The magnitude of the force that the truck exerts on the car is same as the horizontal force exerted by the car on the truck that is 1600 N.
In physics, a force is a force that can change the motion of an object. A force can change the velocity of an object with mass. Pressure can also be intuitively described as pushing or pulling. A force has both a value and a displacement, making it a vector quantity.
Squeeze is pushing and pulling, which affects daily life because people without strength cannot open and close objects, lift arms and legs.
Reason :
This question is a simple application of Newton's third law, which states that if an object A exerts a force on an object B, then B must exert a force on A that is equal in magnitude but opposite in direction.
The car pushes against the ground with a force of 1600 N, so therefore the ground must exert a force on the car, also of 1600 N.
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Two hockey pucks of equal mass approach each
other. Puck 1 has an initial velocity of 20.0 m/s [S
45° E], and puck 2 has an initial velocity of 15 m/s
[S 45° W]. After the collision, the first puck is
moving with a velocity of 10.0 m/s [S 45° W].
(a) Determine the final velocity of the second
puck.
(b) Is this collision elastic, perfectly inelastic, or
(non-perfectly) inelastic? Explain your reasoning.
The final velocity of the second puck will be 20.61 m/s [S 30.95 E] and the collision will be non-perfectly inelastic.
We know that since there is no external force applied to the system of two pucks, So after the collision, Momentum will remain conserved,
Using Momentum conservation in x-direction:
Px(initial) = Px(final)
[tex]m1*u1x + m2*u2x = m1*v1x + m2*v2x[/tex]
[tex]m1 = m2 = m[/tex] (given)
u1 = Initial speed of m1
= 20.0 m/s at S 45 E
= 20.0 m/s at 45 deg below the positive x-axis
u2 = Initial speed of m2
= 15.0 m/s at S 45 W
= 15.0 m/s at 45 deg below the negative x-axis
v1 = final speed of m1
= 10.0 m/s at S 45 W
= 10.0 m/s at 45 deg below the negative x-axis
u1x = Initial velocity of m1 in x-direction
= [tex]20.0*cos 45[/tex]°
= 14.14 m/s
u2x = Initial velocity of m2 in x-direction
= [tex]-15.0*cos 45[/tex]°
= -10.61 m/s
v1x = Final velocity of m1 in x-direction
= [tex]-10.0*cos 45[/tex]°
= -7.07 m/s
v2x = Final velocity of m2 in x-direction = ?
So,
[tex]m*14.14 + m*(-10.61) = m*(-7.07) + m*v2x[/tex]
[tex]v2x = 14.14 - 10.61 + 7.07[/tex]
[tex]v2x= 10.6 m/s[/tex]
Now Using Momentum conservation in the y-direction:
Px(initial) = Px(final)
[tex]m1*u1y + m2*u2y = m1*v1y + m2*v2y[/tex]
u1y = Initial velocity of m1 in y-direction
= [tex]-20.0*sin 45[/tex]°
= -14.14 m/s
u2y = Initial velocity of m2 in y-direction
= [tex]-15.0*sin 45[/tex]°
= -10.61 m/s
v1y = Final velocity of m1 in y-direction
= [tex]-10.0*sin 45[/tex]°
= -7.07 m/s
v2y = Final velocity of m2 in y-direction = ?
So,
[tex]m*(-14.14) + m*(-10.61) = m*(-7.07) + m*v2y[/tex]
[tex]v2y = -14.14 - 10.61 + 7.07[/tex]
[tex]v2y= -17.68 m/s[/tex]
So we have
v2x = 10.6 m/s and v2y = -17.68 m/s
the final speed of puck 2 will be:
[tex]|v2| = sqrt (10.6^2 + (-17.68)^2)[/tex]
[tex]|v2| = 20.61 m/s[/tex]
the final direction of puck 2 will be:[tex]Direction = arctan (\frac{v2y}{v2x} ) = arctan (\frac{-17.68}{10.6})[/tex]
Direction = 59.05 deg below positive x-axis (Since v2x > 0 and v2y < 0, So puck 2 will be moving in 4th quadrant)
Direction = 90 - 59.05
= 30.95 deg
= S 30.95 E
b) Since both pucks did not stick together after the collision, So this is not a perfectly inelastic collision
Now Using energy conservation:
[tex]KE = KEf - KEi[/tex]
[tex]KE = (\frac{1}{2})*m*v1^2 + (\frac{1}{2})*m*v2^2 - (\frac{1}{2})*m*u1^2 - (\frac{1}{2})*m*u2^2[/tex]
[tex]KE = (\frac{1}{2})*m*[10.0^2 + 20.6^2 - 20.0^2 - 15.0^2][/tex]
[tex]KE = -50.32*m[/tex]
So some amount of energy was lost during the collision, which means the above collision is (non-perfectly) inelastic
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a) The magnitude of the final velocity of the second puck is 20.61 m/s in the direction 50.3° east-south.
b) This collision is (non-perfectly) inelastic.
