A small sculpture made of gold ( rho gold =19320 kg/m^ 3 ) is believed to have a secret central cavity. The weight of the sculpture in air is 11.29 N. When it is submerged in water, the weight is 9.190 N. What is the volume of the secret cavity?​

Answers

Answer 1

Answer:

1.1 x 10⁻⁵m³

Explanation:

Given parameters:

Weight in air  = 11.29N

Weight in water  = 9.190N

Density of gold  = 19320kg/m³

Unknown:

Volume of the secret cavity = ?

Solution:

To solve this problem, we need to find the mass of the secret cavity.

Weight of the cavity  = Weight of sculpture in air  - Weight of sculpture in water

 Weight of cavity  = 11.29N  -  9.190N = 2.1N

 Weight  = mass x acceleration due to gravity

        Mass  =[tex]\frac{2.1}{9.8}[/tex]   = 0.2kg

So;

 Volume of substance can be determined from the density.

 Density  = [tex]\frac{mass}{volume}[/tex]  

   Volume  = [tex]\frac{mass}{density}[/tex]  

 Now insert the parameters and solve;

  Volume  = [tex]\frac{0.2}{19320}[/tex]   = 1.1 x 10⁻⁵m³


Related Questions

?
_2. Region surrounding the nucleus where electrons are found.
?
_3. Positively charged center of an atom.
?
4. Particles that differ in number between isotopes.

Answers

Answer:

Electron shell

Nucleus

Neutrons

Explanation:

An atom is made up of three fundamental subatomic particles which are the protons, neutrons and electrons.

Protons are the positively charged particles. Neutrons do not carry any charges. Both protons and neutrons are found in the tiny nucleus at the center of that atom. The electrons are negatively charged. They are found outside the nucleus in electronic shells.

In Einstein’s theory of gravitation, gravity is due to:
A)the acceleration of the universe
B)the presence of mass
C)the rotation of the universe
D)the curvature of spacetime
E)the speed of light

Answers

Answer:

B,  caused by the presence of mass

Explanation:

Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.70 m. The ball is going 7.33 m/s.

If the speed is tripled, what happens to its centripetal force?
a)The new centripetal force is 1/3 what it was
b)The new centripetal force is 9 times more
c)The new centripetal force is 1/9 what it was
d)The new centripetal force is 3 times more

Answers

Answer:

b)The new centripetal force is 9 times more

Explanation:

The formula to apply in this case is that of tension force on a spring which is equal to the centripetal force.

T= mv²/r --------i

where T is the tension on the spring

v= velocity/speed of the ball = 7.33 m/s

m= mass of the ball , 0.015 kg

r= radius of circle , 0.70 m

Use the values in the formula as;

T= {0.015 * 7.33² } / 0.70

T= 0.8059335 / 0.70

T= 1.15 N ---------i

If the speed is tripled then;

v= 21.99 m/s

T= 0.015 * 21.99² / 0.70

T= 10.36 N ------ii

Check the changes by dividing i and ii as ;

10.36 / 1.15 =  9.01

This is 9 times more hence if the speed is tripled ,the new centripetal force is 9 times more.

When you use a
spray bottle, you force air over
a small tube inside the bottle.
Explain why the liquid inside
the bottle comes out.

Answers

Answer: Spray bottles are an extremely useful type of machine and an excellent demonstration of basic plumbing principles. A spray-bottle head is made up of only a few parts. It has a trigger lever, which activates a small pump. This pump is attached to a plastic tube that draws cleaning fluid from the bottom of the reservoir. The pump forces this liquid down a narrow barrel and out a small hole at the gun's muzzle. The hole, or nozzle, serves to focus the flowing liquid so that it forms a concentrated stream.

The only complex element in this design is the fluid pump, and it's about as simple as they come. The main moving element is a piston, housed inside a cylinder. Inside the cylinder, there is a small spring. To operate the pump, you pull the trigger back, pushing the piston into the cylinder. The moving piston compresses the spring, so when you release the trigger, the piston is pushed back out of the cylinder. These two strokes of the piston, into the cylinder and out again, constitute the entire pump cycle.

