.

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A rocket is fired with an initial velocity of 100m/s at angle of 55degree above the horizontal it expodes on the mountain side 12 second after it's firing what is the x and y coordinates of the rocket relative to it's final point

Answers

The coordination of the rocket relative to its firing point is 688.32m and 277.44m.

What is coordination?

The purpose of organizing people or groups so they work together properly.

Sol-

The X and Y coordinates of the rocket relative of firing

As per the given question

Velocity (vi)=100ms-1

Angle=55.0

Time (t)=12

The horizontal range of projectile at X is

X=vxi×t

x=vi×cos×t

Now substituting the required value we get

X=300×cos 55×12

X=100×0.5756×12

X=688.32 m

Now substituting the recauird value

We get

Y= 983.04-705.6

Y=277.44m

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In 1934, the wind speed on Mt.Washington in New Hampshire reached a record high. Suppose a very sturdy glider is launched in this wind, so that in 45.0 s the glider reaches the speed of the wind. If the glider undergoes a constant acceleration of 2.29 m/s2,what is the wind’s speed? Assume that the glider is initially at rest

Answers

The wind's speed at the given constant acceleration is 103.05 m/s.

What is velocity of an object?

The velocity of an object is defined as the rate of change of displacement of the object with time.

Mathematically, the velocity of an object is given as;

v = u + at

where;

a is the acceleration of the objectv is the final velocity of the objectt is time of motion of the objectu is the initial velocity of the object

Since the object started from rest, the initial velocity = 0

v = 0 + (2.29 x 45)

v = 103.05 m/s

Thus, the final velocity of the glider will be greater than his initial velocity moving at the constant acceleration.

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Question at position 3

The table shows mass and weight data of some common items.




Based on the data, which conclusion is valid regarding the relationship between the force of gravity, mass, and weight?



The table shows mass and weight data of some common items.




Based on the data, which conclusion is valid regarding the relationship between the force of gravity, mass, and weight?



The weight of an object depends on the force of gravity of the planet, but the mass does not.



Neither the mass nor the weight of an object depends on the force of gravity.



The mass of an object depends on the force of gravity of the planet, but the weight does not.



Both the mass and the weight of an object depend on the force of gravity.

Answers

An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass. It depends on the object's mass and acceleration due to gravity.

Mass is an intrinsic unchanging property. Weight is a force and it depends on gravitational force. This force is directly proportional to mass the more mass the object has the stronger the force of gravity will be. Because of this, it turns out that gravity does not matter when we compare the distance traveled by objects with different masses. The important part of the force is air resistance also called drag.

The slope of the graph is the relationship between weight and mass. The slope tells how many newtons of weight pull down on each kilogram of mass. Mass is the measure of the amount of matter in an object. This is an immutable property inherent in the body. Mass cannot be destroyed or created. Weight is the production of mass and acceleration due to gravity.

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A motor car having a mass of 2 tonnes is being accelerated up a gradient of 1 in 25. At an engine speed of 4 000 rimin the b. P. Is 57 kw the effective tyre radius is 330 mm, the rolling res?stance is 180 n/tonne, and the rear-axle ratio is 4. 4 to 1 assuming a transmission efficiency of 90 % and neglecting air resistance, determine the value of the acceleration at the given speed 262 mls1.

Answers

The value of the Acceleration at the given speed of 262 m/s will be 0.245 m / s²

Throughout time, the velocity is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second. An object is considered to be accelerating if its velocity is changing; it has acceleration.

Given that:

Mass of car = 2 Tonnes = 2000 kg.

Wheel's power transfer = Efficiency * b.P.