What is law of conservation of momentum?According to the rule of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.
Let the final velocity of the second puck = v i + V j
Now, applying law of conservation of momentum along x axis:
m × 20.0 × cos45° + m × 10.0 ×(- cos45°) = m × 10 × ( - cos45°) + mv
⇒ v =10.6 m/s.
Applying law of conservation of momentum along y axis:
m × 20.0 × (-sin45°) + m × 10.0 ×(- sin45°) = m × 10 × ( - sin45°) + mV
⇒ V = - 17.68 m/s.
Hence, the final velocity of the second puck = 10.6 i - 17.8 j m/s.
The magnitude of the final velocity of the second puck
= √{(10.6)² + (-17.8)²} m/s
= 20.61 m/s.
and the direction is = tan⁻¹(-17.8/10.6) = - 59.22°
b) The amount of loss in kinetic energy = 1/2 × m ( 20.0² + 15.0² - 10.0² - 20.61²) joule
= 50.36m joule.
Hence, as loss of kinetic energy happens, this collision is (non-perfectly) inelastic.
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1 Wire 1 Wire 2 Long, straight, parallel wires 1 and 2 carry current I in opposite directions, as shown. Which of the following correctly describes the magnetic fields from the wires in the region between the wires and provide evidence to support this claim? A The magnetic fields are in opposite directions, because the currents are in opposite directions. B) The magnetic fields are in opposite directions, because the region is on opposite sides of the wires: to the right of wire 1 and to the left of wire 2. C The magnetic fields are in the same directions, because both wires are long and straight. D The magnetic fields are in the same directions, because the currents have the same magnitude. E The magnetic fields are in the same directions, because the currents are in opposite directions and are on opposite sides of the wires: to the right of wire 1 and to the left of wire 2. < >
Based on the information provided, the statement that correctly describes the magnetic fields from the wires in the region between the wires and provide evidence to support this claim is that the magnetic fields are in opposite directions, because the region is on opposite sides of the wires: to the right of wire 1 and to the left of wire 2. (Option B)
A magnetic field refers to a vector field that defines the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field. A current traveling through a loop of wire creates a magnetic field along the axis of the loop. The direction is obtained from the right-hand rule. Hence, the direction of the field inside the loop can be found by curling the fingers of the right hand in the direction of the current through the loop; the thumb then points in the direction of the magnetic field.
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A student initially stands on a circular platform that is free to rotate without friction about its center. The student jumps off tangentially, setting the platform spinning. Quantities that are conserved for the student-platform system as the student jumps include which of the following? 1. Angular momentum II. Linear momentum III. Kinetic energy Al only B Il only С I and II only D II and III only E I, II, and 111
The quantity conserved for the student platform system when the student jumps is included in the momentum angular.
The true choice is A.
Angular momentum is simply defined as the momentum possessed by objects that move circularly.
Momentum angle also has meaning as a measure used to see how much linear momentum is directed around a certain point. This point is known as the center point.
Since angular momentum and linear momentum are vectors, the direction must be considered. As in this question, the direction of the linear momentum keeps changing as the circular platform rotates, and the direction of the angular momentum is always the same (both off the page and into the page). That's why linear momentum changes but angular momentum doesn't. So, the quantity conserved for the student platform system when the student jumps is included in the momentum angular.
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a uniform, 4.0 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. a 1.3 kg raven flying horizontally at 5.0 m/s flies into this door at its center and bounces back at 2.5 m/s in the opposite direction.
The angular speed of the gate just after it is struck by the unfortunate raven is 2.4375rad/s and during the collision, the angular momentum is conserved but not the linear momentum.
Given mass of square (m) =4kg
length of solid wooden gate (l) =1.5m
mass of raven (m1) = 1.3kg
speed of raven (v1) = 5m/s
speed of bouncing back (v2) = 2.5m/s
Impulse on gate (I) = 1/3ml^2 = 1/3x4x1.5x1.5 = 3kgm^2
(a) using conservation of angular momentum Li = Lf
1/2mv1L/2 = mv2L/2+Iω
m(v1+v2)L/2 = 3xω
1.3x(5+2.5)x1.5/2 = 3xω
ω = 2.4375rad/s
(b)As momentum is conserved there is no external torque
initial kinetic energy (KE) = 1/2mv1^2 = 1/2x1.3x5x5 = 16.25J
final kinetic energy (KEf) = 1/2mv2^2+Iω^2/2
KEf = 1x1.3x2x2/2+3x2.4375x2.4375/2 = 2.6+ 8.9 = 11.5J
As Kinetic energy is not conserved, the collision is inelastic.
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Complete question: a uniform, 4.0 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. a 1.3 kg raven flying horizontally at 5.0 m/s flies into this door at its center and bounces back at 2.5 m/s in the opposite direction. (a) What is the angular speed of the gate just after it is struck by the unfortunate raven? (b) During the collision, why is the angular momentum conserved but not the linear momentum?