Explanation:

Awnser: The liquid comes out because you're using your hand to squeeze the handle, which forces it out.

Elizabeth .........................................................................

Answers

Answer:

who's elizabeth? haha

Answer:

What about it?

Explanation:

what is an emergent curriculum

Answers

Answer:

Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.

The ___ of a wave is the reciprocal of its frequency.

Answers

Answer:

time period of the wave

Answer:

The Frequency of a wave is the reciprocal of its Period

The Period of a wave is the reciprocal of its frequency

Explanation:

A P E X

Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflection is the angle between the reflected ray and the normal, which is the surface of the mirror.

Which statement corrects an error on the site?

Answers

Answer:

A

Explanation:

i) Give two practical
application of static friction

Answers

1).  Walking / Driving

If there were no static friction between the soles of your shoes and the ground, then you could move your feet back and forth but your body would never go anywhere.

Same for using tires to move a car, a bus, a bicycle or a motorcycle.

2).  Sleeping

If there were no static friction between your jammies and the sheet, you would slide right off of the bed whenever there was the slightest breeze of air in the room.  

Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.

Answers

Answer:

K = ρL²g

Explanation:

Consider L as the length of the raft inside the water when the raft is displaced through additional distance y;

Then:

F = upthrust ( restoring force) = weight of the liquid displaced.

[tex]F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g[/tex]

where;

A = L²

[tex]\rho_{\omega} = \rho[/tex]

F = ky.

Then,

[tex]Ay \rho g = ky[/tex]

[tex]L^2y \rho g = ky[/tex]

Divide both sides by y

K = ρL²g

List four safety measures one should take when there is a cyclone warning.​

Answers

Answer:

I'm gonna give you more than 4 So u can choose.

Turn off all electricity, gas and water.

Unplug all electrical appliances.

Keep your emergency kit close at hand.

If the building starts to collapse, protect yourself with mattresses, rugs.

Stay tuned to the radio for updates.

Stay inside until told it is safe to go outside.

A 2 kg block slides with constant velocity along a horizontal tabletop. A horizontal applied force of 10 N and a downward applied force of 5 N act on the block, as shown. The coefficient of friction between the block and tabletop is most nearly... ​

Answers

Answer:

huh

Explanation:

Answer:

what are we finding?

Explanation:

what is the surface pressure of Venus?

Answers

answers 93 bar

The atmosphere of Venus is the layer of gases surrounding Venus. It is composed primarily of carbon dioxide and is much denser and hotter than that of Earth. The temperature at the surface is 740 K (467 °C, 872 °F), and the pressure is 93 bar (9.3 MPa), roughly the pressure found 900 m (3,000 ft) underwater on Earth.

an inclinded plane makes work easier by increasing the distance and blank the force

Answers

Hi! I believe your answer is decreasing. An inclined plane makes work easier by decreasing the amount of effort force needed, but increases the distance. I hope this helps you! Good luck and have a great day. ❤️✨

George got a bad grade on the test because he decided he would rather sleep than study. this is an example of a __ attribution

Answers

the right answer for this question would be dispositional

Answer:

dispositional

Explanation:

Which Energy transformation will occur when this rubber band is let go elastic energy -chemical energy mechanical energy -electrical energy chemical energy -mechanical energy elastic energy mechanical- energy elastict

Answers

Elastic Energy - Mechanical Energy

If the speed of a roller coaster at the bottom of a hill is 20.0 m/s , what is the tallest hill the coaster can climb, assuming no friction losses ?

Answers

Answer:

20.4 meters

Explanation:

KE = 1/2 m v^2 = mgh = PE (convert all kinetic energy to potential energy, because at the highest point the coaster can climb, it will be stopped!)

=> h = (1/2 m v^2) / (mg) = v^2/(2*g) = (20 m/s)^2 / (2*9.8 m/s^2) = 20.4 m

The tallest height that the roller coaster can climb is 20 m.