Power = 0.9 * 57000

Therefore, Power = 51300 W

Wheel's angular velocity = (2[tex]\pi[/tex]N  / 60) * (1 / rear-axle ratio)

Angular Velocity = (2[tex]\pi[/tex] * 4000) / 60 * (1 / 4.4)

Therefore, Angular Velocity = 95.15 rad / sec

Wheel:

Power = Torque * Angular Velocity

P = F * Tyre Radius * W

⇒ 51300 = F * 0.33 * 95.15

F = 51300 / (0.33 * 95.15)

F = 51300 / 31.4

Therefore, Force = 1633.76 (by the engine)

Resistance:

Rolling Resistance (Fr) = 180 N/tonne * 2 = 360 N

F₁ = 360N

Gradient Resistance:  

tanθ = 1 / 25

θ = 2.2906°

Fg = mg * sinθ

Fg = 2000 * 9.84 * sin (2.2906)

Fg = 783.37 N

Acceleration (a):

Net force = Mass * Acceleration

F - (Fr + Fg) = 2000 * a

1633.76 - (360 + 783.37) = 2000 * a

a = 490.39 / 2000

Therefore, Acceleration = 0.245 m / s²

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When you drop a .44 kg apple earth exerts a force on it that accelerates it at 9.8 m/s^2 towards the earth's surface. newtons third law, the apple must exert an equal but opposite force on earth. if the mass of earth is 5.98 x 10 ^24 what is the magnitude of the earths acceleration towards the apple

Answers

If the mass of earth is 5.98 x 10 ^24 Then magnitude of the earths acceleration towards the apple 6.56 * 10^(-25) m/s²

A key concept in science is the concept of magnitude in physics. The general quantity or distance is referred to as magnitude. When it comes to the elements of movement, we can tie magnitude to an object's size and motion speed.

A particular object's magnitude is determined by its size or quantity. For instance, when it comes to speed, if a car is moving at a quicker rate than a nearby motorcycle, the magnitude of the automobile's speed is greater than the speed of the motorcycle. Although they contain directions as well as magnitude, vector quantities. Vector quantities include things like force, acceleration, speed, velocity, and many others. A vector's absolute value is referred to as its magnitude.

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a train slows down as it rounds a sharp horizontal turn, going from 96.0 km/h to 58.0 km/h in the 16.0 s that it takes to round the bend. the radius of the curve is 120 m. compute the acceleration at the moment the train speed reaches 58.0 km/h. assume the train continues to slow down at this time at the same rate.

Answers

The acceleration vector will be the vector sum of the tangential and radial acceleration components because the train is changing both its speed and direction.

Since the train is altering both its speed and direction, the vector sum of the tangential and radial acceleration components will represent the acceleration vector.

The radius of curve and the train's speed can be used to calculate the tangential acceleration, while the elapsed time and changing speed can be used to calculate the radial acceleration.

Let's first convert the speed measurements from km/h to m/s:

v I = 90.0 km/h

= (90.0 km/h) (10 3 m/km) (1 hour and 36 minutes)

= 25.0

m/s v f = 50.0 km/h

= (50.0 km/h) (10 3 m/km) (1 hour and 36 minutes)

= 13.9 m/s

Backwards, the tangential acceleration is equal to a t = t v = 15.0s (13.9 m/s 25.0 m/s = 0.741 m/s 2), and the radial acceleration is equal to a r = r v 2.

Consequently, an is equal to 1.48 m/s 2 inward and 29.9 0 backward.

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two boxes sit side-by-side on a smooth horizontal surface. the lighter box has a mass of 5.56 kg, the heavier box has a mass of 7.51 kg. calculate the contact force between these boxes when a horizontal force of 5.02 n is applied to the light box.

Answers

Answer:

18.09

Explanation:

add all the numbers together

what is the correct answer for this ?

Answers

Answer: the correct answer is option "C"

Explanation:

A negative charge of -6.0 x 10-5 exerts an attractive force of 65 N on a second charge 0.50 m away. What is the magnitude of the second charge? Is the second charge negative or positive?

Answers

The magnitude of the second charge is 3.01 x 10⁻⁵C.

The second charge is positive.

What is the magnitude of the second charges?

The magnitude of the second charge is determined by applying Coulomb's law of electrostatic force as shown below.

F = kq₁q₂/r²

where;

r is the distance between the chargesk is coulomb's constantF is the force between the charges

Substitute the given parameters, and solve for the magnitude of the second charge as shown below.

q₂ = Fr²/kq₁

q₂ = (65 x 0.5²) / (9 x 10⁹ x 6 x 10⁻⁵)

q₂ = 3.01 x 10⁻⁵C

Thus, the magnitude of the second charge is 3.01 x 10⁻⁵C. Also, since the force is attractive, the second charge must be positive.