A quantum system has three energy levels, so three wavelengths appear in its emission spectrum. The shortest observed wavelength is 263nm ; light with a 434nm wavelength is also observed.
Part A
What is the third wavelength?
The distance between two successive troughs or crests is known as the wavelength. The third wavelength will range from 700 to 900 nm.
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometres, and other units since it is a distance measurement.
The wavelength emitted is proportional to the difference in the energy level change. The shift in energy level is large for the wavelength 263nm. 434nm light indicates a further shift in energy level,
However, the difference in energy level for this wavelength to be emitted is not bigger than the prior one. There is a chance that these subsystems currently have very little energy
Hence the third wavelength will range from 700 to 900 nm.
The distance between each node is one-third the length of the string. The picture up above displays the standing wave pattern. You should be able to tell from the image that the wavelength of the third harmonic is divided by the string's length in half.
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To avoid last-minute moves, you should be looking down the road to where your vehicle will be in about:
(a) 5 to 10 seconds.
(b) 10 to 15 seconds.
(c) 15 to 20 seconds.
Scrutinize the route 10-15 seconds in advance of your car to spot risks and prevent last-minute maneuvers. It's risky to stare at the car or the road just in front of yours all the time.
What controls the velocity of a vehicle?The ignition switch, brake pedal, or steering wheel are the three inputs on a car that can alter its speed. If either rate or location changes, velocity also does. The idea of acceleration describes how quickly the velocity varies.
What is an illustration of velocity?Velocity can be defined as the rate at which someone moves in a specific direction. as the pace of a car driving north on such a highway or the pace at which a rocket takes off. The location of the automobile is not shown by the speedometer. As a result, this instrument can only determine a vehicle's speed, not its velocity.
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acceleration of 14 m/s/s mass of object is decreased by a factor of 2.2 then the new accelration woul dbe
When the mass of the object is decreased by a factor of 2.2, the acceleration is increased by a factor of 2.2, new acceleration would be of 30.8 m/s/s.
The effect of reducing the mass of an object by a factor of 2.2 on its acceleration is determined by Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
In terms of calculations, the new acceleration can be calculated by multiplying the initial acceleration by the factor by which the mass is decreased. Therefore, the new acceleration of the object with a reduced mass of 2.2 times its original mass would be 2.2 times its initial acceleration of 14 m/s/s. This would result in a new acceleration of 30.8 m/s/s (14 x 2.2 = 30.8).
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Randomized block design: Researchers interested in identifying the optimal planting density for a type of perennial grass performed the following randomized experiment: Ten different plots of land were each divided into eight subplots, and planting densities of 2, 4, 6 and 8 plants per square meter were randomly assigned to the subplots, so that there are two subplots at each density in each plot. At the end of the growing season the amount of plant matter yield was recorded in metric tons per hectare. These data appear in the file pdensity. dat. The researchers want to fit a model like y = β1 + β2x + β3x 2 + , where y is yield and x is planting density, but worry that since soil conditions vary across plots they should allow for some across-plot heterogeneity in this relationship. To accommodate this possibility we will analyze these data using the hierarchical linear model described in Section 11.1. Randomized block design: Researchers interested in identifying the optimal planting density for a type of perennial grass performed the following randomized experiment: Ten different plots of land were each divided into eight subplots, and planting densities of 2, 4, 6 and 8 plants per square meter were randomly assigned to the subplots, so that there are two subplots at each density in each plot. At the end of the growing season the
The diversity of the vegetation on Earth contributes to its attractiveness, particularly the grassland, which is primarily covered in trees and grasses.
There are many different types of grassland, and one of them is savanna grassland, which is home to forbs and perennial grasses.
Large geographic areas called biomes are identified by a certain climatic pattern and a set of dominating plant and animal populations. Savanna and grassland biomes both have a dominant grass composition. In semi-arid climate zones where there is insufficient rainfall to sustain significant tree development, grassland biomes can be found. Savannas are grassland habitats that contain a sizable amount of woody vegetation, such as trees or bushes. Due to their need for a warm climate, they are found closer to the equator.
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a block of mass m on an inclined surface is attached to a spring of negligible mass, as shown. the other end of the spring is attached to a wall, and there is negligible friction between the block and the incline. the block is pulled to a position such that the spring is stretched from its equilibrium position. the block is then released from rest. which of the following systems can be classified as a closed system?
A block of mass m on an inclined surface is attached to a spring of negligible mass, as shown is a system consisting of the block, spring, and Earth.
What is mass?
The amount of matter in a particle or object is represented by its mass, which is denoted by the symbol m. In the International System (SI), the kilogram serves as the default unit of mass (kg).
What is inclined surface ?
An inclined plane is the technical term for a sloped surface. It is well known that objects can accelerate down inclination planes due to an imbalanced force. Analyzing the forces acting onto an object on an inclined plane is crucial for comprehending this form of motion.