A roller coaster is a device in which energy conversions from potential to kinetic energy takes place. Hence the roller coaster can easily be used to demonstrate the conversion of mechanical energy from one form to another.

Given that the velocity of the roller coaster at the bottom of the hill is  20.0 m/s, potential energy is converted into kinetic energy.

Hence;

mgh = 1/2mv^2

gh =1/2v^2

h = 1/2v^2/g

h = 0.5 × (20)^2/10

h = 20 m

Learn more: https://brainly.com/question/999862

A small truck has a mass of 2085 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 13.0 m/s on a level road?

Answers

Answer:

Work required is 328387.5 Joules.

Explanation:

Given the following data;

Mass = 2085kg

Initial velocity, Vi = 13m/s

Final velocity, Vf =22m/s

To find the workdone;

We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.

Mathematically, it is given by the equation;

W = Kf - Ki

Where;

W is the work required.

Kf is the final kinetic energy possessed by the object.

Ki is the initial kinetic energy possessed by the object.

But Kinetic energy = ½MV²

W = ½MVf² - ½MVi²

Substituting into the equation, we have;

W = ½(2085)*22² - ½(2085)*13²

Simplifying the equation, we have;

W = 1042.5 * 484 - 1042.5 * 169

W = 504570 - 176182.5

W = 328387.5J

Therefore, the work required to decrease the speed of the vehicle is 328387.5 Joules.

help please! thank you! please dont plagiarism my teacher checks for plagiarism ;-;

Answers

Answer:

the reason why the crate won't move to the direction of the force being applied (F app). is because the (Fgravity) is pulling it down making it heavy to move

given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone bridge is in equilibrium and then calculate voltages and currents as for reference exercise.​

Answers

Answer:

The balanced condition for Wheat stones bridge is  

Q

P

​  

=  

S

R

​  

 

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R  

1

​  

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R  

2

​  

=R+S

=20+30=50Ω

Net resistance of the network as R  

1

​  

 and R  

2

​  

 are in parallel

i=  

R

V

​  

=  

50

6×3

​  

=0.36 A.

Explanation:

what happens at a transform boundary

Answers

Transform boundaries are places where plates slide sideways past each other.

I hope

Answer:

Answer is "two tectonic plates slide past eachother" ( for a pe x)

Explanation:

A value that describes how heavy an object is and is related to the force of gravity is:

Answers

The weight of an object

Answer: B) weight

Got it right on E2020

А A pool of water of refractive index
4/3! is 60cm deep. Find its apparent
depth when viewed vertically through
air.​

Answers

Answer:

Apparent depth = 45 cm

Explanation:

The refractive index of water in a pool, n = 4/3

Real depth, d = 60 cm

We need to find its apparent  depth when viewed vertically through  air.​ The ratio of real depth to the apparent depth is equal to the refractive index of the material. Let the apparent depth is d'. So,

[tex]n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{60}{\dfrac{4}{3}}\\\\d'=45\ cm[/tex]

So, the apparent depth is 45 cm.

A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process?
A.
velocity and wavelength
OB.
velocity and frequency
Ο Ο Ο Ο
OC.
frequency and wavelength
OD.
frequency and phase
E.
wavelength and phase

Answers

Answer:

Velocity and frequency

Explanation:

Read each scenario below. Then select the answer choices that complete the sentences,

A car engine has

power than a house because a car engine does the same amount of work in

time,

Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height

and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,

Raj applied

power than Yaskrin because his stacking took turve to do the same amount of

Answers

Answer:

Higher

Lesser

Lesser

Longer

Explanation:

Search...

54

ryanzl6659

14 hours ago

Physics

College

Read each scenario below. Then select the answer choices that complete the sentences,

A car engine has HIGHER power than a house because a car engine does the same amount of work in LESSER time,

Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,

Raj applied LESSER power than Yaskrin because his stacking took LONGER to do the same amount of

Answer:

More

Less

Less

More

Explanation:

i got all correct

A barge is pulled by two tugboats. If the resultant of the forces exerted by the
tugboats is 5kN force directed along the axis of the barge, determine the tension in
each of the ropes for α = 45

Answers

Answer:

Approximately [tex]3.5\; \rm kN[/tex] in each of the two ropes.