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I NEED HELP URGENTLY! FOR 20 POINTS!

Answers

The law of definite proportion states that any sample of the compound will always have the same percentage of each element by weight or mass.

There are four elements that made up matter: air, water earth, and fire is not the main idea of dalton's atomic theory.

What is the law of definite proportion?

The Law of Definite Proportion defines that the elements that composed a chemical compound are generally arranged in a definite mass ratio regardless of preparation.

The composition of compounds will always be the same by mass using the law of definite proportions. Chemical compounds are made of elements that are present at fixed ratios in terms of their mass.

In the nitrogen dioxide molecule (NO₂), Nitrogen and oxygen atoms are always present in a 1:2 ratio.

According to Dalton's atomic theory, all matter consists of atoms. The atoms of the same element have the same mass and the atoms of different have different masses and compounds are made of atoms of more than one element.

Therefore, for question (1) option (C) and for (2) option (C) is correct.

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Anya has 115 mangoes lauren has five times the the number of mangoes Anya has they put them together and sold them in the market at $450 to $15 the sold all the mangoes how much money was collected at the end of the sale

Answers

$10,350 is the amount of money that has been collected mangoes are sold by Anya and Lauren at $15.

Number of mangoes of Anya's = 115 mangoes

Number of mangoes of Lauren's = 5 × 115 = 575 mangoes

Total number of mangoes = Number of mangoes Anya has + Number of mangoes Lauren has

= 115 + 575

= 690 mangoes

Amount each mango sold = $15

The total amount of money collected = Total number of mangoes × Amount each mango were sold

= 690 × 15

= $10,350

So, therefore, Anya and Lauren sold their total mangoes for $10,350.

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a plane travels 360 km in 3 hours. what is its velocity

Answers

The velocity of the plane is 120 km/hr.

How would you define velocity?

Velocity is the pace at which an object's location is changing as perceived from a particular point of view and as measured by a certain unit of time (for example, 60 km/h northbound). Velocity is the direction at which an object is traveling. Velocity is a fundamental concept in kinematics, the branch of classical mechanics that deals with the motion of bodies. In order to be defined, the physical vector quantity known as velocity needs to have both a magnitude and a direction. Speed is a coherent derived unit whose quantity is measured in metres per second (m/s or m/s1) in the SI. Speed is the scalar absolute value (magnitude) of velocity (metric system). As opposed to "5 meters per second east," which is a vector, "5 meters per second," for instance, is a scalar.

Distance traveled = 360 km

Time taken = 3 hours

Hence, velocity = 360/3 = 120 kmph

Thus, the velocity of the plane is 120 km/hr.

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If an element starts off with an activity of 100Bq, and its half life is 10 minutes, what would the activity be after 5 minutes???

Answers

The radioactivity of the element after 5 minutes is 75 Bq.

What is radioactivity?

Radioactivity is a phenomenon exhibited by radioactive elements or isotopes by emitting energy and subatomic particles spontaneously.

The radioactivity of a radioactive element or isotope in  becquerels is denoted by decay per second.

The radioactivity of the isotope in  becquerels is calculated as follows;

Bq = decay / time

Half life = 10 min

This implies that after 10 minutes, the activity of the element will be;         ¹/₂(100 Bq) = 50 Bq

The given time, 5 minutes is not up to 10 minutes, so the element will not be reduced to 50 Bq.

5 minutes = half of 10 minutes

half of 50 Bq = 25 Bq

So after 5 minutes, the element will decay 25 Bq, and the activity will be 75 Bq.

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An object is thrown up from the top of a building of height h with an initial velocity v,. The object reaches its maximum height and then returms down to the ground. The velocity of this object when it reaches the maximum height is equal to:

Answers

Maximum height of the object is the highest vertical position along its trajectory. The object is flying upwards before reaching the highest point - and it's falling after that point. It means that at the highest point of projectile motion, the vertical velocity is equal to 0 (Vy = 0)

Look at the energy bar graph on the left. The total energy does not move, as it shows the maximum energy used or stored at any given instant. However, the potential energy and kinetic energy are constantly changing. Why?