Therefore, a block of mass m on an inclined surface is attached to a spring of negligible mass, as shown is a system consisting of the block, spring, and Earth.
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A physics professor demonstrates the Doppler effect by tying a 450
Hz sound generator to a 1.0
−
m
-long rope and whirling it around her head in a horizontal circle at 100
rpm .
A. What is the difference between the highest frequency heard by a student in the classroom and the initial frequency of the sound generator? Express your answer with the appropriate units.
B. What is the difference between the lowest frequency heard by a student in the classroom and the initial frequency of the sound generator? Express your answer with the appropriate units.
The difference between the highest frequency heard by a student in the classroom and the initial frequency of the sound generator is =582.5 Hz and 619.2 Hz
briefly:-F(s) = 600 Hz, the generator's frequency
The rope's length is r = 1 m.
rotating frequency, w = 100 rpm
First, we determine the generator's speed, v (g)
v(g) = r.w
However, it should be remembered that we must convert the whirling speed from rpm to rad/s.
100 rpm is 100*2/60 rad/s.
100 rpm = 200π/60
100 rpm = 620.4 / 60
10.47 rad/s for 100 rpm.
Now, we employ this to determine the generator's speed.
v(g) = r.w
v(g) = 1 * 10.47
v(g) = 10.47 m/s
The frequency is estimated when approaching the generator as
F(a) = F(s) / [(v(g)/v) - 1)]
F(a) = 600 / [1 - (10.47/343)]
F(a) = 600 / 0.969
F(a) = 619.2 Hz
On the other hand, the frequency of the retreating generator is
F(r)=F(s)/[1 + (v(g)/v)]
F(r) = 600 / [1 + (10.47/343)]
F(r) = 600 / 1.030
F(r) = 582.5 Hz
The highest and lowest frequencies are therefore 619.2 Hz and 582.5 Hz, respectively.
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Giraffe bending to drink. In a giraffe with its head 2.0m above its heart, and its heart 2.0m above its feet, the (hydrostatic) gauge pressure in the blood at its heart is 250torr.Assume that the giraffe stands upright and the blood density is . In torr (or mm Hg), find the (gauge) blood pressure (a) at the brain (the pressure is enough to perfuse the brain with blood, to keep the giraffe from fainting) and (b) at the feet (the pressure must be countered by tight-fitting skin acting like a pressure stocking). (c) If the giraffe were to lower its head to drink from a pond without splaying its legs and moving slowly, what would be the increase in the blood pressure in the brain? (Such action would probably be lethal.)
(a) The gauge pressure at the brain of the giraffe is 94 torr.
(b) The gauge pressure at the feet of the giraffe is 4.1×10² torr.
(c) The increase in the blood pressure in the brain as the giraffe lowers its head to the level of its feet is 3.1×10² torr.
We know that,
The blood column between the feet and the brain is where the hydrostatic blood pressure gauge is located.
(a) The gauge pressure at the brain of the giraffe is
P(brain) = P(heart) − ρgh
P(brain) = 250 torr − (1.06×10³ kg/m³)(98 m/s²)(2.0 m) (1 torr/133.33 Pa)
P(brain) = 94 torr.
Hence, The gauge pressure at the brain of the giraffe is 94 torr.
(b) The gauge pressure at the feet of the giraffe is
P(feet) = P(heart) + ρgh
P(feet) = 250 torr + (1.06×10³ kg/m³)(9.8 m/s²)(2.0 m) (1 torr/133.33 Pa)
P(feet) ≈ 4.1×10² torr.
Hence, The gauge pressure at the feet of the giraffe is 4.1×10² torr.
(c) The increase in the blood pressure in the brain as the giraffe lowers its head to the level of its feet is
△P = P(feet) − P(brain)
△P = 406 torr − 94 torr
△P = 312 torr ≈ 3.1×10² torr
Hence, The increase in the blood pressure in the brain as the giraffe lowers its head to the level of its feet is 3.1×10² torr.
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Your system volume is running out of disk space. You need to extend the system volume to give it more space. Which of the following conditions must be met to extend the system volume?O The system volume must be formatted with NTFS.O The disk must have contiguous free space on the same disk.
Contiguous free space on the same disk is the sole available option for expanding the system volume. For both basic or dynamic disks, this is true.
Choose two benefits of solid state storage over hard drives from the list below.Your computer will boot up faster thanks to SSDs, which also provide faster data transfer. When running applications that access vast volumes of data, such an operating system, faster speeds imply SSDs can policies and procedures for managing at the ultra-speeds required in today's commercial environment.
Which of the following has to be true in order to increase the system volume?On the same disk, there must be continuous open space. Only contiguous free space within the same disk can be used to expand the system capacity.
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On the basis of your knowledge of bonding in liquids and solids, which of the following substances has the highest melting temperature? Group of answer choices O CH4 O H2O O Cl2 O SO2 O NaBr
NaBr has the highest melting temperature on the basis of bonding in liquids and solids .