Explanation:

Let [tex]F_1[/tex] and [tex]F_2[/tex] denote the tension in each of the two ropes.

Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.  

The first direction is parallel to resultant force on the barge.

The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \cos(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \cos(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].

These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: [tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}}[/tex]. That force should be equal to [tex]5\; \rm kN[/tex].

The second direction is perpendicular to the resultant force on the barge.

The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \sin(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \sin(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].

These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: [tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}}[/tex]. However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.

That gives a system of two equations and two unknowns:

[tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}} = 5\; \rm kN[/tex], and[tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}} = 0[/tex].

The second equation suggests that [tex]F_1 = F_2[/tex]. Hence, replace the [tex]F_2[/tex] in the first equation with [tex]F_1[/tex] and solve for [tex]F_1\![/tex]:

[tex]F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN[/tex].

Because [tex]F_1 = F_2[/tex] (as seen in the second equation,) [tex]F_2 = F_1 \approx 3.5\; \rm kN[/tex].

In other words, the tension in each of the two ropes is approximately [tex]3.5\; \rm kN[/tex].

The tension in each of the rope is 3,535.5 N

The given expression:

the resultant force, R = 5 kN = 5000 N

the angle in between the forces, α = 45

To find:

the tension in each of the ropes

The tension in  each of the ropes  is calculated as follows;

The tension in vertical direction

[tex]F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N[/tex]

The tension in horizontal direction;

[tex]F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N[/tex]

Thus, the tension in each of the rope is 3,535.5 N

Learn more here:https://brainly.com/question/11194858

A crane lifts a 425 kg steel beam vertically upward a distance of 614.4 m
How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces.

Answers

PHYSICS

*not sure about the answer but here we go*

Mass = 425 kg

distance = 614.4 m

acceleration = 1.8 m/s²

Answer :

Count Force first.

[tex]f \: = m \: \times a[/tex]

F = 425 × 1,8

F = 765 N

Now let's count Work.

[tex]w \: = \: f \: \times s[/tex]

W = 765 × 614.4

W = 470016 J

A 3.35 kg object initially moving in the positive x direction with a velocity of 4.90 m s collides with and sticks to a 1.88 kg object initially moving in the negative y direction with a velocity of 3.12 m/s. Find the final components of velocity of the composite object.

Answers

Answer:

The final components of velocity of the composite object is 3.33 m/s.

Explanation:

Given;

mass of the first object, m₁ = 3.35 kg

initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction

mass of the second object, m₂ = 1.88 kg

initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction

initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s

initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s

The resultant velocity of the two objects is given by;

R² = 16.415² + 5.8656²

R² = 303.858

R = √303.858

R = 17.432 kgm/s

Apply the principle of conservation of linear momentum for inelastic collision;

total initial momentum before = total final momentum after collision

P₁(x) + P₂(y) = Pf

R = Pf

R = v(m₁ + m₂)

17.432 = v(m₁ + m₂)

where;

v is the final components of velocity of the composite object

[tex]v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s[/tex]

Therefore, the final components of velocity of the composite object is 3.33 m/s.

What makes the atmosphere an important part of Earth’s system?

Answers

Answer:

water exchange carbon dioxide is taken away and oxygen is made

The Earths atmosphere protects and sustains the plants inhabitants by providing warmth and absorbing harmful solar rays. In addition to containing the oxygen and carbon dioxide, which living things need to survive, the atmosphere traps the suns energy and wards off many of the dangers of space.

Hope I helped ❤️
Plz mark me brainiest? :)

Let the force of the Moon on the Earth be F1. Let the force of the Earth pulling on the Moon be F2. Which of the following is greater?

Answers

they are both the same because of newton’s third law
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