Answers

The potential energy and kinetic energy are constantly changing because of law of energy conservation as the kinetic energy is constantly being converted into potential energy and vice versa.

What is the law of conservation of energy?

The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

The total mechanical energy of any system is made up of kinetic energy and potential energy.

The kinetic energy is the energy of the object due to its motion while the potential energy is the energy of the object due to its height above the ground.

Based on the law of conservation of energy, the kinetic energy of an object can be converted into potential energy and from potential energy to kinetic energy.

Thus, the potential energy and kinetic energy are constantly changing because of law of energy conservation as the kinetic energy is constantly being converted into potential energy and vice versa.

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a crane lifts a 425 kg steel beam vertically a distance of 79.0 m . how much work does the crane do on the beam if the beam accelerates upward at 1.60 m/s2 ? neglect frictional forces.

Answers

The crane does increase the kinetic and potential energy of the beam: W=ΔK+ΔU. Potential energy fluctuates with height while kinetic energy changes with speed W=mΔv2/2+mgΔh.

We should figure out v before moving on. We are aware that the beam is moving 95 meters away at an acceleration of 1.8 text m/s/s. Assuming that the acceleration is uniform and that the initial velocity was 0 m/s.

v2f=v2i+2aΔx

v2f=(0 m/s)

2+2(1.8 m/s2)(95 m) (95 m)

v2f=342 m2/s2 (saving one additional sign. for calculations in the future)

vf=18.5 m/s

Now that we are aware of acceleration vf and v, we may proceed to calculate W.

W=mΔv22+mgΔh

W=m(Δv22+gΔh)

W = 425 kg((18.5 m/s)22+(9.81 m/s2)(95 m))+(9.81 m/s2)

W=(425 kg)(171 + 932 m2/s2)

W=(425 kg)(1103 m2/s2)

W=469000 J→4.7×105 J

The crane does make the beam's kinetic and potential energy higher: W=K+U. In contrast to kinetic energy, which changes with speed W=mv2/2+mgh, potential energy varies with height.

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2. A peregrine falcon dives 83 m/s to the South-East at a 30 degree angle. What is the x-axis component (East/West) of its velocity? What is the y-axis component (North/South) of its velocity?

Answers

The x - component and the y - component of the falcon will be 71.88 a[x] m/s and  41.5 a[y] m/s respectively.

What are the components of a vector?

Any vector (say [V]) can be resolved along the axes of two - dimensional coordinate system such that the vector components along this direction will be -

[x] = VcosФ a[x]

[y] = VsinФ a[y]

Given is peregrine falcon dives 83 m/s to the South-East at a 30° angle.

Now, the x - component of the falcon will be -

[x] = 83 cos (30) = 71.88 a[x] m/s

Similarly, the y - component of the falcon will be -

[y] = 83 sin(30) = 41.5 a[y] m/s

Therefore, the x - component and the y - component of the falcon will be 71.88 a[x] m/s and  41.5 a[y] m/s respectively.

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adjacent antinodes of a standing wave on a string are 15.0 cmcm apart. a particle at an antinode oscillates in simple harmonic motion with amplitude 0.850 cmcm and period 0.0750 ss. the string lies along the xx-axis and is fixed at xx

Answers

  D = 15 cm , b)  λ = 30.0 cm , c) 0.0850 cm, d) v = 400 cm / s , e)    v = 80.43 cm / s , v = -80.43 cm / s, f)   D₂= 7.5 cm

Standing waves form when two waves of the same frequency traveling in opposite directions,

A) in the waves the distance of the nodes and antinode is the same since the wavelength is constant

         D = 15 cm

B) the wavelength is the distance for which the wave repeats itself, in the case of a standing wave, the distance between two nodes is the lamina of the wavelength.