Option E is correct .
Network covalent solids, including silicon dioxide, graphite, and diamond, have the greatest melting points. A massive covalent structure is held together by a large number of strong bonds. There are certain metals with the next-highest melting points, particularly transitional metals.
Bonds between atoms in covalent compounds share electrons. They have distinctive physical characteristics, such as lower melting temperatures and electrical conductivity compared to ionic compounds, since they share electrons. Ionic compounds have high melting and boiling temperatures because it takes a lot of energy to break the bonds between the many ions in the ionic lattice.
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Question Maple Chobe Worth 2 points)
(08.08 MG)
An auditorium has special panels installed along its walls and portions of the celling to direct sound waves. Whi
property these panels are taking advantage of?
Reflection because reflected waves have a higher intensity
Reflection because reflected waves bounce off a media
Absorption because absorbed waves go into the media
Absorption, because absorbed waves have a lower frequency
Question &
Answer:
(b) Reflection because reflected waves bounce off a media
Explanation:
You want to know the property of special wall and ceiling panels that is being used to direct sound waves.
ReflectionThe properties offered in the answer choices are (1) reflection, and (2) absorption. Of these, the property most likely used is reflection.
Reflection causes the sound to bounce off the panel and move in a direction based on the angle at which it hits the panel. By angling the panels appropriately, the sound can be directed wherever it might be desired.
AbsorptionAbsorption will cause the sound to be "swallowed up" by the panel, so that the energy of it is lost in the panel and not returned to the air. An absorptive panel may also have a certain amount of reflection. In general, such a panel can modify the acoustic behavior of the auditorium, but will not "direct sound waves."
__
Additional comment
Often reflective panels are angled at more or less random angles so that sound is reflected around the room, but not to any particular spot. The purpose is to eliminate any echo in the room.
Answer:
The correct answer to "Which property these panels are taking advantage of?" is B. Reflection because reflected waves bounce off a media.
Explanation:
Part of a wave energy is absorbed by a solid through refraction and some is reflected off of the solids surface. An echo is a representation of reflected sound waves.
Echoes are minimized in theaters and performance venues. Additional panels are placed on walls and ceilings to help absorb and/or direct reflected sound waves in ways that enhance the audience's satisfaction of a live show.
"An auditorium has special panels installed along its walls and portions of the celling to direct sound waves."
"The glider is released at a distance 1.47m from the bottom of the track. Use the acceleration value you obtained in Part C to calculate the speed of the glider when it reaches the bottom of the track. "
(I found the acceleration to be 7.55 m/s-1, as shown in the above picture)
The speed of the glider when it reaches the bottom of the track is 4.71 m/s.
[tex]V^{2}[/tex] = μ² + 2as
μ = 0
ν = [tex]\sqrt{2as}[/tex] = √2 × 7.55 × 1.47 = 4.71 m/s
This glider can create lift equal to its weight and can soar into the air at any speed greater than 30 kts. If the aircraft is launched into the wind at, let's say, a surface wind speed of 10 kts, it just needs to travel 20 kts above the ground before taking off. A winch launch is one of the most popular ways of launch, accelerating a glider from zero to sixty miles per hour in less than two seconds using a very powerful winch and lengthy steel cables. Slowest - normally 25 to 60 km/h for recreational gliders (above 50 km/h necessitates use of a safety device), these steel lines (and the glider linked to them) represent a very serious risk to everyone on the grounds.
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La varilla liviana de la figura 5.12
if the angle between the horizontal and the direction of the 5.0 meters per second veolocity decreases from 30 degrees to 20 defrees the horitonztoal distancr the ball travelks will
The magnitude of the horizontal component of the ball's initial velocity is 4.7 m/s .
In the question ,
it is given that ,
the velocity of the ball is ⇒ 5 m/s .
the angle between horizontal and the direction of 5 m/s decreases from 30 degrees to 20 degrees .
Now , θ = 20° .
We know that ,the trigonometric ratio , Cos θ is = (Adjacent side)/(Hypotenuse)
given velocity = 5 m/s .
So , Cos(20°) = Vₓ/(5) ....Vₓ is the horizontal component .
Simplifying further ,
we get ,
Vₓ = 4.7 m/s .
Therefore , The magnitude of horizontal component is 4.7 m/s .
The given question is incomplete , the complete question is
The ball being kicked by a foot and rising at an angle of 30 degrees from the horizontal. The ball has a velocity of 5.0 meters per second. (Neglect Friction) If the angle between the horizontal and the direction of the 5.0 meters per second decreases from 30 degrees to 20 degrees,
What is the magnitude of the horizontal component of the ball's initial velocity ?
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figure 32-27 shows a closed surface. along the flat top face, which has a radius of 2.0 cm, a perpendicular magnetic field of magnitude 0.30 t is directed outward. along the flat bottom face, a magnetic flux of 0.70 mwb is directed outward. what are the (a) magnitude and (b) direction (inward or outward) of the magnetic flux through the curved part of the surface?
a) The magnitude of the magnetic flux through the curved part of the surface is 0.70 mWb.
b) The magnetic flux through the curved part of the surface is 12.56 cm².
The direction of the magnetic flux through the curved part of the surface is outward.
The magnetic flux through a surface is given by the equation:
Φ = B × A
where Φ is the magnetic flux, B is the strength of the magnetic field, and A is the area of the surface.
In this case, the strength of the magnetic field is given as 0.30 T, and the area of the curved surface is given as the surface area of a hemisphere with a radius of 2.0 cm, which is:
A = 2 × π × r² = 2 × 3.14 × (2.0 cm)² = 12.56 cm²
Plugging these values into the equation gives us a magnetic flux of:
Φ = (0.30 T) × (12.56 cm²) = 0.70 mWb
The direction of the magnetic flux is given as outward for both the top and bottom faces, so the direction of the magnetic flux through the curved part of the surface is also outward.
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A boy is initially seated on the top of a hemispherical ice mound of radius R=13.8m. He begins to slide down the ice, with a negligible initial speed (Fig. 8-47). Approximate the ice as being frictionless. At what height does the boy lose contact with the ice?
The height of the boy above the bottom of the mound is 9.20m.
What is radius ?
The radius of a circle is the distance a circle's center from any point along its perimeter. Usually, "R" or "r" is used to indicate it.
What is speed ?
Speed is the rate of change in location of an item, expressed in metres per second. For instance, the speed of an item is one metre per second if it starts at the origin and goes three metres in three seconds. Speed is easily calculated by dividing a distance by a time.
Let FN be the normal force of the ice on him and m is his mass. The net inward force is mgcosθ−F N , and, according to Newton's second law, this must be equal to mv 2 /R, where v is the speed of the boy. At the point where the boy leaves the ice F N =0, so gcosθ=v 2 /R.. We wish to find his speed. If the gravitational potential energy is taken to be zero when he is at the top of the ice mound, then his potential energy at the time shown is
U=−mgR(1−cosθ).
He starts from rest and his kinetic energy at the time shown is 21 mv 2 . . Thus conservation of energy g 0= 21 mv 2 −mgR(1−cosθ)orv=2gR(1−cosθ).
We substitute this expression into the equation developed from the second law to obtain gcosθ=2g(1−cosθ). This gives cosθ=2/3.
The height of the boy above the bottom of the mound is
h=Rcosθ= 32R= 32(13.8m)=9.20m
Therefore, the height of the boy above the bottom of the mound is 9.20m.
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identify the correlation you would expect to see between the weight of baggage someone carries and the speed at which he or she walks. explain.
Negative association; the pace of walking slows down as the amount of luggage grows.
Positive and negative correlation: what are they?Inverse correlation is another term for negative correlation. In statistics, an inverse correlation explains the association between two variables that vary in the opposite directions from one another, whereas a positive correlation shows the link between two variables that change together.
When two variables behave in synchrony, rising or falling in lockstep with one another, there is a positive correlation. When two variables move in opposition to one another—that is, when one rises, the other falls—this is known as a negative correlation.
A link between two variables that move in the opposing directions is known as a negative correlation.
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Public Radio station KXPR-FM in Sacramento broadcasts at 88.9 MHz. The radio waves pass between two tall skyscrapers that are 15.0m apart along their closest walls.
A). At what horizontal angles, relative to the original direction of the waves, will a distant antenna not receive any signal from this station?
B).If the maximum intensity is 3.40W/m2 at the antenna, what is the intensity at �6.00? from the center of the central maximum at the distant antenna?
The horizontal angle will be 1.4598 rad and the intensity will be 1.576 W/m² in relation to the waves' initial direction.
A radar antenna is a gadget that broadcasts radio waves and watches for reflected waves. An antenna's performance is based on its capacity to recognize the precise direction in which an object is positioned.
The specified direction's horizontal angle is:
sinθ ∝ 1
sinθ = nλ/a
n ∝ λ/a
n = (88.9 * 10⁶ * 15)/ 3 * 10⁸ = 4.4454
n max = 4
The maximum angle θ4 = (4 * 3 * 10⁸)/ 15 * 88.9 * 10⁶ = 64.14°
The value of the wavelength is:
λ = c / v = (3 * 10⁸)/ (88.9 * 10⁶) = 3.3745 m
I = Imax [(sin δ/2)/ δ/2]
β/2 = π /4 (a sinθ)
β = π / 3.3745 (15 sin 6°) = 1.4597 rad
I = 3.4 * (sin 1.4597/ 1.4597)² = 1.576 W/m²
As a result, at horizontal angles, the intensity will be 1.576 W/m2 and the wave direction will be 1.4597 rad.