       D = λ / 2

        λ=  15 2

        λ = 30.0 cm

C) the amplitude of each wave is 0.0850 cm, and the amplitude of the standing wave is double A = 0.17 cm

D) Let's use the speed ratio

       v =  λ f

       f = 1 / T

       v =  λ / T

      v = 30.0 /0.0750

      v = 400 cm / s

E) the transverse speeds are the speed of the oscillatory movement

      y = A cos (wt)

     w = 2π f = 2π / T

     w = 2π / 0.0750

     w = 83.78 rad / s

 

     y = 0.850 cos (83.78 t)

Speed ​​is

     v = dy / dt

     v = -A w cost wt

     v = - 0.850 83.78 cos (83.78 t)

     v = -80.43 cos (83.78 t)

The maximum speed when the cosine values ±1

      v = 80.43 cm / s

      v = -80.43 cm / s

F) if we draw a drawing, the distance between two nodes is half the wavelength, at the distance between an antinode synod is half this, it occupies a quarter of the wavelength

     D₂ = ¼  λ

     D₂ = 30.0/4

     D₂= 7.5 cm

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40 kg girl and an 8.4 kg sled are on the frictionless ice of a frozen lake, 15 m apart but connected by a rope of negli- gible mass. the girl exerts a hori- zontal 5.2 n force on the rope. what are the acceleration magni- tudes of (a) the sled and (b) the girl? (c) how far from the girl’

Answers

a) The acceleration magnitudes of the sled is 0.62 m/s². b) The acceleration magnitudes of the girl is 0.13m/s². c) The distance from the girl is 2.6m.

(a) The girl's force is the sole horizontal force acting on the sled because friction is insignificant. The total of the vertical forces—gravitational force and the normal force of the ice—is zero. The sled accelerates with an acceleration of

a s = F/m s = 52N/8.4kg = 0.62m/s².

​(b) The third law of Newton states that the force exerted by the sled on the girl is 5.2N. Her acceleration is equal to a g times m g.

​a s= F/m s = 5.2N/40kg = 0.13m/s².

(c) The sled and girl are accelerating in the opposite directions. The coordinate for the girl, assuming she starts at the origin and advances in the +x direction, is given by x g = 2 1 a g t 2. The sled moves in the -x direction and begins at x 0 = 15m. Its location is indicated by the coordinates x s =x 0 2 1 a s t 2. They collide when x g = x s, or when 2 1 a g t 2 = x 0 2 1 a s t 2.

When this occurs

t= a \sg \s​ \s +a \ss \s​

2x \s0

​The girl has already traveled the distance x g = 2 1 a s t 2 = a g + a s by that point.

​x \s0 \s​ \s a \sg

​​ \s = \s0.13m/s \s2 \s +0.62m/s \s2

(15m)(0.13m/s \s2 \s ) \s​ \s =2.6m

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What would be the acceleration of gravity (in m/s2) at the surface of a world with nine times Earth's mass and three times its radius?

Answers

Answer:

Explanation:

Given:

M = 9*M₃

R = 3*R₃

g₃ =9.8 m/s²

_______

g - ?

g₃ = G*M₃ / R₃²

g = G*M / R² = G*9·M₃ / (3*R₃)² =  G*9·M₃ / (9*R₃²)  = G*M₃ / R₃² = g₃

Accelerations are the same

Physical science please help me I’m begging

Answers

Answer: the displacmen is 2 blocks north

Explanation:

A metal rod 800mm long is heated from 10°C to 95°C.If it expands by 1.36mm,the linear expansivity of the metal is?

Answers

Answer:

2 x 10^(-5)

Explanation:

The linear expansivity α can be calculated using the following equation:

[tex]\Delta L=\alpha\cdot\Delta T\cdot L[/tex]

Where ΔL is the change in length, ΔT is the change in temperature and L is the original length of the metal. So, replacing the values, we get:

[tex]\begin{gathered} 1.36=\alpha(95-10)(800) \\ 1.36=\alpha(85)(800) \end{gathered}[/tex]

Then, solving for α, we get:

[tex]\begin{gathered} 1.36=\alpha(68000) \\ \frac{1.36}{68000}=\frac{\alpha(68000)}{68000} \\ 2\times10^{-5}=\alpha \end{gathered}[/tex]

Therefore, the linear expansivity of the metal is 2 x 10^(-5)

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