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what is the maximum magnitude of p that can be applied before tipping would occur, assuming the block does not slip? express your answer to three significant figures with appropriate units. ptip
A probabilistic assessment of seismic hazards requires an estimate of the maximum moment intensity M of the largest earthquake that is likely to occur in a given region. The answer is in the image.
Maximum magnitude, an important parameter in calculating seismic hazards, is also a controversial parameter. The choice of value can have a large impact on the final outcome of the results, but it is most likely the magnitude of an earthquake that has not yet occurred in the area under study.
The term size is defined as the number of flocks. For example, the magnitude can be used to describe the speed comparison between a car and a bicycle. It can also be used to describe how far an object has moved or how much an object has in relation to size.
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a mass m starts at rest and then falls down distance l, where it contacts an unstressed spring of negligible mass. if the spring compresses for a maximum of l/2, find the force constant of the spring in terms of mg/l.
For a mass, the spring's force constant is 12 mg/L. M begins at rest and descends l distance before colliding with a negligible mass unstressed spring. if the spring is compressed for no longer than l/2.
The spring constant is significant because it demonstrates a fundamental material characteristic. The amount of force necessary to deform any spring made of any material is specified here. The material is more stiff when the spring constant is higher, and less stiff when the spring constant is lower. The force constant of an undamaged spring is k. It is stretched to an equilibrium length that is well inside the elastic limit by a weight that is suspended from it.
mg(L+L/2) = 0.5 kx^2
mg(3L)/2 = 1/2k(1/2)^2
3mgL/2 = kl^2/8
k = 12mg/L
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a small em-wave source (i.e. a small collection of charges which is vibrating in simple harmonic motion having a known frequency) radiates an electromagnetic wave into the vacuum of space itself. of course, the electromagnetic wave consists of blocks of magnetic and electric fields which are leaving the vibrating source; these blocks of electric and magnetic fields leave the source in all possible directions (i.e. nothing has been done by the designers of the source to form the wave into a tight beam). as the wave moves away from the source, determine what happens to each of the following: a) the frequency of the electromagnetic wave o increases o decreases O remains constant (b) the intensity of the electromagnetic wave increases o decreases O remains constant Give your reasoning as briefly as possible
As the wave moves away from the source, the frequency of the wave (c) remains constant whereas the intensity of the wave (b) decreases.
Frequency stays same because frequency of EM wave does not depend on the distance from the source because waves cannot just disappear in free space.
So, frequency remains constant.
The intensity (I) of a wave is defined as the rate at which it transfers energy divided by the area over which the energy is spread. In other words, intensity is the rate of energy flow per unit area.
Intensity of EM wave is inversely proportional to the square of distance from source, as
I = P/A
So, intensity of wave decreases.
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a piston a has a diameter of 0.81 cm, as shown. a second piston b has a diameter of 4.0 cm. a b 578.8 n f in the absence of friction, determine the magnitude of the force f~ necessary to support the 578.8 n weight. answer in units of n.
11.7 N of force is needed to hold the weight m on Piston 2.
What are example and force?Force is the term used to describe a body's tendency to change or modify its state as a result of an external cause. When force is applied, the item can also alter its size, shape, and direction. kick a ball, pushing and pulling on the door, or kneading dough are a few examples.
Briefing:
The force required to support weight, m on Piston 2 is calculated from Pascal's principle as follows:
P₁ = P₂
where P₁ is pressure on Piston 1 = F₁/A₁
P₂ is pressure on Piston = F₂/A₂
F₁/A₁ = F₂/A₂
F₂ is the force on Piston 2 = 1189 N
A₁ is Area 1 = πr²
where r = d/2
A₁ = π * (0.81/2 *1/100)²
A₁ = 40.5* 10⁻⁵ m²
F₁ is the force on piston 1 = ?
A₂ is area 2
A₂ = π * (4.0/2 *1/100)²
A₂ = 2 * [tex]10^{-2}[/tex] m²
F₁ = A₁ * F₂/A₂
F₁ =40.5* 10⁻⁵ m² * 578.8 N / 2 * [tex]10^{-2}[/tex]m²
F₁ = 11.7N
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A race car starts from rest and travels east along a straight and level track. For the first 5.0 s of the car's motion, the eastward component of the car's velocity is given by vx(t)=(0.970m/s3)t2.
a.What is the acceleration of the car when vx = 16.7 m/s? Express your answer with the appropriate units.
The acceleration of the car when Vₓ = 16.7 m/s is 8.05 m/s² .
In the question ,
it is given that ,
east ward component of the the car's velocity is Vₓ(t) = (0.970 m/s³)t²
To find the acceleration of the car, we differentiate velocity with respect to t ,
We get ,
aₓ = dVₓ/dt = d/dt (0.97 m/s³)t²
aₓ = (2 × 0.97 m/s³)t
aₓ = (1.94 m/s³)t ...equation(1)
given that Vₓ = 16.7 m/s .
So , 16.7 = (0.97 m/s³)t²
t² = 16.7/0.97
t = 4.15 sec .
Substituting, time t = 4.15 in the equation(1) , we get
aₓ = 1.94 × 4.15
= 8.05 m/s²
Therefore , the requires acceleration is 8.05 m/s² .
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Suppose that in cases B, C, and D in problem 1, each combination of springs were replaced by a single spring such that the motion of the block is the same as before the replacement. We will call the spring constant of this new spring the effective spring constant of the original combination. Quantitatively, the effective spring constant, keff , may be defined by the relationship Sigma Fvector block, spring = -Keff , where Sigma block, spring is the sum of all forces on the block by the springs, and is the position of the block with respect to the equilibrium position. Rank the four cases according to keff, from largest to smallest. Explain. Use your ranking above and the relationship T = 2pi root m/keff to rank the cases according to period of oscillation. Explain. Use your ranking from part a and the relationship E total = 1/2 keffA2 to rank the cases according to total energy. Explain.
After solving the equation the cases according to total energy C<A<B= D
What is spring constant ?
A measure of the spring's stiffness is its spring constant, or k. Various springs and materials have different effects. The spring becomes stiffer and more challenging to extend the bigger the spring constant.
What is equilibrium ?
When all external forces (including moments) acting on an item are balanced, the object is said to be in equilibrium in a reference coordinate system. Thus, all external moments and forces acting on this item result in zero as a net effect.
Case A; k effective = K
Case B ; strings connected in parallel
K effective = 2A
Case c; strings connected in series
K effective = k/2
Case D ; strings connected in parallel
K effective = 2K
So, C,<A<B= D
T= 2π[tex]\sqrt{m/Keffective}[/tex]
T∝ [tex]\sqrt{1/K effective }[/tex]
Accordingly time period ranking is C>A>B= D
E total = 1/2 K effective a²
E total ∝ k effective
so ranking will be
C<A<B= D
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Consider two identical rods with lengthLand uniformly distributed massM. The rods are not pinned down, they are free to move both translationally and rotationally. Initially, the center of mass of each rod is stationary, but the left rod is rotating clockwise around its center with an angular speedω0(the right rod is not rotating): The ends of the rods collide. After the collision, the left rod moves directly up towards the top of the page with a speedv, and is no longer rotating around its center: If the collision is elastic, find expressions for the following quantities: - the speedv
- the final translational velocity of the center of mass of the right rod - the final angular velocity of the right rod around its center Express your answers in terms ofω0,L, and numerical factors.
The centre of mass of the right rod has a final translational velocity of MWo2/12. The right rod's final angle of rotation about its centre is ML2/12.
Ordinary velocity, expressed in metres per second, is what translational velocity is. Tangential velocity is the part of ordinary (translational) velocity that is in the tangential direction. For instance, if a rigid body is rotating about a fixed axis at an angular velocity of radians per second, any point r metres away from the axis will have a purely tangential velocity of r metres per second. The speed at which the angular location or orientation of an item varies is represented by a pseudovector in physics as angular velocity or rotational velocity ( or ), also called an angular frequency vector.
Iz = Ix+Iy
Ix = iy
Iz = 2Ix
(ML^2/6)/2 = ML^2/12
the final angular velocity of the right rod around its center is ML^2/12.
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two small speakers a and b are driven in step at 725 hz by the same audio oscillator. these speakers both start out 4.50 m from the listener, but speaker a is slowly moved away. (see (figure 1)).
Speakers both start out 4.50 m from the listener, but speaker a is slowly moved away.The first, constructive interference occurs when the path difference is lambda 0.47m.
A. Let us find the wavelength 1st
use:
v = f * lambda
344 = 725* lambda
lambda = 0.47 m
First destructive interference occurs when the path difference is lambda/2
path difference = d
d = lambda/2
d = 0.47/2
= 0.235 m
B. 2nd destructive interference occurs when the path difference is 3*lambda/2
path difference = d
d =3* lambda/2
d = 3* 0.47/2
= 0.705 m
C. first, constructive interference occurs when the path difference is lambda
path difference = d
d = lambda
d = 0.47 m
Wavelength is the distance between identical points in adjacent cycles of a waveform signal propagating in space or along a wire. In wireless systems, this length is usually expressed in meters, centimeters, or millimeters. Wavelength is the distance between two wave crests and the same for wave troughs.
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start with the smallest problem and progress to the most complex", is another of the rules of the Cartesian method, what rule is it?
Using theory on the Cartesian method, starting with the smallest problem and progressing to the most complex, refers to the rule known as synthesis.
¿What is the Cartesian method?This has been a method developed by René Descartes with which he sought to find what was the truth.
The method established by René Descartes contains four fundamental rules or principles that are:
Rule (Evidence)AnalysisSynthesisVerificationAmong all these rules, the synthesis is the one that indicates that you should start with the smallest problem and progress to the most complex.